etnms/etnms.tex
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\documentclass[a4paper,UKenglish]{lipics}
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\usepackage{graphic}
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\usepackage{data}
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\usepackage{tikz-cd}
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%\usepackage{algorithm}
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\usepackage{amsmath}
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\usepackage{xcolor}
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\usepackage[noend]{algpseudocode}
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\usepackage{enumitem}
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\usepackage{nccmath}
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\usepackage{soul}
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\definecolor{darkblue}{rgb}{0,0,0.6}
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\hypersetup{colorlinks=true,allcolors=darkblue}
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\newcommand{\comment}[1]%
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{{\color{red}$\Rightarrow$}\marginpar{\raggedright\small{\bf\color{red}#1}}}
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% \documentclass{article}
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%\usepackage[utf8]{inputenc}
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%\usepackage[english]{babel}
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%\usepackage{listings}
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% \usepackage{amsthm}
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%\usepackage{hyperref}
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% \usepackage[margin=0.5in]{geometry}
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%\usepackage{pmboxdraw}
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\title{POSIX Regular Expression Matching and Lexing}
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\author{Chengsong Tan}
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\affil{King's College London\\
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London, UK\\
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\texttt{chengsong.tan@kcl.ac.uk}}
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\authorrunning{Chengsong Tan}
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\Copyright{Chengsong Tan}
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\newcommand{\dn}{\stackrel{\mbox{\scriptsize def}}{=}}%
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\newcommand{\ZERO}{\mbox{\bf 0}}
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\newcommand{\ONE}{\mbox{\bf 1}}
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\def\erase{\textit{erase}}
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\def\bders{\textit{bders}}
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\def\lexer{\mathit{lexer}}
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\def\blexer{\textit{blexer}}
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\def\fuse{\textit{fuse}}
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\def\flatten{\textit{flatten}}
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\def\map{\textit{map}}
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\def\blexers{\mathit{blexer\_simp}}
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\def\simp{\mathit{simp}}
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\def\mkeps{\mathit{mkeps}}
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\def\bmkeps{\textit{bmkeps}}
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\def\inj{\mathit{inj}}
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\def\Empty{\mathit{Empty}}
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\def\Left{\mathit{Left}}
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\def\Right{\mathit{Right}}
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\def\Stars{\mathit{Stars}}
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\def\Char{\mathit{Char}}
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\def\Seq{\mathit{Seq}}
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\def\Der{\mathit{Der}}
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\def\nullable{\mathit{nullable}}
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\def\Z{\mathit{Z}}
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\def\S{\mathit{S}}
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\def\flex{\textit{flex}}
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\def\rup{r^\uparrow}
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\def\retrieve{\textit{retrieve}}
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\def\AALTS{\textit{AALTS}}
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\def\AONE{\textit{AONE}}
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%\theoremstyle{theorem}
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%\newtheorem{theorem}{Theorem}
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%\theoremstyle{lemma}
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%\newtheorem{lemma}{Lemma}
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%\newcommand{\lemmaautorefname}{Lemma}
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%\theoremstyle{definition}
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%\newtheorem{definition}{Definition}
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\algnewcommand\algorithmicswitch{\textbf{switch}}
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\algnewcommand\algorithmiccase{\textbf{case}}
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\algnewcommand\algorithmicassert{\texttt{assert}}
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\algnewcommand\Assert[1]{\State \algorithmicassert(#1)}%
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% New "environments"
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\algdef{SE}[SWITCH]{Switch}{EndSwitch}[1]{\algorithmicswitch\ #1\ \algorithmicdo}{\algorithmicend\ \algorithmicswitch}%
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\algdef{SE}[CASE]{Case}{EndCase}[1]{\algorithmiccase\ #1}{\algorithmicend\ \algorithmiccase}%
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\algtext*{EndSwitch}%
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\algtext*{EndCase}%
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\begin{document}
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\maketitle
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\begin{abstract}
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  Brzozowski introduced in 1964 a beautifully simple algorithm for
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  regular expression matching based on the notion of derivatives of
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  regular expressions. In 2014, Sulzmann and Lu extended this
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  algorithm to not just give a YES/NO answer for whether or not a
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  regular expression matches a string, but in case it does also
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  answers with \emph{how} it matches the string.  This is important for
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  applications such as lexing (tokenising a string). The problem is to
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  make the algorithm by Sulzmann and Lu fast on all inputs without
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  breaking its correctness. Being fast depends on a complete set of 
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  simplification rules, some of which 
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  have been put forward by Sulzmann and Lu. We have extended their
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  rules in order to obtain a tight bound on the size of regular expressions.
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  We have tested these extended rules, but have not 
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  formally established their correctness. We have also not yet looked 
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  at extended regular expressions, such as bounded repetitions,
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  negation and back-references.
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\end{abstract}
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\section{Recapitulation of Concepts From the Last Report}
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\subsection*{Regular Expressions and Derivatives}
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Suppose (basic) regular expressions are given by the following grammar:
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\[			r ::=   \ZERO \mid  \ONE
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			 \mid  c  
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			 \mid  r_1 \cdot r_2
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			 \mid  r_1 + r_2   
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			 \mid r^*         
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\]
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\noindent
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The ingenious contribution of Brzozowski is the notion of \emph{derivatives} of
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regular expressions, written~$\_ \backslash \_$. It uses the auxiliary notion of
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$\nullable$ defined below.
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\begin{center}
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		\begin{tabular}{lcl}
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			$\nullable(\ZERO)$     & $\dn$ & $\mathit{false}$ \\  
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			$\nullable(\ONE)$      & $\dn$ & $\mathit{true}$ \\
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			$\nullable(c)$ 	       & $\dn$ & $\mathit{false}$ \\
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			$\nullable(r_1 + r_2)$ & $\dn$ & $\nullable(r_1) \vee \nullable(r_2)$ \\
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			$\nullable(r_1\cdot r_2)$  & $\dn$ & $\nullable(r_1) \wedge \nullable(r_2)$ \\
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			$\nullable(r^*)$       & $\dn$ & $\mathit{true}$ \\
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		\end{tabular}
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	\end{center}
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\begin{center}
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\begin{tabular}{lcl}
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		$\ZERO \backslash c$ & $\dn$ & $\ZERO$\\  
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		$\ONE \backslash c$  & $\dn$ & $\ZERO$\\
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		$d \backslash c$     & $\dn$ & 
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		$\mathit{if} \;c = d\;\mathit{then}\;\ONE\;\mathit{else}\;\ZERO$\\
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$(r_1 + r_2)\backslash c$     & $\dn$ & $r_1 \backslash c \,+\, r_2 \backslash c$\\
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$(r_1 \cdot r_2)\backslash c$ & $\dn$ & $\mathit{if} \, nullable(r_1)$\\
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	&   & $\mathit{then}\;(r_1\backslash c) \cdot r_2 \,+\, r_2\backslash c$\\
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	&   & $\mathit{else}\;(r_1\backslash c) \cdot r_2$\\
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	$(r^*)\backslash c$           & $\dn$ & $(r\backslash c) \cdot r^*$\\
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\end{tabular}
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\end{center}
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%Assuming the classic notion of a
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%\emph{language} of a regular expression, written $L(\_)$, t
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\noindent
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The main property of the derivative operation is that
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\begin{center}
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$c\!::\!s \in L(r)$ holds
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if and only if $s \in L(r\backslash c)$.
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\end{center}
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\noindent
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We can generalise the derivative operation shown above for single characters
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to strings as follows:
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\begin{center}
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\begin{tabular}{lcl}
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$r \backslash (c\!::\!s) $ & $\dn$ & $(r \backslash c) \backslash s$ \\
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$r \backslash [\,] $ & $\dn$ & $r$
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\end{tabular}
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\end{center}
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\noindent
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and then define Brzozowski's  regular-expression matching algorithm as:
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\[
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match\;s\;r \;\dn\; nullable(r\backslash s)
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\]
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\noindent
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Assuming the a string is givane as a sequence of characters, say $c_0c_1..c_n$, 
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this algorithm presented graphically is as follows:
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\begin{equation}\label{graph:*}
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\begin{tikzcd}
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r_0 \arrow[r, "\backslash c_0"]  & r_1 \arrow[r, "\backslash c_1"] & r_2 \arrow[r, dashed]  & r_n  \arrow[r,"\textit{nullable}?"] & \;\textrm{YES}/\textrm{NO}
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\end{tikzcd}
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\end{equation}
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\noindent
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where we start with  a regular expression  $r_0$, build successive
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derivatives until we exhaust the string and then use \textit{nullable}
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to test whether the result can match the empty string. It can  be
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relatively  easily shown that this matcher is correct  (that is given
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an $s = c_0...c_{n-1}$ and an $r_0$, it generates YES if and only if $s \in L(r_0)$).
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\subsection*{Values and the Lexing Algorithm by Sulzmann and Lu}
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One limitation of Brzozowski's algorithm is that it only produces a
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YES/NO answer for whether a string is being matched by a regular
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expression.  Sulzmann and Lu~\cite{Sulzmann2014} extended this algorithm
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to allow generation of an actual matching, called a \emph{value} or
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sometimes also \emph{lexical value}.  These values and regular
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expressions correspond to each other as illustrated in the following
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table:
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\begin{center}
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	\begin{tabular}{c@{\hspace{20mm}}c}
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		\begin{tabular}{@{}rrl@{}}
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			\multicolumn{3}{@{}l}{\textbf{Regular Expressions}}\medskip\\
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			$r$ & $::=$  & $\ZERO$\\
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			& $\mid$ & $\ONE$   \\
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			& $\mid$ & $c$          \\
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			& $\mid$ & $r_1 \cdot r_2$\\
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			& $\mid$ & $r_1 + r_2$   \\
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			\\
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			& $\mid$ & $r^*$         \\
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		\end{tabular}
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		&
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		\begin{tabular}{@{\hspace{0mm}}rrl@{}}
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			\multicolumn{3}{@{}l}{\textbf{Values}}\medskip\\
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			$v$ & $::=$  & \\
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			&        & $\Empty$   \\
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			& $\mid$ & $\Char(c)$          \\
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			& $\mid$ & $\Seq\,v_1\, v_2$\\
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			& $\mid$ & $\Left(v)$   \\
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			& $\mid$ & $\Right(v)$  \\
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			& $\mid$ & $\Stars\,[v_1,\ldots\,v_n]$ \\
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		\end{tabular}
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	\end{tabular}
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\end{center}
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\noindent
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The contribution of Sulzmann and Lu is an extension of Brzozowski's
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algorithm by a second phase (the first phase being building successive
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derivatives---see \eqref{graph:*}). In this second phase, a POSIX value 
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is generated in case the regular expression matches  the string. 
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Pictorially, the Sulzmann and Lu algorithm is as follows:
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\begin{ceqn}
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\begin{equation}\label{graph:2}
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\begin{tikzcd}
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r_0 \arrow[r, "\backslash c_0"]  \arrow[d] & r_1 \arrow[r, "\backslash c_1"] \arrow[d] & r_2 \arrow[r, dashed] \arrow[d] & r_n \arrow[d, "mkeps" description] \\
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v_0           & v_1 \arrow[l,"inj_{r_0} c_0"]                & v_2 \arrow[l, "inj_{r_1} c_1"]              & v_n \arrow[l, dashed]         
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\end{tikzcd}
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\end{equation}
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\end{ceqn}
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\noindent
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For convenience, we shall employ the following notations: the regular
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expression we start with is $r_0$, and the given string $s$ is composed
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of characters $c_0 c_1 \ldots c_{n-1}$. In  the first phase from the
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left to right, we build the derivatives $r_1$, $r_2$, \ldots  according
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to the characters $c_0$, $c_1$  until we exhaust the string and obtain
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the derivative $r_n$. We test whether this derivative is
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$\textit{nullable}$ or not. If not, we know the string does not match
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$r$ and no value needs to be generated. If yes, we start building the
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values incrementally by \emph{injecting} back the characters into the
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earlier values $v_n, \ldots, v_0$. This is the second phase of the
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algorithm from the right to left. For the first value $v_n$, we call the
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function $\textit{mkeps}$, which builds the lexical value
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for how the empty string has been matched by the (nullable) regular
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expression $r_n$. This function is defined as
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	\begin{center}
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		\begin{tabular}{lcl}
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			$\mkeps(\ONE)$ 		& $\dn$ & $\Empty$ \\
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			$\mkeps(r_{1}+r_{2})$	& $\dn$ 
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			& \textit{if} $\nullable(r_{1})$\\ 
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			& & \textit{then} $\Left(\mkeps(r_{1}))$\\ 
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			& & \textit{else} $\Right(\mkeps(r_{2}))$\\
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			$\mkeps(r_1\cdot r_2)$ 	& $\dn$ & $\Seq\,(\mkeps\,r_1)\,(\mkeps\,r_2)$\\
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			$mkeps(r^*)$	        & $\dn$ & $\Stars\,[]$
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		\end{tabular}
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	\end{center}
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\noindent 
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After the $\mkeps$-call, we inject back the characters one by one in order to build
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the lexical value $v_i$ for how the regex $r_i$ matches the string $s_i$
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($s_i = c_i \ldots c_{n-1}$ ) from the previous lexical value $v_{i+1}$.
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After injecting back $n$ characters, we get the lexical value for how $r_0$
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matches $s$. For this Sulzmann and Lu defined a function that reverses
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the ``chopping off'' of characters during the derivative phase. The
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corresponding function is called \emph{injection}, written
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$\textit{inj}$; it takes three arguments: the first one is a regular
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expression ${r_{i-1}}$, before the character is chopped off, the second
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is a character ${c_{i-1}}$, the character we want to inject and the
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third argument is the value ${v_i}$, into which one wants to inject the
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character (it corresponds to the regular expression after the character
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has been chopped off). The result of this function is a new value. The
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definition of $\textit{inj}$ is as follows: 
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\begin{center}
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\begin{tabular}{l@{\hspace{1mm}}c@{\hspace{1mm}}l}
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  $\textit{inj}\,(c)\,c\,Empty$            & $\dn$ & $Char\,c$\\
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  $\textit{inj}\,(r_1 + r_2)\,c\,\Left(v)$ & $\dn$ & $\Left(\textit{inj}\,r_1\,c\,v)$\\
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  $\textit{inj}\,(r_1 + r_2)\,c\,Right(v)$ & $\dn$ & $Right(\textit{inj}\,r_2\,c\,v)$\\
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  $\textit{inj}\,(r_1 \cdot r_2)\,c\,Seq(v_1,v_2)$ & $\dn$  & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\
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  $\textit{inj}\,(r_1 \cdot r_2)\,c\,\Left(Seq(v_1,v_2))$ & $\dn$  & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\
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  $\textit{inj}\,(r_1 \cdot r_2)\,c\,Right(v)$ & $\dn$  & $Seq(\textit{mkeps}(r_1),\textit{inj}\,r_2\,c\,v)$\\
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  $\textit{inj}\,(r^*)\,c\,Seq(v,Stars\,vs)$         & $\dn$  & $Stars((\textit{inj}\,r\,c\,v)\,::\,vs)$\\
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\end{tabular}
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\end{center}
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\noindent This definition is by recursion on the ``shape'' of regular
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expressions and values. 
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\subsection*{Simplification of Regular Expressions}
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The main drawback of building successive derivatives according
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to Brzozowski's definition is that they can grow very quickly in size.
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This is mainly due to the fact that the derivative operation generates
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often ``useless'' $\ZERO$s and $\ONE$s in derivatives.  As a result, if
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implemented naively both algorithms by Brzozowski and by Sulzmann and Lu
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are excruciatingly slow. For example when starting with the regular
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expression $(a + aa)^*$ and building 12 successive derivatives
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w.r.t.~the character $a$, one obtains a derivative regular expression
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with more than 8000 nodes (when viewed as a tree). Operations like
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$\textit{der}$ and $\nullable$ need to traverse such trees and
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consequently the bigger the size of the derivative the slower the
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algorithm. 
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Fortunately, one can simplify regular expressions after each derivative
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step. Various simplifications of regular expressions are possible, such
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as the simplification of $\ZERO + r$, $r + \ZERO$, $\ONE\cdot r$, $r
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\cdot \ONE$, and $r + r$ to just $r$. These simplifications do not
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affect the answer for whether a regular expression matches a string or
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not, but fortunately also do not affect the POSIX strategy of how
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regular expressions match strings---although the latter is much harder
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to establish. Some initial results in this regard have been
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obtained in \cite{AusafDyckhoffUrban2016}. 
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If we want the size of derivatives in Sulzmann and Lu's algorithm to
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stay below this bound, we would need more aggressive simplifications.
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Essentially we need to delete useless $\ZERO$s and $\ONE$s, as well as
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deleting duplicates whenever possible. For example, the parentheses in
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$(a+b) \cdot c + b\cdot c$ can be opened up to get $a\cdot c + b \cdot c + b
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\cdot c$, and then simplified to just $a \cdot c + b \cdot c$. Another
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example is simplifying $(a^*+a) + (a^*+ \ONE) + (a +\ONE)$ to just
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$a^*+a+\ONE$. Adding these more aggressive simplification rules help us
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to achieve the same size bound as that of the partial derivatives. 
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In order to implement the idea of ``spilling out alternatives'' and to
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make them compatible with the $\textit{inj}$-mechanism, we use
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\emph{bitcodes}. They were first introduced by Sulzmann and Lu.
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Here bits and bitcodes (lists of bits) are defined as:
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\begin{center}
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		$b ::=   S \mid  Z \qquad
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bs ::= [] \mid b:bs    
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$
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\end{center}
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\noindent
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The $S$ and $Z$ are arbitrary names for the bits in order to avoid 
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confusion with the regular expressions $\ZERO$ and $\ONE$. Bitcodes (or
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bit-lists) can be used to encode values (or incomplete values) in a
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compact form. This can be straightforwardly seen in the following
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coding function from values to bitcodes: 
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\begin{center}
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\begin{tabular}{lcl}
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  $\textit{code}(\Empty)$ & $\dn$ & $[]$\\
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  $\textit{code}(\Char\,c)$ & $\dn$ & $[]$\\
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  $\textit{code}(\Left\,v)$ & $\dn$ & $\Z :: code(v)$\\
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  $\textit{code}(\Right\,v)$ & $\dn$ & $\S :: code(v)$\\
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  $\textit{code}(\Seq\,v_1\,v_2)$ & $\dn$ & $code(v_1) \,@\, code(v_2)$\\
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  $\textit{code}(\Stars\,[])$ & $\dn$ & $[\Z]$\\
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  $\textit{code}(\Stars\,(v\!::\!vs))$ & $\dn$ & $\S :: code(v) \;@\;
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                                                 code(\Stars\,vs)$
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\end{tabular}    
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\end{center} 
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\noindent
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Here $\textit{code}$ encodes a value into a bitcodes by converting
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$\Left$ into $\Z$, $\Right$ into $\S$, the start point of a non-empty
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star iteration into $\S$, and the border where a local star terminates
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into $\Z$. This coding is lossy, as it throws away the information about
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characters, and also does not encode the ``boundary'' between two
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sequence values. Moreover, with only the bitcode we cannot even tell
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whether the $\S$s and $\Z$s are for $\Left/\Right$ or $\Stars$. The
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reason for choosing this compact way of storing information is that the
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relatively small size of bits can be easily manipulated and ``moved
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around'' in a regular expression. In order to recover values, we will 
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need the corresponding regular expression as an extra information. This
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means the decoding function is defined as:
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%\begin{definition}[Bitdecoding of Values]\mbox{}
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\begin{center}
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Chengsong
parents: 106
diff changeset
   393
\begin{tabular}{@{}l@{\hspace{1mm}}c@{\hspace{1mm}}l@{}}
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parents: 106
diff changeset
   394
  $\textit{decode}'\,bs\,(\ONE)$ & $\dn$ & $(\Empty, bs)$\\
b1e365afa29c changes
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parents: 106
diff changeset
   395
  $\textit{decode}'\,bs\,(c)$ & $\dn$ & $(\Char\,c, bs)$\\
b1e365afa29c changes
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parents: 106
diff changeset
   396
  $\textit{decode}'\,(\Z\!::\!bs)\;(r_1 + r_2)$ & $\dn$ &
b1e365afa29c changes
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parents: 106
diff changeset
   397
     $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}\;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   398
       (\Left\,v, bs_1)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   399
  $\textit{decode}'\,(\S\!::\!bs)\;(r_1 + r_2)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   400
     $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_2\;\textit{in}\;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   401
       (\Right\,v, bs_1)$\\                           
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   402
  $\textit{decode}'\,bs\;(r_1\cdot r_2)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   403
        $\textit{let}\,(v_1, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   404
  & &   $\textit{let}\,(v_2, bs_2) = \textit{decode}'\,bs_1\,r_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   405
  & &   \hspace{35mm}$\textit{in}\;(\Seq\,v_1\,v_2, bs_2)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   406
  $\textit{decode}'\,(\Z\!::\!bs)\,(r^*)$ & $\dn$ & $(\Stars\,[], bs)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   407
  $\textit{decode}'\,(\S\!::\!bs)\,(r^*)$ & $\dn$ & 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   408
         $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r\;\textit{in}$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   409
  & &   $\textit{let}\,(\Stars\,vs, bs_2) = \textit{decode}'\,bs_1\,r^*$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   410
  & &   \hspace{35mm}$\textit{in}\;(\Stars\,v\!::\!vs, bs_2)$\bigskip\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   411
  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   412
  $\textit{decode}\,bs\,r$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   413
     $\textit{let}\,(v, bs') = \textit{decode}'\,bs\,r\;\textit{in}$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   414
  & & $\textit{if}\;bs' = []\;\textit{then}\;\textit{Some}\,v\;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   415
       \textit{else}\;\textit{None}$                       
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   416
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   417
\end{center}    
b1e365afa29c changes
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parents: 106
diff changeset
   418
%\end{definition}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   419
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   420
Sulzmann and Lu's integrated the bitcodes into regular expressions to
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   421
create annotated regular expressions \cite{Sulzmann2014}.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   422
\emph{Annotated regular expressions} are defined by the following
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   423
grammar:%\comment{ALTS should have  an $as$ in  the definitions, not  just $a_1$ and $a_2$}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   424
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   425
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   426
\begin{tabular}{lcl}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   427
  $\textit{a}$ & $::=$  & $\textit{ZERO}$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   428
                  & $\mid$ & $\textit{ONE}\;\;bs$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   429
                  & $\mid$ & $\textit{CHAR}\;\;bs\,c$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   430
                  & $\mid$ & $\textit{ALTS}\;\;bs\,as$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   431
                  & $\mid$ & $\textit{SEQ}\;\;bs\,a_1\,a_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   432
                  & $\mid$ & $\textit{STAR}\;\;bs\,a$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   433
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   434
\end{center}  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   435
%(in \textit{ALTS})
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   436
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   437
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   438
where $bs$ stands for bitcodes, $a$  for $\bold{a}$nnotated regular
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   439
expressions and $as$ for a list of annotated regular expressions.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   440
The alternative constructor($\textit{ALTS}$) has been generalized to 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   441
accept a list of annotated regular expressions rather than just 2.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   442
We will show that these bitcodes encode information about
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   443
the (POSIX) value that should be generated by the Sulzmann and Lu
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   444
algorithm.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   445
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   446
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   447
To do lexing using annotated regular expressions, we shall first
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   448
transform the usual (un-annotated) regular expressions into annotated
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   449
regular expressions. This operation is called \emph{internalisation} and
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   450
defined as follows:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   451
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   452
%\begin{definition}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   453
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   454
\begin{tabular}{lcl}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   455
  $(\ZERO)^\uparrow$ & $\dn$ & $\textit{ZERO}$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   456
  $(\ONE)^\uparrow$ & $\dn$ & $\textit{ONE}\,[]$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   457
  $(c)^\uparrow$ & $\dn$ & $\textit{CHAR}\,[]\,c$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   458
  $(r_1 + r_2)^\uparrow$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   459
  $\textit{ALTS}\;[]\,List((\textit{fuse}\,[\Z]\,r_1^\uparrow),\,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   460
  (\textit{fuse}\,[\S]\,r_2^\uparrow))$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   461
  $(r_1\cdot r_2)^\uparrow$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   462
         $\textit{SEQ}\;[]\,r_1^\uparrow\,r_2^\uparrow$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   463
  $(r^*)^\uparrow$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   464
         $\textit{STAR}\;[]\,r^\uparrow$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   465
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   466
\end{center}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   467
%\end{definition}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   468
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   469
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   470
We use up arrows here to indicate that the basic un-annotated regular
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   471
expressions are ``lifted up'' into something slightly more complex. In the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   472
fourth clause, $\textit{fuse}$ is an auxiliary function that helps to
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   473
attach bits to the front of an annotated regular expression. Its
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   474
definition is as follows:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   475
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   476
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   477
\begin{tabular}{lcl}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   478
  $\textit{fuse}\;bs\,(\textit{ZERO})$ & $\dn$ & $\textit{ZERO}$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   479
  $\textit{fuse}\;bs\,(\textit{ONE}\,bs')$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   480
     $\textit{ONE}\,(bs\,@\,bs')$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   481
  $\textit{fuse}\;bs\,(\textit{CHAR}\,bs'\,c)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   482
     $\textit{CHAR}\,(bs\,@\,bs')\,c$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   483
  $\textit{fuse}\;bs\,(\textit{ALTS}\,bs'\,as)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   484
     $\textit{ALTS}\,(bs\,@\,bs')\,as$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   485
  $\textit{fuse}\;bs\,(\textit{SEQ}\,bs'\,a_1\,a_2)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   486
     $\textit{SEQ}\,(bs\,@\,bs')\,a_1\,a_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   487
  $\textit{fuse}\;bs\,(\textit{STAR}\,bs'\,a)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   488
     $\textit{STAR}\,(bs\,@\,bs')\,a$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   489
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   490
\end{center}  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   491
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   492
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   493
After internalising the regular expression, we perform successive
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   494
derivative operations on the annotated regular expressions. This
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   495
derivative operation is the same as what we had previously for the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   496
basic regular expressions, except that we beed to take care of
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   497
the bitcodes:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   498
109
Chengsong
parents: 108
diff changeset
   499
Chengsong
parents: 108
diff changeset
   500
\iffalse
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   501
 %\begin{definition}{bder}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   502
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   503
  \begin{tabular}{@{}lcl@{}}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   504
  $(\textit{ZERO})\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   505
  $(\textit{ONE}\;bs)\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   506
  $(\textit{CHAR}\;bs\,d)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   507
        $\textit{if}\;c=d\; \;\textit{then}\;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   508
         \textit{ONE}\;bs\;\textit{else}\;\textit{ZERO}$\\  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   509
  $(\textit{ALTS}\;bs\,as)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   510
  $\textit{ALTS}\;bs\,(as.map(\backslash c))$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   511
  $(\textit{SEQ}\;bs\,a_1\,a_2)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   512
     $\textit{if}\;\textit{bnullable}\,a_1$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   513
					       & &$\textit{then}\;\textit{ALTS}\,bs\,List((\textit{SEQ}\,[]\,(a_1\,\backslash c)\,a_2),$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   514
					       & &$\phantom{\textit{then}\;\textit{ALTS}\,bs\,}(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\,\backslash c)))$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   515
  & &$\textit{else}\;\textit{SEQ}\,bs\,(a_1\,\backslash c)\,a_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   516
  $(\textit{STAR}\,bs\,a)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   517
      $\textit{SEQ}\;bs\,(\textit{fuse}\, [\Z] (r\,\backslash c))\,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   518
       (\textit{STAR}\,[]\,r)$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   519
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   520
\end{center}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   521
%\end{definition}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   522
109
Chengsong
parents: 108
diff changeset
   523
\begin{center}
Chengsong
parents: 108
diff changeset
   524
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents: 108
diff changeset
   525
  $(\textit{ZERO})\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
Chengsong
parents: 108
diff changeset
   526
  $(_{bs}\textit{ONE})\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
Chengsong
parents: 108
diff changeset
   527
  $(_{bs}\textit{CHAR}\;d)\,\backslash c$ & $\dn$ &
Chengsong
parents: 108
diff changeset
   528
        $\textit{if}\;c=d\; \;\textit{then}\;
Chengsong
parents: 108
diff changeset
   529
         _{bs}\textit{ONE}\;\textit{else}\;\textit{ZERO}$\\  
Chengsong
parents: 108
diff changeset
   530
  $(_{bs}\textit{ALTS}\;as)\,\backslash c$ & $\dn$ &
Chengsong
parents: 108
diff changeset
   531
  $_{bs}\textit{ALTS}\;(as.map(\backslash c))$\\
Chengsong
parents: 108
diff changeset
   532
  $(_{bs}\textit{SEQ}\;a_1\,a_2)\,\backslash c$ & $\dn$ &
Chengsong
parents: 108
diff changeset
   533
     $\textit{if}\;\textit{bnullable}\,a_1$\\
Chengsong
parents: 108
diff changeset
   534
					       & &$\textit{then}\;_{bs}\textit{ALTS}\,List((_{[]}\textit{SEQ}\,(a_1\,\backslash c)\,a_2),$\\
Chengsong
parents: 108
diff changeset
   535
					       & &$\phantom{\textit{then}\;_{bs}\textit{ALTS}\,}(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\,\backslash c)))$\\
Chengsong
parents: 108
diff changeset
   536
  & &$\textit{else}\;_{bs}\textit{SEQ}\,(a_1\,\backslash c)\,a_2$\\
Chengsong
parents: 108
diff changeset
   537
  $(_{bs}\textit{STAR}\,a)\,\backslash c$ & $\dn$ &
Chengsong
parents: 108
diff changeset
   538
      $_{bs}\textit{SEQ}\;(\textit{fuse}\, [\Z] (r\,\backslash c))\,
Chengsong
parents: 108
diff changeset
   539
       (_{bs}\textit{STAR}\,[]\,r)$
Chengsong
parents: 108
diff changeset
   540
\end{tabular}    
Chengsong
parents: 108
diff changeset
   541
\end{center}    
Chengsong
parents: 108
diff changeset
   542
%\end{definition}
Chengsong
parents: 108
diff changeset
   543
\fi
Chengsong
parents: 108
diff changeset
   544
Chengsong
parents: 108
diff changeset
   545
\begin{center}
Chengsong
parents: 108
diff changeset
   546
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents: 108
diff changeset
   547
  $(\ZERO)\,\backslash c$ & $\dn$ & $\ZERO$\\  
Chengsong
parents: 108
diff changeset
   548
  $(_{bs}\ONE)\,\backslash c$ & $\dn$ & $\ZERO$\\  
Chengsong
parents: 108
diff changeset
   549
  $(_{bs}{\bf d})\,\backslash c$ & $\dn$ &
Chengsong
parents: 108
diff changeset
   550
        $\textit{if}\;c=d\; \;\textit{then}\;
Chengsong
parents: 108
diff changeset
   551
         _{bs}\ONE\;\textit{else}\;\ZERO$\\  
Chengsong
parents: 108
diff changeset
   552
  $(_{bs}\oplus \;as)\,\backslash c$ & $\dn$ &
Chengsong
parents: 108
diff changeset
   553
  $_{bs}\oplus\;(as.map(\backslash c))$\\
Chengsong
parents: 108
diff changeset
   554
  $(_{bs}\;a_1\cdot a_2)\,\backslash c$ & $\dn$ &
Chengsong
parents: 108
diff changeset
   555
     $\textit{if}\;\textit{bnullable}\,a_1$\\
Chengsong
parents: 108
diff changeset
   556
					       & &$\textit{then}\;_{bs}\oplus\,[(_{[]}\,(a_1\,\backslash c)\cdot\,a_2),$\\
Chengsong
parents: 108
diff changeset
   557
					       & &$\phantom{\textit{then},\;_{bs}\oplus\,}(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\,\backslash c))]$\\
Chengsong
parents: 108
diff changeset
   558
  & &$\textit{else}\;_{bs}\,(a_1\,\backslash c)\cdot a_2$\\
Chengsong
parents: 108
diff changeset
   559
  $(_{bs}a^*)\,\backslash c$ & $\dn$ &
Chengsong
parents: 108
diff changeset
   560
      $_{bs}\;((\textit{fuse}\, [\Z] (r\,\backslash c))\cdot
Chengsong
parents: 108
diff changeset
   561
       (_{[]}r^*))$
Chengsong
parents: 108
diff changeset
   562
\end{tabular}    
Chengsong
parents: 108
diff changeset
   563
\end{center}    
Chengsong
parents: 108
diff changeset
   564
Chengsong
parents: 108
diff changeset
   565
%\end{definition}
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   566
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   567
For instance, when we unfold $\textit{STAR} \; bs \; a$ into a sequence,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   568
we need to attach an additional bit $Z$ to the front of $r \backslash c$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   569
to indicate that there is one more star iteration. Also the $SEQ$ clause
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   570
is more subtle---when $a_1$ is $\textit{bnullable}$ (here
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   571
\textit{bnullable} is exactly the same as $\textit{nullable}$, except
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   572
that it is for annotated regular expressions, therefore we omit the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   573
definition). Assume that $bmkeps$ correctly extracts the bitcode for how
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   574
$a_1$ matches the string prior to character $c$ (more on this later),
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   575
then the right branch of $ALTS$, which is $fuse \; bmkeps \;  a_1 (a_2
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   576
\backslash c)$ will collapse the regular expression $a_1$(as it has
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   577
already been fully matched) and store the parsing information at the
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head of the regular expression $a_2 \backslash c$ by fusing to it. The
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   579
bitsequence $bs$, which was initially attached to the head of $SEQ$, has
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   580
now been elevated to the top-level of $ALTS$, as this information will be
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   581
needed whichever way the $SEQ$ is matched---no matter whether $c$ belongs
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   582
to $a_1$ or $ a_2$. After building these derivatives and maintaining all
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   583
the lexing information, we complete the lexing by collecting the
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bitcodes using a generalised version of the $\textit{mkeps}$ function
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   585
for annotated regular expressions, called $\textit{bmkeps}$:
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   586
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   587
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   588
%\begin{definition}[\textit{bmkeps}]\mbox{}
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   589
\begin{center}
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   590
\begin{tabular}{lcl}
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   591
  $\textit{bmkeps}\,(\textit{ONE}\;bs)$ & $\dn$ & $bs$\\
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   592
  $\textit{bmkeps}\,(\textit{ALTS}\;bs\,a::as)$ & $\dn$ &
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   593
     $\textit{if}\;\textit{bnullable}\,a$\\
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  & &$\textit{then}\;bs\,@\,\textit{bmkeps}\,a$\\
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  & &$\textit{else}\;bs\,@\,\textit{bmkeps}\,(\textit{ALTS}\;bs\,as)$\\
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   596
  $\textit{bmkeps}\,(\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ &
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   597
     $bs \,@\,\textit{bmkeps}\,a_1\,@\, \textit{bmkeps}\,a_2$\\
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   598
  $\textit{bmkeps}\,(\textit{STAR}\;bs\,a)$ & $\dn$ &
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   599
     $bs \,@\, [\S]$
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   600
\end{tabular}    
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   601
\end{center}    
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   602
%\end{definition}
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   603
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   604
\noindent
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   605
This function completes the value information by travelling along the
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   606
path of the regular expression that corresponds to a POSIX value and
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   607
collecting all the bitcodes, and using $S$ to indicate the end of star
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   608
iterations. If we take the bitcodes produced by $\textit{bmkeps}$ and
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   609
decode them, we get the value we expect. The corresponding lexing
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   610
algorithm looks as follows:
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   611
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   612
\begin{center}
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diff changeset
   613
\begin{tabular}{lcl}
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   614
  $\textit{blexer}\;r\,s$ & $\dn$ &
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      $\textit{let}\;a = (r^\uparrow)\backslash s\;\textit{in}$\\                
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  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
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  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
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   618
  & & $\;\;\textit{else}\;\textit{None}$
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diff changeset
   619
\end{tabular}
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diff changeset
   620
\end{center}
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   621
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   622
\noindent
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   623
In this definition $\_\backslash s$ is the  generalisation  of the derivative
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   624
operation from characters to strings (just like the derivatives for un-annotated
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   625
regular expressions).
