ChengsongTanPhdThesis/Chapters/Finite.tex
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% Chapter Template
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\chapter{Finiteness Bound} % Main chapter title
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\label{Finite} 
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%  In Chapter 4 \ref{Chapter4} we give the second guarantee
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%of our bitcoded algorithm, that is a finite bound on the size of any 
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%regex's derivatives. 
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In this chapter we give a guarantee in terms of size: 
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given an annotated regular expression $a$, for any string $s$
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our algorithm $\blexersimp$'s internal annotated regular expression 
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size  is finitely bounded
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by a constant $N_a$ that only depends on $a$:
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\begin{center}
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	$\llbracket \bderssimp{a}{s} \rrbracket \leq N_a$
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\end{center}
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\noindent
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where the size of an annotated regular expression is defined
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in terms of the number of nodes in its tree structure:
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\begin{center}
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	\begin{tabular}{ccc}
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		$\llbracket _{bs}\ONE \rrbracket$ & $\dn$ & $1$\\
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		$\llbracket \ZERO \rrbracket$ & $\dn$ & $1$ \\
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		$\llbracket _{bs} r_1 \cdot r_2 \rrbracket$ & $\dn$ & $\llbracket r_1 \rrbracket + \llbracket r_2 \rrbracket + 1$\\
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		$\llbracket _{bs}\mathbf{c} \rrbracket $ & $\dn$ & $1$\\
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		$\llbracket _{bs}\sum as \rrbracket $ & $\dn$ & $\map \; (\llbracket \_ \rrbracket)\; as   + 1$\\
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		$\llbracket _{bs} a^* \rrbracket $ & $\dn$ & $\llbracket a \rrbracket + 1$.
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	\end{tabular}
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\end{center}
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We believe this size formalisation 
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of the algorithm is important in our context, because 
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\begin{itemize}
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	\item
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		It is a stepping stone towards an ``absence of catastrophic-backtracking''
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		guarantee. The next step would be to refine the bound $N_a$ so that it
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		is polynomial on $\llbracket a\rrbracket$.
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	\item
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		The size bound proof gives us a higher confidence that
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		our simplification algorithm $\simp$ does not ``mis-behave''
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		like $\simpsulz$ does.
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		The bound is universal, which is an advantage over work which 
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		only gives empirical evidence on some test cases.
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\end{itemize}
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\section{Formalising About Size}
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\noindent
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In our lexer $\blexersimp$,
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The regular expression is repeatedly being taken derivative of
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and then simplified.
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\begin{figure}[H]
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	\begin{tikzpicture}[scale=2,
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		every node/.style={minimum size=11mm},
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		->,>=stealth',shorten >=1pt,auto,thick
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		]
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		\node (r0) [rectangle, draw=black, thick, minimum size = 5mm, draw=blue] {$a$};
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		\node (r1) [rectangle, draw=black, thick, right=of r0, minimum size = 7mm]{$a_1$};
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		\draw[->,line width=0.2mm](r0)--(r1) node[above,midway] {$\backslash c_1$};
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		\node (r1s) [rectangle, draw=blue, thick, right=of r1, minimum size=6mm]{$a_{1s}$};
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		\draw[->, line width=0.2mm](r1)--(r1s) node[above, midway] {$\simp$};
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		\node (r2) [rectangle, draw=black, thick,  right=of r1s, minimum size = 12mm]{$a_2$};
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		\draw[->,line width=0.2mm](r1s)--(r2) node[above,midway] {$\backslash c_2$};
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		\node (r2s) [rectangle, draw = blue, thick, right=of r2,minimum size=6mm]{$a_{2s}$};
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		\draw[->,line width=0.2mm](r2)--(r2s) node[above,midway] {$\simp$};
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		\node (rns) [rectangle, draw = blue, thick, right=of r2s,minimum size=6mm]{$a_{ns}$};
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		\draw[->,line width=0.2mm, dashed](r2s)--(rns) node[above,midway] {$\backslash \ldots$};
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		\node (v) [circle, thick, draw, right=of rns, minimum size=6mm, right=1.7cm]{$v$};
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		\draw[->, line width=0.2mm](rns)--(v) node[above, midway] {\bmkeps} node [below, midway] {\decode};
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	\end{tikzpicture}
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	\caption{Regular expression size change during our $\blexersimp$ algorithm}\label{simpShrinks}
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\end{figure}
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\noindent
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Each time
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a derivative is taken, a regular expression might grow a bit,
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but simplification always takes care that 
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it stays small.
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This intuition is depicted by the relative size
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change between the black and blue nodes:
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After $\simp$ the node always shrinks.
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Our proof says that all the blue nodes
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stay below a size bound $N_a$ determined by $a$.
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\noindent
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Sulzmann and Lu's assumed something similar about their algorithm,
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though in fact their algorithm's size might be better depicted by the following graph:
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\begin{figure}[H]
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	\begin{tikzpicture}[scale=2,
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		every node/.style={minimum size=11mm},
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		->,>=stealth',shorten >=1pt,auto,thick
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		]
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		\node (r0) [rectangle, draw=black, thick, minimum size = 5mm, draw=blue] {$a$};
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		\node (r1) [rectangle, draw=black, thick, right=of r0, minimum size = 7mm]{$a_1$};
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		\draw[->,line width=0.2mm](r0)--(r1) node[above,midway] {$\backslash c_1$};
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		\node (r1s) [rectangle, draw=blue, thick, right=of r1, minimum size=7mm]{$a_{1s}$};
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		\draw[->, line width=0.2mm](r1)--(r1s) node[above, midway] {$\simp'$};
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		\node (r2) [rectangle, draw=black, thick,  right=of r1s, minimum size = 17mm]{$a_2$};
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		\draw[->,line width=0.2mm](r1s)--(r2) node[above,midway] {$\backslash c_2$};
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		\node (r2s) [rectangle, draw = blue, thick, right=of r2,minimum size=14mm]{$a_{2s}$};
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		\draw[->,line width=0.2mm](r2)--(r2s) node[above,midway] {$\simp'$};
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		\node (r3) [rectangle, draw = black, thick, right= of r2s, minimum size = 22mm]{$a_3$};
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		\draw[->,line width=0.2mm](r2s)--(r3) node[above,midway] {$\backslash c_3$};
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		\node (rns) [right = of r3, draw=blue, minimum size = 20mm]{$a_{3s}$};
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		\draw[->,line width=0.2mm] (r3)--(rns) node [above, midway] {$\simp'$};
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		\node (rnn) [right = of rns, minimum size = 1mm]{};
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		\draw[->, dashed] (rns)--(rnn) node [above, midway] {$\ldots$};
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	\end{tikzpicture}
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	\caption{Regular expression size change during our $\blexersimp$ algorithm}\label{sulzShrinks}
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\end{figure}
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\noindent
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That is, on certain cases their lexer 
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will have an indefinite size explosion, causing the running time 
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of each derivative step to grow arbitrarily large (for example 
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in \ref{SulzmannLuLexerTime}).
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The reason they made this mistake was that
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they tested out the run time of their
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lexer on particular examples such as $(a+b+ab)^*$
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and generalised to all cases, which
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cannot happen with our mecahnised proof.\\
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We give details of the proof in the next sections.
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\subsection{Overview of the Proof}
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Here is a bird's eye view of how the proof of finiteness works,
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which involves three steps:
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\begin{figure}[H]
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	\begin{tikzpicture}[scale=1,font=\bf,
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		node/.style={
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			rectangle,rounded corners=3mm,
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			ultra thick,draw=black!50,minimum height=18mm, 
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			minimum width=20mm,
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		top color=white,bottom color=black!20}]
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		\node (0) at (-5,0) 
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			[node, text width=1.8cm, text centered] 
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			{$\llbracket \bderssimp{a}{s} \rrbracket$};
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		\node (A) at (0,0) 
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			[node,text width=1.6cm,  text centered] 
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			{$\llbracket \rderssimp{r}{s} \rrbracket_r$};
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		\node (B) at (3,0) 
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			[node,text width=3.0cm, anchor=west, minimum width = 40mm] 
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			{$\llbracket \textit{ClosedForm}(r, s)\rrbracket_r$};
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		\node (C) at (9.5,0) [node, minimum width=10mm] {$N_r$};
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		\draw [->,line width=0.5mm] (0) -- 
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			node [above,pos=0.45] {=} (A) node [below, pos = 0.45] {$(r = a \downarrow_r)$} (A); 
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		\draw [->,line width=0.5mm] (A) -- 
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			node [above,pos=0.35] {$\quad =\ldots=$} (B); 
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		\draw [->,line width=0.5mm] (B) -- 
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			node [above,pos=0.35] {$\quad \leq \ldots \leq$} (C); 
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	\end{tikzpicture}
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	%\caption{
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\end{figure}
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\noindent
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We explain the steps one by one:
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\begin{itemize}
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	\item
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		We first introduce the operations such as 
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		derivatives, simplification, size calculation, etc.
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		associated with $\rrexp$s, which we have given
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		a very brief introduction to in chapter \ref{Bitcoded2}.
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		The operations on $\rrexp$s are identical to those on
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		annotated regular expressions except that they are unaware
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		of bitcodes. This means that all proofs about size of $\rrexp$s will apply to
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		annotated regular expressions.
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	\item
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		We prove that $\rderssimp{r}{s} = \textit{ClosedForm}(r, s)$,
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		where $\textit{ClosedForm}(r, s)$ is entirely 
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		written in the derivatives of their children regular 
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		expressions.
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		We call the right-hand-side the \emph{Closed Form}
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		of the derivative $\rderssimp{r}{s}$.
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	\item
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		We estimate $\llbracket \textit{ClosedForm}(r, s) \rrbracket_r$.
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		The key observation is that $\distinctBy$'s output is
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		a list with a constant length bound.
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\end{itemize}
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We will expand on these steps in the next sections.\\
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\section{The $\textit{Rrexp}$ Datatype and Its Lexing-Related Functions}
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The first step is to define 
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$\textit{rrexp}$s.
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They are without bitcodes,
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allowing a much simpler size bound proof.
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Of course, the bits which encode the lexing information 
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would grow linearly with respect 
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to the input, which should be taken into account when we wish to tackle the runtime comlexity.
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But for the sake of the structural size 
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we can safely ignore them.\\
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To recapitulate, the datatype 
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definition of the $\rrexp$, called
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\emph{r-regular expressions},
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was initially defined in \ref{rrexpDef}.
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The reason for the prefix $r$ is
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to make a distinction  
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with basic regular expressions.
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\[			\rrexp ::=   \RZERO \mid  \RONE
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	\mid  \RCHAR{c}  
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	\mid  \RSEQ{r_1}{r_2}
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	\mid  \RALTS{rs}
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	\mid \RSTAR{r}        
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\]
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The size of an r-regular expression is
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written $\llbracket r\rrbracket_r$, 
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whose definition mirrors that of an annotated regular expression. 
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\begin{center}
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	\begin{tabular}{ccc}
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		$\llbracket _{bs}\ONE \rrbracket_r$ & $\dn$ & $1$\\
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		$\llbracket \ZERO \rrbracket_r$ & $\dn$ & $1$ \\
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		$\llbracket _{bs} r_1 \cdot r_2 \rrbracket_r$ & $\dn$ & $\llbracket r_1 \rrbracket_r + \llbracket r_2 \rrbracket_r + 1$\\
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		$\llbracket _{bs}\mathbf{c} \rrbracket_r $ & $\dn$ & $1$\\
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		$\llbracket _{bs}\sum as \rrbracket_r $ & $\dn$ & $\map \; (\llbracket \_ \rrbracket_r)\; as   + 1$\\
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		$\llbracket _{bs} a^* \rrbracket_r $ & $\dn$ & $\llbracket a \rrbracket_r + 1$.
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	\end{tabular}
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\end{center}
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\noindent
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The $r$ in the subscript of $\llbracket \rrbracket_r$ is to 
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differentiate with the same operation for annotated regular expressions.
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Adding $r$ as subscript will be used in 
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other operations as well.\\
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The transformation from an annotated regular expression
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to an r-regular expression is straightforward.
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\begin{center}
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	\begin{tabular}{lcl}
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		$\rerase{\ZERO}$ & $\dn$ & $\RZERO$\\
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		$\rerase{_{bs}\ONE}$ & $\dn$ & $\RONE$\\
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		$\rerase{_{bs}\mathbf{c}}$ & $\dn$ & $\RCHAR{c}$\\
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		$\rerase{_{bs}r_1\cdot r_2}$ & $\dn$ & $\RSEQ{\rerase{r_1}}{\rerase{r_2}}$\\
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		$\rerase{_{bs}\sum as}$ & $\dn$ & $\RALTS{\map \; \rerase{\_} \; as}$\\
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		$\rerase{_{bs} a ^*}$ & $\dn$ & $\rerase{a} ^*$
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	\end{tabular}
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\end{center}
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\noindent
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$\textit{Rerase}$ throws away the bitcodes 
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on the annotated regular expressions, 
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but keeps everything else intact.
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Therefore it does not change the size
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of an annotated regular expression:
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\begin{lemma}\label{rsizeAsize}
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	$\rsize{\rerase a} = \asize a$
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\end{lemma}
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\begin{proof}
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	By routine structural induction on $a$.
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\end{proof}
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\noindent
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\subsection{Motivation Behind a New Datatype}
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The reason we take all the trouble 
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defining a new datatype is that $\erase$ makes things harder.
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We initially started by using 
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plain regular expressions and tried to prove
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the lemma \ref{rsizeAsize},
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however the $\erase$ function unavoidbly messes with the structure of the 
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annotated regular expression.
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The $+$ constructor
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of basic regular expressions is binary whereas $\sum$ 
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takes a list, and one has to convert between them:
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\begin{center}
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	\begin{tabular}{ccc}
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		$\erase \; _{bs}\sum [] $ & $\dn$ & $\ZERO$\\
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		$\erase \; _{bs}\sum [a]$ & $\dn$ & $a$\\
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		$\erase \; _{bs}\sum a :: as$ & $\dn$ & $a + (\erase \; _{[]} \sum as)\quad \text{if $as$ length over 1}$
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	\end{tabular}
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\end{center}
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\noindent
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An alternative regular expression with an empty argument list
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will be turned into a $\ZERO$.
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The singleton alternative $\sum [r]$ would have $r$ during the
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$\erase$ function.
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The  annotated regular expression $\sum[a, b, c]$ would turn into
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$(a+(b+c))$.
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All these operations change the size and structure of
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an annotated regular expressions, adding unnecessary 
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complexities to the size bound proof.\\
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For example, if we define the size of a basic regular expression 
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in the usual way,
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\begin{center}
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	\begin{tabular}{ccc}
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		$\llbracket \ONE \rrbracket_p$ & $\dn$ & $1$\\
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		$\llbracket \ZERO \rrbracket_p$ & $\dn$ & $1$ \\
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		$\llbracket r_1 \cdot r_2 \rrbracket_p$ & $\dn$ & $\llbracket r_1 \rrbracket_p + \llbracket r_2 \rrbracket_p + 1$\\
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		$\llbracket \mathbf{c} \rrbracket_p $ & $\dn$ & $1$\\
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		$\llbracket r_1 \cdot r_2 \rrbracket_p $ & $\dn$ & $\llbracket r_1 \rrbracket_p \; + \llbracket r_2 \rrbracket_p + 1$\\
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		$\llbracket a^* \rrbracket_p $ & $\dn$ & $\llbracket a \rrbracket_p + 1$
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	\end{tabular}
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\end{center}
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\noindent
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Then the property
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\begin{center}
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	$\llbracket a \rrbracket = \llbracket a_\downarrow \rrbracket_p$
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\end{center}
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does not hold.
