author | Christian Urban <urbanc@in.tum.de> |
Mon, 08 Jul 2019 11:10:32 +0100 | |
changeset 70 | cab5eab1f6f1 |
parent 69 | 4c7173b7ddca |
child 71 | 0573615e41a3 |
permissions | -rw-r--r-- |
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\documentclass[a4paper,UKenglish]{lipics} |
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\usepackage{graphic} |
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\usepackage{data} |
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\usepackage{tikz-cd} |
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%\usepackage{algorithm} |
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\usepackage{amsmath} |
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\usepackage[noend]{algpseudocode} |
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\usepackage{enumitem} |
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\usepackage{nccmath} |
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\definecolor{darkblue}{rgb}{0,0,0.6} |
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\hypersetup{colorlinks=true,allcolors=darkblue} |
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\newcommand{\comment}[1]% |
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{{\color{red}$\Rightarrow$}\marginpar{\raggedright\small{\bf\color{red}#1}}} |
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||
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% \documentclass{article} |
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%\usepackage[utf8]{inputenc} |
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%\usepackage[english]{babel} |
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%\usepackage{listings} |
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% \usepackage{amsthm} |
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%\usepackage{hyperref} |
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% \usepackage[margin=0.5in]{geometry} |
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%\usepackage{pmboxdraw} |
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||
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\title{POSIX Regular Expression Matching and Lexing} |
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\author{Chengsong Tan} |
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\affil{King's College London\\ |
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London, UK\\ |
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\texttt{chengsong.tan@kcl.ac.uk}} |
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\authorrunning{Chengsong Tan} |
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\Copyright{Chengsong Tan} |
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||
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\newcommand{\dn}{\stackrel{\mbox{\scriptsize def}}{=}}% |
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\newcommand{\ZERO}{\mbox{\bf 0}} |
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\newcommand{\ONE}{\mbox{\bf 1}} |
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\def\lexer{\mathit{lexer}} |
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\def\mkeps{\mathit{mkeps}} |
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\def\inj{\mathit{inj}} |
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\def\Empty{\mathit{Empty}} |
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\def\Left{\mathit{Left}} |
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\def\Right{\mathit{Right}} |
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\def\Stars{\mathit{Stars}} |
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\def\Char{\mathit{Char}} |
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\def\Seq{\mathit{Seq}} |
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\def\Der{\mathit{Der}} |
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\def\nullable{\mathit{nullable}} |
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\def\Z{\mathit{Z}} |
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\def\S{\mathit{S}} |
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||
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%\theoremstyle{theorem} |
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%\newtheorem{theorem}{Theorem} |
|
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%\theoremstyle{lemma} |
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%\newtheorem{lemma}{Lemma} |
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%\newcommand{\lemmaautorefname}{Lemma} |
|
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%\theoremstyle{definition} |
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%\newtheorem{definition}{Definition} |
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\algnewcommand\algorithmicswitch{\textbf{switch}} |
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\algnewcommand\algorithmiccase{\textbf{case}} |
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\algnewcommand\algorithmicassert{\texttt{assert}} |
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\algnewcommand\Assert[1]{\State \algorithmicassert(#1)}% |
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% New "environments" |
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\algdef{SE}[SWITCH]{Switch}{EndSwitch}[1]{\algorithmicswitch\ #1\ \algorithmicdo}{\algorithmicend\ \algorithmicswitch}% |
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\algdef{SE}[CASE]{Case}{EndCase}[1]{\algorithmiccase\ #1}{\algorithmicend\ \algorithmiccase}% |
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\algtext*{EndSwitch}% |
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\algtext*{EndCase}% |
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||
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\begin{document} |
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||
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\maketitle |
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||
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\begin{abstract} |
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Brzozowski introduced in 1964 a beautifully simple algorithm for |
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regular expression matching based on the notion of derivatives of |
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regular expressions. In 2014, Sulzmann and Lu extended this |
|
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algorithm to not just give a YES/NO answer for whether or not a |
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regular expression matches a string, but in case it does also |
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answers with \emph{how} it matches the string. This is important for |
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applications such as lexing (tokenising a string). The problem is to |
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make the algorithm by Sulzmann and Lu fast on all inputs without |
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breaking its correctness. We have already developed some |
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simplification rules for this, but have not yet proved that they |
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preserve the correctness of the algorithm. We also have not yet |
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looked at extended regular expressions, such as bounded repetitions, |
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negation and back-references. |
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\end{abstract} |
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||
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\section{Introduction} |
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||
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This PhD-project is about regular expression matching and |
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lexing. Given the maturity of this topic, the reader might wonder: |
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Surely, regular expressions must have already been studied to death? |
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What could possibly be \emph{not} known in this area? And surely all |
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implemented algorithms for regular expression matching are blindingly |
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fast? |
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||
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Unfortunately these preconceptions are not supported by evidence: Take |
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for example the regular expression $(a^*)^*\,b$ and ask whether |
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strings of the form $aa..a$ match this regular |
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expression. Obviously not---the expected $b$ in the last |
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position is missing. One would expect that modern regular expression |
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matching engines can find this out very quickly. Alas, if one tries |
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this example in JavaScript, Python or Java 8 with strings like 28 |
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$a$'s, one discovers that this decision takes around 30 seconds and |
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takes considerably longer when adding a few more $a$'s, as the graphs |
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below show: |
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||
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\begin{center} |
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\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}} |
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\begin{tikzpicture} |
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\begin{axis}[ |
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xlabel={$n$}, |
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x label style={at={(1.05,-0.05)}}, |
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ylabel={time in secs}, |
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enlargelimits=false, |
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xtick={0,5,...,30}, |
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xmax=33, |
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ymax=35, |
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ytick={0,5,...,30}, |
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scaled ticks=false, |
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axis lines=left, |
