diff -r c46b6abad24b -r dae99175f584 Quot/QuotBase.thy --- /dev/null Thu Jan 01 00:00:00 1970 +0000 +++ b/Quot/QuotBase.thy Mon Jan 25 18:13:44 2010 +0100 @@ -0,0 +1,694 @@ +(* Title: QuotBase.thy + Author: Cezary Kaliszyk and Christian Urban +*) + +theory QuotBase +imports Plain ATP_Linkup Predicate +begin + +text {* + Basic definition for equivalence relations + that are represented by predicates. +*} + +definition + "equivp E \ \x y. E x y = (E x = E y)" + +definition + "reflp E \ \x. E x x" + +definition + "symp E \ \x y. E x y \ E y x" + +definition + "transp E \ \x y z. E x y \ E y z \ E x z" + +lemma equivp_reflp_symp_transp: + shows "equivp E = (reflp E \ symp E \ transp E)" + unfolding equivp_def reflp_def symp_def transp_def expand_fun_eq + by blast + +lemma equivp_reflp: + shows "equivp E \ (\x. E x x)" + by (simp only: equivp_reflp_symp_transp reflp_def) + +lemma equivp_symp: + shows "equivp E \ (\x y. E x y \ E y x)" + by (metis equivp_reflp_symp_transp symp_def) + +lemma equivp_transp: + shows "equivp E \ (\x y z. E x y \ E y z \ E x z)" + by (metis equivp_reflp_symp_transp transp_def) + +lemma equivpI: + assumes "reflp R" "symp R" "transp R" + shows "equivp R" + using assms by (simp add: equivp_reflp_symp_transp) + +lemma eq_imp_rel: + shows "equivp R \ a = b \ R a b" +by (simp add: equivp_reflp) + +text {* Partial equivalences: not yet used anywhere *} +definition + "part_equivp E \ (\x. E x x) \ (\x y. E x y = (E x x \ E y y \ (E x = E y)))" + +lemma equivp_IMP_part_equivp: + assumes a: "equivp E" + shows "part_equivp E" + using a + unfolding equivp_def part_equivp_def + by auto + +text {* Composition of Relations *} +abbreviation + rel_conj (infixr "OOO" 75) +where + "r1 OOO r2 \ r1 OO r2 OO r1" + +section {* Quotient Predicate *} + +definition + "Quotient E Abs Rep \ + (\a. Abs (Rep a) = a) \ (\a. E (Rep a) (Rep a)) \ + (\r s. E r s = (E r r \ E s s \ (Abs r = Abs s)))" + +lemma Quotient_abs_rep: + assumes a: "Quotient E Abs Rep" + shows "Abs (Rep a) = a" + using a + unfolding Quotient_def + by simp + +lemma Quotient_rep_reflp: + assumes a: "Quotient E Abs Rep" + shows "E (Rep a) (Rep a)" + using a + unfolding Quotient_def + by blast + +lemma Quotient_rel: + assumes a: "Quotient E Abs Rep" + shows " E r s = (E r r \ E s s \ (Abs r = Abs s))" + using a + unfolding Quotient_def + by blast + +lemma Quotient_rel_rep: + assumes a: "Quotient R Abs Rep" + shows "R (Rep a) (Rep b) = (a = b)" + using a + unfolding Quotient_def + by metis + +lemma Quotient_rep_abs: + assumes a: "Quotient R Abs Rep" + shows "R r r \ R (Rep (Abs r)) r" + using a unfolding Quotient_def + by blast + +lemma Quotient_rel_abs: + assumes a: "Quotient E Abs Rep" + shows "E r s \ Abs r = Abs s" + using a unfolding Quotient_def + by blast + +lemma Quotient_symp: + assumes a: "Quotient E Abs Rep" + shows "symp E" + using a unfolding Quotient_def symp_def + by metis + +lemma Quotient_transp: + assumes a: "Quotient E Abs Rep" + shows "transp E" + using a unfolding Quotient_def transp_def + by metis + +section {* Lemmas about (op =) *} + +lemma