author | Christian Urban <christian dot urban at kcl dot ac dot uk> |
Sat, 17 Oct 2015 11:24:41 +0100 | |
changeset 355 | a259eec25156 |
parent 347 | 22b5294daa2a |
child 359 | db106e5b7c4d |
permissions | -rw-r--r-- |
31 | 1 |
\documentclass{article} |
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\usepackage{../style} |
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\usepackage{../graphics} |
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\begin{document} |
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\section*{Homework 4} |
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\HEADER |
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\begin{enumerate} |
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\item If a regular expression $r$ does not contain any occurrence of $\varnothing$, |
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is it possible for $L(r)$ to be empty? |
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\item Define the tokens and regular expressions for a language |
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consisting of numbers, left-parenthesis $($, right-parenthesis $)$, |
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identifiers and the operations $+$, $-$ and $*$. Can the following |
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strings in this language be lexed? |
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\begin{itemize} |
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\item $(a + 3) * b$ |
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\item $)()++ -33$ |
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\item $(a / 3) * 3$ |
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\end{itemize} |
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In case they can, can you give the corresponding token |
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sequences. |
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\item Assume that $s^{-1}$ stands for the operation of reversing a |
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string $s$. Given the following \emph{reversing} function on regular |
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expressions |
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\begin{center} |
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\begin{tabular}{r@{\hspace{1mm}}c@{\hspace{1mm}}l} |
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$rev(\varnothing)$ & $\dn$ & $\varnothing$\\ |
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$rev(\epsilon)$ & $\dn$ & $\epsilon$\\ |
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$rev(c)$ & $\dn$ & $c$\\ |
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$rev(r_1 + r_2)$ & $\dn$ & $rev(r_1) + rev(r_2)$\\ |
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$rev(r_1 \cdot r_2)$ & $\dn$ & $rev(r_2) \cdot rev(r_1)$\\ |
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$rev(r^*)$ & $\dn$ & $rev(r)^*$\\ |
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\end{tabular} |
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\end{center} |
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and the set |
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\begin{center} |
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$Rev\,A \dn \{s^{-1} \;|\; s \in A\}$ |
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\end{center} |
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prove whether |
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\begin{center} |
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$L(rev(r)) = Rev (L(r))$ |
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\end{center} |
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holds. |
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\item Assume the delimiters for comments are \texttt{$\slash$*} and |
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\texttt{*$\slash$}. Give a regular expression that can recognise |
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comments of the form |
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\begin{center} |
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\texttt{$\slash$*~\ldots{}~*$\slash$} |
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\end{center} |
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where the three dots stand for arbitrary characters, but not comment delimiters. |
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(Hint: You can assume you are already given a regular expression written \texttt{ALL}, |
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that can recognise any character, and a regular expression \texttt{NOT} that recognises |
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the complement of a regular expression.) |
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\item Simplify the regular expression |
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\[ |
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(\varnothing \cdot (b \cdot c)) + |
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((\varnothing \cdot c) + \epsilon) |
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\] |
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Does simplification always preserve the meaning of a regular |
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expression? |
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\item The Sulzmann algorithm contains the function $mkeps$ |
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which answers how a regular expression can match the |
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empty string. What is the answer of $mkeps$ for the |
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regular expressions: |
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\[ |
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\begin{array}{l} |
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(\varnothing \cdot (b \cdot c)) + |
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((\varnothing \cdot c) + \epsilon)\\ |
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(a + \varepsilon) \cdot (\varepsilon + \varepsilon) |
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\end{array} |
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\] |
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\item What is the purpose of the record regular expression |
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in the Sulzmann algorithm? |
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%\item (Optional) The tokenizer in \texttt{regexp3.scala} takes as |
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%argument a string and a list of rules. The result is a list of tokens. Improve this tokenizer so |
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%that it filters out all comments and whitespace from the result. |
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|
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%\item (Optional) Modify the tokenizer in \texttt{regexp2.scala} so that it |
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parents:
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%implements the \texttt{findAll} function. This function takes a regular |
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%expressions and a string, and returns all substrings in this string that |
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parents:
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%match the regular expression. |
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\end{enumerate} |
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\end{document} |
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%%% Local Variables: |
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%%% mode: latex |
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%%% TeX-master: t |
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%%% End: |