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One might be able to prove an inequality such as
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$\llbracket a \rrbracket  \leq \llbracket  a_\downarrow \rrbracket_p $
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and then estimate $\llbracket  a_\downarrow \rrbracket_p$,
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but we found our approach more straightforward.\\
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594
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\subsection{Lexing Related Functions for $\rrexp$ such as $\backslash_r$, $\rdistincts$, and $\rsimp$}
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The operations on r-regular expressions are 
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almost identical to those of the annotated regular expressions,
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except that no bitcodes are used. For example,
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the derivative operation becomes simpler:\\
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\begin{center}
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	\begin{tabular}{@{}lcl@{}}
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		$(\ZERO)\,\backslash_r c$ & $\dn$ & $\ZERO$\\  
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		$(\ONE)\,\backslash_r c$ & $\dn$ &
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		$\textit{if}\;c=d\; \;\textit{then}\;
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		\ONE\;\textit{else}\;\ZERO$\\  
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		$(\sum \;\textit{rs})\,\backslash_r c$ & $\dn$ &
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		$\sum\;(\textit{map} \; (\_\backslash_r c) \; rs )$\\
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		$(r_1\cdot r_2)\,\backslash_r c$ & $\dn$ &
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		$\textit{if}\;(\textit{rnullable}\,r_1)$\\
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						 & &$\textit{then}\;\sum\,[(r_1\,\backslash_r c)\cdot\,r_2,$\\
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						 & &$\phantom{\textit{then},\;\sum\,}((r_2\,\backslash_r c))]$\\
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						 & &$\textit{else}\;\,(r_1\,\backslash_r c)\cdot r_2$\\
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		$(r^*)\,\backslash_r c$ & $\dn$ &
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		$( r\,\backslash_r c)\cdot
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		(_{[]}r^*))$
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	\end{tabular}    
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\end{center}  
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\noindent
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Similarly, $\distinctBy$ does not need 
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a function checking equivalence because
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there are no bit annotations causing superficial differences
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between syntactically equal terms.
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\begin{center}
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	\begin{tabular}{lcl}
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		$\rdistinct{[]}{rset} $ & $\dn$ & $[]$\\
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		$\rdistinct{r :: rs}{rset}$ & $\dn$ & 
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		$\textit{if}(r \in \textit{rset}) \; \textit{then} \; \rdistinct{rs}{rset}$\\
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					    &        & $\textit{else}\; \;
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					    r::\rdistinct{rs}{(rset \cup \{r\})}$
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	\end{tabular}
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\end{center}
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%TODO: definition of rsimp (maybe only the alternative clause)
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\noindent
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We would like to make clear
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a difference between our $\rdistincts$ and
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the Isabelle $\textit {distinct}$ predicate.
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In Isabelle $\textit{distinct}$ is a function that returns a boolean
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rather than a list.
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It tests if all the elements of a list are unique.\\
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   353
With $\textit{rdistinct}$,
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and the flatten function for $\rrexp$s:
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 \begin{center}
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  \begin{tabular}{@{}lcl@{}}
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  $\textit{rflts} \; (\sum \textit{as}) :: \textit{as'}$ & $\dn$ & $as \; @ \; \textit{rflts} \; as' $ \\
595
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  $\textit{rflts} \; \ZERO :: as'$ & $\dn$ & $ \textit{rflts} \;  \textit{as'} $ \\
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   359
    $\textit{rflts} \; a :: as'$ & $\dn$ & $a :: \textit{rflts} \; \textit{as'}$ \quad(otherwise) 
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   360
\end{tabular}    
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   361
\end{center}  
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\noindent
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one can chain together all the other modules
596
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such as $\rsimpalts$:
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\begin{center}
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  \begin{tabular}{@{}lcl@{}}
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	  $\rsimpalts \;\; nil$ & $\dn$ & $\RZERO$\\
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	  $\rsimpalts \;\; r::nil$ & $\dn$ & $r$\\
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	  $\rsimpalts \;\; rs$ & $\dn$ & $\sum rs$\\
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\end{tabular}    
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\end{center}  
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\noindent
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and $\rsimpseq$:
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\begin{center}
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  \begin{tabular}{@{}lcl@{}}
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	  $\rsimpseq \;\; \RZERO \; \_ $ &   $=$ &   $\RZERO$\\
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	  $\rsimpseq \;\; \_ \; \RZERO $ &   $=$ &   $\RZERO$\\
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	  $\rsimpseq \;\; \RONE \cdot r_2$ & $\dn$ & $r_2$\\
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	  $\rsimpseq \;\; r_1 r_2$ & $\dn$ & $r_1 \cdot r_2$\\
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\end{tabular}    
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\end{center}  
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and get $\textit{rsimp}$ and $\rderssimp{\_}{\_}$:
595
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   383
\begin{center}
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   384
  \begin{tabular}{@{}lcl@{}}
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596
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	  $\textit{rsimp} \; (r_1\cdot r_2)$ & $\dn$ & $ \textit{rsimp}_{SEQ} \; bs \;(\textit{rsimp} \; r_1) \; (\textit{rsimp}  \; r_2)  $ \\
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	  $\textit{rsimp} \; (_{bs}\sum \textit{rs})$ & $\dn$ & $\textit{rsimp}_{ALTS} \; \textit{bs} \; (\textit{rdistinct} \; ( \textit{rflts} ( \textit{map} \; rsimp \; rs)) \; \rerases \; \varnothing) $ \\
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   $\textit{rsimp} \; r$ & $\dn$ & $\textit{r} \qquad \textit{otherwise}$   
595
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diff changeset
   389
\end{tabular}    
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\end{center} 
596
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\begin{center}
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	\begin{tabular}{@{}lcl@{}}
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		$r\backslash_{rsimp} \, c$ & $\dn$ & $\rsimp \; (r\backslash_r \, c)$
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	\end{tabular}
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\end{center}
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   396
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\begin{center}
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   398
	\begin{tabular}{@{}lcl@{}}
601
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   399
$r \backslash_{rsimps} \; \; c\!::\!s $ & $\dn$ & $(r \backslash_{rsimp}\, c) \backslash_{rsimps}\, s$ \\
596
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diff changeset
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$r \backslash_{rsimps} [\,] $ & $\dn$ & $r$
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diff changeset
   401
	\end{tabular}
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\end{center}
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\noindent
601
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   404
We do not define an r-regular expression version of $\blexersimp$,
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diff changeset
   405
as our proof does not involve its use. 
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diff changeset
   406
Everything about the size of annotated regular expressions
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   407
can be calculated via the size of r-regular expressions:
564
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   408
\begin{lemma}\label{sizeRelations}
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	The following equalities hold:
543
b2bea5968b89 thesis_thys
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diff changeset
   410
	\begin{itemize}
b2bea5968b89 thesis_thys
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diff changeset
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		\item
601
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   412
			$\asize{\bsimps \; a} = \rsize{\rsimp{ \rerase{a}}}$
554
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diff changeset
   413
		\item
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diff changeset
   414
			$\asize{\bderssimp{a}{s}} =  \rsize{\rderssimp{\rerase{a}}{s}}$
554
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diff changeset
   415
	\end{itemize}
532
cc54ce075db5 restructured
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\end{lemma}
601
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   417
\begin{proof}
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   418
	The first part is by induction on the inductive cases
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   419
	of $\textit{bsimp}$.
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diff changeset
   420
	The second part is by induction on the string $s$,
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   421
	where the inductive step follows from part one.
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diff changeset
   422
\end{proof}
543
b2bea5968b89 thesis_thys
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\noindent
596
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   424
With lemma \ref{sizeRelations},
601
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diff changeset
   425
we will be able to focus on 
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   426
estimating only
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diff changeset
   427
$\rsize{\rderssimp{\rerase{a}}{s}}$
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   428
in later parts because
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diff changeset
   429
\begin{center}
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parents: 596
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   430
	$\rsize{\rderssimp{\rerase{a}}{s}} \leq N_r \quad$
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diff changeset
   431
	implies
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diff changeset
   432
	$\quad \llbracket a \backslash_{bsimps} s \rrbracket \leq N_r$.
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diff changeset
   433
\end{center}
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   434
Unless stated otherwise in the rest of this 
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   435
chapter all regular expressions without
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   436
bitcodes are seen as $\rrexp$s.
601
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diff changeset
   437
For the binary alternative r-regular expression $\RALTS{[r_1, r_2]}$,
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diff changeset
   438
we use the notation $r_1 + r_2$
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diff changeset
   439
for brevity.
532
cc54ce075db5 restructured
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parents:
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   440
cc54ce075db5 restructured
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   441
cc54ce075db5 restructured
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%-----------------------------------
596
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   443
%	SUB SECTION ROADMAP RREXP BOUND
532
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%-----------------------------------
553
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596
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%\subsection{Roadmap to a Bound for $\textit{Rrexp}$}
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diff changeset
   447
596
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%The way we obtain the bound for $\rrexp$s is by two steps:
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   449
%\begin{itemize}
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diff changeset
   450
%	\item
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   451
%		First, we rewrite $r\backslash s$ into something else that is easier
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   452
%		to bound. This step is especially important for the inductive case 
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   453
%		$r_1 \cdot r_2$ and $r^*$, where the derivative can grow and bloat in a wild way,
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   454
%		but after simplification they will always be equal or smaller to a form consisting of an alternative
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   455
%		list of regular expressions $f \; (g\; (\sum rs))$ with some functions applied to it, where each element will be distinct after the function application.
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   456
%	\item
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   457
%		Then, for such a sum  list of regular expressions $f\; (g\; (\sum rs))$, we can control its size
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   458
%		by estimation, since $\distinctBy$ and $\flts$ are well-behaved and working together would only 
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   459
%		reduce the size of a regular expression, not adding to it.
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   460
%\end{itemize}
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   461
%
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   462
%\section{Step One: Closed Forms}
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   463
%We transform the function application $\rderssimp{r}{s}$
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diff changeset
   464
%into an equivalent 
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   465
%form $f\; (g \; (\sum rs))$.
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   466
%The functions $f$ and $g$ can be anything from $\flts$, $\distinctBy$ and other helper functions from $\bsimp{\_}$.
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   467
%This way we get a different but equivalent way of expressing : $r\backslash s = f \; (g\; (\sum rs))$, we call the
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   468
%right hand side the "closed form" of $r\backslash s$.
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diff changeset
   469
%
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diff changeset
   470
%\begin{quote}\it
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diff changeset
   471
%	Claim: For regular expressions $r_1 \cdot r_2$, we claim that
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diff changeset
   472
%	\begin{center}
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   473
%		$ \rderssimp{r_1 \cdot r_2}{s} = 
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   474
%		\rsimp{(\sum (r_1 \backslash s \cdot r_2 ) \; :: \;(\map \; \rderssimp{r2}{\_} \;(\vsuf{s}{r_1})))}$
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   475
%	\end{center}
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   476
%\end{quote}
b306628a0eab more chap 56
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diff changeset
   477
%\noindent
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   478
%We explain in detail how we reached those claims.
543
b2bea5968b89 thesis_thys
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diff changeset
   479
\subsection{Basic Properties needed for Closed Forms}
601
Chengsong
parents: 596
diff changeset
   480
If we attempt to prove 
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parents: 596
diff changeset
   481
\begin{center}
Chengsong
parents: 596
diff changeset
   482
	$\forall r. \; \exists N_r.\;\; s.t. \llbracket r\backslash_{bsimps} s \rrbracket_r \leq N_r$
Chengsong
parents: 596
diff changeset
   483
\end{center}
Chengsong
parents: 596
diff changeset
   484
using a naive induction on the structure of $r$,
Chengsong
parents: 596
diff changeset
   485
then we are stuck at the inductive cases such as
Chengsong
parents: 596
diff changeset
   486
$r_1\cdot r_2$.
Chengsong
parents: 596
diff changeset
   487
The inductive hypotheses are:
Chengsong
parents: 596
diff changeset
   488
\begin{center}
Chengsong
parents: 596
diff changeset
   489
	1: $\text{for } r_1, \text{there exists } N_{r_1}.\;\; s.t. 
Chengsong
parents: 596
diff changeset
   490
	\;\;\forall s.  \llbracket r_1 \backslash_{bsimps} s \rrbracket_r \leq N_{r_1}. $\\
Chengsong
parents: 596
diff changeset
   491
	2: $\text{for } r_2, \text{there exists } N_{r_2}.\;\; s.t. 
Chengsong
parents: 596
diff changeset
   492
	\;\; \forall s. \llbracket r_2 \backslash_{bsimps} s \rrbracket_r \leq N_{r_2}. $
Chengsong
parents: 596
diff changeset
   493
\end{center}
Chengsong
parents: 596
diff changeset
   494
The inductive step to prove would be 
Chengsong
parents: 596
diff changeset
   495
\begin{center}
Chengsong
parents: 596
diff changeset
   496
	$\text{there exists } N_{r_1\cdot r_2}. \;\; s.t. \forall s. 
Chengsong
parents: 596
diff changeset
   497
	\llbracket (r_1 \cdot r_2) \backslash_{bsimps} s \rrbracket_r \leq N_{r_1\cdot r_2}.$
Chengsong
parents: 596
diff changeset
   498
\end{center}
Chengsong
parents: 596
diff changeset
   499
The problem is that it is not clear what 
Chengsong
parents: 596
diff changeset
   500
$(r_1\cdot r_2) \backslash_{bsimps} s$ looks like,
Chengsong
parents: 596
diff changeset
   501
and therefore $N_{r_1}$ and $N_{r_2}$ in the
Chengsong
parents: 596
diff changeset
   502
inductive hypotheses cannot be directly used.
Chengsong
parents: 596
diff changeset
   503
Chengsong
parents: 596
diff changeset
   504
596
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diff changeset
   505
The next steps involves getting a closed form for
b306628a0eab more chap 56
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diff changeset
   506
$\rderssimp{r}{s}$ and then obtaining
b306628a0eab more chap 56
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diff changeset
   507
an estimate for the closed form.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   508
\subsubsection{$\textit{rdistinct}$'s Deduplicates Successfully}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   509
The $\textit{rdistinct}$ function, as its name suggests, will
553
0f00d440f484 more changes
Chengsong
parents: 543
diff changeset
   510
remove duplicates in an \emph{r}$\textit{rexp}$ list, 
0f00d440f484 more changes
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parents: 543
diff changeset
   511
according to the accumulator
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   512
and leave only one of each different element in a list:
555
Chengsong
parents: 554
diff changeset
   513
\begin{lemma}\label{rdistinctDoesTheJob}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   514
	The function $\textit{rdistinct}$ satisfies the following
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   515
	properties:
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   516
	\begin{itemize}
b2bea5968b89 thesis_thys
Chengsong
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diff changeset
   517
		\item
b2bea5968b89 thesis_thys
Chengsong
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diff changeset
   518
			If $a \in acc$ then $a \notin (\rdistinct{rs}{acc})$.
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   519
		\item
b2bea5968b89 thesis_thys
Chengsong
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diff changeset
   520
			If list $rs'$ is the result of $\rdistinct{rs}{acc}$,
555
Chengsong
parents: 554
diff changeset
   521
			then $\textit{isDistinct} \; rs'$.