identity_equivp: + shows "equivp (op =)" + unfolding equivp_def + by auto + +lemma identity_quotient: + shows "Quotient (op =) id id" + unfolding Quotient_def id_def + by blast + +section {* Function map and function relation *} + +definition + fun_map (infixr "--->" 55) +where +[simp]: "fun_map f g h x = g (h (f x))" + +definition + fun_rel (infixr "===>" 55) +where +[simp]: "fun_rel E1 E2 f g = (\x y. E1 x y \ E2 (f x) (g y))" + + +lemma fun_map_id: + shows "(id ---> id) = id" + by (simp add: expand_fun_eq id_def) + +lemma fun_rel_eq: + shows "(op =) ===> (op =) \ (op =)" + by (rule eq_reflection) (simp add: expand_fun_eq) + +lemma fun_quotient: + assumes q1: "Quotient R1 abs1 rep1" + and q2: "Quotient R2 abs2 rep2" + shows "Quotient (R1 ===> R2) (rep1 ---> abs2) (abs1 ---> rep2)" +proof - + have "\a. (rep1 ---> abs2) ((abs1 ---> rep2) a) = a" + apply(simp add: expand_fun_eq) + using q1 q2 + apply(simp add: Quotient_def) + done + moreover + have "\a. (R1 ===> R2) ((abs1 ---> rep2) a) ((abs1 ---> rep2) a)" + apply(auto) + using q1 q2 unfolding Quotient_def + apply(metis) + done + moreover + have "\r s. (R1 ===> R2) r s = ((R1 ===> R2) r r \ (R1 ===> R2) s s \ + (rep1 ---> abs2) r = (rep1 ---> abs2) s)" + apply(auto simp add: expand_fun_eq) + using q1 q2 unfolding Quotient_def + apply(metis) + using q1 q2 unfolding Quotient_def + apply(metis) + using q1 q2 unfolding Quotient_def + apply(metis) + using q1 q2 unfolding Quotient_def + apply(metis) + done + ultimately + show "Quotient (R1 ===> R2) (rep1 ---> abs2) (abs1 ---> rep2)" + unfolding Quotient_def by blast +qed + +section {* Respects predicate *} + +definition + Respects +where + "Respects R x \ (R x x)" + +lemma in_respects: + shows "(x \ Respects R) = R x x" + unfolding mem_def Respects_def by simp + +lemma equals_rsp: + assumes q: "Quotient R Abs Rep" + and a: "R xa xb" "R ya yb" + shows "R xa ya = R xb yb" + using Quotient_symp[OF q] Quotient_transp[OF q] unfolding symp_def transp_def + using a by blast + +lemma lambda_prs: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + shows "(Rep1 ---> Abs2) (\x. Rep2 (f (Abs1 x))) = (\x. f x)" + unfolding expand_fun_eq + using Quotient_abs_rep[OF q1] Quotient_abs_rep[OF q2] + by simp + +lemma lambda_prs1: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + shows "(Rep1 ---> Abs2) (\x. (Abs1 ---> Rep2) f x) = (\x. f x)" + unfolding expand_fun_eq + using Quotient_abs_rep[OF q1] Quotient_abs_rep[OF q2] + by simp + +lemma rep_abs_rsp: + assumes q: "Quotient R Abs Rep" + and a: "R x1 x2" + shows "R x1 (Rep (Abs x2))" + using q a by (metis Quotient_rel[OF q] Quotient_abs_rep[OF q] Quotient_rep_reflp[OF q]) + +lemma rep_abs_rsp_left: + assumes q: "Quotient R Abs Rep" + and a: "R x1 x2" + shows "R (Rep (Abs x1)) x2" +using q a by (metis Quotient_rel[OF q] Quotient_abs_rep[OF q] Quotient_rep_reflp[OF q]) + +(* In the following theorem R1 can be instantiated with anything, + but we know some of the types of the Rep and Abs functions; + so by solving Quotient assumptions we can get a unique R1 that + will be provable; which