\documentclass{article}

\usepackage{../style}

\usepackage{../langs}

\begin{document}

\fnote{\copyright{} Christian Urban, 2014}

%% the expectation is that anything encrypted today, will be

%% decrypted in 20 years time

\section*{Handout 5 (Protocols)}

Protocols are the computer science equivalent to fractals and

the Mandelbrot set in mathematics. With the latter two you

have a simple formula, which you just iterate and then you

test whether a point is inside or outside a region\ldots{}it

does not look exciting, but voila something magically

happened.\footnote{\url{http://en.wikipedia.org/wiki/Fractal},

\url{http://en.wikipedia.org/wiki/Mandelbrot_set}} Protocols

are similar: they are simple exchanges of messages, but in the

end something ``magical'' can happen---for example a secret

channel has been established or two entities have

authenticated themselves to each other. This can happen even

in face of strong adversaries who have complete control over

the network involved in the message exchange. The problem with

magic is of course it is poorly understood and even experts

often got, and get, it wrong with protocols.

To have an idea what kind of protocols we are interested in, let

us look at a few examples. One example are (wireless) key 

fobs, which operate the central locking system and the

ignition in a car.

\begin{center}

\includegraphics[scale=0.075]{../pics/keyfob.jpg}

\quad

\includegraphics[scale=0.2025]{../pics/startstop.jpg}

\end{center}

\noindent The point of these key fobs is that everything is

done over the ``air''---there is no physical connection

between the key, doors and engine, as was the case with the

old solid metal keys. With the key fobs we must achieve

security by exchanging certain messages between the key fob on

one side and the doors and engine on the other. Clearly what

we like to accomplish is that I can get into my car and start

it, but that thieves are kept out. The problem is that

everybody can ``overhear'' or skim the exchange of messages

between the key fob and car. In this scenario the simplest

attack you need to defend against is a person-in-the-middle

attack. For this imagine you park your car in front of a

supermarket. One thief follows you with a strong transmitter.

A second thief ``listens'' to the signals from the car and

wirelessly transmits them to the ``colleague'' who followed

you. This thief silently enquires what the key fob answers.

This answer is then send back to the thief at the car. If done

properly, the car will dutifully open and possibly start. No

need to steal your keys anymore. 

That this is an attack one needs to reckon with is

demonstrated by the fact that dodgy

websites\footnote{\url{http://autokeydevices.com/product/wave/}

\ldots{} funnily this webpage says ``not intended for illegal

use'', but I have a hard time finding any legal purpose for

such a device.} sell the necessary equipment for top Ruble.

This webpage is notable for the very helpful picture

of a person-in-the-middle attack (see Figure~\ref{rsa}).

\begin{figure}[t]

\begin{center}

\includegraphics[scale=0.15]{../pics/rsa_attack_eng.jpg}

\end{center}

\caption{From a dodgy webpage about modern car theft. Note the

stylish attackers.\label{rsa}}

\end{figure}

But there are many more such protocols we like to study.

Another example is Wifi---you might sit at a Starbucks and

talk wirelessly to the free access point there and from there

talk to your bank (see The Guardian article cited at the very

end of this handout). Moreover, even if you have to touch in

and out your Oyster card at the reader each time you enter or

exit the Tube, it actually operates wirelessly and with

appropriate equipment over some quite large distance (several

meters). But there are many, many more examples for protocols

(Bitcoins, Tor, mobile phones,\ldots). 

The common characteristics of the protocols we are interested

in is that an adversary or attacker is assumed to be in

complete control over the network or channel over which we

exchanging messages. An attacker can install a packet sniffer

on a network, inject packets, intercept packets, modify

packets, replay old messages, or fake pretty much everything

else. In this hostile environment, the purpose of a protocol

(that is exchange of messages) is to achieve some security

goal. For example only allow the owner of the car in, but

everybody else should be kept out.

The protocols we are interested here are generic descriptions

of how to exchange messages in order to achieve a goal. Unlike

the distant past where, for example, we had to meet a person in

order to authenticate him or her (via a passport for example),

the problem we are facing on the Internet is that we cannot

easily be sure who we are ``talking'' to. The obvious reason

is that only some electrons arrive at our computer; we do not

see the person, or computer, behind the incoming electrons

(messages). 

To start, let us look at one of the simplest protocols that

are part of the TCP protocol (which underlies the Internet).

