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534 appear in Bob's bit vector, then she sends the inverse of $y$ |
534 appear in Bob's bit vector, then she sends the inverse of $y$ |
535 as $h_j$ and 0 as $s_j$. However, notice that when she |
535 as $h_j$ and 0 as $s_j$. However, notice that when she |
536 calculates a solution for $y$ she does not know $r_j$. For this she |
536 calculates a solution for $y$ she does not know $r_j$. For this she |
537 would need to calculate the modular logarithm |
537 would need to calculate the modular logarithm |
538 |
538 |
539 |
539 \[y \equiv A^{r_j}\;mod\;p\] |
540 \[ |
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541 y \equiv A^{r_j}\;mod\;p |
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542 \] |
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543 |
540 |
544 \noindent which is hard (see step 1 in the commitment stage). |
541 \noindent which is hard (see step 1 in the commitment stage). |
545 |
542 |
546 Having settled on what $h_j$ should be, now what should Alice |
543 Having settled on what $h_j$ should be, now what should Alice |
547 send as the other $h_i$ and other $s_i$? If the $b_i$ happens |
544 send as the other $h_i$ and other $s_i$? If the $b_i$ happens |