Chengsong
parents: 554
diff changeset
   522
		\item
Chengsong
parents: 554
diff changeset
   523
			$\rdistinct{rs}{acc} = rs - acc$
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   524
	\end{itemize}
b2bea5968b89 thesis_thys
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diff changeset
   525
\end{lemma}
555
Chengsong
parents: 554
diff changeset
   526
\noindent
Chengsong
parents: 554
diff changeset
   527
The predicate $\textit{isDistinct}$ is for testing
Chengsong
parents: 554
diff changeset
   528
whether a list's elements are all unique. It is defined
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parents: 554
diff changeset
   529
recursively on the structure of a regular expression,
Chengsong
parents: 554
diff changeset
   530
and we omit the precise definition here.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   531
\begin{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   532
	The first part is by an induction on $rs$.
555
Chengsong
parents: 554
diff changeset
   533
	The second and third part can be proven by using the 
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   534
	induction rules of $\rdistinct{\_}{\_}$.
593
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diff changeset
   535
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   536
\end{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   537
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   538
\noindent
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   539
$\rdistinct{\_}{\_}$ will cancel out all regular expression terms
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   540
that are in the accumulator, therefore prepending a list $rs_a$ with an arbitrary
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   541
list $rs$ whose elements are all from the accumulator, and then call $\rdistinct{\_}{\_}$
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   542
on the resulting list, the output will be as if we had called $\rdistinct{\_}{\_}$
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   543
without the prepending of $rs$:
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   544
\begin{lemma}
554
Chengsong
parents: 553
diff changeset
   545
	The elements appearing in the accumulator will always be removed.
Chengsong
parents: 553
diff changeset
   546
	More precisely,
Chengsong
parents: 553
diff changeset
   547
	\begin{itemize}
Chengsong
parents: 553
diff changeset
   548
		\item
Chengsong
parents: 553
diff changeset
   549
			If $rs \subseteq rset$, then 
Chengsong
parents: 553
diff changeset
   550
			$\rdistinct{rs@rsa }{acc} = \rdistinct{rsa }{acc}$.
Chengsong
parents: 553
diff changeset
   551
		\item
Chengsong
parents: 553
diff changeset
   552
			Furthermore, if $a \in rset$ and $\rdistinct{rs}{\{a\}} = []$,
Chengsong
parents: 553
diff changeset
   553
			then $\rdistinct{(rs @ rs')}{rset} = \rdistinct{rs'}{rset}$
Chengsong
parents: 553
diff changeset
   554
	\end{itemize}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   555
\end{lemma}
554
Chengsong
parents: 553
diff changeset
   556
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   557
\begin{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   558
	By induction on $rs$.
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   559
\end{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   560
\noindent
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   561
On the other hand, if an element $r$ does not appear in the input list waiting to be deduplicated,
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   562
then expanding the accumulator to include that element will not cause the output list to change:
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   563
\begin{lemma}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   564
	The accumulator can be augmented to include elements not appearing in the input list,
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   565
	and the output will not change.	
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   566
	\begin{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   567
		\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   568
			If $r \notin rs$, then $\rdistinct{rs}{acc} = \rdistinct{rs}{\{r\} \cup acc}$.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   569
		\item
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   570
			Particularly, when $acc = \varnothing$ and $rs$ de-duplicated, we have\\
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   571
			\[ \rdistinct{rs}{\varnothing} = rs \]
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   572
	\end{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   573
\end{lemma}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   574
\begin{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   575
	The first half is by induction on $rs$. The second half is a corollary of the first.
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   576
\end{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   577
\noindent
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   578
The next property gives the condition for
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   579
when $\rdistinct{\_}{\_}$ becomes an identical mapping
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   580
for any prefix of an input list, in other words, when can 
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   581
we ``push out" the arguments of $\rdistinct{\_}{\_}$:
555
Chengsong
parents: 554
diff changeset
   582
\begin{lemma}\label{distinctRdistinctAppend}
554
Chengsong
parents: 553
diff changeset
   583
	If $\textit{isDistinct} \; rs_1$, and $rs_1 \cap acc = \varnothing$,
555
Chengsong
parents: 554
diff changeset
   584
	then 
553
0f00d440f484 more changes
Chengsong
parents: 543
diff changeset
   585
	\[\textit{rdistinct}\;  (rs_1 @ rsa)\;\, acc
0f00d440f484 more changes
Chengsong
parents: 543
diff changeset
   586
	= rs_1@(\textit{rdistinct} rsa \; (acc \cup rs_1))\]
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   587
\end{lemma}
554
Chengsong
parents: 553
diff changeset
   588
\noindent
555
Chengsong
parents: 554
diff changeset
   589
In other words, it can be taken out and left untouched in the output.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   590
\begin{proof}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   591
	By an induction on $rs_1$, where $rsa$ and $acc$ are allowed to be arbitrary.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   592
\end{proof}
554
Chengsong
parents: 553
diff changeset
   593
\noindent
Chengsong
parents: 553
diff changeset
   594
$\rdistinct{}{}$ removes any element in anywhere of a list, if it
Chengsong
parents: 553
diff changeset
   595
had appeared previously:
Chengsong
parents: 553
diff changeset
   596
\begin{lemma}\label{distinctRemovesMiddle}
Chengsong
parents: 553
diff changeset
   597
	The two properties hold if $r \in rs$:
Chengsong
parents: 553
diff changeset
   598
	\begin{itemize}
Chengsong
parents: 553
diff changeset
   599
		\item
555
Chengsong
parents: 554
diff changeset
   600
			$\rdistinct{rs}{rset} = \rdistinct{(rs @ [r])}{rset}$\\
Chengsong
parents: 554
diff changeset
   601
			and\\
554
Chengsong
parents: 553
diff changeset
   602
			$\rdistinct{(ab :: rs @ [ab])}{rset'} = \rdistinct{(ab :: rs)}{rset'}$
Chengsong
parents: 553
diff changeset
   603
		\item
555
Chengsong
parents: 554
diff changeset
   604
			$\rdistinct{ (rs @ rs') }{rset} = \rdistinct{rs @ [r] @ rs'}{rset}$\\
Chengsong
parents: 554
diff changeset
   605
			and\\
554
Chengsong
parents: 553
diff changeset
   606
			$\rdistinct{(ab :: rs @ [ab] @ rs'')}{rset'} = 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   607
			\rdistinct{(ab :: rs @ rs'')}{rset'}$
554
Chengsong
parents: 553
diff changeset
   608
	\end{itemize}
Chengsong
parents: 553
diff changeset
   609
\end{lemma}
Chengsong
parents: 553
diff changeset
   610
\noindent
Chengsong
parents: 553
diff changeset
   611
\begin{proof}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   612
	By induction on $rs$. All other variables are allowed to be arbitrary.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   613
	The second half of the lemma requires the first half.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   614
	Note that for each half's two sub-propositions need to be proven concurrently,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   615
	so that the induction goes through.
554
Chengsong
parents: 553
diff changeset
   616
\end{proof}
Chengsong
parents: 553
diff changeset
   617
555
Chengsong
parents: 554
diff changeset
   618
\noindent
Chengsong
parents: 554
diff changeset
   619
This allows us to prove ``Idempotency" of $\rdistinct{}{}$ of some kind:
Chengsong
parents: 554
diff changeset
   620
\begin{lemma}\label{rdistinctConcatGeneral}
Chengsong
parents: 554
diff changeset
   621
	The following equalities involving multiple applications  of $\rdistinct{}{}$ hold:
Chengsong
parents: 554
diff changeset
   622
	\begin{itemize}
Chengsong
parents: 554
diff changeset
   623
		\item
Chengsong
parents: 554
diff changeset
   624
			$\rdistinct{(rs @ rs')}{\varnothing} = \rdistinct{((\rdistinct{rs}{\varnothing})@ rs')}{\varnothing}$
Chengsong
parents: 554
diff changeset
   625
		\item
Chengsong
parents: 554
diff changeset
   626
			$\rdistinct{(rs @ rs')}{\varnothing} = \rdistinct{(\rdistinct{rs}{\varnothing} @ rs')}{\varnothing}$
Chengsong
parents: 554
diff changeset
   627
		\item
Chengsong
parents: 554
diff changeset
   628
			If $rset' \subseteq rset$, then $\rdistinct{rs}{rset} = 
Chengsong
parents: 554
diff changeset
   629
			\rdistinct{(\rdistinct{rs}{rset'})}{rset}$. As a corollary
Chengsong
parents: 554
diff changeset
   630
			of this,
Chengsong
parents: 554
diff changeset
   631
		\item
Chengsong
parents: 554
diff changeset
   632
			$\rdistinct{(rs @ rs')}{rset} = \rdistinct{
Chengsong
parents: 554
diff changeset
   633
			(\rdistinct{rs}{\varnothing}) @ rs')}{rset}$. This
Chengsong
parents: 554
diff changeset
   634
			gives another corollary use later:
Chengsong
parents: 554
diff changeset
   635
		\item
Chengsong
parents: 554
diff changeset
   636
			If $a \in rset$, then $\rdistinct{(rs @ rs')}{rset} = \rdistinct{
Chengsong
parents: 554
diff changeset
   637
			(\rdistinct{(a :: rs)}{\varnothing} @ rs')}{rset} $,
Chengsong
parents: 554
diff changeset
   638
Chengsong
parents: 554
diff changeset
   639
	\end{itemize}
Chengsong
parents: 554
diff changeset
   640
\end{lemma}
Chengsong
parents: 554
diff changeset
   641
\begin{proof}
Chengsong
parents: 554
diff changeset
   642
	By \ref{rdistinctDoesTheJob} and \ref{distinctRemovesMiddle}.
Chengsong
parents: 554
diff changeset
   643
\end{proof}
Chengsong
parents: 554
diff changeset
   644
553
0f00d440f484 more changes
Chengsong
parents: 543
diff changeset
   645
\subsubsection{The Properties of $\backslash_r$, $\backslash_{rsimp}$, $\textit{Rflts}$ and $\textit{Rsimp}_{ALTS}$} 
0f00d440f484 more changes
Chengsong
parents: 543
diff changeset
   646
We give in this subsection some properties of how $\backslash_r$, $\backslash_{rsimp}$, $\textit{Rflts}$ and $\textit{Rsimp}_{ALTS} $ interact with each other and with $@$, the concatenation operator.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   647
These will be helpful in later closed form proofs, when
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   648
we want to transform the ways in which multiple functions involving
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   649
those are composed together
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   650
in interleaving derivative and  simplification steps.
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   651
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   652
When the function $\textit{Rflts}$ 
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   653
is applied to the concatenation of two lists, the output can be calculated by first applying the
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   654
functions on two lists separately, and then concatenating them together.
554
Chengsong
parents: 553
diff changeset
   655
\begin{lemma}\label{rfltsProps}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   656
	The function $\rflts$ has the below properties:\\
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   657
	\begin{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   658
		\item
554
Chengsong
parents: 553
diff changeset
   659
			$\rflts \; (rs_1 @ rs_2) = \rflts \; rs_1 @ \rflts \; rs_2$
Chengsong
parents: 553
diff changeset
   660
		\item
Chengsong
parents: 553
diff changeset
   661
			If $r \neq \RZERO$ and $\nexists rs_1. r = \RALTS{rs}_1$, then $\rflts \; (r::rs) = r :: \rflts \; rs$
Chengsong
parents: 553
diff changeset
   662
		\item
Chengsong
parents: 553
diff changeset
   663
			$\rflts \; (rs @ [\RZERO]) = \rflts \; rs$
Chengsong
parents: 553
diff changeset
   664
		\item
Chengsong
parents: 553
diff changeset
   665
			$\rflts \; (rs' @ [\RALTS{rs}]) = \rflts \; rs'@rs$
Chengsong
parents: 553
diff changeset
   666
		\item
Chengsong
parents: 553
diff changeset
   667
			$\rflts \; (rs @ [\RONE]) = \rflts \; rs @ [\RONE]$
Chengsong
parents: 553
diff changeset
   668
		\item
Chengsong
parents: 553
diff changeset
   669
			If $r \neq \RZERO$ and $\nexists rs'. r = \RALTS{rs'}$ then $\rflts \; (rs @ [r])
Chengsong
parents: 553
diff changeset
   670
			= (\rflts \; rs) @ [r]$
555
Chengsong
parents: 554
diff changeset
   671
		\item
Chengsong
parents: 554
diff changeset
   672
			If $r = \RALTS{rs}$ and $r \in rs'$ then for all $r_1 \in rs. 
Chengsong
parents: 554
diff changeset
   673
			r_1 \in \rflts \; rs'$.
Chengsong
parents: 554
diff changeset
   674
		\item
Chengsong
parents: 554
diff changeset
   675
			$\rflts \; (rs_a @ \RZERO :: rs_b) = \rflts \; (rs_a @ rs_b)$
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   676
	\end{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   677
\end{lemma}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   678
\noindent
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   679
\begin{proof}
555
Chengsong
parents: 554
diff changeset
   680
	By induction on $rs_1$ in the first sub-lemma, and induction on $r$ in the second part,
Chengsong
parents: 554
diff changeset
   681
	and induction on $rs$, $rs'$, $rs$, $rs'$, $rs_a$ in the third, fourth, fifth, sixth and 
Chengsong
parents: 554
diff changeset
   682
	last sub-lemma.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   683
\end{proof}
555
Chengsong
parents: 554
diff changeset
   684
554
Chengsong
parents: 553
diff changeset
   685
\subsubsection{The $RL$ Function: Language Interpretation of $\textit{Rrexp}$s}
Chengsong
parents: 553
diff changeset
   686
Much like the definition of $L$ on plain regular expressions, one could also 
Chengsong
parents: 553
diff changeset
   687
define the language interpretation of $\rrexp$s.
Chengsong
parents: 553
diff changeset
   688
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   689
	\begin{tabular}{lcl}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   690
		$RL \; (\ZERO)$ & $\dn$ & $\phi$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   691
		$RL \; (\ONE)$ & $\dn$ & $\{[]\}$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   692
		$RL \; (c)$ & $\dn$ & $\{[c]\}$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   693
		$RL \; \sum rs$ & $\dn$ & $ \bigcup_{r \in rs} (RL \; r)$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   694
		$RL \; (r_1 \cdot r_2)$ & $\dn$ & $ RL \; (r_1) @ RL \; (r_2)$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   695
		$RL \; (r^*)$ & $\dn$ & $ (RL(r))^*$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   696
	\end{tabular}
554
Chengsong
parents: 553
diff changeset
   697
\end{center}
Chengsong
parents: 553
diff changeset
   698
\noindent
Chengsong
parents: 553
diff changeset
   699
The main use of $RL$ is to establish some connections between $\rsimp{}$ 
Chengsong
parents: 553
diff changeset
   700
and $\rnullable{}$:
Chengsong
parents: 553
diff changeset
   701
\begin{lemma}
Chengsong
parents: 553
diff changeset
   702
	The following properties hold:
Chengsong
parents: 553
diff changeset
   703
	\begin{itemize}
Chengsong
parents: 553
diff changeset
   704
		\item
Chengsong
parents: 553
diff changeset
   705
			If $\rnullable{r}$, then $\rsimp{r} \neq \RZERO$.
Chengsong
parents: 553
diff changeset
   706
		\item
Chengsong
parents: 553
diff changeset
   707
			$\rnullable{r \backslash s} \quad $ if and only if $\quad \rnullable{\rderssimp{r}{s}}$.
