cws/cw05.tex
author Christian Urban <christian.urban@kcl.ac.uk>
Sun, 23 Aug 2020 14:39:58 +0100
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% !TEX program = xelatex
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\documentclass{article}
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\usepackage{../style}
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\usepackage{../langs}
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\usepackage{disclaimer}
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\usepackage{tikz}
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\usepackage{pgf}
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\usepackage{pgfplots}
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\usepackage{stackengine}
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%% \usepackage{accents}
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\newcommand\barbelow[1]{\stackunder[1.2pt]{#1}{\raisebox{-4mm}{\boldmath$\uparrow$}}}
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%% change Console to scala.io.StdIn.readByte()
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\begin{document}
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\section*{Part 10 (Scala)}
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\mbox{}\hfill\textit{``If there's one feature that makes Scala, `Scala',}\\
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\mbox{}\hfill\textit{ I would pick implicits.''}\smallskip\\
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\mbox{}\hfill\textit{ --- Martin Odersky (creator of the Scala language)}\bigskip\bigskip
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\noindent
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This part is about a small (esotheric) programming language called
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brainf***. Actually, we will implement an interpreter for our own version
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of this language called brainf*ck++.\bigskip
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\IMPORTANT{This part is worth 10\% and you need to submit on \cwTEN{} at 4pm.}
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\noindent
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Also note that the running time of each part will be restricted to a
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maximum of 30 seconds on my laptop.
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\DISCLAIMER{}
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\newpage
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\subsection*{Reference Implementation}
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As usual, this Scala assignment comes with a reference implementation in
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form of two \texttt{jar}-files. You can download them from KEATS. They
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allow you to run any test cases on your own computer. For example you
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can call Scala on the command line with the option \texttt{-cp bf.jar}
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and then query any function from the \texttt{bf.scala} template file.
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You have to prefix the calls with \texttt{CW10a} and \texttt{CW10b},
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respectively. For example
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\begin{lstlisting}[language={},xleftmargin=1mm,numbers=none,basicstyle=\ttfamily\small]
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$ scala -cp bf.jar
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scala> import CW10a._  
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scala> run(load_bff("sierpinski.bf")) ; ()
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                               *
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                              * *
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                             *   *
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                            * * * *
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                           *       *
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                          * *     * *
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                         *   *   *   *
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                        * * * * * * * *
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                       *               *
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                      * *             * *
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                     *   *           *   *
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                    * * * *         * * * *
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                   *       *       *       *
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                  * *     * *     * *     * *
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                 *   *   *   *   *   *   *   *
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                * * * * * * * * * * * * * * * *
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               *                               *
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              * *                             * *
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             *   *                           *   *
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            * * * *                         * * * *
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           *       *                       *       *
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          * *     * *                     * *     * *
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         *   *   *   *                   *   *   *   *
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        * * * * * * * *                 * * * * * * * *
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       *               *               *               *
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      * *             * *             * *             * *
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     *   *           *   *           *   *           *   *
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    * * * *         * * * *         * * * *         * * * *
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   *       *       *       *       *       *       *       *
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  * *     * *     * *     * *     * *     * *     * *     * *
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 *   *   *   *   *   *   *   *   *   *   *   *   *   *   *   *
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* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
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\end{lstlisting}%$
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\newpage
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\subsection*{Part A (6 Marks)}
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Coming from Java or C++, you might think Scala is a rather esoteric
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programming language.  But remember, some serious companies have built
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their business on
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Scala.\footnote{\url{https://en.wikipedia.org/wiki/Scala_(programming_language)\#Companies}}
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I claim functional programming is not a fad.  And there are far, far
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more esoteric languages out there. One is called \emph{brainf***}. 
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\here{https://esolangs.org/wiki/Brainfuck}
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You
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are asked in this part to implement an interpreter for
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a slight extension of this language.
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Urban M\"uller developed the original version of brainf*** in 1993.  A close
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relative of this language was already introduced in 1964 by Corado
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B\"ohm, an Italian computer pioneer. The main feature of brainf*** is
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its minimalistic set of instructions---just 8 instructions in total
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and all of which are single characters. Despite the minimalism, this
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language has been shown to be Turing complete\ldots{}if this doesn't
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ring any bell with you: it roughly means that every(!) algorithm can,
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in principle, be implemented in brainf***. It just takes a lot of
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determination and quite a lot of memory resources.