is why we need to use apply_rsp and + not the primed version *) +lemma apply_rsp: + fixes f g::"'a \ 'c" + assumes q: "Quotient R1 Abs1 Rep1" + and a: "(R1 ===> R2) f g" "R1 x y" + shows "R2 (f x) (g y)" + using a by simp + +lemma apply_rsp': + assumes a: "(R1 ===> R2) f g" "R1 x y" + shows "R2 (f x) (g y)" + using a by simp + +(* Set of lemmas for regularisation of ball and bex *) + +lemma ball_reg_eqv: + fixes P :: "'a \ bool" + assumes a: "equivp R" + shows "Ball (Respects R) P = (All P)" + by (metis equivp_def in_respects a) + +lemma bex_reg_eqv: + fixes P :: "'a \ bool" + assumes a: "equivp R" + shows "Bex (Respects R) P = (Ex P)" + by (metis equivp_def in_respects a) + +lemma ball_reg_right: + assumes a: "\x. R x \ P x \ Q x" + shows "All P \ Ball R Q" + by (metis COMBC_def Collect_def Collect_mem_eq a) + +lemma bex_reg_left: + assumes a: "\x. R x \ Q x \ P x" + shows "Bex R Q \ Ex P" + by (metis COMBC_def Collect_def Collect_mem_eq a) + +lemma ball_reg_left: + assumes a: "equivp R" + shows "(\x. (Q x \ P x)) \ Ball (Respects R) Q \ All P" + by (metis equivp_reflp in_respects a) + +lemma bex_reg_right: + assumes a: "equivp R" + shows "(\x. (Q x \ P x)) \ Ex Q \ Bex (Respects R) P" + by (metis equivp_reflp in_respects a) + +lemma ball_reg_eqv_range: + fixes P::"'a \ bool" + and x::"'a" + assumes a: "equivp R2" + shows "(Ball (Respects (R1 ===> R2)) (\f. P (f x)) = All (\f. P (f x)))" + apply(rule iffI) + apply(rule allI) + apply(drule_tac x="\y. f x" in bspec) + apply(simp add: in_respects) + apply(rule impI) + using a equivp_reflp_symp_transp[of "R2"] + apply(simp add: reflp_def) + apply(simp) + apply(simp) + done + +lemma bex_reg_eqv_range: + assumes a: "equivp R2" + shows "(Bex (Respects (R1 ===> R2)) (\f. P (f x)) = Ex (\f. P (f x)))" + apply(auto) + apply(rule_tac x="\y. f x" in bexI) + apply(simp) + apply(simp add: Respects_def in_respects) + apply(rule impI) + using a equivp_reflp_symp_transp[of "R2"] + apply(simp add: reflp_def) + done + +lemma all_reg: + assumes a: "!x :: 'a. (P x --> Q x)" + and b: "All P" + shows "All Q" + using a b by (metis) + +lemma ex_reg: + assumes a: "!x :: 'a. (P x --> Q x)" + and b: "Ex P" + shows "Ex Q" + using a b by (metis) + +lemma ball_reg: + assumes a: "!x :: 'a. (R x --> P x --> Q x)" + and b: "Ball R P" + shows "Ball R Q" + using a b by (metis COMBC_def Collect_def Collect_mem_eq) + +lemma bex_reg: + assumes a: "!x :: 'a. (R x --> P x --> Q x)" + and b: "Bex R P" + shows "Bex R Q" + using a b by (metis COMBC_def Collect_def Collect_mem_eq) + +lemma ball_all_comm: + "(\y. (\x\P. A x y) \ (\x. B x y)) \ ((\x\P. \y. A x y) \ (\x. \y. B x y))" + by auto + +lemma bex_ex_comm: + "((\y. \x. A x y) \ (\y. \x\P. B x y)) \ ((\x. \y. A x y) \ (\x\P. \y. B x y))" + by auto + +(* Bounded abstraction *) +definition + Babs :: "('a \ bool) \ ('a \ 'b) \ 'a \ 'b" +where + "(x \ p) \ (Babs p m x = m x)" + +definition + Bexeq :: "('a \ 'a \ bool) \ ('a \ bool) \ bool" +where + "Bexeq R P \ (\x \ Respects R. P x) \ (\x \ Respects R. \y \ Respects R. ((P x \ P y) \ (R x y)))" + +(* 3 lemmas needed for proving repabs_inj *) +lemma ball_rsp: + assumes a: "(R ===> (op =)) f g" + shows "Ball (Respects R) f = Ball (Respects R) g" + using a by (simp add: Ball_def in_respects) + +lemma bex_rsp: + assumes a: "(R ===> (op =)) f g" + shows "(Bex (Respects R) f = Bex (Respects R) g)" + using a by (simp add: Bex_def in_respects) + +lemma bex1_rsp: + assumes a: "(R ===> (op =)) f g" + shows "(Bex1 (Respects R) f = Bex1 (Respects R) g)" + using a +by (simp add: Ex1_def Bex1_def in_respects) auto + +(* TODO/FIXME: simplify the repetitions in this proof *) +lemma bexeq_rsp: +assumes a: "Quotient R absf repf" +shows "((R ===> op =) ===> op =) (Bexeq R) (Bexeq R)" +apply simp +unfolding Bexeq_def +apply rule +apply rule +apply rule +apply rule +apply (erule conjE)+ +apply (erule bexE) +apply rule +apply (rule_tac x="xa" in bexI) +apply metis +apply metis +apply rule+ +apply (erule_tac x="xb" in ballE) +prefer 2 +apply (metis) +apply (erule_tac x="ya" in ballE) +prefer 2 +apply (metis) +apply (metis in_respects) +apply (erule conjE)+ +apply (erule bexE) +apply rule +apply (rule_tac x="xa" in bexI) +apply metis +apply metis +apply rule+ +apply (erule_tac x="xb" in ballE) +prefer 2 +apply (metis) +apply (erule_tac x="ya" in ballE) +prefer 2 +apply (metis) +apply (metis in_respects) +done + +lemma babs_rsp: + assumes q: "Quotient R1 Abs1 Rep1" + and a: "(R1 ===> R2) f g" + shows "(R1 ===> R2) (Babs (Respects R1) f) (Babs (Respects R1) g)" + apply (auto simp add: Babs_def) + apply (subgoal_tac "x \ Respects R1 \ y \ Respects R1") + using a apply (simp add: Babs_def) + apply (simp add: in_respects) + using Quotient_rel[OF q] + by metis + +lemma babs_prs: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + shows "(Rep1 ---> Abs2) (Babs (Respects R1) ((Abs1 ---> Rep2) f)) \ f" + apply(rule eq_reflection) + apply(rule ext) + apply simp + apply (subgoal_tac "Rep1 x \ Respects R1") + apply (simp add: Babs_def Quotient_abs_rep[OF q1] Quotient_abs_rep[OF q2]) + apply (simp add: in_respects Quotient_rel_rep[OF q1]) + done + +lemma babs_simp: + assumes q: "Quotient R1 Abs Rep" + shows "((R1 ===> R2) (Babs (Respects R1) f) (Babs (Respects R1) g)) = ((R1 ===> R2) f g)" + apply(rule iffI) + apply(simp_all only: babs_rsp[OF q]) + apply(auto simp add: Babs_def) + apply (subgoal_tac "x \ Respects R1 \ y \ Respects R1") + apply(metis Babs_def) + apply (simp add: in_respects) + using Quotient_rel[OF q] + by metis + +(* If a user proves that a particular functional relation + is an equivalence this may be useful in regularising *) +lemma babs_reg_eqv: + shows "equivp R \ Babs (Respects R) P = P" + by (simp add: expand_fun_eq Babs_def in_respects equivp_reflp) + +(* 3 lemmas needed for cleaning of quantifiers *) +lemma all_prs: + assumes a: "Quotient R absf repf" + shows "Ball (Respects R) ((absf ---> id) f) = All f" + using a unfolding Quotient_def Ball_def in_respects fun_map_def id_apply +by metis + +lemma ex_prs: + assumes a: "Quotient R absf repf" + shows "Bex (Respects R) ((absf ---> id) f) = Ex f" + using a unfolding Quotient_def Bex_def in_respects fun_map_def id_apply + by metis + +lemma ex1_prs: + assumes a: "Quotient R absf repf" + shows "((absf ---> id) ---> id) (Bexeq R) f = Ex1 f" +apply simp +apply (subst Bexeq_def) +apply (subst Bex_def) +apply (subst Ex1_def) +apply simp +apply rule + apply (erule conjE)+ + apply (erule_tac exE) + apply (erule conjE) + apply (subgoal_tac "\y. R y y \ f (absf y) \ R x y") + apply (rule_tac x="absf x" in exI) + apply (thin_tac "\x\Respects R. \y\Respects R. f (absf x) \ f (absf y) \ R x y") + apply (simp) + apply rule+ + using a unfolding Quotient_def + apply metis + apply rule+ + apply (erule_tac x="x" in ballE) + apply (erule_tac x="y" in ballE) + apply simp + apply (simp add: in_respects) + apply (simp add: in_respects) +apply (erule_tac exE) + apply rule + apply (rule_tac x="repf x" in exI) + apply (simp only: in_respects) + apply rule + apply (metis Quotient_rel_rep[OF a]) +using a unfolding Quotient_def apply (simp) +apply rule+ +using a unfolding Quotient_def in_respects +apply metis +done + +lemma fun_rel_id: + assumes a: "\x y. R1 x y \ R2 (f x) (g y)" + shows "(R1 ===> R2) f g" + using a by simp + +lemma fun_rel_id_asm: + assumes a: "\x y. R1 x y \ (A \ R2 (f x) (g y))" + shows "A \ (R1 ===> R2) f g" + using a by auto + +lemma quot_rel_rsp: + assumes a: "Quotient R Abs Rep" + shows "(R ===> R ===> op =) R R" + apply(rule fun_rel_id)+ + apply(rule equals_rsp[OF a]) + apply(assumption)+ + done + +lemma o_prs: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + and q3: "Quotient R3 Abs3 Rep3" + shows "(Rep1 ---> Abs3) (((Abs2 ---> Rep3) f) o ((Abs1 ---> Rep2) g)) = f o g" + using Quotient_abs_rep[OF q1] Quotient_abs_rep[OF q2] Quotient_abs_rep[OF q3] + unfolding o_def expand_fun_eq by simp + +lemma o_rsp: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + and q3: "Quotient R3 Abs3 Rep3" + and a1: "(R2 ===> R3) f1 f2" + and a2: "(R1 ===> R2) g1 g2" + shows "(R1 ===> R3) (f1 o g1) (f2 o g2)" + using a1 a2 unfolding o_def expand_fun_eq + by (auto) + +lemma cond_prs: + assumes a: "Quotient R absf repf" + shows "absf (if a then repf b else repf c) = (if a then b else c)" + using a unfolding Quotient_def by auto + +lemma if_prs: + assumes q: "Quotient R Abs Rep" + shows "Abs (If a (Rep b) (Rep c)) = If a b c" +using Quotient_abs_rep[OF q] by auto + +(* q not used *) +lemma if_rsp: + assumes q: "Quotient R Abs Rep" + and a: "a1 = a2" "R b1 b2" "R c1 c2" + shows "R (If a1 b1 c1) (If a2 b2 c2)" +using a by auto + +lemma let_prs: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + shows "Abs2 (Let (Rep1 x) ((Abs1 ---> Rep2) f)) = Let x f" + using Quotient_abs_rep[OF q1] Quotient_abs_rep[OF q2] by auto + +lemma let_rsp: + assumes q1: "Quotient R1 Abs1 Rep1" + and a1: "(R1 ===> R2) f g" + and a2: "R1 x y" + shows "R2 ((Let x f)::'c) ((Let y g)::'c)" + using apply_rsp[OF q1 a1] a2 by auto + + + + +(******************************************) +(* REST OF THE FILE IS UNUSED (until now) *) +(******************************************) + +lemma in_fun: + shows "x \ ((f ---> g) s) = g (f x \ s)" + by (simp add: mem_def) + +lemma