This protocol does not do anything security relevant, it just

establishes a ``hello'' from a client to a server which the

server answers with ``I heard you'' and the client answers 

in turn with something like ``thanks''. This protocol

is often called a \emph{three-way handshake}. Graphically it

can be illustrated as follows

\begin{center}

\includegraphics[scale=0.45]{../pics/handshake.png}

\end{center}

\noindent On the left-hand side is a client, say Alice, on the

right-hand side is a server, say. Time is running from top to

bottom. Alice initial SYN message needs some time to travel to

the server. The server answers with SYN-ACK, which will

require some time to arrive at Alice. Her answer ACK will

again take some time to arrive at the server. After the

messages are exchanged, Alice and the server simply have

established a channel to communicate over. Alice does not know

whether she is really talking to the server (somebody else on

the network might have intercepted her message and replied in

place of the server). Similarly, the server has no idea who it

is talking to. Whether they can authenticate themselves

depends on what is exchanged next and is the point of the

protocols we want to study in more detail.

Before we start in earnest, we need to fix a more convenient

notation for protocols. Drawing pictures like the one above

would be awkward in the long-run. The notation we will adopt

abstracts away from a few details we are not interested in:

for example the time the messages need to travel between

endpoints. What we are interested in is in which order the

messages are sent. For the SYN-ACK protocol we will therefore

use the notation 

\begin{equation}

\begin{array}{l@{\hspace{2mm}}l}

A \to S: & SYN\\

S \to A: & SYN\_ACK\\

A \to S: & ACK\\

\end{array}\label{SYNACK}

\end{equation}

\noindent The left-hand side of each clause specifies who is

the sender and who is the receiver of the message. On the

right of the colon is the message that is send. The order from

top to down specifies in which order the messages are sent. We

also have the convention that messages, like $SYN$ above, are

send in clear-text over the network. If we want that a message

is encrypted, then we use the notation

\[

\{msg\}_{K}

\]  

\noindent for messages. The curly braces indicate a kind of

envelope which can only be opened if you know the key $K$

with which the message has been encrypted. We always assume

that an attacker, say Eve, cannot get to the content of the

message, unless she is also in the possession of the key. We

explicitly exclude in our study that the encryption can be

broken.\footnote{\ldots{}which of course is what a good

protocol designer needs to ensure and more often than not

protocols are broken because of a weak encryption method. For

example Oyster cards contain a very weak encryption mechanism

which has been attacked and broken.} It is also

possible that an encrypted message contains several parts. In

this case we would write something like

\[

\{msg_1, msg_2\}_{K}

\] 

\noindent But again Eve would not be able to know 

this unless she also has the key. We also allow the 

possibility that a message is encrypted twice under 

different keys. In this case we write

\[

\{\{msg\}_{K_1}\}_{K_2}

\] 

\noindent The idea is that even if attacker Eve has the

key $K_2$ she could decrypt the outer envelop, but

still does not get to the message, because it is still

encrypted with the key $K_1$. Note, however,

while an attacker cannot obtain the content of the message

without the key, encrypted messages can be observed

and be recorded and then replayed at another time, or

send to another person!

Another very important point is that our notation for

protocols such as shown in \eqref{SYNACK} is a

\underline{schema} how the protocol should proceed.

It could be instantiated by an actual protocol run

between Alice, say, and the server Calcium at King's. In this 

case the specific instance would look like

\[

\begin{array}{l@{\hspace{2mm}}l}

\text{Alice} \to \text{Calcium}: & SYN\\

\text{Calcium} \to \text{Alice}: & SYN\_ACK\\

\text{Alice} \to \text{Calcium}: & ACK\\

\end{array}

\]

\noindent But a server like Calcium of course needs to

serve many clients. So there could be the same protocol

also running with Bob, say

\[

\begin{array}{l@{\hspace{2mm}}l}

\text{Bob} \to \text{Calcium}: & SYN\\

\text{Calcium} \to \text{Bob}: & SYN\_ACK\\

\text{Bob} \to \text{Calcium}: & ACK\\

\end{array}

\]

\noindent And these two instances of the protocol could be

running in parallel or be at different stages. So the protocol

schema shown in \eqref{SYNACK} can be thought of how two 

programs need to run on the side of $A$ and $S$ in order to 

successfully complete the protocol. But it is really just a 

blueprint for how the communication is supposed to proceed. 

This is actually already a way how such protocols can fail.

Although very simple, the $SYN\_ACK$ protocol can cause

headaches for system administrators where an attacker starts

the protocol, but then does not complete it. This looks

graphically like

\begin{center}

\includegraphics[scale=0.4]{../pics/synflood.png}

\end{center}

\noindent The attacker sends lots of $SYN$ requests which the

server dutifully answers. But in doing so the server needs to

keep track of such protocol exchanges. As a result every time

the protocol is initiated a little bit of memory will be eaten

away on the server side until all memory is exhausted. When

poor Alice then tries to contact the server, it is overwhelmed

and does not respond anymore. This kind of attack is called

\emph{SYN

floods}.\footnote{\url{http://en.wikipedia.org/wiki/SYN_flood}}

After reading four pages, you might be wondering where the

magic is with protocols. For this let us take a closer look at

authentication protocols.