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Some relatively sophisticated sample programs in brainf*** are given
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in the file \texttt{bf.scala}, including a brainf*** program for the
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Sierpinski triangle and the Mandelbrot set.  There seems to be even a
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dedicated Windows IDE for bf programs, though I am not sure whether
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this is just an elaborate April fools' joke---judge yourself:
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\begin{center}
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\url{https://www.microsoft.com/en-us/p/brainf-ck/9nblgggzhvq5}
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\end{center}  \bigskip
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\noindent
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As mentioned above, the original brainf*** has 8 single-character
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commands. Our version of bf++ will contain the commands \texttt{'>'},
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\texttt{'<'}, \texttt{'+'}, \texttt{'-'}, \texttt{'.'}, \texttt{'['}
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and \texttt{']'} from the original, and in addition the commands
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\texttt{'@'}, \texttt{'*'} and \texttt{'\#'}.  Every other character
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is considered a comment.
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Our interpreter for bf++ operates on memory cells containing
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integers. For this it uses a single memory pointer that points at each
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stage to one memory cell. This pointer can be moved forward by one
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memory cell by using the command \texttt{'>'}, and backward by using
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\texttt{'<'}. The commands \texttt{'+'} and \texttt{'-'} increase,
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respectively decrease, by 1 the content of the memory cell to which
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the memory pointer currently points to. The command for output is
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\texttt{'.'} whereby output works by reading the content of the memory
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cell to which the memory pointer points to and printing it out as an
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ASCII character.\footnote{In the originial version of bf, there is also a
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  command for input, but we omit it here. All our programs will be
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  ``autonomous''.}  The
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commands \texttt{'['} and \texttt{']'} are looping
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constructs. Everything in between \texttt{'['} and \texttt{']'} is
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repeated until a counter (memory cell) reaches zero.  A typical
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program in brainf*** looks as follows:
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\begin{center}
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\begin{verbatim}
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   ++++++++[>++++[>++>+++>+++>+<<<<-]>+>+>->>+[<]<-]>>.>---.++
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   +++++..+++.>>.<-.<.+++.------.--------.>>+.>++.
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\end{verbatim}
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\end{center}  
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\noindent
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This one prints out Hello World\ldots{}obviously \texttt{;o)} We also
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add 3 new commands to the bf++ langauge, whose purpose we explain later.
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\subsubsection*{Tasks (file bf.scala)}
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\begin{itemize}
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\item[(1)]  Write a function that takes a filename (a string) as an argument
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  and requests the corresponding file from disk. It returns the
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  content of the file as a string. If the file does not exists,
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  the function should return the empty string.\\
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  \mbox{}\hfill[1 Mark]
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\item[(2)] Brainf**k++ memory is represented by a \texttt{Map} from
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  integers to integers. The empty memory is represented by
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  \texttt{Map()}, that is nothing is stored in the
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  memory; \texttt{Map(0 -> 1, 2 -> 3)} stores \texttt{1} at
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  memory location \texttt{0}, and at \texttt{2} it stores \texttt{3}. The
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  convention is that if we query the memory at a location that is
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  \emph{not} defined in the \texttt{Map}, we return \texttt{0}. Write
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  a `safe-read' function, \texttt{sread}, that takes a memory (a \texttt{Map}) and
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  a memory pointer (an \texttt{Int}) as arguments, and `safely' reads the
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  corresponding memory location. If the \texttt{Map} is not defined at
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  the memory pointer, \texttt{sread} returns \texttt{0}.
