diff -r e2be455093a1 -r b38f8d5e0b09 Slides/Slides3.thy --- a/Slides/Slides3.thy Sun Jul 11 00:58:54 2010 +0100 +++ b/Slides/Slides3.thy Sun Jul 11 21:18:02 2010 +0100 @@ -9,24 +9,54 @@ (*>*) +text_raw {* + \renewcommand{\slidecaption}{UNIF, Edinburgh, 14.~July 2010} + %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% + \mode{ + \begin{frame}<1>[c] + \frametitle{Quiz} + + Assuming that \smath{a} and \smath{b} are distinct variables,\\ + is it possible to find $\lambda$-terms \smath{M_1} to \smath{M_7} + that make the following pairs \alert{$\alpha$-equivalent}? + + \begin{tabular}{@ {\hspace{14mm}}p{12cm}} + \begin{itemize} + \item \smath{\lambda a.\lambda b. (M_1\,b)\;} and + \smath{\lambda b.\lambda a. (a\,M_1)\;} + + \item \smath{\lambda a.\lambda b. (M_2\,b)\;} and + \smath{\lambda b.\lambda a. (a\,M_3)\;} + + \item \smath{\lambda a.\lambda b. (b\,M_4)\;} and + \smath{\lambda b.\lambda a. (a\,M_5)\;} + + \item \smath{\lambda a.\lambda b. (b\,M_6)\;} and + \smath{\lambda a.\lambda a. (a\,M_7)\;} + \end{itemize} + \end{tabular} + + If there is one solution for a pair, can you describe all its solutions? + + \end{frame}} + %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% +*} text_raw {* - \renewcommand{\slidecaption}{Cambridge, 8.~June 2010} %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \mode{ \begin{frame}<1>[t] \frametitle{% \begin{tabular}{@ {\hspace{-3mm}}c@ {}} \\ - \huge Nominal 2\\[-2mm] - \large Or, How to Reason Conveniently with\\[-5mm] - \large General Bindings in Isabelle/HOL\\[5mm] + \huge Nominal Unification\\[-2mm] + \Large Hitting a Sweet Spot\\[5mm] \end{tabular}} \begin{center} Christian Urban \end{center} \begin{center} - joint work with {\bf Cezary Kaliszyk}\\[0mm] + \small initial work with Andy Pitts and Jamie Gabbay\\[0mm] \end{center} \end{frame}} %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%