Implementation.thy
author Christian Urban <christian dot urban at kcl dot ac dot uk>
Fri, 29 Jan 2016 17:06:02 +0000
changeset 97 c7ba70dc49bd
parent 95 8d2cc27f45f3
parent 93 524bd3caa6b6
child 104 43482ab31341
permissions -rw-r--r--
merged

(*<*)
theory Implementation
imports PIPBasics
begin
(*>*)
section {*
  This file contains lemmas used to guide the recalculation of current precedence 
  after every system call (or system operation)
*}

text {* (* ddd *)
  One beauty of our modelling is that we follow the definitional extension tradition of HOL.
  The benefit of such a concise and miniature model is that  large number of intuitively 
  obvious facts are derived as lemmas, rather than asserted as axioms.
*}

text {*
  However, the lemmas in the forthcoming several locales are no longer 
  obvious. These lemmas show how the current precedences should be recalculated 
  after every execution step (in our model, every step is represented by an event, 
  which in turn, represents a system call, or operation). Each operation is 
  treated in a separate locale.

  The complication of current precedence recalculation comes 
  because the changing of RAG needs to be taken into account, 
  in addition to the changing of precedence. 

  The reason RAG changing affects current precedence is that,
  according to the definition, current precedence 
  of a thread is the maximum of the precedences of every threads in its subtree, 
  where the notion of sub-tree in RAG is defined in RTree.thy.

  Therefore, for each operation, lemmas about the change of precedences 
  and RAG are derived first, on which lemmas about current precedence 
  recalculation are based on.
*}

section {* The @{term Set} operation *}

context valid_trace_set
begin

text {* (* ddd *)
  The following two lemmas confirm that @{text "Set"}-operation
  only changes the precedence of the initiating thread (or actor)
  of the operation (or event).
*}


lemma eq_preced:
  assumes "th' \<noteq> th"
  shows "preced th' (e#s) = preced th' s"
proof -
  from assms show ?thesis 
    by (unfold is_set, auto simp:preced_def)
qed

lemma eq_the_preced: 
  assumes "th' \<noteq> th"
  shows "the_preced (e#s) th' = the_preced s th'"
  using assms
  by (unfold the_preced_def, intro eq_preced, simp)


text {* (* ddd *)
  Th following lemma @{text "eq_cp_pre"} says that the priority change of @{text "th"}
  only affects those threads, which as @{text "Th th"} in their sub-trees.
  
  The proof of this lemma is simplified by using the alternative definition 
  of @{text "cp"}. 
*}

lemma eq_cp_pre:
  assumes nd: "Th th \<notin> subtree (RAG s) (Th th')"
  shows "cp (e#s) th' = cp s th'"
proof -
  -- {* After unfolding using the alternative definition, elements 
        affecting the @{term "cp"}-value of threads become explicit. 
        We only need to prove the following: *}
  have "Max (the_preced (e#s) ` {th'a. Th th'a \<in> subtree (RAG (e#s)) (Th th')}) =
        Max (the_preced s ` {th'a. Th th'a \<in> subtree (RAG s) (Th th')})"
        (is "Max (?f ` ?S1) = Max (?g ` ?S2)")
  proof -
    -- {* The base sets are equal. *}
    have "?S1 = ?S2" using RAG_unchanged by simp
    -- {* The function values on the base set are equal as well. *}
    moreover have "\<forall> e \<in> ?S2. ?f e = ?g e"
    proof
      fix th1
      assume "th1 \<in> ?S2"
      with nd have "th1 \<noteq> th" by (auto)
      from eq_the_preced[OF this]
      show "the_preced (e#s) th1 = the_preced s th1" .
    qed
    -- {* Therefore, the image of the functions are equal. *}
    ultimately have "(?f ` ?S1) = (?g ` ?S2)" by (auto intro!:f_image_eq)
    thus ?thesis by simp
  qed
  thus ?thesis by (simp add:cp_alt_def)
qed

text {*
  The following lemma shows that @{term "th"} is not in the 
  sub-tree of any other thread. 
*}
lemma th_in_no_subtree:
  assumes "th' \<noteq> th"
  shows "Th th \<notin> subtree (RAG s) (Th th')"
proof -
  from readys_in_no_subtree[OF th_ready_s assms(1)]
  show ?thesis by blast
qed

