Quot/Examples/IntEx.thy
author Cezary Kaliszyk <kaliszyk@in.tum.de>
Fri, 11 Dec 2009 11:08:58 +0100
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New syntax for definitions.
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theory IntEx
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imports "../QuotProd" "../QuotList"
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begin
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fun
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  intrel :: "(nat \<times> nat) \<Rightarrow> (nat \<times> nat) \<Rightarrow> bool" (infix "\<approx>" 50)
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where
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  "intrel (x, y) (u, v) = (x + v = u + y)"
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quotient my_int = "nat \<times> nat" / intrel
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  apply(unfold equivp_def)
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  apply(auto simp add: mem_def expand_fun_eq)
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  done
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thm quot_equiv
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thm quot_thm
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thm my_int_equivp
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print_theorems
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print_quotients
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quotient_def
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  "ZERO :: my_int"
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as
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  "(0::nat, 0::nat)"
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quotient_def
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  "ONE :: my_int"
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as
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  "(1::nat, 0::nat)"
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fun
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  my_plus :: "(nat \<times> nat) \<Rightarrow> (nat \<times> nat) \<Rightarrow> (nat \<times> nat)"
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where
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  "my_plus (x, y) (u, v) = (x + u, y + v)"
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quotient_def
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  "PLUS :: my_int \<Rightarrow> my_int \<Rightarrow> my_int"
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as
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  "my_plus"
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fun
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  my_neg :: "(nat \<times> nat) \<Rightarrow> (nat \<times> nat)"
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where
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  "my_neg (x, y) = (y, x)"
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quotient_def
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  "NEG :: my_int \<Rightarrow> my_int"
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as
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  "my_neg"
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definition
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  MINUS :: "my_int \<Rightarrow> my_int \<Rightarrow> my_int"
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where
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  "MINUS z w = PLUS z (NEG w)"
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fun
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  my_mult :: "(nat \<times> nat) \<Rightarrow> (nat \<times> nat) \<Rightarrow> (nat \<times> nat)"
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where
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  "my_mult (x, y) (u, v) = (x*u + y*v, x*v + y*u)"
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quotient_def
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  "MULT :: my_int \<Rightarrow> my_int \<Rightarrow> my_int"
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  "my_mult"
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(* NOT SURE WETHER THIS DEFINITION IS CORRECT *)
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fun
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  my_le :: "(nat \<times> nat) \<Rightarrow> (nat \<times> nat) \<Rightarrow> bool"
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where
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  "my_le (x, y) (u, v) = (x+v \<le> u+y)"
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quotient_def
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   "LE :: my_int \<Rightarrow> my_int \<Rightarrow> bool"
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as
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  "my_le"
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term LE
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thm LE_def
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definition
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  LESS :: "my_int \<Rightarrow> my_int \<Rightarrow> bool"
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where
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  "LESS z w = (LE z w \<and> z \<noteq> w)"
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term LESS
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thm LESS_def
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definition
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  ABS :: "my_int \<Rightarrow> my_int"
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where
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  "ABS i = (if (LESS i ZERO) then (NEG i) else i)"
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definition
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  SIGN :: "my_int \<Rightarrow> my_int"
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where
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 "SIGN i = (if i = ZERO then ZERO else if (LESS ZERO i) then ONE else (NEG ONE))"
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ML {* print_qconstinfo @{context} *}
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lemma plus_sym_pre:
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  shows "my_plus a b \<approx> my_plus b a"
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  apply(cases a)
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  apply(cases b)
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  apply(auto)
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  done
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lemma plus_rsp[quot_respect]:
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  shows "(intrel ===> intrel ===> intrel) my_plus my_plus"
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by (simp)
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lemma neg_rsp[quot_respect]:
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  shows "(op \<approx> ===> op \<approx>) my_neg my_neg"
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by simp
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lemma test1: "my_plus a b = my_plus a b"
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apply(rule refl)
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done
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lemma "PLUS a b = PLUS a b"