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width=5cm, |
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height=4cm, |
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legend entries={JavaScript}, |
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legend pos=north west, |
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legend cell align=left] |
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\addplot[red,mark=*, mark options={fill=white}] table {re-js.data}; |
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\end{axis} |
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\end{tikzpicture} |
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& |
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\begin{tikzpicture} |
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\begin{axis}[ |
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xlabel={$n$}, |
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x label style={at={(1.05,-0.05)}}, |
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%ylabel={time in secs}, |
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enlargelimits=false, |
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xtick={0,5,...,30}, |
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xmax=33, |
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ymax=35, |
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ytick={0,5,...,30}, |
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scaled ticks=false, |
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axis lines=left, |
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width=5cm, |
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height=4cm, |
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legend entries={Python}, |
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legend pos=north west, |
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legend cell align=left] |
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\addplot[blue,mark=*, mark options={fill=white}] table {re-python2.data}; |
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\end{axis} |
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\end{tikzpicture} |
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& |
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\begin{tikzpicture} |
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\begin{axis}[ |
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xlabel={$n$}, |
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x label style={at={(1.05,-0.05)}}, |
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%ylabel={time in secs}, |
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enlargelimits=false, |
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xtick={0,5,...,30}, |
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xmax=33, |
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ymax=35, |
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ytick={0,5,...,30}, |
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scaled ticks=false, |
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axis lines=left, |
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width=5cm, |
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height=4cm, |
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legend entries={Java 8}, |
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legend pos=north west, |
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legend cell align=left] |
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\addplot[cyan,mark=*, mark options={fill=white}] table {re-java.data}; |
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\end{axis} |
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\end{tikzpicture}\\ |
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\multicolumn{3}{c}{Graphs: Runtime for matching $(a^*)^*\,b$ with strings |
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of the form $\underbrace{aa..a}_{n}$.} |
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\end{tabular} |
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\end{center} |
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||
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\noindent These are clearly abysmal and possibly surprising results. One |
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would expect these systems to do much better than that---after all, |
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given a DFA and a string, deciding whether a string is matched by this |
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DFA should be linear. |
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Admittedly, the regular expression $(a^*)^*\,b$ is carefully chosen to |
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exhibit this exponential behaviour. Unfortunately, such regular |
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expressions are not just a few outliers. They are actually |
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frequent enough to have a separate name created for |
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them---\emph{evil regular expressions}. In empiric work, Davis et al |
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report that they have found thousands of such evil regular expressions |
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in the JavaScript and Python ecosystems \cite{Davis18}. |
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||
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This exponential blowup in matching algorithms sometimes causes |
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considerable grief in real life: for example on 20 July 2016 one evil |
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regular expression brought the webpage |
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\href{http://stackexchange.com}{Stack Exchange} to its |
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knees.\footnote{\url{https://stackstatus.net/post/147710624694/outage-postmortem-july-20-2016}} |
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In this instance, a regular expression intended to just trim white |
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spaces from the beginning and the end of a line actually consumed |
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massive amounts of CPU-resources---causing web servers to |
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grind to a halt. This happened when a post with 20,000 white spaces was |
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submitted, but importantly the white spaces were neither at the |
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beginning nor at the end. As a result, the regular expression matching |
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engine needed to backtrack over many choices. The underlying problem is |
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that many ``real life'' regular expression matching engines do not use |
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DFAs for matching. This is because they support regular expressions that |
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are not covered by the classical automata theory, and in this more |
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general setting there are quite a few research questions still |
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unanswered and fast algorithms still need to be developed (for example |
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how to treat bounded repetitions, negation and back-references |
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efficiently). |
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%question: dfa can have exponential states. isn't this the actual reason why they do not use dfas? |
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%how do they avoid dfas exponential states if they use them for fast matching? |
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There is also another under-researched problem to do with regular |
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expressions and lexing, i.e.~the process of breaking up strings into |
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sequences of tokens according to some regular expressions. In this |
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setting one is not just interested in whether or not a regular |
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expression matches a string, but also in \emph{how}. Consider for example a regular expression |
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$r_{key}$ for recognising keywords such as \textit{if}, \textit{then} |
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and so on; and a regular expression $r_{id}$ for recognising |
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identifiers (say, a single character followed by characters or |
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numbers). One can then form the compound regular expression |
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$(r_{key} + r_{id})^*$ and use it to tokenise strings. But then how |
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should the string \textit{iffoo} be tokenised? It could be tokenised |
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as a keyword followed by an identifier, or the entire string as a |
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single identifier. Similarly, how should the string \textit{if} be |
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tokenised? Both regular expressions, $r_{key}$ and $r_{id}$, would |
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``fire''---so is it an identifier or a keyword? While in applications |
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there is a well-known strategy to decide these questions, called POSIX |
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matching, only relatively recently precise definitions of what POSIX |
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matching actually means has been formalised |
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\cite{AusafDyckhoffUrban2016,OkuiSuzuki2010,Vansummeren2006}. |
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Such a definition has also been given by Sulzmann and Lu \cite{Sulzmann2014}, but the |
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corresponding correctness proof turned out to be faulty \cite{AusafDyckhoffUrban2016}. |
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Roughly, POSIX matching means matching the longest initial substring. |
