Moment.thy.orig
changeset 81 c495eb16beb6
equal deleted inserted replaced
80:17305a85493d 81:c495eb16beb6
       
     1 theory Moment
       
     2 imports Main
       
     3 begin
       
     4 
       
     5 definition moment :: "nat \<Rightarrow> 'a list \<Rightarrow> 'a list"
       
     6 where "moment n s = rev (take n (rev s))"
       
     7 
       
     8 definition restm :: "nat \<Rightarrow> 'a list \<Rightarrow> 'a list"
       
     9 where "restm n s = rev (drop n (rev s))"
       
    10 
       
    11 value "moment 3 [0, 1, 2, 3, 4, 5, 6, 7, 8, 9::int]"
       
    12 value "moment 2 [5, 4, 3, 2, 1, 0::int]"
       
    13 
       
    14 value "restm 3 [0, 1, 2, 3, 4, 5, 6, 7, 8, 9::int]"
       
    15 
       
    16 lemma moment_restm_s: "(restm n s) @ (moment n s) = s"
       
    17   unfolding restm_def moment_def
       
    18 by (metis append_take_drop_id rev_append rev_rev_ident)
       
    19 
       
    20 lemma length_moment_le:
       
    21   assumes le_k: "k \<le> length s"
       
    22   shows "length (moment k s) = k"
       
    23 using le_k unfolding moment_def by auto
       
    24 
       
    25 lemma length_moment_ge:
       
    26   assumes le_k: "length s \<le> k"
       
    27   shows "length (moment k s) = (length s)"
       
    28 using assms unfolding moment_def by simp
       
    29 
       
    30 lemma moment_app [simp]:
       
    31   assumes ile: "i \<le> length s"
       
    32   shows "moment i (s' @ s) = moment i s"
       
    33 using assms unfolding moment_def by simp
       
    34 
       
    35 lemma moment_eq [simp]: "moment (length s) (s' @ s) = s"
       
    36   unfolding moment_def by simp
       
    37 
       
    38 lemma moment_ge [simp]: "length s \<le> n \<Longrightarrow> moment n s = s"
       
    39   by (unfold moment_def, simp)
       
    40 
       
    41 lemma moment_zero [simp]: "moment 0 s = []"
       
    42   by (simp add:moment_def)
       
    43 
       
    44 lemma p_split_gen: 
       
    45   "\<lbrakk>Q s; \<not> Q (moment k s)\<rbrakk> \<Longrightarrow>
       
    46   (\<exists> i. i < length s \<and> k \<le> i \<and> \<not> Q (moment i s) \<and> (\<forall> i' > i. Q (moment i' s)))"
       
    47 proof (induct s, simp)
       
    48   fix a s
       
    49   assume ih: "\<lbrakk>Q s; \<not> Q (moment k s)\<rbrakk>
       
    50            \<Longrightarrow> \<exists>i<length s. k \<le> i \<and> \<not> Q (moment i s) \<and> (\<forall>i'>i. Q (moment i' s))"
       
    51     and nq: "\<not> Q (moment k (a # s))" and qa: "Q (a # s)"
       
    52   have le_k: "k \<le> length s"
       
    53   proof -
       
    54     { assume "length s < k"
       
    55       hence "length (a#s) \<le> k" by simp
       
    56       from moment_ge [OF this] and nq and qa
       
    57       have "False" by auto
       
    58     } thus ?thesis by arith
       
    59   qed
       
    60   have nq_k: "\<not> Q (moment k s)"
       
    61   proof -
       
    62     have "moment k (a#s) = moment k s"
       
    63     proof -
       
    64       from moment_app [OF le_k, of "[a]"] show ?thesis by simp
       
    65     qed
       
    66     with nq show ?thesis by simp
       
    67   qed
       
    68   show "\<exists>i<length (a # s). k \<le> i \<and> \<not> Q (moment i (a # s)) \<and> (\<forall>i'>i. Q (moment i' (a # s)))"
       
    69   proof -
       
    70     { assume "Q s"
       
    71       from ih [OF this nq_k]
       
    72       obtain i where lti: "i < length s" 
       
    73         and nq: "\<not> Q (moment i s)" 
       
    74         and rst: "\<forall>i'>i. Q (moment i' s)" 
       
    75         and lki: "k \<le> i" by auto
       
    76       have ?thesis 
       
    77       proof -
       
    78         from lti have "i < length (a # s)" by auto
       
    79         moreover have " \<not> Q (moment i (a # s))"
       
    80         proof -
       
    81           from lti have "i \<le> (length s)" by simp
       
    82           from moment_app [OF this, of "[a]"]
       
    83           have "moment i (a # s) = moment i s" by simp
       
    84           with nq show ?thesis by auto
       
    85         qed
       
    86         moreover have " (\<forall>i'>i. Q (moment i' (a # s)))"
       
    87         proof -
       
    88           {
       
    89             fix i'
       
    90             assume lti': "i < i'"
       
    91             have "Q (moment i' (a # s))"
       
    92             proof(cases "length (a#s) \<le> i'")
       
    93               case True
       
    94               from True have "moment i' (a#s) = a#s" by simp
       
    95               with qa show ?thesis by simp
       
    96             next
       
    97               case False
       
    98               from False have "i' \<le> length s" by simp
       
    99               from moment_app [OF this, of "[a]"]
       