Chengsong
parents: 553
diff changeset
   708
	\end{itemize}
Chengsong
parents: 553
diff changeset
   709
\end{lemma}
Chengsong
parents: 553
diff changeset
   710
\begin{proof}
Chengsong
parents: 553
diff changeset
   711
	The first part is by induction on $r$. 
Chengsong
parents: 553
diff changeset
   712
	The second part is true because property 
Chengsong
parents: 553
diff changeset
   713
	\[ RL \; r = RL \; (\rsimp{r})\] holds.
Chengsong
parents: 553
diff changeset
   714
\end{proof}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   715
554
Chengsong
parents: 553
diff changeset
   716
\subsubsection{$\rsimp{}$ is Non-Increasing}
Chengsong
parents: 553
diff changeset
   717
In this subsection, we prove that the function $\rsimp{}$ does not 
Chengsong
parents: 553
diff changeset
   718
make the $\llbracket \rrbracket_r$ size increase.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   719
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   720
554
Chengsong
parents: 553
diff changeset
   721
\begin{lemma}\label{rsimpSize}
Chengsong
parents: 553
diff changeset
   722
	$\llbracket \rsimp{r} \rrbracket_r \leq \llbracket r \rrbracket_r$
Chengsong
parents: 553
diff changeset
   723
\end{lemma}
Chengsong
parents: 553
diff changeset
   724
\subsubsection{Simplified $\textit{Rrexp}$s are Good}
Chengsong
parents: 553
diff changeset
   725
We formalise the notion of ``good" regular expressions,
Chengsong
parents: 553
diff changeset
   726
which means regular expressions that
Chengsong
parents: 553
diff changeset
   727
are not fully simplified. For alternative regular expressions that means they
Chengsong
parents: 553
diff changeset
   728
do not contain any nested alternatives like 
Chengsong
parents: 553
diff changeset
   729
\[ r_1 + (r_2 + r_3) \], un-removed $\RZERO$s like \[\RZERO + r\]
Chengsong
parents: 553
diff changeset
   730
or duplicate elements in a children regular expression list like \[ \sum [r, r, \ldots]\]:
Chengsong
parents: 553
diff changeset
   731
\begin{center}
Chengsong
parents: 553
diff changeset
   732
	\begin{tabular}{@{}lcl@{}}
Chengsong
parents: 553
diff changeset
   733
		$\good\; \RZERO$ & $\dn$ & $\textit{false}$\\
Chengsong
parents: 553
diff changeset
   734
		$\good\; \RONE$ & $\dn$ & $\textit{true}$\\
Chengsong
parents: 553
diff changeset
   735
		$\good\; \RCHAR{c}$ & $\dn$ & $\btrue$\\
Chengsong
parents: 553
diff changeset
   736
		$\good\; \RALTS{[]}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 553
diff changeset
   737
		$\good\; \RALTS{[r]}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 553
diff changeset
   738
		$\good\; \RALTS{r_1 :: r_2 :: rs}$ & $\dn$ & 
Chengsong
parents: 553
diff changeset
   739
		$\textit{isDistinct} \; (r_1 :: r_2 :: rs) \;$\\
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   740
						   & & $\textit{and}\; (\forall r' \in (r_1 :: r_2 :: rs).\; \good \; r'\; \,  \textit{and}\; \, \textit{nonAlt}\; r')$\\
554
Chengsong
parents: 553
diff changeset
   741
		$\good \; \RSEQ{\RZERO}{r}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 553
diff changeset
   742
		$\good \; \RSEQ{\RONE}{r}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 553
diff changeset
   743
		$\good \; \RSEQ{r}{\RZERO}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 553
diff changeset
   744
		$\good \; \RSEQ{r_1}{r_2}$ & $\dn$ & $\good \; r_1 \;\, \textit{and} \;\, \good \; r_2$\\
Chengsong
parents: 553
diff changeset
   745
		$\good \; \RSTAR{r}$ & $\dn$ & $\btrue$\\
Chengsong
parents: 553
diff changeset
   746
	\end{tabular}
Chengsong
parents: 553
diff changeset
   747
\end{center}
Chengsong
parents: 553
diff changeset
   748
\noindent
Chengsong
parents: 553
diff changeset
   749
The predicate $\textit{nonAlt}$ evaluates to true when the regular expression is not an
Chengsong
parents: 553
diff changeset
   750
alternative, and false otherwise.
Chengsong
parents: 553
diff changeset
   751
The $\good$ property is preserved under $\rsimp_{ALTS}$, provided that
Chengsong
parents: 553
diff changeset
   752
its non-empty argument list of expressions are all good themsleves, and $\textit{nonAlt}$, 
Chengsong
parents: 553
diff changeset
   753
and unique:
Chengsong
parents: 553
diff changeset
   754
\begin{lemma}\label{rsimpaltsGood}
Chengsong
parents: 553
diff changeset
   755
	If $rs \neq []$ and forall $r \in rs. \textit{nonAlt} \; r$ and $\textit{isDistinct} \; rs$,
Chengsong
parents: 553
diff changeset
   756
	then $\good \; (\rsimpalts \; rs)$ if and only if forall $r \in rs. \; \good \; r$.
Chengsong
parents: 553
diff changeset
   757
\end{lemma}
Chengsong
parents: 553
diff changeset
   758
\noindent
Chengsong
parents: 553
diff changeset
   759
We also note that
Chengsong
parents: 553
diff changeset
   760
if a regular expression $r$ is good, then $\rflts$ on the singleton
Chengsong
parents: 553
diff changeset
   761
list $[r]$ will not break goodness:
Chengsong
parents: 553
diff changeset
   762
\begin{lemma}\label{flts2}
Chengsong
parents: 553
diff changeset
   763
	If $\good \; r$, then forall $r' \in \rflts \; [r]. \; \good \; r'$ and $\textit{nonAlt} \; r'$.
Chengsong
parents: 553
diff changeset
   764
\end{lemma}
Chengsong
parents: 553
diff changeset
   765
\begin{proof}
Chengsong
parents: 553
diff changeset
   766
	By an induction on $r$.
Chengsong
parents: 553
diff changeset
   767
\end{proof}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   768
\noindent
554
Chengsong
parents: 553
diff changeset
   769
The other observation we make about $\rsimp{r}$ is that it never
Chengsong
parents: 553
diff changeset
   770
comes with nested alternatives, which we describe as the $\nonnested$
Chengsong
parents: 553
diff changeset
   771
property:
Chengsong
parents: 553
diff changeset
   772
\begin{center}
Chengsong
parents: 553
diff changeset
   773
	\begin{tabular}{lcl}
Chengsong
parents: 553
diff changeset
   774
		$\nonnested \; \, \sum []$ & $\dn$ & $\btrue$\\
Chengsong
parents: 553
diff changeset
   775
		$\nonnested \; \, \sum ((\sum rs_1) :: rs_2)$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 553
diff changeset
   776
		$\nonnested \; \, \sum (r :: rs)$ & $\dn$ & $\nonnested (\sum rs)$\\
Chengsong
parents: 553
diff changeset
   777
		$\nonnested \; \, r $ & $\dn$ & $\btrue$
Chengsong
parents: 553
diff changeset
   778
	\end{tabular}
Chengsong
parents: 553
diff changeset
   779
\end{center}
Chengsong
parents: 553
diff changeset
   780
\noindent
Chengsong
parents: 553
diff changeset
   781
The $\rflts$ function
Chengsong
parents: 553
diff changeset
   782
always opens up nested alternatives,
Chengsong
parents: 553
diff changeset
   783
which enables $\rsimp$ to be non-nested:
Chengsong
parents: 553
diff changeset
   784
Chengsong
parents: 553
diff changeset
   785
\begin{lemma}\label{nonnestedRsimp}
Chengsong
parents: 553
diff changeset
   786
	$\nonnested \; (\rsimp{r})$
Chengsong
parents: 553
diff changeset
   787
\end{lemma}
Chengsong
parents: 553
diff changeset
   788
\begin{proof}
Chengsong
parents: 553
diff changeset
   789
	By an induction on $r$.
Chengsong
parents: 553
diff changeset
   790
\end{proof}
Chengsong
parents: 553
diff changeset
   791
\noindent
Chengsong
parents: 553
diff changeset
   792
With this we could prove that a regular expressions
Chengsong
parents: 553
diff changeset
   793
after simplification and flattening and de-duplication,
Chengsong
parents: 553
diff changeset
   794
will not contain any alternative regular expression directly:
Chengsong
parents: 553
diff changeset
   795
\begin{lemma}\label{nonaltFltsRd}
Chengsong
parents: 553
diff changeset
   796
	If $x \in \rdistinct{\rflts\; (\map \; \rsimp{} \; rs)}{\varnothing}$ 
Chengsong
parents: 553
diff changeset
   797
	then $\textit{nonAlt} \; x$.
Chengsong
parents: 553
diff changeset
   798
\end{lemma}
Chengsong
parents: 553
diff changeset
   799
\begin{proof}
Chengsong
parents: 553
diff changeset
   800
	By \ref{nonnestedRsimp}.
Chengsong
parents: 553
diff changeset
   801
\end{proof}
Chengsong
parents: 553
diff changeset
   802
\noindent
Chengsong
parents: 553
diff changeset
   803
The other thing we know is that once $\rsimp{}$ had finished
Chengsong
parents: 553
diff changeset
   804
processing an alternative regular expression, it will not
Chengsong
parents: 553
diff changeset
   805
contain any $\RZERO$s, this is because all the recursive 
Chengsong
parents: 553
diff changeset
   806
calls to the simplification on the children regular expressions
Chengsong
parents: 553
diff changeset
   807
make the children good, and $\rflts$ will not take out
Chengsong
parents: 553
diff changeset
   808
any $\RZERO$s out of a good regular expression list,
Chengsong
parents: 553
diff changeset
   809
and $\rdistinct{}$ will not mess with the result.
Chengsong
parents: 553
diff changeset
   810
\begin{lemma}\label{flts3Obv}
Chengsong
parents: 553
diff changeset
   811
	The following are true:
Chengsong
parents: 553
diff changeset
   812
	\begin{itemize}
Chengsong
parents: 553
diff changeset
   813
		\item
Chengsong
parents: 553
diff changeset
   814
			If for all $r \in rs. \, \good \; r $ or $r = \RZERO$,
Chengsong
parents: 553
diff changeset
   815
			then for all $r \in \rflts\; rs. \, \good \; r$.
Chengsong
parents: 553
diff changeset
   816
		\item
Chengsong
parents: 553
diff changeset
   817
			If $x \in \rdistinct{\rflts\; (\map \; rsimp{}\; rs)}{\varnothing}$
Chengsong
parents: 553
diff changeset
   818
			and for all $y$ such that $\llbracket y \rrbracket_r$ less than
Chengsong
parents: 553
diff changeset
   819
			$\llbracket rs \rrbracket_r + 1$, either
Chengsong
parents: 553
diff changeset
   820
			$\good \; (\rsimp{y})$ or $\rsimp{y} = \RZERO$,
Chengsong
parents: 553
diff changeset
   821
			then $\good \; x$.
Chengsong
parents: 553
diff changeset
   822
	\end{itemize}
Chengsong
parents: 553
diff changeset
   823
\end{lemma}
Chengsong
parents: 553
diff changeset
   824
\begin{proof}
Chengsong
parents: 553
diff changeset
   825
	The first part is by induction on $rs$, where the induction
Chengsong
parents: 553
diff changeset
   826
	rule is the inductive cases for $\rflts$.
Chengsong
parents: 553
diff changeset
   827
	The second part is a corollary from the first part.
Chengsong
parents: 553
diff changeset
   828
\end{proof}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   829
554
Chengsong
parents: 553
diff changeset
   830
And this leads to good structural property of $\rsimp{}$,
Chengsong
parents: 553
diff changeset
   831
that after simplification, a regular expression is
Chengsong
parents: 553
diff changeset
   832
either good or $\RZERO$:
Chengsong
parents: 553
diff changeset
   833
\begin{lemma}\label{good1}
Chengsong
parents: 553
diff changeset
   834
	For any r-regular expression $r$, $\good \; \rsimp{r}$ or $\rsimp{r} = \RZERO$.
Chengsong
parents: 553
diff changeset
   835
\end{lemma}
Chengsong
parents: 553
diff changeset
   836
\begin{proof}
Chengsong
parents: 553
diff changeset
   837
	By an induction on $r$. The inductive measure is the size $\llbracket \rrbracket_r$.
Chengsong
parents: 553
diff changeset
   838
	Lemma \ref{rsimpSize} says that 
Chengsong
parents: 553
diff changeset
   839
	$\llbracket \rsimp{r}\rrbracket_r$ is smaller than or equal to
Chengsong
parents: 553
diff changeset
   840
	$\llbracket r \rrbracket_r$.
Chengsong
parents: 553
diff changeset
   841
	Therefore, in the $r_1 \cdot r_2$ and $\sum rs$ case,
Chengsong
parents: 553
diff changeset
   842
	Inductive hypothesis applies to the children regular expressions
Chengsong
parents: 553
diff changeset
   843
	$r_1$, $r_2$, etc. The lemma \ref{flts3Obv}'s precondition is satisfied
Chengsong
parents: 553
diff changeset
   844
	by that as well.
Chengsong
parents: 553
diff changeset
   845
	The lemmas \ref{nonnestedRsimp} and  \ref{nonaltFltsRd} are used
Chengsong
parents: 553
diff changeset
   846
	to ensure that goodness is preserved at the topmost level.
Chengsong
parents: 553
diff changeset
   847
\end{proof}
Chengsong
parents: 553
diff changeset
   848
We shall prove that any good regular expression is 
Chengsong
parents: 553
diff changeset
   849
a fixed-point for $\rsimp{}$.
Chengsong
parents: 553
diff changeset
   850
First we prove an auxiliary lemma:
Chengsong
parents: 553
diff changeset
   851
\begin{lemma}\label{goodaltsNonalt}
Chengsong
parents: 553
diff changeset
   852
	If $\good \; \sum rs$, then $\rflts\; rs = rs$.
Chengsong
parents: 553
diff changeset
   853
\end{lemma}
Chengsong
parents: 553
diff changeset
   854
\begin{proof}
Chengsong
parents: 553
diff changeset
   855
	By an induction on $\sum rs$. The inductive rules are the cases
Chengsong
parents: 553
diff changeset
   856
	for $\good$.
Chengsong
parents: 553
diff changeset
   857
\end{proof}
Chengsong
parents: 553
diff changeset
   858
\noindent
Chengsong
parents: 553
diff changeset
   859
Now we are ready to prove that good regular expressions are invariant
Chengsong
parents: 553
diff changeset
   860
of $\rsimp{}$ application:
Chengsong
parents: 553
diff changeset
   861
\begin{lemma}\label{test}
Chengsong
parents: 553
diff changeset
   862
	If $\good \;r$ then $\rsimp{r} = r$.
Chengsong
parents: 553
diff changeset
   863
\end{lemma}
Chengsong
parents: 553
diff changeset
   864
\begin{proof}
Chengsong
parents: 553
diff changeset
   865
	By an induction on the inductive cases of $\good$.
Chengsong
parents: 553
diff changeset
   866
	The lemma \ref{goodaltsNonalt} is used in the alternative
Chengsong
parents: 553
diff changeset
   867
	case where 2 or more elements are present in the list.