text {* 
  By combining @{thm "eq_cp_pre"} and @{thm "th_in_no_subtree"}, 
  it is obvious that the change of priority only affects the @{text "cp"}-value 
  of the initiating thread @{text "th"}.
*}
lemma eq_cp:
  assumes "th' \<noteq> th"
  shows "cp (e#s) th' = cp s th'"
  by (rule eq_cp_pre[OF th_in_no_subtree[OF assms]])

end

section {* The @{term V} operation *}

text {*
  The following @{text "step_v_cps"} is the locale for @{text "V"}-operation.
*}


context valid_trace_v
begin

lemma ancestors_th: "ancestors (RAG s) (Th th) = {}"
proof -
  from readys_root[OF th_ready_s]
  show ?thesis
  by (unfold root_def, simp)
qed

lemma edge_of_th:
    "(Cs cs, Th th) \<in> RAG s" 
proof -
 from holding_th_cs_s
 show ?thesis 
    by (unfold s_RAG_def holding_eq, auto)
qed

lemma ancestors_cs: 
  "ancestors (RAG s) (Cs cs) = {Th th}"
proof -
  have "ancestors (RAG s) (Cs cs) = ancestors (RAG s) (Th th)  \<union>  {Th th}"
   by (rule rtree_RAG.ancestors_accum[OF edge_of_th])
  from this[unfolded ancestors_th] show ?thesis by simp
qed

end

text {*
  The following @{text "step_v_cps_nt"} is the sub-locale for @{text "V"}-operation, 
  which represents the case when there is another thread @{text "th'"}
  to take over the critical resource released by the initiating thread @{text "th"}.
*}

context valid_trace_v_n
begin

lemma sub_RAGs': 
  "{(Cs cs, Th th), (Th taker, Cs cs)} \<subseteq> RAG s"
     using next_th_RAG[OF next_th_taker]  .

lemma ancestors_th': 
  "ancestors (RAG s) (Th taker) = {Th th, Cs cs}" 
proof -
  have "ancestors (RAG s) (Th taker) = ancestors (RAG s) (Cs cs) \<union> {Cs cs}"
  proof(rule  rtree_RAG.ancestors_accum)
    from sub_RAGs' show "(Th taker, Cs cs) \<in> RAG s" by auto
  qed
  thus ?thesis using ancestors_th ancestors_cs by auto
qed

lemma RAG_s:
  "RAG (e#s) = (RAG s - {(Cs cs, Th th), (Th taker, Cs cs)}) \<union>
                                         {(Cs cs, Th taker)}"
 by (unfold RAG_es waiting_set_eq holding_set_eq, auto)

lemma subtree_kept: (* ddd *)
  assumes "th1 \<notin> {th, taker}"
  shows "subtree (RAG (e#s)) (Th th1) = 
                     subtree (RAG s) (Th th1)" (is "_ = ?R")
proof -
  let ?RAG' = "(RAG s - {(Cs cs, Th th), (Th taker, Cs cs)})"
  let ?RAG'' = "?RAG' \<union> {(Cs cs, Th taker)}"
  have "subtree ?RAG' (Th th1) = ?R" 
  proof(rule subset_del_subtree_outside)
    show "Range {(Cs cs, Th th), (Th taker, Cs cs)} \<inter> subtree (RAG s) (Th th1) = {}"
    proof -
      have "(Th th) \<notin> subtree (RAG s) (Th th1)"
      proof(rule subtree_refute)
        show "Th th1 \<notin> ancestors (RAG s) (Th th)"
          by (unfold ancestors_th, simp)
      next
        from assms show "Th th1 \<noteq> Th th" by simp
      qed
      moreover have "(Cs cs) \<notin>  subtree (RAG s) (Th th1)"
      proof(rule subtree_refute)
        show "Th th1 \<notin> ancestors (RAG s) (Cs cs)"
          by (unfold ancestors_cs, insert assms, auto)
      qed simp
      ultimately have "{Th th, Cs cs} \<inter> subtree (RAG s) (Th th1) = {}" by auto
      thus ?thesis by simp
     qed
  qed
  moreover have "subtree ?RAG'' (Th th1) =  subtree ?RAG' (Th th1)"
  proof(rule subtree_insert_next)
    show "Th taker \<notin> subtree (RAG s - {(Cs cs, Th th), (Th taker, Cs cs)}) (Th th1)"
    proof(rule subtree_refute)
      show "Th th1 \<notin> ancestors (RAG s - {(Cs cs, Th th), (Th taker, Cs cs)}) (Th taker)"
            (is "_ \<notin> ?R")
      proof -
          have "?R \<subseteq> ancestors (RAG s) (Th taker)" by (rule ancestors_mono, auto)
          moreover have "Th th1 \<notin> ..." using ancestors_th' assms by simp
          ultimately show ?thesis by auto
      qed
    next
      from assms show "Th th1 \<noteq> Th taker" by simp
    qed
  qed
  ultimately show ?thesis by (unfold RAG_s, simp)
qed