\subsubsection*{Authentication Protocols}

The simplest authentication protocol between principals

$A$ and $B$, say is

\begin{center}

$A \to B: K_{AB}$ 

\end{center}

\noindent It can be thought of as $A$ sends a common secret to

$B$, for example a password. The idea is that if only $A$ and

$B$ know the key $K_{AB}$ then this should be sufficient for

$B$ to infer it is talking to $A$. But this is of course too

naive in the context where the message can be observed by

everybody else on the network. Eve, for example, could just

record this message $A$ just sent, and next time sends the same

message to $B$. $B$ has no other choice than believing it

talks to $A$. But actually it talks to Eve, who now clears

out $A$'s bank account assuming $B$ had been a bank.

A more sophisticated protocol which tries to avoid the

replay attack is as follows

\begin{center}

\begin{tabular}{l@{\hspace{2mm}}l}

$A \to B:$ & $HELLO$\\

$B \to A:$ & $N$\\

$A \to B:$ & $\{N\}_{K_{AB}}$\\

\end{tabular}

\end{center} 

\noindent With this protocol the idea is that $A$ first sends

a message to $B$ saying ``I want to talk to you''. $B$ sends

then a challenge in form of a random number $N$. In protocols

such random numbers are often called \emph{nonce}. What is the

purpose of this nonce? Well, if an attacker records $A$'s

answer, it will not make sense to replay this message, because

next time this protocol is run, the nonce $B$ sends out will

be different. So if we run this protocol, what can $B$ infer?

It has send out an (unpredictable) nonce to $A$ and received

this challenge back, but encoded under the key $K_{AB}$. If

$B$ assumes only $A$ and $B$ know the key $K_{AB}$ and the

nonce is unpredictable, then $B$ is able to infer it must be

talking to $A$. Of course the implicit assumption on this

inference is that nobody else knows about the key $K_{AB}$

and nobody else can decrypt the message. $B$ of course can

decrypt the answer from $A$ and check whether the answer

corresponds to the challenge (nonce) $B$ has sent earlier.

But what about $A$? Can $A$ make any inferences about whom it

talks to? It dutifully answered the challenge and hopes his or

her bank, say, will be the only one to understand her answer.

But is this the case? No! Let us consider again an attacker

Eve who has control over the network. She could have

intercepted the message $HELLO$ and just replied herself to

$A$ using a random number\ldots{}for example one which she

observed in a previous run of this protocol. Remember that if

a message is sent without curly braces it is sent in clear

text. $A$ would encrypt the nonce with the key $K_{AB}$ and

send it back to Eve. She just throws away the answer. $A$

would hope that she talked to $B$ because she followed the

protocol, but unfortunately she cannot be sure who she is

talking to---it might be Eve. 

The solution is to follow a \emph{mutual challenge-response}

protocol. There $A$ already starts off with a challenge (nonce)

on her own.

\begin{center}

\begin{tabular}{l@{\hspace{2mm}}l}

$A \to B:$ & $N_A$\\

$B \to A:$ & $\{N_A, N_B\}_{K_{AB}}$\\

$A \to B:$ & $N_B$\\

\end{tabular} 

\end{center}

\noindent As seen, $B$ receives this nonce, $N_A$, adds his

own nonce, $N_B$ and encrypts it with the key $K_{AB}$. $A$

receives this message, is able to decrypt it since we assume

she has the key $K_{AB}$ too, and sends back the nonce of $B$.

Let us analyse which inferences $A$ and $B$ can make after the

protocol has run. $B$ received a challenge and answered

correctly to $A$ (inside the encrypted message). An attacker

would not be able to answer this challenge correctly because

the attacker is assumed to not be in the possession of the key

$K_{AB}$; so is not able to generate this message. It could

also not have been the case that it is an old message

replayed, because $A$ would send out each time a fresh nonce.

So with this protocol you can ensure also for $A$ that it

talks to $B$. I leave you to argue that $B$ can be sure to

talk to $A$. Of course these arguments will depend on the

assumptions that only $A$ and $B$ know the key $K_{AB}$ and

that nobody can break the encryption unless they have this key

and that the nonces are fresh each time the protocol is run.