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   626
108
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   628
\subsection*{Our Simplification Rules}
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107
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   630
The main point of the bitcodes and annotated regular expressions is that
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   631
we can apply rather aggressive (in terms of size) simplification rules
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   632
in order to keep derivatives small. We have developed such
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   633
``aggressive'' simplification rules and generated test data that show
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that the expected bound can be achieved. Obviously we could only
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   635
partially cover  the search space as there are infinitely many regular
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   636
expressions and strings. 
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diff changeset
   637
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   638
One modification we introduced is to allow a list of annotated regular
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expressions in the \textit{ALTS} constructor. This allows us to not just
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delete unnecessary $\ZERO$s and $\ONE$s from regular expressions, but
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   641
also unnecessary ``copies'' of regular expressions (very similar to
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   642
simplifying $r + r$ to just $r$, but in a more general setting). Another
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   643
modification is that we use simplification rules inspired by Antimirov's
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work on partial derivatives. They maintain the idea that only the first
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   645
``copy'' of a regular expression in an alternative contributes to the
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   646
calculation of a POSIX value. All subsequent copies can be pruned away from
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diff changeset
   647
the regular expression. A recursive definition of our  simplification function 
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that looks somewhat similar to our Scala code is given below:
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%\comment{Use $\ZERO$, $\ONE$ and so on. 
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%Is it $ALTS$ or $ALTS$?}\\
b1e365afa29c changes
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diff changeset
   651
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diff changeset
   652
\begin{center}
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diff changeset
   653
  \begin{tabular}{@{}lcl@{}}
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diff changeset
   654
   
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  $\textit{simp} \; (\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ & $ (\textit{simp} \; a_1, \textit{simp}  \; a_2) \; \textit{match} $ \\
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   &&$\quad\textit{case} \; (\ZERO, \_) \Rightarrow  \ZERO$ \\
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   657
   &&$\quad\textit{case} \; (\_, \ZERO) \Rightarrow  \ZERO$ \\
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   &&$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$ \\
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   &&$\quad\textit{case} \; (a_1', \ONE) \Rightarrow  \textit{fuse} \; bs \;  a_1'$ \\
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diff changeset
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   &&$\quad\textit{case} \; (a_1', a_2') \Rightarrow  \textit{SEQ} \; bs \; a_1' \;  a_2'$ \\
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diff changeset
   661
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diff changeset
   662
  $\textit{simp} \; (\textit{ALTS}\;bs\,as)$ & $\dn$ & $\textit{distinct}( \textit{flatten} ( \textit{map simp as})) \; \textit{match} $ \\
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   663
  &&$\quad\textit{case} \; [] \Rightarrow  \ZERO$ \\
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diff changeset
   664
   &&$\quad\textit{case} \; a :: [] \Rightarrow  \textit{fuse bs a}$ \\
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   665
   &&$\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$\\ 
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diff changeset
   666
b1e365afa29c changes
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diff changeset
   667
   $\textit{simp} \; a$ & $\dn$ & $\textit{a} \qquad \textit{otherwise}$   
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diff changeset
   668
\end{tabular}    
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diff changeset
   669
\end{center}    
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diff changeset
   670
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diff changeset
   671
\noindent
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diff changeset
   672
The simplification does a pattern matching on the regular expression.
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diff changeset
   673
When it detected that the regular expression is an alternative or
b1e365afa29c changes
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diff changeset
   674
sequence, it will try to simplify its children regular expressions
b1e365afa29c changes
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diff changeset
   675
recursively and then see if one of the children turn into $\ZERO$ or
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diff changeset
   676
$\ONE$, which might trigger further simplification at the current level.
b1e365afa29c changes
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diff changeset
   677
The most involved part is the $\textit{ALTS}$ clause, where we use two
b1e365afa29c changes
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diff changeset
   678
auxiliary functions $\textit{flatten}$ and $\textit{distinct}$ to open up nested
b1e365afa29c changes
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diff changeset
   679
$\textit{ALTS}$ and reduce as many duplicates as possible. Function
b1e365afa29c changes
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diff changeset
   680
$\textit{distinct}$  keeps the first occurring copy only and remove all later ones
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diff changeset
   681
when detected duplicates. Function $\textit{flatten}$ opens up nested \textit{ALTS}.
b1e365afa29c changes
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diff changeset
   682
Its recursive definition is given below:
b1e365afa29c changes
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diff changeset
   683
b1e365afa29c changes
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diff changeset
   684
 \begin{center}
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diff changeset
   685
  \begin{tabular}{@{}lcl@{}}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   686
  $\textit{flatten} \; (\textit{ALTS}\;bs\,as) :: as'$ & $\dn$ & $(\textit{map} \;
b1e365afa29c changes
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parents: 106
diff changeset
   687
     (\textit{fuse}\;bs)\; \textit{as}) \; @ \; \textit{flatten} \; as' $ \\
b1e365afa29c changes
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diff changeset
   688
  $\textit{flatten} \; \textit{ZERO} :: as'$ & $\dn$ & $ \textit{flatten} \;  as' $ \\
b1e365afa29c changes
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parents: 106
diff changeset
   689
    $\textit{flatten} \; a :: as'$ & $\dn$ & $a :: \textit{flatten} \; as'$ \quad(otherwise) 
b1e365afa29c changes
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diff changeset
   690
\end{tabular}    
b1e365afa29c changes
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diff changeset
   691
\end{center}  
b1e365afa29c changes
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parents: 106
diff changeset
   692
b1e365afa29c changes
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parents: 106
diff changeset
   693
\noindent
b1e365afa29c changes
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diff changeset
   694
Here $\textit{flatten}$ behaves like the traditional functional programming flatten
b1e365afa29c changes
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diff changeset
   695
function, except that it also removes $\ZERO$s. Or in terms of regular expressions, it
b1e365afa29c changes
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parents: 106
diff changeset
   696
removes parentheses, for example changing $a+(b+c)$ into $a+b+c$.
b1e365afa29c changes
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parents: 106
diff changeset
   697
b1e365afa29c changes
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parents: 106
diff changeset
   698
Suppose we apply simplification after each derivative step, and view
b1e365afa29c changes
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parents: 106
diff changeset
   699
these two operations as an atomic one: $a \backslash_{simp}\,c \dn
b1e365afa29c changes
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parents: 106
diff changeset
   700
\textit{simp}(a \backslash c)$. Then we can use the previous natural
b1e365afa29c changes
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parents: 106
diff changeset
   701
extension from derivative w.r.t.~character to derivative
b1e365afa29c changes
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diff changeset
   702
w.r.t.~string:%\comment{simp in  the [] case?}
b1e365afa29c changes
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parents: 106
diff changeset
   703
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   704
\begin{center}
b1e365afa29c changes
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diff changeset
   705
\begin{tabular}{lcl}
b1e365afa29c changes
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parents: 106
diff changeset
   706
$r \backslash_{simp} (c\!::\!s) $ & $\dn$ & $(r \backslash_{simp}\, c) \backslash_{simp}\, s$ \\
b1e365afa29c changes
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diff changeset
   707
$r \backslash_{simp} [\,] $ & $\dn$ & $r$
b1e365afa29c changes
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diff changeset
   708
\end{tabular}
b1e365afa29c changes
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diff changeset
   709
\end{center}
b1e365afa29c changes
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diff changeset
   710
b1e365afa29c changes
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diff changeset
   711
\noindent
b1e365afa29c changes
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diff changeset
   712
we obtain an optimised version of the algorithm:
b1e365afa29c changes
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diff changeset
   713
b1e365afa29c changes
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diff changeset
   714
 \begin{center}
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diff changeset
   715
\begin{tabular}{lcl}
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diff changeset
   716
  $\textit{blexer\_simp}\;r\,s$ & $\dn$ &
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diff changeset
   717
      $\textit{let}\;a = (r^\uparrow)\backslash_{simp}\, s\;\textit{in}$\\                
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diff changeset
   718
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
b1e365afa29c changes
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diff changeset
   719
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
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diff changeset
   720
  & & $\;\;\textit{else}\;\textit{None}$
b1e365afa29c changes
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diff changeset
   721
\end{tabular}
b1e365afa29c changes
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diff changeset
   722
\end{center}
b1e365afa29c changes
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diff changeset
   723
b1e365afa29c changes
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diff changeset
   724
\noindent
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diff changeset
   725
This algorithm keeps the regular expression size small, for example,
b1e365afa29c changes
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diff changeset
   726
with this simplification our previous $(a + aa)^*$ example's 8000 nodes
b1e365afa29c changes
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diff changeset
   727
will be reduced to just 6 and stays constant, no matter how long the
b1e365afa29c changes
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diff changeset
   728
input string is.
b1e365afa29c changes
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diff changeset
   729
b1e365afa29c changes
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diff changeset
   730
b1e365afa29c changes
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diff changeset
   731
94
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parents:
diff changeset
   732
\section{Introduction}
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parents:
diff changeset
   733
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   734
While we believe derivatives of regular expressions, written
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   735
$r\backslash s$, are a beautiful concept (in terms of ease of
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   736
implementing them in functional programming languages and in terms of
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   737
reasoning about them formally), they have one major drawback: every
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   738
derivative step can make regular expressions grow drastically in
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   739
size. This in turn has negative effect on the runtime of the
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   740
corresponding lexing algorithms. Consider for example the regular
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   741
expression $(a+aa)^*$ and the short string $aaaaaaaaaaaa$. The
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   742
corresponding derivative contains already 8668 nodes where we assume
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   743
the derivative is given as a tree. The reason for the poor runtime of
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   744
the derivative-based lexing algorithms is that they need to traverse
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   745
such trees over and over again. The solution is to find a complete set
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   746
of simplification rules that keep the sizes of derivatives uniformly
105
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   747
small.
94
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parents:
diff changeset
   748
105
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   749
For reasons beyond this report, it turns out that a complete set of
317a7d54ebcc updated
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parents: 103
diff changeset
   750
simplification rules depends on values being encoded as
317a7d54ebcc updated
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parents: 103
diff changeset
   751
bitsequences.\footnote{Values are the results the lexing algorithms
317a7d54ebcc updated
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parents: 103
diff changeset
   752
  generate; they encode how a regular expression matched a string.} We
317a7d54ebcc updated
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parents: 103
diff changeset
   753
already know that the lexing algorithm using bitsequences but
317a7d54ebcc updated
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parents: 103
diff changeset
   754
\emph{without} simplification is correct, albeilt horribly
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   755
slow. Therefore in the past 6 months I was trying to prove that the
105
317a7d54ebcc updated
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parents: 103
diff changeset
   756
algorithm using bitsequences plus our simplification rules is
106
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parents: 105 104
diff changeset
   757
also correct. Formally this amounts to show that
100
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parents: 95
diff changeset
   758
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   759
\begin{equation}\label{mainthm}
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   760
\blexers \; r \; s = \blexer \;r\;s
397b31867ea6 copied christian changes
Chengsong
parents: 95
diff changeset
   761
\end{equation}
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   762
94
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parents:
diff changeset
   763
\noindent
105
317a7d54ebcc updated
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parents: 103
diff changeset
   764
whereby $\blexers$ simplifies (makes derivatives smaller) in each
317a7d54ebcc updated
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diff changeset
   765
step, whereas with $\blexer$ the size can grow exponentially. This
106
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   766
would be an important milestone for my thesis, because we already
105
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diff changeset
   767
have a very good idea how to establish that our set our simplification
317a7d54ebcc updated
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diff changeset
   768
rules keeps the size of derivativs below a relatively tight bound.
100
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parents: 95
diff changeset
   769
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   770
In order to prove the main theorem in \eqref{mainthm}, we need to prove that the
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   771
two functions produce the same output. The definition of these two  functions 
100
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   772
is shown below.
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   773
94
Chengsong
parents:
diff changeset
   774
\begin{center}
Chengsong
parents:
diff changeset
   775
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
   776
  $\textit{blexer}\;r\,s$ & $\dn$ &
Chengsong
parents:
diff changeset
   777
      $\textit{let}\;a = (r^\uparrow)\backslash s\;\textit{in}$\\                
Chengsong
parents:
diff changeset
   778
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
Chengsong
parents:
diff changeset
   779
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
Chengsong
parents:
diff changeset
   780
  & & $\;\;\textit{else}\;\textit{None}$
Chengsong
parents:
diff changeset
   781
\end{tabular}
Chengsong
parents:
diff changeset
   782
\end{center}
Chengsong
parents:
diff changeset
   783
100
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parents: 95
diff changeset
   784
\begin{center}
94
Chengsong
parents:
diff changeset
   785
\begin{tabular}{lcl}
100
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   786
  $\blexers \; r \, s$ &$\dn$ &
397b31867ea6 copied christian changes
Chengsong
parents: 95
diff changeset
   787
    $\textit{let} \; a = (r^\uparrow)\backslash_{simp}\, s\; \textit{in}$\\
397b31867ea6 copied christian changes
Chengsong
parents: 95
diff changeset
   788
  & & $\; \; \textit{if} \; \textit{bnullable}(a)$\\
397b31867ea6 copied christian changes
Chengsong
parents: 95
diff changeset
   789
  & & $\; \; \textit{then} \; \textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   790
  & & $\;\;   \textit{else}\;\textit{None}$
94
Chengsong
parents:
diff changeset
   791
\end{tabular}
Chengsong
parents:
diff changeset
   792
\end{center}
Chengsong
parents:
diff changeset
   793
\noindent
105
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parents: 103
diff changeset
   794
In these definitions $(r^\uparrow)$ is a kind of coding function that
317a7d54ebcc updated
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parents: 103
diff changeset
   795
is the same in each case, similarly the decode and the \textit{bmkeps}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   796
are functions that are the same in each case. Our main
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   797
theorem~\eqref{mainthm} therefore boils down to proving the following
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   798
two propositions (depending on which branch the if-else clause
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   799
takes). They establish how the derivatives \emph{with} simplification
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   800
do not change the computed result:
94
Chengsong
parents:
diff changeset
   801
Chengsong
parents:
diff changeset
   802
\begin{itemize}
105
317a7d54ebcc updated
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diff changeset
   803
\item{(a)} If a string $s$ is in the language of $L(r)$, then \\
100
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   804
$\textit{bmkeps} (r^\uparrow)\backslash_{simp}\,s = \textit{bmkeps} (r^\uparrow)\backslash s$,\\
105
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diff changeset
   805
\item{(b)} If a string $s$ is in the language $L(r)$, then 
100
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   806
$\rup \backslash_{simp} \,s$ is not nullable.
94
Chengsong
parents:
diff changeset
   807
\end{itemize}
100
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parents: 95
diff changeset
   808
94
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parents:
diff changeset
   809
\noindent
106
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   810
We have already proved the second part  in Isabelle. This is actually
105
317a7d54ebcc updated
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parents: 103
diff changeset
   811
not too difficult because we can show that simplification does not
317a7d54ebcc updated
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parents: 103
diff changeset
   812
change the language of simplified regular expressions.
100
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parents: 95
diff changeset
   813
105
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parents: 103
diff changeset
   814
If we can prove the first part, that is the bitsequence algorithm with
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   815
simplification produces the same result as the one without
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   816
simplification, then we are done.  Unfortunately that part requires
317a7d54ebcc updated
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parents: 103
diff changeset
   817
more effort, because simplification does not only need to \emph{not}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   818
change the language, but also not change the value (that is the
317a7d54ebcc updated
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parents: 103
diff changeset
   819
computed result).
100
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parents: 95
diff changeset
   820
105
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parents: 103
diff changeset
   821
%\bigskip\noindent\rule[1.5ex]{\linewidth}{5pt}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   822
%Do you want to keep this? You essentially want to say that the old
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   823
%method used retrieve, which unfortunately cannot be adopted to 
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   824
%the simplification rules. You could just say that and give an example.
317a7d54ebcc updated
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parents: 103
diff changeset
   825
%However you have to think about how you give the example....nobody knows
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   826
%about AZERO etc yet. Maybe it might be better to use normal regexes
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   827
%like $a + aa$, but annotate bitsequences as subscript like $_1(_0a + _1aa)$.
104
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parents: 103
diff changeset
   828
105
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parents: 103
diff changeset
   829
%\bigskip\noindent\rule[1.5ex]{\linewidth}{5pt}
317a7d54ebcc updated
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parents: 103
diff changeset
   830
%REPLY:\\
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   831
%Yes, I am essentially saying that the old method
317a7d54ebcc updated
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parents: 103
diff changeset
   832
%cannot be adopted without adjustments.
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   833
%But this does not mean we should skip
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   834
%the proof of the bit-coded algorithm
317a7d54ebcc updated
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parents: 103
diff changeset
   835
%as it is still the main direction we are looking into
317a7d54ebcc updated
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parents: 103
diff changeset
   836
%to prove things. We are trying to modify
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   837
%the old proof to suit our needs, but not give 
317a7d54ebcc updated
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parents: 103
diff changeset
   838
%up it totally, that is why i believe the old 
317a7d54ebcc updated
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parents: 103
diff changeset
   839
%proof is fundamental in understanding
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   840
%what we are doing in the past 6 months.
317a7d54ebcc updated
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parents: 103
diff changeset
   841
%\bigskip\noindent\rule[1.5ex]{\linewidth}{5pt}
100
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   842
106
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   843
\subsubsection*{Existing Proof}
100
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parents: 95
diff changeset
   844
104
e7ba4da53930 merged christian changes
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parents: 103
diff changeset
   845
For this we have started with looking at the original proof that
105
317a7d54ebcc updated
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parents: 103
diff changeset
   846
established that the bitsequence algorrithm produces the same result
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   847
as the algorithm not using bitsequences. Formally this proof
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   848
established
100
397b31867ea6 copied christian changes
Chengsong
parents: 95
diff changeset
   849
105
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Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   850
\begin{equation}\label{lexer}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   851
\blexer \; (r^\uparrow)  s = \lexer \;r \;s
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   852
\end{equation}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   853
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   854
%\noindent
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   855
%might provide us insight into proving 
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   856
%\begin{center}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   857
%$\blexer \; r^\uparrow \;s = \blexers \; r^\uparrow \;s$
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   858
%\end{center}
104
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   859
94
Chengsong
parents:
diff changeset
   860
\noindent
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   861
The proof uses two ``tricks''. One is that it uses a \flex-function
104
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   862
94
Chengsong
parents:
diff changeset
   863
\begin{center}
Chengsong
parents:
diff changeset
   864
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
   865
$\textit{flex} \;r\; f\; (c\!::\!s) $ & $\dn$ & $\textit{flex} \;  (r\backslash c) \;(\lambda v. f (inj \; r \; c \; v)) \;s$ \\
Chengsong
parents:
diff changeset
   866
$\textit{flex} \;r\; f\;  [\,] $ & $\dn$ & $f$
Chengsong
parents:
diff changeset
   867
\end{tabular}
Chengsong
parents:
diff changeset
   868
\end{center}
104
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   869
94
Chengsong
parents:
diff changeset
   870
\noindent
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   871
and then proves for the right-hand side in \eqref{lexer}
104
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   872
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   873
\begin{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   874
$\lexer \;r\; s = \flex \;\textit{id} \; r\;s \;(\mkeps \; (r\backslash s))$
104
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   875
\end{center}.
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   876
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   877
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   878
104
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   879
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   880
\noindent
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   881
The $\flex$-function essentially does lexing by
105
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   882
stacking up injection functions while doing derivatives.
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   883
94
Chengsong
parents:
diff changeset
   884
explicitly showing the order of characters being
Chengsong
parents:
diff changeset
   885
injected back in each step.
Chengsong
parents:
diff changeset
   886
With $\flex$ we can write $\lexer$ this way: 
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   887
94
Chengsong
parents:
diff changeset
   888
\begin{center}
Chengsong
parents:
diff changeset
   889
$\lexer \;r\; s = \flex \;id \; r\;s \;(\mkeps r\backslash s)$
Chengsong
parents:
diff changeset
   890
\end{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   891
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   892
%\noindent
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   893
%$\flex$ focuses on the injections instead of the derivatives ,
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   894
%compared to the original definition of $\lexer$, which puts equal
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   895
%amount of emphasis on injection and derivative with respect to each
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   896
%character:
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   897
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   898
%\begin{center}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   899
%\begin{tabular}{lcl}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   900
%$\textit{lexer} \; r\; (c\!::\!s) $ & $\dn$ & $\textit{case} \; \lexer \; (r\backslash c) \;s \; %\textit{of}$ \\
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   901
% & & $\textit{None} \; \Longrightarrow \; \textit{None}$\\
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   902
%  & & $\textbar \; v \; \Longrightarrow \; \inj \; r\;c\;v$\\
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   903
%$\textit{lexer} \; r\;  [\,] $ & $\dn$ & $\textit{if} \; \nullable (r) \; \textit{then} \; \mkeps% (r) \; \textit{else} \;None$
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   904
%\end{tabular}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   905
%\end{center}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   906
94
Chengsong
parents:
diff changeset
   907
\noindent
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   908
The crux in the existing proof is how $\flex$ relates to injection, namely
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   909
94
Chengsong
parents:
diff changeset
   910
\begin{center}
Chengsong
parents:
diff changeset
   911
$\flex \; r \; id \; (s@[c]) \; v = \flex \;  r \; id \; s \; (inj \; (r\backslash s) \; c\; v)$.
