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(**
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* the Nominal Unification algorithm by Urban, Pitts & Gabbay
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* June, 2003
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*)
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open List;;
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exception Fail;; (* exception for unification failure *)
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(* terms *)
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type term =
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Unit (* units *)
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| Atm of string (* atoms *)
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| Susp of (string * string) list * string (* suspensions *)
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| Fun of string * term (* function symbols *)
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| Abst of string * term (* abstracted terms *)
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| Pair of term * term;; (* pairs *)
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(* swapping operation on atoms *)
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let swap (a,b) c =
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if a=c then b else if b=c then a else c;;
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let swaps pi c = fold_right swap pi c;;
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(* permutation on terms *)
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let rec perm pi t =
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match t with
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Unit -> Unit
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| Atm(a) -> Atm(swaps pi a)
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| Susp(pi',x) -> Susp(pi@pi',x)
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| Fun(name,t') -> Fun(name, perm pi t')
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| Abst(a,t') -> Abst(swaps pi a,perm pi t')
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| Pair(t1,t2) -> Pair(perm pi t1,perm pi t2);;
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(* substitution operation
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* - implements the simple operation of "hole filling" or "context substitution"
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*)
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let rec subst t sigma =
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match t with
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Unit -> Unit
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| Atm(a) -> Atm(a)
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| Susp(pi,y) -> (try (perm pi (assoc y sigma)) with Not_found -> Susp(pi,y))
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| Fun(name,t') -> Fun(name,subst t' sigma)
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| Abst(a,t') -> Abst(a,subst t' sigma)
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| Pair(t1,t2) -> Pair(subst t1 sigma,subst t2 sigma);;
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(* substitution composition *)
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let rec subst_compose sigma =
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match sigma with
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[] -> []
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| h::tail -> h::(map (fun (v,t) -> (v,subst t [h])) (subst_compose tail));;
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(* occurs check *)
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let rec occurs x t =
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match t with
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Unit -> false
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| Atm(a) -> false
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| Susp(pi,y) -> if x=y then true else false
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| Fun(_,t') | Abst(_,t') -> occurs x t'
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| Pair(t1,t2) -> (occurs x t1) || (occurs x t2);;
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(* deletes duplicates from a list
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* - used for calculating disagreement sets
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*)
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let rec delete_dups l =
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match l with
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[] -> []
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| h::t -> let t' = delete_dups t in if mem h t' then t' else (h::t');;
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(* disagreement set
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* - takes two permutation (lists of pairs of atoms) as arguments
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*)
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let rec ds pi pi' =
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let (l1,l2) = split (pi@pi')
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in filter (fun a -> (swaps pi a)!=(swaps pi' a)) (delete_dups (l1@l2))
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(* eliminates a solved equation *)
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let eliminate (v,t) (eprobs,fprobs) =
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if occurs v t
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then raise Fail
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else (map (fun (t1,t2) -> (subst t1 [(v,t)],subst t2 [(v,t)])) eprobs,
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map (fun (a,t') -> (a,subst t' [(v,t)])) fprobs);;
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(***************)
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(* unification *)
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(***************)
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(* checks and solves all freshness problems *)
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let rec check fprobs =
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match fprobs with
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[] -> []
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| (a,Unit)::tail -> check tail
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| (a,Atm(b))::tail -> if a=b then raise Fail else check tail
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| (a,Susp(pi,x))::tail -> (swaps (rev pi) a,x)::(check tail)
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| (a,Fun(_,t))::tail -> check ((a,t)::tail)
