Moment.thy
changeset 74 83ba2d8c859a
parent 73 b0054fb0d1ce
child 75 2aa37de77f31
equal deleted inserted replaced
73:b0054fb0d1ce 74:83ba2d8c859a
    34   by (unfold moment_def, simp)
    34   by (unfold moment_def, simp)
    35 
    35 
    36 lemma moment_zero [simp]: "moment 0 s = []"
    36 lemma moment_zero [simp]: "moment 0 s = []"
    37   by (simp add:moment_def)
    37   by (simp add:moment_def)
    38 
    38 
    39 lemma p_split_gen: 
    39 lemma least_idx:
    40   "\<lbrakk>Q s; \<not> Q (moment k s)\<rbrakk> \<Longrightarrow>
    40   assumes "Q (i::nat)"
    41   (\<exists> i. i < length s \<and> k \<le> i \<and> \<not> Q (moment i s) \<and> (\<forall> i' > i. Q (moment i' s)))"
    41   obtains j where "j \<le> i" "Q j" "\<forall> k < j. \<not> Q k"
    42 proof (induct s, simp)
    42   using assms
    43   fix a s
    43   by (metis ex_least_nat_le le0 not_less0) 
    44   assume ih: "\<lbrakk>Q s; \<not> Q (moment k s)\<rbrakk>
    44 
    45            \<Longrightarrow> \<exists>i<length s. k \<le> i \<and> \<not> Q (moment i s) \<and> (\<forall>i'>i. Q (moment i' s))"
    45 lemma duration_idx:
    46     and nq: "\<not> Q (moment k (a # s))" and qa: "Q (a # s)"
    46   assumes "\<not> Q (i::nat)"
    47   have le_k: "k \<le> length s"
    47   and "Q j"
    48   proof -
    48   and "i \<le> j"
    49     { assume "length s < k"
    49   obtains k where "i \<le> k" "k < j" "\<not> Q k" "\<forall> i'. k < i' \<and> i' \<le> j \<longrightarrow> Q i'" 
    50       hence "length (a#s) \<le> k" by simp
    50 proof -
    51       from moment_ge [OF this] and nq and qa
    51   let ?Q = "\<lambda> t. t \<le> j \<and> \<not> Q (j - t)"
    52       have "False" by auto
    52   have "?Q (j - i)" using assms by (simp add: assms(1)) 
    53     } thus ?thesis by arith
    53   from least_idx [of ?Q, OF this]
    54   qed
    54   obtain l
    55   have nq_k: "\<not> Q (moment k s)"
    55   where h: "l \<le> j - i" "\<not> Q (j - l)" "\<forall>k<l. \<not> (k \<le> j \<and> \<not> Q (j - k))"
    56   proof -
    56     by metis
    57     have "moment k (a#s) = moment k s"
    57   let ?k = "j - l"
    58     proof -
    58   have "i \<le> ?k" using assms(3) h(1) by linarith 
    59       from moment_app [OF le_k, of "[a]"] show ?thesis by simp
    59   moreover have "?k < j" by (metis assms(2) diff_le_self h(2) le_neq_implies_less) 
    60     qed
    60   moreover have "\<not> Q ?k" by (simp add: h(2)) 
    61     with nq show ?thesis by simp
    61   moreover have "\<forall> i'. ?k < i' \<and> i' \<le> j \<longrightarrow> Q i'"
    62   qed
    62       by (metis diff_diff_cancel diff_le_self diff_less_mono2 h(3) 
    63   show "\<exists>i<length (a # s). k \<le> i \<and> \<not> Q (moment i (a # s)) \<and> (\<forall>i'>i. Q (moment i' (a # s)))"
    63               less_imp_diff_less not_less) 
    64   proof -
    64   ultimately show ?thesis using that by metis
    65     { assume "Q s"
       
    66       from ih [OF this nq_k]
       
    67       obtain i where lti: "i < length s" 
       
    68         and nq: "\<not> Q (moment i s)" 
       
    69         and rst: "\<forall>i'>i. Q (moment i' s)" 
       
    70         and lki: "k \<le> i" by auto
       
    71       have ?thesis 
       
    72       proof -
       
    73         from lti have "i < length (a # s)" by auto
       
    74         moreover have " \<not> Q (moment i (a # s))"
       
    75         proof -
       
    76           from lti have "i \<le> (length s)" by simp
       
    77           from moment_app [OF this, of "[a]"]
       
    78           have "moment i (a # s) = moment i s" by simp
       
    79           with nq show ?thesis by auto
       
    80         qed
       
    81         moreover have " (\<forall>i'>i. Q (moment i' (a # s)))"
       
    82         proof -
       
    83           {
       
    84             fix i'
       
    85             assume lti': "i < i'"
       
    86             have "Q (moment i' (a # s))"
       
    87             proof(cases "length (a#s) \<le> i'")
       
    88               case True
       
    89               from True have "moment i' (a#s) = a#s" by simp
       
    90               with qa show ?thesis by simp
       
    91             next
       
    92               case False
       
    93               from False have "i' \<le> length s" by simp
       
    94               from moment_app [OF this, of "[a]"]
       
