CpsG.thy
author xingyuan zhang <xingyuanzhang@126.com>
Sat, 17 Oct 2015 16:10:33 +0800
changeset 53 8142e80f5d58
parent 45 fc83f79009bd
child 55 b85cfbd58f59
permissions -rw-r--r--
Finished comments on PrioGDef.thy

section {*
  This file contains lemmas used to guide the recalculation of current precedence 
  after every system call (or system operation)
*}
theory CpsG
imports PrioG Max
begin

(* obvious lemma *)
lemma not_thread_holdents:
  fixes th s
  assumes vt: "vt s"
  and not_in: "th \<notin> threads s" 
  shows "holdents s th = {}"
proof -
  from vt not_in show ?thesis
  proof(induct arbitrary:th)
    case (vt_cons s e th)
    assume vt: "vt s"
      and ih: "\<And>th. th \<notin> threads s \<Longrightarrow> holdents s th = {}"
      and stp: "step s e"
      and not_in: "th \<notin> threads (e # s)"
    from stp show ?case
    proof(cases)
      case (thread_create thread prio)
      assume eq_e: "e = Create thread prio"
        and not_in': "thread \<notin> threads s"
      have "holdents (e # s) th = holdents s th"
        apply (unfold eq_e holdents_test)
        by (simp add:RAG_create_unchanged)
      moreover have "th \<notin> threads s" 
      proof -
        from not_in eq_e show ?thesis by simp
      qed
      moreover note ih ultimately show ?thesis by auto
    next
      case (thread_exit thread)
      assume eq_e: "e = Exit thread"
      and nh: "holdents s thread = {}"
      show ?thesis
      proof(cases "th = thread")
        case True
        with nh eq_e
        show ?thesis 
          by (auto simp:holdents_test RAG_exit_unchanged)
      next
        case False
        with not_in and eq_e
        have "th \<notin> threads s" by simp
        from ih[OF this] False eq_e show ?thesis 
          by (auto simp:holdents_test RAG_exit_unchanged)
      qed
    next
      case (thread_P thread cs)
      assume eq_e: "e = P thread cs"
      and is_runing: "thread \<in> runing s"
      from assms thread_exit ih stp not_in vt eq_e have vtp: "vt (P thread cs#s)" by auto
      have neq_th: "th \<noteq> thread" 
      proof -
        from not_in eq_e have "th \<notin> threads s" by simp
        moreover from is_runing have "thread \<in> threads s"
          by (simp add:runing_def readys_def)
        ultimately show ?thesis by auto
      qed
      hence "holdents (e # s) th  = holdents s th "
        apply (unfold cntCS_def holdents_test eq_e)
        by (unfold step_RAG_p[OF vtp], auto)
      moreover have "holdents s th = {}"
      proof(rule ih)
        from not_in eq_e show "th \<notin> threads s" by simp
      qed
      ultimately show ?thesis by simp
    next
      case (thread_V thread cs)
      assume eq_e: "e = V thread cs"
        and is_runing: "thread \<in> runing s"
        and hold: "holding s thread cs"
      have neq_th: "th \<noteq> thread" 
      proof -
        from not_in eq_e have "th \<notin> threads s" by simp
        moreover from is_runing have "thread \<in> threads s"
          by (simp add:runing_def readys_def)
        ultimately show ?thesis by auto
      qed
      from assms thread_V eq_e ih stp not_in vt have vtv: "vt (V thread cs#s)" by auto
      from hold obtain rest 
        where eq_wq: "wq s cs = thread # rest"
        by (case_tac "wq s cs", auto simp: wq_def s_holding_def)
      from not_in eq_e eq_wq
      have "\<not> next_th s thread cs th"
        apply (auto simp:next_th_def)
      proof -
        assume ne: "rest \<noteq> []"
          and ni: "hd (SOME q. distinct q \<and> set q = set rest) \<notin> threads s" (is "?t \<notin> threads s")
        have "?t \<in> set rest"
        proof(rule someI2)
          from wq_distinct[OF step_back_vt[OF vtv], of cs] and eq_wq
          show "distinct rest \<and> set rest = set rest" by auto
        next
          fix x assume "distinct x \<and> set x = set rest" with ne
          show "hd x \<in> set rest" by (cases x, auto)
        qed
        with eq_wq have "?t \<in> set (wq s cs)" by simp
        from wq_threads[OF step_back_vt[OF vtv], OF this] and ni
        show False by auto
      qed
      moreover note neq_th eq_wq
      ultimately have "holdents (e # s) th  = holdents s th"
        by (unfold eq_e cntCS_def holdents_test step_RAG_v[OF vtv], auto)
      moreover have "holdents s th = {}"
      proof(rule ih)
        from not_in eq_e show "th \<notin> threads s" by simp
      qed
      ultimately show ?thesis by simp
    next
      case (thread_set thread prio)
      print_facts
      assume eq_e: "e = Set thread prio"
        and is_runing: "thread \<in> runing s"
      from not_in and eq_e have "th \<notin> threads s" by auto
      from ih [OF this] and eq_e
      show ?thesis 
        apply (unfold eq_e cntCS_def holdents_test)
        by (simp add:RAG_set_unchanged)
    qed
    next
      case vt_nil
      show ?case
      by (auto simp:count_def holdents_test s_RAG_def wq_def cs_holding_def)
  qed
qed

(* obvious lemma *)
lemma next_th_neq: 
  assumes vt: "vt s"
  and nt: "next_th s th cs th'"
  shows "th' \<noteq> th"
proof -
  from nt show ?thesis
    apply (auto simp:next_th_def)
  proof -
    fix rest
    assume eq_wq: "wq s cs = hd (SOME q. distinct q \<and> set q = set rest) # rest"
      and ne: "rest \<noteq> []"
    have "hd (SOME q. distinct q \<and> set q = set rest) \<in> set rest" 
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      fix x
      assume "distinct x \<and> set x = set rest"
      hence eq_set: "set x = set rest" by auto
      with ne have "x \<noteq> []" by auto
      hence "hd x \<in> set x" by auto
      with eq_set show "hd x \<in> set rest" by auto
    qed
    with wq_distinct[OF vt, of cs] eq_wq show False by auto
  qed
qed

(* obvious lemma *)
lemma next_th_unique: 
  assumes nt1: "next_th s th cs th1"
  and nt2: "next_th s th cs th2"
  shows "th1 = th2"
using assms by (unfold next_th_def, auto)

lemma wf_RAG:
  assumes vt: "vt s"
  shows "wf (RAG s)"
proof(rule finite_acyclic_wf)
  from finite_RAG[OF vt] show "finite (RAG s)" .
next
  from acyclic_RAG[OF vt] show "acyclic (RAG s)" .
qed

definition child :: "state \<Rightarrow> (node \<times> node) set"
  where "child s \<equiv>
            {(Th th', Th th) | th th'. \<exists>cs. (Th th', Cs cs) \<in> RAG s \<and> (Cs cs, Th th) \<in> RAG s}"

definition children :: "state \<Rightarrow> thread \<Rightarrow> thread set"
  where "children s th \<equiv> {th'. (Th th', Th th) \<in> child s}"

lemma children_def2:
  "children s th \<equiv> {th'. \<exists> cs. (Th th', Cs cs) \<in> RAG s \<and> (Cs cs, Th th) \<in> RAG s}"
unfolding child_def children_def by simp

lemma children_dependants: 
  "children s th \<subseteq> dependants (wq s) th"
  unfolding children_def2
  unfolding cs_dependants_def
  by (auto simp add: eq_RAG)

lemma child_unique:
  assumes vt: "vt s"
  and ch1: "(Th th, Th th1) \<in> child s"
  and ch2: "(Th th, Th th2) \<in> child s"
  shows "th1 = th2"
using ch1 ch2 
proof(unfold child_def, clarsimp)
  fix cs csa
  assume h1: "(Th th, Cs cs) \<in> RAG s"
    and h2: "(Cs cs, Th th1) \<in> RAG s"
    and h3: "(Th th, Cs csa) \<in> RAG s"
    and h4: "(Cs csa, Th th2) \<in> RAG s"
  from unique_RAG[OF vt h1 h3] have "cs = csa" by simp
  with h4 have "(Cs cs, Th th2) \<in> RAG s" by simp
  from unique_RAG[OF vt h2 this]
  show "th1 = th2" by simp
qed 