   100               have "moment i' (a#s) = moment i' s" by simp
       
   101               with rst lti' show ?thesis by auto
       
   102             qed
       
   103           } thus ?thesis by auto
       
   104         qed
       
   105         moreover note lki
       
   106         ultimately show ?thesis by auto
       
   107       qed
       
   108     } moreover {
       
   109       assume ns: "\<not> Q s"
       
   110       have ?thesis
       
   111       proof -
       
   112         let ?i = "length s"
       
   113         have "\<not> Q (moment ?i (a#s))"
       
   114         proof -
       
   115           have "?i \<le> length s" by simp
       
   116           from moment_app [OF this, of "[a]"]
       
   117           have "moment ?i (a#s) = moment ?i s" by simp
       
   118           moreover have "\<dots> = s" by simp
       
   119           ultimately show ?thesis using ns by auto
       
   120         qed
       
   121         moreover have "\<forall> i' > ?i. Q (moment i' (a#s))" 
       
   122         proof -
       
   123           { fix i'
       
   124             assume "i' > ?i"
       
   125             hence "length (a#s) \<le> i'" by simp
       
   126             from moment_ge [OF this] 
       
   127             have " moment i' (a # s) = a # s" .
       
   128             with qa have "Q (moment i' (a#s))" by simp
       
   129           } thus ?thesis by auto
       
   130         qed
       
   131         moreover have "?i < length (a#s)" by simp
       
   132         moreover note le_k
       
   133         ultimately show ?thesis by auto
       
   134       qed
       
   135     } ultimately show ?thesis by auto
       
   136   qed
       
   137 qed
       
   138 
       
   139 lemma p_split: 
       
   140   "\<lbrakk>Q s; \<not> Q []\<rbrakk> \<Longrightarrow> 
       
   141        (\<exists> i. i < length s \<and> \<not> Q (moment i s) \<and> (\<forall> i' > i. Q (moment i' s)))"
       
   142 proof -
       
   143   fix s Q
       
   144   assume qs: "Q s" and nq: "\<not> Q []"
       
   145   from nq have "\<not> Q (moment 0 s)" by simp
       
   146   from p_split_gen [of Q s 0, OF qs this]
       
   147   show "(\<exists> i. i < length s \<and> \<not> Q (moment i s) \<and> (\<forall> i' > i. Q (moment i' s)))"
       
   148     by auto
       
   149 qed
       
   150 
       
   151 lemma moment_plus_split:
       
   152   shows "moment (m + i) s = moment m (restm i s) @ moment i s"
       
   153 unfolding moment_def restm_def
       
   154 by (metis add.commute rev_append rev_rev_ident take_add)
       
   155 
       
   156 lemma moment_prefix: 
       
   157   "(moment i t @ s) = moment (i + length s) (t @ s)"
       
   158 proof -
       
   159   from moment_plus_split [of i "length s" "t@s"]
       
   160   have " moment (i + length s) (t @ s) = moment i (restm (length s) (t @ s)) @ moment (length s) (t @ s)"
       
   161     by auto
       
   162   have "moment (i + length s) (t @ s) = moment i t @ moment (length s) (t @ s)" 
       
   163     by (simp add: moment_def)
       
   164   with moment_app show ?thesis by auto
       
   165 qed
       
   166 
       
   167 lemma moment_plus: 
       
   168   "Suc i \<le> length s \<Longrightarrow> moment (Suc i) s = (hd (moment (Suc i) s)) # (moment i s)"
       
   169 proof(induct s, simp+)
       
   170   fix a s
       
   171   assume ih: "Suc i \<le> length s \<Longrightarrow> moment (Suc i) s = hd (moment (Suc i) s) # moment i s"
       
   172     and le_i: "i \<le> length s"
       
   173   show "moment (Suc i) (a # s) = hd (moment (Suc i) (a # s)) # moment i (a # s)"
       
   174   proof(cases "i= length s")
       
   175     case True
       
   176     hence "Suc i = length (a#s)" by simp
       
   177     with moment_eq have "moment (Suc i) (a#s) = a#s" by auto
       
   178     moreover have "moment i (a#s) = s"
       
   179     proof -
       
   180       from moment_app [OF le_i, of "[a]"]
       
   181       and True show ?thesis by simp
       
   182     qed
       
   183     ultimately show ?thesis by auto
       
   184   next
       
   185     case False
       
   186     from False and le_i have lti: "i < length s" by arith
       
   187     hence les_i: "Suc i \<le> length s" by arith
       
   188     show ?thesis 
       
   189     proof -
       
   190       from moment_app [OF les_i, of "[a]"]
       
   191       have "moment (Suc i) (a # s) = moment (Suc i) s" by simp
       
   192       moreover have "moment i (a#s) = moment i s" 
       
   193       proof -
       
   194         from lti have "i \<le> length s" by simp
       
   195         from moment_app [OF this, of "[a]"] show ?thesis by simp
       
   196       qed
       
   197       moreover note ih [OF les_i]
       
   198       ultimately show ?thesis by auto
       
   199     qed
       
   200   qed
       
   201 qed
       
   202 
       
   203 end
       
   204