Chengsong
parents: 553
diff changeset
   868
\end{proof}
555
Chengsong
parents: 554
diff changeset
   869
\noindent
Chengsong
parents: 554
diff changeset
   870
Given below is a property involving $\rflts$, $\rdistinct{}{}$, $\rsimp{}$ and $\rsimp_{ALTS}$,
Chengsong
parents: 554
diff changeset
   871
which requires $\ref{good1}$ to go through smoothly.
Chengsong
parents: 554
diff changeset
   872
It says that an application of $\rsimp_{ALTS}$ can be "absorbed",
Chengsong
parents: 554
diff changeset
   873
if it its output is concatenated with a list and then applied to $\rflts$.
Chengsong
parents: 554
diff changeset
   874
\begin{lemma}\label{flattenRsimpalts}
Chengsong
parents: 554
diff changeset
   875
	$\rflts \; ( (\rsimp_{ALTS} \; 
Chengsong
parents: 554
diff changeset
   876
	(\rdistinct{(\rflts \; (\map \; \rsimp{}\; rs))}{\varnothing})) :: 
Chengsong
parents: 554
diff changeset
   877
	\map \; \rsimp{} \; rs' ) = 
Chengsong
parents: 554
diff changeset
   878
	\rflts \; ( (\rdistinct{(\rflts \; (\map \; \rsimp{}\; rs))}{\varnothing}) @ (
Chengsong
parents: 554
diff changeset
   879
	\map \; \rsimp{rs'}))$
554
Chengsong
parents: 553
diff changeset
   880
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   881
555
Chengsong
parents: 554
diff changeset
   882
\end{lemma}
Chengsong
parents: 554
diff changeset
   883
\begin{proof}
Chengsong
parents: 554
diff changeset
   884
	By \ref{good1}.
Chengsong
parents: 554
diff changeset
   885
\end{proof}
Chengsong
parents: 554
diff changeset
   886
\noindent
Chengsong
parents: 554
diff changeset
   887
Chengsong
parents: 554
diff changeset
   888
Chengsong
parents: 554
diff changeset
   889
Chengsong
parents: 554
diff changeset
   890
Chengsong
parents: 554
diff changeset
   891
Chengsong
parents: 554
diff changeset
   892
We are also 
554
Chengsong
parents: 553
diff changeset
   893
\subsubsection{$\rsimp$ is Idempotent}
Chengsong
parents: 553
diff changeset
   894
The idempotency of $\rsimp$ is very useful in 
Chengsong
parents: 553
diff changeset
   895
manipulating regular expression terms into desired
Chengsong
parents: 553
diff changeset
   896
forms so that key steps allowing further rewriting to closed forms
Chengsong
parents: 553
diff changeset
   897
are possible.
Chengsong
parents: 553
diff changeset
   898
\begin{lemma}\label{rsimpIdem}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   899
	$\rsimp{r} = \rsimp{\rsimp{r}}$
554
Chengsong
parents: 553
diff changeset
   900
\end{lemma}
Chengsong
parents: 553
diff changeset
   901
Chengsong
parents: 553
diff changeset
   902
\begin{proof}
Chengsong
parents: 553
diff changeset
   903
	By \ref{test} and \ref{good1}.
Chengsong
parents: 553
diff changeset
   904
\end{proof}
Chengsong
parents: 553
diff changeset
   905
\noindent
Chengsong
parents: 553
diff changeset
   906
This property means we do not have to repeatedly
Chengsong
parents: 553
diff changeset
   907
apply simplification in each step, which justifies
Chengsong
parents: 553
diff changeset
   908
our definition of $\blexersimp$.
Chengsong
parents: 553
diff changeset
   909
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   910
554
Chengsong
parents: 553
diff changeset
   911
On the other hand, we could repeat the same $\rsimp{}$ applications
Chengsong
parents: 553
diff changeset
   912
on regular expressions as many times as we want, if we have at least
Chengsong
parents: 553
diff changeset
   913
one simplification applied to it, and apply it wherever we would like to:
Chengsong
parents: 553
diff changeset
   914
\begin{corollary}\label{headOneMoreSimp}
555
Chengsong
parents: 554
diff changeset
   915
	The following properties hold, directly from \ref{rsimpIdem}:
Chengsong
parents: 554
diff changeset
   916
Chengsong
parents: 554
diff changeset
   917
	\begin{itemize}
Chengsong
parents: 554
diff changeset
   918
		\item
Chengsong
parents: 554
diff changeset
   919
			$\map \; \rsimp{(r :: rs)} = \map \; \rsimp{} \; (\rsimp{r} :: rs)$
Chengsong
parents: 554
diff changeset
   920
		\item
Chengsong
parents: 554
diff changeset
   921
			$\rsimp{(\RALTS{rs})} = \rsimp{(\RALTS{\map \; \rsimp{} \; rs})}$
Chengsong
parents: 554
diff changeset
   922
	\end{itemize}
554
Chengsong
parents: 553
diff changeset
   923
\end{corollary}
Chengsong
parents: 553
diff changeset
   924
\noindent
Chengsong
parents: 553
diff changeset
   925
This will be useful in later closed form proof's rewriting steps.
Chengsong
parents: 553
diff changeset
   926
Similarly, we point out the following useful facts below:
Chengsong
parents: 553
diff changeset
   927
\begin{lemma}
Chengsong
parents: 553
diff changeset
   928
	The following equalities hold if $r = \rsimp{r'}$ for some $r'$:
Chengsong
parents: 553
diff changeset
   929
	\begin{itemize}
Chengsong
parents: 553
diff changeset
   930
		\item
Chengsong
parents: 553
diff changeset
   931
			If $r  = \sum rs$ then $\rsimpalts \; rs = \sum rs$.
Chengsong
parents: 553
diff changeset
   932
		\item
Chengsong
parents: 553
diff changeset
   933
			If $r = \sum rs$ then $\rdistinct{rs}{\varnothing} = rs$.
Chengsong
parents: 553
diff changeset
   934
		\item
Chengsong
parents: 553
diff changeset
   935
			$\rsimpalts \; (\rdistinct{\rflts \; [r]}{\varnothing}) = r$.
Chengsong
parents: 553
diff changeset
   936
	\end{itemize}
Chengsong
parents: 553
diff changeset
   937
\end{lemma}
Chengsong
parents: 553
diff changeset
   938
\begin{proof}
Chengsong
parents: 553
diff changeset
   939
	By application of \ref{rsimpIdem} and \ref{good1}.
Chengsong
parents: 553
diff changeset
   940
\end{proof}
Chengsong
parents: 553
diff changeset
   941
Chengsong
parents: 553
diff changeset
   942
\noindent
Chengsong
parents: 553
diff changeset
   943
With the idempotency of $\rsimp{}$ and its corollaries, 
Chengsong
parents: 553
diff changeset
   944
we can start proving some key equalities leading to the 
Chengsong
parents: 553
diff changeset
   945
closed forms.
Chengsong
parents: 553
diff changeset
   946
Now presented are a few equivalent terms under $\rsimp{}$.
Chengsong
parents: 553
diff changeset
   947
We use $r_1 \sequal r_2 $ here to denote $\rsimp{r_1} = \rsimp{r_2}$.
Chengsong
parents: 553
diff changeset
   948
\begin{lemma}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   949
	\begin{itemize}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   950
		The following equivalence hold:
554
Chengsong
parents: 553
diff changeset
   951
	\item
Chengsong
parents: 553
diff changeset
   952
		$\rsimpalts \; (\RZERO :: rs) \sequal \rsimpalts\; rs$
Chengsong
parents: 553
diff changeset
   953
	\item
Chengsong
parents: 553
diff changeset
   954
		$\rsimpalts \; rs \sequal \rsimpalts (\map \; \rsimp{} \; rs)$
Chengsong
parents: 553
diff changeset
   955
	\item
Chengsong
parents: 553
diff changeset
   956
		$\RALTS{\RALTS{rs}} \sequal \RALTS{rs}$
555
Chengsong
parents: 554
diff changeset
   957
	\item
Chengsong
parents: 554
diff changeset
   958
		$\sum ((\sum rs_a) :: rs_b) \sequal \sum rs_a @ rs_b$
Chengsong
parents: 554
diff changeset
   959
	\item
Chengsong
parents: 554
diff changeset
   960
		$\RALTS{rs} = \RALTS{\map \; \rsimp{} \; rs}$
554
Chengsong
parents: 553
diff changeset
   961
\end{itemize}
Chengsong
parents: 553
diff changeset
   962
\end{lemma}
555
Chengsong
parents: 554
diff changeset
   963
\begin{proof}
Chengsong
parents: 554
diff changeset
   964
	By induction on the lists involved.
Chengsong
parents: 554
diff changeset
   965
\end{proof}
Chengsong
parents: 554
diff changeset
   966
\noindent
Chengsong
parents: 554
diff changeset
   967
Similarly,
Chengsong
parents: 554
diff changeset
   968
we introduce the equality for $\sum$ when certain child regular expressions
Chengsong
parents: 554
diff changeset
   969
are $\sum$ themselves:
Chengsong
parents: 554
diff changeset
   970
\begin{lemma}\label{simpFlatten3}
Chengsong
parents: 554
diff changeset
   971
	One can flatten the inside $\sum$ of a $\sum$ if it is being 
Chengsong
parents: 554
diff changeset
   972
	simplified. Concretely,
Chengsong
parents: 554
diff changeset
   973
	\begin{itemize}
Chengsong
parents: 554
diff changeset
   974
		\item
Chengsong
parents: 554
diff changeset
   975
			If for all $r \in rs, rs', rs''$, we have $\good \; r $
Chengsong
parents: 554
diff changeset
   976
			or $r = \RZERO$, then $\sum (rs' @ rs @ rs'') \sequal 
Chengsong
parents: 554
diff changeset
   977
			\sum (rs' @ [\sum rs] @ rs'')$ holds. As a corollary,
Chengsong
parents: 554
diff changeset
   978
		\item
Chengsong
parents: 554
diff changeset
   979
			$\sum (rs' @ [\sum rs] @ rs'') \sequal \sum (rs' @ rs @ rs'')$
Chengsong
parents: 554
diff changeset
   980
	\end{itemize}
Chengsong
parents: 554
diff changeset
   981
\end{lemma}
Chengsong
parents: 554
diff changeset
   982
\begin{proof}
Chengsong
parents: 554
diff changeset
   983
	By rewriting steps involving the use of \ref{test} and \ref{rdistinctConcatGeneral}.
Chengsong
parents: 554
diff changeset
   984
	The second sub-lemma is a corollary of the previous.
Chengsong
parents: 554
diff changeset
   985
\end{proof}
Chengsong
parents: 554
diff changeset
   986
%Rewriting steps not put in--too long and complicated-------------------------------
Chengsong
parents: 554
diff changeset
   987
\begin{comment}
Chengsong
parents: 554
diff changeset
   988
	\begin{center}
Chengsong
parents: 554
diff changeset
   989
		$\rsimp{\sum (rs' @ rs @ rs'')}  \stackrel{def of bsimp}{=}$  \\
Chengsong
parents: 554
diff changeset
   990
		$\rsimpalts \; (\rdistinct{\rflts \; ((\map \; \rsimp{}\; rs') @ (\map \; \rsimp{} \; rs ) @ (\map \; \rsimp{} \; rs''))}{\varnothing})$ \\
Chengsong
parents: 554
diff changeset
   991
		$\stackrel{by \ref{test}}{=} 
Chengsong
parents: 554
diff changeset
   992
		\rsimpalts \; (\rdistinct{(\rflts \; rs' @ \rflts \; rs @ \rflts \; rs'')}{
Chengsong
parents: 554
diff changeset
   993
		\varnothing})$\\
Chengsong
parents: 554
diff changeset
   994
		$\stackrel{by \ref{rdistinctConcatGeneral}}{=}
Chengsong
parents: 554
diff changeset
   995
		\rsimpalts \; (\rdistinct{\rflts \; rs'}{\varnothing} @ \rdistinct{(
Chengsong
parents: 554
diff changeset
   996
		\rflts\; rs @ \rflts \; rs'')}{\rflts \; rs'})$\\
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   997
555
Chengsong
parents: 554
diff changeset
   998
	\end{center}
Chengsong
parents: 554
diff changeset
   999
\end{comment}
Chengsong
parents: 554
diff changeset
  1000
%Rewriting steps not put in--too long and complicated-------------------------------
554
Chengsong
parents: 553
diff changeset
  1001
\noindent
Chengsong
parents: 553
diff changeset
  1002
We need more equalities like the above to enable a closed form,
Chengsong
parents: 553
diff changeset
  1003
but to proceed we need to introduce two rewrite relations,
Chengsong
parents: 553
diff changeset
  1004
to make things smoother.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1005
\subsubsection{The rewrite relation $\hrewrite$ , $\scfrewrites$ , $\frewrite$ and $\grewrite$}
554
Chengsong
parents: 553
diff changeset
  1006
Insired by the success we had in the correctness proof 
Chengsong
parents: 553
diff changeset
  1007
in \ref{Bitcoded2}, where we invented
555
Chengsong
parents: 554
diff changeset
  1008
a term rewriting system to capture the similarity between terms,
Chengsong
parents: 554
diff changeset
  1009
we follow suit here defining simplification
Chengsong
parents: 554
diff changeset
  1010
steps as rewriting steps. This allows capturing 
Chengsong
parents: 554
diff changeset
  1011
similarities between terms that would be otherwise
Chengsong
parents: 554
diff changeset
  1012
hard to express.
Chengsong
parents: 554
diff changeset
  1013
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1014
We use $\hrewrite$ for one-step atomic rewrite of 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1015
regular expression simplification, 
555
Chengsong
parents: 554
diff changeset
  1016
$\frewrite$ for rewrite of list of regular expressions that 
Chengsong
parents: 554
diff changeset
  1017
include all operations carried out in $\rflts$, and $\grewrite$ for
Chengsong
parents: 554
diff changeset
  1018
rewriting a list of regular expressions possible in both $\rflts$ and $\rdistinct{}{}$.
Chengsong
parents: 554
diff changeset
  1019
Their reflexive transitive closures are used to denote zero or many steps,
Chengsong
parents: 554
diff changeset
  1020
as was the case in the previous chapter.
554
Chengsong
parents: 553
diff changeset
  1021
The presentation will be more concise than that in \ref{Bitcoded2}.
Chengsong
parents: 553
diff changeset
  1022
To differentiate between the rewriting steps for annotated regular expressions
Chengsong
parents: 553
diff changeset
  1023
and $\rrexp$s, we add characters $h$ and $g$ below the squig arrow symbol
Chengsong
parents: 553
diff changeset
  1024
to mean atomic simplification transitions 
Chengsong
parents: 553
diff changeset
  1025
of $\rrexp$s and $\rrexp$ lists, respectively.