lemma cp_kept:
  assumes "th1 \<notin> {th, taker}"
  shows "cp (e#s) th1 = cp s th1"
    by (unfold cp_alt_def the_preced_es subtree_kept[OF assms], simp)

end


context valid_trace_v_e
begin

find_theorems RAG s e

lemma RAG_s: "RAG (e#s) = RAG s - {(Cs cs, Th th)}"
  by (unfold RAG_es waiting_set_eq holding_set_eq, simp)

lemma subtree_kept:
  assumes "th1 \<noteq> th"
  shows "subtree (RAG (e#s)) (Th th1) = subtree (RAG s) (Th th1)"
proof(unfold RAG_s, rule subset_del_subtree_outside)
  show "Range {(Cs cs, Th th)} \<inter> subtree (RAG s) (Th th1) = {}"
  proof -
    have "(Th th) \<notin> subtree (RAG s) (Th th1)"
    proof(rule subtree_refute)
      show "Th th1 \<notin> ancestors (RAG s) (Th th)"
          by (unfold ancestors_th, simp)
    next
      from assms show "Th th1 \<noteq> Th th" by simp
    qed
    thus ?thesis by auto
  qed
qed

lemma cp_kept_1:
  assumes "th1 \<noteq> th"
  shows "cp (e#s) th1 = cp s th1"
    by (unfold cp_alt_def the_preced_es subtree_kept[OF assms], simp)

lemma subtree_cs: "subtree (RAG s) (Cs cs) = {Cs cs}"
proof -
  { fix n
    have "(Cs cs) \<notin> ancestors (RAG s) n"
    proof
      assume "Cs cs \<in> ancestors (RAG s) n"
      hence "(n, Cs cs) \<in> (RAG s)^+" by (auto simp:ancestors_def)
      from tranclE[OF this] obtain nn where h: "(nn, Cs cs) \<in> RAG s" by auto
      then obtain th' where "nn = Th th'"
        by (unfold s_RAG_def, auto)
      from h[unfolded this] have "(Th th', Cs cs) \<in> RAG s" .
      from this[unfolded s_RAG_def]
      have "waiting (wq s) th' cs" by auto
      from this[unfolded cs_waiting_def]
      have "1 < length (wq s cs)"
          by (cases "wq s cs", auto)
      from holding_next_thI[OF holding_th_cs_s this]
      obtain th' where "next_th s th cs th'" by auto
      thus False using no_taker by blast
    qed
  } note h = this
  {  fix n
     assume "n \<in> subtree (RAG s) (Cs cs)"
     hence "n = (Cs cs)"
     by (elim subtreeE, insert h, auto)
  } moreover have "(Cs cs) \<in> subtree (RAG s) (Cs cs)"
      by (auto simp:subtree_def)
  ultimately show ?thesis by auto 
qed

lemma subtree_th: 
  "subtree (RAG (e#s)) (Th th) = subtree (RAG s) (Th th) - {Cs cs}"
proof(unfold RAG_s, fold subtree_cs, rule rtree_RAG.subtree_del_inside)
  from edge_of_th
  show "(Cs cs, Th th) \<in> edges_in (RAG s) (Th th)"
    by (unfold edges_in_def, auto simp:subtree_def)
qed