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In the case of a tie, the initial sub-match is chosen according to some priorities attached to the |
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regular expressions (e.g.~keywords have a higher priority than |
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identifiers). This sounds rather simple, but according to Grathwohl et |
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al \cite[Page 36]{CrashCourse2014} this is not the case. They wrote: |
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||
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\begin{quote} |
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\it{}``The POSIX strategy is more complicated than the greedy because of |
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the dependence on information about the length of matched strings in the |
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various subexpressions.'' |
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\end{quote} |
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||
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\noindent |
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This is also supported by evidence collected by Kuklewicz |
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\cite{Kuklewicz} who noticed that a number of POSIX regular expression |
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matchers calculate incorrect results. |
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Our focus is on an algorithm introduced by Sulzmann and Lu in 2014 for |
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regular expression matching according to the POSIX strategy |
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\cite{Sulzmann2014}. Their algorithm is based on an older algorithm by |
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Brzozowski from 1964 where he introduced the notion of derivatives of |
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regular expressions \cite{Brzozowski1964}. We shall briefly explain |
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this algorithm next. |
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\section{The Algorithm by Brzozowski based on Derivatives of Regular |
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Expressions} |
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Suppose (basic) regular expressions are given by the following grammar: |
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\[ r ::= \ZERO \mid \ONE |
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\mid c |
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\mid r_1 \cdot r_2 |
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\mid r_1 + r_2 |
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\mid r^* |
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\] |
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\noindent |
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The intended meaning of the constructors is as follows: $\ZERO$ |
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cannot match any string, $\ONE$ can match the empty string, the |
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character regular expression $c$ can match the character $c$, and so |
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on. |
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||
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The ingenious contribution by Brzozowski is the notion of |
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\emph{derivatives} of regular expressions. The idea behind this |
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notion is as follows: suppose a regular expression $r$ can match a |
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string of the form $c\!::\! s$ (that is a list of characters starting |
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with $c$), what does the regular expression look like that can match |
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just $s$? Brzozowski gave a neat answer to this question. He started |
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with the definition of $nullable$: |
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\begin{center} |
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\begin{tabular}{lcl} |
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$\nullable(\ZERO)$ & $\dn$ & $\mathit{false}$ \\ |
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$\nullable(\ONE)$ & $\dn$ & $\mathit{true}$ \\ |
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$\nullable(c)$ & $\dn$ & $\mathit{false}$ \\ |
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$\nullable(r_1 + r_2)$ & $\dn$ & $\nullable(r_1) \vee \nullable(r_2)$ \\ |
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$\nullable(r_1\cdot r_2)$ & $\dn$ & $\nullable(r_1) \wedge \nullable(r_2)$ \\ |
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$\nullable(r^*)$ & $\dn$ & $\mathit{true}$ \\ |
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\end{tabular} |
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\end{center} |
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This function simply tests whether the empty string is in $L(r)$. |
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He then defined |
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the following operation on regular expressions, written |
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$r\backslash c$ (the derivative of $r$ w.r.t.~the character $c$): |
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||
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\begin{center} |
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\begin{tabular}{lcl} |
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$\ZERO \backslash c$ & $\dn$ & $\ZERO$\\ |
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$\ONE \backslash c$ & $\dn$ & $\ZERO$\\ |
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$d \backslash c$ & $\dn$ & |
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$\mathit{if} \;c = d\;\mathit{then}\;\ONE\;\mathit{else}\;\ZERO$\\ |
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$(r_1 + r_2)\backslash c$ & $\dn$ & $r_1 \backslash c \,+\, r_2 \backslash c$\\ |
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$(r_1 \cdot r_2)\backslash c$ & $\dn$ & $\mathit{if} \, nullable(r_1)$\\ |
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& & $\mathit{then}\;(r_1\backslash c) \cdot r_2 \,+\, r_2\backslash c$\\ |
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& & $\mathit{else}\;(r_1\backslash c) \cdot r_2$\\ |
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$(r^*)\backslash c$ & $\dn$ & $(r\backslash c) \cdot r^*$\\ |
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\end{tabular} |
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\end{center} |
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||
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%Assuming the classic notion of a |
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%\emph{language} of a regular expression, written $L(\_)$, t |
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\noindent |
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The main property of the derivative operation is that |
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\begin{center} |
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$c\!::\!s \in L(r)$ holds |
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if and only if $s \in L(r\backslash c)$. |
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\end{center} |
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||
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\noindent |
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For us the main advantage is that derivatives can be |
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straightforwardly implemented in any functional programming language, |
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and are easily definable and reasoned about in theorem provers---the |
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definitions just consist of inductive datatypes and simple recursive |
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functions. Moreover, the notion of derivatives can be easily |
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generalised to cover extended regular expression constructors such as |
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the not-regular expression, written $\neg\,r$, or bounded repetitions |
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(for example $r^{\{n\}}$ and $r^{\{n..m\}}$), which cannot be so |
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straightforwardly realised within the classic automata approach. |
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For the moment however, we focus only on the usual basic regular expressions. |
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||
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||
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Now if we want to find out whether a string $s$ matches with a regular |
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expression $r$, build the derivatives of $r$ w.r.t.\ (in succession) |
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all the characters of the string $s$. Finally, test whether the |
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resulting regular expression can match the empty string. If yes, then |
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$r$ matches $s$, and no in the negative case. To implement this idea |
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we can generalise the derivative operation to strings like this: |
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|
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\begin{center} |
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\begin{tabular}{lcl} |
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$r \backslash (c\!::\!s) $ & $\dn$ & $(r \backslash c) \backslash s$ \\ |
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$r \backslash [\,] $ & $\dn$ & $r$ |
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\end{tabular} |
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\end{center} |
|
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|
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\noindent |
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and then define as regular-expression matching algorithm: |
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\[ |