Chengsong
parents:
diff changeset
   912
\end{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   913
94
Chengsong
parents:
diff changeset
   914
\noindent
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   915
This property allows one to rewrite an induction hypothesis like 
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   916
94
Chengsong
parents:
diff changeset
   917
\begin{center} 
Chengsong
parents:
diff changeset
   918
$ \flex \; r\; id\; (s@[c])\; v = \textit{decode} \;( \textit{retrieve}\; (\rup \backslash s) \; (\inj \; (r\backslash s) \;c\;v)\;) r$
Chengsong
parents:
diff changeset
   919
\end{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   920
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   921
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   922
\subsubsection{Retrieve Function}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   923
The crucial point is to find the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   924
$\textit{POSIX}$  information of a regular expression and how it is modified,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   925
augmented and propagated 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   926
during simplification in parallel with the regular expression that
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   927
has not been simplified in the subsequent derivative operations.  To aid this,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   928
we use the helper function retrieve described by Sulzmann and Lu:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   929
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   930
\begin{tabular}{@{}l@{\hspace{2mm}}c@{\hspace{2mm}}l@{}}
110
Chengsong
parents: 109
diff changeset
   931
  $\textit{retrieve}\,(_{bs}\ONE)\,\Empty$ & $\dn$ & $bs$\\
Chengsong
parents: 109
diff changeset
   932
  $\textit{retrieve}\,(_{bs}{\bf c})\,(\Char\,d)$ & $\dn$ & $bs$\\
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   933
  $\textit{retrieve}\,(\textit{ALTS}\,bs\,a::as)\,(\Left\,v)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   934
     $bs \,@\, \textit{retrieve}\,a\,v$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   935
  $\textit{retrieve}\,(\textit{ALTS}\,bs\,a::as)\,(\Right\,v)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   936
  $bs \,@\, \textit{retrieve}\,(\textit{ALTS}\,bs\,as)\,v$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   937
  $\textit{retrieve}\,(\textit{SEQ}\,bs\,a_1\,a_2)\,(\Seq\,v_1\,v_2)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   938
     $bs \,@\,\textit{retrieve}\,a_1\,v_1\,@\, \textit{retrieve}\,a_2\,v_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   939
  $\textit{retrieve}\,(\textit{STAR}\,bs\,a)\,(\Stars\,[])$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   940
     $bs \,@\, [\S]$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   941
  $\textit{retrieve}\,(\textit{STAR}\,bs\,a)\,(\Stars\,(v\!::\!vs))$ & $\dn$ &\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   942
  \multicolumn{3}{l}{
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   943
     \hspace{3cm}$bs \,@\, [\Z] \,@\, \textit{retrieve}\,a\,v\,@\,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   944
                    \textit{retrieve}\,(\textit{STAR}\,[]\,a)\,(\Stars\,vs)$}\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   945
\end{tabular}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   946
\end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   947
%\comment{Did not read further}\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   948
This function assembles the bitcode 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   949
%that corresponds to a lexical value for how
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   950
%the current derivative matches the suffix of the string(the characters that
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   951
%have not yet appeared, but will appear as the successive derivatives go on.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   952
%How do we get this "future" information? By the value $v$, which is
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   953
%computed by a pass of the algorithm that uses
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   954
%$inj$ as described in the previous section).  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   955
using information from both the derivative regular expression and the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   956
value. Sulzmann and Lu poroposed this function, but did not prove
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   957
anything about it. Ausaf and Urban used it to connect the bitcoded
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   958
algorithm to the older algorithm by the following equation:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   959
 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   960
 \begin{center} $inj \;a\; c \; v = \textit{decode} \; (\textit{retrieve}\;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   961
	 (r^\uparrow)\backslash_{simp} \,c)\,v)$ 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   962
 \end{center} 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   963
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   964
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   965
whereby $r^\uparrow$ stands for the internalised version of $r$. Ausaf
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   966
and Urban also used this fact to prove  the correctness of bitcoded
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   967
algorithm without simplification.  Our purpose of using this, however,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   968
is to establish 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   969
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   970
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   971
$ \textit{retrieve} \;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   972
a \; v \;=\; \textit{retrieve}  \; (\textit{simp}\,a) \; v'.$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   973
\end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   974
The idea is that using $v'$, a simplified version of $v$ that had gone
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   975
through the same simplification step as $\textit{simp}(a)$, we are able
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   976
to extract the bitcode that gives the same parsing information as the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   977
unsimplified one. However, we noticed that constructing such a  $v'$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   978
from $v$ is not so straightforward. The point of this is that  we might
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   979
be able to finally bridge the gap by proving
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   980
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   981
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   982
\noindent\rule[1.5ex]{\linewidth}{4pt}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   983
There is no mention of retrieve yet .... this is the second trick in the
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   984
existing proof. I am not sure whether you need to explain annotated regular
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   985
expressions much earlier - maybe before the ``existing proof'' section, or
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   986
evan earlier.
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   987
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   988
\noindent\rule[1.5ex]{\linewidth}{4pt}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   989
94
Chengsong
parents:
diff changeset
   990
\noindent
Chengsong
parents:
diff changeset
   991
By using a property of retrieve we have the $\textit{RHS}$ of the above equality is
Chengsong
parents:
diff changeset
   992
$decode (retrieve (r^\uparrow \backslash(s @ [c])) v) r$, and this gives the 
Chengsong
parents:
diff changeset
   993
main lemma result:
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   994
94
Chengsong
parents:
diff changeset
   995
\begin{center}
Chengsong
parents:
diff changeset
   996
$ \flex \;r\;  id \; (s@[c]) \; v =\textit{decode}(\textit{retrieve} (\rup \backslash (s@[c])) \;v) r$
Chengsong
parents:
diff changeset
   997
\end{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   998
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   999
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
  1000
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
  1001
94
Chengsong
parents:
diff changeset
  1002
\noindent
Chengsong
parents:
diff changeset
  1003
To use this lemma result for our 
Chengsong
parents:
diff changeset
  1004
correctness proof, simply replace the $v$ in the
Chengsong
parents:
diff changeset
  1005
$\textit{RHS}$ of the above equality with
Chengsong
parents:
diff changeset
  1006
$\mkeps\;(r\backslash (s@[c]))$, and apply the lemma that
Chengsong
parents:
diff changeset
  1007
 
Chengsong
parents:
diff changeset
  1008
\begin{center}
Chengsong
parents:
diff changeset
  1009
$\textit{decode} \; \bmkeps \; \rup \; r = \textit{decode} \; (\textit{retrieve} \; \rup \; \mkeps(r)) \;r$
Chengsong
parents:
diff changeset
  1010
\end{center}
Chengsong
parents:
diff changeset
  1011
\noindent
Chengsong
parents:
diff changeset
  1012
We get the correctness of our bit-coded algorithm:
Chengsong
parents:
diff changeset
  1013
\begin{center}
Chengsong
parents:
diff changeset
  1014
$\flex \;r\;  id \; s \; (\mkeps \; r\backslash s) = \textit{decode} \; \bmkeps \; \rup\backslash s \; r$
Chengsong
parents:
diff changeset
  1015
\end{center}
Chengsong
parents:
diff changeset
  1016
\noindent
Chengsong
parents:
diff changeset
  1017
The bridge between the above chain of equalities
Chengsong
parents:
diff changeset
  1018
is the use of $\retrieve$,
Chengsong
parents:
diff changeset
  1019
if we want to use a similar technique for the 
Chengsong
parents:
diff changeset
  1020
simplified version of algorithm,
Chengsong
parents:
diff changeset
  1021
we face the problem that in the above 
Chengsong
parents:
diff changeset
  1022
equalities,
Chengsong
parents:
diff changeset
  1023
$\retrieve \; a \; v$ is not always defined.
Chengsong
parents:
diff changeset
  1024
for example,
100
397b31867ea6 copied christian changes
Chengsong
parents: 95
diff changeset
  1025
$\retrieve \; _0(_1a+_0a) \; \Left(\Empty)$
101
Chengsong
parents: 100
diff changeset
  1026
is defined, but not $\retrieve \; (_{01}a) \;\Left(\Empty)$,
94
Chengsong
parents:
diff changeset
  1027
though we can extract the same POSIX
Chengsong
parents:
diff changeset
  1028
bits from the two annotated regular expressions.
95
Chengsong
parents: 94
diff changeset
  1029
The latter might occur when we try to retrieve from 
Chengsong
parents: 94
diff changeset
  1030
a simplified regular expression using the same value
Chengsong
parents: 94
diff changeset
  1031
as the unsimplified one.
Chengsong
parents: 94
diff changeset
  1032
This is because $\Left(\Empty)$ corresponds to
101
Chengsong
parents: 100
diff changeset
  1033
the regular expression structure $\ONE+r_2$ instead of
Chengsong
parents: 100
diff changeset
  1034
$\ONE$.
94
Chengsong
parents:
diff changeset
  1035
That means, if we 
Chengsong
parents:
diff changeset
  1036
want to prove that 
Chengsong
parents:
diff changeset
  1037
\begin{center}
Chengsong
parents:
diff changeset
  1038
$\textit{decode} \; \bmkeps \; \rup\backslash s \; r = \textit{decode} \; \bmkeps \; \rup\backslash_{simp} s \; r$
Chengsong
parents:
diff changeset
  1039
\end{center}
Chengsong
parents:
diff changeset
  1040
\noindent
Chengsong
parents:
diff changeset
  1041
holds by using $\retrieve$,
Chengsong
parents:
diff changeset
  1042
we probably need to prove an equality like below:
Chengsong
parents:
diff changeset
  1043
\begin{center}
Chengsong
parents:
diff changeset
  1044
%$\retrieve \; \rup\backslash_{simp} s \; \mkeps(r\backslash_{simp} s)=\textit{retrieve} \; \rup\backslash s \; \mkeps(r\backslash s)$
101
Chengsong
parents: 100
diff changeset
  1045
$\retrieve \; \rup\backslash_{simp} s \; \mkeps(f(r\backslash s))=\textit{retrieve} \; \rup\backslash s \; \mkeps(r\backslash s)$
94
Chengsong
parents:
diff changeset
  1046
\end{center}
Chengsong
parents:
diff changeset
  1047
\noindent
101
Chengsong
parents: 100
diff changeset
  1048
$f$ rectifies $r\backslash s$ so the value $\mkeps(f(r\backslash s))$ becomes
Chengsong
parents: 100
diff changeset
  1049
 something simpler
94
Chengsong
parents:
diff changeset
  1050
to make the retrieve function defined.\\
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1051
\subsubsection{Ways to Rectify Value}
95
Chengsong
parents: 94
diff changeset
  1052
One way to do this is to prove the following:
Chengsong
parents: 94
diff changeset
  1053
\begin{center}
Chengsong
parents: 94
diff changeset
  1054
$\retrieve \; \rup\backslash_{simp} s \; \mkeps(\simp(r\backslash s))=\textit{retrieve} \; \rup\backslash s \; \mkeps(r\backslash s)$
Chengsong
parents: 94
diff changeset
  1055
\end{center}
Chengsong
parents: 94
diff changeset
  1056
\noindent
101
Chengsong
parents: 100
diff changeset
  1057
The reason why we choose $\simp$ as $f$ is because
Chengsong
parents: 100
diff changeset
  1058
$\rup\backslash_{simp} \, s$ and $\simp(\rup\backslash \, s)$
Chengsong
parents: 100
diff changeset
  1059
have the same shape:
Chengsong
parents: 100
diff changeset
  1060
\begin{center}
Chengsong
parents: 100
diff changeset
  1061
$\erase (\rup\backslash_{simp} \, s) = \erase(\simp(\rup\backslash s))$
Chengsong
parents: 100
diff changeset
  1062
\end{center}
Chengsong
parents: 100
diff changeset
  1063
Chengsong
parents: 100
diff changeset
  1064
\noindent
Chengsong
parents: 100
diff changeset
  1065
$\erase$ in the above equality means to remove the bit-codes
Chengsong
parents: 100
diff changeset
  1066
in an annotated regular expression and only keep the original
Chengsong
parents: 100
diff changeset
  1067
regular expression(just like "erasing" the bits). Its definition is omitted.
Chengsong
parents: 100
diff changeset
  1068
$\rup\backslash_{simp} \, s$ and $\simp(\rup\backslash s)$
Chengsong
parents: 100
diff changeset
  1069
are very closely related, but not identical.
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1070
\subsubsection{Example for $\rup\backslash_{simp} \, s \neq \simp(\rup\backslash s)$}
101
Chengsong
parents: 100
diff changeset
  1071
For example, let $r$ be the regular expression
Chengsong
parents: 100
diff changeset
  1072
$(a+b)(a+a*)$ and $s$  be the string $aa$, then
103
Chengsong
parents: 102
diff changeset
  1073
both $\erase (\rup\backslash_{simp} \, s)$ and $\erase (\simp (\rup\backslash s))$
Chengsong
parents: 102
diff changeset
  1074
are $\ONE + a^*$. However, without $\erase$ 
101
Chengsong
parents: 100
diff changeset
  1075
\begin{center}
Chengsong
parents: 100
diff changeset
  1076
$\rup\backslash_{simp} \, s$ is equal to $_0(_0\ONE +_{11}a^*)$
Chengsong
parents: 100
diff changeset
  1077
\end{center}
Chengsong
parents: 100
diff changeset
  1078
\noindent
Chengsong
parents: 100
diff changeset
  1079
whereas
Chengsong
parents: 100
diff changeset
  1080
\begin{center}
103
Chengsong
parents: 102
diff changeset
  1081
$\simp(\rup\backslash  s)$ is equal to $(_{00}\ONE +_{011}a^*)$
101
Chengsong
parents: 100
diff changeset
  1082
\end{center}
Chengsong
parents: 100
diff changeset
  1083
\noindent
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1084
(For the sake of visual simplicity, we use numbers to denote the bits
103
Chengsong
parents: 102
diff changeset
  1085
in bitcodes as we have previously defined for annotated 
Chengsong
parents: 102
diff changeset
  1086
regular expressions. $\S$ is replaced by 
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1087
subscript $_1$ and $\Z$ by $_0$.)
103
Chengsong
parents: 102
diff changeset
  1088
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1089
What makes the difference?
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1090
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1091
%Two "rules" might be inferred from the above example.
103
Chengsong
parents: 102
diff changeset
  1092
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1093
%First, after erasing the bits the two regular expressions
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1094
%are exactly the same: both become $1+a^*$. Here the 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1095
%function $\simp$ exhibits the "one in the end equals many times
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1096
%at the front"
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1097
%property: one simplification in the end causes the 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1098
%same regular expression structure as
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1099
%successive simplifications done alongside derivatives.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1100
%$\rup\backslash_{simp} \, s$ unfolds to 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1101
%$\simp((\simp(r\backslash a))\backslash a)$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1102
%and $\simp(\rup\backslash s)$ unfolds to 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1103
%$\simp((r\backslash a)\backslash a)$. The one simplification
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1104
%in the latter causes the resulting regular expression to 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1105
%become $1+a^*$, exactly the same as the former with
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1106
%two simplifications.
103
Chengsong
parents: 102
diff changeset
  1107
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1108
%Second, the bit-codes are different, but they are essentially
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1109
%the same: if we push the outmost bits ${\bf_0}(_0\ONE +_{11}a^*)$ of $\rup\backslash_{simp} \, s$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1110
%inside then we get $(_{00}\ONE +_{011}a^*)$, exactly the 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1111
%same as that of $\rup\backslash \, s$. And this difference 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1112
%does not matter when we try to apply $\bmkeps$ or $\retrieve$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1113
%to it. This seems a good news if we want to use $\retrieve$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1114
%to prove things.
103
Chengsong
parents: 102
diff changeset
  1115
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1116
%If we look into the difference above, we could see that the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1117
%difference is not fundamental: the bits are just being moved
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1118
%around in a way that does not hurt the correctness.
103
Chengsong
parents: 102
diff changeset
  1119
During the first derivative operation, 
Chengsong
parents: 102
diff changeset
  1120
$\rup\backslash a=(_0\ONE  + \ZERO)(_0a  +  _1a^*)$  is
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1121
in the form of a sequence regular expression with
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1122
two components, the first
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1123
one $\ONE + \ZERO$ being nullable. 
103
Chengsong
parents: 102
diff changeset
  1124
Recall the simplification function definition:
Chengsong
parents: 102
diff changeset
  1125
\begin{center}
Chengsong
parents: 102
diff changeset
  1126
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents: 102
diff changeset
  1127
   
Chengsong
parents: 102
diff changeset
  1128
  $\textit{simp} \; (\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ & $ (\textit{simp} \; a_1, \textit{simp}  \; a_2) \; \textit{match} $ \\
Chengsong
parents: 102
diff changeset
  1129
   &&$\quad\textit{case} \; (\ZERO, \_) \Rightarrow  \ZERO$ \\
Chengsong
parents: 102
diff changeset
  1130
   &&$\quad\textit{case} \; (\_, \ZERO) \Rightarrow  \ZERO$ \\
Chengsong
parents: 102
diff changeset
  1131
   &&$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$ \\
Chengsong
parents: 102
diff changeset
  1132
   &&$\quad\textit{case} \; (a_1', \ONE) \Rightarrow  \textit{fuse} \; bs \;  a_1'$ \\
Chengsong
parents: 102
diff changeset
  1133
   &&$\quad\textit{case} \; (a_1', a_2') \Rightarrow  \textit{SEQ} \; bs \; a_1' \;  a_2'$ \\
Chengsong
parents: 102
diff changeset
  1134
Chengsong
parents: 102
diff changeset
  1135
  $\textit{simp} \; (\textit{ALTS}\;bs\,as)$ & $\dn$ & $\textit{distinct}( \textit{flatten} ( \textit{map simp as})) \; \textit{match} $ \\
Chengsong
parents: 102
diff changeset
  1136
  &&$\quad\textit{case} \; [] \Rightarrow  \ZERO$ \\
Chengsong
parents: 102
diff changeset
  1137
   &&$\quad\textit{case} \; a :: [] \Rightarrow  \textit{fuse bs a}$ \\
Chengsong
parents: 102
diff changeset
  1138
   &&$\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$\\ 
Chengsong
parents: 102
diff changeset
  1139
Chengsong
parents: 102
diff changeset
  1140
   $\textit{simp} \; a$ & $\dn$ & $\textit{a} \qquad \textit{otherwise}$   
Chengsong
parents: 102
diff changeset
  1141
\end{tabular}    
Chengsong
parents: 102
diff changeset
  1142
\end{center}    
Chengsong
parents: 102
diff changeset
  1143
Chengsong
parents: 102
diff changeset
  1144
\noindent
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1145
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1146
and the difinition of $\flatten$:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1147
 \begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1148
 \begin{tabular}{c c c}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1149
 $\flatten \; []$ & $\dn$ & $[]$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1150
 $\flatten \; \ZERO::rs$ & $\dn$ & $rs$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1151
 $\flatten \;(_{\textit{bs}_1}\oplus \textit{rs}_1 ::rs)$ & $\dn$ & $(\map \, (\fuse \, \textit{bs}_1) \,\textit{rs}_1) ::: \flatten(rs)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1152
 $\flatten \; r :: rs$ & $\dn$ & $r::\flatten(rs)$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1153
 \end{tabular}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1154
 \end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1155
 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1156
 \noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1157
If we call $\simp$ on $\rup\backslash a$, just as $\backslash_{simp}$
103
Chengsong
parents: 102
diff changeset
  1158
requires, then we would go throught the third clause of 
Chengsong
parents: 102
diff changeset
  1159
the sequence case:$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$.
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1160
The $\ZERO$ of $(_0\ONE  + \ZERO)$ is thrown away 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1161
by $\flatten$ and 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1162
$_0\ONE$ merged into $(_0a  +  _1a^*)$ by simply
103
Chengsong
parents: 102
diff changeset
  1163
putting its bits($_0$) to the front of the second component:
Chengsong
parents: 102
diff changeset
  1164
 ${\bf_0}(_0a  +  _1a^*)$. 
Chengsong
parents: 102
diff changeset
  1165
 After a second derivative operation,
Chengsong
parents: 102
diff changeset
  1166
 namely, $(_0(_0a  +  _1a^*))\backslash a$, we get 
Chengsong
parents: 102
diff changeset
  1167
 $
Chengsong
parents: 102
diff changeset
  1168
 _0(_0 \ONE  +  _1(_1\ONE \cdot a^*))
Chengsong
parents: 102
diff changeset
  1169
 $, and this simplifies to $_0(_0 \ONE  +  _{11} a^*)$
Chengsong
parents: 102
diff changeset
  1170
 by the third clause of the alternative case:
Chengsong
parents: 102
diff changeset
  1171
 $\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$.
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1172
The outmost bit $_0$ stays with 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1173
the outmost regular expression, rather than being fused to
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1174
its child regular expressions, as what we will later see happens
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1175
to $\simp(\rup\backslash \, s)$.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1176
If we choose to not simplify in the midst of derivative operations,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1177
but only do it at the end after the string has been exhausted, 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1178
namely, $\simp(\rup\backslash \, s)=\simp((\rup\backslash a)\backslash a)$,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1179
then at the {\bf second} derivative of 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1180
$(\rup\backslash a)\bf{\backslash a}$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1181
we will go throught the clause of $\backslash$:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1182
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1183
\begin{tabular}{lcl}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1184
$(\textit{SEQ}\;bs\,a_1\,a_2)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1185
     $(when \; \textit{bnullable}\,a_1)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1186
					       & &$\textit{ALTS}\,bs\,List(\;\;(\textit{SEQ}\,[]\,(a_1\,\backslash c)\,a_2),$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1187
					       & &$(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\,\backslash c))\;\;)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1188
\end{tabular}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1189
\end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1190
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1191
because
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1192
$\rup\backslash a = (_0\ONE  + \ZERO)(_0a  +  _1a^*)$  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1193
is a sequence
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1194
with the first component being nullable
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1195
(unsimplified, unlike the first round of running$\backslash_{simp}$).
103
Chengsong
parents: 102
diff changeset
  1196
Therefore $((_0\ONE  + \ZERO)(_0a  +  _1a^*))\backslash a$ splits into
Chengsong
parents: 102
diff changeset
  1197
$([(\ZERO + \ZERO)\cdot(_0a  +  _1a^*)] + _0( _0\ONE  + _1[_1\ONE \cdot a^*]))$.
Chengsong
parents: 102
diff changeset
  1198
After these two successive derivatives without simplification,
Chengsong
parents: 102
diff changeset
  1199
we apply $\simp$ to this regular expression, which goes through
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1200
the alternative clause, and each component of 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1201
$([(\ZERO + \ZERO)\cdot(_0a  +  _1a^*)] + _0( _0\ONE  + _1[_1\ONE \cdot a^*]))$ 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1202
will be simplified, giving us the list:$[\ZERO, _0(_0\ONE  + _{11}a^*)]$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1203
This list is then "flattened"--$\ZERO$ will be
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1204
thrown away by $\textit{flatten}$; $ _0(_0\ONE  + _{11}a^*)$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1205
is opened up to make the list consisting of two separate elements 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1206
$_{00}\ONE$ and $_{011}a^*$, note that $flatten$ 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1207
$\fuse$s the bit(s) $_0$ to the front of $_0\ONE $ and $_{11}a^*$.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1208
In a nutshell, the order of simplification causes
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1209
the bits to be moved differently.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1210
 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1211
 \subsubsection{A Failed Attempt To Remedy the Problem Above}
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1212
A simple class of regular expression and string
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1213
pairs $(r, s)$ can be deduced from the above example 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1214
which trigger the difference between 
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1215
$\rup\backslash_{simp} \, s$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1216
and  $\simp(\rup\backslash s)$:
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1217
\begin{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1218
\begin{tabular}{lcl}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1219
$D =\{ (r_1 \cdot r_2,\; [c_1c_2]) \mid $ & $\simp(r_2) = r_2, \simp(r_1 \backslash c_1) = \ONE,$\\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1220
 $r_1 \; not \; \nullable, c_2 \in L(r_2),$ & $\exists \textit{rs},\textit{bs}.\;  r_2 \backslash c_2 = _{bs}{\oplus rs}$\\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1221
$\exists \textit{rs}_1. \; \simp(r_2 \backslash c_2) = _{bs}{\oplus \textit{rs}_1}$ &  $and \;\simp(r_1 \backslash [c_1c_2]) = \ZERO\}$\\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1222
\end{tabular}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1223
\end{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1224
We take a pair $(r, \;s)$ from the set $D$.
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1225
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1226
Now we compute ${\bf \rup \backslash_{simp} s}$, we get:
110
Chengsong
parents: 109
diff changeset
  1227
\begin{center}
Chengsong
parents: 109
diff changeset
  1228
\begin{tabular}{lcl}
Chengsong
parents: 109
diff changeset
  1229
$(r_1\cdot r_2)\backslash_{simp} \, [c_1c_2]$ & $= \simp\left[ \big(\simp\left[ \left( r_1\cdot r_2 \right) \backslash c_1\right] \big)\backslash c_2\right]$\\
Chengsong
parents: 109
diff changeset
  1230
								      & $= \simp\left[ \big(\simp \left[  \left(r_1 \backslash c_1\right) \cdot r_2 \right] \big) \backslash c_2 \right]$\\
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1231
								      & $= \simp \left[  (\fuse \; \bmkeps(r_1\backslash c_1) \; \simp(r_2) ) \backslash c_2 \right]$,\\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1232
								      & $= \simp \left[  (\fuse \; \bmkeps(r_1\backslash c_1) \; r_2 ) \backslash c_2 \right]$,
110
Chengsong
parents: 109
diff changeset
  1233
\end{tabular}
Chengsong
parents: 109
diff changeset
  1234
\end{center}
Chengsong
parents: 109
diff changeset
  1235
\noindent
Chengsong
parents: 109
diff changeset
  1236
from the definition of $D$ we know $r_1 \backslash c_1$ is nullable, therefore
Chengsong
parents: 109
diff changeset
  1237
$\bmkeps(r_1\backslash c_1)$  returns a bitcode, we shall call it
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1238
 $\textit{bs}_2$. 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1239
The above term can be rewritten as
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1240
\begin{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1241
$ \simp \left[  \fuse \; \textit{bs}_2\; r_2  \backslash c_2 \right]$,
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1242
\end{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1243
which is equal to 
110
Chengsong
parents: 109
diff changeset
  1244
\begin{center}
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1245
$\simp \left[ \fuse \; \textit{bs}_2 \; _{bs}{\oplus rs} \right]$\\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1246
$=\simp \left[  \; _{bs_2++bs}{\oplus rs} \right]$\\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1247
$=  \; _{bs_2++bs}{\oplus \textit{rs}_1} $
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1248
\end{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1249
\noindent
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1250
by using the properties from the set $D$ again
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1251
and again(The reason why we set so many conditions 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1252
that the pair $(r,s)$ need to satisfy is because we can
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1253
rewrite them easily to construct the difference.)
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1254
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1255
Now we compute ${\bf \simp(\rup \backslash s)}$:
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1256
\begin{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1257
$\simp \big[(r_1\cdot r_2) \backslash [c_1c_2] \big]= \simp \left[ ((r_1 \cdot r_2 )\backslash c_1) \backslash c_2 \right]$
110
Chengsong
parents: 109
diff changeset
  1258
\end{center}
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1259
\noindent
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1260
Again, using the properties above, we obtain
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1261
the following chain of equalities:
110
Chengsong
parents: 109
diff changeset
  1262
\begin{center}
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1263
$\simp(\rup \backslash s)= \simp \left[ ((r_1 \cdot r_2 )\backslash c_1) \backslash c_2 \right]= \simp\left[    \left(r_1 \backslash c_1\right) \cdot r_2  \big) \backslash c_2 \right]$\\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1264
$= \simp \left[ \oplus[\big( \left(r_1 \backslash c_1\right) \backslash c_2 \big) \cdot r_2 \; , \; \fuse \; (\bmkeps \;r_1\backslash c_1) \; r_2 \backslash c_2 ] \right]$,
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1265
\end{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1266
\noindent
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1267
as before, we call the bitcode returned by 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1268
$\bmkeps(r_1\backslash c_1)$ as
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1269
$\textit{bs}_2$. 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1270
Also, $\simp(r_2 \backslash c_2)$ is 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1271
$_{bs}\oplus \textit{rs}_1$, 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1272
and $( \left(r_1 \backslash c_1\right) \backslash c_2  \cdot r_2)$
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1273
simplifies to $\ZERO$,
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1274
so the above term can be expanded as
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1275
\begin{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1276
\begin{tabular}{l}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1277
$\textit{distinct}(\flatten[\ZERO\;, \; _{\textit{bs}_2++\textit{bs}}\oplus \textit{rs}_1] ) \; \textit{match} $ \\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1278
  $\textit{case} \; [] \Rightarrow  \ZERO$ \\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1279
   $\textit{case} \; a :: [] \Rightarrow  \textit{\fuse \; \textit{bs} a}$ \\
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1280
    $\textit{case} \;  as' \Rightarrow  _{[]}\oplus as'$\\ 
110
Chengsong
parents: 109
diff changeset
  1281
\end{tabular}
Chengsong
parents: 109
diff changeset
  1282
\end{center}
Chengsong
parents: 109
diff changeset
  1283
\noindent
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1284
Applying the definition of $\flatten$, we get
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1285
\begin{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1286
$_{[]}\oplus (\textit{map} \; \fuse (\textit{bs}_2 ++ bs) rs_1)$
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1287
\end{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1288
\noindent
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1289
compared to the result 
110
Chengsong
parents: 109
diff changeset
  1290
\begin{center}
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1291
$ \; _{bs_2++bs}{\oplus \textit{rs}_1} $
110
Chengsong
parents: 109
diff changeset
  1292
\end{center}
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1293
\noindent
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1294
Note how these two regular expressions only
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1295
differ in terms of the position of the bits 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1296
$\textit{bs}_2++\textit{bs}$. They are the same otherwise.
