\documentclass{article}
\usepackage{../style}
\usepackage{../langs}
\usepackage{../graphics}
\usepackage{../grammar}
\usepackage{multicol}
\begin{document}
\section*{Handout 9 (Static Analysis)}
If we want to improve the safety and security of our programs,
we need a more principled approach to programming. Testing is
good, but as Dijkstra famously wrote:
\begin{quote}\it
``Program testing can be a very effective way to show the
\underline{\smash{presence}} of bugs, but it is hopelessly
inadequate for showing their \underline{\smash{absence}}.''
\end{quote}
\noindent While such a more principled approach has been the
subject of intense study for a long, long time, only in the
past few years some impressive results have been achieved. One
is the complete formalisation and (mathematical) verification
of a microkernel operating system called seL4.
\begin{center}
\url{http://sel4.systems}
\end{center}
\noindent In 2011 this work was included in the MIT Technology
Review in the annual list of the world’s ten most important
emerging
technologies.\footnote{\url{http://www2.technologyreview.com/tr10/?year=2011}}
While this work is impressive, its technical details are too
enormous for an explanation here. Therefore let us look at
something much simpler, namely finding out properties about
programs using \emph{static analysis}.
Static analysis is a technique that checks properties of a
program without actually running the program. This should
raise alarm bells with you---because almost all interesting
properties about programs are equivalent to the halting
problem, which we know is undecidable. For example estimating
the memory consumption of programs is in general undecidable,
just like the halting problem. Static analysis circumvents
this undecidability-problem by essentially allowing answers
\emph{yes} and \emph{no}, but also \emph{don't know}. With
this ``trick'' even the halting problem becomes
decidable\ldots{}for example we could always say \emph{don't
know}. Of course this would be silly. The point is that we
should be striving for a method that answers as often as
possible either \emph{yes} or \emph{no}---just in cases when
it is too difficult we fall back on the
\emph{don't-know}-answer. This might sound all like abstract
nonsense. Therefore let us look at a concrete example.
\subsubsection*{A Simple, Idealised Programming Language}
Our starting point is a small, idealised programming language.
It is idealised because we cut several corners in comparison
with real programming languages. The language we will study
contains, amongst other things, variables holding integers.
Using static analysis, we want to find out what the sign of
these integers (positive or negative) will be when the program
runs. This sign-analysis seems like a very simple problem. But
it will turn out even such simple problems, if approached
naively, are in general undecidable, just like Turing's
halting problem. I let you think why?
Is sign-analysis of variables an interesting problem? Well,
yes---if a compiler can find out that for example a variable
will never be negative and this variable is used as an index
for an array, then the compiler does not need to generate code
for an underflow-test. Remember some languages are immune to
buffer-overflow attacks, but they need to add underflow and
overflow checks everywhere. If the compiler can omit the
underflow test, for example, then this can potentially
drastically speed up the generated code.
What do programs in our programming language look like? The
following grammar gives a first specification:
\begin{multicols}{2}
\begin{plstx}[rhs style=,one per line,left margin=9mm]
: \meta{Stmt} ::= \meta{label} \texttt{:}
| \meta{var} \texttt{:=} \meta{Exp}
| \texttt{jmp?} \meta{Exp} \meta{label}
| \texttt{goto} \meta{label}\\
: \meta{Prog} ::= \meta{Stmt} \ldots{} \meta{Stmt}\\
\end{plstx}
\columnbreak
\begin{plstx}[rhs style=,one per line]
: \meta{Exp} ::= \meta{Exp} \texttt{+} \meta{Exp}
| \meta{Exp} \texttt{*} \meta{Exp}
| \meta{Exp} \texttt{=} \meta{Exp}
| \meta{num}
| \meta{var}\\
\end{plstx}
\end{multicols}
\noindent I assume you are familiar with such
grammars.\footnote{\url{http://en.wikipedia.org/wiki/Backus–Naur_Form}}
There are three main syntactic categories: \emph{statments}
and \emph{expressions} as well as \emph{programs}, which are
sequences of statements. Statements are either labels,
variable assignments, conditional jumps (\pcode{jmp?}) and
unconditional jumps (\pcode{goto}). Labels are just strings,
which can be used as the target of a jump. We assume that in
every program the labels are unique---otherwise if there is a
clash we do not know where to jump to. The conditional jumps
and variable assignments involve (arithmetic) expressions.