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match\;s\;r \;\dn\; nullable(r\backslash s) |
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\] |
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|
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\noindent |
|
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This algorithm looks graphically as follows: |
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\begin{equation}\label{graph:*} |
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\begin{tikzcd} |
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r_0 \arrow[r, "\backslash c_0"] & r_1 \arrow[r, "\backslash c_1"] & r_2 \arrow[r, dashed] & r_n \arrow[r,"\textit{nullable}?"] & \;\textrm{YES}/\textrm{NO} |
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\end{tikzcd} |
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\end{equation} |
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|
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\noindent |
|
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where we start with a regular expression $r_0$, build successive |
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derivatives until we exhaust the string and then use \textit{nullable} |
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to test whether the result can match the empty string. It can be |
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relatively easily shown that this matcher is correct (that is given |
|
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an $s = c_0...c_{n-1}$ and an $r_0$, it generates YES if and only if $s \in L(r_0)$). |
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|
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||
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\section{Values and the Algorithm by Sulzmann and Lu} |
|
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|
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One limitation, however, of Brzozowski's algorithm is that it only |
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produces a YES/NO answer for whether a string is being matched by a |
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regular expression. Sulzmann and Lu~\cite{Sulzmann2014} extended this |
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algorithm to allow generation of an actual matching, called a |
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\emph{value}. Values and regular expressions correspond to each |
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other as illustrated in the following table: |
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||
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|
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\begin{center} |
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\begin{tabular}{c@{\hspace{20mm}}c} |
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\begin{tabular}{@{}rrl@{}} |
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\multicolumn{3}{@{}l}{\textbf{Regular Expressions}}\medskip\\ |
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$r$ & $::=$ & $\ZERO$\\ |
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& $\mid$ & $\ONE$ \\ |
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& $\mid$ & $c$ \\ |
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& $\mid$ & $r_1 \cdot r_2$\\ |
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& $\mid$ & $r_1 + r_2$ \\ |
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\\ |
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& $\mid$ & $r^*$ \\ |
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\end{tabular} |
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& |
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\begin{tabular}{@{\hspace{0mm}}rrl@{}} |
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\multicolumn{3}{@{}l}{\textbf{Values}}\medskip\\ |
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$v$ & $::=$ & \\ |
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& & $\Empty$ \\ |
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& $\mid$ & $\Char(c)$ \\ |
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& $\mid$ & $\Seq\,v_1\, v_2$\\ |
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& $\mid$ & $\Left(v)$ \\ |
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& $\mid$ & $\Right(v)$ \\ |
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& $\mid$ & $\Stars\,[v_1,\ldots\,v_n]$ \\ |
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\end{tabular} |
|
403 |
\end{tabular} |
|
404 |
\end{center} |
|
405 |
||
406 |
\noindent |
|
64 | 407 |
No value corresponds to $\ZERO$; $\Empty$ corresponds to |
63 | 408 |
$\ONE$; $\Char$ to the character regular expression; $\Seq$ to the |
409 |
sequence regular expression and so on. The idea of values is to encode |
|
64 | 410 |
parse trees for how the sub-parts of a regular expression matches |
411 |
the sub-parts of a string. To see this, suppose a \emph{flatten} operation, written |
|
63 | 412 |
$|v|$. We use this function to extract the underlying string of a value |
413 |
$v$. For example, $|\mathit{Seq} \, (\textit{Char x}) \, (\textit{Char |
|
414 |
y})|$ is the string $xy$. Using flatten, we can describe how values |
|
64 | 415 |
encode parse trees: $\Seq\,v_1\, v_2$ encodes a tree with 2 children nodes |
416 |
that tells how the string $|v_1| @ |
|
63 | 417 |
|v_2|$ matches the regex $r_1 \cdot r_2$ whereby $r_1$ matches the |
418 |
substring $|v_1|$ and, respectively, $r_2$ matches the substring |
|
419 |
$|v_2|$. Exactly how these two are matched is contained in the |
|
64 | 420 |
children nodes $v_1$ and $v_2$ of parent $\textit{Seq}$ . |
30 | 421 |
|
59 | 422 |
To give a concrete example of how value works, consider the string $xy$ |
46 | 423 |
and the regular expression $(x + (y + xy))^*$. We can view this regular |
30 | 424 |
expression as a tree and if the string $xy$ is matched by two Star |
46 | 425 |
``iterations'', then the $x$ is matched by the left-most alternative in |
426 |
this tree and the $y$ by the right-left alternative. This suggests to |
|
427 |
record this matching as |
|
30 | 428 |
|
429 |
\begin{center} |
|
430 |
$\Stars\,[\Left\,(\Char\,x), \Right(\Left(\Char\,y))]$ |
|
431 |
\end{center} |
|
432 |
||
433 |
\noindent |
|
64 | 434 |
where $\Stars [\ldots]$ records all the |
435 |
iterations; and $\Left$, respectively $\Right$, which |
|
30 | 436 |
alternative is used. The value for |
437 |
matching $xy$ in a single ``iteration'', i.e.~the POSIX value, |
|
438 |
would look as follows |
|
439 |
||
440 |
\begin{center} |
|
441 |
$\Stars\,[\Seq\,(\Char\,x)\,(\Char\,y)]$ |
|
442 |
\end{center} |
|
443 |
||
444 |
\noindent |
|
445 |
where $\Stars$ has only a single-element list for the single iteration |
|
446 |
and $\Seq$ indicates that $xy$ is matched by a sequence regular |
|
447 |
expression. |
|
448 |
||
449 |
The contribution of Sulzmann and Lu is an extension of Brzozowski's |
|
450 |
algorithm by a second phase (the first phase being building successive |
|
46 | 451 |
derivatives---see \eqref{graph:*}). In this second phase, a POSIX value |
452 |
is generated assuming the regular expression matches the string. |
|
54 | 453 |
Pictorially, the algorithm is as follows: |
46 | 454 |
|
70 | 455 |
\begin{ceqn} |
59 | 456 |
\begin{equation}\label{graph:2} |
30 | 457 |
\begin{tikzcd} |
36 | 458 |
r_0 \arrow[r, "\backslash c_0"] \arrow[d] & r_1 \arrow[r, "\backslash c_1"] \arrow[d] & r_2 \arrow[r, dashed] \arrow[d] & r_n \arrow[d, "mkeps" description] \\ |
30 | 459 |
v_0 & v_1 \arrow[l,"inj_{r_0} c_0"] & v_2 \arrow[l, "inj_{r_1} c_1"] & v_n \arrow[l, dashed] |
460 |
\end{tikzcd} |
|
59 | 461 |
\end{equation} |
70 | 462 |
\end{ceqn} |
37 | 463 |
|
46 | 464 |
\noindent |
59 | 465 |
For convenience, we shall employ the following notations: the regular expression we |
58 | 466 |
start with is $r_0$, and the given string $s$ is composed of characters $c_0 c_1 |
64 | 467 |
\ldots c_{n-1}$. In the first phase, we build the derivatives $r_1$, $r_2$, \ldots according to |
46 | 468 |
the characters $c_0$, $c_1$,\ldots until we exhaust the string and |
58 | 469 |
obtain at the derivative $r_n$. We test whether this derivative is |
46 | 470 |
$\textit{nullable}$ or not. If not, we know the string does not match |
471 |
$r$ and no value needs to be generated. If yes, we start building the |
|
472 |
parse tree incrementally by \emph{injecting} back the characters into |
|
58 | 473 |
the values $v_n, \ldots, v_0$. For this we first call the function |
46 | 474 |
$\textit{mkeps}$, which builds the parse tree for how the empty string |
58 | 475 |
has matched the (nullable) regular expression $r_n$. This function is defined |
46 | 476 |
as |
30 | 477 |
|
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|
478 |
\begin{center} |
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|
479 |
\begin{tabular}{lcl} |
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|
480 |
$\mkeps(\ONE)$ & $\dn$ & $\Empty$ \\ |
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481 |
$\mkeps(r_{1}+r_{2})$ & $\dn$ |
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|
482 |
& \textit{if} $\nullable(r_{1})$\\ |
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|
483 |
& & \textit{then} $\Left(\mkeps(r_{1}))$\\ |
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|
484 |
& & \textit{else} $\Right(\mkeps(r_{2}))$\\ |
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485 |
$\mkeps(r_1\cdot r_2)$ & $\dn$ & $\Seq\,(\mkeps\,r_1)\,(\mkeps\,r_2)$\\ |
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486 |
$mkeps(r^*)$ & $\dn$ & $\Stars\,[]$ |
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|
487 |
\end{tabular} |
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488 |
\end{center} |
41 | 489 |
|
59 | 490 |
|
491 |
\noindent There are no cases for $\ZERO$ and $c$, since |
|
492 |
these regular expression cannot match the empty string. Note |
|
493 |
also that in case of alternatives we give preference to the |
|
494 |
regular expression on the left-hand side. This will become |
|
495 |
important later on. |
|
496 |
||
497 |
After this, we inject back the characters one by one in order to build |
|
63 | 498 |
the parse tree $v_i$ for how the regex $r_i$ matches the string $s_i$ |
64 | 499 |
($s_i = c_i \ldots c_{n-1}$ ) from the previous parse tree $v_{i+1}$. After |
63 | 500 |
injecting back $n$ characters, we get the parse tree for how $r_0$ |
501 |
matches $s$. For this Sulzmann and Lu defined a function that reverses |
|
502 |
the ``chopping off'' of characters during the derivative phase. The |
|
503 |
corresponding function is called $\textit{inj}$; it takes three |
|
504 |