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1297
What caused this difference to happen?
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1298
The culprit is the $\flatten$ function, which spills
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1299
out the bitcodes in the inner alternatives when 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1300
there exists an outer alternative.
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1301
Note how the absence of simplification
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1302
caused $\simp(\rup \backslash s)$ to
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1303
generate the nested alternatives structure:
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1304
\begin{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1305
$  \oplus[\ZERO \;, \; _{bs}\oplus \textit{rs} ]$
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1306
\end{center}
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1307
and this will always trigger the $\flatten$ to 
112
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1308
spill out the inner alternative's bitcode $\textit{bs}$,
111
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1309
whereas when
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1310
simplification is done along the way, 
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1311
the structure of nested alternatives is never created(we can
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1312
actually prove that simplification function never allows nested
af2c63f9bdf9 refined section a bit
Chengsong
parents: 110
diff changeset
  1313
alternatives to happen, more on this later).
110
Chengsong
parents: 109
diff changeset
  1314
113
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1315
How about we do not allow the function $\simp$
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1316
to fuse out the bits when it is unnecessary?
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1317
Like, for the above regular expression, we might
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1318
just delete the outer layer of alternative
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1319
\begin{center}
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1320
\st{$ {\oplus[\ZERO \;,}$} $_{bs}\oplus \textit{rs}$ \st{$]$}
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1321
\end{center}
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1322
and get $_{bs}\oplus \textit{rs}$ instead, without
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1323
fusing the bits $\textit{bs}$ inside to every element 
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1324
of $\textit{rs}$.
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1325
This idea can be realized by making the following
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1326
changes to the $\simp$-function:
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1327
\begin{center}
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1328
  \begin{tabular}{@{}lcl@{}}
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1329
   
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1330
  $\textit{simp} \; (_{\textit{bs}}(a_1 \cdot a_2))$ & $\dn$ & $ (\textit{simp} \; a_1, \textit{simp}  \; a_2) \; \textit{match} $ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1331
   &&$\quad\textit{case} \; (\ZERO, \_) \Rightarrow  \ZERO$ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1332
   &&$\quad\textit{case} \; (\_, \ZERO) \Rightarrow  \ZERO$ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1333
   &&$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1334
   &&$\quad\textit{case} \; (a_1', \ONE) \Rightarrow  \textit{fuse} \; bs \;  a_1'$ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1335
   &&$\quad\textit{case} \; (a_1', a_2') \Rightarrow  _{\textit{bs}}(a_1' \cdot a_2')$ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1336
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1337
  $\textit{simp} \; (bs_\oplus as)$ & $\dn$ & $\textit{distinct}( \textit{flatten} ( \textit{map simp as})) \; \textit{match} $ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1338
  &&$\quad\textit{case} \; [] \Rightarrow  \ZERO$ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1339
   &&$\quad\textit{case} \; a :: [] \Rightarrow  \textit{fuse bs a}$ \\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1340
   &&$\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$\\ 
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1341
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1342
   $\textit{simp} \; a$ & $\dn$ & $\textit{a} \qquad \textit{otherwise}$   
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1343
\end{tabular}    
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1344
\end{center}    
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1345
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1346
\noindent
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1347
112
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1348
\subsection{Properties of the Function $\simp$}
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1349
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1350
We have proved in Isabelle quite a few properties
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1351
of the $\simp$-function, which helps the proof to go forward
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1352
and we list them here to aid comprehension.
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1353
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1354
To start, we need a bit of auxiliary notations,
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1355
which is quite basic and is only written here
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1356
for clarity.
113
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1357
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1358
$\textit{sub}(r)$ computes the set of the 
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1359
sub-regular expression of $r$:
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1360
\begin{center}
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1361
$\textit{sub}(\ONE) \dn \{\ONE\}$\\
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1362
$\textit{sub}(r_1 \cdot r_2) \dn \textit{sub}(r_1) \cup \textit{sub}(r_2) \cup \{r_1 \cdot r_2\}$\\
112
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1363
$\textit{sub}(r_1 + r_2) \dn \textit{sub}(r_1) \cup \textit{sub}(r_2) \cup \{r_1+r_2\}$\\
113
8dbc83ecea3b test for talisker address change
Chengsong
parents: 112
diff changeset
  1364
\end{center}
112
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1365
$\textit{good}(r) \dn r \neq \ZERO \land \\
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1366
\forall r' \in \textit{sub}(r), \textit{if} \; r' = _{bs_1}\oplus(rs_1), \;
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1367
\textit{then} \nexists r'' \in \textit{rs}_1 \; s.t.\;
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1368
r'' = _{bs_2}\oplus \textit{rs}_2 $
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1369
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1370
The properties are mainly the ones below:
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1371
\begin{itemize}
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1372
\item
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1373
\begin{center}
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1374
$\simp(\simp(r)) = \simp(r)$
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1375
\end{center}
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1376
\item
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1377
\begin{center}
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1378
$\textit{if} r = \simp(r') \textit{then} \; \textit{good}(r) $
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1379
\end{center}
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1380
\end{itemize}
c19f2d20d92c added section
Chengsong
parents: 111
diff changeset
  1381
110
Chengsong
parents: 109
diff changeset
  1382
%CONSTRUCTION SITE HERE
101
Chengsong
parents: 100
diff changeset
  1383
that is to say, despite the bits are being moved around on the regular expression
Chengsong
parents: 100
diff changeset
  1384
(difference in bits), the structure of the (unannotated)regular expression
Chengsong
parents: 100
diff changeset
  1385
after one simplification is exactly the same after the 
Chengsong
parents: 100
diff changeset
  1386
same sequence of derivative operations 
Chengsong
parents: 100
diff changeset
  1387
regardless of whether we did simplification
Chengsong
parents: 100
diff changeset
  1388
along the way.
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1389
 One way would be to give a function that calls
110
Chengsong
parents: 109
diff changeset
  1390
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1391
fuse is the culprit: it causes the order in which alternatives
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1392
are opened up to be remembered and finally the difference
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1393
appear in $\simp(\rup \backslash s)$ and $\rup \backslash{simp} \,s$.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1394
but we have to use them as they are essential in the simplification:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1395
flatten needs them.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1396
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1397
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1398
101
Chengsong
parents: 100
diff changeset
  1399
However, without erase the above equality does not hold:
Chengsong
parents: 100
diff changeset
  1400
for the regular expression  
Chengsong
parents: 100
diff changeset
  1401
$(a+b)(a+a*)$,
Chengsong
parents: 100
diff changeset
  1402
if we do derivative with respect to string $aa$,
Chengsong
parents: 100
diff changeset
  1403
we get
103
Chengsong
parents: 102
diff changeset
  1404
109
Chengsong
parents: 108
diff changeset
  1405
\subsection{Another Proof Strategy}
101
Chengsong
parents: 100
diff changeset
  1406
sdddddr does not equal sdsdsdsr sometimes.\\
Chengsong
parents: 100
diff changeset
  1407
For example,
Chengsong
parents: 100
diff changeset
  1408
Chengsong
parents: 100
diff changeset
  1409
This equicalence class method might still have the potential of proving this,
Chengsong
parents: 100
diff changeset
  1410
but not yet
Chengsong
parents: 100
diff changeset
  1411
i parallelly tried another method of using retrieve\\
Chengsong
parents: 100
diff changeset
  1412
Chengsong
parents: 100
diff changeset
  1413
94
Chengsong
parents:
diff changeset
  1414
The vsimp function, defined as follows
Chengsong
parents:
diff changeset
  1415
tries to simplify the value in lockstep with 
Chengsong
parents:
diff changeset
  1416
regular expression:\\
Chengsong
parents:
diff changeset
  1417
Chengsong
parents:
diff changeset
  1418
Chengsong
parents:
diff changeset
  1419
The problem here is that 
Chengsong
parents:
diff changeset
  1420
Chengsong
parents:
diff changeset
  1421
we used retrieve for the key induction:
Chengsong
parents:
diff changeset
  1422
$decode (retrieve (r\backslash (s @ [c])) v) r $
Chengsong
parents:
diff changeset
  1423
$decode (retrieve (r\backslash s) (inj (r\backslash s) c v)) r$
Chengsong
parents:
diff changeset
  1424
Here, decode recovers a value that corresponds to a match(possibly partial)
Chengsong
parents:
diff changeset
  1425
from bits, and the bits are extracted by retrieve,
Chengsong
parents:
diff changeset
  1426
and the key value $v$ that guides retrieve is
Chengsong
parents:
diff changeset
  1427
$mkeps r\backslash s$, $inj r c (mkeps r\backslash s)$, $inj (inj (v))$, ......
Chengsong
parents:
diff changeset
  1428
if we can 
Chengsong
parents:
diff changeset
  1429
the problem is that 
Chengsong
parents:
diff changeset
  1430
need vsiimp to make a value that is suitable for decoding
Chengsong
parents:
diff changeset
  1431
$Some(flex rid(s@[c])v) = Some(flex rids(inj (r\backslash s)cv))$
Chengsong
parents:
diff changeset
  1432
another way that christian came up with that might circumvent the 
Chengsong
parents:
diff changeset
  1433
prblem of finding suitable value is by not stating the visimp
Chengsong
parents:
diff changeset
  1434
function but include all possible value in a set that a regex is able to produce,
Chengsong
parents:
diff changeset
  1435
and proving that both r and sr are able to produce the bits that correspond the POSIX value
Chengsong
parents:
diff changeset
  1436
Chengsong
parents:
diff changeset
  1437
produced by feeding the same initial regular expression $r$ and string $s$ to the
Chengsong
parents:
diff changeset
  1438
 two functions $ders$ and $ders\_simp$.
Chengsong
parents:
diff changeset
  1439
The reason why
Chengsong
parents:
diff changeset
  1440
Namely, if $bmkeps( r_1) = bmkeps(r_2)$, then we 
Chengsong
parents:
diff changeset
  1441
Chengsong
parents:
diff changeset
  1442
Chengsong
parents:
diff changeset
  1443
If we define the equivalence relation $\sim_{m\epsilon}$ between two regular expressions
Chengsong
parents:
diff changeset
  1444
$r_1$ and $r_2$as follows:
Chengsong
parents:
diff changeset
  1445
$r_1 \sim_{m\epsilon} r_2  \iff bmkeps(r_1)= bmkeps(r_2)$
Chengsong
parents:
diff changeset
  1446
(in other words, they $r1$ and $r2$ produce the same output under the function $bmkeps$.)
Chengsong
parents:
diff changeset
  1447
Then the first goal 
Chengsong
parents:
diff changeset
  1448
might be restated as 
Chengsong
parents:
diff changeset
  1449
$(r^\uparrow)\backslash_{simp}\, s  \sim_{m\epsilon} (r^\uparrow)\backslash s$.
Chengsong
parents:
diff changeset
  1450
I tried to establish an equivalence relation between the regular experssions 
Chengsong
parents:
diff changeset
  1451
like dddr dddsr,.....
Chengsong
parents:
diff changeset
  1452
but right now i am only able to establish dsr and dr, using structural induction on r.
Chengsong
parents:
diff changeset
  1453
Those involve multiple derivative operations are harder to prove.
Chengsong
parents:
diff changeset
  1454
Two attempts have been made:
Chengsong
parents:
diff changeset
  1455
(1)induction on the number of der operations(or in other words, the length of the string s),
Chengsong
parents:
diff changeset
  1456
the inductive hypothesis was initially specified as 
Chengsong
parents:
diff changeset
  1457
"For an arbitrary regular expression r, 
Chengsong
parents:
diff changeset
  1458
For all string s in the language of r whose length do not exceed 
Chengsong
parents:
diff changeset
  1459
the number n, ders s r me derssimp s r"
Chengsong
parents:
diff changeset
  1460
and the proof goal may be stated as
Chengsong
parents:
diff changeset
  1461
"For an arbitrary regular expression r, 
Chengsong
parents:
diff changeset
  1462
For all string s in the language of r whose length do not exceed 
Chengsong
parents:
diff changeset
  1463
the number n+1, ders s r me derssimp s r"
Chengsong
parents:
diff changeset
  1464
the problem here is that although we can easily break down
Chengsong
parents:
diff changeset
  1465
a string s of length n+1 into s1@list(c), it is not that easy
Chengsong
parents:
diff changeset
  1466
to use the i.h. as a stepping stone to prove anything because s1 may well be not
Chengsong
parents:
diff changeset
  1467
in the language L(r). This inhibits us from obtaining the fact that
Chengsong
parents:
diff changeset
  1468
ders s1 r me derssimps s1 r.
Chengsong
parents:
diff changeset
  1469
Further exploration is needed to amend this hypothesis so it includes the
Chengsong
parents:
diff changeset
  1470
situation when s1 is not nullable.
Chengsong
parents:
diff changeset
  1471
For example, what information(bits? 
Chengsong
parents:
diff changeset
  1472
values?) can be extracted
Chengsong
parents:
diff changeset
  1473
from the regular expression ders(s1,r) so that we can compute or predict the possible 
Chengsong
parents:
diff changeset
  1474
result of bmkeps after another derivative operation. What function f can used to 
Chengsong
parents:
diff changeset
  1475
carry out the task? The possible way of exploration can be 
Chengsong
parents:
diff changeset
  1476
more directly perceived throught the graph below:
Chengsong
parents:
diff changeset
  1477
find a function
Chengsong
parents:
diff changeset
  1478
f
Chengsong
parents:
diff changeset
  1479
such that
Chengsong
parents:
diff changeset
  1480
f(bders s1 r)
Chengsong
parents:
diff changeset
  1481
= re1
Chengsong
parents:
diff changeset
  1482
f(bderss s1 r)
Chengsong
parents:
diff changeset
  1483
= re2
Chengsong
parents:
diff changeset
  1484
bmkeps(bders s r) = g(re1,c)
Chengsong
parents:
diff changeset
  1485
bmkeps(bderssimp s r) = g(re2,c)
Chengsong
parents:
diff changeset
  1486
and g(re1,c) = g(re2,c)
Chengsong
parents:
diff changeset
  1487
The inductive hypothesis would be
Chengsong
parents:
diff changeset
  1488
"For all strings s1 of length <= n, 
Chengsong
parents:
diff changeset
  1489
f(bders s1 r)
Chengsong
parents:
diff changeset
  1490
= re1
Chengsong
parents:
diff changeset
  1491
f(bderss s1 r)
Chengsong
parents:
diff changeset
  1492
= re2"
Chengsong
parents:
diff changeset
  1493
proving this would be a lemma for the main proof:
Chengsong
parents:
diff changeset
  1494
the main proof would be 
Chengsong
parents:
diff changeset
  1495
"
Chengsong
parents:
diff changeset
  1496
bmkeps(bders s r) = g(re1,c)
Chengsong
parents:
diff changeset
  1497
bmkeps(bderssimp s r) = g(re2,c)
Chengsong
parents:
diff changeset
  1498
for s = s1@c
Chengsong
parents:
diff changeset
  1499
"
Chengsong
parents:
diff changeset
  1500
and f need to be a recursive property for the lemma to be proved:
Chengsong
parents:
diff changeset
  1501
it needs to store not only the "after one char nullable info",
Chengsong
parents:
diff changeset
  1502
but also the "after two char nullable info",
Chengsong
parents:
diff changeset
  1503
and so on so that it is able to  predict what f will compute after a derivative operation,
Chengsong
parents:
diff changeset
  1504
in other words, it needs to be "infinitely recursive"\\
Chengsong
parents:
diff changeset
  1505
To prove the lemma, in other words, to get
Chengsong
parents:
diff changeset
  1506
"For all strings s1 of length <= n+1, 
Chengsong
parents:
diff changeset
  1507
f(bders s1 r)
Chengsong
parents:
diff changeset
  1508
= re3
Chengsong
parents:
diff changeset
  1509
f(bderss s1 r)
Chengsong
parents:
diff changeset
  1510
= re4"\\
Chengsong
parents:
diff changeset
  1511
from\\
Chengsong
parents:
diff changeset
  1512
"For all strings s1 of length <= n, 
Chengsong
parents:
diff changeset
  1513
f(bders s1 r)
Chengsong
parents:
diff changeset
  1514
= re1
Chengsong
parents:
diff changeset
  1515
f(bderss s1 r)
Chengsong
parents:
diff changeset
  1516
= re2"\\
Chengsong
parents:
diff changeset
  1517
it might be best to construct an auxiliary function h such that\\
Chengsong
parents:
diff changeset
  1518
h(re1, c) = re3\\
Chengsong
parents:
diff changeset
  1519
h(re2, c) = re4\\
Chengsong
parents:
diff changeset
  1520
and re3 = f(bder c (bders s1 r))\\
Chengsong
parents:
diff changeset
  1521
re4 = f(simp(bder c (bderss s1 r)))
Chengsong
parents:
diff changeset
  1522
The key point here is that we are not satisfied with what bders s r will produce under
Chengsong
parents:
diff changeset
  1523
bmkeps, but also how it will perform after a derivative operation and then bmkeps, and two 
Chengsong
parents:
diff changeset
  1524
derivative operations and so on. In essence, we are preserving the regular expression 
Chengsong
parents:
diff changeset
  1525
itself under the function f, in a less compact way than the regluar expression: we are
Chengsong
parents:
diff changeset
  1526
not just recording but also interpreting what the regular expression matches.
Chengsong
parents:
diff changeset
  1527
In other words, we need to prove the properties of bderss s r beyond the bmkeps result,
Chengsong
parents:
diff changeset
  1528
i.e., not just the nullable ones, but also those containing remaining characters.\\
Chengsong
parents:
diff changeset
  1529
(2)we observed the fact that 
Chengsong
parents:
diff changeset
  1530
erase sdddddr= erase sdsdsdsr
Chengsong
parents:
diff changeset
  1531
that is to say, despite the bits are being moved around on the regular expression
Chengsong
parents:
diff changeset
  1532
(difference in bits), the structure of the (unannotated)regular expression
Chengsong
parents:
diff changeset
  1533
after one simplification is exactly the same after the 
Chengsong
parents:
diff changeset
  1534
same sequence of derivative operations 
Chengsong
parents:
diff changeset
  1535
regardless of whether we did simplification
Chengsong
parents:
diff changeset
  1536
along the way.
Chengsong
parents:
diff changeset
  1537
However, without erase the above equality does not hold:
Chengsong
parents:
diff changeset
  1538
for the regular expression  
Chengsong
parents:
diff changeset
  1539
$(a+b)(a+a*)$,
Chengsong
parents:
diff changeset
  1540
if we do derivative with respect to string $aa$,
Chengsong
parents:
diff changeset
  1541
we get
Chengsong
parents:
diff changeset
  1542
%TODO
Chengsong
parents:
diff changeset
  1543
sdddddr does not equal sdsdsdsr sometimes.\\
Chengsong
parents:
diff changeset
  1544
For example,
Chengsong
parents:
diff changeset
  1545
Chengsong
parents:
diff changeset
  1546
This equicalence class method might still have the potential of proving this,
Chengsong
parents:
diff changeset
  1547
but not yet
Chengsong
parents:
diff changeset
  1548
i parallelly tried another method of using retrieve\\
Chengsong
parents:
diff changeset
  1549
Chengsong
parents:
diff changeset
  1550
Chengsong
parents:
diff changeset
  1551
Chengsong
parents:
diff changeset
  1552
\noindent\rule[0.5ex]{\linewidth}{1pt}
Chengsong
parents:
diff changeset
  1553
Chengsong
parents:
diff changeset
  1554
This PhD-project is about regular expression matching and
Chengsong
parents:
diff changeset
  1555
lexing. Given the maturity of this topic, the reader might wonder:
Chengsong
parents:
diff changeset
  1556
Surely, regular expressions must have already been studied to death?
Chengsong
parents:
diff changeset
  1557
What could possibly be \emph{not} known in this area? And surely all
Chengsong
parents:
diff changeset
  1558
implemented algorithms for regular expression matching are blindingly
Chengsong
parents:
diff changeset
  1559
fast?
Chengsong
parents:
diff changeset
  1560
Chengsong
parents:
diff changeset
  1561
Unfortunately these preconceptions are not supported by evidence: Take
Chengsong
parents:
diff changeset
  1562
for example the regular expression $(a^*)^*\,b$ and ask whether
Chengsong
parents:
diff changeset
  1563
strings of the form $aa..a$ match this regular
Chengsong
parents:
diff changeset
  1564
expression. Obviously this is not the case---the expected $b$ in the last
Chengsong
parents:
diff changeset
  1565
position is missing. One would expect that modern regular expression
Chengsong
parents:
diff changeset
  1566
matching engines can find this out very quickly. Alas, if one tries
Chengsong
parents:
diff changeset
  1567
this example in JavaScript, Python or Java 8 with strings like 28
Chengsong
parents:
diff changeset
  1568
$a$'s, one discovers that this decision takes around 30 seconds and
Chengsong
parents:
diff changeset
  1569
takes considerably longer when adding a few more $a$'s, as the graphs
Chengsong
parents:
diff changeset
  1570
below show:
Chengsong
parents:
diff changeset
  1571
Chengsong
parents:
diff changeset
  1572
\begin{center}
Chengsong
parents:
diff changeset
  1573
\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}}
Chengsong
parents:
diff changeset
  1574
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  1575
\begin{axis}[
Chengsong
parents:
diff changeset
  1576
    xlabel={$n$},
Chengsong
parents:
diff changeset
  1577
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  1578
    ylabel={time in secs},
Chengsong
parents:
diff changeset
  1579
    enlargelimits=false,
Chengsong
parents:
diff changeset
  1580
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  1581
    xmax=33,
Chengsong
parents:
diff changeset
  1582
    ymax=35,
Chengsong
parents:
diff changeset
  1583
    ytick={0,5,...,30},
Chengsong
parents:
diff changeset
  1584
    scaled ticks=false,
Chengsong
parents:
diff changeset
  1585
    axis lines=left,
Chengsong
parents:
diff changeset
  1586
    width=5cm,
Chengsong
parents:
diff changeset
  1587
    height=4cm, 
Chengsong
parents:
diff changeset
  1588
    legend entries={JavaScript},  
Chengsong
parents:
diff changeset
  1589
    legend pos=north west,
Chengsong
parents:
diff changeset
  1590
    legend cell align=left]
Chengsong
parents:
diff changeset
  1591
\addplot[red,mark=*, mark options={fill=white}] table {re-js.data};
Chengsong
parents:
diff changeset
  1592
\end{axis}
Chengsong
parents:
diff changeset
  1593
\end{tikzpicture}
Chengsong
parents:
diff changeset
  1594
  &
Chengsong
parents:
diff changeset
  1595
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  1596
\begin{axis}[
Chengsong
parents:
diff changeset
  1597
    xlabel={$n$},
Chengsong
parents:
diff changeset
  1598
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  1599
    %ylabel={time in secs},
Chengsong
parents:
diff changeset
  1600
    enlargelimits=false,
Chengsong
parents:
diff changeset
  1601
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  1602
    xmax=33,
Chengsong
parents:
diff changeset
  1603
    ymax=35,
Chengsong
parents:
diff changeset
  1604
    ytick={0,5,...,30},
Chengsong
parents:
diff changeset
  1605
    scaled ticks=false,
Chengsong
parents:
diff changeset
  1606
    axis lines=left,
Chengsong
parents:
diff changeset
  1607
    width=5cm,
Chengsong
parents:
diff changeset
  1608
    height=4cm, 
Chengsong
parents:
diff changeset
  1609
    legend entries={Python},  
Chengsong
parents:
diff changeset
  1610
    legend pos=north west,
Chengsong
parents:
diff changeset
  1611
    legend cell align=left]
Chengsong
parents:
diff changeset
  1612
\addplot[blue,mark=*, mark options={fill=white}] table {re-python2.data};
Chengsong
parents:
diff changeset
  1613
\end{axis}
Chengsong
parents:
diff changeset
  1614
\end{tikzpicture}
Chengsong
parents:
diff changeset
  1615
  &
Chengsong
parents:
diff changeset
  1616
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  1617
\begin{axis}[
Chengsong
parents:
diff changeset
  1618
    xlabel={$n$},
Chengsong
parents:
diff changeset
  1619
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  1620
    %ylabel={time in secs},
Chengsong
parents:
diff changeset
  1621
    enlargelimits=false,
Chengsong
parents:
diff changeset
  1622
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  1623
    xmax=33,
Chengsong
parents:
diff changeset
  1624
    ymax=35,
Chengsong
parents:
diff changeset
  1625
    ytick={0,5,...,30},
Chengsong
parents:
diff changeset
  1626
    scaled ticks=false,
Chengsong
parents:
diff changeset
  1627
    axis lines=left,
Chengsong
parents:
diff changeset
  1628
    width=5cm,
Chengsong
parents:
diff changeset
  1629
    height=4cm, 
Chengsong
parents:
diff changeset
  1630
    legend entries={Java 8},  
Chengsong
parents:
diff changeset
  1631
    legend pos=north west,
Chengsong
parents:
diff changeset
  1632
    legend cell align=left]
Chengsong
parents:
diff changeset
  1633
\addplot[cyan,mark=*, mark options={fill=white}] table {re-java.data};
Chengsong
parents:
diff changeset
  1634
\end{axis}
Chengsong
parents:
diff changeset
  1635
\end{tikzpicture}\\
Chengsong
parents:
diff changeset
  1636
\multicolumn{3}{c}{Graphs: Runtime for matching $(a^*)^*\,b$ with strings 
Chengsong
parents:
diff changeset
  1637
           of the form $\underbrace{aa..a}_{n}$.}
Chengsong
parents:
diff changeset
  1638
\end{tabular}    
Chengsong
parents:
diff changeset
  1639
\end{center}  
Chengsong
parents:
diff changeset
  1640
Chengsong
parents:
diff changeset
  1641
\noindent These are clearly abysmal and possibly surprising results. One
Chengsong
parents:
diff changeset
  1642
would expect these systems to do  much better than that---after all,
Chengsong
parents:
diff changeset
  1643
given a DFA and a string, deciding whether a string is matched by this
Chengsong
parents:
diff changeset
  1644
DFA should be linear in terms of the size of the regular expression and
Chengsong
parents:
diff changeset
  1645
the string?
Chengsong
parents:
diff changeset
  1646
Chengsong
parents:
diff changeset
  1647
Admittedly, the regular expression $(a^*)^*\,b$ is carefully chosen to
Chengsong
parents:
diff changeset
  1648
exhibit this super-linear behaviour.  But unfortunately, such regular
Chengsong
parents:
diff changeset
  1649
expressions are not just a few outliers. They are actually 
Chengsong
parents:
diff changeset
  1650
frequent enough to have a separate name created for
Chengsong
parents:
diff changeset
  1651
them---\emph{evil regular expressions}. In empiric work, Davis et al
Chengsong
parents:
diff changeset
  1652
report that they have found thousands of such evil regular expressions
Chengsong
parents:
diff changeset
  1653
in the JavaScript and Python ecosystems \cite{Davis18}. Static analysis
Chengsong
parents:
diff changeset
  1654
approach that is both sound and complete exists\cite{17Bir}, but the running 
Chengsong
parents:
diff changeset
  1655
time on certain examples in the RegExLib and Snort regular expressions
Chengsong
parents:
diff changeset
  1656
libraries is unacceptable. Therefore the problem of efficiency still remains.