The purpose of the nonces, the random numbers that are sent

around, might be a bit opaque. Because they are unpredictable

they fulfil an important role in protocols. Suppose

\begin{enumerate}

\item I generate a nonce and send it to you encrypted with a

      key we share

\item you increase it by one, encrypt it under a key I know

      and send it back to me 

\end{enumerate}

\noindent In our notation this would correspond to the 

protocol

\begin{center}

\begin{tabular}{l@{\hspace{2mm}}l}

$I \to Y:$ & $\{N\}_{K_{IY}}$\\

$Y \to I:$ & $\{N + 1\}_{K_{IY}}$\\

\end{tabular} 

\end{center}

\noindent What can I infer from this simple exchange:

\begin{itemize}

\item you must have received my message (it could not just be

      deflected by somebody on the network, because the

      response required some calculation; doing the

      calculation and sending the answer requires the key

      $K_{IY}$)

\item you could only have generated your answer after I have

      sent you my initial message (since my $N$ is always new,

      it could not have been a message that was generated

      before I myself knew what $N$ is)

\item if only you and me know the key $K_{IY}$, the message

      must have come from you

\end{itemize}

\noindent Even if this does not seem much information we can

glean from such an exchange, it is in fact the basic building

block in protocols for establishing some secret or for

achieving some security goal (like authentication). This is

what I meant by magic: we send around ``just'' some random

numbers, but actually can use them to make some meaningful

inferences.

While the mutual challenge-response protocol solves the

authentication problem, there are some limitations. One is of

course that it requires a pre-shared secret key. That is

something that needs to be established beforehand. Not all

situations allow such an assumption. For example if I am a

whistleblower (say Snowden) and want to talk to a journalist

(say Greenwald) then I might not have a secret pre-shared key.

Another limitation is that such mutual challenge-response

systems often work in the same system in the ``challenge

mode'' but also in the ``response mode''. For example if two

servers want to talk to each other---they would need the

protocol in response mode, but also if they want to talk to

other servers in challenge mode. Similarly if you are in an

military aircraft you have to challenge everybody you see, in

case there is a friend amongst the targets you like to shoot,

but you also have to respond to any of your own anti-aircraft

guns on the ground, lest they shoot you. In these situations

you have to be careful to not decode, or answer, your own

challenge. Recall the protocol is

\begin{center}

\begin{tabular}{l@{\hspace{2mm}}l}

$A \rightarrow B$: & $N_A$\\  

$B \rightarrow A$: & $\{N_A, N_B\}_{K_{AB}}$\\

$A \rightarrow B$: & $N_B$\\

\end{tabular}

\end{center}

\noindent but it does not specify who is $A$ and who is $B$.

If the protocol works in response and in challenge mode, then

$A$ will be $A$ in one instance, but $B$ in the other. I hope

this makes sense. Let us look at the details and let us assume

our adversary is $E$ who just deflects our messages back to

us. 

\begin{center}

\begin{tabular}{lllll}

& \multicolumn{2}{l}{challenge mode:} & 

\multicolumn{2}{l}{response mode:}\smallskip\\

1. & $A \rightarrow E$: & $N_A$\\ 

2. & & & $E \rightarrow A$: & $N_A$\\ 

3. & & & $A \rightarrow E$: & $\{N_A, N_A'\}_{K_{AB}}$\\

4. & $E \rightarrow A$: & $\{N_A, N_A'\}_{K_{AB}}$\\

5. & $A \rightarrow E$: & $N_A'$\\

\end{tabular}

\end{center}

\noindent In the first step we challenge $E$ with a nonce we

created. Since we also run the protocol in ``response mode'',

$E$ can now feed us the same challenge in step 2. We do not

know where it came from (it's over the air), but if we are in

a fighter aircraft we better quickly answer it, otherwise we

risk to be shot. So we add our own challenge $N'_A$ and

encrypt it under the secret key $K_{AB}$ (step 3). Now $E$

does not need to know this key in order to form the correct

answer for the first protocol. It will just replays this

message back to us in the challenge mode (step 4). I happily

accept this message---after all it is encrypted under the

secret key $K_{AB}$ and it contains the correct challenge from

me, namely $N_A$. So I accept that $E$ is a friend and send

even back the challenge $N'_A$. The problem is that $E$ now

starts firing at me and I have no clue what is going on. I

might suspect, erroneously, that an idiot must have leaked the

secret key. Because I followed in both cases the protocol to

the letter, but somehow $E$, unknowingly to me with my help,

managed to disguise as a friend. As a pilot, I would be a bit

peeved at that moment and would have preferred the designer of

this challenge-response protocol had been a tad smarter. For

one thing they violated the best practice in protocol design

of using the same key, $K_{AB}$, for two different

purposes---namely challenging and responding. They better had

used two different keys. This would have averted this attack

and would have saved me a lot of inconvenience.

\subsubsection*{Trusted Third Parties}

One limitation the protocols we discussed so far have is that

they pre-suppose a secret shared key. As already mentioned,

this is a convenience we cannot always assume. How to

establish a secret key then? Well, if both parties, say $A$

and $B$, mutually trust a third party, say $S$, then they can

use the following protocol:

\begin{center}