arguments: the first one is a regular expression ${r_{i-1}}$, before the |
|
505 |
character is chopped off, the second is a character ${c_{i-1}}$, the |
|
506 |
character we want to inject and the third argument is the value |
|
64 | 507 |
${v_i}$, into which one wants to inject the character (it |
63 | 508 |
corresponds to the regular expression after the character has been |
509 |
chopped off). The result of this function is a new value. The definition |
|
510 |
of $\textit{inj}$ is as follows: |
|
59 | 511 |
|
512 |
\begin{center} |
|
513 |
\begin{tabular}{l@{\hspace{1mm}}c@{\hspace{1mm}}l} |
|
514 |
$\textit{inj}\,(c)\,c\,Empty$ & $\dn$ & $Char\,c$\\ |
|
515 |
$\textit{inj}\,(r_1 + r_2)\,c\,\Left(v)$ & $\dn$ & $\Left(\textit{inj}\,r_1\,c\,v)$\\ |
|
516 |
$\textit{inj}\,(r_1 + r_2)\,c\,Right(v)$ & $\dn$ & $Right(\textit{inj}\,r_2\,c\,v)$\\ |
|
517 |
$\textit{inj}\,(r_1 \cdot r_2)\,c\,Seq(v_1,v_2)$ & $\dn$ & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\ |
|
518 |
$\textit{inj}\,(r_1 \cdot r_2)\,c\,\Left(Seq(v_1,v_2))$ & $\dn$ & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\ |
|
519 |
$\textit{inj}\,(r_1 \cdot r_2)\,c\,Right(v)$ & $\dn$ & $Seq(\textit{mkeps}(r_1),\textit{inj}\,r_2\,c\,v)$\\ |
|
520 |
$\textit{inj}\,(r^*)\,c\,Seq(v,Stars\,vs)$ & $\dn$ & $Stars((\textit{inj}\,r\,c\,v)\,::\,vs)$\\ |
|
521 |
\end{tabular} |
|
522 |
\end{center} |
|
523 |
||
63 | 524 |
\noindent This definition is by recursion on the ``shape'' of regular |
525 |
expressions and values. To understands this definition better consider |
|
526 |
the situation when we build the derivative on regular expression $r_{i-1}$. |
|
527 |
For this we chop off a character from $r_{i-1}$ to form $r_i$. This leaves a |
|
64 | 528 |
``hole'' in $r_i$ and its corresponding value $v_i$ |
529 |
. To calculate $v_{i-1}$, we need to |
|
530 |
locate where that hole is and fill it. |
|
531 |
We can find this location by |
|
63 | 532 |
comparing $r_{i-1}$ and $v_i$. For instance, if $r_{i-1}$ is of shape |
64 | 533 |
$r_a \cdot r_b$, and $v_i$ is of shape $\Left(Seq(v_1,v_2))$, we know immediately that |
63 | 534 |
% |
535 |
\[ (r_a \cdot r_b)\backslash c = (r_a\backslash c) \cdot r_b \,+\, r_b\backslash c,\] |
|
536 |
||
537 |
\noindent |
|
59 | 538 |
otherwise if $r_a$ is not nullable, |
63 | 539 |
\[ (r_a \cdot r_b)\backslash c = (r_a\backslash c) \cdot r_b,\] |
540 |
||
541 |
\noindent |
|
64 | 542 |
the value $v_i$ should be $\Seq(\ldots)$, contradicting the fact that |
543 |
$v_i$ is actually of shape $\Left(\ldots)$. Furthermore, since $v_i$ is of shape |
|
63 | 544 |
$\Left(\ldots)$ instead of $\Right(\ldots)$, we know that the left |
64 | 545 |
branch of \[ (r_a \cdot r_b)\backslash c = |
546 |
\bold{\underline{ (r_a\backslash c) \cdot r_b} }\,+\, r_b\backslash c,\](underlined) |
|
547 |
is taken instead of the right one. This means $c$ is chopped off |
|
548 |
from $r_a$ rather than $r_b$. |
|
549 |
We have therefore found out |
|
63 | 550 |
that the hole will be on $r_a$. So we recursively call $\inj\, |
64 | 551 |
r_a\,c\,v_a$ to fill that hole in $v_a$. After injection, the value |
63 | 552 |
$v_i$ for $r_i = r_a \cdot r_b$ should be $\Seq\,(\inj\,r_a\,c\,v_a)\,v_b$. |
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553 |
Other clauses can be understood in a similar way. |
59 | 554 |
|
70 | 555 |
The following example gives a \comment{Other word: insight?}taste of $\textit{inj}$'s effect |
65 | 556 |
and how Sulzmann and Lu's algorithm works as a whole. |
557 |
Suppose we have a |
|
558 |
regular expression $((((a+b)+ab)+c)+abc)^*$, and want to match it against |
|
63 | 559 |
the string $abc$ (when $abc$ is written as a regular expression, the most |
560 |
standard way of expressing it should be $a \cdot (b \cdot c)$. We omit |
|
65 | 561 |
the parentheses and dots here for readability). |
562 |
This algorithm returns a POSIX value, which means it |
|
563 |
will go for the longest matching, i.e.~it should match the string |
|
564 |
$abc$ in one star iteration, using the longest alternative $abc$ in the |
|
565 |
sub-expression $((((a+b)+ab)+c)+abc)$ (we use $r$ to denote this sub-expression |
|
64 | 566 |
for conciseness). |
65 | 567 |
Before $\textit{inj}$ comes into play, |
568 |
our lexer first builds derivative using string $abc$ (we simplified some regular expressions like |
|
569 |
$0 \cdot b$ to $0$ for conciseness; we also omit parentheses if |
|
63 | 570 |
they are clear from the context): |
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|
571 |
%Similarly, we allow |
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|
572 |
%$\textit{ALT}$ to take a list of regular expressions as an argument |
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|
573 |
%instead of just 2 operands to reduce the nested depth of |
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|
574 |
%$\textit{ALT}$ |
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|
575 |
\begin{center} |
63 | 576 |
\begin{tabular}{lcl} |
577 |
$r^*$ & $\xrightarrow{\backslash a}$ & $r_1 = (1+0+1 \cdot b + 0 + 1 \cdot b \cdot c) \cdot r^*$\\ |
|
578 |
& $\xrightarrow{\backslash b}$ & $r_2 = (0+0+1 \cdot 1 + 0 + 1 \cdot 1 \cdot c) \cdot r^* +(0+1+0 + 0 + 0) \cdot r^*$\\ |
|
579 |
& $\xrightarrow{\backslash c}$ & $r_3 = ((0+0+0 + 0 + 1 \cdot 1 \cdot 1) \cdot r^* + (0+0+0 + 1 + 0) \cdot r^*) + $\\ |
|
580 |
& & $\phantom{r_3 = (} ((0+1+0 + 0 + 0) \cdot r^* + (0+0+0 + 1 + 0) \cdot r^* )$ |
|
581 |
\end{tabular} |
|
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|
582 |
\end{center} |
63 | 583 |
|
584 |
\noindent |
|
70 | 585 |
In case $r_3$ is nullable, we can call $mkeps$ |
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|
586 |
to construct a parse tree for how $r_3$ matched the string $abc$. |
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|
587 |
$mkeps$ gives the following value $v_3$: |
65 | 588 |
\begin{center} |
589 |
$\Left(\Left(\Seq(\Right(\Seq(\Empty, \Seq(\Empty,\Empty))), \Stars [])))$ |
|
590 |
\end{center} |
|
591 |
The outer $\Left(\Left(\ldots))$ tells us the leftmost nullable part of $r_3$(underlined): |
|
70 | 592 |
|
65 | 593 |
\begin{center} |
594 |
$( \underline{(0+0+0 + 0 + 1 \cdot 1 \cdot 1) \cdot r^*} + (0+0+0 + 1 + 0) |
|
595 |
\cdot r^*) +((0+1+0 + 0 + 0) \cdot r^*+(0+0+0 + 1 + 0) \cdot r^* ).$ |
|
596 |
\end{center} |
|
70 | 597 |
|
598 |
\noindent |
|
599 |
Note that the leftmost location of term $((0+0+0 + 0 + 1 \cdot 1 \cdot |
|
600 |
1) \cdot r^*$ (which corresponds to the initial sub-match $abc$) allows |
|
601 |
$mkeps$ to pick it up because $mkeps$ is defined to always choose the |
|
602 |
left one when it is nullable. In the case of this example, $abc$ is |
|
603 |
preferred over $a$ or $ab$. This $\Left(\Left(\ldots))$ location is |
|
604 |
naturally generated by two applications of the splitting clause |
|
605 |
||
606 |
\begin{center} |
|
65 | 607 |
$(r_1 \cdot r_2)\backslash c (when \; r_1 \; nullable) \, = (r_1\backslash c) \cdot r_2 \,+\, r_2\backslash c.$ |
70 | 608 |
\end{center} |
609 |
||
610 |
\noindent |
|
611 |
By this clause, we put $r_1 \backslash c \cdot r_2 $ at the |
|
612 |
$\textit{front}$ and $r_2 \backslash c$ at the $\textit{back}$. This |
|
613 |
allows $mkeps$ to always pick up among two matches the one with a longer |
|
614 |
initial sub-match. Removing the outside $\Left(\Left(...))$, the inside |
|
615 |
sub-value |
|
616 |
||
617 |
\begin{center} |
|
65 | 618 |
$\Seq(\Right(\Seq(\Empty, \Seq(\Empty, \Empty))), \Stars [])$ |
70 | 619 |
\end{center} |
620 |
||
621 |
\noindent |
|
622 |
tells us how the empty string $[]$ is matched with $(0+0+0 + 0 + 1 \cdot |
|
623 |
1 \cdot 1) \cdot r^*$. We match $[]$ by a sequence of 2 nullable regular |
|
624 |
expressions. The first one is an alternative, we take the rightmost |
|
625 |
alternative---whose language contains the empty string. The second |
|
626 |
nullable regular expression is a Kleene star. $\Stars$ tells us how it |
|
627 |
generates the nullable regular expression: by 0 iterations to form |
|
628 |
$\epsilon$. Now $\textit{inj}$ injects characters back and incrementally |
|
629 |
builds a parse tree based on $v_3$. Using the value $v_3$, the character |
|
630 |
c, and the regular expression $r_2$, we can recover how $r_2$ matched |
|
631 |
the string $[c]$ : $\textit{inj} \; r_2 \; c \; v_3$ gives us |
|
65 | 632 |
\begin{center} |
633 |
$v_2 = \Left(\Seq(\Right(\Seq(\Empty, \Seq(\Empty, c))), \Stars [])),$ |
|
634 |
\end{center} |
|
635 |
which tells us how $r_2$ matched $[c]$. After this we inject back the character $b$, and get |
|
636 |
\begin{center} |
|
637 |
$v_1 = \Seq(\Right(\Seq(\Empty, \Seq(b, c))), \Stars [])$ |
|
638 |
\end{center} |
|
61 | 639 |
for how |
65 | 640 |
\begin{center} |
641 |
$r_1= (1+0+1 \cdot b + 0 + 1 \cdot b \cdot c) \cdot r*$ |
|
642 |
\end{center} |
|
61 | 643 |
matched the string $bc$ before it split into 2 pieces. |
644 |
Finally, after injecting character $a$ back to $v_1$, |
|
65 | 645 |
we get the parse tree |
646 |
\begin{center} |
|
647 |
$v_0= \Stars [\Right(\Seq(a, \Seq(b, c)))]$ |
|
648 |
\end{center} |
|
649 |
for how $r$ matched $abc$. This completes the algorithm. |
|
650 |
||
61 | 651 |
%We omit the details of injection function, which is provided by Sulzmann and Lu's paper \cite{Sulzmann2014}. |
652 |
Readers might have noticed that the parse tree information |
|
653 |
is actually already available when doing derivatives. |
|
654 |
For example, immediately after the operation $\backslash a$ we know that if we want to match a string that starts with $a$, |
|
655 |
we can either take the initial match to be |
|
65 | 656 |
\begin{center} |
42 | 657 |
\begin{enumerate} |
658 |
\item[1)] just $a$ or |
|
659 |
\item[2)] string $ab$ or |
|
660 |
\item[3)] string $abc$. |
|
661 |
\end{enumerate} |
|
65 | 662 |
\end{center} |
70 | 663 |
|
664 |
\noindent |
|
665 |
In order to differentiate between these choices, we just need to |
|
666 |
remember their positions--$a$ is on the left, $ab$ is in the middle , |
|
667 |
and $abc$ is on the right. Which one of these alternatives is chosen |
|
668 |
later does not affect their relative position because our algorithm does |
|
669 |
not change this order. If this parsing information can be determined and |
|
670 |
does not change because of later derivatives, there is no point in |
|
671 |
traversing this information twice. This leads to an optimisation---if we |
|
672 |
store the information for parse trees inside the regular expression, |
|
673 |
update it when we do derivative on them, and collect the information |
|
674 |
when finished with derivatives and call $mkeps$ for deciding which |
|
675 |
branch is POSIX, we can generate the parse tree in one pass, instead of |
|
676 |
doing the rest $n$ injections. This leads to Sulzmann and Lu's novel |