lemma RAG_children:
  assumes h: "(Th th1, Th th2) \<in> (RAG s)^+"
  shows "th1 \<in> children s th2 \<or> (\<exists> th3. th3 \<in> children s th2 \<and> (Th th1, Th th3) \<in> (RAG s)^+)"
proof -
  from h show ?thesis
  proof(induct rule: tranclE)
    fix c th2
    assume h1: "(Th th1, c) \<in> (RAG s)\<^sup>+"
    and h2: "(c, Th th2) \<in> RAG s"
    from h2 obtain cs where eq_c: "c = Cs cs"
      by (case_tac c, auto simp:s_RAG_def)
    show "th1 \<in> children s th2 \<or> (\<exists>th3. th3 \<in> children s th2 \<and> (Th th1, Th th3) \<in> (RAG s)\<^sup>+)"
    proof(rule tranclE[OF h1])
      fix ca
      assume h3: "(Th th1, ca) \<in> (RAG s)\<^sup>+"
        and h4: "(ca, c) \<in> RAG s"
      show "th1 \<in> children s th2 \<or> (\<exists>th3. th3 \<in> children s th2 \<and> (Th th1, Th th3) \<in> (RAG s)\<^sup>+)"
      proof -
        from eq_c and h4 obtain th3 where eq_ca: "ca = Th th3"
          by (case_tac ca, auto simp:s_RAG_def)
        from eq_ca h4 h2 eq_c
        have "th3 \<in> children s th2" by (auto simp:children_def child_def)
        moreover from h3 eq_ca have "(Th th1, Th th3) \<in> (RAG s)\<^sup>+" by simp
        ultimately show ?thesis by auto
      qed
    next
      assume "(Th th1, c) \<in> RAG s"
      with h2 eq_c
      have "th1 \<in> children s th2"
        by (auto simp:children_def child_def)
      thus ?thesis by auto
    qed
  next
    assume "(Th th1, Th th2) \<in> RAG s"
    thus ?thesis
      by (auto simp:s_RAG_def)
  qed
qed

lemma sub_child: "child s \<subseteq> (RAG s)^+"
  by (unfold child_def, auto)

lemma wf_child: 
  assumes vt: "vt s"
  shows "wf (child s)"
apply(rule wf_subset)
apply(rule wf_trancl[OF wf_RAG[OF vt]])
apply(rule sub_child)
done

lemma RAG_child_pre:
  assumes vt: "vt s"
  shows
  "(Th th, n) \<in> (RAG s)^+ \<longrightarrow> (\<forall> th'. n = (Th th') \<longrightarrow> (Th th, Th th') \<in> (child s)^+)" (is "?P n")
proof -
  from wf_trancl[OF wf_RAG[OF vt]]
  have wf: "wf ((RAG s)^+)" .
  show ?thesis
  proof(rule wf_induct[OF wf, of ?P], clarsimp)
    fix th'
    assume ih[rule_format]: "\<forall>y. (y, Th th') \<in> (RAG s)\<^sup>+ \<longrightarrow>
               (Th th, y) \<in> (RAG s)\<^sup>+ \<longrightarrow> (\<forall>th'. y = Th th' \<longrightarrow> (Th th, Th th') \<in> (child s)\<^sup>+)"
    and h: "(Th th, Th th') \<in> (RAG s)\<^sup>+"
    show "(Th th, Th th') \<in> (child s)\<^sup>+"
    proof -
      from RAG_children[OF h]
      have "th \<in> children s th' \<or> (\<exists>th3. th3 \<in> children s th' \<and> (Th th, Th th3) \<in> (RAG s)\<^sup>+)" .
      thus ?thesis
      proof
        assume "th \<in> children s th'"
        thus "(Th th, Th th') \<in> (child s)\<^sup>+" by (auto simp:children_def)
      next
        assume "\<exists>th3. th3 \<in> children s th' \<and> (Th th, Th th3) \<in> (RAG s)\<^sup>+"
        then obtain th3 where th3_in: "th3 \<in> children s th'" 
          and th_dp: "(Th th, Th th3) \<in> (RAG s)\<^sup>+" by auto
        from th3_in have "(Th th3, Th th') \<in> (RAG s)^+" by (auto simp:children_def child_def)
        from ih[OF this th_dp, of th3] have "(Th th, Th th3) \<in> (child s)\<^sup>+" by simp
        with th3_in show "(Th th, Th th') \<in> (child s)\<^sup>+" by (auto simp:children_def)
      qed
    qed
  qed
qed

lemma RAG_child: "\<lbrakk>vt s; (Th th, Th th') \<in> (RAG s)^+\<rbrakk> \<Longrightarrow> (Th th, Th th') \<in> (child s)^+"
  by (insert RAG_child_pre, auto)

lemma child_RAG_p:
  assumes "(n1, n2) \<in> (child s)^+"
  shows "(n1, n2) \<in> (RAG s)^+"
proof -
  from assms show ?thesis
  proof(induct)
    case (base y)
    with sub_child show ?case by auto
  next
    case (step y z)
    assume "(y, z) \<in> child s"
    with sub_child have "(y, z) \<in> (RAG s)^+" by auto
    moreover have "(n1, y) \<in> (RAG s)^+" by fact
    ultimately show ?case by auto
  qed
qed

text {* (* ??? *)
*}
lemma child_RAG_eq: 
  assumes vt: "vt s"
  shows "(Th th1, Th th2) \<in> (child s)^+  \<longleftrightarrow> (Th th1, Th th2) \<in> (RAG s)^+"
  by (auto intro: RAG_child[OF vt] child_RAG_p)

text {* (* ??? *)
*}
lemma children_no_dep:
  fixes s th th1 th2 th3
  assumes vt: "vt s"
  and ch1: "(Th th1, Th th) \<in> child s"
  and ch2: "(Th th2, Th th) \<in> child s"
  and ch3: "(Th th1, Th th2) \<in> (RAG s)^+"
  shows "False"
proof -
  from RAG_child[OF vt ch3]
  have "(Th th1, Th th2) \<in> (child s)\<^sup>+" .
  thus ?thesis
  proof(rule converse_tranclE)
    assume "(Th th1, Th th2) \<in> child s"
    from child_unique[OF vt ch1 this] have "th = th2" by simp
    with ch2 have "(Th th2, Th th2) \<in> child s" by simp
    with wf_child[OF vt] show ?thesis by auto
  next
    fix c
    assume h1: "(Th th1, c) \<in> child s"
      and h2: "(c, Th th2) \<in> (child s)\<^sup>+"
    from h1 obtain th3 where eq_c: "c = Th th3" by (unfold child_def, auto)
    with h1 have "(Th th1, Th th3) \<in> child s" by simp
    from child_unique[OF vt ch1 this] have eq_th3: "th3 = th" by simp
    with eq_c and h2 have "(Th th, Th th2) \<in> (child s)\<^sup>+" by simp
    with ch2 have "(Th th, Th th) \<in> (child s)\<^sup>+" by auto
    moreover have "wf ((child s)\<^sup>+)"
    proof(rule wf_trancl)
      from wf_child[OF vt] show "wf (child s)" .
    qed
    ultimately show False by auto
  qed
qed

text {* (* ??? *)
*}
lemma unique_RAG_p:
  assumes vt: "vt s"
  and dp1: "(n, n1) \<in> (RAG s)^+"
  and dp2: "(n, n2) \<in> (RAG s)^+"
  and neq: "n1 \<noteq> n2"
  shows "(n1, n2) \<in> (RAG s)^+ \<or> (n2, n1) \<in> (RAG s)^+"
proof(rule unique_chain [OF _ dp1 dp2 neq])
  from unique_RAG[OF vt]
  show "\<And>a b c. \<lbrakk>(a, b) \<in> RAG s; (a, c) \<in> RAG s\<rbrakk> \<Longrightarrow> b = c" by auto
qed

text {* (* ??? *)
*}
lemma dependants_child_unique:
  fixes s th th1 th2 th3
  assumes vt: "vt s"
  and ch1: "(Th th1, Th th) \<in> child s"
  and ch2: "(Th th2, Th th) \<in> child s"
  and dp1: "th3 \<in> dependants s th1"
  and dp2: "th3 \<in> dependants s th2"
shows "th1 = th2"
proof -
  { assume neq: "th1 \<noteq> th2"
    from dp1 have dp1: "(Th th3, Th th1) \<in> (RAG s)^+" 
      by (simp add:s_dependants_def eq_RAG)
    from dp2 have dp2: "(Th th3, Th th2) \<in> (RAG s)^+" 
      by (simp add:s_dependants_def eq_RAG)
    from unique_RAG_p[OF vt dp1 dp2] and neq
    have "(Th th1, Th th2) \<in> (RAG s)\<^sup>+ \<or> (Th th2, Th th1) \<in> (RAG s)\<^sup>+" by auto
    hence False
    proof
      assume "(Th th1, Th th2) \<in> (RAG s)\<^sup>+ "
      from children_no_dep[OF vt ch1 ch2 this] show ?thesis .
    next
      assume " (Th th2, Th th1) \<in> (RAG s)\<^sup>+"
      from children_no_dep[OF vt ch2 ch1 this] show ?thesis .
    qed
  } thus ?thesis by auto
qed

lemma RAG_plus_elim:
  assumes "vt s"
  fixes x
  assumes "(Th x, Th th) \<in> (RAG (wq s))\<^sup>+"
  shows "\<exists>th'\<in>children s th. x = th' \<or> (Th x, Th th') \<in> (RAG (wq s))\<^sup>+"
  using assms(2)[unfolded eq_RAG, folded child_RAG_eq[OF `vt s`]]
  apply (unfold children_def)
  by (metis assms(2) children_def RAG_children eq_RAG)

text {* (* ??? *)
*}
lemma dependants_expand:
  assumes "vt s"
  shows "dependants (wq s) th = (children s th) \<union> (\<Union>((dependants (wq s)) ` children s th))"
apply(simp add: image_def)
unfolding cs_dependants_def
apply(auto)
apply (metis assms RAG_plus_elim mem_Collect_eq)
apply (metis child_RAG_p children_def eq_RAG mem_Collect_eq r_into_trancl')
by (metis assms child_RAG_eq children_def eq_RAG mem_Collect_eq trancl.trancl_into_trancl)