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| (a,Abst(b,t))::tail -> if a=b then (check tail) else (check ((a,t)::tail))
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| (a,Pair(t1,t2))::tail -> check ((a,t1)::(a,t2)::tail);;
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(* solves all equational problems *)
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let rec solve eprobs fprobs = solve_aux eprobs fprobs []
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and solve_aux eprobs fprobs sigma =
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match eprobs with
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[] -> (subst_compose sigma, delete_dups (check fprobs))
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| (Unit,Unit)::tail -> solve_aux tail fprobs sigma
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| (Atm(a),Atm(b))::tail -> if a=b then (solve_aux tail fprobs sigma) else raise Fail
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| (Susp(pi,x),Susp(pi',x'))::tail when x=x' ->
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let new_fps = map (fun a -> (a,Susp([],x))) (ds pi pi')
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in solve_aux tail (new_fps @ fprobs) sigma
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| (Susp(pi,x),t)::tail | (t,Susp(pi,x))::tail ->
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let new_sigma = (x,perm (rev pi) t) in
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let (new_eprobs,new_fprobs) = eliminate new_sigma (tail,fprobs)
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in solve_aux new_eprobs new_fprobs (new_sigma::sigma)
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| (Fun(n1,t1),Fun(n2,t2))::tail ->
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if n1 = n2
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then solve_aux ((t1,t2)::tail) fprobs sigma
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else raise Fail
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| (Abst(a1,t1),Abst(a2,t2))::tail ->
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if a1 = a2
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then solve_aux ((t1,t2)::tail) fprobs sigma
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else solve_aux ((t1,perm [(a1,a2)] t2)::tail) ((a1,t2)::fprobs) sigma
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| (Pair(t1,t2),Pair(s1,s2))::tail ->
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solve_aux ((t1,s1)::(t2,s2)::tail) fprobs sigma
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| _ -> raise Fail;;
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(************)
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(* Examples *)
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(************)
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(* a few variables*)
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let x = Susp([],"X")
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and y = Susp([],"Y")
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and z = Susp([],"Z");;
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(* lam a.(X a) =? lam b.(c b) --> [X:=c] *)
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let t1 = Abst("a",Pair(x,Atm("a")));;
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let t2 = Abst("b",Pair(Atm("c"),Atm("b")));;
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solve [(t1,t2)] [];;
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(* lam a.(X a) =? lam b.(a b) --> fails *)
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let t1 = Abst("a",Pair(x,Atm("a")));;
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let t2 = Abst("b",Pair(Atm("a"),Atm("b")));;
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solve [(t1,t2)] [];;
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(* lam a.(X a) =? lam b.(X b) --> a#X, b#X *)
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let t1 = Abst("a",Pair(x,Atm("a")));;
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let t2 = Abst("b",Pair(x,Atm("b")));;
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solve [(t1,t2)] [];;
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(* lam a.(X a) =? lam b.(Y b) --> [X:=(a b)oY] a#Y *)
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(* --> [Y:=(b a)oX] b#X *)
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let t1 = Abst("a",Pair(x,Atm("a")));;
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let t2 = Abst("b",Pair(y,Atm("b")));;
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solve [(t1,t2)] [];;
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solve [(t2,t1)] [];;
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(* quiz-questions from the paper *)
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let m1 = Susp([],"M1")
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and m2 = Susp([],"M2")
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and m3 = Susp([],"M3")
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and m4 = Susp([],"M4")
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and m5 = Susp([],"M5")
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and m6 = Susp([],"M6")
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and m7 = Susp([],"M7");;
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(* 1 --> fail *)
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let t1 = Abst("a",Abst("b",Pair(m1,Atm("b"))));;
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let t2 = Abst("b",Abst("a",Pair(Atm("a"),m1)));;
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solve [(t1,t2)] [];;
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(* 2 --> [M2:=b ,M3:=a] *)
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let t1 = Abst("a",Abst("b",Pair(m2,Atm("b"))));;
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let t2 = Abst("b",Abst("a",Pair(Atm("a"),m3)));;
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solve [(t1,t2)] [];;
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(* 3 --> [M4:=(a b)o M5] *)
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let t1 = Abst("a",Abst("b",Pair(Atm("b"),m4)));;
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let t2 = Abst("b",Abst("a",Pair(Atm("a"),m5)));;
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solve [(t1,t2)] [];;
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(* 4 --> [M6:=(b a)oM7] b#M7 *)
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let t1 = Abst("a",Abst("b",Pair(Atm("b"),m6)));;
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let t2 = Abst("a",Abst("a",Pair(Atm("a"),m7)));;
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solve [(t1,t2)] [];;
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