Chengsong
parents: 553
diff changeset
  1026
555
Chengsong
parents: 554
diff changeset
  1027
Chengsong
parents: 554
diff changeset
  1028
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1029
List of one-step rewrite rules for $\rrexp$ ($\hrewrite$):
555
Chengsong
parents: 554
diff changeset
  1030
Chengsong
parents: 554
diff changeset
  1031
554
Chengsong
parents: 553
diff changeset
  1032
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1033
	\begin{mathpar}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1034
		\inferrule[RSEQ0L]{}{\RZERO \cdot r_2 \hrewrite \RZERO\\}
555
Chengsong
parents: 554
diff changeset
  1035
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1036
		\inferrule[RSEQ0R]{}{r_1 \cdot \RZERO \hrewrite \RZERO\\}
555
Chengsong
parents: 554
diff changeset
  1037
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1038
		\inferrule[RSEQ1]{}{(\RONE \cdot r) \hrewrite  r\\}\\	
555
Chengsong
parents: 554
diff changeset
  1039
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1040
		\inferrule[RSEQL]{ r_1 \hrewrite r_2}{r_1 \cdot r_3 \hrewrite r_2 \cdot r_3\\}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1041
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1042
		\inferrule[RSEQR]{ r_3 \hrewrite r_4}{r_1 \cdot r_3 \hrewrite r_1 \cdot r_4\\}\\
555
Chengsong
parents: 554
diff changeset
  1043
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1044
		\inferrule[RALTSChild]{r \hrewrite r'}{\sum (rs_1 @ [r] @ rs_2) \hrewrite \sum (rs_1 @ [r'] @ rs_2)\\}
555
Chengsong
parents: 554
diff changeset
  1045
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1046
		\inferrule[RALTS0]{}{\sum (rs_a @ [\RZERO] @ rs_b) \hrewrite \sum (rs_a @ rs_b)}
555
Chengsong
parents: 554
diff changeset
  1047
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1048
		\inferrule[RALTSNested]{}{\sum (rs_a @ [\sum rs_1] @ rs_b) \hrewrite \sum (rs_a @ rs_1 @ rs_b)}
555
Chengsong
parents: 554
diff changeset
  1049
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1050
		\inferrule[RALTSNil]{}{ \sum [] \hrewrite \RZERO\\}
555
Chengsong
parents: 554
diff changeset
  1051
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1052
		\inferrule[RALTSSingle]{}{ \sum [r] \hrewrite  r\\}	
555
Chengsong
parents: 554
diff changeset
  1053
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1054
		\inferrule[RALTSDelete]{\\ r_1 = r_2}{\sum rs_a @ [r_1] @ rs_b @ [r_2] @ rsc \hrewrite \sum rs_a @ [r_1] @ rs_b @ rs_c}
555
Chengsong
parents: 554
diff changeset
  1055
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1056
	\end{mathpar}
555
Chengsong
parents: 554
diff changeset
  1057
\end{center}
554
Chengsong
parents: 553
diff changeset
  1058
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1059
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1060
List of rewrite rules for a list of regular expressions,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1061
where each element can rewrite in many steps to the other (scf stands for
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1062
li\emph{s}t \emph{c}losed \emph{f}orm). This relation is similar to the 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1063
$\stackrel{s*}{\rightsquigarrow}$ for annotated regular expressions.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1064
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1065
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1066
	\begin{mathpar}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1067
		\inferrule{}{[] \scfrewrites [] }
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1068
		\inferrule{r \hrewrites r' \\ rs \scfrewrites rs'}{r :: rs \scfrewrites r' :: rs'}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1069
	\end{mathpar}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1070
\end{center}
555
Chengsong
parents: 554
diff changeset
  1071
%frewrite
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1072
List of one-step rewrite rules for flattening 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1073
a list of  regular expressions($\frewrite$):
555
Chengsong
parents: 554
diff changeset
  1074
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1075
	\begin{mathpar}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1076
		\inferrule{}{\RZERO :: rs \frewrite rs \\}
555
Chengsong
parents: 554
diff changeset
  1077
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1078
		\inferrule{}{(\sum rs) :: rs_a \frewrite rs @ rs_a \\}
555
Chengsong
parents: 554
diff changeset
  1079
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1080
		\inferrule{rs_1 \frewrite rs_2}{r :: rs_1 \frewrite r :: rs_2}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1081
	\end{mathpar}
555
Chengsong
parents: 554
diff changeset
  1082
\end{center}
Chengsong
parents: 554
diff changeset
  1083
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1084
Lists of one-step rewrite rules for flattening and de-duplicating
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1085
a list of regular expressions ($\grewrite$):
555
Chengsong
parents: 554
diff changeset
  1086
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1087
	\begin{mathpar}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1088
		\inferrule{}{\RZERO :: rs \grewrite rs \\}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1089
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1090
		\inferrule{}{(\sum rs) :: rs_a \grewrite rs @ rs_a \\}
555
Chengsong
parents: 554
diff changeset
  1091
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1092
		\inferrule{rs_1 \grewrite rs_2}{r :: rs_1 \grewrite r :: rs_2}
555
Chengsong
parents: 554
diff changeset
  1093
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1094
		\inferrule[dB]{}{rs_a @ [a] @ rs_b @[a] @ rs_c \grewrite rs_a @ [a] @ rsb @ rsc}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1095
	\end{mathpar}
555
Chengsong
parents: 554
diff changeset
  1096
\end{center}
Chengsong
parents: 554
diff changeset
  1097
Chengsong
parents: 554
diff changeset
  1098
\noindent
Chengsong
parents: 554
diff changeset
  1099
The reason why we take the trouble of defining 
Chengsong
parents: 554
diff changeset
  1100
two separate list rewriting definitions $\frewrite$ and $\grewrite$
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1101
is to separate the two stages of simplification: flattening and de-duplicating.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1102
Sometimes $\grewrites$ is slightly too powerful
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1103
so we would rather use $\frewrites$ which makes certain rewriting steps 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1104
more straightforward to prove.
556
Chengsong
parents: 555
diff changeset
  1105
For example, when proving the closed-form for the alternative regular expression,
Chengsong
parents: 555
diff changeset
  1106
one of the rewriting steps would be:
Chengsong
parents: 555
diff changeset
  1107
\begin{lemma}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1108
	$\sum (\rDistinct \;\; (\map \; (\_ \backslash x) \; (\rflts \; rs)) \;\; \varnothing) \sequal
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1109
	\sum (\rDistinct \;\;  (\rflts \; (\map \; (\_ \backslash x) \; rs)) \;\; \varnothing)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1110
	$
556
Chengsong
parents: 555
diff changeset
  1111
\end{lemma}
Chengsong
parents: 555
diff changeset
  1112
\noindent
Chengsong
parents: 555
diff changeset
  1113
Proving this is by first showing 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1114
\begin{lemma}\label{earlyLaterDerFrewrites}
556
Chengsong
parents: 555
diff changeset
  1115
	$\map \; (\_ \backslash x) \;  (\rflts \; rs) \frewrites
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1116
	\rflts \; (\map \; (\_ \backslash x) \; rs)$
556
Chengsong
parents: 555
diff changeset
  1117
\end{lemma}
Chengsong
parents: 555
diff changeset
  1118
\noindent
Chengsong
parents: 555
diff changeset
  1119
and then using lemma
Chengsong
parents: 555
diff changeset
  1120
\begin{lemma}\label{frewritesSimpeq}
Chengsong
parents: 555
diff changeset
  1121
	If $rs_1 \frewrites rs_2 $, then $\sum (\rDistinct \; rs_1 \; \varnothing) \sequal 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1122
	\sum (\rDistinct \;  rs_2 \;  \varnothing)$.
556
Chengsong
parents: 555
diff changeset
  1123
\end{lemma}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1124
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1125
is a piece of cake.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1126
But this trick will not work for $\grewrites$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1127
For example, a rewriting step in proving
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1128
closed forms is:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1129
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1130
	$\rsimp{(\rsimpalts \; (\map \; (\_ \backslash x) \; (\rdistinct{(\rflts \; (\map \; (\rsimp{} \; \circ \; (\lambda r. \rderssimp{r}{xs}))))}{\varnothing})))}$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1131
	$=$ \\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1132
	$\rsimp{(\rsimpalts \; (\rdistinct{(\map \; (\_ \backslash x) \; (\rflts \; (\map \; (\rsimp{} \; \circ \; (\lambda r. \rderssimp{r}{xs})))) ) }{\varnothing}))} $
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1133
	\noindent
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1134
\end{center}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1135
For this one would hope to have a rewriting relation between the two lists involved,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1136
similar to \ref{earlyLaterDerFrewrites}. However, it turns out that 
556
Chengsong
parents: 555
diff changeset
  1137
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1138
	$\map \; (\_ \backslash x) \; (\rDistinct \; rs \; rset) \grewrites \rDistinct \; (\map \;
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1139
	(\_ \backslash x) \; rs) \; ( rset \backslash x)$
556
Chengsong
parents: 555
diff changeset
  1140
\end{center}
Chengsong
parents: 555
diff changeset
  1141
\noindent
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1142
does $\mathbf{not}$ hold in general.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1143
For this rewriting step we will introduce some slightly more cumbersome
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1144
proof technique in later sections.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1145
The point is that $\frewrite$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1146
allows us to prove equivalence in a straightforward two-step method that is 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1147
not possible for $\grewrite$, thereby reducing the complexity of the entire proof.
555
Chengsong
parents: 554
diff changeset
  1148
556
Chengsong
parents: 555
diff changeset
  1149
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1150
\subsubsection{Terms That Can Be Rewritten Using $\hrewrites$, $\grewrites$, and $\frewrites$}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1151
We present in the below lemma a few pairs of terms that are rewritable via 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1152
$\grewrites$:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1153
\begin{lemma}\label{gstarRdistinctGeneral}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1154
	\begin{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1155
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1156
			$rs_1 @ rs \grewrites rs_1 @ (\rDistinct \; rs \; rs_1)$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1157
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1158
			$rs \grewrites \rDistinct \; rs \; \varnothing$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1159
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1160
			$rs_a @ (\rDistinct \; rs \; rs_a) \grewrites rs_a @ (\rDistinct \; 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1161
			rs \; (\{\RZERO\} \cup rs_a))$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1162
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1163
			$rs \;\; @ \;\; \rDistinct \; rs_a \; rset \grewrites rs @  \rDistinct \; rs_a \;
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1164
			(rest \cup rs)$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1165
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1166
	\end{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1167
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1168
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1169
If a pair of terms $rs_1, rs_2$ are rewritable via $\grewrites$ to each other,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1170
then they are equivalent under $\rsimp{}$:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1171
\begin{lemma}\label{grewritesSimpalts}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1172
	If $rs_1 \grewrites rs_2$, then
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1173
	we have the following equivalence hold:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1174
	\begin{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1175
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1176
			$\sum rs_1 \sequal \sum rs_2$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1177
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1178
			$\rsimpalts \; rs_1 \sequal \rsimpalts \; rs_2$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1179
	\end{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1180
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1181
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1182
Here are a few connecting lemmas showing that
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1183
if a list of regular expressions can be rewritten using $\grewrites$ or $\frewrites $ or
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1184
$\scfrewrites$,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1185
then an alternative constructor taking the list can also be rewritten using $\hrewrites$:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1186
\begin{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1187
	\begin{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1188
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1189
			If $rs \grewrites rs'$ then $\sum rs \hrewrites \sum rs'$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1190
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1191
			If $rs \grewrites rs'$ then $\sum rs \hrewrites \rsimpalts \; rs'$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1192
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1193
			If $rs_1 \scfrewrites rs_2$ then $\sum (rs @ rs_1) \hrewrites \sum (rs @ rs_2)$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1194
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1195
			If $rs_1 \scfrewrites rs_2$ then $\sum rs_1 \hrewrites \sum rs_2$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1196
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1197
	\end{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1198
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1199
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1200
Here comes the meat of the proof, 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1201
which says that once two lists are rewritable to each other,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1202
then they are equivalent under $\rsimp{}$:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1203
\begin{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1204
	If $r_1 \hrewrites r_2$ then $r_1 \sequal r_2$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1205
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1206
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1207
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1208
And similar to \ref{Bitcoded2} one can preserve rewritability after taking derivative
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1209
of two regular expressions on both sides:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1210
\begin{lemma}\label{interleave}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1211
	If $r \hrewrites r' $ then $\rder{c}{r} \hrewrites \rder{c}{r'}$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1212
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1213
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1214
This allows proving more $\mathbf{rsimp}$-equivalent terms, involving $\backslash_r$ now.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1215
\begin{lemma}\label{insideSimpRemoval}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1216
	$\rsimp{\rder{c}{\rsimp{r}}} = \rsimp{\rder{c}{r}}  $
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1217
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1218
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1219
\begin{proof}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1220
	By \ref{interleave} and \ref{rsimpIdem}.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1221
\end{proof}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1222
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1223
And this unlocks more equivalent terms:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1224
\begin{lemma}\label{Simpders}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1225
	As corollaries of \ref{insideSimpRemoval}, we have
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1226
	\begin{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1227
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1228
			If $s \neq []$ then $\rderssimp{r}{s} = \rsimp{(\rders \; r \; s)}$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1229
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1230
			$\rsimpalts \; (\map \; (\_ \backslash_r x) \;
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1231
			(\rdistinct{rs}{\varnothing})) \sequal
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1232
			\rsimpalts \; (\rDistinct \; 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1233
			(\map \; (\_ \backslash_r x) rs) \;\varnothing  )$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1234
	\end{itemize}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1235
\end{lemma}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1236
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1237
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1238
Finally,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1239
together with 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1240
\begin{lemma}\label{rderRsimpAltsCommute}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1241
	$\rder{x}{(\rsimpalts \; rs)} = \rsimpalts \; (\map \; (\rder{x}{\_}) \; rs)$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1242
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1243
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1244
this leads to the first closed form--
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1245
\begin{lemma}\label{altsClosedForm}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1246
	\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1247
		$\rderssimp{(\sum rs)}{s} \sequal
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1248
		\sum \; (\map \; (\rderssimp{\_}{s}) \; rs)$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1249
	\end{center}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1250
\end{lemma}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1251
556
Chengsong
parents: 555
diff changeset
  1252
\noindent
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1253
\begin{proof}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1254
	By a reverse induction on the string $s$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1255
	One rewriting step, as we mentioned earlier,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1256
	involves
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1257
	\begin{center}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1258
		$\rsimpalts \; (\map \; (\_ \backslash x) \; 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1259
		(\rdistinct{(\rflts \; (\map \; (\rsimp{} \; \circ \; 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1260
		(\lambda r. \rderssimp{r}{xs}))))}{\varnothing}))
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1261
		\sequal
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1262
		\rsimpalts \; (\rdistinct{(\map \; (\_ \backslash x) \; 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1263
			(\rflts \; (\map \; (\rsimp{} \; \circ \; 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1264
		(\lambda r. \rderssimp{r}{xs})))) ) }{\varnothing}) $.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1265
	\end{center}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1266
	This can be proven by a combination of 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1267
	\ref{grewritesSimpalts}, \ref{gstarRdistinctGeneral}, \ref{rderRsimpAltsCommute}, and
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1268
	\ref{insideSimpRemoval}.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1269
\end{proof}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1270
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1271
This closed form has a variant which can be more convenient in later proofs:
559
Chengsong
parents: 558
diff changeset
  1272
\begin{corollary}{altsClosedForm1}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1273
	If $s \neq []$ then 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1274
	$\rderssimp \; (\sum \; rs) \; s = 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1275
	\rsimp{(\sum \; (\map \; \rderssimp{\_}{s} \; rs))}$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1276
\end{corollary}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1277
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1278
The harder closed forms are the sequence and star ones.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1279
Before we go on to obtain them, some preliminary definitions
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1280
are needed to make proof statements concise.
556
Chengsong
parents: 555
diff changeset
  1281
558
Chengsong
parents: 557
diff changeset
  1282
\section{"Closed Forms" of Sequence Regular Expressions}
Chengsong
parents: 557
diff changeset
  1283
The problem of obataining a closed-form for sequence regular expression 
Chengsong
parents: 557
diff changeset
  1284
is constructing $(r_1 \cdot r_2) \backslash_r s$
Chengsong
parents: 557
diff changeset
  1285
if we are only allowed to use a combination of $r_1 \backslash s''$ 
Chengsong
parents: 557
diff changeset
  1286
and  $r_2 \backslash s''$ , where $s''$ is from $s$.