Chengsong
parents:
diff changeset
  1657
Chengsong
parents:
diff changeset
  1658
This superlinear blowup in matching algorithms sometimes causes
Chengsong
parents:
diff changeset
  1659
considerable grief in real life: for example on 20 July 2016 one evil
Chengsong
parents:
diff changeset
  1660
regular expression brought the webpage
Chengsong
parents:
diff changeset
  1661
\href{http://stackexchange.com}{Stack Exchange} to its
Chengsong
parents:
diff changeset
  1662
knees.\footnote{\url{https://stackstatus.net/post/147710624694/outage-postmortem-july-20-2016}}
Chengsong
parents:
diff changeset
  1663
In this instance, a regular expression intended to just trim white
Chengsong
parents:
diff changeset
  1664
spaces from the beginning and the end of a line actually consumed
Chengsong
parents:
diff changeset
  1665
massive amounts of CPU-resources---causing web servers to grind to a
Chengsong
parents:
diff changeset
  1666
halt. This happened when a post with 20,000 white spaces was submitted,
Chengsong
parents:
diff changeset
  1667
but importantly the white spaces were neither at the beginning nor at
Chengsong
parents:
diff changeset
  1668
the end. As a result, the regular expression matching engine needed to
Chengsong
parents:
diff changeset
  1669
backtrack over many choices. In this example, the time needed to process
Chengsong
parents:
diff changeset
  1670
the string was $O(n^2)$ with respect to the string length. This
Chengsong
parents:
diff changeset
  1671
quadratic overhead was enough for the homepage of Stack Exchange to
Chengsong
parents:
diff changeset
  1672
respond so slowly that the load balancer assumed there must be some
Chengsong
parents:
diff changeset
  1673
attack and therefore stopped the servers from responding to any
Chengsong
parents:
diff changeset
  1674
requests. This made the whole site become unavailable. Another very
Chengsong
parents:
diff changeset
  1675
recent example is a global outage of all Cloudflare servers on 2 July
Chengsong
parents:
diff changeset
  1676
2019. A poorly written regular expression exhibited exponential
Chengsong
parents:
diff changeset
  1677
behaviour and exhausted CPUs that serve HTTP traffic. Although the
Chengsong
parents:
diff changeset
  1678
outage had several causes, at the heart was a regular expression that
Chengsong
parents:
diff changeset
  1679
was used to monitor network
Chengsong
parents:
diff changeset
  1680
traffic.\footnote{\url{https://blog.cloudflare.com/details-of-the-cloudflare-outage-on-july-2-2019/}}
Chengsong
parents:
diff changeset
  1681
Chengsong
parents:
diff changeset
  1682
The underlying problem is that many ``real life'' regular expression
Chengsong
parents:
diff changeset
  1683
matching engines do not use DFAs for matching. This is because they
Chengsong
parents:
diff changeset
  1684
support regular expressions that are not covered by the classical
Chengsong
parents:
diff changeset
  1685
automata theory, and in this more general setting there are quite a few
Chengsong
parents:
diff changeset
  1686
research questions still unanswered and fast algorithms still need to be
Chengsong
parents:
diff changeset
  1687
developed (for example how to treat efficiently bounded repetitions, negation and
Chengsong
parents:
diff changeset
  1688
back-references).
Chengsong
parents:
diff changeset
  1689
%question: dfa can have exponential states. isn't this the actual reason why they do not use dfas?
Chengsong
parents:
diff changeset
  1690
%how do they avoid dfas exponential states if they use them for fast matching?
Chengsong
parents:
diff changeset
  1691
Chengsong
parents:
diff changeset
  1692
There is also another under-researched problem to do with regular
Chengsong
parents:
diff changeset
  1693
expressions and lexing, i.e.~the process of breaking up strings into
Chengsong
parents:
diff changeset
  1694
sequences of tokens according to some regular expressions. In this
Chengsong
parents:
diff changeset
  1695
setting one is not just interested in whether or not a regular
Chengsong
parents:
diff changeset
  1696
expression matches a string, but also in \emph{how}.  Consider for
Chengsong
parents:
diff changeset
  1697
example a regular expression $r_{key}$ for recognising keywords such as
Chengsong
parents:
diff changeset
  1698
\textit{if}, \textit{then} and so on; and a regular expression $r_{id}$
Chengsong
parents:
diff changeset
  1699
for recognising identifiers (say, a single character followed by
Chengsong
parents:
diff changeset
  1700
characters or numbers). One can then form the compound regular
Chengsong
parents:
diff changeset
  1701
expression $(r_{key} + r_{id})^*$ and use it to tokenise strings.  But
Chengsong
parents:
diff changeset
  1702
then how should the string \textit{iffoo} be tokenised?  It could be
Chengsong
parents:
diff changeset
  1703
tokenised as a keyword followed by an identifier, or the entire string
Chengsong
parents:
diff changeset
  1704
as a single identifier.  Similarly, how should the string \textit{if} be
Chengsong
parents:
diff changeset
  1705
tokenised? Both regular expressions, $r_{key}$ and $r_{id}$, would
Chengsong
parents:
diff changeset
  1706
``fire''---so is it an identifier or a keyword?  While in applications
Chengsong
parents:
diff changeset
  1707
there is a well-known strategy to decide these questions, called POSIX
Chengsong
parents:
diff changeset
  1708
matching, only relatively recently precise definitions of what POSIX
Chengsong
parents:
diff changeset
  1709
matching actually means have been formalised
Chengsong
parents:
diff changeset
  1710
\cite{AusafDyckhoffUrban2016,OkuiSuzuki2010,Vansummeren2006}. Such a
Chengsong
parents:
diff changeset
  1711
definition has also been given by Sulzmann and  Lu \cite{Sulzmann2014},
Chengsong
parents:
diff changeset
  1712
but the corresponding correctness proof turned out to be  faulty
Chengsong
parents:
diff changeset
  1713
\cite{AusafDyckhoffUrban2016}. Roughly, POSIX matching means matching
Chengsong
parents:
diff changeset
  1714
the longest initial substring. In the case of a tie, the initial
Chengsong
parents:
diff changeset
  1715
sub-match is chosen according to some priorities attached to the regular
Chengsong
parents:
diff changeset
  1716
expressions (e.g.~keywords have a higher priority than identifiers).
Chengsong
parents:
diff changeset
  1717
This sounds rather simple, but according to Grathwohl et al \cite[Page
Chengsong
parents:
diff changeset
  1718
36]{CrashCourse2014} this is not the case. They wrote:
Chengsong
parents:
diff changeset
  1719
Chengsong
parents:
diff changeset
  1720
\begin{quote}
Chengsong
parents:
diff changeset
  1721
\it{}``The POSIX strategy is more complicated than the greedy because of 
Chengsong
parents:
diff changeset
  1722
the dependence on information about the length of matched strings in the 
Chengsong
parents:
diff changeset
  1723
various subexpressions.''
Chengsong
parents:
diff changeset
  1724
\end{quote}
Chengsong
parents:
diff changeset
  1725
Chengsong
parents:
diff changeset
  1726
\noindent
Chengsong
parents:
diff changeset
  1727
This is also supported by evidence collected by Kuklewicz
Chengsong
parents:
diff changeset
  1728
\cite{Kuklewicz} who noticed that a number of POSIX regular expression
Chengsong
parents:
diff changeset
  1729
matchers calculate incorrect results.
Chengsong
parents:
diff changeset
  1730
Chengsong
parents:
diff changeset
  1731
Our focus in this project is on an algorithm introduced by Sulzmann and
Chengsong
parents:
diff changeset
  1732
Lu in 2014 for regular expression matching according to the POSIX
Chengsong
parents:
diff changeset
  1733
strategy \cite{Sulzmann2014}. Their algorithm is based on an older
Chengsong
parents:
diff changeset
  1734
algorithm by Brzozowski from 1964 where he introduced the notion of
Chengsong
parents:
diff changeset
  1735
derivatives of regular expressions~\cite{Brzozowski1964}. We shall
Chengsong
parents:
diff changeset
  1736
briefly explain this algorithm next.
Chengsong
parents:
diff changeset
  1737
Chengsong
parents:
diff changeset
  1738
\section{The Algorithm by Brzozowski based on Derivatives of Regular
Chengsong
parents:
diff changeset
  1739
Expressions}
Chengsong
parents:
diff changeset
  1740
Chengsong
parents:
diff changeset
  1741
Suppose (basic) regular expressions are given by the following grammar:
Chengsong
parents:
diff changeset
  1742
\[			r ::=   \ZERO \mid  \ONE
Chengsong
parents:
diff changeset
  1743
			 \mid  c  
Chengsong
parents:
diff changeset
  1744
			 \mid  r_1 \cdot r_2
Chengsong
parents:
diff changeset
  1745
			 \mid  r_1 + r_2   
Chengsong
parents:
diff changeset
  1746
			 \mid r^*         
Chengsong
parents:
diff changeset
  1747
\]
Chengsong
parents:
diff changeset
  1748
Chengsong
parents:
diff changeset
  1749
\noindent
Chengsong
parents:
diff changeset
  1750
The intended meaning of the constructors is as follows: $\ZERO$
Chengsong
parents:
diff changeset
  1751
cannot match any string, $\ONE$ can match the empty string, the
Chengsong
parents:
diff changeset
  1752
character regular expression $c$ can match the character $c$, and so
Chengsong
parents:
diff changeset
  1753
on.
Chengsong
parents:
diff changeset
  1754
Chengsong
parents:
diff changeset
  1755
The ingenious contribution by Brzozowski is the notion of
Chengsong
parents:
diff changeset
  1756
\emph{derivatives} of regular expressions.  The idea behind this
Chengsong
parents:
diff changeset
  1757
notion is as follows: suppose a regular expression $r$ can match a
Chengsong
parents:
diff changeset
  1758
string of the form $c\!::\! s$ (that is a list of characters starting
Chengsong
parents:
diff changeset
  1759
with $c$), what does the regular expression look like that can match
Chengsong
parents:
diff changeset
  1760
just $s$? Brzozowski gave a neat answer to this question. He started
Chengsong
parents:
diff changeset
  1761
with the definition of $nullable$:
Chengsong
parents:
diff changeset
  1762
\begin{center}
Chengsong
parents:
diff changeset
  1763
		\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1764
			$\nullable(\ZERO)$     & $\dn$ & $\mathit{false}$ \\  
Chengsong
parents:
diff changeset
  1765
			$\nullable(\ONE)$      & $\dn$ & $\mathit{true}$ \\
Chengsong
parents:
diff changeset
  1766
			$\nullable(c)$ 	       & $\dn$ & $\mathit{false}$ \\
Chengsong
parents:
diff changeset
  1767
			$\nullable(r_1 + r_2)$ & $\dn$ & $\nullable(r_1) \vee \nullable(r_2)$ \\
Chengsong
parents:
diff changeset
  1768
			$\nullable(r_1\cdot r_2)$  & $\dn$ & $\nullable(r_1) \wedge \nullable(r_2)$ \\
Chengsong
parents:
diff changeset
  1769
			$\nullable(r^*)$       & $\dn$ & $\mathit{true}$ \\
Chengsong
parents:
diff changeset
  1770
		\end{tabular}
Chengsong
parents:
diff changeset
  1771
	\end{center}
Chengsong
parents:
diff changeset
  1772
This function simply tests whether the empty string is in $L(r)$.
Chengsong
parents:
diff changeset
  1773
He then defined
Chengsong
parents:
diff changeset
  1774
the following operation on regular expressions, written
Chengsong
parents:
diff changeset
  1775
$r\backslash c$ (the derivative of $r$ w.r.t.~the character $c$):
Chengsong
parents:
diff changeset
  1776
Chengsong
parents:
diff changeset
  1777
\begin{center}
Chengsong
parents:
diff changeset
  1778
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1779
		$\ZERO \backslash c$ & $\dn$ & $\ZERO$\\  
Chengsong
parents:
diff changeset
  1780
		$\ONE \backslash c$  & $\dn$ & $\ZERO$\\
Chengsong
parents:
diff changeset
  1781
		$d \backslash c$     & $\dn$ & 
Chengsong
parents:
diff changeset
  1782
		$\mathit{if} \;c = d\;\mathit{then}\;\ONE\;\mathit{else}\;\ZERO$\\
Chengsong
parents:
diff changeset
  1783
$(r_1 + r_2)\backslash c$     & $\dn$ & $r_1 \backslash c \,+\, r_2 \backslash c$\\
Chengsong
parents:
diff changeset
  1784
$(r_1 \cdot r_2)\backslash c$ & $\dn$ & $\mathit{if} \, nullable(r_1)$\\
Chengsong
parents:
diff changeset
  1785
	&   & $\mathit{then}\;(r_1\backslash c) \cdot r_2 \,+\, r_2\backslash c$\\
Chengsong
parents:
diff changeset
  1786
	&   & $\mathit{else}\;(r_1\backslash c) \cdot r_2$\\
Chengsong
parents:
diff changeset
  1787
	$(r^*)\backslash c$           & $\dn$ & $(r\backslash c) \cdot r^*$\\
Chengsong
parents:
diff changeset
  1788
\end{tabular}
Chengsong
parents:
diff changeset
  1789
\end{center}
Chengsong
parents:
diff changeset
  1790
Chengsong
parents:
diff changeset
  1791
%Assuming the classic notion of a
Chengsong
parents:
diff changeset
  1792
%\emph{language} of a regular expression, written $L(\_)$, t
Chengsong
parents:
diff changeset
  1793
Chengsong
parents:
diff changeset
  1794
\noindent
Chengsong
parents:
diff changeset
  1795
The main property of the derivative operation is that
Chengsong
parents:
diff changeset
  1796
Chengsong
parents:
diff changeset
  1797
\begin{center}
Chengsong
parents:
diff changeset
  1798
$c\!::\!s \in L(r)$ holds
Chengsong
parents:
diff changeset
  1799
if and only if $s \in L(r\backslash c)$.
Chengsong
parents:
diff changeset
  1800
\end{center}
Chengsong
parents:
diff changeset
  1801
Chengsong
parents:
diff changeset
  1802
\noindent
Chengsong
parents:
diff changeset
  1803
For us the main advantage is that derivatives can be
Chengsong
parents:
diff changeset
  1804
straightforwardly implemented in any functional programming language,
Chengsong
parents:
diff changeset
  1805
and are easily definable and reasoned about in theorem provers---the
Chengsong
parents:
diff changeset
  1806
definitions just consist of inductive datatypes and simple recursive
Chengsong
parents:
diff changeset
  1807
functions. Moreover, the notion of derivatives can be easily
Chengsong
parents:
diff changeset
  1808
generalised to cover extended regular expression constructors such as
Chengsong
parents:
diff changeset
  1809
the not-regular expression, written $\neg\,r$, or bounded repetitions
Chengsong
parents:
diff changeset
  1810
(for example $r^{\{n\}}$ and $r^{\{n..m\}}$), which cannot be so
Chengsong
parents:
diff changeset
  1811
straightforwardly realised within the classic automata approach.
Chengsong
parents:
diff changeset
  1812
For the moment however, we focus only on the usual basic regular expressions.
Chengsong
parents:
diff changeset
  1813
Chengsong
parents:
diff changeset
  1814
Chengsong
parents:
diff changeset
  1815
Now if we want to find out whether a string $s$ matches with a regular
Chengsong
parents:
diff changeset
  1816
expression $r$, we can build the derivatives of $r$ w.r.t.\ (in succession)
Chengsong
parents:
diff changeset
  1817
all the characters of the string $s$. Finally, test whether the
Chengsong
parents:
diff changeset
  1818
resulting regular expression can match the empty string.  If yes, then
Chengsong
parents:
diff changeset
  1819
$r$ matches $s$, and no in the negative case. To implement this idea
Chengsong
parents:
diff changeset
  1820
we can generalise the derivative operation to strings like this:
Chengsong
parents:
diff changeset
  1821
Chengsong
parents:
diff changeset
  1822
\begin{center}
Chengsong
parents:
diff changeset
  1823
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1824
$r \backslash (c\!::\!s) $ & $\dn$ & $(r \backslash c) \backslash s$ \\
Chengsong
parents:
diff changeset
  1825
$r \backslash [\,] $ & $\dn$ & $r$
Chengsong
parents:
diff changeset
  1826
\end{tabular}
Chengsong
parents:
diff changeset
  1827
\end{center}
Chengsong
parents:
diff changeset
  1828
Chengsong
parents:
diff changeset
  1829
\noindent
Chengsong
parents:
diff changeset
  1830
and then define as  regular-expression matching algorithm: 
Chengsong
parents:
diff changeset
  1831
\[
Chengsong
parents:
diff changeset
  1832
match\;s\;r \;\dn\; nullable(r\backslash s)
Chengsong
parents:
diff changeset
  1833
\]
Chengsong
parents:
diff changeset
  1834
Chengsong
parents:
diff changeset
  1835
\noindent
Chengsong
parents:
diff changeset
  1836
This algorithm looks graphically as follows:
Chengsong
parents:
diff changeset
  1837
\begin{equation}\label{graph:*}
Chengsong
parents:
diff changeset
  1838
\begin{tikzcd}
Chengsong
parents:
diff changeset
  1839
r_0 \arrow[r, "\backslash c_0"]  & r_1 \arrow[r, "\backslash c_1"] & r_2 \arrow[r, dashed]  & r_n  \arrow[r,"\textit{nullable}?"] & \;\textrm{YES}/\textrm{NO}
Chengsong
parents:
diff changeset
  1840
\end{tikzcd}
Chengsong
parents:
diff changeset
  1841
\end{equation}
Chengsong
parents:
diff changeset
  1842
Chengsong
parents:
diff changeset
  1843
\noindent
Chengsong
parents:
diff changeset
  1844
where we start with  a regular expression  $r_0$, build successive
Chengsong
parents:
diff changeset
  1845
derivatives until we exhaust the string and then use \textit{nullable}
Chengsong
parents:
diff changeset
  1846
to test whether the result can match the empty string. It can  be
Chengsong
parents:
diff changeset
  1847
relatively  easily shown that this matcher is correct  (that is given
Chengsong
parents:
diff changeset
  1848
an $s = c_0...c_{n-1}$ and an $r_0$, it generates YES if and only if $s \in L(r_0)$).
Chengsong
parents:
diff changeset
  1849
Chengsong
parents:
diff changeset
  1850
 
Chengsong
parents:
diff changeset
  1851
\section{Values and the Algorithm by Sulzmann and Lu}
Chengsong
parents:
diff changeset
  1852
Chengsong
parents:
diff changeset
  1853
One limitation of Brzozowski's algorithm is that it only produces a
Chengsong
parents:
diff changeset
  1854
YES/NO answer for whether a string is being matched by a regular
Chengsong
parents:
diff changeset
  1855
expression.  Sulzmann and Lu~\cite{Sulzmann2014} extended this algorithm
Chengsong
parents:
diff changeset
  1856
to allow generation of an actual matching, called a \emph{value} or
Chengsong
parents:
diff changeset
  1857
sometimes also \emph{lexical value}.  These values and regular
Chengsong
parents:
diff changeset
  1858
expressions correspond to each other as illustrated in the following
Chengsong
parents:
diff changeset
  1859
table:
Chengsong
parents:
diff changeset
  1860
Chengsong
parents:
diff changeset
  1861
Chengsong
parents:
diff changeset
  1862
\begin{center}
Chengsong
parents:
diff changeset
  1863
	\begin{tabular}{c@{\hspace{20mm}}c}
Chengsong
parents:
diff changeset
  1864
		\begin{tabular}{@{}rrl@{}}
Chengsong
parents:
diff changeset
  1865
			\multicolumn{3}{@{}l}{\textbf{Regular Expressions}}\medskip\\
Chengsong
parents:
diff changeset
  1866
			$r$ & $::=$  & $\ZERO$\\
Chengsong
parents:
diff changeset
  1867
			& $\mid$ & $\ONE$   \\
Chengsong
parents:
diff changeset
  1868
			& $\mid$ & $c$          \\
Chengsong
parents:
diff changeset
  1869
			& $\mid$ & $r_1 \cdot r_2$\\
Chengsong
parents:
diff changeset
  1870
			& $\mid$ & $r_1 + r_2$   \\
Chengsong
parents:
diff changeset
  1871
			\\
Chengsong
parents:
diff changeset
  1872
			& $\mid$ & $r^*$         \\
Chengsong
parents:
diff changeset
  1873
		\end{tabular}
Chengsong
parents:
diff changeset
  1874
		&
Chengsong
parents:
diff changeset
  1875
		\begin{tabular}{@{\hspace{0mm}}rrl@{}}
Chengsong
parents:
diff changeset
  1876
			\multicolumn{3}{@{}l}{\textbf{Values}}\medskip\\
Chengsong
parents:
diff changeset
  1877
			$v$ & $::=$  & \\
Chengsong
parents:
diff changeset
  1878
			&        & $\Empty$   \\
Chengsong
parents:
diff changeset
  1879
			& $\mid$ & $\Char(c)$          \\
Chengsong
parents:
diff changeset
  1880
			& $\mid$ & $\Seq\,v_1\, v_2$\\
Chengsong
parents:
diff changeset
  1881
			& $\mid$ & $\Left(v)$   \\
Chengsong
parents:
diff changeset
  1882
			& $\mid$ & $\Right(v)$  \\
Chengsong
parents:
diff changeset
  1883
			& $\mid$ & $\Stars\,[v_1,\ldots\,v_n]$ \\
Chengsong
parents:
diff changeset
  1884
		\end{tabular}
Chengsong
parents:
diff changeset
  1885
	\end{tabular}
Chengsong
parents:
diff changeset
  1886
\end{center}
Chengsong
parents:
diff changeset
  1887
Chengsong
parents:
diff changeset
  1888
\noindent
Chengsong
parents:
diff changeset
  1889
No value  corresponds to $\ZERO$; $\Empty$ corresponds to $\ONE$;
Chengsong
parents:
diff changeset
  1890
$\Char$ to the character regular expression; $\Seq$ to the sequence
Chengsong
parents:
diff changeset
  1891
regular expression and so on. The idea of values is to encode a kind of
Chengsong
parents:
diff changeset
  1892
lexical value for how the sub-parts of a regular expression match the
Chengsong
parents:
diff changeset
  1893
sub-parts of a string. To see this, suppose a \emph{flatten} operation,
Chengsong
parents:
diff changeset
  1894
written $|v|$ for values. We can use this function to extract the
Chengsong
parents:
diff changeset
  1895
underlying string of a value $v$. For example, $|\mathit{Seq} \,
Chengsong
parents:
diff changeset
  1896
(\textit{Char x}) \, (\textit{Char y})|$ is the string $xy$.  Using
Chengsong
parents:
diff changeset
  1897
flatten, we can describe how values encode lexical values: $\Seq\,v_1\,
Chengsong
parents:
diff changeset
  1898
v_2$ encodes a tree with two children nodes that tells how the string
Chengsong
parents:
diff changeset
  1899
$|v_1| @ |v_2|$ matches the regex $r_1 \cdot r_2$ whereby $r_1$ matches
Chengsong
parents:
diff changeset
  1900
the substring $|v_1|$ and, respectively, $r_2$ matches the substring
Chengsong
parents:
diff changeset
  1901
$|v_2|$. Exactly how these two are matched is contained in the children
Chengsong
parents:
diff changeset
  1902
nodes $v_1$ and $v_2$ of parent $\textit{Seq}$. 
Chengsong
parents:
diff changeset
  1903
Chengsong
parents:
diff changeset
  1904
To give a concrete example of how values work, consider the string $xy$
Chengsong
parents:
diff changeset
  1905
and the regular expression $(x + (y + xy))^*$. We can view this regular
Chengsong
parents:
diff changeset
  1906
expression as a tree and if the string $xy$ is matched by two Star
Chengsong
parents:
diff changeset
  1907
``iterations'', then the $x$ is matched by the left-most alternative in
Chengsong
parents:
diff changeset
  1908
this tree and the $y$ by the right-left alternative. This suggests to
Chengsong
parents:
diff changeset
  1909
record this matching as
Chengsong
parents:
diff changeset
  1910
Chengsong
parents:
diff changeset
  1911
\begin{center}
Chengsong
parents:
diff changeset
  1912
$\Stars\,[\Left\,(\Char\,x), \Right(\Left(\Char\,y))]$
Chengsong
parents:
diff changeset
  1913
\end{center}
Chengsong
parents:
diff changeset
  1914
Chengsong
parents:
diff changeset
  1915
\noindent
Chengsong
parents:
diff changeset
  1916
where $\Stars \; [\ldots]$ records all the
Chengsong
parents:
diff changeset
  1917
iterations; and $\Left$, respectively $\Right$, which
Chengsong
parents:
diff changeset
  1918
alternative is used. The value for
Chengsong
parents:
diff changeset
  1919
matching $xy$ in a single ``iteration'', i.e.~the POSIX value,
Chengsong
parents:
diff changeset
  1920
would look as follows
Chengsong
parents:
diff changeset
  1921
Chengsong
parents:
diff changeset
  1922
\begin{center}
Chengsong
parents:
diff changeset
  1923
$\Stars\,[\Seq\,(\Char\,x)\,(\Char\,y)]$
Chengsong
parents:
diff changeset
  1924
\end{center}
Chengsong
parents:
diff changeset
  1925
Chengsong
parents:
diff changeset
  1926
\noindent
Chengsong
parents:
diff changeset
  1927
where $\Stars$ has only a single-element list for the single iteration
Chengsong
parents:
diff changeset
  1928
and $\Seq$ indicates that $xy$ is matched by a sequence regular
Chengsong
parents:
diff changeset
  1929
expression.
Chengsong
parents:
diff changeset
  1930
Chengsong
parents:
diff changeset
  1931
The contribution of Sulzmann and Lu is an extension of Brzozowski's
Chengsong
parents:
diff changeset
  1932
algorithm by a second phase (the first phase being building successive
Chengsong
parents:
diff changeset
  1933
derivatives---see \eqref{graph:*}). In this second phase, a POSIX value 
Chengsong
parents:
diff changeset
  1934
is generated in case the regular expression matches  the string. 
Chengsong
parents:
diff changeset
  1935
Pictorially, the Sulzmann and Lu algorithm is as follows:
Chengsong
parents:
diff changeset
  1936
Chengsong
parents:
diff changeset
  1937
\begin{ceqn}
Chengsong
parents:
diff changeset
  1938
\begin{equation}\label{graph:2}
Chengsong
parents:
diff changeset
  1939
\begin{tikzcd}
Chengsong
parents:
diff changeset
  1940
r_0 \arrow[r, "\backslash c_0"]  \arrow[d] & r_1 \arrow[r, "\backslash c_1"] \arrow[d] & r_2 \arrow[r, dashed] \arrow[d] & r_n \arrow[d, "mkeps" description] \\
Chengsong
parents:
diff changeset
  1941
v_0           & v_1 \arrow[l,"inj_{r_0} c_0"]                & v_2 \arrow[l, "inj_{r_1} c_1"]              & v_n \arrow[l, dashed]         
Chengsong
parents:
diff changeset
  1942
\end{tikzcd}
Chengsong
parents:
diff changeset
  1943
\end{equation}
Chengsong
parents:
diff changeset
  1944
\end{ceqn}
Chengsong
parents:
diff changeset
  1945
Chengsong
parents:
diff changeset
  1946
\noindent
Chengsong
parents:
diff changeset
  1947
For convenience, we shall employ the following notations: the regular
Chengsong
parents:
diff changeset
  1948
expression we start with is $r_0$, and the given string $s$ is composed
Chengsong
parents:
diff changeset
  1949
of characters $c_0 c_1 \ldots c_{n-1}$. In  the first phase from the
Chengsong
parents:
diff changeset
  1950
left to right, we build the derivatives $r_1$, $r_2$, \ldots  according
Chengsong
parents:
diff changeset
  1951
to the characters $c_0$, $c_1$  until we exhaust the string and obtain
Chengsong
parents:
diff changeset
  1952
the derivative $r_n$. We test whether this derivative is
Chengsong
parents:
diff changeset
  1953
$\textit{nullable}$ or not. If not, we know the string does not match
Chengsong
parents:
diff changeset
  1954
$r$ and no value needs to be generated. If yes, we start building the
Chengsong
parents:
diff changeset
  1955
values incrementally by \emph{injecting} back the characters into the
Chengsong
parents:
diff changeset
  1956
earlier values $v_n, \ldots, v_0$. This is the second phase of the
Chengsong
parents:
diff changeset
  1957
algorithm from the right to left. For the first value $v_n$, we call the
Chengsong
parents:
diff changeset
  1958
function $\textit{mkeps}$, which builds the lexical value
Chengsong
parents:
diff changeset
  1959
for how the empty string has been matched by the (nullable) regular
Chengsong
parents:
diff changeset
  1960
expression $r_n$. This function is defined as
Chengsong
parents:
diff changeset
  1961
Chengsong
parents:
diff changeset
  1962
	\begin{center}
Chengsong
parents:
diff changeset
  1963
		\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1964
			$\mkeps(\ONE)$ 		& $\dn$ & $\Empty$ \\
Chengsong
parents:
diff changeset
  1965
			$\mkeps(r_{1}+r_{2})$	& $\dn$ 
Chengsong
parents:
diff changeset
  1966
			& \textit{if} $\nullable(r_{1})$\\ 
Chengsong
parents:
diff changeset
  1967
			& & \textit{then} $\Left(\mkeps(r_{1}))$\\ 
Chengsong
parents:
diff changeset
  1968
			& & \textit{else} $\Right(\mkeps(r_{2}))$\\
Chengsong
parents:
diff changeset
  1969
			$\mkeps(r_1\cdot r_2)$ 	& $\dn$ & $\Seq\,(\mkeps\,r_1)\,(\mkeps\,r_2)$\\
Chengsong
parents:
diff changeset
  1970
			$mkeps(r^*)$	        & $\dn$ & $\Stars\,[]$
Chengsong
parents:
diff changeset
  1971
		\end{tabular}
Chengsong
parents:
diff changeset
  1972
	\end{center}
Chengsong
parents:
diff changeset
  1973
Chengsong
parents:
diff changeset
  1974
Chengsong
parents:
diff changeset
  1975
\noindent There are no cases for $\ZERO$ and $c$, since
Chengsong
parents:
diff changeset
  1976
these regular expression cannot match the empty string. Note
Chengsong
parents:
diff changeset
  1977
also that in case of alternatives we give preference to the
Chengsong
parents:
diff changeset
  1978
regular expression on the left-hand side. This will become
Chengsong
parents:
diff changeset
  1979
important later on about what value is calculated.