lemma finite_children:
  assumes "vt s"
  shows "finite (children s th)"
  using children_dependants dependants_threads[OF assms] finite_threads[OF assms]
  by (metis rev_finite_subset)
  
lemma finite_dependants:
  assumes "vt s"
  shows "finite (dependants (wq s) th')"
  using dependants_threads[OF assms] finite_threads[OF assms]
  by (metis rev_finite_subset)

abbreviation
  "preceds s ths \<equiv> {preced th s| th. th \<in> ths}"

abbreviation
  "cpreceds s ths \<equiv> (cp s) ` ths"

lemma Un_compr:
  "{f th | th. R th \<or> Q th} = ({f th | th. R th} \<union> {f th' | th'. Q th'})"
by auto

lemma in_disj:
  shows "x \<in> A \<or> (\<exists>y \<in> A. x \<in> Q y) \<longleftrightarrow> (\<exists>y \<in> A. x = y \<or> x \<in> Q y)"
by metis

lemma UN_exists:
  shows "(\<Union>x \<in> A. {f y | y. Q y x}) = ({f y | y. (\<exists>x \<in> A. Q y x)})"
by auto

text {* (* ??? *)
*}
lemma cp_rec:
  fixes s th
  assumes vt: "vt s"
  shows "cp s th = Max ({preced th s} \<union> (cp s ` children s th))"
proof(cases "children s th = {}")
  case True
  show ?thesis
    unfolding cp_eq_cpreced cpreced_def 
    by (subst dependants_expand[OF `vt s`]) (simp add: True)
next
  case False
  show ?thesis (is "?LHS = ?RHS")
  proof -
    have eq_cp: "cp s = (\<lambda>th. Max (preceds s ({th} \<union> dependants (wq s) th)))"
      by (simp add: fun_eq_iff cp_eq_cpreced cpreced_def Un_compr image_Collect[symmetric])
  
    have not_emptyness_facts[simp]: 
      "dependants (wq s) th \<noteq> {}" "children s th \<noteq> {}"
      using False dependants_expand[OF assms] by(auto simp only: Un_empty)

    have finiteness_facts[simp]:
      "\<And>th. finite (dependants (wq s) th)" "\<And>th. finite (children s th)"
      by (simp_all add: finite_dependants[OF `vt s`] finite_children[OF `vt s`])

    (* expanding definition *)
    have "?LHS = Max ({preced th s} \<union> preceds s (dependants (wq s) th))"
      unfolding eq_cp by (simp add: Un_compr)
    
    (* moving Max in *)
    also have "\<dots> = max (Max {preced th s}) (Max (preceds s (dependants (wq s) th)))"
      by (simp add: Max_Un)

    (* expanding dependants *)
    also have "\<dots> = max (Max {preced th s}) 
      (Max (preceds s (children s th \<union> \<Union>(dependants (wq s) ` children s th))))"
      by (subst dependants_expand[OF `vt s`]) (simp)

    (* moving out big Union *)
    also have "\<dots> = max (Max {preced th s})
      (Max (preceds s (\<Union> ({children s th} \<union> (dependants (wq s) ` children s th)))))"  
      by simp

    (* moving in small union *)
    also have "\<dots> = max (Max {preced th s})
      (Max (preceds s (\<Union> ((\<lambda>th. {th} \<union> (dependants (wq s) th)) ` children s th))))"  
      by (simp add: in_disj)

    (* moving in preceds *)
    also have "\<dots> = max (Max {preced th s})  
      (Max (\<Union> ((\<lambda>th. preceds s ({th} \<union> (dependants (wq s) th))) ` children s th)))" 
      by (simp add: UN_exists)

    (* moving in Max *)
    also have "\<dots> = max (Max {preced th s})  
      (Max ((\<lambda>th. Max (preceds s ({th} \<union> (dependants (wq s) th)))) ` children s th))" 
      by (subst Max_Union) (auto simp add: image_image)

    (* folding cp + moving out Max *)
    also have "\<dots> = ?RHS" 
      unfolding eq_cp by (simp add: Max_insert)

    finally show "?LHS = ?RHS" .
  qed
qed

definition cps:: "state \<Rightarrow> (thread \<times> precedence) set"
where "cps s = {(th, cp s th) | th . th \<in> threads s}"

locale step_set_cps =
  fixes s' th prio s 
  defines s_def : "s \<equiv> (Set th prio#s')"
  assumes vt_s: "vt s"

context step_set_cps 
begin

lemma eq_preced:
  fixes th'
  assumes "th' \<noteq> th"
  shows "preced th' s = preced th' s'"
proof -
  from assms show ?thesis 
    by (unfold s_def, auto simp:preced_def)
qed

lemma eq_dep: "RAG s = RAG s'"
  by (unfold s_def RAG_set_unchanged, auto)

lemma eq_cp_pre:
  fixes th' 
  assumes neq_th: "th' \<noteq> th"
  and nd: "th \<notin> dependants s th'"
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    by (unfold cs_dependants_def, auto simp:eq_dep eq_RAG)
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      with eq_preced[OF neq_th]
      show "preced th1 s = preced th1 s'" by simp
    next
      assume "th1 \<in> dependants (wq s') th'"
      with nd and eq_dp have "th1 \<noteq> th"
        by (auto simp:eq_RAG cs_dependants_def s_dependants_def eq_dep)
      from eq_preced[OF this] show "preced th1 s = preced th1 s'" by simp
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

lemma no_dependants:
  assumes "th' \<noteq> th"
  shows "th \<notin> dependants s th'"
proof
  assume h: "th \<in> dependants s th'"
  from step_back_step [OF vt_s[unfolded s_def]]
  have "step s' (Set th prio)" .
  hence "th \<in> runing s'" by (cases, simp)
  hence rd_th: "th \<in> readys s'" 
    by (simp add:readys_def runing_def)
  from h have "(Th th, Th th') \<in> (RAG s')\<^sup>+"
    by (unfold s_dependants_def, unfold eq_RAG, unfold eq_dep, auto)
  from tranclD[OF this]
  obtain z where "(Th th, z) \<in> RAG s'" by auto
  with rd_th show "False"
    apply (case_tac z, auto simp:readys_def s_RAG_def s_waiting_def cs_waiting_def)
    by (fold wq_def, blast)
qed

(* Result improved *)
lemma eq_cp:
 fixes th' 
  assumes neq_th: "th' \<noteq> th"
  shows "cp s th' = cp s' th'"
proof(rule eq_cp_pre [OF neq_th])
  from no_dependants[OF neq_th] 
  show "th \<notin> dependants s th'" .
qed

lemma eq_up:
  fixes th' th''
  assumes dp1: "th \<in> dependants s th'"
  and dp2: "th' \<in> dependants s th''"
  and eq_cps: "cp s th' = cp s' th'"
  shows "cp s th'' = cp s' th''"
proof -
  from dp2
  have "(Th th', Th th'') \<in> (RAG (wq s))\<^sup>+" by (simp add:s_dependants_def)
  from RAG_child[OF vt_s this[unfolded eq_RAG]]
  have ch_th': "(Th th', Th th'') \<in> (child s)\<^sup>+" .
  moreover { fix n th''
    have "\<lbrakk>(Th th', n) \<in> (child s)^+\<rbrakk> \<Longrightarrow>
                   (\<forall> th'' . n = Th th'' \<longrightarrow> cp s th'' = cp s' th'')"
    proof(erule trancl_induct, auto)
      fix y th''
      assume y_ch: "(y, Th th'') \<in> child s"
        and ih: "\<forall>th''. y = Th th'' \<longrightarrow> cp s th'' = cp s' th''"
        and ch': "(Th th', y) \<in> (child s)\<^sup>+"
      from y_ch obtain thy where eq_y: "y = Th thy" by (auto simp:child_def)
      with ih have eq_cpy:"cp s thy = cp s' thy" by blast
      from dp1 have "(Th th, Th th') \<in> (RAG s)^+" by (auto simp:s_dependants_def eq_RAG)
      moreover from child_RAG_p[OF ch'] and eq_y
      have "(Th th', Th thy) \<in> (RAG s)^+" by simp
      ultimately have dp_thy: "(Th th, Th thy) \<in> (RAG s)^+" by auto
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
        proof(rule eq_preced)
          show "th'' \<noteq> th"
          proof
            assume "th'' = th"
            with dp_thy y_ch[unfolded eq_y] 
            have "(Th th, Th th) \<in> (RAG s)^+"
              by (auto simp:child_def)
            with wf_trancl[OF wf_RAG[OF vt_s]] 
            show False by auto
          qed
        qed
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = thy")
            case True
            with eq_cpy show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp_thy have "(Th th1, Th thy) \<in> (RAG s)^+" by simp
              from children_no_dep[OF vt_s _ _ this] and 
              th1_in y_ch eq_y show False by (auto simp:children_def)
            qed
            have "th \<notin> dependants s th1"
            proof
              assume h:"th \<in> dependants s th1"
              from eq_y dp_thy have "th \<in> dependants s thy" by (auto simp:s_dependants_def eq_RAG)
              from dependants_child_unique[OF vt_s _ _ h this]
              th1_in y_ch eq_y have "th1 = thy" by (auto simp:children_def child_def)
              with False show False by auto
            qed
            from eq_cp_pre[OF neq_th1 this]
            show ?thesis .
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          by (unfold children_def child_def s_def RAG_set_unchanged, simp)
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed
    next
      fix th''
      assume dp': "(Th th', Th th'') \<in> child s"
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
        proof(rule eq_preced)
          show "th'' \<noteq> th"
          proof
            assume "th'' = th"
            with dp1 dp'
            have "(Th th, Th th) \<in> (RAG s)^+"
              by (auto simp:child_def s_dependants_def eq_RAG)
            with wf_trancl[OF wf_RAG[OF vt_s]] 
            show False by auto
          qed
        qed
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = th'")
            case True
            with eq_cps show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp1 have "(Th th1, Th th') \<in> (RAG s)^+" 
                by (auto simp:s_dependants_def eq_RAG)
              from children_no_dep[OF vt_s _ _ this]
              th1_in dp'
              show False by (auto simp:children_def)
            qed
            thus ?thesis
            proof(rule eq_cp_pre)
              show "th \<notin> dependants s th1"
              proof
                assume "th \<in> dependants s th1"
                from dependants_child_unique[OF vt_s _ _ this dp1]
                th1_in dp' have "th1 = th'"
                  by (auto simp:children_def)
                with False show False by auto
              qed
            qed
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          by (unfold children_def child_def s_def RAG_set_unchanged, simp)
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed     
    qed
  }
  ultimately show ?thesis by auto
qed