Expressions are either numbers, variables or compound
expressions built up from \pcode{+}, \pcode{*} and \emph{=}
(for simplicity reasons we do not consider any other
operations). We assume we have negative and positive numbers,
\ldots \pcode{-2}, \pcode{-1}, \pcode{0}, \pcode{1},
\pcode{2}\ldots{} An example program that calculates the
factorial of 5 is as follows:
\begin{lstlisting}[language={},xleftmargin=10mm]
a := 1
n := 5
top:
jmp? n = 0 done
a := a * n
n := n + -1
goto top
done:
\end{lstlisting}
\noindent Each line of the program contains a statement. In
the first two lines we assign values to the variables
\pcode{a} and \pcode{n}. In line 4 we test whether \pcode{n}
is zero, in which case we jump to the end of the program
marked with the label \pcode{done}. If \pcode{n} is not zero,
we multiply the content of \pcode{a} by \pcode{n}, decrease
\pcode{n} by one and jump back to the beginning of the loop,
marked with the label \pcode{top}. Another program in our
language is shown in Figure~\ref{fib}. I let you think what it
calculates.
\begin{figure}[t]
\begin{lstlisting}[numbers=none,
language={},xleftmargin=10mm]
n := 6
m1 := 0
m2 := 1
loop:
jmp? n = 0 done
tmp := m2
m2 := m1 + m2
m1 := tmp
n := n + -1
goto top
done:
\end{lstlisting}
\caption{A mystery program in our idealised programming language.
Try to find out what it calculates! \label{fib}}
\end{figure}
Even if our language is rather small, it is still Turing
complete---meaning quite powerful. However, discussing this
fact in more detail would lead us too far astray. Clearly, our
programming is rather low-level and not very comfortable for
writing programs. It is inspired by machine code, which is the
code that is actually executed by a CPU. So a more interesting
question is what is missing in comparison with real machine
code? Well, not much\ldots{}in principle. Real machine code,
of course, contains many more arithmetic instructions (not
just addition and multiplication) and many more conditional
jumps. We could add these to our language if we wanted, but
complexity is really beside the point here. Furthermore, real
machine code has many instructions for manipulating memory. We
do not have this at all. This is actually a more serious
simplification because we assume numbers to be arbitrary small
or large, which is not the case with real machine code. In
real code basic number formats have a range and might
over-flow or under-flow from this range. Also the number of
variables in our programs is potentially unlimited, while
memory in an actual computer, of course, is always limited
somehow on any actual. To sum up, our language might look very
simple, but it is not completely removed from practically
relevant issues.
\subsubsection*{An Interpreter}
Designing a language is like playing god: you can say what
names for variables you allow; what programs should look like;
most importantly you can decide what each part of the program
should mean and do. While our language is rather simple and
the meaning is rather straightforward, there are still places
where we need to make a real choice. For example with
conditional jumps, say the one in the factorial program:
\begin{center}
\code{jmp? n = 0 done}
\end{center}
\noindent How should they work? We could introduce Booleans
(\pcode{true} and \pcode{false}) and then jump only when the
condition is \pcode{true}. However, since we have numbers in
our language anyway, why not just encoding \emph{true} as
zero, and \pcode{false} as anything else? In this way we can
dispense with the additional concept of Booleans, but also we
could replace the jump above by
\begin{center}
\code{jmp? n done}
\end{center}
\noindent which behaves exactly the same. But what does it
mean that two jumps behave the same?
I hope the above discussion makes it already clear we need to
be a bit more careful with our programs. Below we shall
describe an interpreter for our programs, which specifies
exactly how programs are supposed to be run\ldots{}at least we
will specify this for all \emph{good} programs. By good
programs we mean where for example all variables are
initialised. Our interpreter will just crash if it cannot find
out the value for a variable, because it is not initialised.
First we will pre-process our programs. This will simplify
our definition of our interpreter later on. We will transform
programs into \emph{snippets}.
\end{document}
%%% Local Variables:
%%% mode: latex
%%% TeX-master: t
%%% End: