Automatic cleaning of Bexeq<->Ex1 theorems.
--- a/Quot/Examples/IntEx.thy Thu Jan 21 10:55:09 2010 +0100
+++ b/Quot/Examples/IntEx.thy Thu Jan 21 11:11:22 2010 +0100
@@ -195,9 +195,6 @@
apply injection
apply (rule quot_respect(9))
apply (rule Quotient_my_int)
-
-apply(cleaning)
-apply (simp add: ex1_prs[OF Quotient_my_int])
done
lemma ho_tst: "foldl my_plus x [] = x"
--- a/Quot/QuotScript.thy Thu Jan 21 10:55:09 2010 +0100
+++ b/Quot/QuotScript.thy Thu Jan 21 11:11:22 2010 +0100
@@ -468,7 +468,8 @@
lemma ex1_prs:
assumes a: "Quotient R absf repf"
- shows "Bexeq R ((absf ---> id) f) = Ex1 f"
+ shows "((absf ---> id) ---> id) (Bexeq R) f = Ex1 f"
+apply simp
apply (subst Bexeq_def)
apply (subst Bex_def)
apply (subst Ex1_def)
--- a/Quot/quotient_tacs.ML Thu Jan 21 10:55:09 2010 +0100
+++ b/Quot/quotient_tacs.ML Thu Jan 21 11:11:22 2010 +0100
@@ -500,7 +500,7 @@
(* Cleaning consists of:
1. folding of definitions and preservation lemmas;
- and simplification with babs_prs all_prs ex_prs
+ and simplification with babs_prs all_prs ex_prs ex1_prs
2. unfolding of ---> in front of everything, except
bound variables
@@ -509,6 +509,7 @@
3. simplification with lambda_prs
4. simplification with Quotient_abs_rep Quotient_rel_rep id_simps
+ and ex1_prs (since it may need lambdas to be folded).
5. test for refl
*)
@@ -520,8 +521,8 @@
val ids = id_simps_get lthy
fun mk_simps thms = (mk_minimal_ss lthy) addsimps thms addSolver quotient_solver
- val ss1 = mk_simps (defs @ prs @ @{thms babs_prs all_prs ex_prs})
- val ss2 = mk_simps (@{thms Quotient_abs_rep Quotient_rel_rep} @ ids)
+ val ss1 = mk_simps (defs @ prs @ @{thms babs_prs all_prs ex_prs ex1_prs})
+ val ss2 = mk_simps (@{thms Quotient_abs_rep Quotient_rel_rep ex1_prs} @ ids)
in
EVERY' [simp_tac ss1,
fun_map_tac lthy,