    95               have "moment i' (a#s) = moment i' s" by simp
       
    96               with rst lti' show ?thesis by auto
       
    97             qed
       
    98           } thus ?thesis by auto
       
    99         qed
       
   100         moreover note lki
       
   101         ultimately show ?thesis by auto
       
   102       qed
       
   103     } moreover {
       
   104       assume ns: "\<not> Q s"
       
   105       have ?thesis
       
   106       proof -
       
   107         let ?i = "length s"
       
   108         have "\<not> Q (moment ?i (a#s))"
       
   109         proof -
       
   110           have "?i \<le> length s" by simp
       
   111           from moment_app [OF this, of "[a]"]
       
   112           have "moment ?i (a#s) = moment ?i s" by simp
       
   113           moreover have "\<dots> = s" by simp
       
   114           ultimately show ?thesis using ns by auto
       
   115         qed
       
   116         moreover have "\<forall> i' > ?i. Q (moment i' (a#s))" 
       
   117         proof -
       
   118           { fix i'
       
   119             assume "i' > ?i"
       
   120             hence "length (a#s) \<le> i'" by simp
       
   121             from moment_ge [OF this] 
       
   122             have " moment i' (a # s) = a # s" .
       
   123             with qa have "Q (moment i' (a#s))" by simp
       
   124           } thus ?thesis by auto
       
   125         qed
       
   126         moreover have "?i < length (a#s)" by simp
       
   127         moreover note le_k
       
   128         ultimately show ?thesis by auto
       
   129       qed
       
   130     } ultimately show ?thesis by auto
       
   131   qed
       
   132 qed
    65 qed
   133 
    66 
       
    67 lemma p_split_gen: 
       
    68   assumes "Q s"
       
    69   and "\<not> Q (moment k s)"
       
    70   shows "(\<exists> i. i < length s \<and> k \<le> i \<and> \<not> Q (moment i s) \<and> (\<forall> i' > i. Q (moment i' s)))"
       
    71 proof(cases "k \<le> length s")
       
    72   case True
       
    73   let ?Q = "\<lambda> t. Q (moment t s)"
       
    74   have "?Q (length s)" using assms(1) by simp
       
    75   from duration_idx[of ?Q, OF assms(2) this True]
       
    76   obtain i where h: "k \<le> i" "i < length s" "\<not> Q (moment i s)"
       
    77     "\<forall>i'. i < i' \<and> i' \<le> length s \<longrightarrow> Q (moment i' s)" by metis
       
    78   moreover have "(\<forall> i' > i. Q (moment i' s))" using h(4) assms(1) not_less
       
    79     by fastforce
       
    80   ultimately show ?thesis by metis
       
    81 qed (insert assms, auto)
       
    82 
   134 lemma p_split: 
    83 lemma p_split: 
   135   "\<lbrakk>Q s; \<not> Q []\<rbrakk> \<Longrightarrow> 
    84   assumes qs: "Q s"
   136        (\<exists> i. i < length s \<and> \<not> Q (moment i s) \<and> (\<forall> i' > i. Q (moment i' s)))"
    85   and nq: "\<not> Q []"
       
    86   shows "(\<exists> i. i < length s \<and> \<not> Q (moment i s) \<and> (\<forall> i' > i. Q (moment i' s)))"
   137 proof -
    87 proof -
   138   fix s Q
       
   139   assume qs: "Q s" and nq: "\<not> Q []"
       
   140   from nq have "\<not> Q (moment 0 s)" by simp
    88   from nq have "\<not> Q (moment 0 s)" by simp
   141   from p_split_gen [of Q s 0, OF qs this]
    89   from p_split_gen [of Q s 0, OF qs this]
   142   show "(\<exists> i. i < length s \<and> \<not> Q (moment i s) \<and> (\<forall> i' > i. Q (moment i' s)))"
    90   show ?thesis by auto
   143     by auto
       
   144 qed
    91 qed
   145 
    92 
   146 lemma moment_Suc_tl:
    93 lemma moment_Suc_tl:
   147   assumes "Suc i \<le> length s"
    94   assumes "Suc i \<le> length s"
   148   shows "tl (moment (Suc i) s) = moment i s"
    95   shows "tl (moment (Suc i) s) = moment i s"
   149   using assms unfolding moment_def rev_take
    96   using assms 
   150   by (simp, metis Suc_diff_le diff_Suc_Suc drop_Suc tl_drop)
    97   by (simp add:moment_def rev_take, 
       
    98       metis Suc_diff_le diff_Suc_Suc drop_Suc tl_drop)
   151   
    99   
   152 lemma moment_plus:
   100 lemma moment_plus:
   153   assumes "Suc i \<le> length s"
   101   assumes "Suc i \<le> length s"
   154   shows "(moment (Suc i) s) = (hd (moment (Suc i) s)) # (moment i s)"
   102   shows "(moment (Suc i) s) = (hd (moment (Suc i) s)) # (moment i s)"
   155 proof -
   103 proof -