|
677 |
idea of using bit-codes in derivatives. |
|
42 | 678 |
|
63 | 679 |
In the next section, we shall focus on the bit-coded algorithm and the |
680 |
process of simplification of regular expressions. This is needed in |
|
30 | 681 |
order to obtain \emph{fast} versions of the Brzozowski's, and Sulzmann |
63 | 682 |
and Lu's algorithms. This is where the PhD-project aims to advance the |
683 |
state-of-the-art. |
|
30 | 684 |
|
685 |
||
686 |
\section{Simplification of Regular Expressions} |
|
63 | 687 |
|
70 | 688 |
Using bitcodes to guide parsing is not a novel idea. It was applied to |
63 | 689 |
context free grammars and then adapted by Henglein and Nielson for |
70 | 690 |
efficient regular expression parsing using DFAs~\cite{nielson11bcre}. |
691 |
Sulzmann and Lu took this idea of bitcodes a step further by integrating |
|
692 |
bitcodes into derivatives. The reason why we want to use bitcodes in |
|
693 |
this project is that we want to introduce more aggressive |
|
694 |
simplifications in order to keep the size of derivatives small |
|
695 |
throughout. This is because the main drawback of building successive |
|
696 |
derivatives according to Brzozowski's definition is that they can grow |
|
697 |
very quickly in size. This is mainly due to the fact that the derivative |
|
698 |
operation generates often ``useless'' $\ZERO$s and $\ONE$s in |
|
63 | 699 |
derivatives. As a result, if implemented naively both algorithms by |
70 | 700 |
Brzozowski and by Sulzmann and Lu are excruciatingly slow. For example |
701 |
when starting with the regular expression $(a + aa)^*$ and building 12 |
|
63 | 702 |
successive derivatives w.r.t.~the character $a$, one obtains a |
703 |
derivative regular expression with more than 8000 nodes (when viewed as |
|
704 |
a tree). Operations like derivative and $\nullable$ need to traverse |
|
705 |
such trees and consequently the bigger the size of the derivative the |
|
66 | 706 |
slower the algorithm. |
35 | 707 |
|
70 | 708 |
Fortunately, one can simplify regular expressions after each derivative |
709 |
step. Various simplifications of regular expressions are possible, such |
|
710 |
as the simplifications of $\ZERO + r$, $r + \ZERO$, $\ONE\cdot r$, $r |
|
711 |
\cdot \ONE$, and $r + r$ to just $r$. These simplifications do not |
|
712 |
affect the answer for whether a regular expression matches a string or |
|
713 |
not, but fortunately also do not affect the POSIX strategy of how |
|
714 |
regular expressions match strings---although the latter is much harder |
|
715 |
to establish. \comment{Does not make sense.} The argument for |
|
716 |
complicating the data structures from basic regular expressions to those |
|
717 |
with bitcodes is that we can introduce simplification without making the |
|
718 |
algorithm crash or overly complex to reason about. The latter is crucial |
|
719 |
for a correctness proof. Some initial results in this regard have been |
|
720 |
obtained in \cite{AusafDyckhoffUrban2016}. |
|
721 |
||
722 |
Unfortunately, the simplification rules outlined above are not |
|
723 |
sufficient to prevent an explosion for all regular expression. We |
|
724 |
believe a tighter bound can be achieved that prevents an explosion in |
|
725 |
all cases. Such a tighter bound is suggested by work of Antimirov who |
|
726 |
proved that (partial) derivatives can be bound by the number of |
|
727 |
characters contained in the initial regular expression |
|
728 |
\cite{Antimirov95}. He defined the \emph{partial derivatives} of regular |
|
729 |
expressions as follows: |
|
730 |
||
52
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|
731 |
\begin{center} |
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|
732 |
\begin{tabular}{lcl} |
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|
733 |
$\textit{pder} \; c \; 0$ & $\dn$ & $\emptyset$\\ |
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|
734 |
$\textit{pder} \; c \; 1$ & $\dn$ & $\emptyset$ \\ |
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735 |
$\textit{pder} \; c \; d$ & $\dn$ & $\textit{if} \; c \,=\, d \; \{ 1 \} \; \textit{else} \; \emptyset$ \\ |
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|
736 |
$\textit{pder} \; c \; r_1+r_2$ & $\dn$ & $pder \; c \; r_1 \cup pder \; c \; r_2$ \\ |
70 | 737 |
$\textit{pder} \; c \; r_1 \cdot r_2$ & $\dn$ & $\textit{if} \; nullable \; r_1 $\\ |
738 |
& & $\textit{then} \; \{ r \cdot r_2 \mid r \in pder \; c \; r_1 \} \cup pder \; c \; r_2 \;$\\ |
|
739 |
& & $\textit{else} \; \{ r \cdot r_2 \mid r \in pder \; c \; r_1 \} $ \\ |
|
52
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|
740 |
$\textit{pder} \; c \; r^*$ & $\dn$ & $ \{ r' \cdot r^* \mid r' \in pder \; c \; r \} $ \\ |
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|
741 |
\end{tabular} |
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|
742 |
\end{center} |
70 | 743 |
|
744 |
\noindent |
|
745 |
A partial derivative of a regular expression $r$ is essentially a set of |
|
746 |
regular expressions that are either $r$'s children expressions or a |
|
747 |
concatenation of them. Antimirov has proved a tight bound of the size of |
|
748 |
partial derivatives. \comment{That looks too preliminary to me.} Roughly |
|
749 |
speaking the size will not exceed the fourth power of the number of |
|
750 |
nodes in that regular expression. \comment{Improve: which |
|
751 |
simplifications?}Interestingly, we observed from experiment that after |
|
752 |
the simplification step, our regular expression has the same size or is |
|
753 |
smaller than the partial derivatives. This allows us to prove a tight |
|
754 |
bound on the size of regular expression during the running time of the |
|
755 |
algorithm if we can establish the connection between our simplification |
|
756 |
rules and partial derivatives. |
|
35 | 757 |
|
758 |
%We believe, and have generated test |
|
759 |
%data, that a similar bound can be obtained for the derivatives in |
|
760 |
%Sulzmann and Lu's algorithm. Let us give some details about this next. |
|
30 | 761 |
|
43 | 762 |
Bit-codes look like this: |
67 | 763 |
\begin{center} |
764 |
$b ::= S \mid Z \; \;\; |
|
43 | 765 |
bs ::= [] \mid b:bs |
67 | 766 |
$ |
767 |
\end{center} |
|
68 | 768 |
They are just a string of bits, the names $S$ and $Z$ here are quite arbitrary, we can use 0 and 1 or any other set of binary symbols to substitute them. Bit-codes(or bit-sequences) are a compact form of parse trees. |
43 | 769 |
Here is how values and bit-codes are related: |
770 |
Bitcodes are essentially incomplete values. |
|
30 | 771 |
This can be straightforwardly seen in the following transformation: |
772 |
\begin{center} |
|
773 |
\begin{tabular}{lcl} |
|
774 |
$\textit{code}(\Empty)$ & $\dn$ & $[]$\\ |
|
775 |
$\textit{code}(\Char\,c)$ & $\dn$ & $[]$\\ |
|
776 |
$\textit{code}(\Left\,v)$ & $\dn$ & $\Z :: code(v)$\\ |
|
777 |
$\textit{code}(\Right\,v)$ & $\dn$ & $\S :: code(v)$\\ |
|
778 |
$\textit{code}(\Seq\,v_1\,v_2)$ & $\dn$ & $code(v_1) \,@\, code(v_2)$\\ |
|
68 | 779 |
$\textit{code}(\Stars\,[])$ & $\dn$ & $[\Z]$\\ |
780 |
$\textit{code}(\Stars\,(v\!::\!vs))$ & $\dn$ & $\S :: code(v) \;@\; |
|
30 | 781 |
code(\Stars\,vs)$ |
782 |
\end{tabular} |
|
783 |
\end{center} |
|
70 | 784 |
|
785 |
Here code encodes a value into a bit-sequence by converting Left into |
|
786 |
$\Z$, Right into $\S$, the start point of a non-empty star iteration |
|
787 |
into $\S$, and the border where a local star terminates into $\Z$. This |
|
788 |
conversion is apparently lossy, as it throws away the character |
|
789 |
information, and does not decode the boundary between the two operands |
|
790 |
of the sequence constructor. Moreover, with only the bitcode we cannot |
|
791 |
even tell whether the $\S$s and $\Z$s are for $\Left/\Right$ or |
|
792 |
$\Stars$. The reason for choosing this compact way of storing |
|
793 |
information is that the relatively small size of bits can be easily |
|
794 |
moved around. In order to recover the bitcode back into values, we will |
|
795 |
need the regular expression as the extra information and decode it back |
|
796 |
into value:\\ |
|
797 |
||
798 |
||
37 | 799 |
%\begin{definition}[Bitdecoding of Values]\mbox{} |
36 | 800 |
\begin{center} |
801 |
\begin{tabular}{@{}l@{\hspace{1mm}}c@{\hspace{1mm}}l@{}} |
|
802 |
$\textit{decode}'\,bs\,(\ONE)$ & $\dn$ & $(\Empty, bs)$\\ |
|
803 |
$\textit{decode}'\,bs\,(c)$ & $\dn$ & $(\Char\,c, bs)$\\ |
|
804 |
$\textit{decode}'\,(\Z\!::\!bs)\;(r_1 + r_2)$ & $\dn$ & |
|
805 |
$\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}\; |
|
806 |
(\Left\,v, bs_1)$\\ |
|
807 |
$\textit{decode}'\,(\S\!::\!bs)\;(r_1 + r_2)$ & $\dn$ & |
|
808 |
$\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_2\;\textit{in}\; |
|
809 |
(\Right\,v, bs_1)$\\ |
|
810 |
$\textit{decode}'\,bs\;(r_1\cdot r_2)$ & $\dn$ & |
|
811 |
$\textit{let}\,(v_1, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}$\\ |
|
812 |
& & $\textit{let}\,(v_2, bs_2) = \textit{decode}'\,bs_1\,r_2$\\ |
|
813 |
& & \hspace{35mm}$\textit{in}\;(\Seq\,v_1\,v_2, bs_2)$\\ |
|
814 |
$\textit{decode}'\,(\Z\!::\!bs)\,(r^*)$ & $\dn$ & $(\Stars\,[], bs)$\\ |
|
815 |
$\textit{decode}'\,(\S\!::\!bs)\,(r^*)$ & $\dn$ & |
|
816 |
$\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r\;\textit{in}$\\ |
|
817 |
& & $\textit{let}\,(\Stars\,vs, bs_2) = \textit{decode}'\,bs_1\,r^*$\\ |
|
818 |
& & \hspace{35mm}$\textit{in}\;(\Stars\,v\!::\!vs, bs_2)$\bigskip\\ |
|
819 |
||
820 |
$\textit{decode}\,bs\,r$ & $\dn$ & |
|
821 |
$\textit{let}\,(v, bs') = \textit{decode}'\,bs\,r\;\textit{in}$\\ |
|
822 |
& & $\textit{if}\;bs' = []\;\textit{then}\;\textit{Some}\,v\; |
|
823 |
\textit{else}\;\textit{None}$ |
|
824 |
\end{tabular} |
|
825 |
\end{center} |
|
37 | 826 |
%\end{definition} |
30 | 827 |
|
43 | 828 |
|
70 | 829 |
Sulzmann and Lu's integrated the bitcodes into annotated regular |
830 |
expressions by attaching them to the head of every substructure of a |
|
831 |
regular expression\cite{Sulzmann2014}. They are defined by the following |
|
832 |
grammar: |
|
43 | 833 |
|
834 |
\begin{center} |
|
835 |
\begin{tabular}{lcl} |
|
836 |
$\textit{a}$ & $::=$ & $\textit{ZERO}$\\ |
|
837 |
& $\mid$ & $\textit{ONE}\;\;bs$\\ |
|
838 |
& $\mid$ & $\textit{CHAR}\;\;bs\,c$\\ |
|
839 |
& $\mid$ & $\textit{ALTS}\;\;bs\,as$\\ |
|
840 |
& $\mid$ & $\textit{SEQ}\;\;bs\,a_1\,a_2$\\ |
|
841 |
& $\mid$ & $\textit{STAR}\;\;bs\,a$ |
|
842 |
\end{tabular} |
|
843 |
\end{center} |
|
844 |
||
845 |
\noindent |
|
846 |
where $bs$ stands for bitsequences, and $as$ (in \textit{ALTS}) for a |
|
847 |
list of annotated regular expressions. These bitsequences encode |
|
848 |
information about the (POSIX) value that should be generated by the |
|
849 |
Sulzmann and Lu algorithm. |