Chengsong
parents:
diff changeset
  1980
Chengsong
parents:
diff changeset
  1981
After the $\mkeps$-call, we inject back the characters one by one in order to build
Chengsong
parents:
diff changeset
  1982
the lexical value $v_i$ for how the regex $r_i$ matches the string $s_i$
Chengsong
parents:
diff changeset
  1983
($s_i = c_i \ldots c_{n-1}$ ) from the previous lexical value $v_{i+1}$.
Chengsong
parents:
diff changeset
  1984
After injecting back $n$ characters, we get the lexical value for how $r_0$
Chengsong
parents:
diff changeset
  1985
matches $s$. For this Sulzmann and Lu defined a function that reverses
Chengsong
parents:
diff changeset
  1986
the ``chopping off'' of characters during the derivative phase. The
Chengsong
parents:
diff changeset
  1987
corresponding function is called \emph{injection}, written
Chengsong
parents:
diff changeset
  1988
$\textit{inj}$; it takes three arguments: the first one is a regular
Chengsong
parents:
diff changeset
  1989
expression ${r_{i-1}}$, before the character is chopped off, the second
Chengsong
parents:
diff changeset
  1990
is a character ${c_{i-1}}$, the character we want to inject and the
Chengsong
parents:
diff changeset
  1991
third argument is the value ${v_i}$, into which one wants to inject the
Chengsong
parents:
diff changeset
  1992
character (it corresponds to the regular expression after the character
Chengsong
parents:
diff changeset
  1993
has been chopped off). The result of this function is a new value. The
Chengsong
parents:
diff changeset
  1994
definition of $\textit{inj}$ is as follows: 
Chengsong
parents:
diff changeset
  1995
Chengsong
parents:
diff changeset
  1996
\begin{center}
Chengsong
parents:
diff changeset
  1997
\begin{tabular}{l@{\hspace{1mm}}c@{\hspace{1mm}}l}
Chengsong
parents:
diff changeset
  1998
  $\textit{inj}\,(c)\,c\,Empty$            & $\dn$ & $Char\,c$\\
Chengsong
parents:
diff changeset
  1999
  $\textit{inj}\,(r_1 + r_2)\,c\,\Left(v)$ & $\dn$ & $\Left(\textit{inj}\,r_1\,c\,v)$\\
Chengsong
parents:
diff changeset
  2000
  $\textit{inj}\,(r_1 + r_2)\,c\,Right(v)$ & $\dn$ & $Right(\textit{inj}\,r_2\,c\,v)$\\
Chengsong
parents:
diff changeset
  2001
  $\textit{inj}\,(r_1 \cdot r_2)\,c\,Seq(v_1,v_2)$ & $\dn$  & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\
Chengsong
parents:
diff changeset
  2002
  $\textit{inj}\,(r_1 \cdot r_2)\,c\,\Left(Seq(v_1,v_2))$ & $\dn$  & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\
Chengsong
parents:
diff changeset
  2003
  $\textit{inj}\,(r_1 \cdot r_2)\,c\,Right(v)$ & $\dn$  & $Seq(\textit{mkeps}(r_1),\textit{inj}\,r_2\,c\,v)$\\
Chengsong
parents:
diff changeset
  2004
  $\textit{inj}\,(r^*)\,c\,Seq(v,Stars\,vs)$         & $\dn$  & $Stars((\textit{inj}\,r\,c\,v)\,::\,vs)$\\
Chengsong
parents:
diff changeset
  2005
\end{tabular}
Chengsong
parents:
diff changeset
  2006
\end{center}
Chengsong
parents:
diff changeset
  2007
Chengsong
parents:
diff changeset
  2008
\noindent This definition is by recursion on the ``shape'' of regular
Chengsong
parents:
diff changeset
  2009
expressions and values. To understands this definition better consider
Chengsong
parents:
diff changeset
  2010
the situation when we build the derivative on regular expression $r_{i-1}$.
Chengsong
parents:
diff changeset
  2011
For this we chop off a character from $r_{i-1}$ to form $r_i$. This leaves a
Chengsong
parents:
diff changeset
  2012
``hole'' in $r_i$ and its corresponding value $v_i$. 
Chengsong
parents:
diff changeset
  2013
To calculate $v_{i-1}$, we need to
Chengsong
parents:
diff changeset
  2014
locate where that hole is and fill it. 
Chengsong
parents:
diff changeset
  2015
We can find this location by
Chengsong
parents:
diff changeset
  2016
comparing $r_{i-1}$ and $v_i$. For instance, if $r_{i-1}$ is of shape
Chengsong
parents:
diff changeset
  2017
$r_a \cdot r_b$, and $v_i$ is of shape $\Left(Seq(v_1,v_2))$, we know immediately that 
Chengsong
parents:
diff changeset
  2018
%
Chengsong
parents:
diff changeset
  2019
\[ (r_a \cdot r_b)\backslash c = (r_a\backslash c) \cdot r_b \,+\, r_b\backslash c,\]
Chengsong
parents:
diff changeset
  2020
Chengsong
parents:
diff changeset
  2021
\noindent
Chengsong
parents:
diff changeset
  2022
otherwise if $r_a$ is not nullable,
Chengsong
parents:
diff changeset
  2023
\[ (r_a \cdot r_b)\backslash c = (r_a\backslash c) \cdot r_b,\]
Chengsong
parents:
diff changeset
  2024
Chengsong
parents:
diff changeset
  2025
\noindent
Chengsong
parents:
diff changeset
  2026
the value $v_i$ should be  $\Seq(\ldots)$, contradicting the fact that
Chengsong
parents:
diff changeset
  2027
$v_i$ is actually of shape $\Left(\ldots)$. Furthermore, since $v_i$ is of shape
Chengsong
parents:
diff changeset
  2028
$\Left(\ldots)$ instead of $\Right(\ldots)$, we know that the left
Chengsong
parents:
diff changeset
  2029
branch of \[ (r_a \cdot r_b)\backslash c =
Chengsong
parents:
diff changeset
  2030
\bold{\underline{ (r_a\backslash c) \cdot r_b} }\,+\, r_b\backslash c,\](underlined)
Chengsong
parents:
diff changeset
  2031
 is taken instead of the right one. This means $c$ is chopped off 
Chengsong
parents:
diff changeset
  2032
from $r_a$ rather than $r_b$.
Chengsong
parents:
diff changeset
  2033
We have therefore found out 
Chengsong
parents:
diff changeset
  2034
that the hole will be on $r_a$. So we recursively call $\inj\, 
Chengsong
parents:
diff changeset
  2035
r_a\,c\,v_a$ to fill that hole in $v_a$. After injection, the value 
Chengsong
parents:
diff changeset
  2036
$v_i$ for $r_i = r_a \cdot r_b$ should be $\Seq\,(\inj\,r_a\,c\,v_a)\,v_b$.
Chengsong
parents:
diff changeset
  2037
Other clauses can be understood in a similar way.
Chengsong
parents:
diff changeset
  2038
Chengsong
parents:
diff changeset
  2039
%\comment{Other word: insight?}
Chengsong
parents:
diff changeset
  2040
The following example gives an insight of $\textit{inj}$'s effect and
Chengsong
parents:
diff changeset
  2041
how Sulzmann and Lu's algorithm works as a whole. Suppose we have a
Chengsong
parents:
diff changeset
  2042
regular expression $((((a+b)+ab)+c)+abc)^*$, and want to match it
Chengsong
parents:
diff changeset
  2043
against the string $abc$ (when $abc$ is written as a regular expression,
Chengsong
parents:
diff changeset
  2044
the standard way of expressing it is $a \cdot (b \cdot c)$. But we
Chengsong
parents:
diff changeset
  2045
usually omit the parentheses and dots here for better readability. This
Chengsong
parents:
diff changeset
  2046
algorithm returns a POSIX value, which means it will produce the longest
Chengsong
parents:
diff changeset
  2047
matching. Consequently, it matches the string $abc$ in one star
Chengsong
parents:
diff changeset
  2048
iteration, using the longest alternative $abc$ in the sub-expression (we shall use $r$ to denote this
Chengsong
parents:
diff changeset
  2049
sub-expression for conciseness):
Chengsong
parents:
diff changeset
  2050
Chengsong
parents:
diff changeset
  2051
\[((((a+b)+ab)+c)+\underbrace{abc}_r)\] 
Chengsong
parents:
diff changeset
  2052
Chengsong
parents:
diff changeset
  2053
\noindent
Chengsong
parents:
diff changeset
  2054
Before $\textit{inj}$ is called, our lexer first builds derivative using
Chengsong
parents:
diff changeset
  2055
string $abc$ (we simplified some regular expressions like $\ZERO \cdot
Chengsong
parents:
diff changeset
  2056
b$ to $\ZERO$ for conciseness; we also omit parentheses if they are
Chengsong
parents:
diff changeset
  2057
clear from the context):
Chengsong
parents:
diff changeset
  2058
Chengsong
parents:
diff changeset
  2059
%Similarly, we allow
Chengsong
parents:
diff changeset
  2060
%$\textit{ALT}$ to take a list of regular expressions as an argument
Chengsong
parents:
diff changeset
  2061
%instead of just 2 operands to reduce the nested depth of
Chengsong
parents:
diff changeset
  2062
%$\textit{ALT}$
Chengsong
parents:
diff changeset
  2063
Chengsong
parents:
diff changeset
  2064
\begin{center}
Chengsong
parents:
diff changeset
  2065
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2066
$r^*$ & $\xrightarrow{\backslash a}$ & $r_1 = (\ONE+\ZERO+\ONE \cdot b + \ZERO + \ONE \cdot b \cdot c) \cdot r^*$\\
Chengsong
parents:
diff changeset
  2067
      & $\xrightarrow{\backslash b}$ & $r_2 = (\ZERO+\ZERO+\ONE \cdot \ONE + \ZERO + \ONE \cdot \ONE \cdot c) \cdot r^* +(\ZERO+\ONE+\ZERO  + \ZERO + \ZERO) \cdot r^*$\\
Chengsong
parents:
diff changeset
  2068
      & $\xrightarrow{\backslash c}$ & $r_3 = ((\ZERO+\ZERO+\ZERO + \ZERO + \ONE \cdot \ONE \cdot \ONE) \cdot r^* + (\ZERO+\ZERO+\ZERO  + \ONE + \ZERO) \cdot r^*) + $\\ 
Chengsong
parents:
diff changeset
  2069
      &                              & $\phantom{r_3 = (} ((\ZERO+\ONE+\ZERO  + \ZERO + \ZERO) \cdot r^* + (\ZERO+\ZERO+\ZERO  + \ONE + \ZERO) \cdot r^* )$
Chengsong
parents:
diff changeset
  2070
\end{tabular}
Chengsong
parents:
diff changeset
  2071
\end{center}
Chengsong
parents:
diff changeset
  2072
Chengsong
parents:
diff changeset
  2073
\noindent
Chengsong
parents:
diff changeset
  2074
In  case $r_3$ is nullable, we can call $\textit{mkeps}$ 
Chengsong
parents:
diff changeset
  2075
to construct a lexical value for how $r_3$ matched the string $abc$. 
Chengsong
parents:
diff changeset
  2076
This function gives the following value $v_3$: 
Chengsong
parents:
diff changeset
  2077
Chengsong
parents:
diff changeset
  2078
Chengsong
parents:
diff changeset
  2079
\begin{center}
Chengsong
parents:
diff changeset
  2080
$\Left(\Left(\Seq(\Right(\Seq(\Empty, \Seq(\Empty,\Empty))), \Stars [])))$
Chengsong
parents:
diff changeset
  2081
\end{center}
Chengsong
parents:
diff changeset
  2082
The outer $\Left(\Left(\ldots))$ tells us the leftmost nullable part of $r_3$(underlined):
Chengsong
parents:
diff changeset
  2083
Chengsong
parents:
diff changeset
  2084
\begin{center}
Chengsong
parents:
diff changeset
  2085
	\begin{tabular}{l@{\hspace{2mm}}l}
Chengsong
parents:
diff changeset
  2086
    & $\big(\underline{(\ZERO+\ZERO+\ZERO+ \ZERO+ \ONE \cdot \ONE \cdot \ONE) \cdot r^*} 
Chengsong
parents:
diff changeset
  2087
    \;+\; (\ZERO+\ZERO+\ZERO + \ONE + \ZERO) \cdot r^*\big)$ \smallskip\\
Chengsong
parents:
diff changeset
  2088
    $+$ & $\big((\ZERO+\ONE+\ZERO  + \ZERO + \ZERO) \cdot r^*
Chengsong
parents:
diff changeset
  2089
    \;+\; (\ZERO+\ZERO+\ZERO  + \ONE + \ZERO) \cdot r^* \big)$
Chengsong
parents:
diff changeset
  2090
  	\end{tabular}
Chengsong
parents:
diff changeset
  2091
 \end{center}
Chengsong
parents:
diff changeset
  2092
Chengsong
parents:
diff changeset
  2093
\noindent
Chengsong
parents:
diff changeset
  2094
 Note that the leftmost location of term $(\ZERO+\ZERO+\ZERO + \ZERO + \ONE \cdot \ONE \cdot
Chengsong
parents:
diff changeset
  2095
 \ONE) \cdot r^*$ (which corresponds to the initial sub-match $abc$) allows
Chengsong
parents:
diff changeset
  2096
 $\textit{mkeps}$ to pick it up because $\textit{mkeps}$ is defined to always choose the
Chengsong
parents:
diff changeset
  2097
 left one when it is nullable. In the case of this example, $abc$ is
Chengsong
parents:
diff changeset
  2098
 preferred over $a$ or $ab$. This $\Left(\Left(\ldots))$ location is
Chengsong
parents:
diff changeset
  2099
 generated by two applications of the splitting clause
Chengsong
parents:
diff changeset
  2100
Chengsong
parents:
diff changeset
  2101
\begin{center}
Chengsong
parents:
diff changeset
  2102
     $(r_1 \cdot r_2)\backslash c  \;\;(when \; r_1 \; nullable) \, = (r_1\backslash c) \cdot r_2 \,+\, r_2\backslash c.$
Chengsong
parents:
diff changeset
  2103
\end{center}
Chengsong
parents:
diff changeset
  2104
       
Chengsong
parents:
diff changeset
  2105
\noindent
Chengsong
parents:
diff changeset
  2106
By this clause, we put $r_1 \backslash c \cdot r_2 $ at the
Chengsong
parents:
diff changeset
  2107
$\textit{front}$ and $r_2 \backslash c$ at the $\textit{back}$. This
Chengsong
parents:
diff changeset
  2108
allows $\textit{mkeps}$ to always pick up among two matches the one with a longer
Chengsong
parents:
diff changeset
  2109
initial sub-match. Removing the outside $\Left(\Left(...))$, the inside
Chengsong
parents:
diff changeset
  2110
sub-value 
Chengsong
parents:
diff changeset
  2111
 
Chengsong
parents:
diff changeset
  2112
\begin{center}
Chengsong
parents:
diff changeset
  2113
 $\Seq(\Right(\Seq(\Empty, \Seq(\Empty, \Empty))), \Stars [])$
Chengsong
parents:
diff changeset
  2114
\end{center}
Chengsong
parents:
diff changeset
  2115
Chengsong
parents:
diff changeset
  2116
\noindent
Chengsong
parents:
diff changeset
  2117
tells us how the empty string $[]$ is matched with $(\ZERO+\ZERO+\ZERO + \ZERO + \ONE \cdot
Chengsong
parents:
diff changeset
  2118
\ONE \cdot \ONE) \cdot r^*$. We match $[]$ by a sequence of two nullable regular
Chengsong
parents:
diff changeset
  2119
expressions. The first one is an alternative, we take the rightmost
Chengsong
parents:
diff changeset
  2120
alternative---whose language contains the empty string. The second
Chengsong
parents:
diff changeset
  2121
nullable regular expression is a Kleene star. $\Stars$ tells us how it
Chengsong
parents:
diff changeset
  2122
generates the nullable regular expression: by 0 iterations to form
Chengsong
parents:
diff changeset
  2123
$\ONE$. Now $\textit{inj}$ injects characters back and incrementally
Chengsong
parents:
diff changeset
  2124
builds a lexical value based on $v_3$. Using the value $v_3$, the character
Chengsong
parents:
diff changeset
  2125
c, and the regular expression $r_2$, we can recover how $r_2$ matched
Chengsong
parents:
diff changeset
  2126
the string $[c]$ : $\textit{inj} \; r_2 \; c \; v_3$ gives us
Chengsong
parents:
diff changeset
  2127
 \begin{center}
Chengsong
parents:
diff changeset
  2128
 $v_2 = \Left(\Seq(\Right(\Seq(\Empty, \Seq(\Empty, c))), \Stars [])),$
Chengsong
parents:
diff changeset
  2129
 \end{center}
Chengsong
parents:
diff changeset
  2130
which tells us how $r_2$ matched $[c]$. After this we inject back the character $b$, and get
Chengsong
parents:
diff changeset
  2131
\begin{center}
Chengsong
parents:
diff changeset
  2132
$v_1 = \Seq(\Right(\Seq(\Empty, \Seq(b, c))), \Stars [])$
Chengsong
parents:
diff changeset
  2133
\end{center}
Chengsong
parents:
diff changeset
  2134
 for how 
Chengsong
parents:
diff changeset
  2135
 \begin{center}
Chengsong
parents:
diff changeset
  2136
 $r_1= (\ONE+\ZERO+\ONE \cdot b + \ZERO + \ONE \cdot b \cdot c) \cdot r*$
Chengsong
parents:
diff changeset
  2137
 \end{center}
Chengsong
parents:
diff changeset
  2138
  matched  the string $bc$ before it split into two substrings. 
Chengsong
parents:
diff changeset
  2139
  Finally, after injecting character $a$ back to $v_1$, 
Chengsong
parents:
diff changeset
  2140
  we get  the lexical value tree 
Chengsong
parents:
diff changeset
  2141
  \begin{center}
Chengsong
parents:
diff changeset
  2142
  $v_0= \Stars [\Right(\Seq(a, \Seq(b, c)))]$
Chengsong
parents:
diff changeset
  2143
  \end{center}
Chengsong
parents:
diff changeset
  2144
   for how $r$ matched $abc$. This completes the algorithm.
Chengsong
parents:
diff changeset
  2145
   
Chengsong
parents:
diff changeset
  2146
%We omit the details of injection function, which is provided by Sulzmann and Lu's paper \cite{Sulzmann2014}. 
Chengsong
parents:
diff changeset
  2147
Readers might have noticed that the lexical value information is actually
Chengsong
parents:
diff changeset
  2148
already available when doing derivatives. For example, immediately after
Chengsong
parents:
diff changeset
  2149
the operation $\backslash a$ we know that if we want to match a string
Chengsong
parents:
diff changeset
  2150
that starts with $a$, we can either take the initial match to be 
Chengsong
parents:
diff changeset
  2151
Chengsong
parents:
diff changeset
  2152
 \begin{center}
Chengsong
parents:
diff changeset
  2153
\begin{enumerate}
Chengsong
parents:
diff changeset
  2154
    \item[1)] just $a$ or
Chengsong
parents:
diff changeset
  2155
    \item[2)] string $ab$ or 
Chengsong
parents:
diff changeset
  2156
    \item[3)] string $abc$.
Chengsong
parents:
diff changeset
  2157
\end{enumerate}
Chengsong
parents:
diff changeset
  2158
\end{center}
Chengsong
parents:
diff changeset
  2159
Chengsong
parents:
diff changeset
  2160
\noindent
Chengsong
parents:
diff changeset
  2161
In order to differentiate between these choices, we just need to
Chengsong
parents:
diff changeset
  2162
remember their positions---$a$ is on the left, $ab$ is in the middle ,
Chengsong
parents:
diff changeset
  2163
and $abc$ is on the right. Which of these alternatives is chosen
Chengsong
parents:
diff changeset
  2164
later does not affect their relative position because the algorithm does
Chengsong
parents:
diff changeset
  2165
not change this order. If this parsing information can be determined and
Chengsong
parents:
diff changeset
  2166
does not change because of later derivatives, there is no point in
Chengsong
parents:
diff changeset
  2167
traversing this information twice. This leads to an optimisation---if we
Chengsong
parents:
diff changeset
  2168
store the information for lexical values inside the regular expression,
Chengsong
parents:
diff changeset
  2169
update it when we do derivative on them, and collect the information
Chengsong
parents:
diff changeset
  2170
when finished with derivatives and call $\textit{mkeps}$ for deciding which
Chengsong
parents:
diff changeset
  2171
branch is POSIX, we can generate the lexical value in one pass, instead of
Chengsong
parents:
diff changeset
  2172
doing the rest $n$ injections. This leads to Sulzmann and Lu's novel
Chengsong
parents:
diff changeset
  2173
idea of using bitcodes in derivatives.
Chengsong
parents:
diff changeset
  2174
Chengsong
parents:
diff changeset
  2175
In the next section, we shall focus on the bitcoded algorithm and the
Chengsong
parents:
diff changeset
  2176
process of simplification of regular expressions. This is needed in
Chengsong
parents:
diff changeset
  2177
order to obtain \emph{fast} versions of the Brzozowski's, and Sulzmann
Chengsong
parents:
diff changeset
  2178
and Lu's algorithms.  This is where the PhD-project aims to advance the
Chengsong
parents:
diff changeset
  2179
state-of-the-art.
Chengsong
parents:
diff changeset
  2180
Chengsong
parents:
diff changeset
  2181
Chengsong
parents:
diff changeset
  2182
\section{Simplification of Regular Expressions}
Chengsong
parents:
diff changeset
  2183
Chengsong
parents:
diff changeset
  2184
Using bitcodes to guide  parsing is not a novel idea. It was applied to
Chengsong
parents:
diff changeset
  2185
context free grammars and then adapted by Henglein and Nielson for
Chengsong
parents:
diff changeset
  2186
efficient regular expression  lexing using DFAs~\cite{nielson11bcre}.
Chengsong
parents:
diff changeset
  2187
Sulzmann and Lu took this idea of bitcodes a step further by integrating
Chengsong
parents:
diff changeset
  2188
bitcodes into derivatives. The reason why we want to use bitcodes in
Chengsong
parents:
diff changeset
  2189
this project is that we want to introduce more aggressive simplification
Chengsong
parents:
diff changeset
  2190
rules in order to keep the size of derivatives small throughout. This is
Chengsong
parents:
diff changeset
  2191
because the main drawback of building successive derivatives according
Chengsong
parents:
diff changeset
  2192
to Brzozowski's definition is that they can grow very quickly in size.
Chengsong
parents:
diff changeset
  2193
This is mainly due to the fact that the derivative operation generates
Chengsong
parents:
diff changeset
  2194
often ``useless'' $\ZERO$s and $\ONE$s in derivatives.  As a result, if
Chengsong
parents:
diff changeset
  2195
implemented naively both algorithms by Brzozowski and by Sulzmann and Lu
Chengsong
parents:
diff changeset
  2196
are excruciatingly slow. For example when starting with the regular
Chengsong
parents:
diff changeset
  2197
expression $(a + aa)^*$ and building 12 successive derivatives
Chengsong
parents:
diff changeset
  2198
w.r.t.~the character $a$, one obtains a derivative regular expression
Chengsong
parents:
diff changeset
  2199
with more than 8000 nodes (when viewed as a tree). Operations like
Chengsong
parents:
diff changeset
  2200
$\textit{der}$ and $\nullable$ need to traverse such trees and
Chengsong
parents:
diff changeset
  2201
consequently the bigger the size of the derivative the slower the
Chengsong
parents:
diff changeset
  2202
algorithm. 
Chengsong
parents:
diff changeset
  2203
Chengsong
parents:
diff changeset
  2204
Fortunately, one can simplify regular expressions after each derivative
Chengsong
parents:
diff changeset
  2205
step. Various simplifications of regular expressions are possible, such
Chengsong
parents:
diff changeset
  2206
as the simplification of $\ZERO + r$, $r + \ZERO$, $\ONE\cdot r$, $r
Chengsong
parents:
diff changeset
  2207
\cdot \ONE$, and $r + r$ to just $r$. These simplifications do not
Chengsong
parents:
diff changeset
  2208
affect the answer for whether a regular expression matches a string or
Chengsong
parents:
diff changeset
  2209
not, but fortunately also do not affect the POSIX strategy of how
Chengsong
parents:
diff changeset
  2210
regular expressions match strings---although the latter is much harder
Chengsong
parents:
diff changeset
  2211
to establish. Some initial results in this regard have been
Chengsong
parents:
diff changeset
  2212
obtained in \cite{AusafDyckhoffUrban2016}. 
Chengsong
parents:
diff changeset
  2213
Chengsong
parents:
diff changeset
  2214
Unfortunately, the simplification rules outlined above  are not
Chengsong
parents:
diff changeset
  2215
sufficient to prevent a size explosion in all cases. We
Chengsong
parents:
diff changeset
  2216
believe a tighter bound can be achieved that prevents an explosion in
Chengsong
parents:
diff changeset
  2217
\emph{all} cases. Such a tighter bound is suggested by work of Antimirov who
Chengsong
parents:
diff changeset
  2218
proved that (partial) derivatives can be bound by the number of
Chengsong
parents:
diff changeset
  2219
characters contained in the initial regular expression
Chengsong
parents:
diff changeset
  2220
\cite{Antimirov95}. He defined the \emph{partial derivatives} of regular
Chengsong
parents:
diff changeset
  2221
expressions as follows:
Chengsong
parents:
diff changeset
  2222
Chengsong
parents:
diff changeset
  2223
\begin{center}
Chengsong
parents:
diff changeset
  2224
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2225
 $\textit{pder} \; c \; \ZERO$ & $\dn$ & $\emptyset$\\
Chengsong
parents:
diff changeset
  2226
 $\textit{pder} \; c \; \ONE$ & $\dn$ & $\emptyset$ \\
Chengsong
parents:
diff changeset
  2227
 $\textit{pder} \; c \; d$ & $\dn$ & $\textit{if} \; c \,=\, d \; \{  \ONE   \}  \; \textit{else} \; \emptyset$ \\ 
Chengsong
parents:
diff changeset
  2228
  $\textit{pder} \; c \; r_1+r_2$ & $\dn$ & $pder \; c \; r_1 \cup pder \; c \;  r_2$ \\
Chengsong
parents:
diff changeset
  2229
   $\textit{pder} \; c \; r_1 \cdot r_2$ & $\dn$ & $\textit{if} \; nullable \; r_1 $\\
Chengsong
parents:
diff changeset
  2230
     & & $\textit{then} \; \{  r \cdot r_2 \mid r \in pder \; c \; r_1   \}  \cup pder \; c \; r_2 \;$\\
Chengsong
parents:
diff changeset
  2231
     & & $\textit{else} \; \{  r \cdot r_2 \mid r \in pder \; c \; r_1   \} $ \\ 
Chengsong
parents:
diff changeset
  2232
     $\textit{pder} \; c \; r^*$ & $\dn$ & $ \{  r' \cdot r^* \mid r' \in pder \; c \; r   \}  $ \\  
Chengsong
parents:
diff changeset
  2233
 \end{tabular}
Chengsong
parents:
diff changeset
  2234
 \end{center}
Chengsong
parents:
diff changeset
  2235
Chengsong
parents:
diff changeset
  2236
\noindent
Chengsong
parents:
diff changeset
  2237
A partial derivative of a regular expression $r$ is essentially a set of
Chengsong
parents:
diff changeset
  2238
regular expressions that are either $r$'s children expressions or a
Chengsong
parents:
diff changeset
  2239
concatenation of them. Antimirov has proved a tight bound of the sum of
Chengsong
parents:
diff changeset
  2240
the size of \emph{all} partial derivatives no matter what the string
Chengsong
parents:
diff changeset
  2241
looks like. Roughly speaking the size sum will be at most cubic in the
Chengsong
parents:
diff changeset
  2242
size of the regular expression.