respects_thm: + shows "Respects (R1 ===> R2) f = (\x y. R1 x y \ R2 (f x) (f y))" + unfolding Respects_def + by (simp add: expand_fun_eq) + +lemma respects_rep_abs: + assumes a: "Quotient R1 Abs1 Rep1" + and b: "Respects (R1 ===> R2) f" + and c: "R1 x x" + shows "R2 (f (Rep1 (Abs1 x))) (f x)" + using a b[simplified respects_thm] c unfolding Quotient_def + by blast + +lemma respects_mp: + assumes a: "Respects (R1 ===> R2) f" + and b: "R1 x y" + shows "R2 (f x) (f y)" + using a b unfolding Respects_def + by simp + +lemma respects_o: + assumes a: "Respects (R2 ===> R3) f" + and b: "Respects (R1 ===> R2) g" + shows "Respects (R1 ===> R3) (f o g)" + using a b unfolding Respects_def + by simp + +lemma abs_o_rep: + assumes a: "Quotient r absf repf" + shows "absf o repf = id" + apply(rule ext) + apply(simp add: Quotient_abs_rep[OF a]) + done + +lemma eq_comp_r: "op = OO R OO op = \ R" + apply (rule eq_reflection) + apply (rule ext)+ + apply auto + done + +lemma fun_rel_eq_rel: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + shows "(R1 ===> R2) f g = ((Respects (R1 ===> R2) f) \ (Respects (R1 ===> R2) g) + \ ((Rep1 ---> Abs2) f = (Rep1 ---> Abs2) g))" + using fun_quotient[OF q1 q2] unfolding Respects_def Quotient_def expand_fun_eq + by blast + +lemma let_babs: + "v \ r \ Let v (Babs r lam) = Let v lam" + by (simp add: Babs_def) + +lemma fun_rel_equals: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + and r1: "Respects (R1 ===> R2) f" + and r2: "Respects (R1 ===> R2) g" + shows "((Rep1 ---> Abs2) f = (Rep1 ---> Abs2) g) = (\x y. R1 x y \ R2 (f x) (g y))" + apply(rule_tac iffI) + apply(rule)+ + apply (rule apply_rsp'[of "R1" "R2"]) + apply(subst Quotient_rel[OF fun_quotient[OF q1 q2]]) + apply auto + using fun_quotient[OF q1 q2] r1 r2 unfolding Quotient_def Respects_def + apply (metis let_rsp q1) + apply (metis fun_rel_eq_rel let_rsp q1 q2 r2) + using r1 unfolding Respects_def expand_fun_eq + apply(simp (no_asm_use)) + apply(metis Quotient_rel[OF q2] Quotient_rel_rep[OF q1]) + done + +(* ask Peter: fun_rel_IMP used twice *) +lemma fun_rel_IMP2: + assumes q1: "Quotient R1 Abs1 Rep1" + and q2: "Quotient R2 Abs2 Rep2" + and r1: "Respects (R1 ===> R2) f" + and r2: "Respects (R1 ===> R2) g" + and a: "(Rep1 ---> Abs2) f = (Rep1 ---> Abs2) g" + shows "R1 x y \ R2 (f x) (g y)" + using q1 q2 r1 r2 a + by (simp add: fun_rel_equals) + +lemma lambda_rep_abs_rsp: + assumes r1: "\r r'. R1 r r' \R1 r (Rep1 (Abs1 r'))" + and r2: "\r r'. R2 r r' \R2 r (Rep2 (Abs2 r'))" + shows "(R1 ===> R2) f1 f2 \ (R1 ===> R2) f1 ((Abs1 ---> Rep2) ((Rep1 ---> Abs2) f2))" + using r1 r2 by auto + +(* ask peter what are literal_case *) +(* literal_case_PRS *) +(* literal_case_RSP *) +(* Cez: !f x. literal_case f x = f x *) + +(* We use id_simps which includes id_apply; so these 2 theorems can be removed *) +lemma id_prs: + assumes q: "Quotient R Abs Rep" + shows "Abs (id (Rep e)) = id e" + using Quotient_abs_rep[OF q] by auto + +lemma id_rsp: + assumes q: "Quotient R Abs Rep" + and a: "R e1 e2" + shows "R (id e1) (id e2)" + using a by auto + +end +