|
850 |
||
70 | 851 |
To do lexing using annotated regular expressions, we shall first |
852 |
transform the usual (un-annotated) regular expressions into annotated |
|
853 |
regular expressions. This operation is called \emph{internalisation} and |
|
854 |
defined as follows: |
|
855 |
||
37 | 856 |
%\begin{definition} |
36 | 857 |
\begin{center} |
858 |
\begin{tabular}{lcl} |
|
859 |
$(\ZERO)^\uparrow$ & $\dn$ & $\textit{ZERO}$\\ |
|
860 |
$(\ONE)^\uparrow$ & $\dn$ & $\textit{ONE}\,[]$\\ |
|
861 |
$(c)^\uparrow$ & $\dn$ & $\textit{CHAR}\,[]\,c$\\ |
|
862 |
$(r_1 + r_2)^\uparrow$ & $\dn$ & |
|
863 |
$\textit{ALT}\;[]\,(\textit{fuse}\,[\Z]\,r_1^\uparrow)\, |
|
864 |
(\textit{fuse}\,[\S]\,r_2^\uparrow)$\\ |
|
865 |
$(r_1\cdot r_2)^\uparrow$ & $\dn$ & |
|
866 |
$\textit{SEQ}\;[]\,r_1^\uparrow\,r_2^\uparrow$\\ |
|
867 |
$(r^*)^\uparrow$ & $\dn$ & |
|
868 |
$\textit{STAR}\;[]\,r^\uparrow$\\ |
|
869 |
\end{tabular} |
|
870 |
\end{center} |
|
37 | 871 |
%\end{definition} |
44
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872 |
|
70 | 873 |
\noindent |
874 |
In the fourth clause, $fuse$ is an auxiliary function that helps to attach bits to the |
|
875 |
front of an annotated regular expression. Its definition is as follows: |
|
876 |
||
44
4d674a971852
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|
877 |
\begin{center} |
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|
878 |
\begin{tabular}{lcl} |
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|
879 |
$\textit{fuse}\,bs\,(\textit{ZERO})$ & $\dn$ & $\textit{ZERO}$\\ |
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|
880 |
$\textit{fuse}\,bs\,(\textit{ONE}\,bs')$ & $\dn$ & |
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|
881 |
$\textit{ONE}\,(bs\,@\,bs')$\\ |
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|
882 |
$\textit{fuse}\,bs\,(\textit{CHAR}\,bs'\,c)$ & $\dn$ & |
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|
883 |
$\textit{CHAR}\,(bs\,@\,bs')\,c$\\ |
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|
884 |
$\textit{fuse}\,bs\,(\textit{ALT}\,bs'\,a_1\,a_2)$ & $\dn$ & |
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|
885 |
$\textit{ALT}\,(bs\,@\,bs')\,a_1\,a_2$\\ |
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|
886 |
$\textit{fuse}\,bs\,(\textit{SEQ}\,bs'\,a_1\,a_2)$ & $\dn$ & |
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|
887 |
$\textit{SEQ}\,(bs\,@\,bs')\,a_1\,a_2$\\ |
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|
888 |
$\textit{fuse}\,bs\,(\textit{STAR}\,bs'\,a)$ & $\dn$ & |
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|
889 |
$\textit{STAR}\,(bs\,@\,bs')\,a$ |
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|
890 |
\end{tabular} |
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|
891 |
\end{center} |
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|
892 |
|
70 | 893 |
\noindent |
894 |
After internalise we do successive derivative operations on the |
|
895 |
annotated regular expression. This derivative operation is the same as |
|
896 |
what we previously have for the simple regular expressions, except that |
|
897 |
we take special care of the bits :\\ |
|
898 |
||
899 |
%\begin{definition}{bder} |
|
36 | 900 |
\begin{center} |
901 |
\begin{tabular}{@{}lcl@{}} |
|
902 |
$(\textit{ZERO})\backslash c$ & $\dn$ & $\textit{ZERO}$\\ |
|
903 |
$(\textit{ONE}\;bs)\backslash c$ & $\dn$ & $\textit{ZERO}$\\ |
|
904 |
$(\textit{CHAR}\;bs\,d)\backslash c$ & $\dn$ & |
|
905 |
$\textit{if}\;c=d\; \;\textit{then}\; |
|
906 |
\textit{ONE}\;bs\;\textit{else}\;\textit{ZERO}$\\ |
|
907 |
$(\textit{ALT}\;bs\,a_1\,a_2)\backslash c$ & $\dn$ & |
|
908 |
$\textit{ALT}\,bs\,(a_1\backslash c)\,(a_2\backslash c)$\\ |
|
909 |
$(\textit{SEQ}\;bs\,a_1\,a_2)\backslash c$ & $\dn$ & |
|
910 |
$\textit{if}\;\textit{bnullable}\,a_1$\\ |
|
911 |
& &$\textit{then}\;\textit{ALT}\,bs\,(\textit{SEQ}\,[]\,(a_1\backslash c)\,a_2)$\\ |
|
912 |
& &$\phantom{\textit{then}\;\textit{ALT}\,bs\,}(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\backslash c))$\\ |
|
913 |
& &$\textit{else}\;\textit{SEQ}\,bs\,(a_1\backslash c)\,a_2$\\ |
|
914 |
$(\textit{STAR}\,bs\,a)\backslash c$ & $\dn$ & |
|
915 |
$\textit{SEQ}\;bs\,(\textit{fuse}\, [\Z] (r\backslash c))\, |
|
916 |
(\textit{STAR}\,[]\,r)$ |
|
917 |
\end{tabular} |
|
918 |
\end{center} |
|
37 | 919 |
%\end{definition} |
44
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|
920 |
For instance, when we unfold $STAR \; bs \; a$ into a sequence, we attach an additional bit Z to the front of $r \backslash c$ to indicate that there is one more star iteration. |
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|
921 |
The other example, the $SEQ$ clause is more subtle-- when $a_1$ is $bnullable$(here bnullable is exactly the same as nullable, except that it is for annotated regular expressions, therefore we omit the definition). |
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|
922 |
Assume that $bmkeps$ correctly extracts the bitcode for how $a_1$ matches the string prior to character c(more on this later), then the right branch of $ALTS$, which is $fuse \; bmkeps \; a_1 (a_2 \backslash c)$ will collapse the regular expression $a_1$(as it has already been fully matched) and store the parsing information at the head of the regular expression $a_2 \backslash c$ by fusing to it. The bitsequence $bs$, which was initially attached to the head of $SEQ$, has now been elevated to the top-level of ALT, |
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|
923 |
as this information will be needed whichever way the $SEQ$ is matched--no matter whether c belongs to $a_1$ or $ a_2$. |
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|
924 |
After carefully doing these derivatives and maintaining all the parsing information, we complete the parsing by collecting the bits using a special $mkeps$ function for annotated regular expressions--$bmkeps$: |
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|
925 |
|
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|
926 |
|
37 | 927 |
%\begin{definition}[\textit{bmkeps}]\mbox{} |
36 | 928 |
\begin{center} |
929 |
\begin{tabular}{lcl} |
|
930 |
$\textit{bmkeps}\,(\textit{ONE}\,bs)$ & $\dn$ & $bs$\\ |
|
931 |
$\textit{bmkeps}\,(\textit{ALT}\,bs\,a_1\,a_2)$ & $\dn$ & |
|
932 |
$\textit{if}\;\textit{bnullable}\,a_1$\\ |
|
933 |
& &$\textit{then}\;bs\,@\,\textit{bmkeps}\,a_1$\\ |
|
934 |
& &$\textit{else}\;bs\,@\,\textit{bmkeps}\,a_2$\\ |
|
935 |
$\textit{bmkeps}\,(\textit{SEQ}\,bs\,a_1\,a_2)$ & $\dn$ & |
|
936 |
$bs \,@\,\textit{bmkeps}\,a_1\,@\, \textit{bmkeps}\,a_2$\\ |
|
937 |
$\textit{bmkeps}\,(\textit{STAR}\,bs\,a)$ & $\dn$ & |
|
938 |
$bs \,@\, [\S]$ |
|
939 |
\end{tabular} |
|
940 |
\end{center} |
|
37 | 941 |
%\end{definition} |
70 | 942 |
|
943 |
\noindent |
|
44
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|
944 |
This function completes the parse tree information by |
45 | 945 |
travelling along the path on the regular expression that corresponds to a POSIX value snd collect all the bits, and |
44
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|
946 |
using S to indicate the end of star iterations. If we take the bitsproduced by $bmkeps$ and decode it, |
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|
947 |
we get the parse tree we need, the working flow looks like this:\\ |
37 | 948 |
\begin{center} |
949 |
\begin{tabular}{lcl} |
|
950 |
$\textit{blexer}\;r\,s$ & $\dn$ & |
|
951 |
$\textit{let}\;a = (r^\uparrow)\backslash s\;\textit{in}$\\ |
|
952 |
& & $\;\;\textit{if}\; \textit{bnullable}(a)$\\ |
|
953 |
& & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\ |
|
954 |
& & $\;\;\textit{else}\;\textit{None}$ |
|
955 |
\end{tabular} |
|
956 |
\end{center} |
|
53 | 957 |
Here $(r^\uparrow)\backslash s$ is similar to what we have previously defined for |
958 |
$r\backslash s$. |
|
30 | 959 |
|
960 |
The main point of the bitsequences and annotated regular expressions |
|
961 |
is that we can apply rather aggressive (in terms of size) |
|
962 |
simplification rules in order to keep derivatives small. |
|
963 |
||
964 |
We have |
|
965 |
developed such ``aggressive'' simplification rules and generated test |
|
966 |
data that show that the expected bound can be achieved. Obviously we |
|
967 |
could only partially cover the search space as there are infinitely |
|
968 |
many regular expressions and strings. One modification we introduced |
|
969 |
is to allow a list of annotated regular expressions in the |
|
970 |
\textit{ALTS} constructor. This allows us to not just delete |
|
971 |
unnecessary $\ZERO$s and $\ONE$s from regular expressions, but also |
|
972 |
unnecessary ``copies'' of regular expressions (very similar to |
|
973 |
simplifying $r + r$ to just $r$, but in a more general |
|
35 | 974 |
setting). |
49 | 975 |
Another modification is that we use simplification rules |
976 |
inspired by Antimirov's work on partial derivatives. They maintain the |
|
977 |
idea that only the first ``copy'' of a regular expression in an |
|
978 |
alternative contributes to the calculation of a POSIX value. All |
|
979 |
subsequent copies can be pruned from the regular expression. |
|
980 |
||
52
25bbbb8b0e90
just in case of some accidents from erasing my work
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51
diff
changeset
|
981 |
A recursive definition of simplification function that looks similar to scala code is given below:\\ |
25bbbb8b0e90
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51
diff
changeset
|
982 |
\begin{center} |
25bbbb8b0e90
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51
diff
changeset
|
983 |
\begin{tabular}{@{}lcl@{}} |
25bbbb8b0e90
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51
diff
changeset
|
984 |
$\textit{simp} \; a$ & $\dn$ & $\textit{a} \; \textit{if} \; a = (\textit{ONE} \; bs) \; or\; (\textit{CHAR} \, bs \; c) \; or\; (\textit{STAR}\; bs\; a_1)$\\ |
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Chengsong
parents:
51
diff
changeset
|
985 |
|
25bbbb8b0e90
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51
diff
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|
986 |
$\textit{simp} \; \textit{SEQ}\;bs\,a_1\,a_2$ & $\dn$ & $ (\textit{simp} \; a_1, \textit{simp} \; a_2) \; \textit{match} $ \\ |
25bbbb8b0e90
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51
diff
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|
987 |
&&$\textit{case} \; (0, \_) \Rightarrow 0$ \\ |
25bbbb8b0e90
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51
diff
changeset
|
988 |
&&$ \textit{case} \; (\_, 0) \Rightarrow 0$ \\ |
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51
diff
changeset
|
989 |
&&$ \textit{case} \; (1, a_2') \Rightarrow \textit{fuse} \; bs \; a_2'$ \\ |