Chengsong
parents: 557
diff changeset
  1287
First let's look at a series of derivatives steps on a sequence 
Chengsong
parents: 557
diff changeset
  1288
regular expression, assuming that each time the first
Chengsong
parents: 557
diff changeset
  1289
component of the sequence is always nullable):
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1290
\begin{center}
558
Chengsong
parents: 557
diff changeset
  1291
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1292
	$r_1 \cdot r_2 \quad \longrightarrow_{\backslash c}  \quad   r_1  \backslash c \cdot r_2 + r_2 \backslash c \quad \longrightarrow_{\backslash c'} \quad (r_1 \backslash cc' \cdot r_2 + r_2 \backslash c') + r_2 \backslash cc' \longrightarrow_{\backslash c''} \quad$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1293
	$((r_1 \backslash cc'c'' \cdot r_2 + r_2 \backslash c'') + r_2 \backslash c'c'') + r_2 \backslash cc'c''   \longrightarrow_{\backslash c''} \quad
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1294
	\ldots$
558
Chengsong
parents: 557
diff changeset
  1295
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1296
\end{center}
558
Chengsong
parents: 557
diff changeset
  1297
Roughly speaking $r_1 \cdot r_2 \backslash s$ can be expresssed as 
Chengsong
parents: 557
diff changeset
  1298
a giant alternative taking a list of terms 
Chengsong
parents: 557
diff changeset
  1299
$[r_1 \backslash_r s \cdot r_2, r_2 \backslash_r s'', r_2 \backslash_r s_1'', \ldots]$,
Chengsong
parents: 557
diff changeset
  1300
where the head of the list is always the term
Chengsong
parents: 557
diff changeset
  1301
representing a match involving only $r_1$, and the tail of the list consisting of
Chengsong
parents: 557
diff changeset
  1302
terms of the shape $r_2 \backslash_r s''$, $s''$ being a suffix of $s$.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1303
This intuition is also echoed by IndianPaper, where they gave
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1304
a pencil-and-paper derivation of $(r_1 \cdot r_2)\backslash s$:
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1305
\begin{center}
558
Chengsong
parents: 557
diff changeset
  1306
	\begin{tabular}{c}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1307
		$(r_1 \cdot r_2) \backslash_r (c_1 :: c_2 :: \ldots c_n) \myequiv$\\ 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1308
		\rule{0pt}{3ex} $((r_1 \backslash_r c_1) \cdot r_2 + (\delta\; (\rnullable \; r_1) \; r_2 \backslash_r c_1)) \backslash_r (c_2 :: \ldots c_n) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1309
		\myequiv$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1310
		\rule{0pt}{3ex} $((r_1 \backslash_r c_1c_2 \cdot r_2 + (\delta \; (\rnullable \; r_1) \; r_2 \backslash_r c_1c_2))
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1311
		+ (\delta \ (\rnullable \; r_1 \backslash_r c)\; r_2 \backslash_r c_2)) \backslash_r (c_3 \ldots c_n)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1312
		$
558
Chengsong
parents: 557
diff changeset
  1313
	\end{tabular}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1314
\end{center}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1315
\noindent
558
Chengsong
parents: 557
diff changeset
  1316
The equality in above should be interpretated
Chengsong
parents: 557
diff changeset
  1317
as language equivalence. 
Chengsong
parents: 557
diff changeset
  1318
The $\delta$ function works similarly to that of
Chengsong
parents: 557
diff changeset
  1319
a Kronecker delta function:
Chengsong
parents: 557
diff changeset
  1320
\[ \delta \; b\; r\]
Chengsong
parents: 557
diff changeset
  1321
will produce $r$
Chengsong
parents: 557
diff changeset
  1322
if $b$ evaluates to true, 
Chengsong
parents: 557
diff changeset
  1323
and $\RZERO$ otherwise.
Chengsong
parents: 557
diff changeset
  1324
Note that their formulation  
Chengsong
parents: 557
diff changeset
  1325
\[
Chengsong
parents: 557
diff changeset
  1326
	((r_1 \backslash_r \, c_1c_2 \cdot r_2 + (\delta \; (\rnullable) \; r_1, r_2 \backslash_r c_1c_2)
Chengsong
parents: 557
diff changeset
  1327
	+ (\delta \; (\rnullable \; r_1 \backslash_r c)\; r_2 \backslash_r c_2)
Chengsong
parents: 557
diff changeset
  1328
\]
Chengsong
parents: 557
diff changeset
  1329
does not faithfully
Chengsong
parents: 557
diff changeset
  1330
represent what the intermediate derivatives would actually look like
Chengsong
parents: 557
diff changeset
  1331
when one or more intermediate results $r_1 \backslash s' \cdot r_2$ are not 
Chengsong
parents: 557
diff changeset
  1332
nullable in the head of the sequence.
Chengsong
parents: 557
diff changeset
  1333
For example, when $r_1$ and $r_1 \backslash_r c_1$ are not nullable,
Chengsong
parents: 557
diff changeset
  1334
the regular expression would not look like 
Chengsong
parents: 557
diff changeset
  1335
\[
Chengsong
parents: 557
diff changeset
  1336
	(r_1 \backslash_r c_1c_2 + \RZERO ) + \RZERO,
Chengsong
parents: 557
diff changeset
  1337
\]
Chengsong
parents: 557
diff changeset
  1338
but actually $r_1 \backslash_r c_1c_2$, the redundant $\RZERO$s will not be created in the
Chengsong
parents: 557
diff changeset
  1339
first place.
Chengsong
parents: 557
diff changeset
  1340
In a closed-form one would want to take into account this 
Chengsong
parents: 557
diff changeset
  1341
and generate the list of
Chengsong
parents: 557
diff changeset
  1342
regular expressions $r_2 \backslash_r s''$ with
Chengsong
parents: 557
diff changeset
  1343
string pairs $(s', s'')$ where $s'@s'' = s$ and
Chengsong
parents: 557
diff changeset
  1344
$r_1 \backslash s'$ nullable.
Chengsong
parents: 557
diff changeset
  1345
We denote the list consisting of such 
Chengsong
parents: 557
diff changeset
  1346
strings $s''$ as $\vsuf{s}{r_1}$.
Chengsong
parents: 557
diff changeset
  1347
Chengsong
parents: 557
diff changeset
  1348
The function $\vsuf{\_}{\_}$ is defined recursively on the structure of the string:
Chengsong
parents: 557
diff changeset
  1349
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1350
	\begin{tabular}{lcl}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1351
		$\vsuf{[]}{\_} $ & $=$ &  $[]$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1352
		$\vsuf{c::cs}{r_1}$ & $ =$ & $ \textit{if} (\rnullable{r_1}) \textit{then} \; (\vsuf{cs}{(\rder{c}{r_1})}) @ [c :: cs]$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1353
				    && $\textit{else} \; (\vsuf{cs}{(\rder{c}{r_1}) })  $
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1354
	\end{tabular}
558
Chengsong
parents: 557
diff changeset
  1355
\end{center}
Chengsong
parents: 557
diff changeset
  1356
\noindent
Chengsong
parents: 557
diff changeset
  1357
The list is sorted in the order $r_2\backslash s''$ 
Chengsong
parents: 557
diff changeset
  1358
appears in $(r_1\cdot r_2)\backslash s$.
Chengsong
parents: 557
diff changeset
  1359
In essence, $\vsuf{\_}{\_}$ is doing a 
Chengsong
parents: 557
diff changeset
  1360
"virtual derivative" of $r_1 \cdot r_2$, but instead of producing 
Chengsong
parents: 557
diff changeset
  1361
the entire result $(r_1 \cdot r_2) \backslash s$, 
Chengsong
parents: 557
diff changeset
  1362
it only stores all the strings $s''$ such that $r_2 \backslash s''$
Chengsong
parents: 557
diff changeset
  1363
are occurring terms in $(r_1\cdot r_2)\backslash s$.
Chengsong
parents: 557
diff changeset
  1364
Chengsong
parents: 557
diff changeset
  1365
To make the closed form representation 
Chengsong
parents: 557
diff changeset
  1366
more straightforward,
Chengsong
parents: 557
diff changeset
  1367
the flattetning function $\sflat{\_}$ is used to enable the transformation from 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1368
a left-associative nested sequence of alternatives into 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1369
a flattened list:
558
Chengsong
parents: 557
diff changeset
  1370
\[
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1371
	\sum [r_1, r_2, r_3, \ldots] \stackrel{\sflat{\_}}{\rightarrow} 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1372
	(\ldots ((r_1 + r_2) + r_3) + \ldots)
558
Chengsong
parents: 557
diff changeset
  1373
\]
Chengsong
parents: 557
diff changeset
  1374
\noindent
Chengsong
parents: 557
diff changeset
  1375
The definitions $\sflat{\_}$, $\sflataux{\_}$ are given below.
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1376
\begin{center}  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1377
	\begin{tabular}{ccc}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1378
		$\sflataux{\AALTS{ }{r :: rs}}$ & $=$ & $\sflataux{r} @ rs$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1379
		$\sflataux{\AALTS{ }{[]}}$ & $ = $ & $ []$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1380
		$\sflataux r$ & $=$ & $ [r]$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1381
	\end{tabular}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1382
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1383
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1384
\begin{center} 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1385
	\begin{tabular}{ccc}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1386
		$\sflat{(\sum r :: rs)}$ & $=$ & $\sum (\sflataux{r} @ rs)$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1387
		$\sflat{\sum []}$ & $ = $ & $ \sum []$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1388
		$\sflat r$ & $=$ & $ r$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1389
	\end{tabular}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1390
\end{center}
558
Chengsong
parents: 557
diff changeset
  1391
\noindent
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  1392
$\sflataux{\_}$ breaks up nested alternative regular expressions 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1393
of the $(\ldots((r_1 + r_2) + r_3) + \ldots )$(left-associated) shape
558
Chengsong
parents: 557
diff changeset
  1394
into a "balanced" list: $\AALTS{\_}{[r_1,\, r_2 ,\, r_3, \ldots]}$.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1395
It will return the singleton list $[r]$ otherwise.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1396
$\sflat{\_}$ works the same  as $\sflataux{\_}$, except that it keeps
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1397
the output type a regular expression, not a list.
558
Chengsong
parents: 557
diff changeset
  1398
$\sflataux{\_}$  and $\sflat{\_}$ are only recursive on the  
Chengsong
parents: 557
diff changeset
  1399
first element of the list.
Chengsong
parents: 557
diff changeset
  1400
Chengsong
parents: 557
diff changeset
  1401
With $\sflataux{}$ a preliminary to the closed form can be stated,
Chengsong
parents: 557
diff changeset
  1402
where the derivative of $r_1 \cdot r_2 \backslash s$ can be
Chengsong
parents: 557
diff changeset
  1403
flattened into a list whose head and tail meet the description
Chengsong
parents: 557
diff changeset
  1404
we gave earlier.
Chengsong
parents: 557
diff changeset
  1405
\begin{lemma}\label{seqSfau0}
Chengsong
parents: 557
diff changeset
  1406
	$\sflataux{\rders{(r_1 \cdot r_2) \backslash s }} = (r_1 \backslash_r s) \cdot r_2 
Chengsong
parents: 557
diff changeset
  1407
	:: (\map \; (r_2 \backslash_r \_) \; (\textit{Suffix} \; s \; r1))$ 
Chengsong
parents: 557
diff changeset
  1408
\end{lemma}
Chengsong
parents: 557
diff changeset
  1409
\begin{proof}
Chengsong
parents: 557
diff changeset
  1410
	By an induction on the string $s$, where the inductive cases 
Chengsong
parents: 557
diff changeset
  1411
	are split as $[]$ and $xs @ [x]$.
Chengsong
parents: 557
diff changeset
  1412
	Note the key identify holds:
Chengsong
parents: 557
diff changeset
  1413
	\[
Chengsong
parents: 557
diff changeset
  1414
		\map \; (r_2 \backslash_r \_) \; (\vsuf{[x]}{(r_1 \backslash_r xs)}) \;\; @ \;\;
Chengsong
parents: 557
diff changeset
  1415
		\map \; (\_ \backslash_r x) \; (\map \; (r_2 \backslash \_) \; (\vsuf{xs}{r_1}))
Chengsong
parents: 557
diff changeset
  1416
	\]
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1417
	=
558
Chengsong
parents: 557
diff changeset
  1418
	\[
Chengsong
parents: 557
diff changeset
  1419
		\map \; (r_2 \backslash_r \_) \; (\vsuf{xs @ [x]}{r_1})
Chengsong
parents: 557
diff changeset
  1420
	\]
Chengsong
parents: 557
diff changeset
  1421
	This enables the inductive case to go through.
Chengsong
parents: 557
diff changeset
  1422
\end{proof}
Chengsong
parents: 557
diff changeset
  1423
\noindent 
Chengsong
parents: 557
diff changeset
  1424
Note that this lemma does $\mathbf{not}$ depend on any
Chengsong
parents: 557
diff changeset
  1425
specific definitions we used,
Chengsong
parents: 557
diff changeset
  1426
allowing people investigating derivatives to get an alternative
Chengsong
parents: 557
diff changeset
  1427
view of what $r_1 \cdot r_2$ is.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1428
558
Chengsong
parents: 557
diff changeset
  1429
Now we are able to use this for the intuition that 
Chengsong
parents: 557
diff changeset
  1430
the different ways in which regular expressions are 
Chengsong
parents: 557
diff changeset
  1431
nested do not matter under $\rsimp{}$:
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1432
\begin{center}
558
Chengsong
parents: 557
diff changeset
  1433
	$\rsimp{r} \stackrel{?}{\sequal} \rsimp{r'}$ if $r = \sum [r_1, r_2, r_3, \ldots]$ 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1434
	and $r' =(\ldots ((r_1 + r_2) + r_3) + \ldots)$
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1435
\end{center}
558
Chengsong
parents: 557
diff changeset
  1436
Simply wrap with $\sum$ constructor and add 
Chengsong
parents: 557
diff changeset
  1437
simplifications to both sides of \ref{seqSfau0}
Chengsong
parents: 557
diff changeset
  1438
and one gets
Chengsong
parents: 557
diff changeset
  1439
\begin{corollary}\label{seqClosedFormGeneral}
Chengsong
parents: 557
diff changeset
  1440
	$\rsimp{\sflat{(r_1 \cdot r_2) \backslash s} }
Chengsong
parents: 557
diff changeset
  1441
	=\rsimp{(\sum (  (r_1 \backslash s) \cdot r_2 :: 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1442
	\map\; (r_2 \backslash \_) \; (\vsuf{s}{r_1})))}$
558
Chengsong
parents: 557
diff changeset
  1443
\end{corollary}
Chengsong
parents: 557
diff changeset
  1444
Together with the idempotency property of $\rsimp{}$ (lemma \ref{rsimpIdem}),
Chengsong
parents: 557
diff changeset
  1445
it is possible to convert the above lemma to obtain a "closed form"
Chengsong
parents: 557
diff changeset
  1446
for  derivatives nested with simplification:
Chengsong
parents: 557
diff changeset
  1447
\begin{lemma}\label{seqClosedForm}
Chengsong
parents: 557
diff changeset
  1448
	$\rderssimp{(r_1 \cdot r_2)}{s} = \rsimp{(\sum ((r_1 \backslash s) \cdot r_2 ) 
Chengsong
parents: 557
diff changeset
  1449
	:: (\map \; (r_2 \backslash \_) (\vsuf{s}{r_1})))}$
Chengsong
parents: 557
diff changeset
  1450
\end{lemma}
Chengsong
parents: 557
diff changeset
  1451
\begin{proof}
Chengsong
parents: 557
diff changeset
  1452
	By a case analysis of string $s$.