lemma cp_kept_2: 
  shows "cp (e#s) th = cp s th" 
 by (unfold cp_alt_def subtree_th the_preced_es, auto)

lemma eq_cp:
  shows "cp (e#s) th' = cp s th'"
  using cp_kept_1 cp_kept_2
  by (cases "th' = th", auto)

end


section {* The @{term P} operation *}

context valid_trace_p
begin

lemma root_th: "root (RAG s) (Th th)"
  by (simp add: ready_th_s readys_root)

lemma in_no_others_subtree:
  assumes "th' \<noteq> th"
  shows "Th th \<notin> subtree (RAG s) (Th th')"
proof
  assume "Th th \<in> subtree (RAG s) (Th th')"
  thus False
  proof(cases rule:subtreeE)
    case 1
    with assms show ?thesis by auto
  next
    case 2
    with root_th show ?thesis by (auto simp:root_def)
  qed
qed

lemma preced_kept: "the_preced (e#s) = the_preced s"
proof
  fix th'
  show "the_preced (e # s) th' = the_preced s th'"
    by (unfold the_preced_def is_p preced_def, simp)
qed

end


context valid_trace_p_h
begin

lemma subtree_kept:
  assumes "th' \<noteq> th"
  shows "subtree (RAG (e#s)) (Th th') = subtree (RAG s) (Th th')"
proof(unfold RAG_es, rule subtree_insert_next)
  from in_no_others_subtree[OF assms] 
  show "Th th \<notin> subtree (RAG s) (Th th')" .
qed

lemma cp_kept: 
  assumes "th' \<noteq> th"
  shows "cp (e#s) th' = cp s th'"
proof -
  have "(the_preced (e#s) ` {th'a. Th th'a \<in> subtree (RAG (e#s)) (Th th')}) =
        (the_preced s ` {th'a. Th th'a \<in> subtree (RAG s) (Th th')})"
        by (unfold preced_kept subtree_kept[OF assms], simp)
  thus ?thesis by (unfold cp_alt_def, simp)
qed

end

context valid_trace_p_w
begin

interpretation vat_e: valid_trace "e#s"
  by (unfold_locales, insert vt_e, simp)

lemma cs_held: "(Cs cs, Th holder) \<in> RAG s"
  using holding_s_holder
  by (unfold s_RAG_def, fold holding_eq, auto)

lemma tRAG_s: 
  "tRAG (e#s) = tRAG s \<union> {(Th th, Th holder)}"
  using local.RAG_tRAG_transfer[OF RAG_es cs_held] .

lemma cp_kept:
  assumes "Th th'' \<notin> ancestors (tRAG (e#s)) (Th th)"
  shows "cp (e#s) th'' = cp s th''"
proof -
  have h: "subtree (tRAG (e#s)) (Th th'') = subtree (tRAG s) (Th th'')"
  proof -
    have "Th holder \<notin> subtree (tRAG s) (Th th'')"
    proof
      assume "Th holder \<in> subtree (tRAG s) (Th th'')"
      thus False
      proof(rule subtreeE)
         assume "Th holder = Th th''"
         from assms[unfolded tRAG_s ancestors_def, folded this]
         show ?thesis by auto
      next
         assume "Th th'' \<in> ancestors (tRAG s) (Th holder)"
         moreover have "... \<subseteq> ancestors (tRAG (e#s)) (Th holder)"
         proof(rule ancestors_mono)
            show "tRAG s \<subseteq> tRAG (e#s)" by (unfold tRAG_s, auto)
         qed 
         ultimately have "Th th'' \<in> ancestors (tRAG (e#s)) (Th holder)" by auto
         moreover have "Th holder \<in> ancestors (tRAG (e#s)) (Th th)"
           by (unfold tRAG_s, auto simp:ancestors_def)
         ultimately have "Th th'' \<in> ancestors (tRAG (e#s)) (Th th)"
                       by (auto simp:ancestors_def)
         with assms show ?thesis by auto
      qed
    qed
    from subtree_insert_next[OF this]
    have "subtree (tRAG s \<union> {(Th th, Th holder)}) (Th th'') = subtree (tRAG s) (Th th'')" .
    from this[folded tRAG_s] show ?thesis .
  qed
  show ?thesis by (unfold cp_alt_def1 h preced_kept, simp)
qed

lemma cp_gen_update_stop: (* ddd *)
  assumes "u \<in> ancestors (tRAG (e#s)) (Th th)"
  and "cp_gen (e#s) u = cp_gen s u"
  and "y \<in> ancestors (tRAG (e#s)) u"
  shows "cp_gen (e#s) y = cp_gen s y"
  using assms(3)
proof(induct rule:wf_induct[OF vat_e.fsbttRAGs.wf])
  case (1 x)
  show ?case (is "?L = ?R")
  proof -
    from tRAG_ancestorsE[OF 1(2)]
    obtain th2 where eq_x: "x = Th th2" by blast
    from vat_e.cp_gen_rec[OF this]
    have "?L = 
          Max ({the_preced (e#s) th2} \<union> cp_gen (e#s) ` RTree.children (tRAG (e#s)) x)" .
    also have "... = 
          Max ({the_preced s th2} \<union> cp_gen s ` RTree.children (tRAG s) x)"
    proof -
      from preced_kept have "the_preced (e#s) th2 = the_preced s th2" by simp
      moreover have "cp_gen (e#s) ` RTree.children (tRAG (e#s)) x =
                     cp_gen s ` RTree.children (tRAG s) x"
      proof -
        have "RTree.children (tRAG (e#s)) x =  RTree.children (tRAG s) x"
        proof(unfold tRAG_s, rule children_union_kept)
          have start: "(Th th, Th holder) \<in> tRAG (e#s)"
            by (unfold tRAG_s, auto)
          note x_u = 1(2)
          show "x \<notin> Range {(Th th, Th holder)}"
          proof
            assume "x \<in> Range {(Th th, Th holder)}"
            hence eq_x: "x = Th holder" using RangeE by auto
            show False
            proof(cases rule:vat_e.ancestors_headE[OF assms(1) start])
              case 1
              from x_u[folded this, unfolded eq_x] vat_e.acyclic_tRAG
              show ?thesis by (auto simp:ancestors_def acyclic_def)
            next
              case 2
              with x_u[unfolded eq_x]
              have "(Th holder, Th holder) \<in> (tRAG (e#s))^+" by (auto simp:ancestors_def)
              with vat_e.acyclic_tRAG show ?thesis by (auto simp:acyclic_def)
            qed
          qed
        qed
        moreover have "cp_gen (e#s) ` RTree.children (tRAG (e#s)) x =
                       cp_gen s ` RTree.children (tRAG (e#s)) x" (is "?f ` ?A = ?g ` ?A")
        proof(rule f_image_eq)
          fix a
          assume a_in: "a \<in> ?A"
          from 1(2)
          show "?f a = ?g a"
          proof(cases rule:vat_e.rtree_s.ancestors_childrenE[case_names in_ch out_ch])
             case in_ch
             show ?thesis
             proof(cases "a = u")
                case True
                from assms(2)[folded this] show ?thesis .
             next
                case False
                have a_not_in: "a \<notin> ancestors (tRAG (e#s)) (Th th)"
                proof
                  assume a_in': "a \<in> ancestors (tRAG (e#s)) (Th th)"
                  have "a = u"
                  proof(rule vat_e.rtree_s.ancestors_children_unique)
                    from a_in' a_in show "a \<in> ancestors (tRAG (e#s)) (Th th) \<inter> 
                                          RTree.children (tRAG (e#s)) x" by auto
                  next 
                    from assms(1) in_ch show "u \<in> ancestors (tRAG (e#s)) (Th th) \<inter> 
                                      RTree.children (tRAG (e#s)) x" by auto
                  qed
                  with False show False by simp
                qed
                from a_in obtain th_a where eq_a: "a = Th th_a" 
                    by (unfold RTree.children_def tRAG_alt_def, auto)
                from cp_kept[OF a_not_in[unfolded eq_a]]
                have "cp (e#s) th_a = cp s th_a" .
                from this [unfolded cp_gen_def_cond[OF eq_a], folded eq_a]
                show ?thesis .
             qed
          next
            case (out_ch z)
            hence h: "z \<in> ancestors (tRAG (e#s)) u" "z \<in> RTree.children (tRAG (e#s)) x" by auto
            show ?thesis
            proof(cases "a = z")
              case True
              from h(2) have zx_in: "(z, x) \<in> (tRAG (e#s))" by (auto simp:RTree.children_def)
              from 1(1)[rule_format, OF this h(1)]
              have eq_cp_gen: "cp_gen (e#s) z = cp_gen s z" .
              with True show ?thesis by metis
            next
              case False
              from a_in obtain th_a where eq_a: "a = Th th_a"
                by (auto simp:RTree.children_def tRAG_alt_def)
              have "a \<notin> ancestors (tRAG (e#s)) (Th th)"
              proof
                assume a_in': "a \<in> ancestors (tRAG (e#s)) (Th th)"
                have "a = z"
                proof(rule vat_e.rtree_s.ancestors_children_unique)
                  from assms(1) h(1) have "z \<in> ancestors (tRAG (e#s)) (Th th)"
                      by (auto simp:ancestors_def)
                  with h(2) show " z \<in> ancestors (tRAG (e#s)) (Th th) \<inter> 
                                       RTree.children (tRAG (e#s)) x" by auto
                next
                  from a_in a_in'
                  show "a \<in> ancestors (tRAG (e#s)) (Th th) \<inter> RTree.children (tRAG (e#s)) x"
                    by auto
                qed
                with False show False by auto
              qed
              from cp_kept[OF this[unfolded eq_a]]
              have "cp (e#s) th_a = cp s th_a" .
              from this[unfolded cp_gen_def_cond[OF eq_a], folded eq_a]
              show ?thesis .
            qed
          qed
        qed
        ultimately show ?thesis by metis
      qed
      ultimately show ?thesis by simp
    qed
    also have "... = ?R"
      by (fold cp_gen_rec[OF eq_x], simp)
    finally show ?thesis .
  qed
qed

lemma cp_up:
  assumes "(Th th') \<in> ancestors (tRAG (e#s)) (Th th)"
  and "cp (e#s) th' = cp s th'"
  and "(Th th'') \<in> ancestors (tRAG (e#s)) (Th th')"
  shows "cp (e#s) th'' = cp s th''"
proof -
  have "cp_gen (e#s) (Th th'') = cp_gen s (Th th'')"
  proof(rule cp_gen_update_stop[OF assms(1) _ assms(3)])
    from assms(2) cp_gen_def_cond[OF refl[of "Th th'"]]
    show "cp_gen (e#s) (Th th') = cp_gen s (Th th')" by metis
  qed
  with cp_gen_def_cond[OF refl[of "Th th''"]]
  show ?thesis by metis
qed

end

section {* The @{term Create} operation *}

context valid_trace_create
begin 

interpretation vat_e: valid_trace "e#s"
  by (unfold_locales, insert vt_e, simp)

lemma tRAG_kept: "tRAG (e#s) = tRAG s"
  by (unfold tRAG_alt_def RAG_unchanged, auto)

lemma preced_kept:
  assumes "th' \<noteq> th"
  shows "the_preced (e#s) th' = the_preced s th'"
  by (unfold the_preced_def preced_def is_create, insert assms, auto)

lemma th_not_in: "Th th \<notin> Field (tRAG s)"
  by (meson not_in_thread_isolated subsetCE tRAG_Field th_not_live_s)

lemma eq_cp:
  assumes neq_th: "th' \<noteq> th"
  shows "cp (e#s) th' = cp s th'"
proof -
  have "(the_preced (e#s) \<circ> the_thread) ` subtree (tRAG (e#s)) (Th th') =
        (the_preced s \<circ> the_thread) ` subtree (tRAG s) (Th th')"
  proof(unfold tRAG_kept, rule f_image_eq)
    fix a
    assume a_in: "a \<in> subtree (tRAG s) (Th th')"
    then obtain th_a where eq_a: "a = Th th_a" 
    proof(cases rule:subtreeE)
      case 2
      from ancestors_Field[OF 2(2)]
      and that show ?thesis by (unfold tRAG_alt_def, auto)
    qed auto
    have neq_th_a: "th_a \<noteq> th"
    proof -
      have "(Th th) \<notin> subtree (tRAG s) (Th th')"
      proof
        assume "Th th \<in> subtree (tRAG s) (Th th')"
        thus False
        proof(cases rule:subtreeE)
          case 2
          from ancestors_Field[OF this(2)]
          and th_not_in[unfolded Field_def]
          show ?thesis by auto
        qed (insert assms, auto)
      qed
      with a_in[unfolded eq_a] show ?thesis by auto
    qed
    from preced_kept[OF this]
    show "(the_preced (e#s) \<circ> the_thread) a = (the_preced s \<circ> the_thread) a"
      by (unfold eq_a, simp)
  qed
  thus ?thesis by (unfold cp_alt_def1, simp)
qed

lemma children_of_th: "RTree.children (tRAG (e#s)) (Th th) = {}"
proof -
  { fix a
    assume "a \<in> RTree.children (tRAG (e#s)) (Th th)"
    hence "(a, Th th) \<in> tRAG (e#s)" by (auto simp:RTree.children_def)
    with th_not_in have False 
     by (unfold Field_def tRAG_kept, auto)
  } thus ?thesis by auto
qed

lemma eq_cp_th: "cp (e#s) th = preced th (e#s)"
 by (unfold vat_e.cp_rec children_of_th, simp add:the_preced_def)

end


context valid_trace_exit
begin

lemma preced_kept:
  assumes "th' \<noteq> th"
  shows "the_preced (e#s) th' = the_preced s th'"
  using assms
  by (unfold the_preced_def is_exit preced_def, simp)

lemma tRAG_kept: "tRAG (e#s) = tRAG s"
  by (unfold tRAG_alt_def RAG_unchanged, auto)

lemma th_RAG: "Th th \<notin> Field (RAG s)"
proof -
  have "Th th \<notin> Range (RAG s)"
  proof
    assume "Th th \<in> Range (RAG s)"
    then obtain cs where "holding (wq s) th cs"
      by (unfold Range_iff s_RAG_def, auto)
    with holdents_th_s[unfolded holdents_def]
    show False by (unfold holding_eq, auto)
  qed
  moreover have "Th th \<notin> Domain (RAG s)"
  proof
    assume "Th th \<in> Domain (RAG s)"
    then obtain cs where "waiting (wq s) th cs"
      by (unfold Domain_iff s_RAG_def, auto)
    with th_ready_s show False by (unfold readys_def waiting_eq, auto)
  qed
  ultimately show ?thesis by (auto simp:Field_def)
qed

lemma th_tRAG: "(Th th) \<notin> Field (tRAG s)"
  using th_RAG tRAG_Field by auto

lemma eq_cp:
  assumes neq_th: "th' \<noteq> th"
  shows "cp (e#s) th' = cp s th'"
proof -
  have "(the_preced (e#s) \<circ> the_thread) ` subtree (tRAG (e#s)) (Th th') =
        (the_preced s \<circ> the_thread) ` subtree (tRAG s) (Th th')"
  proof(unfold tRAG_kept, rule f_image_eq)
    fix a
    assume a_in: "a \<in> subtree (tRAG s) (Th th')"
    then obtain th_a where eq_a: "a = Th th_a" 
    proof(cases rule:subtreeE)
      case 2
      from ancestors_Field[OF 2(2)]
      and that show ?thesis by (unfold tRAG_alt_def, auto)
    qed auto
    have neq_th_a: "th_a \<noteq> th"
    proof -
      from readys_in_no_subtree[OF th_ready_s assms]
      have "(Th th) \<notin> subtree (RAG s) (Th th')" .
      with tRAG_subtree_RAG[of s "Th th'"]
      have "(Th th) \<notin> subtree (tRAG s) (Th th')" by auto
      with a_in[unfolded eq_a] show ?thesis by auto
    qed
    from preced_kept[OF this]
    show "(the_preced (e#s) \<circ> the_thread) a = (the_preced s \<circ> the_thread) a"
      by (unfold eq_a, simp)
  qed
  thus ?thesis by (unfold cp_alt_def1, simp)
qed

end

end