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parents:
51
diff
changeset
|
990 |
&&$ \textit{case} \; (a_1', 1) \Rightarrow \textit{fuse} \; bs \; a_1'$ \\ |
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51
diff
changeset
|
991 |
&&$ \textit{case} \; (a_1', a_2') \Rightarrow \textit{SEQ} \; bs \; a_1' \; a_2'$ \\ |
25bbbb8b0e90
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51
diff
changeset
|
992 |
|
25bbbb8b0e90
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parents:
51
diff
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|
993 |
$\textit{simp} \; \textit{ALT}\;bs\,as$ & $\dn$ & $\textit{ distinct}( \textit{flatten} ( \textit{map simp as})) \; \textit{match} $ \\ |
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51
diff
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|
994 |
&&$\textit{case} \; [] \Rightarrow 0$ \\ |
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51
diff
changeset
|
995 |
&&$ \textit{case} \; a :: [] \Rightarrow \textit{fuse bs a}$ \\ |
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parents:
51
diff
changeset
|
996 |
&&$ \textit{case} \; as' \Rightarrow \textit{ALT bs as'}$ |
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51
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changeset
|
997 |
\end{tabular} |
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changeset
|
998 |
\end{center} |
47 | 999 |
|
1000 |
The simplification does a pattern matching on the regular expression. When it detected that |
|
1001 |
the regular expression is an alternative or sequence, it will try to simplify its children regular expressions |
|
1002 |
recursively and then see if one of the children turn into 0 or 1, which might trigger further simplification |
|
1003 |
at the current level. The most involved part is the ALTS clause, where we use two auxiliary functions |
|
1004 |
flatten and distinct to open up nested ALT and reduce as many duplicates as possible. |
|
48 | 1005 |
Function distinct keeps the first occurring copy only and remove all later ones when detected duplicates. |
1006 |
Function flatten opens up nested ALT. Its recursive definition is given below: |
|
53 | 1007 |
\begin{center} |
1008 |
\begin{tabular}{@{}lcl@{}} |
|
70 | 1009 |
$\textit{flatten} \; (\textit{ALT}\;bs\,as) :: as'$ & $\dn$ & $(\textit{map} \; |
1010 |
(\textit{fuse}\;bs)\; \textit{as}) \; @ \; \textit{flatten} \; as' $ \\ |
|
53 | 1011 |
$\textit{flatten} \; \textit{ZERO} :: as'$ & $\dn$ & $ \textit{flatten} \; as' $ \\ |
70 | 1012 |
$\textit{flatten} \; a :: as'$ & $\dn$ & $a :: \textit{flatten} \; as'$ \quad(otherwise) |
53 | 1013 |
\end{tabular} |
1014 |
\end{center} |
|
1015 |
||
70 | 1016 |
\noindent |
1017 |
\comment{No: functional flatten does not remove ZEROs}Here flatten behaves like the traditional functional programming flatten function, |
|
48 | 1018 |
what it does is basically removing parentheses like changing $a+(b+c)$ into $a+b+c$. |
47 | 1019 |
|
53 | 1020 |
Suppose we apply simplification after each derivative step, |
1021 |
and view these two operations as an atomic one: $a \backslash_{simp} c \dn \textit{simp}(a \backslash c)$. |
|
1022 |
Then we can use the previous natural extension from derivative w.r.t character to derivative w.r.t string: |
|
1023 |
||
1024 |
\begin{center} |
|
1025 |
\begin{tabular}{lcl} |
|
1026 |
$r \backslash_{simp} (c\!::\!s) $ & $\dn$ & $(r \backslash_{simp} c) \backslash_{simp} s$ \\ |
|
1027 |
$r \backslash [\,] $ & $\dn$ & $r$ |
|
1028 |
\end{tabular} |
|
1029 |
\end{center} |
|
1030 |
||
1031 |
we get an optimized version of the algorithm: |
|
1032 |
\begin{center} |
|
1033 |
\begin{tabular}{lcl} |
|
1034 |
$\textit{blexer\_simp}\;r\,s$ & $\dn$ & |
|
1035 |
$\textit{let}\;a = (r^\uparrow)\backslash_{simp} s\;\textit{in}$\\ |
|
1036 |
& & $\;\;\textit{if}\; \textit{bnullable}(a)$\\ |
|
1037 |
& & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\ |
|
1038 |
& & $\;\;\textit{else}\;\textit{None}$ |
|
1039 |
\end{tabular} |
|
1040 |
\end{center} |
|
48 | 1041 |
|
1042 |
This algorithm effectively keeps the regular expression size small, for example, |
|
1043 |
with this simplification our previous $(a + aa)^*$ example's 8000 nodes will be reduced to only 6 and stay constant, however long the input string is. |
|
35 | 1044 |
|
30 | 1045 |
|
35 | 1046 |
|
70 | 1047 |
\section{Current Work} |
1048 |
||
1049 |
We are currently engaged in two tasks related to this algorithm. |
|
1050 |
||
1051 |
\begin{itemize} |
|
1052 |
\item |
|
49 | 1053 |
The first one is proving that our simplification rules |
30 | 1054 |
actually do not affect the POSIX value that should be generated by the |
49 | 1055 |
algorithm according to the specification of a POSIX value |
1056 |
and furthermore obtain a much |
|
1057 |
tighter bound on the sizes of derivatives. The result is that our |
|
1058 |
algorithm should be correct and faster on all inputs. The original |
|
1059 |
blow-up, as observed in JavaScript, Python and Java, would be excluded |
|
1060 |
from happening in our algorithm.For |
|
30 | 1061 |
this proof we use the theorem prover Isabelle. Once completed, this |
1062 |
result will advance the state-of-the-art: Sulzmann and Lu wrote in |
|
1063 |
their paper \cite{Sulzmann2014} about the bitcoded ``incremental |
|
1064 |
parsing method'' (that is the matching algorithm outlined in this |
|
1065 |
section): |
|
1066 |
||
1067 |
\begin{quote}\it |
|
1068 |
``Correctness Claim: We further claim that the incremental parsing |
|
1069 |
method in Figure~5 in combination with the simplification steps in |
|
1070 |
Figure 6 yields POSIX parse trees. We have tested this claim |
|
1071 |
extensively by using the method in Figure~3 as a reference but yet |
|
1072 |
have to work out all proof details.'' |
|
1073 |
\end{quote} |
|
1074 |
||
1075 |
\noindent |
|
49 | 1076 |
We would settle the correctness claim. |
70 | 1077 |
It is relatively straightforward to establish that after one simplification step, the part of derivative that corresponds to a POSIX value remains intact and can still be collected, in other words, |
1078 |
\comment{that only holds when r is nullable}bmkeps r = bmkeps simp r |
|
58 | 1079 |
as this basically comes down to proving actions like removing the additional $r$ in $r+r$ does not delete important POSIX information in a regular expression. |
49 | 1080 |
The hardcore of this problem is to prove that |
1081 |
bmkeps bders r = bmkeps bders simp r |
|
62 | 1082 |
That is, if we do derivative on regular expression r and the simplified version for, they can still prove the same POSIX value if there is one . This is not as straightforward as the previous proposition, as the two regular expression r and simp r might become very different regular expressions after repeated application ofd simp and derivative. |
70 | 1083 |
The crucial point is to find the \comment{What?}"gene" of a regular expression and how it is kept intact during simplification. |
1084 |
To aid this, we are use the helping function retrieve described by Sulzmann and Lu: |
|
49 | 1085 |
\\definition of retrieve\\ |
58 | 1086 |
This function assembled the bitcode that corresponds to a parse tree for how the current derivative matches the suffix of the string(the characters that have not yet appeared, but is stored in the value). |
49 | 1087 |
Sulzmann and Lu used this to connect the bit-coded algorithm to the older algorithm by the following equation:\\ |
53 | 1088 |
$inj \;a\; c \; v = \textit{decode} \; (\textit{retrieve}\; ((\textit{internalise}\; r)\backslash_{simp} c) v)$\\ |
1089 |
A little fact that needs to be stated to help comprehension:\\ |
|
1090 |
$r^\uparrow = a$($a$ stands for $annotated$).\\ |
|
58 | 1091 |
Fahad and Christian also used this fact to prove the correctness of bit-coded algorithm without simplification. |
50 | 1092 |
Our purpose of using this, however, is try to establish \\ |
53 | 1093 |
$ \textit{retrieve} \; a \; v \;=\; \textit{retrieve} \; \textit{simp}(a) \; v'.$\\ |
1094 |
The idea is that using $v'$, |
|
58 | 1095 |
a simplified version of $v$ that possibly had gone through the same simplification step as $\textit{simp}(a)$ we are still able to extract the bitsequence that gives the same parsing information as the unsimplified one. |
53 | 1096 |
After establishing this, we might be able to finally bridge the gap of proving\\ |
1097 |
$\textit{retrieve} \; r \backslash s \; v = \;\textit{retrieve} \; \textit{simp}(r) \backslash s \; v'$\\ |
|
1098 |
and subsequently\\ |
|
1099 |
$\textit{retrieve} \; r \backslash s \; v\; = \; \textit{retrieve} \; r \backslash_{simp} s \; v'$.\\ |
|
58 | 1100 |
This proves that our simplified version of regular expression still contains all the bitcodes needed. |
49 | 1101 |
|
70 | 1102 |
\item |
1103 |
The second task is to speed up the more aggressive simplification. |
|
1104 |
Currently it is slower than a naive simplification(the naive version as |
|
1105 |
implemented in ADU of course can explode in some cases). So it needs to |
|
1106 |
be explored how to make it faster. Our possibility would be to explore |
|
1107 |
again the connection to DFAs. This is very much work in progress. |
|
1108 |
\end{itemize} |
|
30 | 1109 |
|
1110 |
\section{Conclusion} |
|
1111 |
||
1112 |
In this PhD-project we are interested in fast algorithms for regular |
|
1113 |
expression matching. While this seems to be a ``settled'' area, in |
|
1114 |
fact interesting research questions are popping up as soon as one steps |
|
1115 |
outside the classic automata theory (for example in terms of what kind |
|
1116 |
of regular expressions are supported). The reason why it is |
|
1117 |
interesting for us to look at the derivative approach introduced by |
|
1118 |
Brzozowski for regular expression matching, and then much further |
|
1119 |
developed by Sulzmann and Lu, is that derivatives can elegantly deal |
|
1120 |
with some of the regular expressions that are of interest in ``real |
|
1121 |
life''. This includes the not-regular expression, written $\neg\,r$ |
|
1122 |
(that is all strings that are not recognised by $r$), but also bounded |
|
1123 |
regular expressions such as $r^{\{n\}}$ and $r^{\{n..m\}}$). There is |
|
1124 |
also hope that the derivatives can provide another angle for how to |
|
1125 |
deal more efficiently with back-references, which are one of the |
|
1126 |
reasons why regular expression engines in JavaScript, Python and Java |
|
1127 |
choose to not implement the classic automata approach of transforming |
|
1128 |
regular expressions into NFAs and then DFAs---because we simply do not |
|
1129 |
know how such back-references can be represented by DFAs. |
|
1130 |
||
1131 |
||
1132 |
\bibliographystyle{plain} |
|
1133 |
\bibliography{root} |
|
1134 |
||
1135 |
||
1136 |
\end{document} |