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  Write another function \texttt{write}, which takes a memory, a
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  memory pointer and an integer value as arguments and updates the
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  \texttt{Map} with the value at the given memory location. As usual,
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  the \texttt{Map} is not updated `in-place' but a new map is created
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  with the same data, except the new value is stored at the given memory
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  pointer.\hfill[1 Mark]
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\item[(3)] Write two functions, \texttt{jumpRight} and
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  \texttt{jumpLeft}, that are needed to implement the loop constructs
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  in brainf**k++. They take a program (a \texttt{String}) and a program
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  counter (an \texttt{Int}) as arguments and move right (respectively
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  left) in the string in order to find the \textbf{matching}
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  opening/closing bracket. For example, given the following program
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  with the program counter indicated by an arrow:
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  \begin{center}
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  \texttt{--[\barbelow{.}.+>--].>.++}
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  \end{center}
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  then the matching closing bracket is in 9th position (counting from 0) and
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  \texttt{jumpRight} is supposed to return the position just after this
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  \begin{center}
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  \texttt{--[..+>--]\barbelow{.}>.++}
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  \end{center}
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  meaning it jumps to after the loop. Similarly, if you are in 8th position,
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  then \texttt{jumpLeft} is supposed to jump to just after the opening
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  bracket (that is jumping to the beginning of the loop):
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  \begin{center}
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    \texttt{--[..+>-\barbelow{-}].>.++}
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    \qquad$\stackrel{\texttt{jumpLeft}}{\longrightarrow}$\qquad
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    \texttt{--[\barbelow{.}.+>--].>.++}
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  \end{center}
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  Unfortunately we have to take into account that there might be
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  other opening and closing brackets on the `way' to find the
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  matching bracket. For example in the brain*ck++ program
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  \begin{center}
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  \texttt{--[\barbelow{.}.[+>]--].>.++}
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  \end{center}
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  we do not want to return the index for the \texttt{'-'} in the 9th
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  position, but the program counter for \texttt{'.'} in 12th
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  position. The easiest to find out whether a bracket is matched is by
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  using levels (which are the third argument in \texttt{jumpLeft} and
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  \texttt{jumpLeft}). In case of \texttt{jumpRight} you increase the
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  level by one whenever you find an opening bracket and decrease by
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  one for a closing bracket. Then in \texttt{jumpRight} you are looking
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  for the closing bracket on level \texttt{0}. For \texttt{jumpLeft} you
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  do the opposite. In this way you can find \textbf{matching} brackets
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  in strings such as
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  \begin{center}
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  \texttt{--[\barbelow{.}.[[-]+>[.]]--].>.++}
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  \end{center}
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  for which \texttt{jumpRight} should produce the position:
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  \begin{center}
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  \texttt{--[..[[-]+>[.]]--]\barbelow{.}>.++}
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  \end{center}
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  It is also possible that the position returned by \texttt{jumpRight} or
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  \texttt{jumpLeft} is outside the string in cases where there are
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  no matching brackets. For example
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  \begin{center}
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  \texttt{--[\barbelow{.}.[[-]+>[.]]--.>.++}
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  \qquad$\stackrel{\texttt{jumpRight}}{\longrightarrow}$\qquad
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  \texttt{--[..[[-]+>[.]]-->.++\barbelow{\;\phantom{+}}}
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  \end{center}
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  \hfill[2 Marks]
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\item[(4)] Write a recursive function \texttt{compute} that runs a
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  brain*u*k++ program. It takes a program, a program counter, a memory
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  pointer and a memory as arguments. If the program counter is outside
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  the program string, the execution stops and \texttt{compute} returns the
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  memory. If the program counter is inside the string, it reads the
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  corresponding character and updates the program counter \texttt{pc},
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  memory pointer \texttt{mp} and memory \texttt{mem} according to the
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  rules shown in Figure~\ref{comms}. It then calls recursively
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  \texttt{compute} with the updated data. The most convenient way to
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  implement the brainf**k++ rules in Scala is to use pattern-matching
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  and to calculate a triple consisting of the updated \texttt{pc},
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  \texttt{mp} and \texttt{mem}.