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apply(lifting_setup test1)
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apply(regularize)
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apply(injection)
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apply(cleaning)
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done
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thm lambda_prs
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lemma test2: "my_plus a = my_plus a"
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apply(rule refl)
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done
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lemma "PLUS a = PLUS a"
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apply(tactic {* procedure_tac @{context} @{thm test2} 1 *})
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apply(rule impI)
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apply(rule ballI)
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apply(rule apply_rsp[OF Quotient_my_int plus_rsp])
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apply(simp only: in_respects)
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apply(tactic {* all_inj_repabs_tac @{context} 1*})
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apply(tactic {* clean_tac @{context} 1 *})
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done
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lemma test3: "my_plus = my_plus"
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apply(rule refl)
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done
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lemma "PLUS = PLUS"
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apply(tactic {* procedure_tac @{context} @{thm test3} 1 *})
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apply(rule impI)
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apply(rule plus_rsp)
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apply(injection)
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apply(cleaning)
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done
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lemma "PLUS a b = PLUS b a"
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apply(tactic {* procedure_tac @{context} @{thm plus_sym_pre} 1 *})
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apply(tactic {* regularize_tac @{context} 1 *})
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apply(tactic {* all_inj_repabs_tac @{context} 1*})
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apply(tactic {* clean_tac @{context} 1 *})
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done
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lemma plus_assoc_pre:
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  shows "my_plus (my_plus i j) k \<approx> my_plus i (my_plus j k)"
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  apply (cases i)
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  apply (cases j)
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  apply (cases k)
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  apply (simp)
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  done
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lemma plus_assoc: "PLUS (PLUS x xa) xb = PLUS x (PLUS xa xb)"
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apply(tactic {* procedure_tac @{context} @{thm plus_assoc_pre} 1 *})
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apply(tactic {* regularize_tac @{context} 1 *})
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apply(tactic {* all_inj_repabs_tac @{context} 1*})
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apply(tactic {* clean_tac @{context} 1 *})
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done
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692
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lemma int_induct_raw:
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  assumes a: "P (0::nat, 0)"
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  and     b: "\<And>i. P i \<Longrightarrow> P (my_plus i (1,0))"
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  and     c: "\<And>i. P i \<Longrightarrow> P (my_plus i (my_neg (1,0)))"
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  shows      "P x"
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  apply(case_tac x) apply(simp)
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  apply(rule_tac x="b" in spec)
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  apply(rule_tac Nat.induct)
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  apply(rule allI)
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  apply(rule_tac Nat.induct)
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  using a b c apply(auto)
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  done
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lemma int_induct:
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  assumes a: "P ZERO"
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  and     b: "\<And>i. P i \<Longrightarrow> P (PLUS i ONE)"
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  and     c: "\<And>i. P i \<Longrightarrow> P (PLUS i (NEG ONE))"
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  shows      "P x"
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  using a b c
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  by (lifting int_induct_raw)
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lemma ho_tst: "foldl my_plus x [] = x"
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apply simp
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done
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lemma "foldl PLUS x [] = x"
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apply(lifting ho_tst)
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done
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lemma ho_tst2: "foldl my_plus x (h # t) \<approx> my_plus h (foldl my_plus x t)"
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sorry
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lemma "foldl PLUS x (h # t) = PLUS h (foldl PLUS x t)"
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apply(lifting_setup ho_tst2)
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apply(regularize)
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apply(injection)
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apply(cleaning)
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done
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lemma ho_tst3: "foldl f (s::nat \<times> nat) ([]::(nat \<times> nat) list) = s"
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by simp
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lemma "foldl f (x::my_int) ([]::my_int list) = x"
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apply(lifting ho_tst3)
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done
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lemma lam_tst: "(\<lambda>x. (x, x)) y = (y, (y :: nat \<times> nat))"
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by simp
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(* Don't know how to keep the goal non-contracted... *)
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lemma "(\<lambda>x. (x, x)) (y::my_int) = (y, y)"
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apply(lifting lam_tst)
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done
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lemma lam_tst2: "(\<lambda>(y :: nat \<times> nat). y) = (\<lambda>(x :: nat \<times> nat). x)"
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by simp
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(* test about lifting identity equations *)
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ML {*
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(* helper code from QuotMain *)
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val pat_ball = @{term "Ball (Respects (R1 ===> R2)) P"}
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val pat_bex  = @{term "Bex (Respects (R1 ===> R2)) P"}
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val simproc = Simplifier.simproc_i @{theory} "" [pat_ball, pat_bex] (K (ball_bex_range_simproc))
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val simpset = (mk_minimal_ss @{context}) 
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                       addsimps @{thms ball_reg_eqv bex_reg_eqv babs_reg_eqv}
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                       addsimprocs [simproc] addSolver equiv_solver
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*}
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(* What regularising does *)
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(*========================*)
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(* 0. preliminary simplification step *)
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thm ball_reg_eqv bex_reg_eqv (* of no use: babs_reg_eqv *)
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    ball_reg_eqv_range bex_reg_eqv_range
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(* 1. first two rtacs *)
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thm ball_reg_right bex_reg_left
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(* 2. monos *)
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(* 3. commutation rules *)
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thm ball_all_comm bex_ex_comm
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(* 4. then rel-equality *)
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thm eq_imp_rel
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(* 5. then simplification like 0 *)
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(* finally jump to 1 *)
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(* What cleaning does *)
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(*====================*)
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(* 1. conversion *)
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thm lambda_prs
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(* 2. simplification with *)
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thm all_prs ex_prs
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(* 3. Simplification with *)
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thm fun_map.simps id_simps Quotient_abs_rep Quotient_rel_rep
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(* 4. Test for refl *)
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lemma
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  shows "equivp (op \<approx>)"
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df7a2f76daae Nitpick found a counterexample for one lemma.
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  and "equivp ((op \<approx>) ===> (op \<approx>))"
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(* Nitpick finds a counterexample! *)
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oops
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lemma lam_tst3a: "(\<lambda>(y :: nat \<times> nat). y) = (\<lambda>(x :: nat \<times> nat). x)"
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by auto
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620
a98b136fc88a It also regularizes.
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lemma id_rsp:
a98b136fc88a It also regularizes.
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  shows "(R ===> R) id id"
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by simp
a98b136fc88a It also regularizes.
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a98b136fc88a It also regularizes.
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lemma lam_tst3a_reg: "(op \<approx> ===> op \<approx>) (Babs (Respects op \<approx>) (\<lambda>y. y)) (Babs (Respects op \<approx>) (\<lambda>x. x))"
a98b136fc88a It also regularizes.
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apply (rule babs_rsp[OF Quotient_my_int])
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apply (simp add: id_rsp)
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done
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lemma "(\<lambda>(y :: my_int). y) = (\<lambda>(x :: my_int). x)"
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apply(tactic {* procedure_tac @{context} @{thm lam_tst3a} 1 *})
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apply(rule impI)
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apply(rule lam_tst3a_reg)
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2bee5ca44ef5 removed "global" data and lookup functions; had to move a tactic out from the inj_repabs_match tactic since apply_rsp interferes with a trans2 rule for ===>
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apply(tactic {* all_inj_repabs_tac @{context} 1*})
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e56eeb9fedb3 make_inst for lambda_prs where the second quotient is not identity.
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apply(tactic {* clean_tac  @{context} 1 *})
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done
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lemma lam_tst3b: "(\<lambda>(y :: nat \<times> nat \<Rightarrow> nat \<times> nat). y) = (\<lambda>(x :: nat \<times> nat \<Rightarrow> nat \<times> nat). x)"
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by auto
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lemma "(\<lambda>(y :: my_int => my_int). y) = (\<lambda>(x :: my_int => my_int). x)"
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apply(lifting lam_tst3b)
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apply(rule impI)
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apply(rule babs_rsp[OF fun_quotient[OF Quotient_my_int Quotient_my_int]])
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apply(simp add: id_rsp)
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done
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term map
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lemma lam_tst4: "map (\<lambda>x. my_plus x (0,0)) l = l"
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apply (induct l)
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apply simp
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apply (case_tac a)
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apply simp
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done
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lemma "map (\<lambda>x. PLUS x ZERO) l = l"
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apply(lifting lam_tst4)
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c86a47d4966e Temporarily repeated fun_map_tac 4 times. Cleaning for all examples work.
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done
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end