lemma eq_up_self:
  fixes th' th''
  assumes dp: "th \<in> dependants s th''"
  and eq_cps: "cp s th = cp s' th"
  shows "cp s th'' = cp s' th''"
proof -
  from dp
  have "(Th th, Th th'') \<in> (RAG (wq s))\<^sup>+" by (simp add:s_dependants_def)
  from RAG_child[OF vt_s this[unfolded eq_RAG]]
  have ch_th': "(Th th, Th th'') \<in> (child s)\<^sup>+" .
  moreover { fix n th''
    have "\<lbrakk>(Th th, n) \<in> (child s)^+\<rbrakk> \<Longrightarrow>
                   (\<forall> th'' . n = Th th'' \<longrightarrow> cp s th'' = cp s' th'')"
    proof(erule trancl_induct, auto)
      fix y th''
      assume y_ch: "(y, Th th'') \<in> child s"
        and ih: "\<forall>th''. y = Th th'' \<longrightarrow> cp s th'' = cp s' th''"
        and ch': "(Th th, y) \<in> (child s)\<^sup>+"
      from y_ch obtain thy where eq_y: "y = Th thy" by (auto simp:child_def)
      with ih have eq_cpy:"cp s thy = cp s' thy" by blast
      from child_RAG_p[OF ch'] and eq_y
      have dp_thy: "(Th th, Th thy) \<in> (RAG s)^+" by simp
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
        proof(rule eq_preced)
          show "th'' \<noteq> th"
          proof
            assume "th'' = th"
            with dp_thy y_ch[unfolded eq_y] 
            have "(Th th, Th th) \<in> (RAG s)^+"
              by (auto simp:child_def)
            with wf_trancl[OF wf_RAG[OF vt_s]] 
            show False by auto
          qed
        qed
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = thy")
            case True
            with eq_cpy show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp_thy have "(Th th1, Th thy) \<in> (RAG s)^+" by simp
              from children_no_dep[OF vt_s _ _ this] and 
              th1_in y_ch eq_y show False by (auto simp:children_def)
            qed
            have "th \<notin> dependants s th1"
            proof
              assume h:"th \<in> dependants s th1"
              from eq_y dp_thy have "th \<in> dependants s thy" by (auto simp:s_dependants_def eq_RAG)
              from dependants_child_unique[OF vt_s _ _ h this]
              th1_in y_ch eq_y have "th1 = thy" by (auto simp:children_def child_def)
              with False show False by auto
            qed
            from eq_cp_pre[OF neq_th1 this]
            show ?thesis .
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          by (unfold children_def child_def s_def RAG_set_unchanged, simp)
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed
    next
      fix th''
      assume dp': "(Th th, Th th'') \<in> child s"
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
        proof(rule eq_preced)
          show "th'' \<noteq> th"
          proof
            assume "th'' = th"
            with dp dp'
            have "(Th th, Th th) \<in> (RAG s)^+"
              by (auto simp:child_def s_dependants_def eq_RAG)
            with wf_trancl[OF wf_RAG[OF vt_s]] 
            show False by auto
          qed
        qed
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = th")
            case True
            with eq_cps show ?thesis by simp
          next
            case False
            assume neq_th1: "th1 \<noteq> th"
            thus ?thesis
            proof(rule eq_cp_pre)
              show "th \<notin> dependants s th1"
              proof
                assume "th \<in> dependants s th1"
                hence "(Th th, Th th1) \<in> (RAG s)^+" by (auto simp:s_dependants_def eq_RAG)
                from children_no_dep[OF vt_s _ _ this]
                and th1_in dp' show False
                  by (auto simp:children_def)
              qed
            qed
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          by (unfold children_def child_def s_def RAG_set_unchanged, simp)
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed     
    qed
  }
  ultimately show ?thesis by auto
qed
end

lemma next_waiting:
  assumes vt: "vt s"
  and nxt: "next_th s th cs th'"
  shows "waiting s th' cs"
proof -
  from assms show ?thesis
    apply (auto simp:next_th_def s_waiting_def[folded wq_def])
  proof -
    fix rest
    assume ni: "hd (SOME q. distinct q \<and> set q = set rest) \<notin> set rest"
      and eq_wq: "wq s cs = th # rest"
      and ne: "rest \<noteq> []"
    have "set (SOME q. distinct q \<and> set q = set rest) = set rest" 
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      show "\<And>x. distinct x \<and> set x = set rest \<Longrightarrow> set x = set rest" by auto
    qed
    with ni
    have "hd (SOME q. distinct q \<and> set q = set rest) \<notin>  set (SOME q. distinct q \<and> set q = set rest)"
      by simp
    moreover have "(SOME q. distinct q \<and> set q = set rest) \<noteq> []"
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      from ne show "\<And>x. distinct x \<and> set x = set rest \<Longrightarrow> x \<noteq> []" by auto
    qed
    ultimately show "hd (SOME q. distinct q \<and> set q = set rest) = th" by auto
  next
    fix rest
    assume eq_wq: "wq s cs = hd (SOME q. distinct q \<and> set q = set rest) # rest"
      and ne: "rest \<noteq> []"
    have "(SOME q. distinct q \<and> set q = set rest) \<noteq> []"
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      from ne show "\<And>x. distinct x \<and> set x = set rest \<Longrightarrow> x \<noteq> []" by auto
    qed
    hence "hd (SOME q. distinct q \<and> set q = set rest) \<in> set (SOME q. distinct q \<and> set q = set rest)"
      by auto
    moreover have "set (SOME q. distinct q \<and> set q = set rest) = set rest" 
    proof(rule someI2)
      from wq_distinct[OF vt, of cs] eq_wq
      show "distinct rest \<and> set rest = set rest" by auto
    next
      show "\<And>x. distinct x \<and> set x = set rest \<Longrightarrow> set x = set rest" by auto
    qed
    ultimately have "hd (SOME q. distinct q \<and> set q = set rest) \<in> set rest" by simp
    with eq_wq and wq_distinct[OF vt, of cs]
    show False by auto
  qed
qed


locale step_v_cps =
  fixes s' th cs s 
  defines s_def : "s \<equiv> (V th cs#s')"
  assumes vt_s: "vt s"

locale step_v_cps_nt = step_v_cps +
  fixes th'
  assumes nt: "next_th s' th cs th'"

context step_v_cps_nt
begin

lemma RAG_s:
  "RAG s = (RAG s' - {(Cs cs, Th th), (Th th', Cs cs)}) \<union>
                                         {(Cs cs, Th th')}"
proof -
  from step_RAG_v[OF vt_s[unfolded s_def], folded s_def]
    and nt show ?thesis  by (auto intro:next_th_unique)
qed

lemma dependants_kept:
  fixes th''
  assumes neq1: "th'' \<noteq> th"
  and neq2: "th'' \<noteq> th'"
  shows "dependants (wq s) th'' = dependants (wq s') th''"
proof(auto)
  fix x
  assume "x \<in> dependants (wq s) th''"
  hence dp: "(Th x, Th th'') \<in> (RAG s)^+"
    by (auto simp:cs_dependants_def eq_RAG)
  { fix n
    have "(n, Th th'') \<in> (RAG s)^+ \<Longrightarrow>  (n, Th th'') \<in> (RAG s')^+"
    proof(induct rule:converse_trancl_induct)
      fix y 
      assume "(y, Th th'') \<in> RAG s"
      with RAG_s neq1 neq2
      have "(y, Th th'') \<in> RAG s'" by auto
      thus "(y, Th th'') \<in> (RAG s')\<^sup>+" by auto
    next
      fix y z 
      assume yz: "(y, z) \<in> RAG s"
        and ztp: "(z, Th th'') \<in> (RAG s)\<^sup>+"
        and ztp': "(z, Th th'') \<in> (RAG s')\<^sup>+"
      have "y \<noteq> Cs cs \<and> y \<noteq> Th th'"
      proof
        show "y \<noteq> Cs cs"
        proof
          assume eq_y: "y = Cs cs"
          with yz have dp_yz: "(Cs cs, z) \<in> RAG s" by simp
          from RAG_s
          have cst': "(Cs cs, Th th') \<in> RAG s" by simp
          from unique_RAG[OF vt_s this dp_yz] 
          have eq_z: "z = Th th'" by simp
          with ztp have "(Th th', Th th'') \<in> (RAG s)^+" by simp
          from converse_tranclE[OF this]
          obtain cs' where dp'': "(Th th', Cs cs') \<in> RAG s"
            by (auto simp:s_RAG_def)
          with RAG_s have dp': "(Th th', Cs cs') \<in> RAG s'" by auto
          from dp'' eq_y yz eq_z have "(Cs cs, Cs cs') \<in> (RAG s)^+" by auto
          moreover have "cs' = cs"
          proof -
            from next_waiting[OF step_back_vt[OF vt_s[unfolded s_def]] nt]
            have "(Th th', Cs cs) \<in> RAG s'"
              by (auto simp:s_waiting_def wq_def s_RAG_def cs_waiting_def)
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] this dp']
            show ?thesis by simp
          qed
          ultimately have "(Cs cs, Cs cs) \<in> (RAG s)^+" by simp
          moreover note wf_trancl[OF wf_RAG[OF vt_s]]
          ultimately show False by auto
        qed
      next
        show "y \<noteq> Th th'"
        proof
          assume eq_y: "y = Th th'"
          with yz have dps: "(Th th', z) \<in> RAG s" by simp
          with RAG_s have dps': "(Th th', z) \<in> RAG s'" by auto
          have "z = Cs cs"
          proof -
            from next_waiting[OF step_back_vt[OF vt_s[unfolded s_def]] nt]
            have "(Th th', Cs cs) \<in> RAG s'"
              by (auto simp:s_waiting_def wq_def s_RAG_def cs_waiting_def)
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] dps' this]
            show ?thesis .
          qed
          with dps RAG_s show False by auto
        qed
      qed
      with RAG_s yz have "(y, z) \<in> RAG s'" by auto
      with ztp'
      show "(y, Th th'') \<in> (RAG s')\<^sup>+" by auto
    qed    
  }
  from this[OF dp]
  show "x \<in> dependants (wq s') th''" 
    by (auto simp:cs_dependants_def eq_RAG)
next
  fix x
  assume "x \<in> dependants (wq s') th''"
  hence dp: "(Th x, Th th'') \<in> (RAG s')^+"
    by (auto simp:cs_dependants_def eq_RAG)
  { fix n
    have "(n, Th th'') \<in> (RAG s')^+ \<Longrightarrow>  (n, Th th'') \<in> (RAG s)^+"
    proof(induct rule:converse_trancl_induct)
      fix y 
      assume "(y, Th th'') \<in> RAG s'"
      with RAG_s neq1 neq2
      have "(y, Th th'') \<in> RAG s" by auto
      thus "(y, Th th'') \<in> (RAG s)\<^sup>+" by auto
    next
      fix y z 
      assume yz: "(y, z) \<in> RAG s'"
        and ztp: "(z, Th th'') \<in> (RAG s')\<^sup>+"
        and ztp': "(z, Th th'') \<in> (RAG s)\<^sup>+"
      have "y \<noteq> Cs cs \<and> y \<noteq> Th th'"
      proof
        show "y \<noteq> Cs cs"
        proof
          assume eq_y: "y = Cs cs"
          with yz have dp_yz: "(Cs cs, z) \<in> RAG s'" by simp
          from this have eq_z: "z = Th th"
          proof -
            from step_back_step[OF vt_s[unfolded s_def]]
            have "(Cs cs, Th th) \<in> RAG s'"
              by(cases, auto simp: wq_def s_RAG_def cs_holding_def s_holding_def)
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] this dp_yz]
            show ?thesis by simp
          qed
          from converse_tranclE[OF ztp]
          obtain u where "(z, u) \<in> RAG s'" by auto
          moreover 
          from step_back_step[OF vt_s[unfolded s_def]]
          have "th \<in> readys s'" by (cases, simp add:runing_def)
          moreover note eq_z
          ultimately show False 
            by (auto simp:readys_def wq_def s_RAG_def s_waiting_def cs_waiting_def)
        qed
      next
        show "y \<noteq> Th th'"
        proof
          assume eq_y: "y = Th th'"
          with yz have dps: "(Th th', z) \<in> RAG s'" by simp
          have "z = Cs cs"
          proof -
            from next_waiting[OF step_back_vt[OF vt_s[unfolded s_def]] nt]
            have "(Th th', Cs cs) \<in> RAG s'"
              by (auto simp:s_waiting_def wq_def s_RAG_def cs_waiting_def)
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] dps this]
            show ?thesis .
          qed
          with ztp have cs_i: "(Cs cs, Th th'') \<in>  (RAG s')\<^sup>+" by simp
          from step_back_step[OF vt_s[unfolded s_def]]
          have cs_th: "(Cs cs, Th th) \<in> RAG s'"
            by(cases, auto simp: s_RAG_def wq_def cs_holding_def s_holding_def)
          have "(Cs cs, Th th'') \<notin>  RAG s'"
          proof
            assume "(Cs cs, Th th'') \<in> RAG s'"
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] this cs_th]
            and neq1 show "False" by simp
          qed
          with converse_tranclE[OF cs_i]
          obtain u where cu: "(Cs cs, u) \<in> RAG s'"  
            and u_t: "(u, Th th'') \<in> (RAG s')\<^sup>+" by auto
          have "u = Th th"
          proof -
            from unique_RAG[OF step_back_vt[OF vt_s[unfolded s_def]] cu cs_th]
            show ?thesis .
          qed
          with u_t have "(Th th, Th th'') \<in> (RAG s')\<^sup>+" by simp
          from converse_tranclE[OF this]
          obtain v where "(Th th, v) \<in> (RAG s')" by auto
          moreover from step_back_step[OF vt_s[unfolded s_def]]
          have "th \<in> readys s'" by (cases, simp add:runing_def)
          ultimately show False 
            by (auto simp:readys_def wq_def s_RAG_def s_waiting_def cs_waiting_def)
        qed
      qed
      with RAG_s yz have "(y, z) \<in> RAG s" by auto
      with ztp'
      show "(y, Th th'') \<in> (RAG s)\<^sup>+" by auto
    qed    
  }
  from this[OF dp]
  show "x \<in> dependants (wq s) th''"
    by (auto simp:cs_dependants_def eq_RAG)
qed

lemma cp_kept:
  fixes th''
  assumes neq1: "th'' \<noteq> th"
  and neq2: "th'' \<noteq> th'"
  shows "cp s th'' = cp s' th''"
proof -
  from dependants_kept[OF neq1 neq2]
  have "dependants (wq s) th'' = dependants (wq s') th''" .
  moreover {
    fix th1
    assume "th1 \<in> dependants (wq s) th''"
    have "preced th1 s = preced th1 s'" 
      by (unfold s_def, auto simp:preced_def)
  }
  moreover have "preced th'' s = preced th'' s'" 
    by (unfold s_def, auto simp:preced_def)
  ultimately have "((\<lambda>th. preced th s) ` ({th''} \<union> dependants (wq s) th'')) = 
    ((\<lambda>th. preced th s') ` ({th''} \<union> dependants (wq s') th''))"
    by (auto simp:image_def)
  thus ?thesis
    by (unfold cp_eq_cpreced cpreced_def, simp)
qed

end

locale step_v_cps_nnt = step_v_cps +
  assumes nnt: "\<And> th'. (\<not> next_th s' th cs th')"

context step_v_cps_nnt
begin

lemma nw_cs: "(Th th1, Cs cs) \<notin> RAG s'"
proof
  assume "(Th th1, Cs cs) \<in> RAG s'"
  thus "False"
    apply (auto simp:s_RAG_def cs_waiting_def)
  proof -
    assume h1: "th1 \<in> set (wq s' cs)"
      and h2: "th1 \<noteq> hd (wq s' cs)"
    from step_back_step[OF vt_s[unfolded s_def]]
    show "False"
    proof(cases)
      assume "holding s' th cs" 
      then obtain rest where
        eq_wq: "wq s' cs = th#rest"
        apply (unfold s_holding_def wq_def[symmetric])
        by (case_tac "(wq s' cs)", auto)
      with h1 h2 have ne: "rest \<noteq> []" by auto
      with eq_wq
      have "next_th s' th cs (hd (SOME q. distinct q \<and> set q = set rest))"
        by(unfold next_th_def, rule_tac x = "rest" in exI, auto)
      with nnt show ?thesis by auto
    qed
  qed
qed

lemma RAG_s: "RAG s = RAG s' - {(Cs cs, Th th)}"
proof -
  from nnt and  step_RAG_v[OF vt_s[unfolded s_def], folded s_def]
  show ?thesis by auto
qed

lemma child_kept_left:
  assumes 
  "(n1, n2) \<in> (child s')^+"
  shows "(n1, n2) \<in> (child s)^+"
proof -
  from assms show ?thesis 
  proof(induct rule: converse_trancl_induct)
    case (base y)
    from base obtain th1 cs1 th2
      where h1: "(Th th1, Cs cs1) \<in> RAG s'"
      and h2: "(Cs cs1, Th th2) \<in> RAG s'"
      and eq_y: "y = Th th1" and eq_n2: "n2 = Th th2"  by (auto simp:child_def)
    have "cs1 \<noteq> cs"
    proof
      assume eq_cs: "cs1 = cs"
      with h1 have "(Th th1, Cs cs1) \<in> RAG s'" by simp
      with nw_cs eq_cs show False by auto
    qed
    with h1 h2 RAG_s have 
      h1': "(Th th1, Cs cs1) \<in> RAG s" and
      h2': "(Cs cs1, Th th2) \<in> RAG s" by auto
    hence "(Th th1, Th th2) \<in> child s" by (auto simp:child_def)
    with eq_y eq_n2 have "(y, n2) \<in> child s" by simp
    thus ?case by auto
  next
    case (step y z)
    have "(y, z) \<in> child s'" by fact
    then obtain th1 cs1 th2
      where h1: "(Th th1, Cs cs1) \<in> RAG s'"
      and h2: "(Cs cs1, Th th2) \<in> RAG s'"
      and eq_y: "y = Th th1" and eq_z: "z = Th th2"  by (auto simp:child_def)
    have "cs1 \<noteq> cs"
    proof
      assume eq_cs: "cs1 = cs"
      with h1 have "(Th th1, Cs cs1) \<in> RAG s'" by simp
      with nw_cs eq_cs show False by auto
    qed
    with h1 h2 RAG_s have 
      h1': "(Th th1, Cs cs1) \<in> RAG s" and
      h2': "(Cs cs1, Th th2) \<in> RAG s" by auto
    hence "(Th th1, Th th2) \<in> child s" by (auto simp:child_def)
    with eq_y eq_z have "(y, z) \<in> child s" by simp
    moreover have "(z, n2) \<in> (child s)^+" by fact
    ultimately show ?case by auto
  qed
qed

lemma  child_kept_right:
  assumes
  "(n1, n2) \<in> (child s)^+"
  shows "(n1, n2) \<in> (child s')^+"
proof -
  from assms show ?thesis
  proof(induct)
    case (base y)
    from base and RAG_s 
    have "(n1, y) \<in> child s'"
      by (auto simp:child_def)
    thus ?case by auto
  next
    case (step y z)
    have "(y, z) \<in> child s" by fact
    with RAG_s have "(y, z) \<in> child s'"
      by (auto simp:child_def)
    moreover have "(n1, y) \<in> (child s')\<^sup>+" by fact
    ultimately show ?case by auto
  qed
qed

lemma eq_child: "(child s)^+ = (child s')^+"
  by (insert child_kept_left child_kept_right, auto)

lemma eq_cp:
  fixes th' 
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    apply (unfold cs_dependants_def, unfold eq_RAG)
  proof -
    from eq_child
    have "\<And>th. {th'. (Th th', Th th) \<in> (child s)\<^sup>+} = {th'. (Th th', Th th) \<in> (child s')\<^sup>+}"
      by simp
    with child_RAG_eq[OF vt_s] child_RAG_eq[OF step_back_vt[OF vt_s[unfolded s_def]]]
    show "\<And>th. {th'. (Th th', Th th) \<in> (RAG s)\<^sup>+} = {th'. (Th th', Th th) \<in> (RAG s')\<^sup>+}"
      by simp
  qed
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      show "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
    next
      assume "th1 \<in> dependants (wq s') th'"
      show "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

end

locale step_P_cps =
  fixes s' th cs s 
  defines s_def : "s \<equiv> (P th cs#s')"
  assumes vt_s: "vt s"

locale step_P_cps_ne =step_P_cps +
  assumes ne: "wq s' cs \<noteq> []"

locale step_P_cps_e =step_P_cps +
  assumes ee: "wq s' cs = []"

context step_P_cps_e
begin

lemma RAG_s: "RAG s = RAG s' \<union> {(Cs cs, Th th)}"
proof -
  from ee and  step_RAG_p[OF vt_s[unfolded s_def], folded s_def]
  show ?thesis by auto
qed

lemma child_kept_left:
  assumes 
  "(n1, n2) \<in> (child s')^+"
  shows "(n1, n2) \<in> (child s)^+"
proof -
  from assms show ?thesis 
  proof(induct rule: converse_trancl_induct)
    case (base y)
    from base obtain th1 cs1 th2
      where h1: "(Th th1, Cs cs1) \<in> RAG s'"
      and h2: "(Cs cs1, Th th2) \<in> RAG s'"
      and eq_y: "y = Th th1" and eq_n2: "n2 = Th th2"  by (auto simp:child_def)
    have "cs1 \<noteq> cs"
    proof
      assume eq_cs: "cs1 = cs"
      with h1 have "(Th th1, Cs cs) \<in> RAG s'" by simp
      with ee show False
        by (auto simp:s_RAG_def cs_waiting_def)
    qed
    with h1 h2 RAG_s have 
      h1': "(Th th1, Cs cs1) \<in> RAG s" and
      h2': "(Cs cs1, Th th2) \<in> RAG s" by auto
    hence "(Th th1, Th th2) \<in> child s" by (auto simp:child_def)
    with eq_y eq_n2 have "(y, n2) \<in> child s" by simp
    thus ?case by auto
  next
    case (step y z)
    have "(y, z) \<in> child s'" by fact
    then obtain th1 cs1 th2
      where h1: "(Th th1, Cs cs1) \<in> RAG s'"
      and h2: "(Cs cs1, Th th2) \<in> RAG s'"
      and eq_y: "y = Th th1" and eq_z: "z = Th th2"  by (auto simp:child_def)
    have "cs1 \<noteq> cs"
    proof
      assume eq_cs: "cs1 = cs"
      with h1 have "(Th th1, Cs cs) \<in> RAG s'" by simp
      with ee show False 
        by (auto simp:s_RAG_def cs_waiting_def)
    qed
    with h1 h2 RAG_s have 
      h1': "(Th th1, Cs cs1) \<in> RAG s" and
      h2': "(Cs cs1, Th th2) \<in> RAG s" by auto
    hence "(Th th1, Th th2) \<in> child s" by (auto simp:child_def)
    with eq_y eq_z have "(y, z) \<in> child s" by simp
    moreover have "(z, n2) \<in> (child s)^+" by fact
    ultimately show ?case by auto
  qed
qed

lemma  child_kept_right:
  assumes
  "(n1, n2) \<in> (child s)^+"
  shows "(n1, n2) \<in> (child s')^+"
proof -
  from assms show ?thesis
  proof(induct)
    case (base y)
    from base and RAG_s
    have "(n1, y) \<in> child s'"
      apply (auto simp:child_def)
      proof -
        fix th'
        assume "(Th th', Cs cs) \<in> RAG s'"
        with ee have "False"
          by (auto simp:s_RAG_def cs_waiting_def)
        thus "\<exists>cs. (Th th', Cs cs) \<in> RAG s' \<and> (Cs cs, Th th) \<in> RAG s'" by auto 
      qed
    thus ?case by auto
  next
    case (step y z)
    have "(y, z) \<in> child s" by fact
    with RAG_s have "(y, z) \<in> child s'"
      apply (auto simp:child_def)
      proof -
        fix th'
        assume "(Th th', Cs cs) \<in> RAG s'"
        with ee have "False"
          by (auto simp:s_RAG_def cs_waiting_def)
        thus "\<exists>cs. (Th th', Cs cs) \<in> RAG s' \<and> (Cs cs, Th th) \<in> RAG s'" by auto 
      qed
    moreover have "(n1, y) \<in> (child s')\<^sup>+" by fact
    ultimately show ?case by auto
  qed
qed

lemma eq_child: "(child s)^+ = (child s')^+"
  by (insert child_kept_left child_kept_right, auto)

lemma eq_cp:
  fixes th' 
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    apply (unfold cs_dependants_def, unfold eq_RAG)
  proof -
    from eq_child
    have "\<And>th. {th'. (Th th', Th th) \<in> (child s)\<^sup>+} = {th'. (Th th', Th th) \<in> (child s')\<^sup>+}"
      by auto
    with child_RAG_eq[OF vt_s] child_RAG_eq[OF step_back_vt[OF vt_s[unfolded s_def]]]
    show "\<And>th. {th'. (Th th', Th th) \<in> (RAG s)\<^sup>+} = {th'. (Th th', Th th) \<in> (RAG s')\<^sup>+}"
      by simp
  qed
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      show "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
    next
      assume "th1 \<in> dependants (wq s') th'"
      show "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

end

context step_P_cps_ne
begin

lemma RAG_s: "RAG s = RAG s' \<union> {(Th th, Cs cs)}"
proof -
  from step_RAG_p[OF vt_s[unfolded s_def]] and ne
  show ?thesis by (simp add:s_def)
qed

lemma eq_child_left:
  assumes nd: "(Th th, Th th') \<notin> (child s)^+"
  shows "(n1, Th th') \<in> (child s)^+ \<Longrightarrow> (n1, Th th') \<in> (child s')^+"
proof(induct rule:converse_trancl_induct)
  case (base y)
  from base obtain th1 cs1
    where h1: "(Th th1, Cs cs1) \<in> RAG s"
    and h2: "(Cs cs1, Th th') \<in> RAG s"
    and eq_y: "y = Th th1"   by (auto simp:child_def)
  have "th1 \<noteq> th"
  proof
    assume "th1 = th"
    with base eq_y have "(Th th, Th th') \<in> child s" by simp
    with nd show False by auto
  qed
  with h1 h2 RAG_s 
  have h1': "(Th th1, Cs cs1) \<in> RAG s'" and 
       h2': "(Cs cs1, Th th') \<in> RAG s'" by auto
  with eq_y show ?case by (auto simp:child_def)
next
  case (step y z)
  have yz: "(y, z) \<in> child s" by fact
  then obtain th1 cs1 th2
    where h1: "(Th th1, Cs cs1) \<in> RAG s"
    and h2: "(Cs cs1, Th th2) \<in> RAG s"
    and eq_y: "y = Th th1" and eq_z: "z = Th th2"  by (auto simp:child_def)
  have "th1 \<noteq> th"
  proof
    assume "th1 = th"
    with yz eq_y have "(Th th, z) \<in> child s" by simp
    moreover have "(z, Th th') \<in> (child s)^+" by fact
    ultimately have "(Th th, Th th') \<in> (child s)^+" by auto
    with nd show False by auto
  qed
  with h1 h2 RAG_s have h1': "(Th th1, Cs cs1) \<in> RAG s'"
                       and h2': "(Cs cs1, Th th2) \<in> RAG s'" by auto
  with eq_y eq_z have "(y, z) \<in> child s'" by (auto simp:child_def)
  moreover have "(z, Th th') \<in> (child s')^+" by fact
  ultimately show ?case by auto
qed

lemma eq_child_right:
  shows "(n1, Th th') \<in> (child s')^+ \<Longrightarrow> (n1, Th th') \<in> (child s)^+"
proof(induct rule:converse_trancl_induct)
  case (base y)
  with RAG_s show ?case by (auto simp:child_def)
next
  case (step y z)
  have "(y, z) \<in> child s'" by fact
  with RAG_s have "(y, z) \<in> child s" by (auto simp:child_def)
  moreover have "(z, Th th') \<in> (child s)^+" by fact
  ultimately show ?case by auto
qed

lemma eq_child:
  assumes nd: "(Th th, Th th') \<notin> (child s)^+"
  shows "((n1, Th th') \<in> (child s)^+) = ((n1, Th th') \<in> (child s')^+)"
  by (insert eq_child_left[OF nd] eq_child_right, auto)

lemma eq_cp:
  fixes th' 
  assumes nd: "th \<notin> dependants s th'"
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have nd': "(Th th, Th th') \<notin> (child s)^+"
  proof
    assume "(Th th, Th th') \<in> (child s)\<^sup>+"
    with child_RAG_eq[OF vt_s]
    have "(Th th, Th th') \<in> (RAG s)\<^sup>+" by simp
    with nd show False 
      by (simp add:s_dependants_def eq_RAG)
  qed
  have eq_dp: "dependants (wq s) th' = dependants (wq s') th'"
  proof(auto)
    fix x assume " x \<in> dependants (wq s) th'"
    thus "x \<in> dependants (wq s') th'"
      apply (auto simp:cs_dependants_def eq_RAG)
    proof -
      assume "(Th x, Th th') \<in> (RAG s)\<^sup>+"
      with  child_RAG_eq[OF vt_s] have "(Th x, Th th') \<in> (child s)\<^sup>+" by simp
      with eq_child[OF nd'] have "(Th x, Th th') \<in> (child s')^+" by simp
      with child_RAG_eq[OF step_back_vt[OF vt_s[unfolded s_def]]]
      show "(Th x, Th th') \<in> (RAG s')\<^sup>+" by simp
    qed
  next
    fix x assume "x \<in> dependants (wq s') th'"
    thus "x \<in> dependants (wq s) th'"
      apply (auto simp:cs_dependants_def eq_RAG)
    proof -
      assume "(Th x, Th th') \<in> (RAG s')\<^sup>+"
      with child_RAG_eq[OF step_back_vt[OF vt_s[unfolded s_def]]] 
      have "(Th x, Th th') \<in> (child s')\<^sup>+" by simp
      with eq_child[OF nd'] have "(Th x, Th th') \<in> (child s)^+" by simp
      with  child_RAG_eq[OF vt_s]
      show "(Th x, Th th') \<in> (RAG s)\<^sup>+" by simp
    qed
  qed
  moreover {
    fix th1 have "preced th1 s = preced th1 s'" by (simp add:s_def preced_def)
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

lemma eq_up:
  fixes th' th''
  assumes dp1: "th \<in> dependants s th'"
  and dp2: "th' \<in> dependants s th''"
  and eq_cps: "cp s th' = cp s' th'"
  shows "cp s th'' = cp s' th''"
proof -
  from dp2
  have "(Th th', Th th'') \<in> (RAG (wq s))\<^sup>+" by (simp add:s_dependants_def)
  from RAG_child[OF vt_s this[unfolded eq_RAG]]
  have ch_th': "(Th th', Th th'') \<in> (child s)\<^sup>+" .
  moreover {
    fix n th''
    have "\<lbrakk>(Th th', n) \<in> (child s)^+\<rbrakk> \<Longrightarrow>
                   (\<forall> th'' . n = Th th'' \<longrightarrow> cp s th'' = cp s' th'')"
    proof(erule trancl_induct, auto)
      fix y th''
      assume y_ch: "(y, Th th'') \<in> child s"
        and ih: "\<forall>th''. y = Th th'' \<longrightarrow> cp s th'' = cp s' th''"
        and ch': "(Th th', y) \<in> (child s)\<^sup>+"
      from y_ch obtain thy where eq_y: "y = Th thy" by (auto simp:child_def)
      with ih have eq_cpy:"cp s thy = cp s' thy" by blast
      from dp1 have "(Th th, Th th') \<in> (RAG s)^+" by (auto simp:s_dependants_def eq_RAG)
      moreover from child_RAG_p[OF ch'] and eq_y
      have "(Th th', Th thy) \<in> (RAG s)^+" by simp
      ultimately have dp_thy: "(Th th, Th thy) \<in> (RAG s)^+" by auto
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
          by (simp add:s_def preced_def)
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = thy")
            case True
            with eq_cpy show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp_thy have "(Th th1, Th thy) \<in> (RAG s)^+" by simp
              from children_no_dep[OF vt_s _ _ this] and 
              th1_in y_ch eq_y show False by (auto simp:children_def)
            qed
            have "th \<notin> dependants s th1"
            proof
              assume h:"th \<in> dependants s th1"
              from eq_y dp_thy have "th \<in> dependants s thy" by (auto simp:s_dependants_def eq_RAG)
              from dependants_child_unique[OF vt_s _ _ h this]
              th1_in y_ch eq_y have "th1 = thy" by (auto simp:children_def child_def)
              with False show False by auto
            qed
            from eq_cp[OF this]
            show ?thesis .
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          apply (unfold children_def child_def s_def RAG_set_unchanged, simp)
          apply (fold s_def, auto simp:RAG_s)
          proof -
            assume "(Cs cs, Th th'') \<in> RAG s'"
            with RAG_s have cs_th': "(Cs cs, Th th'') \<in> RAG s" by auto
            from dp1 have "(Th th, Th th') \<in> (RAG s)^+"
              by (auto simp:s_dependants_def eq_RAG)
            from converse_tranclE[OF this]
            obtain cs1 where h1: "(Th th, Cs cs1) \<in> RAG s"
              and h2: "(Cs cs1 , Th th') \<in> (RAG s)\<^sup>+"
              by (auto simp:s_RAG_def)
            have eq_cs: "cs1 = cs" 
            proof -
              from RAG_s have "(Th th, Cs cs) \<in> RAG s" by simp
              from unique_RAG[OF vt_s this h1]
              show ?thesis by simp
            qed
            have False
            proof(rule converse_tranclE[OF h2])
              assume "(Cs cs1, Th th') \<in> RAG s"
              with eq_cs have "(Cs cs, Th th') \<in> RAG s" by simp
              from unique_RAG[OF vt_s this cs_th']
              have "th' = th''" by simp
              with ch' y_ch have "(Th th'', Th th'') \<in> (child s)^+" by auto
              with wf_trancl[OF wf_child[OF vt_s]] 
              show False by auto
            next
              fix y
              assume "(Cs cs1, y) \<in> RAG s"
                and ytd: " (y, Th th') \<in> (RAG s)\<^sup>+"
              with eq_cs have csy: "(Cs cs, y) \<in> RAG s" by simp
              from unique_RAG[OF vt_s this cs_th']
              have "y = Th th''" .
              with ytd have "(Th th'', Th th') \<in> (RAG s)^+" by simp
              from RAG_child[OF vt_s this]
              have "(Th th'', Th th') \<in> (child s)\<^sup>+" .
              moreover from ch' y_ch have ch'': "(Th th', Th th'') \<in> (child s)^+" by auto
              ultimately have "(Th th'', Th th'') \<in> (child s)^+" by auto 
              with wf_trancl[OF wf_child[OF vt_s]] 
              show False by auto
            qed
            thus "\<exists>cs. (Th th, Cs cs) \<in> RAG s' \<and> (Cs cs, Th th'') \<in> RAG s'" by auto
          qed
          ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed
    next
      fix th''
      assume dp': "(Th th', Th th'') \<in> child s"
      show "cp s th'' = cp s' th''"
        apply (subst cp_rec[OF vt_s])
      proof -
        have "preced th'' s = preced th'' s'"
          by (simp add:s_def preced_def)
        moreover { 
          fix th1
          assume th1_in: "th1 \<in> children s th''"
          have "cp s th1 = cp s' th1"
          proof(cases "th1 = th'")
            case True
            with eq_cps show ?thesis by simp
          next
            case False
            have neq_th1: "th1 \<noteq> th"
            proof
              assume eq_th1: "th1 = th"
              with dp1 have "(Th th1, Th th') \<in> (RAG s)^+" 
                by (auto simp:s_dependants_def eq_RAG)
              from children_no_dep[OF vt_s _ _ this]
              th1_in dp'
              show False by (auto simp:children_def)
            qed
            show ?thesis
            proof(rule eq_cp)
              show "th \<notin> dependants s th1"
              proof
                assume "th \<in> dependants s th1"
                from dependants_child_unique[OF vt_s _ _ this dp1]
                th1_in dp' have "th1 = th'"
                  by (auto simp:children_def)
                with False show False by auto
              qed
            qed
          qed
        }
        ultimately have "{preced th'' s} \<union> (cp s ` children s th'') = 
          {preced th'' s'} \<union> (cp s' ` children s th'')" by (auto simp:image_def)
        moreover have "children s th'' = children s' th''"
          apply (unfold children_def child_def s_def RAG_set_unchanged, simp)
          apply (fold s_def, auto simp:RAG_s)
          proof -
            assume "(Cs cs, Th th'') \<in> RAG s'"
            with RAG_s have cs_th': "(Cs cs, Th th'') \<in> RAG s" by auto
            from dp1 have "(Th th, Th th') \<in> (RAG s)^+"
              by (auto simp:s_dependants_def eq_RAG)
            from converse_tranclE[OF this]
            obtain cs1 where h1: "(Th th, Cs cs1) \<in> RAG s"
              and h2: "(Cs cs1 , Th th') \<in> (RAG s)\<^sup>+"
              by (auto simp:s_RAG_def)
            have eq_cs: "cs1 = cs" 
            proof -
              from RAG_s have "(Th th, Cs cs) \<in> RAG s" by simp
              from unique_RAG[OF vt_s this h1]
              show ?thesis by simp
            qed
            have False
            proof(rule converse_tranclE[OF h2])
              assume "(Cs cs1, Th th') \<in> RAG s"
              with eq_cs have "(Cs cs, Th th') \<in> RAG s" by simp
              from unique_RAG[OF vt_s this cs_th']
              have "th' = th''" by simp
              with dp' have "(Th th'', Th th'') \<in> (child s)^+" by auto
              with wf_trancl[OF wf_child[OF vt_s]] 
              show False by auto
            next
              fix y
              assume "(Cs cs1, y) \<in> RAG s"
                and ytd: " (y, Th th') \<in> (RAG s)\<^sup>+"
              with eq_cs have csy: "(Cs cs, y) \<in> RAG s" by simp
              from unique_RAG[OF vt_s this cs_th']
              have "y = Th th''" .
              with ytd have "(Th th'', Th th') \<in> (RAG s)^+" by simp
              from RAG_child[OF vt_s this]
              have "(Th th'', Th th') \<in> (child s)\<^sup>+" .
              moreover from dp' have ch'': "(Th th', Th th'') \<in> (child s)^+" by auto
              ultimately have "(Th th'', Th th'') \<in> (child s)^+" by auto 
              with wf_trancl[OF wf_child[OF vt_s]] 
              show False by auto
            qed
            thus "\<exists>cs. (Th th, Cs cs) \<in> RAG s' \<and> (Cs cs, Th th'') \<in> RAG s'" by auto
          qed
        ultimately show "Max ({preced th'' s} \<union> cp s ` children s th'') = cp s' th''"
          by (simp add:cp_rec[OF step_back_vt[OF vt_s[unfolded s_def]]])
      qed     
    qed
  }
  ultimately show ?thesis by auto
qed