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  Write another function \texttt{run} that calls \texttt{compute} with a
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  given brainfu*k++ program and memory, and the program counter and memory pointer
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  set to~$0$. Like \texttt{compute}, it returns the memory after the execution
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  of the program finishes. You can test your brainf**k++ interpreter with the
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  Sierpinski triangle or the Hello world programs (they seem to be particularly
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  useful for debugging purposes), or have a look at
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  \begin{center}
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  \url{https://esolangs.org/wiki/Brainfuck}
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  \end{center}\hfill[2 Marks]
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  \begin{figure}[p]
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  \begin{center}
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    \begin{tabular}{|@{\hspace{0.5mm}}p{0.8cm}|l|}
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      \hline
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      \hfill\texttt{'>'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp} + 1$\\
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                       $\bullet$ & \texttt{mem} unchanged
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                     \end{tabular}\\\hline   
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      \hfill\texttt{'<'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp} - 1$\\
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                       $\bullet$ & \texttt{mem} unchanged
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                     \end{tabular}\\\hline   
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      \hfill\texttt{'+'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp}$ unchanged\\
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                       $\bullet$ & \texttt{mem} updated with \texttt{mp -> mem(mp) + 1}\\
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                     \end{tabular}\\\hline   
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      \hfill\texttt{'-'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp}$ unchanged\\
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                       $\bullet$ & \texttt{mem} updated with \texttt{mp -> mem(mp) - 1}\\
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                     \end{tabular}\\\hline   
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      \hfill\texttt{'.'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp}$ and \texttt{mem} unchanged\\
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                       $\bullet$ & print out \,\texttt{mem(mp)} as a character\\
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                     \end{tabular}\\\hline   
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      %\hfill\texttt{','} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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      %                 $\bullet$ & $\texttt{pc} + 1$\\
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      %                 $\bullet$ & $\texttt{mp}$ unchanged\\
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      %                 $\bullet$ & \texttt{mem} updated with \texttt{mp -> \textrm{input}}\\
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      %                 \multicolumn{2}{@{}l}{the input is given by \texttt{Console.in.read().toByte}}
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      %               \end{tabular}\\\hline   
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      \hfill\texttt{'['} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       \multicolumn{2}{@{}l}{if \texttt{mem(mp) == 0} then}\\
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                       $\bullet$ & $\texttt{pc = jumpRight(prog, pc + 1, 0)}$\\
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                       $\bullet$ & $\texttt{mp}$ and \texttt{mem} unchanged\medskip\\
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                       \multicolumn{2}{@{}l}{otherwise if \texttt{mem(mp) != 0} then}\\
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp}$ and \texttt{mem} unchanged\\
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                     \end{tabular}
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                     \\\hline   
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      \hfill\texttt{']'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       \multicolumn{2}{@{}l}{if \texttt{mem(mp) != 0} then}\\
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                       $\bullet$ & $\texttt{pc = jumpLeft(prog, pc - 1, 0)}$\\
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                       $\bullet$ & $\texttt{mp}$ and \texttt{mem} unchanged\medskip\\
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                       \multicolumn{2}{@{}l}{otherwise if \texttt{mem(mp) == 0} then}\\
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp}$ and \texttt{mem} unchanged\\
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                           \end{tabular}\\\hline
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      \hfill\texttt{'@'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp}$ unchanged\\
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                       $\bullet$ & \texttt{mem} updated with \texttt{mp -> \textrm{input}}\\
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                       \multicolumn{2}{@{}l}{the input is given by \texttt{Console.in.read().toByte}}
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                           \end{tabular}\\\hline
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      \hfill\texttt{'*'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp}$ unchanged\\
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                       $\bullet$ & \texttt{mem} updated with \texttt{mp -> \textrm{input}}\\
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                       \multicolumn{2}{@{}l}{the input is given by \texttt{Console.in.read().toByte}}
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                           \end{tabular}\\\hline
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      \hfill\texttt{'\#'} & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                       $\bullet$ & $\texttt{pc} + 1$\\
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                       $\bullet$ & $\texttt{mp}$ unchanged\\
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                       $\bullet$ & \texttt{mem} updated with \texttt{mp -> \textrm{input}}\\
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                       \multicolumn{2}{@{}l}{the input is given by \texttt{Console.in.read().toByte}}
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                     \end{tabular}\\\hline  
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      any other char & \begin{tabular}[t]{@{}l@{\hspace{2mm}}l@{}}
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                         $\bullet$ & $\texttt{pc} + 1$\\
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                         $\bullet$ & \texttt{mp} and \texttt{mem} unchanged
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                       \end{tabular}\\
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      \hline                 
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   358
    \end{tabular}
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   359
  \end{center}
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  \caption{The rules for how commands in the brainf*** language update the program counter \texttt{pc},
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    the memory pointer \texttt{mp} and the memory \texttt{mem}.\label{comms}}
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  \end{figure}
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\end{itemize}\bigskip  
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%%\newpage
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\subsection*{Part B (4 Marks)}
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233
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I am sure you agree while it is fun to look at bf-programs, like the
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Sierpinski triangle or the Mandelbrot program, being interpreted, it
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is much more fun to write a compiler for the bf-language.
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\subsubsection*{Tasks (file bfc.scala)}
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\begin{itemize}
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\item[(5)] Compilers in general attempt to make programs run
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  faster by precomputing as much information as possible
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  before running the program. In our case we can precompute the
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  addresses where we need to jump at the beginning and end of
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  loops. 
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  For this write a function \texttt{jtable} that precomputes the ``jump
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  table'' for a bf-program. This function takes a bf-program 
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  as an argument and returns a \texttt{Map[Int, Int]}. The 
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  purpose of this Map is to record the information, in cases
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  a pc-position points to a '\texttt{[}' or a '\texttt{]}',
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  to which pc-position do we need to jump next?
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   389
 
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   390
  For example for the program
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   391
    
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  \begin{center}
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    \texttt{+++++[->++++++++++<]>--<+++[->>++++++++++}
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   394
    \texttt{<<]>>++<<----------[+>.>.<+<]}
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   395
  \end{center}
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   396
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   397
  we obtain the Map (note the precise numbers might differ depending on white
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   398
  spaces etc.~in the bf-program):
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   399
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   400
  \begin{center}
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   401
  \texttt{Map(69 -> 61, 5 -> 20, 60 -> 70, 27 -> 44, 43 -> 28, 19 -> 6)}
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   402
  \end{center}  
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diff changeset
   403
  
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   404
  This Map states that for the '\texttt{[}' on position 5, we need to
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   405
  jump to position 20, which is just after the corresponding '\texttt{]}'.
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   406
  Similarly, for the '\texttt{]}' on position 19, we need to jump to
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   407
  position 6, which is just after the '\texttt{[}' on position 5, and so
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   408
  on. The idea is to not calculate this information each time
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   409
  we hit a bracket, but just look up this information in the 
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   410
  \texttt{jtable}. 
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diff changeset
   411
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   412
  Then adapt the \texttt{compute} and \texttt{run} functions
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   413
  from Part 1 in order to take advantage of the information
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   414
  stored in the \texttt{jtable}. This means whenever \texttt{jumpLeft}
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diff changeset
   415
  and \texttt{jumpRight} was called previously, you should look
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   416
  up the jump address in the \texttt{jtable}. Feel free to reuse
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diff changeset
   417
  the function \texttt{jumpLeft} and \texttt{jumpRight} for
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   418
  calculating the \texttt{jtable}.\hfill{[1 Mark]}
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   419
237
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   420
\item[(6)] Compilers try to eliminate any ``dead'' code that could
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   421
  slow down programs and also perform what is often called
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   422
  \emph{peephole
db4d2fcd8063 updated
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   423
    optimisations}.\footnote{\url{https://en.wikipedia.org/wiki/Peephole_optimization}}
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   424
  For the latter consider that it is difficult for compilers to
241
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   425
  comprehend what is intended with whole programs, but they are very good
237
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   426
  at finding out what small snippets of code do, and then try to
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diff changeset
   427
  generate faster code for such snippets.
233
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diff changeset
   428
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diff changeset
   429
  In our case, dead code is everything that is not a bf-command.
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diff changeset
   430
  Therefore write a function \texttt{optimise} which deletes such
237
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diff changeset
   431
  dead code from a bf-program. Moreover this function should replace every substring
233
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diff changeset
   432
  of the form \pcode{[-]} by a new command \texttt{0}. 
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diff changeset
   433
  The idea is that the loop \pcode{[-]} just resets the
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diff changeset
   434
  memory at the current location to 0. It is more efficient
237
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   435
  to do this in a single step, rather than stepwise in a loop as in
233
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diff changeset
   436
  the original bf-programs.
218
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diff changeset
   437
233
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diff changeset
   438
  In the extended \texttt{compute3} and \texttt{run3} functions you should
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diff changeset
   439
  implement this command by writing 0 to \pcode{mem(mp)}, that is use
38ea26f227af updated
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diff changeset
   440
  \pcode{write(mem, mp, 0)} as the rule for the command \texttt{0}.
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diff changeset
   441
  The easiest way to modify a string in this way is to use the regular
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diff changeset
   442
  expression \pcode{"""[^<>+-.,\\[\\]]"""}, which recognises everything that is 
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diff changeset
   443
  not a bf-command. Similarly, the
237
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diff changeset
   444
  regular expression \pcode{"""\\[-\\]"""} finds all occurrences of \pcode{[-]}.  By using the Scala method \pcode{.replaceAll} you can replace substrings
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diff changeset
   445
  with new strings.\\
db4d2fcd8063 updated
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diff changeset
   446
  \mbox{}\hfill{[1 Mark]}
233
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diff changeset
   447
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diff changeset
   448
\item[(7)] Finally, real compilers try to take advantage of CPUs which often
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diff changeset
   449
  provide complex operations in hardware that can combine many smaller
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diff changeset
   450
  instructions into a single faster instruction.
38ea26f227af updated
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parents: 230
diff changeset
   451
237
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diff changeset
   452
  In our case we can optimise the several single increments performed at a
233
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diff changeset
   453
  memory cell, for example \pcode{++++}, by a single ``increment by
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   454
  4''. For this optimisation we just have to make sure these single
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   455
  increments are all next to each other. Similar optimisations should apply
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   456
  for the bf-commands \pcode{-}, \pcode{<} and
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   457
  \pcode{>}, which can all be replaced by extended versions that take
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   458
  the amount of the increment (decrement) into account. We will do
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   459
  this by introducing two-character bf-commands. For example
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   460
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   461
  \begin{center}
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    \begin{tabular}{l|l}
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      original bf-cmds & replacement\\
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      \hline
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      \pcode{+} & \pcode{+A}\\
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      \pcode{++} & \pcode{+B}\\
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      \pcode{+++} & \pcode{+C}\\
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      \ldots{} & \ldots{}\\
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      \pcode{+++....++} & \pcode{+Z}\\
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      \hspace{5mm}(these are 26 \pcode{+}'s)\\
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    \end{tabular} 
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   472
  \end{center}  
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   473
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   474
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   475
  If there are more
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  than 26 \pcode{+}'s in a row, then more than one ``two-character''
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  bf-commands need to be generated (the idea is that more than
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  26 copies of a single bf-command in a row is a rare occurrence in
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  actual bf-programs). Similar replacements apply
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   480
  for \pcode{-}, \pcode{<} and \pcode{>}, but
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  all other bf-commands should be unaffected by this
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  change. 
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   483
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   484
  For this write a function \texttt{combine} which replaces sequences
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   485
  of repeated increment and decrement commands by appropriate
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  two-character commands. In the functions \pcode{compute4} and
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  \pcode{run4}, the ``combine'' and the optimisation from (6) should
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   488
  be performed. Make sure that when a two-character bf-command is
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   489
  encountered you need to increase the \pcode{pc}-counter by two in
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  order to progress to the next command. For example
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   491
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   492
  \begin{center}
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  \pcode{combine(optimise(load_bff("benchmark.bf")))}  
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   494
  \end{center}  
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   495
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   496
  generates the improved program
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   497
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   498
  \begin{center}
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  \pcode{>A+B[<A+M>A-A]<A[[}\hspace{3mm}\ldots{}
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  \end{center}  
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   501
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   502
  for the original benchmark program
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diff changeset
   503
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   504
  \begin{center}
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   505
    \pcode{>++[<+++++++++++++>-]<[[}\hspace{3mm}\ldots
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   506
  \end{center}    
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   507
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   508
  As you can see, the compiler bets on saving a lot of time on the
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   509
  \pcode{+B} and \pcode{+M} steps so that the optimisations is
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   510
  worthwhile overall (of course for the \pcode{>A}'s and so on, the compiler incurs a
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   511
  penalty). Luckily, after you have performed all
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   512
  optimisations in (5) - (7), you can expect that the
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   513
  \pcode{benchmark.bf} program runs four to five times faster.
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   514
  You can also test whether your compiler produces the correct result
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  by for example testing
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   516
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   517
  \begin{center}
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   518
  \pcode{run(load_bff("sierpinski.bf")) == run4(load_bff("sierpinski.bf"))}
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   519
  \end{center}
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   520
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   521
  which should return true for all the different compiler stages. \\ 
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  \mbox{}\hfill{[2 Marks]}
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\end{itemize}  
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\end{document}
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%%% Local Variables: 
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%%% mode: latex
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%%% TeX-master: t
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%%% End: