CpsG.thy
author xingyuan zhang <xingyuanzhang@126.com>
Fri, 30 Oct 2015 20:40:11 +0800
changeset 55 b85cfbd58f59
parent 53 8142e80f5d58
child 56 0fd478e14e87
permissions -rw-r--r--
Comments for Set-operation finished

section {*
  This file contains lemmas used to guide the recalculation of current precedence 
  after every system call (or system operation)
*}
theory CpsG
imports PrioG Max
begin

lemma eq_dependants: "dependants (wq s) = dependants s"
  by (simp add: s_dependants_abv wq_def)
  
(* obvious lemma *)
lemma not_thread_holdents:
  fixes th s
  assumes vt: "vt s"
  and not_in: "th \<notin> threads s" 
  shows "holdents s th = {}"
proof -
  from vt not_in show ?thesis
  proof(induct arbitrary:th)
    case (vt_cons s e th)
    assume vt: "vt s"
      and ih: "\<And>th. th \<notin> threads s \<Longrightarrow> holdents s th = {}"
      and stp: "step s e"
      and not_in: "th \<notin> threads (e # s)"
    from stp show ?case
    proof(cases)
      case (thread_create thread prio)
      assume eq_e: "e = Create thread prio"
        and not_in': "thread \<notin> threads s"
      have "holdents (e # s) th = holdents s th"
        apply (unfold eq_e holdents_test)
        by (simp add:RAG_create_unchanged)
      moreover have "th \<notin> threads s" 
      proof -
        from not_in eq_e show ?thesis by simp
      qed
      moreover note ih ultimately show ?thesis by auto
    next
      case (thread_exit thread)
      assume eq_e: "e = Exit thread"
      and nh: "holdents s thread = {}"
      show ?thesis
      proof(cases "th = thread")
        case True
        with nh eq_e
        show ?thesis 
          by (auto simp:holdents_test RAG_exit_unchanged)
      next
        case False
        with not_in and eq_e
        have "th \<notin> threads s" by simp
        from ih[OF this] False eq_e show ?thesis 
          by (auto simp:holdents_test RAG_exit_unchanged)
      qed
    next
      case (thread_P thread cs)
      assume eq_e: "e = P thread cs"
      and is_runing: "thread \<in> runing s"
      from assms thread_exit ih stp not_in vt eq_e have vtp: "vt (P thread cs#s)" by auto
      have neq_th: "th \<noteq> thread" 
      proof -
        from not_in eq_e have "th \<notin> threads s" by simp
        moreover from is_runing have "thread \<in> threads s"
          by (simp add:runing_def readys_def)
        ultimately show ?thesis by auto
      qed
      hence "holdents (e # s) th  = holdents s th "
        apply (unfold cntCS_def holdents_test eq_e)
        by (unfold step_RAG_p[OF vtp], auto)
      moreover have "holdents s th = {}"
      proof(rule ih)
        from not_in eq_e show "th \<notin> threads s" by simp
      qed
      ultimately show ?thesis by simp
    next
      case (thread_V thread cs)
      assume eq_e: "e = V thread cs"
        and is_runing: "thread \<in> runing s"
        and hold: "holding s thread cs"
      have neq_th: "th \<noteq> thread" 
      proof -
        from not_in eq_e have "th \<notin> threads s" by simp
        moreover from is_runing have "thread \<in> threads s"
          by (simp add:runing_def readys_def)
        ultimately show ?thesis by auto
      qed
      from assms thread_V eq_e ih stp not_in vt have vtv: "vt (V thread cs#s)" by auto
      from hold obtain rest 
        where eq_wq: "wq s cs = thread # rest"
        by (case_tac "wq s cs", auto simp: wq_def s_holding_def)
      from not_in eq_e eq_wq
      have "\<not> next_th s thread cs th"
        apply (auto simp:next_th_def)
      proof -
        assume ne: "rest \<noteq> []"
          and ni: "hd (SOME q. distinct q \<and> set q = set rest) \<notin> threads s" (is "?t \<notin> threads s")
        have "?t \<in> set rest"
        proof(rule someI2)
          from wq_distinct[OF step_back_vt[OF vtv], of cs] and eq_wq
          show "distinct rest \<and> set rest = set rest" by auto
        next
          fix x assume "distinct x \<and> set x = set rest" with ne
          show "hd x \<in> set rest" by (cases x, auto)
        qed
        with eq_wq have "?t \<in> set (wq s cs)" by simp
        from wq_threads[OF step_back_vt[OF vtv], OF this] and ni
        show False by auto
      qed
      moreover note neq_th eq_wq
      ultimately have "holdents (e # s) th  = holdents s th"
        by (unfold eq_e cntCS_def holdents_test step_RAG_v[OF vtv], auto)
      moreover have "holdents s th = {}"
      proof(rule ih)
        from not_in eq_e show "th \<notin> threads s" by simp
      qed
      ultimately show ?thesis by simp
    next
      case (thread_set thread prio)
      print_facts
      assume eq_e: "e = Set thread prio"
        and is_runing: "thread \<in> runing s"
      from not_in and eq_e have "th \<notin> threads s" by auto
      from ih [OF this] and eq_e
      show ?thesis 
        apply (unfold eq_e cntCS_def holdents_test)
        by (simp add:RAG_set_unchanged)
    qed
    next
      case vt_nil
      show ?case
      by (auto simp:count_def holdents_test s_RAG_def wq_def cs_holding_def)
  qed
qed

(* obvious lemma *)
lemma next_th_neq: 
  assumes vt: "vt s"
  and nt: "next_th s th cs th'"
  shows "th' \<noteq> th"
proof -
  from nt show ?thesis
    apply (auto simp:next_th_def)
  proof -
    fix rest
    assume eq_wq: "wq s cs = hd (SOME q. distinct q \<and> set q = set rest) # rest"
      and ne: "rest \<noteq> []"
    have "hd (SOME q. distinct q \<and> set q = set rest) \<in> set rest" 
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      fix x
      assume "distinct x \<and> set x = set rest"
      hence eq_set: "set x = set rest" by auto
      with ne have "x \<noteq> []" by auto
      hence "hd x \<in> set x" by auto
      with eq_set show "hd x \<in> set rest" by auto
    qed
    with wq_distinct[OF vt, of cs] eq_wq show False by auto
  qed
qed

(* obvious lemma *)
lemma next_th_unique: 
  assumes nt1: "next_th s th cs th1"
  and nt2: "next_th s th cs th2"
  shows "th1 = th2"
using assms by (unfold next_th_def, auto)

lemma wf_RAG:
  assumes vt: "vt s"
  shows "wf (RAG s)"
proof(rule finite_acyclic_wf)
  from finite_RAG[OF vt] show "finite (RAG s)" .
next
  from acyclic_RAG[OF vt] show "acyclic (RAG s)" .
qed

definition child :: "state \<Rightarrow> (node \<times> node) set"
  where "child s \<equiv>
            {(Th th', Th th) | th th'. \<exists>cs. (Th th', Cs cs) \<in> RAG s \<and> (Cs cs, Th th) \<in> RAG s}"

definition children :: "state \<Rightarrow> thread \<Rightarrow> thread set"
  where "children s th \<equiv> {th'. (Th th', Th th) \<in> child s}"

lemma children_def2:
  "children s th \<equiv> {th'. \<exists> cs. (Th th', Cs cs) \<in> RAG s \<and> (Cs cs, Th th) \<in> RAG s}"
unfolding child_def children_def by simp

lemma children_dependants: 
  "children s th \<subseteq> dependants (wq s) th"
  unfolding children_def2
  unfolding cs_dependants_def
  by (auto simp add: eq_RAG)

lemma child_unique:
  assumes vt: "vt s"
  and ch1: "(Th th, Th th1) \<in> child s"
  and ch2: "(Th th, Th th2) \<in> child s"
  shows "th1 = th2"
using ch1 ch2 
proof(unfold child_def, clarsimp)
  fix cs csa
  assume h1: "(Th th, Cs cs) \<in> RAG s"
    and h2: "(Cs cs, Th th1) \<in> RAG s"
    and h3: "(Th th, Cs csa) \<in> RAG s"
    and h4: "(Cs csa, Th th2) \<in> RAG s"
  from unique_RAG[OF vt h1 h3] have "cs = csa" by simp
  with h4 have "(Cs cs, Th th2) \<in> RAG s" by simp
  from unique_RAG[OF vt h2 this]
  show "th1 = th2" by simp
qed 

lemma RAG_children:
  assumes h: "(Th th1, Th th2) \<in> (RAG s)^+"
  shows "th1 \<in> children s th2 \<or> (\<exists> th3. th3 \<in> children s th2 \<and> (Th th1, Th th3) \<in> (RAG s)^+)"
proof -
  from h show ?thesis
  proof(induct rule: tranclE)
    fix c th2
    assume h1: "(Th th1, c) \<in> (RAG s)\<^sup>+"
    and h2: "(c, Th th2) \<in> RAG s"
    from h2 obtain cs where eq_c: "c = Cs cs"
      by (case_tac c, auto simp:s_RAG_def)
    show "th1 \<in> children s th2 \<or> (\<exists>th3. th3 \<in> children s th2 \<and> (Th th1, Th th3) \<in> (RAG s)\<^sup>+)"
    proof(rule tranclE[OF h1])
      fix ca
      assume h3: "(Th th1, ca) \<in> (RAG s)\<^sup>+"
        and h4: "(ca, c) \<in> RAG s"
      show "th1 \<in> children s th2 \<or> (\<exists>th3. th3 \<in> children s th2 \<and> (Th th1, Th th3) \<in> (RAG s)\<^sup>+)"
      proof -
        from eq_c and h4 obtain th3 where eq_ca: "ca = Th th3"
          by (case_tac ca, auto simp:s_RAG_def)
        from eq_ca h4 h2 eq_c
        have "th3 \<in> children s th2" by (auto simp:children_def child_def)
        moreover from h3 eq_ca have "(Th th1, Th th3) \<in> (RAG s)\<^sup>+" by simp
        ultimately show ?thesis by auto
      qed
    next
      assume "(Th th1, c) \<in> RAG s"
      with h2 eq_c
      have "th1 \<in> children s th2"
        by (auto simp:children_def child_def)
      thus ?thesis by auto
    qed
  next
    assume "(Th th1, Th th2) \<in> RAG s"
    thus ?thesis
      by (auto simp:s_RAG_def)
  qed
qed

lemma sub_child: "child s \<subseteq> (RAG s)^+"
  by (unfold child_def, auto)

lemma wf_child: 
  assumes vt: "vt s"
  shows "wf (child s)"
apply(rule wf_subset)
apply(rule wf_trancl[OF wf_RAG[OF vt]])
apply(rule sub_child)
done

lemma RAG_child_pre:
  assumes vt: "vt s"
  shows
  "(Th th, n) \<in> (RAG s)^+ \<longrightarrow> (\<forall> th'. n = (Th th') \<longrightarrow> (Th th, Th th') \<in> (child s)^+)" (is "?P n")
proof -
  from wf_trancl[OF wf_RAG[OF vt]]
  have wf: "wf ((RAG s)^+)" .
  show ?thesis
  proof(rule wf_induct[OF wf, of ?P], clarsimp)
    fix th'
    assume ih[rule_format]: "\<forall>y. (y, Th th') \<in> (RAG s)\<^sup>+ \<longrightarrow>
               (Th th, y) \<in> (RAG s)\<^sup>+ \<longrightarrow> (\<forall>th'. y = Th th' \<longrightarrow> (Th th, Th th') \<in> (child s)\<^sup>+)"
    and h: "(Th th, Th th') \<in> (RAG s)\<^sup>+"
    show "(Th th, Th th') \<in> (child s)\<^sup>+"
    proof -
      from RAG_children[OF h]
      have "th \<in> children s th' \<or> (\<exists>th3. th3 \<in> children s th' \<and> (Th th, Th th3) \<in> (RAG s)\<^sup>+)" .
      thus ?thesis
      proof
        assume "th \<in> children s th'"
        thus "(Th th, Th th') \<in> (child s)\<^sup>+" by (auto simp:children_def)
      next
        assume "\<exists>th3. th3 \<in> children s th' \<and> (Th th, Th th3) \<in> (RAG s)\<^sup>+"
        then obtain th3 where th3_in: "th3 \<in> children s th'" 
          and th_dp: "(Th th, Th th3) \<in> (RAG s)\<^sup>+" by auto
        from th3_in have "(Th th3, Th th') \<in> (RAG s)^+" by (auto simp:children_def child_def)
        from ih[OF this th_dp, of th3] have "(Th th, Th th3) \<in> (child s)\<^sup>+" by simp
        with th3_in show "(Th th, Th th') \<in> (child s)\<^sup>+" by (auto simp:children_def)
      qed
    qed
  qed
qed

lemma RAG_child: "\<lbrakk>vt s; (Th th, Th th') \<in> (RAG s)^+\<rbrakk> \<Longrightarrow> (Th th, Th th') \<in> (child s)^+"
  by (insert RAG_child_pre, auto)

lemma child_RAG_p:
  assumes "(n1, n2) \<in> (child s)^+"
  shows "(n1, n2) \<in> (RAG s)^+"
proof -
  from assms show ?thesis
  proof(induct)
    case (base y)
    with sub_child show ?case by auto
  next
    case (step y z)
    assume "(y, z) \<in> child s"
    with sub_child have "(y, z) \<in> (RAG s)^+" by auto
    moreover have "(n1, y) \<in> (RAG s)^+" by fact
    ultimately show ?case by auto
  qed
qed

text {* (* ddd *)
*}
lemma child_RAG_eq: 
  assumes vt: "vt s"
  shows "(Th th1, Th th2) \<in> (child s)^+  \<longleftrightarrow> (Th th1, Th th2) \<in> (RAG s)^+"
  by (auto intro: RAG_child[OF vt] child_RAG_p)

text {* (* ddd *)
*}
lemma children_no_dep:
  fixes s th th1 th2 th3
  assumes vt: "vt s"
  and ch1: "(Th th1, Th th) \<in> child s"
  and ch2: "(Th th2, Th th) \<in> child s"
  and ch3: "(Th th1, Th th2) \<in> (RAG s)^+"
  shows "False"
proof -
  from RAG_child[OF vt ch3]
  have "(Th th1, Th th2) \<in> (child s)\<^sup>+" .
  thus ?thesis
  proof(rule converse_tranclE)
    assume "(Th th1, Th th2) \<in> child s"
    from child_unique[OF vt ch1 this] have "th = th2" by simp
    with ch2 have "(Th th2, Th th2) \<in> child s" by simp
    with wf_child[OF vt] show ?thesis by auto
  next
    fix c
    assume h1: "(Th th1, c) \<in> child s"
      and h2: "(c, Th th2) \<in> (child s)\<^sup>+"
    from h1 obtain th3 where eq_c: "c = Th th3" by (unfold child_def, auto)
    with h1 have "(Th th1, Th th3) \<in> child s" by simp
    from child_unique[OF vt ch1 this] have eq_th3: "th3 = th" by simp
    with eq_c and h2 have "(Th th, Th th2) \<in> (child s)\<^sup>+" by simp
    with ch2 have "(Th th, Th th) \<in> (child s)\<^sup>+" by auto
    moreover have "wf ((child s)\<^sup>+)"
    proof(rule wf_trancl)
      from wf_child[OF vt] show "wf (child s)" .
    qed
    ultimately show False by auto
  qed
qed

text {* (* ddd *)
*}
lemma unique_RAG_p:
  assumes vt: "vt s"
  and dp1: "(n, n1) \<in> (RAG s)^+"
  and dp2: "(n, n2) \<in> (RAG s)^+"
  and neq: "n1 \<noteq> n2"
  shows "(n1, n2) \<in> (RAG s)^+ \<or> (n2, n1) \<in> (RAG s)^+"
proof(rule unique_chain [OF _ dp1 dp2 neq])
  from unique_RAG[OF vt]
  show "\<And>a b c. \<lbrakk>(a, b) \<in> RAG s; (a, c) \<in> RAG s\<rbrakk> \<Longrightarrow> b = c" by auto
qed

text {* (* ddd *)
*}
lemma dependants_child_unique:
  fixes s th th1 th2 th3
  assumes vt: "vt s"
  and ch1: "(Th th1, Th th) \<in> child s"
  and ch2: "(Th th2, Th th) \<in> child s"
  and dp1: "th3 \<in> dependants s th1"
  and dp2: "th3 \<in> dependants s th2"
shows "th1 = th2"
proof -
  { assume neq: "th1 \<noteq> th2"
    from dp1 have dp1: "(Th th3, Th th1) \<in> (RAG s)^+" 
      by (simp add:s_dependants_def eq_RAG)
    from dp2 have dp2: "(Th th3, Th th2) \<in> (RAG s)^+" 
      by (simp add:s_dependants_def eq_RAG)
    from unique_RAG_p[OF vt dp1 dp2] and neq
    have "(Th th1, Th th2) \<in> (RAG s)\<^sup>+ \<or> (Th th2, Th th1) \<in> (RAG s)\<^sup>+" by auto
    hence False
    proof
      assume "(Th th1, Th th2) \<in> (RAG s)\<^sup>+ "
      from children_no_dep[OF vt ch1 ch2 this] show ?thesis .
    next
      assume " (Th th2, Th th1) \<in> (RAG s)\<^sup>+"
      from children_no_dep[OF vt ch2 ch1 this] show ?thesis .
    qed
  } thus ?thesis by auto
qed

lemma RAG_plus_elim:
  assumes "vt s"
  fixes x
  assumes "(Th x, Th th) \<in> (RAG (wq s))\<^sup>+"
  shows "\<exists>th'\<in>children s th. x = th' \<or> (Th x, Th th') \<in> (RAG (wq s))\<^sup>+"
  using assms(2)[unfolded eq_RAG, folded child_RAG_eq[OF `vt s`]]
  apply (unfold children_def)
  by (metis assms(2) children_def RAG_children eq_RAG)

text {* (* ddd *)
*}
lemma dependants_expand:
  assumes "vt s"
  shows "dependants (wq s) th = (children s th) \<union> (\<Union>((dependants (wq s)) ` children s th))"
apply(simp add: image_def)
unfolding cs_dependants_def
apply(auto)
apply (metis assms RAG_plus_elim mem_Collect_eq)
apply (metis child_RAG_p children_def eq_RAG mem_Collect_eq r_into_trancl')
by (metis assms child_RAG_eq children_def eq_RAG mem_Collect_eq trancl.trancl_into_trancl)

lemma finite_children:
  assumes "vt s"
  shows "finite (children s th)"
  using children_dependants dependants_threads[OF assms] finite_threads[OF assms]
  by (metis rev_finite_subset)
  
lemma finite_dependants:
  assumes "vt s"
  shows "finite (dependants (wq s) th')"
  using dependants_threads[OF assms] finite_threads[OF assms]
  by (metis rev_finite_subset)

abbreviation
  "preceds s ths \<equiv> {preced th s| th. th \<in> ths}"

abbreviation
  "cpreceds s ths \<equiv> (cp s) ` ths"

lemma Un_compr:
  "{f th | th. R th \<or> Q th} = ({f th | th. R th} \<union> {f th' | th'. Q th'})"
by auto

lemma in_disj:
  shows "x \<in> A \<or> (\<exists>y \<in> A. x \<in> Q y) \<longleftrightarrow> (\<exists>y \<in> A. x = y \<or> x \<in> Q y)"
by metis

lemma UN_exists:
  shows "(\<Union>x \<in> A. {f y | y. Q y x}) = ({f y | y. (\<exists>x \<in> A. Q y x)})"
by auto

text {* (* ddd *)
  This is the recursive equation used to compute the current precedence of 
  a thread (the @{text "th"}) here. 
*}
lemma cp_rec:
  fixes s th
  assumes vt: "vt s"
  shows "cp s th = Max ({preced th s} \<union> (cp s ` children s th))"
proof(cases "children s th = {}")
  case True
  show ?thesis
    unfolding cp_eq_cpreced cpreced_def 
    by (subst dependants_expand[OF `vt s`]) (simp add: True)
next
  case False
  show ?thesis (is "?LHS = ?RHS")
  proof -
    have eq_cp: "cp s = (\<lambda>th. Max (preceds s ({th} \<union> dependants (wq s) th)))"
      by (simp add: fun_eq_iff cp_eq_cpreced cpreced_def Un_compr image_Collect[symmetric])
  
    have not_emptyness_facts[simp]: 
      "dependants (wq s) th \<noteq> {}" "children s th \<noteq> {}"
      using False dependants_expand[OF assms] by(auto simp only: Un_empty)

    have finiteness_facts[simp]:
      "\<And>th. finite (dependants (wq s) th)" "\<And>th. finite (children s th)"
      by (simp_all add: finite_dependants[OF `vt s`] finite_children[OF `vt s`])

    (* expanding definition *)
    have "?LHS = Max ({preced th s} \<union> preceds s (dependants (wq s) th))"
      unfolding eq_cp by (simp add: Un_compr)
    
    (* moving Max in *)
    also have "\<dots> = max (Max {preced th s}) (Max (preceds s (dependants (wq s) th)))"
      by (simp add: Max_Un)

    (* expanding dependants *)
    also have "\<dots> = max (Max {preced th s}) 
      (Max (preceds s (children s th \<union> \<Union>(dependants (wq s) ` children s th))))"
      by (subst dependants_expand[OF `vt s`]) (simp)

    (* moving out big Union *)
    also have "\<dots> = max (Max {preced th s})
      (Max (preceds s (\<Union> ({children s th} \<union> (dependants (wq s) ` children s th)))))"  
      by simp

    (* moving in small union *)
    also have "\<dots> = max (Max {preced th s})
      (Max (preceds s (\<Union> ((\<lambda>th. {th} \<union> (dependants (wq s) th)) ` children s th))))"  
      by (simp add: in_disj)

    (* moving in preceds *)
    also have "\<dots> = max (Max {preced th s})  
      (Max (\<Union> ((\<lambda>th. preceds s ({th} \<union> (dependants (wq s) th))) ` children s th)))" 
      by (simp add: UN_exists)

    (* moving in Max *)
    also have "\<dots> = max (Max {preced th s})  
      (Max ((\<lambda>th. Max (preceds s ({th} \<union> (dependants (wq s) th)))) ` children s th))" 
      by (subst Max_Union) (auto simp add: image_image)

    (* folding cp + moving out Max *)
    also have "\<dots> = ?RHS" 
      unfolding eq_cp by (simp add: Max_insert)

    finally show "?LHS = ?RHS" .
  qed
qed

lemma next_waiting:
  assumes vt: "vt s"
  and nxt: "next_th s th cs th'"
  shows "waiting s th' cs"
proof -
  from assms show ?thesis
    apply (auto simp:next_th_def s_waiting_def[folded wq_def])
  proof -
    fix rest
    assume ni: "hd (SOME q. distinct q \<and> set q = set rest) \<notin> set rest"
      and eq_wq: "wq s cs = th # rest"
      and ne: "rest \<noteq> []"
    have "set (SOME q. distinct q \<and> set q = set rest) = set rest" 
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      show "\<And>x. distinct x \<and> set x = set rest \<Longrightarrow> set x = set rest" by auto
    qed
    with ni
    have "hd (SOME q. distinct q \<and> set q = set rest) \<notin>  set (SOME q. distinct q \<and> set q = set rest)"
      by simp
    moreover have "(SOME q. distinct q \<and> set q = set rest) \<noteq> []"
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      from ne show "\<And>x. distinct x \<and> set x = set rest \<Longrightarrow> x \<noteq> []" by auto
    qed
    ultimately show "hd (SOME q. distinct q \<and> set q = set rest) = th" by auto
  next
    fix rest
    assume eq_wq: "wq s cs = hd (SOME q. distinct q \<and> set q = set rest) # rest"
      and ne: "rest \<noteq> []"
    have "(SOME q. distinct q \<and> set q = set rest) \<noteq> []"
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      from ne show "\<And>x. distinct x \<and> set x = set rest \<Longrightarrow> x \<noteq> []" by auto
    qed
    hence "hd (SOME q. distinct q \<and> set q = set rest) \<in> set (SOME q. distinct q \<and> set q = set rest)"
      by auto
    moreover have "set (SOME q. distinct q \<and> set q = set rest) = set rest" 
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      show "\<And>x. distinct x \<and> set x = set rest \<Longrightarrow> set x = set rest" by auto
    qed
    ultimately have "hd (SOME q. distinct q \<and> set q = set rest) \<in> set rest" by simp
    with eq_wq and wq_distinct[OF vt, of cs]
    show False by auto
  qed
qed

definition cps:: "state \<Rightarrow> (thread \<times> precedence) set"
where "cps s = {(th, cp s th) | th . th \<in> threads s}"

text {* (* ddd *)
  One beauty of our modelling is that we follow the definitional extension tradition of HOL.
  The benefit of such a concise and miniature model is that  large number of intuitively 
  obvious facts are derived as lemmas, rather than asserted as axioms.
*}

text {*
  However, the lemmas in the forthcoming several locales are no longer 
  obvious. These lemmas show how the current precedences should be recalculated 
  after every execution step (in our model, every step is represented by an event, 
  which in turn, represents a system call, or operation). Each operation is 
  treated in a separate locale.

  The complication of current precedence recalculation comes 
  because the changing of RAG needs to be taken into account, 
  in addition to the changing of precedence. 
  The reason RAG changing affects current precedence is that,
  according to the definition, current precedence 
  of a thread is the maximum of the precedences of its dependants, 
  where the dependants are defined in terms of RAG.

  Therefore, each operation, lemmas concerning the change of the precedences 
  and RAG are derived first, so that the lemmas about
  current precedence recalculation can be based on.
*}

text {* (* ddd *)
  The following locale @{text "step_set_cps"} investigates the recalculation 
  after the @{text "Set"} operation.
*}
locale step_set_cps =
  fixes s' th prio s 
  -- {* @{text "s'"} is the system state before the operation *}
  -- {* @{text "s"} is the system state after the operation *}
  defines s_def : "s \<equiv> (Set th prio#s')" 
  -- {* @{text "s"} is assumed to be a legitimate state, from which
         the legitimacy of @{text "s"} can be derived. *}
  assumes vt_s: "vt s"

context step_set_cps 
begin

text {* (* ddd *)
  The following lemma confirms that @{text "Set"}-operating only changes the precedence 
  of initiating thread.
*}

lemma eq_preced:
  fixes th'
  assumes "th' \<noteq> th"
  shows "preced th' s = preced th' s'"
proof -
  from assms show ?thesis 
    by (unfold s_def, auto simp:preced_def)
qed

text {* (* ddd *)
  The following lemma assures that the resetting of priority does not change the RAG. 
*}

lemma eq_dep: "RAG s = RAG s'"
  by (unfold s_def RAG_set_unchanged, auto)

text {*
  Th following lemma @{text "eq_cp_pre"} circumscribe a rough range of recalculation.
  It says, thread other than the initiating thread @{text "th"} does not need recalculation
  unless it lies upstream of @{text "th"} in the RAG. 

  The reason behind this lemma is that: 
  the change of precedence of one thread can only affect it's upstream threads, according to 
  lemma @{text "eq_preced"}. Since the only thread which might change precedence is
  @{text "th"}, so only @{text "th"} and its upstream threads need recalculation.
  (* ccc *)
*}

lemma eq_cp_pre:
  fixes th' 
  assumes neq_th: "th' \<noteq> th"
  and nd: "th \<notin> dependants s th'"
  shows "cp s th' = cp s' th'"
proof -
  -- {* This is what we need to prove after expanding the definition of @{text "cp"} *}
  have "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))"
   (is "Max (?f1 ` ({th'} \<union> ?A)) = Max (?f2 ` ({th'} \<union> ?B))") 
  proof -
      -- {* Since RAG is not changed by @{text "Set"}-operation, the dependants of 
            any threads are not changed, this is one of key facts underpinning this 
            lemma *}
      have eq_ab: "?A = ?B" by (unfold cs_dependants_def, auto simp:eq_dep eq_RAG)
      have "(?f1 ` ({th'} \<union> ?A)) =  (?f2 ` ({th'} \<union> ?B))"
      proof(rule image_cong)
        show "{th'} \<union> ?A = {th'} \<union> ?B" by (simp only:eq_ab)
      next  
        fix x
        assume x_in: "x \<in> {th'} \<union> ?B"
        show "?f1 x = ?f2 x"
        proof(rule eq_preced) -- {* The other key fact underpinning this lemma is @{text "eq_preced"} *}
          from x_in[folded eq_ab, unfolded eq_dependants]
          have "x \<in> {th'} \<union> dependants s th'" .
          thus "x \<noteq> th"
          proof
            assume "x \<in> {th'}" 
            with `th' \<noteq> th` show ?thesis by simp
          next
            assume "x \<in> dependants s th'"
            with `th \<notin> dependants s th'` show ?thesis by auto
          qed 
        qed 
      qed
      thus ?thesis by simp
  qed 
  thus ?thesis by (unfold cp_eq_cpreced cpreced_def)
qed

text {*
  The following lemma shows that no thread lies upstream of the initiating thread @{text "th"}. 
  The reason for this is that only no-blocked thread can initiate 
  a system call. Since thread @{text "th"} is non-blocked, it is not waiting for any 
  critical resource. Therefore, there is edge leading out of @{text "th"} in the RAG.
  Consequently, there is no node (neither resource nor thread) upstream of @{text "th"}.
*}
lemma no_dependants:
  shows "th \<notin> dependants s th'"
proof
  assume "th \<in> dependants s th'"
  from `th \<in> dependants s th'` have "(Th th, Th th') \<in> (RAG s')\<^sup>+"
    by (unfold s_dependants_def, unfold eq_RAG, unfold eq_dep, auto)
  from tranclD[OF this]
  obtain z where "(Th th, z) \<in> RAG s'" by auto
  moreover have "th \<in> readys s'"
  proof -
    from step_back_step [OF vt_s[unfolded s_def]]
    have "step s' (Set th prio)" .
    hence "th \<in> runing s'" by (cases, simp)
    thus ?thesis by (simp add:readys_def runing_def)
  qed
  ultimately show "False"
    apply (case_tac z, auto simp:readys_def s_RAG_def s_waiting_def cs_waiting_def)
    by (fold wq_def, blast)
qed

(* Result improved *)
text {* 
  A simple combination of @{text "eq_cp_pre"} and @{text "no_dependants"}
  gives the main lemma of this locale, which shows that
  only the initiating thread needs a recalculation of current precedence.
*}
lemma eq_cp:
  fixes th' 
  assumes "th' \<noteq> th"
  shows "cp s th' = cp s' th'"
  by (rule eq_cp_pre[OF assms no_dependants])


text {* (* ddd *) \noindent
   The following @{text "eq_up"} was originally designed to save the recalculations
   of current precedence going upstream from thread @{text "th"} can stop earlier. 
   If at a certain point along way, the recalculation results in the same
   result, the recalculation can stop there. 
   This lemma is obsolete because we found that @{text "th"} is not contained in 
   any thread's dependants set. 

   The foregoing lemma says only those threads which 
*}
lemma eq_up:
  fixes th' th''
  assumes dp1: "th \<in> dependants s th'"
  and dp2: "th' \<in> dependants s th''"
  and eq_cps: "cp s th' = cp s' th'"
  shows "cp s th'' = cp s' th''"
proof -
  from dp2
  have "(Th th', Th th'') \<in> (RAG (wq s))\<^sup>+" by (simp add:s_dependants_def)
  from RAG_child[OF vt_s this[unfolded eq_RAG]]
  have ch_th': "(Th th', Th th'') \<in> (child s)\<^sup>+" .
  moreover { fix n th''
    have "\<lbrakk>(Th th', n) \<in> (child s)^+\<rbrakk> \<Longrightarrow>
                   (\<forall> th'' . n = Th th'' \<longrightarrow> cp s th'' = cp s' th'')"
    proof(erule trancl_induct, auto)
      fix y th''
      assume y_ch: "(y, Th th'') \<in> child s"
        and ih: "\<forall>th''. y = Th th'' \<longrightarrow> cp s th'' = cp s' th''"
        and ch': "(Th th', y) \<in> (child s)\<^sup>+"
      from y_ch obtain thy where eq_y: "y = Th thy" by (auto simp:child_def)
      with ih have eq_cpy:"cp s thy = cp s' thy" by blast
      from dp1 have "(Th th, Th th') \<in> (RAG s)^+" by (auto simp:s_dependants_def eq_RAG)
      moreover from child_RAG_p[OF ch'] and eq_y
      have "(Th th', Th thy) \<in> (RAG s)^+" by simp
      ultimately have dp_thy: "(Th th, Th thy) \<in> (RAG s)^+" by auto
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
        proof(rule eq_preced)
          show "th'' \<noteq> th"
          proof
            assume "th'' = th"
            with dp_thy y_ch[unfolded eq_y] 
            have "(Th th, Th th) \<in> (RAG s)^+"
              by (auto simp:child_def)
            with wf_trancl[OF wf_RAG[OF vt_s]] 
            show False by auto
          qed
        qed
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = thy")
            case True
            with eq_cpy show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp_thy have "(Th th1, Th thy) \<in> (RAG s)^+" by simp
              from children_no_dep[OF vt_s _ _ this] and 
              th1_in y_ch eq_y show False by (auto simp:children_def)
            qed
            have "th \<notin> dependants s th1"
            proof
              assume h:"th \<in> dependants s th1"
              from eq_y dp_thy have "th \<in> dependants s thy" by (auto simp:s_dependants_def eq_RAG)
              from dependants_child_unique[OF vt_s _ _ h this]
              th1_in y_ch eq_y have "th1 = thy" by (auto simp:children_def child_def)
              with False show False by auto
            qed
            from eq_cp_pre[OF neq_th1 this]
            show ?thesis .
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          by (unfold children_def child_def s_def RAG_set_unchanged, simp)
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed
    next
      fix th''
      assume dp': "(Th th', Th th'') \<in> child s"
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
        proof(rule eq_preced)
          show "th'' \<noteq> th"
          proof
            assume "th'' = th"
            with dp1 dp'
            have "(Th th, Th th) \<in> (RAG s)^+"
              by (auto simp:child_def s_dependants_def eq_RAG)
            with wf_trancl[OF wf_RAG[OF vt_s]] 
            show False by auto
          qed
        qed
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = th'")
            case True
            with eq_cps show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp1 have "(Th th1, Th th') \<in> (RAG s)^+" 
                by (auto simp:s_dependants_def eq_RAG)
              from children_no_dep[OF vt_s _ _ this]
              th1_in dp'
              show False by (auto simp:children_def)
            qed
            thus ?thesis
            proof(rule eq_cp_pre)
              show "th \<notin> dependants s th1"
              proof
                assume "th \<in> dependants s th1"
                from dependants_child_unique[OF vt_s _ _ this dp1]
                th1_in dp' have "th1 = th'"
                  by (auto simp:children_def)
                with False show False by auto
              qed
            qed
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          by (unfold children_def child_def s_def RAG_set_unchanged, simp)
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed     
    qed
  }
  ultimately show ?thesis by auto
qed

text {* (* ddd *)
  For those @{text "th''"},  @{text "th \<in> dependants s th''"} means that 
  the current precedence of such @{text "th''"} might possibly be boosted if the 
  current precedence of @{text "th"} somehow get raised. The following lemma
  says that if the resetting of its own priority by thread @{text "th"} does not
  change its current precedence, then the current precedence of such @{text "th''"}
  will remain unchanged. The situation such that @{text "th"}'s current 
  precedence does not change with the resetting of its priority might happen in many
  different cases. For example, if the current precedence of @{text "th"} is already an inherited one,
  the lowering of its priority will not change its current precedence, and the increasing 
  of its priority will not change its current precedence neither, if 
  incidental rising of its own precedence is not large enough to surpass the inherited precedence. 
*}

lemma eq_up_self:
  fixes th' th''
  assumes dp: "th \<in> dependants s th''"
  and eq_cps: "cp s th = cp s' th"
  shows "cp s th'' = cp s' th''"
proof -
  from dp
  have "(Th th, Th th'') \<in> (RAG (wq s))\<^sup>+" by (simp add:s_dependants_def)
  from RAG_child[OF vt_s this[unfolded eq_RAG]]
  have ch_th': "(Th th, Th th'') \<in> (child s)\<^sup>+" .
  moreover { fix n th''
    have "\<lbrakk>(Th th, n) \<in> (child s)^+\<rbrakk> \<Longrightarrow>
                   (\<forall> th'' . n = Th th'' \<longrightarrow> cp s th'' = cp s' th'')"
    proof(erule trancl_induct, auto)
      fix y th''
      assume y_ch: "(y, Th th'') \<in> child s"
        and ih: "\<forall>th''. y = Th th'' \<longrightarrow> cp s th'' = cp s' th''"
        and ch': "(Th th, y) \<in> (child s)\<^sup>+"
      from y_ch obtain thy where eq_y: "y = Th thy" by (auto simp:child_def)
      with ih have eq_cpy:"cp s thy = cp s' thy" by blast
      from child_RAG_p[OF ch'] and eq_y
      have dp_thy: "(Th th, Th thy) \<in> (RAG s)^+" by simp
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
        proof(rule eq_preced)
          show "th'' \<noteq> th"
          proof
            assume "th'' = th"
            with dp_thy y_ch[unfolded eq_y] 
            have "(Th th, Th th) \<in> (RAG s)^+"
              by (auto simp:child_def)
            with wf_trancl[OF wf_RAG[OF vt_s]] 
            show False by auto
          qed
        qed
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = thy")
            case True
            with eq_cpy show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp_thy have "(Th th1, Th thy) \<in> (RAG s)^+" by simp
              from children_no_dep[OF vt_s _ _ this] and 
              th1_in y_ch eq_y show False by (auto simp:children_def)
            qed
            have "th \<notin> dependants s th1"
            proof
              assume h:"th \<in> dependants s th1"
              from eq_y dp_thy have "th \<in> dependants s thy" by (auto simp:s_dependants_def eq_RAG)
              from dependants_child_unique[OF vt_s _ _ h this]
              th1_in y_ch eq_y have "th1 = thy" by (auto simp:children_def child_def)
              with False show False by auto
            qed
            from eq_cp_pre[OF neq_th1 this]
            show ?thesis .
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          by (unfold children_def child_def s_def RAG_set_unchanged, simp)
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed
    next
      fix th''
      assume dp': "(Th th, Th th'') \<in> child s"
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
        proof(rule eq_preced)
          show "th'' \<noteq> th"
          proof
            assume "th'' = th"
            with dp dp'
            have "(Th th, Th th) \<in> (RAG s)^+"
              by (auto simp:child_def s_dependants_def eq_RAG)
            with wf_trancl[OF wf_RAG[OF vt_s]] 
            show False by auto
          qed
        qed
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = th")
            case True
            with eq_cps show ?thesis by simp
          next
            case False
            assume neq_th1: "th1 \<noteq> th"
            thus ?thesis
            proof(rule eq_cp_pre)
              show "th \<notin> dependants s th1"
              proof
                assume "th \<in> dependants s th1"
                hence "(Th th, Th th1) \<in> (RAG s)^+" by (auto simp:s_dependants_def eq_RAG)
                from children_no_dep[OF vt_s _ _ this]
                and th1_in dp' show False
                  by (auto simp:children_def)
              qed
            qed
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          by (unfold children_def child_def s_def RAG_set_unchanged, simp)
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed     
    qed
  }
  ultimately show ?thesis by auto
qed
end

locale step_v_cps =
  fixes s' th cs s 
  defines s_def : "s \<equiv> (V th cs#s')"
  assumes vt_s: "vt s"

locale step_v_cps_nt = step_v_cps +
  fixes th'
  assumes nt: "next_th s' th cs th'"

context step_v_cps_nt
begin

lemma RAG_s:
  "RAG s = (RAG s' - {(Cs cs, Th th), (Th th', Cs cs)}) \<union>
                                         {(Cs cs, Th th')}"
proof -
  from step_RAG_v[OF vt_s[unfolded s_def], folded s_def]
    and nt show ?thesis  by (auto intro:next_th_unique)
qed

lemma dependants_kept:
  fixes th''
  assumes neq1: "th'' \<noteq> th"
  and neq2: "th'' \<noteq> th'"
  shows "dependants (wq s) th'' = dependants (wq s') th''"
proof(auto)
  fix x
  assume "x \<in> dependants (wq s) th''"
  hence dp: "(Th x, Th th'') \<in> (RAG s)^+"
    by (auto simp:cs_dependants_def eq_RAG)
  { fix n
    have "(n, Th th'') \<in> (RAG s)^+ \<Longrightarrow>  (n, Th th'') \<in> (RAG s')^+"
    proof(induct rule:converse_trancl_induct)
      fix y 
      assume "(y, Th th'') \<in> RAG s"
      with RAG_s neq1 neq2
      have "(y, Th th'') \<in> RAG s'" by auto
      thus "(y, Th th'') \<in> (RAG s')\<^sup>+" by auto
    next
      fix y z 
      assume yz: "(y, z) \<in> RAG s"
        and ztp: "(z, Th th'') \<in> (RAG s)\<^sup>+"
        and ztp': "(z, Th th'') \<in> (RAG s')\<^sup>+"
      have "y \<noteq> Cs cs \<and> y \<noteq> Th th'"
      proof
        show "y \<noteq> Cs cs"
        proof
          assume eq_y: "y = Cs cs"
          with yz have dp_yz: "(Cs cs, z) \<in> RAG s" by simp
          from RAG_s
          have cst': "(Cs cs, Th th') \<in> RAG s" by simp
          from unique_RAG[OF vt_s this dp_yz] 
          have eq_z: "z = Th th'" by simp
          with ztp have "(Th th', Th th'') \<in> (RAG s)^+" by simp
          from converse_tranclE[OF this]
          obtain cs' where dp'': "(Th th', Cs cs') \<in> RAG s"
            by (auto simp:s_RAG_def)
          with RAG_s have dp': "(Th th', Cs cs') \<in> RAG s'" by auto
          from dp'' eq_y yz eq_z have "(Cs cs, Cs cs') \<in> (RAG s)^+" by auto
          moreover have "cs' = cs"
          proof -
            from next_waiting[OF step_back_vt[OF vt_s[unfolded s_def]] nt]
            have "(Th th', Cs cs) \<in> RAG s'"
              by (auto simp:s_waiting_def wq_def s_RAG_def cs_waiting_def)
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] this dp']
            show ?thesis by simp
          qed
          ultimately have "(Cs cs, Cs cs) \<in> (RAG s)^+" by simp
          moreover note wf_trancl[OF wf_RAG[OF vt_s]]
          ultimately show False by auto
        qed
      next
        show "y \<noteq> Th th'"
        proof
          assume eq_y: "y = Th th'"
          with yz have dps: "(Th th', z) \<in> RAG s" by simp
          with RAG_s have dps': "(Th th', z) \<in> RAG s'" by auto
          have "z = Cs cs"
          proof -
            from next_waiting[OF step_back_vt[OF vt_s[unfolded s_def]] nt]
            have "(Th th', Cs cs) \<in> RAG s'"
              by (auto simp:s_waiting_def wq_def s_RAG_def cs_waiting_def)
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] dps' this]
            show ?thesis .
          qed
          with dps RAG_s show False by auto
        qed
      qed
      with RAG_s yz have "(y, z) \<in> RAG s'" by auto
      with ztp'
      show "(y, Th th'') \<in> (RAG s')\<^sup>+" by auto
    qed    
  }
  from this[OF dp]
  show "x \<in> dependants (wq s') th''" 
    by (auto simp:cs_dependants_def eq_RAG)
next
  fix x
  assume "x \<in> dependants (wq s') th''"
  hence dp: "(Th x, Th th'') \<in> (RAG s')^+"
    by (auto simp:cs_dependants_def eq_RAG)
  { fix n
    have "(n, Th th'') \<in> (RAG s')^+ \<Longrightarrow>  (n, Th th'') \<in> (RAG s)^+"
    proof(induct rule:converse_trancl_induct)
      fix y 
      assume "(y, Th th'') \<in> RAG s'"
      with RAG_s neq1 neq2
      have "(y, Th th'') \<in> RAG s" by auto
      thus "(y, Th th'') \<in> (RAG s)\<^sup>+" by auto
    next
      fix y z 
      assume yz: "(y, z) \<in> RAG s'"
        and ztp: "(z, Th th'') \<in> (RAG s')\<^sup>+"
        and ztp': "(z, Th th'') \<in> (RAG s)\<^sup>+"
      have "y \<noteq> Cs cs \<and> y \<noteq> Th th'"
      proof
        show "y \<noteq> Cs cs"
        proof
          assume eq_y: "y = Cs cs"
          with yz have dp_yz: "(Cs cs, z) \<in> RAG s'" by simp
          from this have eq_z: "z = Th th"
          proof -
            from step_back_step[OF vt_s[unfolded s_def]]
            have "(Cs cs, Th th) \<in> RAG s'"
              by(cases, auto simp: wq_def s_RAG_def cs_holding_def s_holding_def)
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] this dp_yz]
            show ?thesis by simp
          qed
          from converse_tranclE[OF ztp]
          obtain u where "(z, u) \<in> RAG s'" by auto
          moreover 
          from step_back_step[OF vt_s[unfolded s_def]]
          have "th \<in> readys s'" by (cases, simp add:runing_def)
          moreover note eq_z
          ultimately show False 
            by (auto simp:readys_def wq_def s_RAG_def s_waiting_def cs_waiting_def)
        qed
      next
        show "y \<noteq> Th th'"
        proof
          assume eq_y: "y = Th th'"
          with yz have dps: "(Th th', z) \<in> RAG s'" by simp
          have "z = Cs cs"
          proof -
            from next_waiting[OF step_back_vt[OF vt_s[unfolded s_def]] nt]
            have "(Th th', Cs cs) \<in> RAG s'"
              by (auto simp:s_waiting_def wq_def s_RAG_def cs_waiting_def)
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] dps this]
            show ?thesis .
          qed
          with ztp have cs_i: "(Cs cs, Th th'') \<in>  (RAG s')\<^sup>+" by simp
          from step_back_step[OF vt_s[unfolded s_def]]
          have cs_th: "(Cs cs, Th th) \<in> RAG s'"
            by(cases, auto simp: s_RAG_def wq_def cs_holding_def s_holding_def)
          have "(Cs cs, Th th'') \<notin>  RAG s'"
          proof
            assume "(Cs cs, Th th'') \<in> RAG s'"
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] this cs_th]
            and neq1 show "False" by simp
          qed
          with converse_tranclE[OF cs_i]
          obtain u where cu: "(Cs cs, u) \<in> RAG s'"  
            and u_t: "(u, Th th'') \<in> (RAG s')\<^sup>+" by auto
          have "u = Th th"
          proof -
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] cu cs_th]
            show ?thesis .
          qed
          with u_t have "(Th th, Th th'') \<in> (RAG s')\<^sup>+" by simp
          from converse_tranclE[OF this]
          obtain v where "(Th th, v) \<in> (RAG s')" by auto
          moreover from step_back_step[OF vt_s[unfolded s_def]]
          have "th \<in> readys s'" by (cases, simp add:runing_def)
          ultimately show False 
            by (auto simp:readys_def wq_def s_RAG_def s_waiting_def cs_waiting_def)
        qed
      qed
      with RAG_s yz have "(y, z) \<in> RAG s" by auto
      with ztp'
      show "(y, Th th'') \<in> (RAG s)\<^sup>+" by auto
    qed    
  }
  from this[OF dp]
  show "x \<in> dependants (wq s) th''"
    by (auto simp:cs_dependants_def eq_RAG)
qed

lemma cp_kept:
  fixes th''
  assumes neq1: "th'' \<noteq> th"
  and neq2: "th'' \<noteq> th'"
  shows "cp s th'' = cp s' th''"
proof -
  from dependants_kept[OF neq1 neq2]
  have "dependants (wq s) th'' = dependants (wq s') th''" .
  moreover {
    fix th1
    assume "th1 \<in> dependants (wq s) th''"
    have "preced th1 s = preced th1 s'" 
      by (unfold s_def, auto simp:preced_def)
  }
  moreover have "preced th'' s = preced th'' s'" 
    by (unfold s_def, auto simp:preced_def)
  ultimately have "((\<lambda>th. preced th s) ` ({th''} \<union> dependants (wq s) th'')) = 
    ((\<lambda>th. preced th s') ` ({th''} \<union> dependants (wq s') th''))"
    by (auto simp:image_def)
  thus ?thesis
    by (unfold cp_eq_cpreced cpreced_def, simp)
qed

end

locale step_v_cps_nnt = step_v_cps +
  assumes nnt: "\<And> th'. (\<not> next_th s' th cs th')"

context step_v_cps_nnt
begin

lemma nw_cs: "(Th th1, Cs cs) \<notin> RAG s'"
proof
  assume "(Th th1, Cs cs) \<in> RAG s'"
  thus "False"
    apply (auto simp:s_RAG_def cs_waiting_def)
  proof -
    assume h1: "th1 \<in> set (wq s' cs)"
      and h2: "th1 \<noteq> hd (wq s' cs)"
    from step_back_step[OF vt_s[unfolded s_def]]
    show "False"
    proof(cases)
      assume "holding s' th cs" 
      then obtain rest where
        eq_wq: "wq s' cs = th#rest"
        apply (unfold s_holding_def wq_def[symmetric])
        by (case_tac "(wq s' cs)", auto)
      with h1 h2 have ne: "rest \<noteq> []" by auto
      with eq_wq
      have "next_th s' th cs (hd (SOME q. distinct q \<and> set q = set rest))"
        by(unfold next_th_def, rule_tac x = "rest" in exI, auto)
      with nnt show ?thesis by auto
    qed
  qed
qed

lemma RAG_s: "RAG s = RAG s' - {(Cs cs, Th th)}"
proof -
  from nnt and  step_RAG_v[OF vt_s[unfolded s_def], folded s_def]
  show ?thesis by auto
qed

lemma child_kept_left:
  assumes 
  "(n1, n2) \<in> (child s')^+"
  shows "(n1, n2) \<in> (child s)^+"
proof -
  from assms show ?thesis 
  proof(induct rule: converse_trancl_induct)
    case (base y)
    from base obtain th1 cs1 th2
      where h1: "(Th th1, Cs cs1) \<in> RAG s'"
      and h2: "(Cs cs1, Th th2) \<in> RAG s'"
      and eq_y: "y = Th th1" and eq_n2: "n2 = Th th2"  by (auto simp:child_def)
    have "cs1 \<noteq> cs"
    proof
      assume eq_cs: "cs1 = cs"
      with h1 have "(Th th1, Cs cs1) \<in> RAG s'" by simp
      with nw_cs eq_cs show False by auto
    qed
    with h1 h2 RAG_s have 
      h1': "(Th th1, Cs cs1) \<in> RAG s" and
      h2': "(Cs cs1, Th th2) \<in> RAG s" by auto
    hence "(Th th1, Th th2) \<in> child s" by (auto simp:child_def)
    with eq_y eq_n2 have "(y, n2) \<in> child s" by simp
    thus ?case by auto
  next
    case (step y z)
    have "(y, z) \<in> child s'" by fact
    then obtain th1 cs1 th2
      where h1: "(Th th1, Cs cs1) \<in> RAG s'"
      and h2: "(Cs cs1, Th th2) \<in> RAG s'"
      and eq_y: "y = Th th1" and eq_z: "z = Th th2"  by (auto simp:child_def)
    have "cs1 \<noteq> cs"
    proof
      assume eq_cs: "cs1 = cs"
      with h1 have "(Th th1, Cs cs1) \<in> RAG s'" by simp
      with nw_cs eq_cs show False by auto
    qed
    with h1 h2 RAG_s have 
      h1': "(Th th1, Cs cs1) \<in> RAG s" and
      h2': "(Cs cs1, Th th2) \<in> RAG s" by auto
    hence "(Th th1, Th th2) \<in> child s" by (auto simp:child_def)
    with eq_y eq_z have "(y, z) \<in> child s" by simp
    moreover have "(z, n2) \<in> (child s)^+" by fact
    ultimately show ?case by auto
  qed
qed

lemma  child_kept_right:
  assumes
  "(n1, n2) \<in> (child s)^+"
  shows "(n1, n2) \<in> (child s')^+"
proof -
  from assms show ?thesis
  proof(induct)
    case (base y)
    from base and RAG_s 
    have "(n1, y) \<in> child s'"
      by (auto simp:child_def)
    thus ?case by auto
  next
    case (step y z)
    have "(y, z) \<in> child s" by fact
    with RAG_s have "(y, z) \<in> child s'"
      by (auto simp:child_def)
    moreover have "(n1, y) \<in> (child s')\<^sup>+" by fact
    ultimately show ?case by auto
  qed
qed

lemma eq_child: "(child s)^+ = (child s')^+"
  by (insert child_kept_left child_kept_right, auto)

lemma eq_cp:
  fixes th' 
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    apply (unfold cs_dependants_def, unfold eq_RAG)
  proof -
    from eq_child
    have "\<And>th. {th'. (Th th', Th th) \<in> (child s)\<^sup>+} = {th'. (Th th', Th th) \<in> (child s')\<^sup>+}"
      by simp
    with child_RAG_eq[OF vt_s] child_RAG_eq[OF step_back_vt[OF vt_s[unfolded s_def]]]
    show "\<And>th. {th'. (Th th', Th th) \<in> (RAG s)\<^sup>+} = {th'. (Th th', Th th) \<in> (RAG s')\<^sup>+}"
      by simp
  qed
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      show "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
    next
      assume "th1 \<in> dependants (wq s') th'"
      show "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

end

locale step_P_cps =
  fixes s' th cs s 
  defines s_def : "s \<equiv> (P th cs#s')"
  assumes vt_s: "vt s"

locale step_P_cps_ne =step_P_cps +
  assumes ne: "wq s' cs \<noteq> []"

locale step_P_cps_e =step_P_cps +
  assumes ee: "wq s' cs = []"

context step_P_cps_e
begin

lemma RAG_s: "RAG s = RAG s' \<union> {(Cs cs, Th th)}"
proof -
  from ee and  step_RAG_p[OF vt_s[unfolded s_def], folded s_def]
  show ?thesis by auto
qed

lemma child_kept_left:
  assumes 
  "(n1, n2) \<in> (child s')^+"
  shows "(n1, n2) \<in> (child s)^+"
proof -
  from assms show ?thesis 
  proof(induct rule: converse_trancl_induct)
    case (base y)
    from base obtain th1 cs1 th2
      where h1: "(Th th1, Cs cs1) \<in> RAG s'"
      and h2: "(Cs cs1, Th th2) \<in> RAG s'"
      and eq_y: "y = Th th1" and eq_n2: "n2 = Th th2"  by (auto simp:child_def)
    have "cs1 \<noteq> cs"
    proof
      assume eq_cs: "cs1 = cs"
      with h1 have "(Th th1, Cs cs) \<in> RAG s'" by simp
      with ee show False
        by (auto simp:s_RAG_def cs_waiting_def)
    qed
    with h1 h2 RAG_s have 
      h1': "(Th th1, Cs cs1) \<in> RAG s" and
      h2': "(Cs cs1, Th th2) \<in> RAG s" by auto
    hence "(Th th1, Th th2) \<in> child s" by (auto simp:child_def)
    with eq_y eq_n2 have "(y, n2) \<in> child s" by simp
    thus ?case by auto
  next
    case (step y z)
    have "(y, z) \<in> child s'" by fact
    then obtain th1 cs1 th2
      where h1: "(Th th1, Cs cs1) \<in> RAG s'"
      and h2: "(Cs cs1, Th th2) \<in> RAG s'"
      and eq_y: "y = Th th1" and eq_z: "z = Th th2"  by (auto simp:child_def)
    have "cs1 \<noteq> cs"
    proof
      assume eq_cs: "cs1 = cs"
      with h1 have "(Th th1, Cs cs) \<in> RAG s'" by simp
      with ee show False 
        by (auto simp:s_RAG_def cs_waiting_def)
    qed
    with h1 h2 RAG_s have 
      h1': "(Th th1, Cs cs1) \<in> RAG s" and
      h2': "(Cs cs1, Th th2) \<in> RAG s" by auto
    hence "(Th th1, Th th2) \<in> child s" by (auto simp:child_def)
    with eq_y eq_z have "(y, z) \<in> child s" by simp
    moreover have "(z, n2) \<in> (child s)^+" by fact
    ultimately show ?case by auto
  qed
qed

lemma  child_kept_right:
  assumes
  "(n1, n2) \<in> (child s)^+"
  shows "(n1, n2) \<in> (child s')^+"
proof -
  from assms show ?thesis
  proof(induct)
    case (base y)
    from base and RAG_s
    have "(n1, y) \<in> child s'"
      apply (auto simp:child_def)
      proof -
        fix th'
        assume "(Th th', Cs cs) \<in> RAG s'"
        with ee have "False"
          by (auto simp:s_RAG_def cs_waiting_def)
        thus "\<exists>cs. (Th th', Cs cs) \<in> RAG s' \<and> (Cs cs, Th th) \<in> RAG s'" by auto 
      qed
    thus ?case by auto
  next
    case (step y z)
    have "(y, z) \<in> child s" by fact
    with RAG_s have "(y, z) \<in> child s'"
      apply (auto simp:child_def)
      proof -
        fix th'
        assume "(Th th', Cs cs) \<in> RAG s'"
        with ee have "False"
          by (auto simp:s_RAG_def cs_waiting_def)
        thus "\<exists>cs. (Th th', Cs cs) \<in> RAG s' \<and> (Cs cs, Th th) \<in> RAG s'" by auto 
      qed
    moreover have "(n1, y) \<in> (child s')\<^sup>+" by fact
    ultimately show ?case by auto
  qed
qed

lemma eq_child: "(child s)^+ = (child s')^+"
  by (insert child_kept_left child_kept_right, auto)

lemma eq_cp:
  fixes th' 
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    apply (unfold cs_dependants_def, unfold eq_RAG)
  proof -
    from eq_child
    have "\<And>th. {th'. (Th th', Th th) \<in> (child s)\<^sup>+} = {th'. (Th th', Th th) \<in> (child s')\<^sup>+}"
      by auto
    with child_RAG_eq[OF vt_s] child_RAG_eq[OF step_back_vt[OF vt_s[unfolded s_def]]]
    show "\<And>th. {th'. (Th th', Th th) \<in> (RAG s)\<^sup>+} = {th'. (Th th', Th th) \<in> (RAG s')\<^sup>+}"
      by simp
  qed
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      show "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
    next
      assume "th1 \<in> dependants (wq s') th'"
      show "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

end

context step_P_cps_ne
begin

lemma RAG_s: "RAG s = RAG s' \<union> {(Th th, Cs cs)}"
proof -
  from step_RAG_p[OF vt_s[unfolded s_def]] and ne
  show ?thesis by (simp add:s_def)
qed

lemma eq_child_left:
  assumes nd: "(Th th, Th th') \<notin> (child s)^+"
  shows "(n1, Th th') \<in> (child s)^+ \<Longrightarrow> (n1, Th th') \<in> (child s')^+"
proof(induct rule:converse_trancl_induct)
  case (base y)
  from base obtain th1 cs1
    where h1: "(Th th1, Cs cs1) \<in> RAG s"
    and h2: "(Cs cs1, Th th') \<in> RAG s"
    and eq_y: "y = Th th1"   by (auto simp:child_def)
  have "th1 \<noteq> th"
  proof
    assume "th1 = th"
    with base eq_y have "(Th th, Th th') \<in> child s" by simp
    with nd show False by auto
  qed
  with h1 h2 RAG_s 
  have h1': "(Th th1, Cs cs1) \<in> RAG s'" and 
       h2': "(Cs cs1, Th th') \<in> RAG s'" by auto
  with eq_y show ?case by (auto simp:child_def)
next
  case (step y z)
  have yz: "(y, z) \<in> child s" by fact
  then obtain th1 cs1 th2
    where h1: "(Th th1, Cs cs1) \<in> RAG s"
    and h2: "(Cs cs1, Th th2) \<in> RAG s"
    and eq_y: "y = Th th1" and eq_z: "z = Th th2"  by (auto simp:child_def)
  have "th1 \<noteq> th"
  proof
    assume "th1 = th"
    with yz eq_y have "(Th th, z) \<in> child s" by simp
    moreover have "(z, Th th') \<in> (child s)^+" by fact
    ultimately have "(Th th, Th th') \<in> (child s)^+" by auto
    with nd show False by auto
  qed
  with h1 h2 RAG_s have h1': "(Th th1, Cs cs1) \<in> RAG s'"
                       and h2': "(Cs cs1, Th th2) \<in> RAG s'" by auto
  with eq_y eq_z have "(y, z) \<in> child s'" by (auto simp:child_def)
  moreover have "(z, Th th') \<in> (child s')^+" by fact
  ultimately show ?case by auto
qed

lemma eq_child_right:
  shows "(n1, Th th') \<in> (child s')^+ \<Longrightarrow> (n1, Th th') \<in> (child s)^+"
proof(induct rule:converse_trancl_induct)
  case (base y)
  with RAG_s show ?case by (auto simp:child_def)
next
  case (step y z)
  have "(y, z) \<in> child s'" by fact
  with RAG_s have "(y, z) \<in> child s" by (auto simp:child_def)
  moreover have "(z, Th th') \<in> (child s)^+" by fact
  ultimately show ?case by auto
qed

lemma eq_child:
  assumes nd: "(Th th, Th th') \<notin> (child s)^+"
  shows "((n1, Th th') \<in> (child s)^+) = ((n1, Th th') \<in> (child s')^+)"
  by (insert eq_child_left[OF nd] eq_child_right, auto)

lemma eq_cp:
  fixes th' 
  assumes nd: "th \<notin> dependants s th'"
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have nd': "(Th th, Th th') \<notin> (child s)^+"
  proof
    assume "(Th th, Th th') \<in> (child s)\<^sup>+"
    with child_RAG_eq[OF vt_s]
    have "(Th th, Th th') \<in> (RAG s)\<^sup>+" by simp
    with nd show False 
      by (simp add:s_dependants_def eq_RAG)
  qed
  have eq_dp: "dependants (wq s) th' = dependants (wq s') th'"
  proof(auto)
    fix x assume " x \<in> dependants (wq s) th'"
    thus "x \<in> dependants (wq s') th'"
      apply (auto simp:cs_dependants_def eq_RAG)
    proof -
      assume "(Th x, Th th') \<in> (RAG s)\<^sup>+"
      with  child_RAG_eq[OF vt_s] have "(Th x, Th th') \<in> (child s)\<^sup>+" by simp
      with eq_child[OF nd'] have "(Th x, Th th') \<in> (child s')^+" by simp
      with child_RAG_eq[OF step_back_vt[OF vt_s[unfolded s_def]]]
      show "(Th x, Th th') \<in> (RAG s')\<^sup>+" by simp
    qed
  next
    fix x assume "x \<in> dependants (wq s') th'"
    thus "x \<in> dependants (wq s) th'"
      apply (auto simp:cs_dependants_def eq_RAG)
    proof -
      assume "(Th x, Th th') \<in> (RAG s')\<^sup>+"
      with child_RAG_eq[OF step_back_vt[OF vt_s[unfolded s_def]]] 
      have "(Th x, Th th') \<in> (child s')\<^sup>+" by simp
      with eq_child[OF nd'] have "(Th x, Th th') \<in> (child s)^+" by simp
      with  child_RAG_eq[OF vt_s]
      show "(Th x, Th th') \<in> (RAG s)\<^sup>+" by simp
    qed
  qed
  moreover {
    fix th1 have "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

lemma eq_up:
  fixes th' th''
  assumes dp1: "th \<in> dependants s th'"
  and dp2: "th' \<in> dependants s th''"
  and eq_cps: "cp s th' = cp s' th'"
  shows "cp s th'' = cp s' th''"
proof -
  from dp2
  have "(Th th', Th th'') \<in> (RAG (wq s))\<^sup>+" by (simp add:s_dependants_def)
  from RAG_child[OF vt_s this[unfolded eq_RAG]]
  have ch_th': "(Th th', Th th'') \<in> (child s)\<^sup>+" .
  moreover {
    fix n th''
    have "\<lbrakk>(Th th', n) \<in> (child s)^+\<rbrakk> \<Longrightarrow>
                   (\<forall> th'' . n = Th th'' \<longrightarrow> cp s th'' = cp s' th'')"
    proof(erule trancl_induct, auto)
      fix y th''
      assume y_ch: "(y, Th th'') \<in> child s"
        and ih: "\<forall>th''. y = Th th'' \<longrightarrow> cp s th'' = cp s' th''"
        and ch': "(Th th', y) \<in> (child s)\<^sup>+"
      from y_ch obtain thy where eq_y: "y = Th thy" by (auto simp:child_def)
      with ih have eq_cpy:"cp s thy = cp s' thy" by blast
      from dp1 have "(Th th, Th th') \<in> (RAG s)^+" by (auto simp:s_dependants_def eq_RAG)
      moreover from child_RAG_p[OF ch'] and eq_y
      have "(Th th', Th thy) \<in> (RAG s)^+" by simp
      ultimately have dp_thy: "(Th th, Th thy) \<in> (RAG s)^+" by auto
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
          by (simp add:s_def preced_def)
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = thy")
            case True
            with eq_cpy show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp_thy have "(Th th1, Th thy) \<in> (RAG s)^+" by simp
              from children_no_dep[OF vt_s _ _ this] and 
              th1_in y_ch eq_y show False by (auto simp:children_def)
            qed
            have "th \<notin> dependants s th1"
            proof
              assume h:"th \<in> dependants s th1"
              from eq_y dp_thy have "th \<in> dependants s thy" by (auto simp:s_dependants_def eq_RAG)
              from dependants_child_unique[OF vt_s _ _ h this]
              th1_in y_ch eq_y have "th1 = thy" by (auto simp:children_def child_def)
              with False show False by auto
            qed
            from eq_cp[OF this]
            show ?thesis .
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          apply (unfold children_def child_def s_def RAG_set_unchanged, simp)
          apply (fold s_def, auto simp:RAG_s)
          proof -
            assume "(Cs cs, Th th'') \<in> RAG s'"
            with RAG_s have cs_th': "(Cs cs, Th th'') \<in> RAG s" by auto
            from dp1 have "(Th th, Th th') \<in> (RAG s)^+"
              by (auto simp:s_dependants_def eq_RAG)
            from converse_tranclE[OF this]
            obtain cs1 where h1: "(Th th, Cs cs1) \<in> RAG s"
              and h2: "(Cs cs1 , Th th') \<in> (RAG s)\<^sup>+"
              by (auto simp:s_RAG_def)
            have eq_cs: "cs1 = cs" 
            proof -
              from RAG_s have "(Th th, Cs cs) \<in> RAG s" by simp
              from unique_RAG[OF vt_s this h1]
              show ?thesis by simp
            qed
            have False
            proof(rule converse_tranclE[OF h2])
              assume "(Cs cs1, Th th') \<in> RAG s"
              with eq_cs have "(Cs cs, Th th') \<in> RAG s" by simp
              from unique_RAG[OF vt_s this cs_th']
              have "th' = th''" by simp
              with ch' y_ch have "(Th th'', Th th'') \<in> (child s)^+" by auto
              with wf_trancl[OF wf_child[OF vt_s]] 
              show False by auto
            next
              fix y
              assume "(Cs cs1, y) \<in> RAG s"
                and ytd: " (y, Th th') \<in> (RAG s)\<^sup>+"
              with eq_cs have csy: "(Cs cs, y) \<in> RAG s" by simp
              from unique_RAG[OF vt_s this cs_th']
              have "y = Th th''" .
              with ytd have "(Th th'', Th th') \<in> (RAG s)^+" by simp
              from RAG_child[OF vt_s this]
              have "(Th th'', Th th') \<in> (child s)\<^sup>+" .
              moreover from ch' y_ch have ch'': "(Th th', Th th'') \<in> (child s)^+" by auto
              ultimately have "(Th th'', Th th'') \<in> (child s)^+" by auto 
              with wf_trancl[OF wf_child[OF vt_s]] 
              show False by auto
            qed
            thus "\<exists>cs. (Th th, Cs cs) \<in> RAG s' \<and> (Cs cs, Th th'') \<in> RAG s'" by auto
          qed
          ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed
    next
      fix th''
      assume dp': "(Th th', Th th'') \<in> child s"
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
          by (simp add:s_def preced_def)
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = th'")
            case True
            with eq_cps show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp1 have "(Th th1, Th th') \<in> (RAG s)^+" 
                by (auto simp:s_dependants_def eq_RAG)
              from children_no_dep[OF vt_s _ _ this]
              th1_in dp'
              show False by (auto simp:children_def)
            qed
            show ?thesis
            proof(rule eq_cp)
              show "th \<notin> dependants s th1"
              proof
                assume "th \<in> dependants s th1"
                from dependants_child_unique[OF vt_s _ _ this dp1]
                th1_in dp' have "th1 = th'"
                  by (auto simp:children_def)
                with False show False by auto
              qed
            qed
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          apply (unfold children_def child_def s_def RAG_set_unchanged, simp)
          apply (fold s_def, auto simp:RAG_s)
          proof -
            assume "(Cs cs, Th th'') \<in> RAG s'"
            with RAG_s have cs_th': "(Cs cs, Th th'') \<in> RAG s" by auto
            from dp1 have "(Th th, Th th') \<in> (RAG s)^+"
              by (auto simp:s_dependants_def eq_RAG)
            from converse_tranclE[OF this]
            obtain cs1 where h1: "(Th th, Cs cs1) \<in> RAG s"
              and h2: "(Cs cs1 , Th th') \<in> (RAG s)\<^sup>+"
              by (auto simp:s_RAG_def)
            have eq_cs: "cs1 = cs" 
            proof -
              from RAG_s have "(Th th, Cs cs) \<in> RAG s" by simp
              from unique_RAG[OF vt_s this h1]
              show ?thesis by simp
            qed
            have False
            proof(rule converse_tranclE[OF h2])
              assume "(Cs cs1, Th th') \<in> RAG s"
              with eq_cs have "(Cs cs, Th th') \<in> RAG s" by simp
              from unique_RAG[OF vt_s this cs_th']
              have "th' = th''" by simp
              with dp' have "(Th th'', Th th'') \<in> (child s)^+" by auto
              with wf_trancl[OF wf_child[OF vt_s]] 
              show False by auto
            next
              fix y
              assume "(Cs cs1, y) \<in> RAG s"
                and ytd: " (y, Th th') \<in> (RAG s)\<^sup>+"
              with eq_cs have csy: "(Cs cs, y) \<in> RAG s" by simp
              from unique_RAG[OF vt_s this cs_th']
              have "y = Th th''" .
              with ytd have "(Th th'', Th th') \<in> (RAG s)^+" by simp
              from RAG_child[OF vt_s this]
              have "(Th th'', Th th') \<in> (child s)\<^sup>+" .
              moreover from dp' have ch'': "(Th th', Th th'') \<in> (child s)^+" by auto
              ultimately have "(Th th'', Th th'') \<in> (child s)^+" by auto 
              with wf_trancl[OF wf_child[OF vt_s]] 
              show False by auto
            qed
            thus "\<exists>cs. (Th th, Cs cs) \<in> RAG s' \<and> (Cs cs, Th th'') \<in> RAG s'" by auto
          qed
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed     
    qed
  }
  ultimately show ?thesis by auto
qed

end

locale step_create_cps =
  fixes s' th prio s 
  defines s_def : "s \<equiv> (Create th prio#s')"
  assumes vt_s: "vt s"

context step_create_cps
begin

lemma eq_dep: "RAG s = RAG s'"
  by (unfold s_def RAG_create_unchanged, auto)

lemma eq_cp:
  fixes th' 
  assumes neq_th: "th' \<noteq> th"
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have nd: "th \<notin> dependants s th'"
  proof
    assume "th \<in> dependants s th'"
    hence "(Th th, Th th') \<in> (RAG s)^+" by (simp add:s_dependants_def eq_RAG)
    with eq_dep have "(Th th, Th th') \<in> (RAG s')^+" by simp
    from converse_tranclE[OF this]
    obtain y where "(Th th, y) \<in> RAG s'" by auto
    with dm_RAG_threads[OF step_back_vt[OF vt_s[unfolded s_def]]]
    have in_th: "th \<in> threads s'" by auto
    from step_back_step[OF vt_s[unfolded s_def]]
    show False
    proof(cases)
      assume "th \<notin> threads s'" 
      with in_th show ?thesis by simp
    qed
  qed
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    by (unfold cs_dependants_def, auto simp:eq_dep eq_RAG)
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      with neq_th
      show "preced th1 s = preced th1 s'" by (auto simp:s_def preced_def)
    next
      assume "th1 \<in> dependants (wq s') th'"
      with nd and eq_dp have "th1 \<noteq> th"
        by (auto simp:eq_RAG cs_dependants_def s_dependants_def eq_dep)
      thus "preced th1 s = preced th1 s'" by (auto simp:s_def preced_def)
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

lemma nil_dependants: "dependants s th = {}"
proof -
  from step_back_step[OF vt_s[unfolded s_def]]
  show ?thesis
  proof(cases)
    assume "th \<notin> threads s'"
    from not_thread_holdents[OF step_back_vt[OF vt_s[unfolded s_def]] this]
    have hdn: " holdents s' th = {}" .
    have "dependants s' th = {}"
    proof -
      { assume "dependants s' th \<noteq> {}"
        then obtain th' where dp: "(Th th', Th th) \<in> (RAG s')^+"
          by (auto simp:s_dependants_def eq_RAG)
        from tranclE[OF this] obtain cs' where 
          "(Cs cs', Th th) \<in> RAG s'" by (auto simp:s_RAG_def)
        with hdn
        have False by (auto simp:holdents_test)
      } thus ?thesis by auto
    qed
    thus ?thesis 
      by (unfold s_def s_dependants_def eq_RAG RAG_create_unchanged, simp)
  qed
qed

lemma eq_cp_th: "cp s th = preced th s"
  apply (unfold cp_eq_cpreced cpreced_def)
  by (insert nil_dependants, unfold s_dependants_def cs_dependants_def, auto)

end


locale step_exit_cps =
  fixes s' th prio s 
  defines s_def : "s \<equiv> Exit th # s'"
  assumes vt_s: "vt s"

context step_exit_cps
begin

lemma eq_dep: "RAG s = RAG s'"
  by (unfold s_def RAG_exit_unchanged, auto)

lemma eq_cp:
  fixes th' 
  assumes neq_th: "th' \<noteq> th"
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have nd: "th \<notin> dependants s th'"
  proof
    assume "th \<in> dependants s th'"
    hence "(Th th, Th th') \<in> (RAG s)^+" by (simp add:s_dependants_def eq_RAG)
    with eq_dep have "(Th th, Th th') \<in> (RAG s')^+" by simp
    from converse_tranclE[OF this]
    obtain cs' where bk: "(Th th, Cs cs') \<in> RAG s'"
      by (auto simp:s_RAG_def)
    from step_back_step[OF vt_s[unfolded s_def]]
    show False
    proof(cases)
      assume "th \<in> runing s'"
      with bk show ?thesis
        apply (unfold runing_def readys_def s_waiting_def s_RAG_def)
        by (auto simp:cs_waiting_def wq_def)
    qed
  qed
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    by (unfold cs_dependants_def, auto simp:eq_dep eq_RAG)
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      with neq_th
      show "preced th1 s = preced th1 s'" by (auto simp:s_def preced_def)
    next
      assume "th1 \<in> dependants (wq s') th'"
      with nd and eq_dp have "th1 \<noteq> th"
        by (auto simp:eq_RAG cs_dependants_def s_dependants_def eq_dep)
      thus "preced th1 s = preced th1 s'" by (auto simp:s_def preced_def)
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

end
end