end

locale step_create_cps =
  fixes s' th prio s 
  defines s_def : "s \<equiv> (Create th prio#s')"
  assumes vt_s: "vt s"

context step_create_cps
begin

lemma eq_dep: "RAG s = RAG s'"
  by (unfold s_def RAG_create_unchanged, auto)

lemma eq_cp:
  fixes th' 
  assumes neq_th: "th' \<noteq> th"
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have nd: "th \<notin> dependants s th'"
  proof
    assume "th \<in> dependants s th'"
    hence "(Th th, Th th') \<in> (RAG s)^+" by (simp add:s_dependants_def eq_RAG)
    with eq_dep have "(Th th, Th th') \<in> (RAG s')^+" by simp
    from converse_tranclE[OF this]
    obtain y where "(Th th, y) \<in> RAG s'" by auto
    with dm_RAG_threads[OF step_back_vt[OF vt_s[unfolded s_def]]]
    have in_th: "th \<in> threads s'" by auto
    from step_back_step[OF vt_s[unfolded s_def]]
    show False
    proof(cases)
      assume "th \<notin> threads s'" 
      with in_th show ?thesis by simp
    qed
  qed
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    by (unfold cs_dependants_def, auto simp:eq_dep eq_RAG)
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      with neq_th
      show "preced th1 s = preced th1 s'" by (auto simp:s_def preced_def)
    next
      assume "th1 \<in> dependants (wq s') th'"
      with nd and eq_dp have "th1 \<noteq> th"
        by (auto simp:eq_RAG cs_dependants_def s_dependants_def eq_dep)
      thus "preced th1 s = preced th1 s'" by (auto simp:s_def preced_def)
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

lemma nil_dependants: "dependants s th = {}"
proof -
  from step_back_step[OF vt_s[unfolded s_def]]
  show ?thesis
  proof(cases)
    assume "th \<notin> threads s'"
    from not_thread_holdents[OF step_back_vt[OF vt_s[unfolded s_def]] this]
    have hdn: " holdents s' th = {}" .
    have "dependants s' th = {}"
    proof -
      { assume "dependants s' th \<noteq> {}"
        then obtain th' where dp: "(Th th', Th th) \<in> (RAG s')^+"
          by (auto simp:s_dependants_def eq_RAG)
        from tranclE[OF this] obtain cs' where 
          "(Cs cs', Th th) \<in> RAG s'" by (auto simp:s_RAG_def)
        with hdn
        have False by (auto simp:holdents_test)
      } thus ?thesis by auto
    qed
    thus ?thesis 
      by (unfold s_def s_dependants_def eq_RAG RAG_create_unchanged, simp)
  qed
qed

lemma eq_cp_th: "cp s th = preced th s"
  apply (unfold cp_eq_cpreced cpreced_def)
  by (insert nil_dependants, unfold s_dependants_def cs_dependants_def, auto)

end


locale step_exit_cps =
  fixes s' th prio s 
  defines s_def : "s \<equiv> Exit th # s'"
  assumes vt_s: "vt s"

context step_exit_cps
begin

lemma eq_dep: "RAG s = RAG s'"
  by (unfold s_def RAG_exit_unchanged, auto)

lemma eq_cp:
  fixes th' 
  assumes neq_th: "th' \<noteq> th"
  shows "cp s th' = cp s' th'"
  apply (unfold cp_eq_cpreced cpreced_def)
proof -
  have nd: "th \<notin> dependants s th'"
  proof
    assume "th \<in> dependants s th'"
    hence "(Th th, Th th') \<in> (RAG s)^+" by (simp add:s_dependants_def eq_RAG)
    with eq_dep have "(Th th, Th th') \<in> (RAG s')^+" by simp
    from converse_tranclE[OF this]
    obtain cs' where bk: "(Th th, Cs cs') \<in> RAG s'"
      by (auto simp:s_RAG_def)
    from step_back_step[OF vt_s[unfolded s_def]]
    show False
    proof(cases)
      assume "th \<in> runing s'"
      with bk show ?thesis
        apply (unfold runing_def readys_def s_waiting_def s_RAG_def)
        by (auto simp:cs_waiting_def wq_def)
    qed
  qed
  have eq_dp: "\<And> th. dependants (wq s) th = dependants (wq s') th"
    by (unfold cs_dependants_def, auto simp:eq_dep eq_RAG)
  moreover {
    fix th1 
    assume "th1 \<in> {th'} \<union> dependants (wq s') th'"
    hence "th1 = th' \<or> th1 \<in> dependants (wq s') th'" by auto
    hence "preced th1 s = preced th1 s'"
    proof
      assume "th1 = th'"
      with neq_th
      show "preced th1 s = preced th1 s'" by (auto simp:s_def preced_def)
    next
      assume "th1 \<in> dependants (wq s') th'"
      with nd and eq_dp have "th1 \<noteq> th"
        by (auto simp:eq_RAG cs_dependants_def s_dependants_def eq_dep)
      thus "preced th1 s = preced th1 s'" by (auto simp:s_def preced_def)
    qed
  } ultimately have "((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) = 
                     ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" 
    by (auto simp:image_def)
  thus "Max ((\<lambda>th. preced th s) ` ({th'} \<union> dependants (wq s) th')) =
        Max ((\<lambda>th. preced th s') ` ({th'} \<union> dependants (wq s') th'))" by simp
qed

end
end