// Core Part about Regular Expression Matching
//=============================================
object CW8c {
// Regular Expressions
abstract class Rexp
case object ZERO extends Rexp
case object ONE extends Rexp
case class CHAR(c: Char) extends Rexp
case class ALT(r1: Rexp, r2: Rexp) extends Rexp // alternative
case class SEQ(r1: Rexp, r2: Rexp) extends Rexp // sequence
case class STAR(r: Rexp) extends Rexp // star
// some convenience for typing regular expressions
import scala.language.implicitConversions
import scala.language.reflectiveCalls
def charlist2rexp(s: List[Char]): Rexp = s match {
case Nil => ONE
case c::Nil => CHAR(c)
case c::s => SEQ(CHAR(c), charlist2rexp(s))
}
implicit def string2rexp(s: String): Rexp = charlist2rexp(s.toList)
implicit def RexpOps (r: Rexp) = new {
def | (s: Rexp) = ALT(r, s)
def % = STAR(r)
def ~ (s: Rexp) = SEQ(r, s)
}
implicit def stringOps (s: String) = new {
def | (r: Rexp) = ALT(s, r)
def | (r: String) = ALT(s, r)
def % = STAR(s)
def ~ (r: Rexp) = SEQ(s, r)
def ~ (r: String) = SEQ(s, r)
}
// (1) Complete the function nullable according to
// the definition given in the coursework; this
// function checks whether a regular expression
// can match the empty string and Returns a boolean
// accordingly.
def nullable (r: Rexp) : Boolean = ???
// (2) Complete the function der according to
// the definition given in the coursework; this
// function calculates the derivative of a
// regular expression w.r.t. a character.
def der (c: Char, r: Rexp) : Rexp = ???
// (3) Complete the simp function according to
// the specification given in the coursework; this
// function simplifies a regular expression from
// the inside out, like you would simplify arithmetic
// expressions; however it does not simplify inside
// STAR-regular expressions.
def simp(r: Rexp) : Rexp = ???
// (4) Complete the two functions below; the first
// calculates the derivative w.r.t. a string; the second
// is the regular expression matcher taking a regular
// expression and a string and checks whether the
// string matches the regular expression
def ders (s: List[Char], r: Rexp) : Rexp = ???
def matcher(r: Rexp, s: String): Boolean = ???
// (5) Complete the size function for regular
// expressions according to the specification
// given in the coursework.
def size(r: Rexp): Int = ???
// some testing data
/*
matcher(("a" ~ "b") ~ "c", "abc") // => true
matcher(("a" ~ "b") ~ "c", "ab") // => false
// the supposedly 'evil' regular expression (a*)* b
val EVIL = SEQ(STAR(STAR(CHAR('a'))), CHAR('b'))
matcher(EVIL, "a" * 1000 ++ "b") // => true
matcher(EVIL, "a" * 1000) // => false
// size without simplifications
size(der('a', der('a', EVIL))) // => 28
size(der('a', der('a', der('a', EVIL)))) // => 58
// size with simplification
size(simp(der('a', der('a', EVIL)))) // => 8
size(simp(der('a', der('a', der('a', EVIL))))) // => 8
// Python needs around 30 seconds for matching 28 a's with EVIL.
// Java 9 and later increase this to an "astonishing" 40000 a's in
// 30 seconds.
//
// Lets see how long it really takes to match strings with
// 5 Million a's...it should be in the range of a couple
// of seconds.
def time_needed[T](i: Int, code: => T) = {
val start = System.nanoTime()
for (j <- 1 to i) code
val end = System.nanoTime()
(end - start)/(i * 1.0e9)
}
for (i <- 0 to 5000000 by 500000) {
println(i + " " + "%.5f".format(time_needed(2, matcher(EVIL, "a" * i))))
}
// another "power" test case
simp(Iterator.iterate(ONE:Rexp)(r => SEQ(r, ONE | ONE)).drop(50).next) == ONE
// the Iterator produces the rexp
//
// SEQ(SEQ(SEQ(..., ONE | ONE) , ONE | ONE), ONE | ONE)
//
// where SEQ is nested 50 times.
*/
}