Chengsong
parents:
diff changeset
  2243
Chengsong
parents:
diff changeset
  2244
If we want the size of derivatives in Sulzmann and Lu's algorithm to
Chengsong
parents:
diff changeset
  2245
stay below this bound, we would need more aggressive simplifications.
Chengsong
parents:
diff changeset
  2246
Essentially we need to delete useless $\ZERO$s and $\ONE$s, as well as
Chengsong
parents:
diff changeset
  2247
deleting duplicates whenever possible. For example, the parentheses in
Chengsong
parents:
diff changeset
  2248
$(a+b) \cdot c + bc$ can be opened up to get $a\cdot c +  b \cdot c + b
Chengsong
parents:
diff changeset
  2249
\cdot c$, and then simplified to just $a \cdot c + b \cdot c$. Another
Chengsong
parents:
diff changeset
  2250
example is simplifying $(a^*+a) + (a^*+ \ONE) + (a +\ONE)$ to just
Chengsong
parents:
diff changeset
  2251
$a^*+a+\ONE$. Adding these more aggressive simplification rules helps us
Chengsong
parents:
diff changeset
  2252
to achieve the same size bound as that of the partial derivatives. 
Chengsong
parents:
diff changeset
  2253
Chengsong
parents:
diff changeset
  2254
In order to implement the idea of ``spilling out alternatives'' and to
Chengsong
parents:
diff changeset
  2255
make them compatible with the $\text{inj}$-mechanism, we use
Chengsong
parents:
diff changeset
  2256
\emph{bitcodes}. Bits and bitcodes (lists of bits) are just:
Chengsong
parents:
diff changeset
  2257
Chengsong
parents:
diff changeset
  2258
%This allows us to prove a tight
Chengsong
parents:
diff changeset
  2259
%bound on the size of regular expression during the running time of the
Chengsong
parents:
diff changeset
  2260
%algorithm if we can establish the connection between our simplification
Chengsong
parents:
diff changeset
  2261
%rules and partial derivatives.
Chengsong
parents:
diff changeset
  2262
Chengsong
parents:
diff changeset
  2263
 %We believe, and have generated test
Chengsong
parents:
diff changeset
  2264
%data, that a similar bound can be obtained for the derivatives in
Chengsong
parents:
diff changeset
  2265
%Sulzmann and Lu's algorithm. Let us give some details about this next.
Chengsong
parents:
diff changeset
  2266
Chengsong
parents:
diff changeset
  2267
Chengsong
parents:
diff changeset
  2268
\begin{center}
Chengsong
parents:
diff changeset
  2269
		$b ::=   S \mid  Z \qquad
Chengsong
parents:
diff changeset
  2270
bs ::= [] \mid b:bs    
Chengsong
parents:
diff changeset
  2271
$
Chengsong
parents:
diff changeset
  2272
\end{center}
Chengsong
parents:
diff changeset
  2273
Chengsong
parents:
diff changeset
  2274
\noindent
Chengsong
parents:
diff changeset
  2275
The $S$ and $Z$ are arbitrary names for the bits in order to avoid 
Chengsong
parents:
diff changeset
  2276
confusion with the regular expressions $\ZERO$ and $\ONE$. Bitcodes (or
Chengsong
parents:
diff changeset
  2277
bit-lists) can be used to encode values (or incomplete values) in a
Chengsong
parents:
diff changeset
  2278
compact form. This can be straightforwardly seen in the following
Chengsong
parents:
diff changeset
  2279
coding function from values to bitcodes: 
Chengsong
parents:
diff changeset
  2280
Chengsong
parents:
diff changeset
  2281
\begin{center}
Chengsong
parents:
diff changeset
  2282
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2283
  $\textit{code}(\Empty)$ & $\dn$ & $[]$\\
Chengsong
parents:
diff changeset
  2284
  $\textit{code}(\Char\,c)$ & $\dn$ & $[]$\\
Chengsong
parents:
diff changeset
  2285
  $\textit{code}(\Left\,v)$ & $\dn$ & $\Z :: code(v)$\\
Chengsong
parents:
diff changeset
  2286
  $\textit{code}(\Right\,v)$ & $\dn$ & $\S :: code(v)$\\
Chengsong
parents:
diff changeset
  2287
  $\textit{code}(\Seq\,v_1\,v_2)$ & $\dn$ & $code(v_1) \,@\, code(v_2)$\\
Chengsong
parents:
diff changeset
  2288
  $\textit{code}(\Stars\,[])$ & $\dn$ & $[\Z]$\\
Chengsong
parents:
diff changeset
  2289
  $\textit{code}(\Stars\,(v\!::\!vs))$ & $\dn$ & $\S :: code(v) \;@\;
Chengsong
parents:
diff changeset
  2290
                                                 code(\Stars\,vs)$
Chengsong
parents:
diff changeset
  2291
\end{tabular}    
Chengsong
parents:
diff changeset
  2292
\end{center} 
Chengsong
parents:
diff changeset
  2293
Chengsong
parents:
diff changeset
  2294
\noindent
Chengsong
parents:
diff changeset
  2295
Here $\textit{code}$ encodes a value into a bitcodes by converting
Chengsong
parents:
diff changeset
  2296
$\Left$ into $\Z$, $\Right$ into $\S$, the start point of a non-empty
Chengsong
parents:
diff changeset
  2297
star iteration into $\S$, and the border where a local star terminates
Chengsong
parents:
diff changeset
  2298
into $\Z$. This coding is lossy, as it throws away the information about
Chengsong
parents:
diff changeset
  2299
characters, and also does not encode the ``boundary'' between two
Chengsong
parents:
diff changeset
  2300
sequence values. Moreover, with only the bitcode we cannot even tell
Chengsong
parents:
diff changeset
  2301
whether the $\S$s and $\Z$s are for $\Left/\Right$ or $\Stars$. The
Chengsong
parents:
diff changeset
  2302
reason for choosing this compact way of storing information is that the
Chengsong
parents:
diff changeset
  2303
relatively small size of bits can be easily manipulated and ``moved
Chengsong
parents:
diff changeset
  2304
around'' in a regular expression. In order to recover values, we will 
Chengsong
parents:
diff changeset
  2305
need the corresponding regular expression as an extra information. This
Chengsong
parents:
diff changeset
  2306
means the decoding function is defined as:
Chengsong
parents:
diff changeset
  2307
Chengsong
parents:
diff changeset
  2308
Chengsong
parents:
diff changeset
  2309
%\begin{definition}[Bitdecoding of Values]\mbox{}
Chengsong
parents:
diff changeset
  2310
\begin{center}
Chengsong
parents:
diff changeset
  2311
\begin{tabular}{@{}l@{\hspace{1mm}}c@{\hspace{1mm}}l@{}}
Chengsong
parents:
diff changeset
  2312
  $\textit{decode}'\,bs\,(\ONE)$ & $\dn$ & $(\Empty, bs)$\\
Chengsong
parents:
diff changeset
  2313
  $\textit{decode}'\,bs\,(c)$ & $\dn$ & $(\Char\,c, bs)$\\
Chengsong
parents:
diff changeset
  2314
  $\textit{decode}'\,(\Z\!::\!bs)\;(r_1 + r_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2315
     $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}\;
Chengsong
parents:
diff changeset
  2316
       (\Left\,v, bs_1)$\\
Chengsong
parents:
diff changeset
  2317
  $\textit{decode}'\,(\S\!::\!bs)\;(r_1 + r_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2318
     $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_2\;\textit{in}\;
Chengsong
parents:
diff changeset
  2319
       (\Right\,v, bs_1)$\\                           
Chengsong
parents:
diff changeset
  2320
  $\textit{decode}'\,bs\;(r_1\cdot r_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2321
        $\textit{let}\,(v_1, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}$\\
Chengsong
parents:
diff changeset
  2322
  & &   $\textit{let}\,(v_2, bs_2) = \textit{decode}'\,bs_1\,r_2$\\
Chengsong
parents:
diff changeset
  2323
  & &   \hspace{35mm}$\textit{in}\;(\Seq\,v_1\,v_2, bs_2)$\\
Chengsong
parents:
diff changeset
  2324
  $\textit{decode}'\,(\Z\!::\!bs)\,(r^*)$ & $\dn$ & $(\Stars\,[], bs)$\\
Chengsong
parents:
diff changeset
  2325
  $\textit{decode}'\,(\S\!::\!bs)\,(r^*)$ & $\dn$ & 
Chengsong
parents:
diff changeset
  2326
         $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r\;\textit{in}$\\
Chengsong
parents:
diff changeset
  2327
  & &   $\textit{let}\,(\Stars\,vs, bs_2) = \textit{decode}'\,bs_1\,r^*$\\
Chengsong
parents:
diff changeset
  2328
  & &   \hspace{35mm}$\textit{in}\;(\Stars\,v\!::\!vs, bs_2)$\bigskip\\
Chengsong
parents:
diff changeset
  2329
  
Chengsong
parents:
diff changeset
  2330
  $\textit{decode}\,bs\,r$ & $\dn$ &
Chengsong
parents:
diff changeset
  2331
     $\textit{let}\,(v, bs') = \textit{decode}'\,bs\,r\;\textit{in}$\\
Chengsong
parents:
diff changeset
  2332
  & & $\textit{if}\;bs' = []\;\textit{then}\;\textit{Some}\,v\;
Chengsong
parents:
diff changeset
  2333
       \textit{else}\;\textit{None}$                       
Chengsong
parents:
diff changeset
  2334
\end{tabular}    
Chengsong
parents:
diff changeset
  2335
\end{center}    
Chengsong
parents:
diff changeset
  2336
%\end{definition}
Chengsong
parents:
diff changeset
  2337
Chengsong
parents:
diff changeset
  2338
Sulzmann and Lu's integrated the bitcodes into regular expressions to
Chengsong
parents:
diff changeset
  2339
create annotated regular expressions \cite{Sulzmann2014}.
Chengsong
parents:
diff changeset
  2340
\emph{Annotated regular expressions} are defined by the following
Chengsong
parents:
diff changeset
  2341
grammar:%\comment{ALTS should have  an $as$ in  the definitions, not  just $a_1$ and $a_2$}
Chengsong
parents:
diff changeset
  2342
Chengsong
parents:
diff changeset
  2343
\begin{center}
Chengsong
parents:
diff changeset
  2344
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2345
  $\textit{a}$ & $::=$  & $\textit{ZERO}$\\
Chengsong
parents:
diff changeset
  2346
                  & $\mid$ & $\textit{ONE}\;\;bs$\\
Chengsong
parents:
diff changeset
  2347
                  & $\mid$ & $\textit{CHAR}\;\;bs\,c$\\
Chengsong
parents:
diff changeset
  2348
                  & $\mid$ & $\textit{ALTS}\;\;bs\,as$\\
Chengsong
parents:
diff changeset
  2349
                  & $\mid$ & $\textit{SEQ}\;\;bs\,a_1\,a_2$\\
Chengsong
parents:
diff changeset
  2350
                  & $\mid$ & $\textit{STAR}\;\;bs\,a$
Chengsong
parents:
diff changeset
  2351
\end{tabular}    
Chengsong
parents:
diff changeset
  2352
\end{center}  
Chengsong
parents:
diff changeset
  2353
%(in \textit{ALTS})
Chengsong
parents:
diff changeset
  2354
Chengsong
parents:
diff changeset
  2355
\noindent
Chengsong
parents:
diff changeset
  2356
where $bs$ stands for bitcodes, $a$  for $\bold{a}$nnotated regular
Chengsong
parents:
diff changeset
  2357
expressions and $as$ for a list of annotated regular expressions.
Chengsong
parents:
diff changeset
  2358
The alternative constructor($\textit{ALTS}$) has been generalized to 
Chengsong
parents:
diff changeset
  2359
accept a list of annotated regular expressions rather than just 2.
Chengsong
parents:
diff changeset
  2360
We will show that these bitcodes encode information about
Chengsong
parents:
diff changeset
  2361
the (POSIX) value that should be generated by the Sulzmann and Lu
Chengsong
parents:
diff changeset
  2362
algorithm.
Chengsong
parents:
diff changeset
  2363
Chengsong
parents:
diff changeset
  2364
Chengsong
parents:
diff changeset
  2365
To do lexing using annotated regular expressions, we shall first
Chengsong
parents:
diff changeset
  2366
transform the usual (un-annotated) regular expressions into annotated
Chengsong
parents:
diff changeset
  2367
regular expressions. This operation is called \emph{internalisation} and
Chengsong
parents:
diff changeset
  2368
defined as follows:
Chengsong
parents:
diff changeset
  2369
Chengsong
parents:
diff changeset
  2370
%\begin{definition}
Chengsong
parents:
diff changeset
  2371
\begin{center}
Chengsong
parents:
diff changeset
  2372
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2373
  $(\ZERO)^\uparrow$ & $\dn$ & $\textit{ZERO}$\\
Chengsong
parents:
diff changeset
  2374
  $(\ONE)^\uparrow$ & $\dn$ & $\textit{ONE}\,[]$\\
Chengsong
parents:
diff changeset
  2375
  $(c)^\uparrow$ & $\dn$ & $\textit{CHAR}\,[]\,c$\\
Chengsong
parents:
diff changeset
  2376
  $(r_1 + r_2)^\uparrow$ & $\dn$ &
Chengsong
parents:
diff changeset
  2377
  $\textit{ALTS}\;[]\,List((\textit{fuse}\,[\Z]\,r_1^\uparrow),\,
Chengsong
parents:
diff changeset
  2378
  (\textit{fuse}\,[\S]\,r_2^\uparrow))$\\
Chengsong
parents:
diff changeset
  2379
  $(r_1\cdot r_2)^\uparrow$ & $\dn$ &
Chengsong
parents:
diff changeset
  2380
         $\textit{SEQ}\;[]\,r_1^\uparrow\,r_2^\uparrow$\\
Chengsong
parents:
diff changeset
  2381
  $(r^*)^\uparrow$ & $\dn$ &
Chengsong
parents:
diff changeset
  2382
         $\textit{STAR}\;[]\,r^\uparrow$\\
Chengsong
parents:
diff changeset
  2383
\end{tabular}    
Chengsong
parents:
diff changeset
  2384
\end{center}    
Chengsong
parents:
diff changeset
  2385
%\end{definition}
Chengsong
parents:
diff changeset
  2386
Chengsong
parents:
diff changeset
  2387
\noindent
Chengsong
parents:
diff changeset
  2388
We use up arrows here to indicate that the basic un-annotated regular
Chengsong
parents:
diff changeset
  2389
expressions are ``lifted up'' into something slightly more complex. In the
Chengsong
parents:
diff changeset
  2390
fourth clause, $\textit{fuse}$ is an auxiliary function that helps to
Chengsong
parents:
diff changeset
  2391
attach bits to the front of an annotated regular expression. Its
Chengsong
parents:
diff changeset
  2392
definition is as follows:
Chengsong
parents:
diff changeset
  2393
Chengsong
parents:
diff changeset
  2394
\begin{center}
Chengsong
parents:
diff changeset
  2395
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2396
  $\textit{fuse}\;bs\,(\textit{ZERO})$ & $\dn$ & $\textit{ZERO}$\\
Chengsong
parents:
diff changeset
  2397
  $\textit{fuse}\;bs\,(\textit{ONE}\,bs')$ & $\dn$ &
Chengsong
parents:
diff changeset
  2398
     $\textit{ONE}\,(bs\,@\,bs')$\\
Chengsong
parents:
diff changeset
  2399
  $\textit{fuse}\;bs\,(\textit{CHAR}\,bs'\,c)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2400
     $\textit{CHAR}\,(bs\,@\,bs')\,c$\\
Chengsong
parents:
diff changeset
  2401
  $\textit{fuse}\;bs\,(\textit{ALTS}\,bs'\,as)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2402
     $\textit{ALTS}\,(bs\,@\,bs')\,as$\\
Chengsong
parents:
diff changeset
  2403
  $\textit{fuse}\;bs\,(\textit{SEQ}\,bs'\,a_1\,a_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2404
     $\textit{SEQ}\,(bs\,@\,bs')\,a_1\,a_2$\\
Chengsong
parents:
diff changeset
  2405
  $\textit{fuse}\;bs\,(\textit{STAR}\,bs'\,a)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2406
     $\textit{STAR}\,(bs\,@\,bs')\,a$
Chengsong
parents:
diff changeset
  2407
\end{tabular}    
Chengsong
parents:
diff changeset
  2408
\end{center}  
Chengsong
parents:
diff changeset
  2409
Chengsong
parents:
diff changeset
  2410
\noindent
Chengsong
parents:
diff changeset
  2411
After internalising the regular expression, we perform successive
Chengsong
parents:
diff changeset
  2412
derivative operations on the annotated regular expressions. This
Chengsong
parents:
diff changeset
  2413
derivative operation is the same as what we had previously for the
Chengsong
parents:
diff changeset
  2414
basic regular expressions, except that we beed to take care of
Chengsong
parents:
diff changeset
  2415
the bitcodes:
Chengsong
parents:
diff changeset
  2416
Chengsong
parents:
diff changeset
  2417
 %\begin{definition}{bder}
Chengsong
parents:
diff changeset
  2418
\begin{center}
Chengsong
parents:
diff changeset
  2419
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents:
diff changeset
  2420
  $(\textit{ZERO})\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
Chengsong
parents:
diff changeset
  2421
  $(\textit{ONE}\;bs)\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
Chengsong
parents:
diff changeset
  2422
  $(\textit{CHAR}\;bs\,d)\,\backslash c$ & $\dn$ &
Chengsong
parents:
diff changeset
  2423
        $\textit{if}\;c=d\; \;\textit{then}\;
Chengsong
parents:
diff changeset
  2424
         \textit{ONE}\;bs\;\textit{else}\;\textit{ZERO}$\\  
Chengsong
parents:
diff changeset
  2425
  $(\textit{ALTS}\;bs\,as)\,\backslash c$ & $\dn$ &
Chengsong
parents:
diff changeset
  2426
  $\textit{ALTS}\;bs\,(as.map(\backslash c))$\\
Chengsong
parents:
diff changeset
  2427
  $(\textit{SEQ}\;bs\,a_1\,a_2)\,\backslash c$ & $\dn$ &
Chengsong
parents:
diff changeset
  2428
     $\textit{if}\;\textit{bnullable}\,a_1$\\
Chengsong
parents:
diff changeset
  2429
					       & &$\textit{then}\;\textit{ALTS}\,bs\,List((\textit{SEQ}\,[]\,(a_1\,\backslash c)\,a_2),$\\
Chengsong
parents:
diff changeset
  2430
					       & &$\phantom{\textit{then}\;\textit{ALTS}\,bs\,}(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\,\backslash c)))$\\
Chengsong
parents:
diff changeset
  2431
  & &$\textit{else}\;\textit{SEQ}\,bs\,(a_1\,\backslash c)\,a_2$\\
Chengsong
parents:
diff changeset
  2432
  $(\textit{STAR}\,bs\,a)\,\backslash c$ & $\dn$ &
Chengsong
parents:
diff changeset
  2433
      $\textit{SEQ}\;bs\,(\textit{fuse}\, [\Z] (r\,\backslash c))\,
Chengsong
parents:
diff changeset
  2434
       (\textit{STAR}\,[]\,r)$
Chengsong
parents:
diff changeset
  2435
\end{tabular}    
Chengsong
parents:
diff changeset
  2436
\end{center}    
Chengsong
parents:
diff changeset
  2437
%\end{definition}
Chengsong
parents:
diff changeset
  2438
Chengsong
parents:
diff changeset
  2439
\noindent
Chengsong
parents:
diff changeset
  2440
For instance, when we unfold $\textit{STAR} \; bs \; a$ into a sequence,
Chengsong
parents:
diff changeset
  2441
we need to attach an additional bit $Z$ to the front of $r \backslash c$
Chengsong
parents:
diff changeset
  2442
to indicate that there is one more star iteration. Also the $SEQ$ clause
Chengsong
parents:
diff changeset
  2443
is more subtle---when $a_1$ is $\textit{bnullable}$ (here
Chengsong
parents:
diff changeset
  2444
\textit{bnullable} is exactly the same as $\textit{nullable}$, except
Chengsong
parents:
diff changeset
  2445
that it is for annotated regular expressions, therefore we omit the
Chengsong
parents:
diff changeset
  2446
definition). Assume that $bmkeps$ correctly extracts the bitcode for how
Chengsong
parents:
diff changeset
  2447
$a_1$ matches the string prior to character $c$ (more on this later),
Chengsong
parents:
diff changeset
  2448
then the right branch of $ALTS$, which is $fuse \; bmkeps \;  a_1 (a_2
Chengsong
parents:
diff changeset
  2449
\backslash c)$ will collapse the regular expression $a_1$(as it has
Chengsong
parents:
diff changeset
  2450
already been fully matched) and store the parsing information at the
Chengsong
parents:
diff changeset
  2451
head of the regular expression $a_2 \backslash c$ by fusing to it. The
Chengsong
parents:
diff changeset
  2452
bitsequence $bs$, which was initially attached to the head of $SEQ$, has
Chengsong
parents:
diff changeset
  2453
now been elevated to the top-level of $ALTS$, as this information will be
Chengsong
parents:
diff changeset
  2454
needed whichever way the $SEQ$ is matched---no matter whether $c$ belongs
Chengsong
parents:
diff changeset
  2455
to $a_1$ or $ a_2$. After building these derivatives and maintaining all
Chengsong
parents:
diff changeset
  2456
the lexing information, we complete the lexing by collecting the
Chengsong
parents:
diff changeset
  2457
bitcodes using a generalised version of the $\textit{mkeps}$ function
Chengsong
parents:
diff changeset
  2458
for annotated regular expressions, called $\textit{bmkeps}$:
Chengsong
parents:
diff changeset
  2459
Chengsong
parents:
diff changeset
  2460
Chengsong
parents:
diff changeset
  2461
%\begin{definition}[\textit{bmkeps}]\mbox{}
Chengsong
parents:
diff changeset
  2462
\begin{center}
Chengsong
parents:
diff changeset
  2463
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2464
  $\textit{bmkeps}\,(\textit{ONE}\;bs)$ & $\dn$ & $bs$\\
Chengsong
parents:
diff changeset
  2465
  $\textit{bmkeps}\,(\textit{ALTS}\;bs\,a::as)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2466
     $\textit{if}\;\textit{bnullable}\,a$\\
Chengsong
parents:
diff changeset
  2467
  & &$\textit{then}\;bs\,@\,\textit{bmkeps}\,a$\\
Chengsong
parents:
diff changeset
  2468
  & &$\textit{else}\;bs\,@\,\textit{bmkeps}\,(\textit{ALTS}\;bs\,as)$\\
Chengsong
parents:
diff changeset
  2469
  $\textit{bmkeps}\,(\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2470
     $bs \,@\,\textit{bmkeps}\,a_1\,@\, \textit{bmkeps}\,a_2$\\
Chengsong
parents:
diff changeset
  2471
  $\textit{bmkeps}\,(\textit{STAR}\;bs\,a)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2472
     $bs \,@\, [\S]$
Chengsong
parents:
diff changeset
  2473
\end{tabular}    
Chengsong
parents:
diff changeset
  2474
\end{center}    
Chengsong
parents:
diff changeset
  2475
%\end{definition}
Chengsong
parents:
diff changeset
  2476
Chengsong
parents:
diff changeset
  2477
\noindent
Chengsong
parents:
diff changeset
  2478
This function completes the value information by travelling along the
Chengsong
parents:
diff changeset
  2479
path of the regular expression that corresponds to a POSIX value and
Chengsong
parents:
diff changeset
  2480
collecting all the bitcodes, and using $S$ to indicate the end of star
Chengsong
parents:
diff changeset
  2481
iterations. If we take the bitcodes produced by $\textit{bmkeps}$ and
Chengsong
parents:
diff changeset
  2482
decode them, we get the value we expect. The corresponding lexing
Chengsong
parents:
diff changeset
  2483
algorithm looks as follows:
Chengsong
parents:
diff changeset
  2484
Chengsong
parents:
diff changeset
  2485
\begin{center}
Chengsong
parents:
diff changeset
  2486
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2487
  $\textit{blexer}\;r\,s$ & $\dn$ &
Chengsong
parents:
diff changeset
  2488
      $\textit{let}\;a = (r^\uparrow)\backslash s\;\textit{in}$\\                
Chengsong
parents:
diff changeset
  2489
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
Chengsong
parents:
diff changeset
  2490
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
Chengsong
parents:
diff changeset
  2491
  & & $\;\;\textit{else}\;\textit{None}$
Chengsong
parents:
diff changeset
  2492
\end{tabular}
Chengsong
parents:
diff changeset
  2493
\end{center}
Chengsong
parents:
diff changeset
  2494
Chengsong
parents:
diff changeset
  2495
\noindent
Chengsong
parents:
diff changeset
  2496
In this definition $\_\backslash s$ is the  generalisation  of the derivative
Chengsong
parents:
diff changeset
  2497
operation from characters to strings (just like the derivatives for un-annotated
Chengsong
parents:
diff changeset
  2498
regular expressions).
Chengsong
parents:
diff changeset
  2499
Chengsong
parents:
diff changeset
  2500
The main point of the bitcodes and annotated regular expressions is that
Chengsong
parents:
diff changeset
  2501
we can apply rather aggressive (in terms of size) simplification rules
Chengsong
parents:
diff changeset
  2502
in order to keep derivatives small. We have developed such
Chengsong
parents:
diff changeset
  2503
``aggressive'' simplification rules and generated test data that show
Chengsong
parents:
diff changeset
  2504
that the expected bound can be achieved. Obviously we could only
Chengsong
parents:
diff changeset
  2505
partially cover  the search space as there are infinitely many regular
Chengsong
parents:
diff changeset
  2506
expressions and strings. 
Chengsong
parents:
diff changeset
  2507
Chengsong
parents:
diff changeset
  2508
One modification we introduced is to allow a list of annotated regular
Chengsong
parents:
diff changeset
  2509
expressions in the \textit{ALTS} constructor. This allows us to not just
Chengsong
parents:
diff changeset
  2510
delete unnecessary $\ZERO$s and $\ONE$s from regular expressions, but
Chengsong
parents:
diff changeset
  2511
also unnecessary ``copies'' of regular expressions (very similar to
Chengsong
parents:
diff changeset
  2512
simplifying $r + r$ to just $r$, but in a more general setting). Another
Chengsong
parents:
diff changeset
  2513
modification is that we use simplification rules inspired by Antimirov's
Chengsong
parents:
diff changeset
  2514
work on partial derivatives. They maintain the idea that only the first
Chengsong
parents:
diff changeset
  2515
``copy'' of a regular expression in an alternative contributes to the
Chengsong
parents:
diff changeset
  2516
calculation of a POSIX value. All subsequent copies can be pruned away from
Chengsong
parents:
diff changeset
  2517
the regular expression. A recursive definition of our  simplification function 
Chengsong
parents:
diff changeset
  2518
that looks somewhat similar to our Scala code is given below:
Chengsong
parents:
diff changeset
  2519
%\comment{Use $\ZERO$, $\ONE$ and so on. 
Chengsong
parents:
diff changeset
  2520
%Is it $ALTS$ or $ALTS$?}\\
Chengsong
parents:
diff changeset
  2521
Chengsong
parents:
diff changeset
  2522
\begin{center}
Chengsong
parents:
diff changeset
  2523
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents:
diff changeset
  2524
   
Chengsong
parents:
diff changeset
  2525
  $\textit{simp} \; (\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ & $ (\textit{simp} \; a_1, \textit{simp}  \; a_2) \; \textit{match} $ \\
Chengsong
parents:
diff changeset
  2526
   &&$\quad\textit{case} \; (\ZERO, \_) \Rightarrow  \ZERO$ \\
Chengsong
parents:
diff changeset
  2527
   &&$\quad\textit{case} \; (\_, \ZERO) \Rightarrow  \ZERO$ \\
Chengsong
parents:
diff changeset
  2528
   &&$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$ \\
Chengsong
parents:
diff changeset
  2529
   &&$\quad\textit{case} \; (a_1', \ONE) \Rightarrow  \textit{fuse} \; bs \;  a_1'$ \\
Chengsong
parents:
diff changeset
  2530
   &&$\quad\textit{case} \; (a_1', a_2') \Rightarrow  \textit{SEQ} \; bs \; a_1' \;  a_2'$ \\
Chengsong
parents:
diff changeset
  2531
Chengsong
parents:
diff changeset
  2532
  $\textit{simp} \; (\textit{ALTS}\;bs\,as)$ & $\dn$ & $\textit{distinct}( \textit{flatten} ( \textit{map simp as})) \; \textit{match} $ \\
Chengsong
parents:
diff changeset
  2533
  &&$\quad\textit{case} \; [] \Rightarrow  \ZERO$ \\
Chengsong
parents:
diff changeset
  2534
   &&$\quad\textit{case} \; a :: [] \Rightarrow  \textit{fuse bs a}$ \\
Chengsong
parents:
diff changeset
  2535
   &&$\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$\\ 
Chengsong
parents:
diff changeset
  2536
Chengsong
parents:
diff changeset
  2537
   $\textit{simp} \; a$ & $\dn$ & $\textit{a} \qquad \textit{otherwise}$   
Chengsong
parents:
diff changeset
  2538
\end{tabular}    
Chengsong
parents:
diff changeset
  2539
\end{center}    
Chengsong
parents:
diff changeset
  2540
Chengsong
parents:
diff changeset
  2541
\noindent
Chengsong
parents:
diff changeset
  2542
The simplification does a pattern matching on the regular expression.
Chengsong
parents:
diff changeset
  2543
When it detected that the regular expression is an alternative or
Chengsong
parents:
diff changeset
  2544
sequence, it will try to simplify its children regular expressions
Chengsong
parents:
diff changeset
  2545
recursively and then see if one of the children turn into $\ZERO$ or
Chengsong
parents:
diff changeset
  2546
$\ONE$, which might trigger further simplification at the current level.
Chengsong
parents:
diff changeset
  2547
The most involved part is the $\textit{ALTS}$ clause, where we use two
Chengsong
parents:
diff changeset
  2548
auxiliary functions $\textit{flatten}$ and $\textit{distinct}$ to open up nested
Chengsong
parents:
diff changeset
  2549
$\textit{ALTS}$ and reduce as many duplicates as possible. Function
Chengsong
parents:
diff changeset
  2550
$\textit{distinct}$  keeps the first occurring copy only and remove all later ones
Chengsong
parents:
diff changeset
  2551
when detected duplicates. Function $\textit{flatten}$ opens up nested \textit{ALTS}.
Chengsong
parents:
diff changeset
  2552
Its recursive definition is given below:
Chengsong
parents:
diff changeset
  2553
Chengsong
parents:
diff changeset
  2554
 \begin{center}
Chengsong
parents:
diff changeset
  2555
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents:
diff changeset
  2556
  $\textit{flatten} \; (\textit{ALTS}\;bs\,as) :: as'$ & $\dn$ & $(\textit{map} \;
Chengsong
parents:
diff changeset
  2557
     (\textit{fuse}\;bs)\; \textit{as}) \; @ \; \textit{flatten} \; as' $ \\
Chengsong
parents:
diff changeset
  2558
  $\textit{flatten} \; \textit{ZERO} :: as'$ & $\dn$ & $ \textit{flatten} \;  as' $ \\
Chengsong
parents:
diff changeset
  2559
    $\textit{flatten} \; a :: as'$ & $\dn$ & $a :: \textit{flatten} \; as'$ \quad(otherwise) 
Chengsong
parents:
diff changeset
  2560
\end{tabular}    
Chengsong
parents:
diff changeset
  2561
\end{center}  
Chengsong
parents:
diff changeset
  2562
Chengsong
parents:
diff changeset
  2563
\noindent
Chengsong
parents:
diff changeset
  2564
Here $\textit{flatten}$ behaves like the traditional functional programming flatten
Chengsong
parents:
diff changeset
  2565
function, except that it also removes $\ZERO$s. Or in terms of regular expressions, it
Chengsong
parents:
diff changeset
  2566
removes parentheses, for example changing $a+(b+c)$ into $a+b+c$.
Chengsong
parents:
diff changeset
  2567
Chengsong
parents:
diff changeset
  2568
Suppose we apply simplification after each derivative step, and view
Chengsong
parents:
diff changeset
  2569
these two operations as an atomic one: $a \backslash_{simp}\,c \dn
Chengsong
parents:
diff changeset
  2570
\textit{simp}(a \backslash c)$. Then we can use the previous natural
Chengsong
parents:
diff changeset
  2571
extension from derivative w.r.t.~character to derivative
Chengsong
parents:
diff changeset
  2572
w.r.t.~string:%\comment{simp in  the [] case?}
Chengsong
parents:
diff changeset
  2573
Chengsong
parents:
diff changeset
  2574
\begin{center}
Chengsong
parents:
diff changeset
  2575
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2576
$r \backslash_{simp} (c\!::\!s) $ & $\dn$ & $(r \backslash_{simp}\, c) \backslash_{simp}\, s$ \\
Chengsong
parents:
diff changeset
  2577
$r \backslash_{simp} [\,] $ & $\dn$ & $r$
Chengsong
parents:
diff changeset
  2578
\end{tabular}
Chengsong
parents:
diff changeset
  2579
\end{center}
Chengsong
parents:
diff changeset
  2580
Chengsong
parents:
diff changeset
  2581
\noindent
Chengsong
parents:
diff changeset
  2582
we obtain an optimised version of the algorithm:
Chengsong
parents:
diff changeset
  2583
Chengsong
parents:
diff changeset
  2584
 \begin{center}
Chengsong
parents:
diff changeset
  2585
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2586
  $\textit{blexer\_simp}\;r\,s$ & $\dn$ &
Chengsong
parents:
diff changeset
  2587
      $\textit{let}\;a = (r^\uparrow)\backslash_{simp}\, s\;\textit{in}$\\                
Chengsong
parents:
diff changeset
  2588
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
Chengsong
parents:
diff changeset
  2589
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
Chengsong
parents:
diff changeset
  2590
  & & $\;\;\textit{else}\;\textit{None}$
Chengsong
parents:
diff changeset
  2591
\end{tabular}
Chengsong
parents:
diff changeset
  2592
\end{center}
Chengsong
parents:
diff changeset
  2593
Chengsong
parents:
diff changeset
  2594
\noindent
Chengsong
parents:
diff changeset
  2595
This algorithm keeps the regular expression size small, for example,
Chengsong
parents:
diff changeset
  2596
with this simplification our previous $(a + aa)^*$ example's 8000 nodes
Chengsong
parents:
diff changeset
  2597
will be reduced to just 6 and stays constant, no matter how long the
Chengsong
parents:
diff changeset
  2598
input string is.
Chengsong
parents:
diff changeset
  2599
Chengsong
parents:
diff changeset
  2600
Chengsong
parents:
diff changeset
  2601
Chengsong
parents:
diff changeset
  2602
\section{Current Work}
Chengsong
parents:
diff changeset
  2603
Chengsong
parents:
diff changeset
  2604
We are currently engaged in two tasks related to this algorithm. The
Chengsong
parents:
diff changeset
  2605
first task is proving that our simplification rules actually do not
Chengsong
parents:
diff changeset
  2606
affect the POSIX value that should be generated by the algorithm
Chengsong
parents:
diff changeset
  2607
according to the specification of a POSIX value and furthermore obtain a
Chengsong
parents:
diff changeset
  2608
much tighter bound on the sizes of derivatives. The result is that our
Chengsong
parents:
diff changeset
  2609
algorithm should be correct and faster on all inputs.  The original
Chengsong
parents:
diff changeset
  2610
blow-up, as observed in JavaScript, Python and Java, would be excluded
Chengsong
parents:
diff changeset
  2611
from happening in our algorithm. For this proof we use the theorem prover
Chengsong
parents:
diff changeset
  2612
Isabelle. Once completed, this result will advance the state-of-the-art:
Chengsong
parents:
diff changeset
  2613
Sulzmann and Lu wrote in their paper~\cite{Sulzmann2014} about the
Chengsong
parents:
diff changeset
  2614
bitcoded ``incremental parsing method'' (that is the lexing algorithm
Chengsong
parents:
diff changeset
  2615
outlined in this section):
Chengsong
parents:
diff changeset
  2616
Chengsong
parents:
diff changeset
  2617
\begin{quote}\it
Chengsong
parents:
diff changeset
  2618
  ``Correctness Claim: We further claim that the incremental parsing
Chengsong
parents:
diff changeset
  2619
  method in Figure~5 in combination with the simplification steps in
Chengsong
parents:
diff changeset
  2620
  Figure 6 yields POSIX parse tree [our lexical values]. We have tested this claim
Chengsong
parents:
diff changeset
  2621
  extensively by using the method in Figure~3 as a reference but yet
Chengsong
parents:
diff changeset
  2622
  have to work out all proof details.''
Chengsong
parents:
diff changeset
  2623
\end{quote}  
Chengsong
parents:
diff changeset
  2624
Chengsong
parents:
diff changeset
  2625
\noindent 
Chengsong
parents:
diff changeset
  2626
We like to settle this correctness claim. It is relatively
Chengsong
parents:
diff changeset
  2627
straightforward to establish that after one simplification step, the part of a
Chengsong
parents:
diff changeset
  2628
nullable derivative that corresponds to a POSIX value remains intact and can
Chengsong
parents:
diff changeset
  2629
still be collected, in other words, we can show that
Chengsong
parents:
diff changeset
  2630
%\comment{Double-check....I
Chengsong
parents:
diff changeset
  2631
%think this  is not the case}
Chengsong
parents:
diff changeset
  2632
%\comment{If i remember correctly, you have proved this lemma.
Chengsong
parents:
diff changeset
  2633
%I feel this is indeed not true because you might place arbitrary 
Chengsong
parents:
diff changeset
  2634
%bits on the regex r, however if this is the case, did i remember wrongly that
Chengsong
parents:
diff changeset
  2635
%you proved something like simplification does not affect $\textit{bmkeps}$ results?
Chengsong
parents:
diff changeset
  2636
%Anyway, i have amended this a little bit so it does not allow arbitrary bits attached
Chengsong
parents:
diff changeset
  2637
%to a regex. Maybe it works now.}
Chengsong
parents:
diff changeset
  2638
Chengsong
parents:
diff changeset
  2639
\begin{center}
Chengsong
parents:
diff changeset
  2640
	$\textit{bmkeps} \; a = \textit{bmkeps} \; \textit{bsimp} \; a\;($\textit{provided}$ \; a\; is \; \textit{bnullable} )$
Chengsong
parents:
diff changeset
  2641
\end{center} 
Chengsong
parents:
diff changeset
  2642
Chengsong
parents:
diff changeset
  2643
\noindent
Chengsong
parents:
diff changeset
  2644
as this basically comes down to proving actions like removing the
Chengsong
parents:
diff changeset
  2645
additional $r$ in $r+r$  does not delete important POSIX information in
Chengsong
parents:
diff changeset
  2646
a regular expression. The hard part of this proof is to establish that
Chengsong
parents:
diff changeset
  2647
Chengsong
parents:
diff changeset
  2648
\begin{center}
Chengsong
parents:
diff changeset
  2649
	$ \textit{blexer}\_{simp}(r, \; s) =  \textit{blexer}(r, \; s)$
Chengsong
parents:
diff changeset
  2650
\end{center}
Chengsong
parents:
diff changeset
  2651
%comment{This is not true either...look at the definion blexer/blexer-simp}
Chengsong
parents:
diff changeset
  2652
Chengsong
parents:
diff changeset
  2653
\noindent That is, if we do derivative on regular expression $r$ and then
Chengsong
parents:
diff changeset
  2654
simplify it, and repeat this process until we exhaust the string, we get a
Chengsong
parents:
diff changeset
  2655
regular expression $r''$($\textit{LHS}$)  that provides the POSIX matching
Chengsong
parents:
diff changeset
  2656
information, which is exactly the same as the result $r'$($\textit{RHS}$ of the
Chengsong
parents:
diff changeset
  2657
normal derivative algorithm that only does derivative repeatedly and has no
Chengsong
parents:
diff changeset
  2658
simplification at all.  This might seem at first glance very unintuitive, as
Chengsong
parents:
diff changeset
  2659
the $r'$ could be exponentially larger than $r''$, but can be explained in the
Chengsong
parents:
diff changeset
  2660
following way: we are pruning away the possible matches that are not POSIX.
Chengsong
parents:
diff changeset
  2661
Since there could be exponentially many 
Chengsong
parents:
diff changeset
  2662
non-POSIX matchings and only 1 POSIX matching, it
Chengsong
parents:
diff changeset
  2663
is understandable that our $r''$ can be a lot smaller.  we can still provide
Chengsong
parents:
diff changeset
  2664
the same POSIX value if there is one.  This is not as straightforward as the
Chengsong
parents:
diff changeset
  2665
previous proposition, as the two regular expressions $r'$ and $r''$ might have
Chengsong
parents:
diff changeset
  2666
become very different.  The crucial point is to find the
Chengsong
parents:
diff changeset
  2667
$\textit{POSIX}$  information of a regular expression and how it is modified,
Chengsong
parents:
diff changeset
  2668
augmented and propagated 
Chengsong
parents:
diff changeset
  2669
during simplification in parallel with the regular expression that
Chengsong
parents:
diff changeset
  2670
has not been simplified in the subsequent derivative operations.  To aid this,
Chengsong
parents:
diff changeset
  2671
we use the helper function retrieve described by Sulzmann and Lu:
Chengsong
parents:
diff changeset
  2672
\begin{center}
Chengsong
parents:
diff changeset
  2673
\begin{tabular}{@{}l@{\hspace{2mm}}c@{\hspace{2mm}}l@{}}
Chengsong
parents:
diff changeset
  2674
  $\textit{retrieve}\,(\textit{ONE}\,bs)\,\Empty$ & $\dn$ & $bs$\\
Chengsong
parents:
diff changeset
  2675
  $\textit{retrieve}\,(\textit{CHAR}\,bs\,c)\,(\Char\,d)$ & $\dn$ & $bs$\\
Chengsong
parents:
diff changeset
  2676
  $\textit{retrieve}\,(\textit{ALTS}\,bs\,a::as)\,(\Left\,v)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2677
     $bs \,@\, \textit{retrieve}\,a\,v$\\
Chengsong
parents:
diff changeset
  2678
  $\textit{retrieve}\,(\textit{ALTS}\,bs\,a::as)\,(\Right\,v)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2679
  $bs \,@\, \textit{retrieve}\,(\textit{ALTS}\,bs\,as)\,v$\\
Chengsong
parents:
diff changeset
  2680
  $\textit{retrieve}\,(\textit{SEQ}\,bs\,a_1\,a_2)\,(\Seq\,v_1\,v_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2681
     $bs \,@\,\textit{retrieve}\,a_1\,v_1\,@\, \textit{retrieve}\,a_2\,v_2$\\
Chengsong
parents:
diff changeset
  2682
  $\textit{retrieve}\,(\textit{STAR}\,bs\,a)\,(\Stars\,[])$ & $\dn$ &
Chengsong
parents:
diff changeset
  2683
     $bs \,@\, [\S]$\\
Chengsong
parents:
diff changeset
  2684
  $\textit{retrieve}\,(\textit{STAR}\,bs\,a)\,(\Stars\,(v\!::\!vs))$ & $\dn$ &\\
Chengsong
parents:
diff changeset
  2685
  \multicolumn{3}{l}{
Chengsong
parents:
diff changeset
  2686
     \hspace{3cm}$bs \,@\, [\Z] \,@\, \textit{retrieve}\,a\,v\,@\,
Chengsong
parents:
diff changeset
  2687
                    \textit{retrieve}\,(\textit{STAR}\,[]\,a)\,(\Stars\,vs)$}\\
Chengsong
parents:
diff changeset
  2688
\end{tabular}
Chengsong
parents:
diff changeset
  2689
\end{center}
Chengsong
parents:
diff changeset
  2690
%\comment{Did not read further}\\
Chengsong
parents:
diff changeset
  2691
This function assembles the bitcode 
Chengsong
parents:
diff changeset
  2692
%that corresponds to a lexical value for how
Chengsong
parents:
diff changeset
  2693
%the current derivative matches the suffix of the string(the characters that
Chengsong
parents:
diff changeset
  2694
%have not yet appeared, but will appear as the successive derivatives go on.
Chengsong
parents:
diff changeset
  2695
%How do we get this "future" information? By the value $v$, which is
Chengsong
parents:
diff changeset
  2696
%computed by a pass of the algorithm that uses
Chengsong
parents:
diff changeset
  2697
%$inj$ as described in the previous section).  
Chengsong
parents:
diff changeset
  2698
using information from both the derivative regular expression and the
Chengsong
parents:
diff changeset
  2699
value. Sulzmann and Lu poroposed this function, but did not prove
Chengsong
parents:
diff changeset
  2700
anything about it. Ausaf and Urban used it to connect the bitcoded
Chengsong
parents:
diff changeset
  2701
algorithm to the older algorithm by the following equation:
Chengsong
parents:
diff changeset
  2702
 
Chengsong
parents:
diff changeset
  2703
 \begin{center} $inj \;a\; c \; v = \textit{decode} \; (\textit{retrieve}\;
Chengsong
parents:
diff changeset
  2704
	 (r^\uparrow)\backslash_{simp} \,c)\,v)$ 
Chengsong
parents:
diff changeset
  2705
 \end{center} 
Chengsong
parents:
diff changeset
  2706
Chengsong
parents:
diff changeset
  2707
\noindent
Chengsong
parents:
diff changeset
  2708
whereby $r^\uparrow$ stands for the internalised version of $r$. Ausaf
Chengsong
parents:
diff changeset
  2709
and Urban also used this fact to prove  the correctness of bitcoded
Chengsong
parents:
diff changeset
  2710
algorithm without simplification.  Our purpose of using this, however,
Chengsong
parents:
diff changeset
  2711
is to establish 
Chengsong
parents:
diff changeset
  2712
Chengsong
parents:
diff changeset
  2713
\begin{center}
Chengsong
parents:
diff changeset
  2714
$ \textit{retrieve} \;
Chengsong
parents:
diff changeset
  2715
a \; v \;=\; \textit{retrieve}  \; (\textit{simp}\,a) \; v'.$
Chengsong
parents:
diff changeset
  2716
\end{center}
Chengsong
parents:
diff changeset
  2717
The idea is that using $v'$, a simplified version of $v$ that had gone
Chengsong
parents:
diff changeset
  2718
through the same simplification step as $\textit{simp}(a)$, we are able
Chengsong
parents:
diff changeset
  2719
to extract the bitcode that gives the same parsing information as the
Chengsong
parents:
diff changeset
  2720
unsimplified one. However, we noticed that constructing such a  $v'$
Chengsong
parents:
diff changeset
  2721
from $v$ is not so straightforward. The point of this is that  we might
Chengsong
parents:
diff changeset
  2722
be able to finally bridge the gap by proving
Chengsong
parents:
diff changeset
  2723
Chengsong
parents:
diff changeset
  2724
\begin{center}
Chengsong
parents:
diff changeset
  2725
$\textit{retrieve} \; (r^\uparrow   \backslash  s) \; v = \;\textit{retrieve} \;
Chengsong
parents:
diff changeset
  2726
(\textit{simp}(r^\uparrow)  \backslash  s) \; v'$
Chengsong
parents:
diff changeset
  2727
\end{center}
Chengsong
parents:
diff changeset
  2728
Chengsong
parents:
diff changeset
  2729
\noindent
Chengsong
parents:
diff changeset
  2730
and subsequently
Chengsong
parents:
diff changeset
  2731
Chengsong
parents:
diff changeset
  2732
\begin{center}
Chengsong
parents:
diff changeset
  2733
$\textit{retrieve} \; (r^\uparrow \backslash  s) \; v\; = \; \textit{retrieve} \;
Chengsong
parents:
diff changeset
  2734
(r^\uparrow  \backslash_{simp}  \, s) \; v'$.
Chengsong
parents:
diff changeset
  2735
\end{center}
Chengsong
parents:
diff changeset
  2736
Chengsong
parents:
diff changeset
  2737
\noindent
Chengsong
parents:
diff changeset
  2738
The $\textit{LHS}$ of the above equation is the bitcode we want. This
Chengsong
parents:
diff changeset
  2739
would prove that our simplified version of regular expression still
Chengsong
parents:
diff changeset
  2740
contains all the bitcodes needed. The task here is to find a way to
Chengsong
parents:
diff changeset
  2741
compute the correct $v'$.
Chengsong
parents:
diff changeset
  2742
Chengsong
parents:
diff changeset
  2743
The second task is to speed up the more aggressive simplification.  Currently
Chengsong
parents:
diff changeset
  2744
it is slower than the original naive simplification by Ausaf and Urban (the
Chengsong
parents:
diff changeset
  2745
naive version as implemented by Ausaf   and Urban of course can ``explode'' in
Chengsong
parents:
diff changeset
  2746
some cases).  It is therefore not surprising that the speed is also much slower
Chengsong
parents:
diff changeset
  2747
than regular expression engines in popular programming languages such as Java
Chengsong
parents:
diff changeset
  2748
and Python on most inputs that are linear. For example, just by rewriting the
Chengsong
parents:
diff changeset
  2749
example regular expression in the beginning of this report  $(a^*)^*\,b$ into
Chengsong
parents:
diff changeset
  2750
$a^*\,b$ would eliminate the ambiguity in the matching and make the time
Chengsong
parents:
diff changeset
  2751
for matching linear with respect to the input string size. This allows the 
Chengsong
parents:
diff changeset
  2752
DFA approach to become blindingly fast, and dwarf the speed of our current
Chengsong
parents:
diff changeset
  2753
implementation. For example, here is a comparison of Java regex engine 
Chengsong
parents:
diff changeset
  2754
and our implementation on this example.
Chengsong
parents:
diff changeset
  2755
Chengsong
parents:
diff changeset
  2756
\begin{center}
Chengsong
parents:
diff changeset
  2757
\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}}
Chengsong
parents:
diff changeset
  2758
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  2759
\begin{axis}[
Chengsong
parents:
diff changeset
  2760
    xlabel={$n*1000$},
Chengsong
parents:
diff changeset
  2761
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  2762
    ylabel={time in secs},
Chengsong
parents:
diff changeset
  2763
    enlargelimits=false,
Chengsong
parents:
diff changeset
  2764
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  2765
    xmax=33,
Chengsong
parents:
diff changeset
  2766
    ymax=9,
Chengsong
parents:
diff changeset
  2767
    scaled ticks=true,
Chengsong
parents:
diff changeset
  2768
    axis lines=left,
Chengsong
parents:
diff changeset
  2769
    width=5cm,
Chengsong
parents:
diff changeset
  2770
    height=4cm, 
Chengsong
parents:
diff changeset
  2771
    legend entries={Bitcoded Algorithm},  
Chengsong
parents:
diff changeset
  2772
    legend pos=north west,
Chengsong
parents:
diff changeset
  2773
    legend cell align=left]
Chengsong
parents:
diff changeset
  2774
\addplot[red,mark=*, mark options={fill=white}] table {bad-scala.data};
Chengsong
parents:
diff changeset
  2775
\end{axis}
Chengsong
parents:
diff changeset
  2776
\end{tikzpicture}
Chengsong
parents:
diff changeset
  2777
  &
Chengsong
parents:
diff changeset
  2778
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  2779
\begin{axis}[
Chengsong
parents:
diff changeset
  2780
    xlabel={$n*1000$},
Chengsong
parents:
diff changeset
  2781
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  2782
    %ylabel={time in secs},
Chengsong
parents:
diff changeset
  2783
    enlargelimits=false,
Chengsong
parents:
diff changeset
  2784
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  2785
    xmax=33,
Chengsong
parents:
diff changeset
  2786
    ymax=9,
Chengsong
parents:
diff changeset
  2787
    scaled ticks=false,
Chengsong
parents:
diff changeset
  2788
    axis lines=left,
Chengsong
parents:
diff changeset
  2789
    width=5cm,
Chengsong
parents:
diff changeset
  2790
    height=4cm, 
Chengsong
parents:
diff changeset
  2791
    legend entries={Java},  
Chengsong
parents:
diff changeset
  2792
    legend pos=north west,
Chengsong
parents:
diff changeset
  2793
    legend cell align=left]
Chengsong
parents:
diff changeset
  2794
\addplot[cyan,mark=*, mark options={fill=white}] table {good-java.data};
Chengsong
parents:
diff changeset
  2795
\end{axis}
Chengsong
parents:
diff changeset
  2796
\end{tikzpicture}\\
Chengsong
parents:
diff changeset
  2797
\multicolumn{3}{c}{Graphs: Runtime for matching $a^*\,b$ with strings 
Chengsong
parents:
diff changeset
  2798
           of the form $\underbrace{aa..a}_{n}$.}
Chengsong
parents:
diff changeset
  2799
\end{tabular}    
Chengsong
parents:
diff changeset
  2800
\end{center}  
Chengsong
parents:
diff changeset
  2801
Chengsong
parents:
diff changeset
  2802
Chengsong
parents:
diff changeset
  2803
Java regex engine can match string of thousands of characters in a few milliseconds,
Chengsong
parents:
diff changeset
  2804
whereas our current algorithm gets excruciatingly slow on input of this size.
Chengsong
parents:
diff changeset
  2805
The running time in theory is linear, however it does not appear to be the 
Chengsong
parents:
diff changeset
  2806
case in an actual implementation. So it needs to be explored how to
Chengsong
parents:
diff changeset
  2807
make our algorithm faster on all inputs.  It could be the recursive calls that are
Chengsong
parents:
diff changeset
  2808
needed to manipulate bits that are causing the slow down. A possible solution
Chengsong
parents:
diff changeset
  2809
is to write recursive functions into tail-recusive form.
Chengsong
parents:
diff changeset
  2810
Another possibility would be to explore
Chengsong
parents:
diff changeset
  2811
again the connection to DFAs to speed up the algorithm on 
Chengsong
parents:
diff changeset
  2812
subcalls that are small enough. This is very much work in progress.
Chengsong
parents:
diff changeset
  2813
Chengsong
parents:
diff changeset
  2814
\section{Conclusion}
Chengsong
parents:
diff changeset
  2815
Chengsong
parents:
diff changeset
  2816
In this PhD-project we are interested in fast algorithms for regular
Chengsong
parents:
diff changeset
  2817
expression matching. While this seems to be a ``settled'' area, in
Chengsong
parents:
diff changeset
  2818
fact interesting research questions are popping up as soon as one steps
Chengsong
parents:
diff changeset
  2819
outside the classic automata theory (for example in terms of what kind
Chengsong
parents:
diff changeset
  2820
of regular expressions are supported). The reason why it is
Chengsong
parents:
diff changeset
  2821
interesting for us to look at the derivative approach introduced by
Chengsong
parents:
diff changeset
  2822
Brzozowski for regular expression matching, and then much further
Chengsong
parents:
diff changeset
  2823
developed by Sulzmann and Lu, is that derivatives can elegantly deal
Chengsong
parents:
diff changeset
  2824
with some of the regular expressions that are of interest in ``real
Chengsong
parents:
diff changeset
  2825
life''. This includes the not-regular expression, written $\neg\,r$
Chengsong
parents:
diff changeset
  2826
(that is all strings that are not recognised by $r$), but also bounded
Chengsong
parents:
diff changeset
  2827
regular expressions such as $r^{\{n\}}$ and $r^{\{n..m\}}$). There is
Chengsong
parents:
diff changeset
  2828
also hope that the derivatives can provide another angle for how to
Chengsong
parents:
diff changeset
  2829
deal more efficiently with back-references, which are one of the
Chengsong
parents:
diff changeset
  2830
reasons why regular expression engines in JavaScript, Python and Java
Chengsong
parents:
diff changeset
  2831
choose to not implement the classic automata approach of transforming
Chengsong
parents:
diff changeset
  2832
regular expressions into NFAs and then DFAs---because we simply do not
Chengsong
parents:
diff changeset
  2833
know how such back-references can be represented by DFAs.
Chengsong
parents:
diff changeset
  2834
We also plan to implement the bitcoded algorithm
Chengsong
parents:
diff changeset
  2835
in some imperative language like C to see if the inefficiency of the 
Chengsong
parents:
diff changeset
  2836
Scala implementation
Chengsong
parents:
diff changeset
  2837
is language specific. To make this research more comprehensive we also plan
Chengsong
parents:
diff changeset
  2838
to contrast our (faster) version of bitcoded algorithm with the
Chengsong
parents:
diff changeset
  2839
Symbolic Regex Matcher, the RE2, the Rust Regex Engine, and the static
Chengsong
parents:
diff changeset
  2840
analysis approach by implementing them in the same language and then compare
Chengsong
parents:
diff changeset
  2841
their performance.
Chengsong
parents:
diff changeset
  2842
Chengsong
parents:
diff changeset
  2843
\bibliographystyle{plain}
Chengsong
parents:
diff changeset
  2844
\bibliography{root}
Chengsong
parents:
diff changeset
  2845
Chengsong
parents:
diff changeset
  2846
Chengsong
parents:
diff changeset
  2847
\end{document}