| 401 |      1 | // Core Part 1 about the 3n+1 conjecture
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| 430 |      2 | //============================================
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|  |      3 | 
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|  |      4 | object C1 {
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|  |      5 | 
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|  |      6 | // ADD YOUR CODE BELOW
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|  |      7 | //======================
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| 363 |      8 | 
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| 430 |      9 | // test1 7 Nov
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|  |     10 | // test2
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|  |     11 | // test3
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|  |     12 | // test4
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| 363 |     13 | 
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| 208 |     14 | 
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| 430 |     15 | //(1) 
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|  |     16 | def collatz(n: Long) : Long = 
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| 363 |     17 |   if (n == 1) 0 else
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|  |     18 |     if (n % 2 == 0) 1 + collatz(n / 2) else 
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|  |     19 |       1 + collatz(3 * n + 1)
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| 208 |     20 | 
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| 363 |     21 | 
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| 430 |     22 | //(2) 
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|  |     23 | //def collatz_max(bnd: Long) : (Long, Long) = {
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|  |     24 | //  val all = for (i <- (1L to bnd)) yield (collatz(i), i)
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|  |     25 | //  all.maxBy(_._1)
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|  |     26 | //}
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|  |     27 | 
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| 363 |     28 | def collatz_max(bnd: Long): (Long, Long) = {
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|  |     29 |   val all = for (i <- (1L to bnd)) yield (collatz(i), i)
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|  |     30 |   all.maxBy(_._1)
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|  |     31 | }
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| 208 |     32 | 
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|  |     33 | 
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| 401 |     34 | 
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| 430 |     35 | //(3)
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|  |     36 | 
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|  |     37 | def is_pow_of_two(n: Long) : Boolean = (n & (n - 1)) == 0
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| 363 |     38 | 
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| 430 |     39 | def is_hard(n: Long) : Boolean = is_pow_of_two(3 * n + 1)
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| 363 |     40 | 
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| 430 |     41 | def last_odd(n: Long) : Long = if (is_hard(n)) n else
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| 363 |     42 |     if (n % 2 == 0) last_odd(n / 2) else 
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|  |     43 |       last_odd(3 * n + 1)
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| 335 |     44 | 
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| 363 |     45 | }
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| 335 |     46 | 
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|  |     47 | 
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|  |     48 | 
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| 430 |     49 | // This template code is subject to copyright 
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|  |     50 | // by King's College London, 2022. Do not 
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|  |     51 | // make the template code public in any shape 
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|  |     52 | // or form, and do not exchange it with other 
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|  |     53 | // students under any circumstance.
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