Chengsong
parents: 557
diff changeset
  1453
	When $s$ is empty list, the rewrite is straightforward.
Chengsong
parents: 557
diff changeset
  1454
	When $s$ is a list, one could use the corollary \ref{seqSfau0},
Chengsong
parents: 557
diff changeset
  1455
	and lemma \ref{Simpders} to rewrite the left-hand-side.
Chengsong
parents: 557
diff changeset
  1456
\end{proof}
Chengsong
parents: 557
diff changeset
  1457
As a corollary for this closed form, one can estimate the size 
Chengsong
parents: 557
diff changeset
  1458
of the sequence derivative $r_1 \cdot r_2 \backslash_r s$ using 
Chengsong
parents: 557
diff changeset
  1459
an easier-to-handle expression:
Chengsong
parents: 557
diff changeset
  1460
\begin{corollary}\label{seqEstimate1}
Chengsong
parents: 557
diff changeset
  1461
	\begin{center}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1462
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1463
		$\llbracket \rderssimp{(r_1 \cdot r_2)}{s} \rrbracket_r = \llbracket \rsimp{(\sum ((r_1 \backslash s) \cdot r_2 ) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1464
		:: (\map \; (r_2 \backslash \_) (\vsuf{s}{r_1})))} \rrbracket_r$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1465
558
Chengsong
parents: 557
diff changeset
  1466
	\end{center}
Chengsong
parents: 557
diff changeset
  1467
\end{corollary}
Chengsong
parents: 557
diff changeset
  1468
\noindent
Chengsong
parents: 557
diff changeset
  1469
\subsection{Closed Forms for Star Regular Expressions}
564
Chengsong
parents: 562
diff changeset
  1470
We have shown how to control the size of the sequence regular expression $r_1\cdot r_2$ using
Chengsong
parents: 562
diff changeset
  1471
the "closed form" of $(r_1 \cdot r_2) \backslash s$ and then 
Chengsong
parents: 562
diff changeset
  1472
the property of the $\distinct$ function.
Chengsong
parents: 562
diff changeset
  1473
Now we try to get a bound on $r^* \backslash s$ as well.
Chengsong
parents: 562
diff changeset
  1474
Again, we first look at how a star's derivatives evolve, if they grow maximally: 
Chengsong
parents: 562
diff changeset
  1475
\begin{center}
Chengsong
parents: 562
diff changeset
  1476
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1477
	$r^* \quad \longrightarrow_{\backslash c}  \quad   (r\backslash c)  \cdot  r^* \quad \longrightarrow_{\backslash c'}  \quad
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1478
	r \backslash cc'  \cdot r^* + r \backslash c' \cdot r^*  \quad \longrightarrow_{\backslash c''} \quad 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1479
	(r_1 \backslash cc'c'' \cdot r^* + r \backslash c'') + (r \backslash c'c'' \cdot r^* + r \backslash c'' \cdot r^*)   \quad \longrightarrow_{\backslash c'''}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1480
	\quad \ldots$
564
Chengsong
parents: 562
diff changeset
  1481
Chengsong
parents: 562
diff changeset
  1482
\end{center}
Chengsong
parents: 562
diff changeset
  1483
When we have a string $s = c :: c' :: c'' \ldots$  such that $r \backslash c$, $r \backslash cc'$, $r \backslash c'$, 
Chengsong
parents: 562
diff changeset
  1484
$r \backslash cc'c''$, $r \backslash c'c''$, $r\backslash c''$ etc. are all nullable,
Chengsong
parents: 562
diff changeset
  1485
the number of terms in $r^* \backslash s$ will grow exponentially, causing the size
Chengsong
parents: 562
diff changeset
  1486
of the derivatives $r^* \backslash s$ to grow exponentially, even if we do not 
Chengsong
parents: 562
diff changeset
  1487
count the possible size explosions of $r \backslash c$ themselves.
Chengsong
parents: 562
diff changeset
  1488
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  1489
Thanks to $\rflts$ and $\rDistinct$, we are able to open up regular expressions like
564
Chengsong
parents: 562
diff changeset
  1490
$(r_1 \backslash cc'c'' \cdot r^* + r \backslash c'') + 
Chengsong
parents: 562
diff changeset
  1491
(r \backslash c'c'' \cdot r^* + r \backslash c'' \cdot r^*) $ 
Chengsong
parents: 562
diff changeset
  1492
into $\RALTS{[r_1 \backslash cc'c'' \cdot r^*, r \backslash c'', 
Chengsong
parents: 562
diff changeset
  1493
r \backslash c'c'' \cdot r^*, r \backslash c'' \cdot r^*]}$
Chengsong
parents: 562
diff changeset
  1494
and then de-duplicate terms of the form $r\backslash s' \cdot r^*$ ($s'$ being a substring of $s$).
Chengsong
parents: 562
diff changeset
  1495
This allows us to use a similar technique as $r_1 \cdot r_2$ case,
Chengsong
parents: 562
diff changeset
  1496
where the crux is to get an equivalent form of 
Chengsong
parents: 562
diff changeset
  1497
$\rderssimp{r^*}{s}$ with shape $\rsimp{\sum rs}$.
Chengsong
parents: 562
diff changeset
  1498
This requires generating 
558
Chengsong
parents: 557
diff changeset
  1499
all possible sub-strings $s'$ of $s$
Chengsong
parents: 557
diff changeset
  1500
such that $r\backslash s' \cdot r^*$ will appear 
Chengsong
parents: 557
diff changeset
  1501
as a term in $(r^*) \backslash s$.
Chengsong
parents: 557
diff changeset
  1502
The first function we define is a single-step
Chengsong
parents: 557
diff changeset
  1503
updating function $\starupdate$, which takes three arguments as input:
Chengsong
parents: 557
diff changeset
  1504
the new character $c$ to take derivative with, 
Chengsong
parents: 557
diff changeset
  1505
the regular expression
Chengsong
parents: 557
diff changeset
  1506
$r$ directly under the star $r^*$, and the
Chengsong
parents: 557
diff changeset
  1507
list of strings $sSet$ for the derivative $r^* \backslash s$ 
Chengsong
parents: 557
diff changeset
  1508
up til this point  
Chengsong
parents: 557
diff changeset
  1509
such that $(r^*) \backslash s = \sum_{s' \in sSet} (r\backslash s') \cdot r^*$ 
Chengsong
parents: 557
diff changeset
  1510
(the equality is not exact, more on this later).
Chengsong
parents: 557
diff changeset
  1511
\begin{center}
Chengsong
parents: 557
diff changeset
  1512
	\begin{tabular}{lcl}
Chengsong
parents: 557
diff changeset
  1513
		$\starupdate \; c \; r \; [] $ & $\dn$ & $[]$\\
Chengsong
parents: 557
diff changeset
  1514
		$\starupdate \; c \; r \; (s :: Ss)$ & $\dn$ & \\
Chengsong
parents: 557
diff changeset
  1515
						     & & $\textit{if} \; 
Chengsong
parents: 557
diff changeset
  1516
						     (\rnullable \; (\rders \; r \; s))$ \\
Chengsong
parents: 557
diff changeset
  1517
						     & & $\textit{then} \;\; (s @ [c]) :: [c] :: (
Chengsong
parents: 557
diff changeset
  1518
						     \starupdate \; c \; r \; Ss)$ \\
Chengsong
parents: 557
diff changeset
  1519
						     & & $\textit{else} \;\; (s @ [c]) :: (
Chengsong
parents: 557
diff changeset
  1520
						     \starupdate \; c \; r \; Ss)$
Chengsong
parents: 557
diff changeset
  1521
	\end{tabular}
Chengsong
parents: 557
diff changeset
  1522
\end{center}
Chengsong
parents: 557
diff changeset
  1523
\noindent
Chengsong
parents: 557
diff changeset
  1524
As a generalisation from characters to strings,
Chengsong
parents: 557
diff changeset
  1525
$\starupdates$ takes a string instead of a character
Chengsong
parents: 557
diff changeset
  1526
as the first input argument, and is otherwise the same
Chengsong
parents: 557
diff changeset
  1527
as $\starupdate$.
Chengsong
parents: 557
diff changeset
  1528
\begin{center}
Chengsong
parents: 557
diff changeset
  1529
	\begin{tabular}{lcl}
Chengsong
parents: 557
diff changeset
  1530
		$\starupdates \; [] \; r \; Ss$ & $=$ & $Ss$\\
Chengsong
parents: 557
diff changeset
  1531
		$\starupdates \; (c :: cs) \; r \; Ss$ &  $=$ &  $\starupdates \; cs \; r \; (
Chengsong
parents: 557
diff changeset
  1532
		\starupdate \; c \; r \; Ss)$
Chengsong
parents: 557
diff changeset
  1533
	\end{tabular}
Chengsong
parents: 557
diff changeset
  1534
\end{center}
Chengsong
parents: 557
diff changeset
  1535
\noindent
Chengsong
parents: 557
diff changeset
  1536
For the star regular expression,
Chengsong
parents: 557
diff changeset
  1537
its derivatives can be seen as  a nested gigantic
Chengsong
parents: 557
diff changeset
  1538
alternative similar to that of sequence regular expression's derivatives, 
Chengsong
parents: 557
diff changeset
  1539
and therefore need
Chengsong
parents: 557
diff changeset
  1540
to be ``straightened out" as well.
Chengsong
parents: 557
diff changeset
  1541
The function for this would be $\hflat{}$ and $\hflataux{}$.
Chengsong
parents: 557
diff changeset
  1542
\begin{center}
Chengsong
parents: 557
diff changeset
  1543
	\begin{tabular}{lcl}
Chengsong
parents: 557
diff changeset
  1544
		$\hflataux{r_1 + r_2}$ & $\dn$ & $\hflataux{r_1} @ \hflataux{r_2}$\\
Chengsong
parents: 557
diff changeset
  1545
		$\hflataux{r}$ & $\dn$ & $[r]$
Chengsong
parents: 557
diff changeset
  1546
	\end{tabular}
Chengsong
parents: 557
diff changeset
  1547
\end{center}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1548
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1549
\begin{center}
558
Chengsong
parents: 557
diff changeset
  1550
	\begin{tabular}{lcl}
Chengsong
parents: 557
diff changeset
  1551
		$\hflat{r_1 + r_2}$ & $\dn$ & $\sum (\hflataux {r_1} @ \hflataux {r_2}) $\\
Chengsong
parents: 557
diff changeset
  1552
		$\hflat{r}$ & $\dn$ & $r$
Chengsong
parents: 557
diff changeset
  1553
	\end{tabular}
Chengsong
parents: 557
diff changeset
  1554
\end{center}
Chengsong
parents: 557
diff changeset
  1555
\noindent
Chengsong
parents: 557
diff changeset
  1556
%MAYBE TODO: introduce createdByStar
564
Chengsong
parents: 562
diff changeset
  1557
Again these definitions are tailor-made for dealing with alternatives that have
Chengsong
parents: 562
diff changeset
  1558
originated from a star's derivatives, so we do not attempt to open up all possible 
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  1559
regular expressions of the form $\RALTS{rs}$, where $\textit{rs}$ might not contain precisely 2
564
Chengsong
parents: 562
diff changeset
  1560
elements.
Chengsong
parents: 562
diff changeset
  1561
We give a predicate for such "star-created" regular expressions:
Chengsong
parents: 562
diff changeset
  1562
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1563
	\begin{tabular}{lcr}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1564
	 &    &       $\createdByStar{(\RSEQ{ra}{\RSTAR{rb}}) }$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1565
		$\createdByStar{r_1} \land \createdByStar{r_2} $ & $ \Longrightarrow$ & $\createdByStar{(r_1 + r_2)}$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1566
	\end{tabular}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1567
\end{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1568
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1569
These definitions allows us the flexibility to talk about 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1570
regular expressions in their most convenient format,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1571
for example, flattened out $\RALTS{[r_1, r_2, \ldots, r_n]} $
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1572
instead of binary-nested: $((r_1 + r_2) + (r_3 + r_4)) + \ldots$.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1573
These definitions help express that certain classes of syntatically 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1574
distinct regular expressions are actually the same under simplification.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1575
This is not entirely true for annotated regular expressions: 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1576
%TODO: bsimp bders \neq bderssimp
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1577
\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1578
	$(1+ (c\cdot \ASEQ{bs}{c^*}{c} ))$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1579
\end{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1580
For bit-codes, the order in which simplification is applied
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1581
might cause a difference in the location they are placed.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1582
If we want something like
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1583
\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1584
	$\bderssimp{r}{s} \myequiv \bsimp{\bders{r}{s}}$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1585
\end{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1586
Some "canonicalization" procedure is required,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1587
which either pushes all the common bitcodes to nodes
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1588
as senior as possible:
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1589
\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1590
	$_{bs}(_{bs_1 @ bs'}r_1 + _{bs_1 @ bs''}r_2) \rightarrow _{bs @ bs_1}(_{bs'}r_1 + _{bs''}r_2) $
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1591
\end{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1592
or does the reverse. However bitcodes are not of interest if we are talking about
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1593
the $\llbracket r \rrbracket$ size of a regex.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1594
Therefore for the ease and simplicity of producing a
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1595
proof for a size bound, we are happy to restrict ourselves to 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1596
unannotated regular expressions, and obtain such equalities as
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1597
\begin{lemma}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1598
	$\rsimp{r_1 + r_2} = \rsimp{\RALTS{\hflataux{r_1} @ \hflataux{r_2}}}$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1599
\end{lemma}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1600
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1601
\begin{proof}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1602
	By using the rewriting relation $\rightsquigarrow$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1603
\end{proof}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1604
%TODO: rsimp sflat
564
Chengsong
parents: 562
diff changeset
  1605
And from this we obtain a proof that a star's derivative will be the same
Chengsong
parents: 562
diff changeset
  1606
as if it had all its nested alternatives created during deriving being flattened out:
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1607
For example,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1608
\begin{lemma}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1609
	$\createdByStar{r} \implies \rsimp{r} = \rsimp{\RALTS{\hflataux{r}}}$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1610
\end{lemma}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1611
\begin{proof}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1612
	By structural induction on $r$, where the induction rules are these of $\createdByStar{_}$.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1613
\end{proof}
564
Chengsong
parents: 562
diff changeset
  1614
% The simplification of a flattened out regular expression, provided it comes
Chengsong
parents: 562
diff changeset
  1615
%from the derivative of a star, is the same as the one nested.
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1616
564
Chengsong
parents: 562
diff changeset
  1617
Chengsong
parents: 562
diff changeset
  1618
558
Chengsong
parents: 557
diff changeset
  1619
We first introduce an inductive property
Chengsong
parents: 557
diff changeset
  1620
for $\starupdate$ and $\hflataux{\_}$, 
Chengsong
parents: 557
diff changeset
  1621
it says if we do derivatives of $r^*$
Chengsong
parents: 557
diff changeset
  1622
with a string that starts with $c$,
Chengsong
parents: 557
diff changeset
  1623
then flatten it out,
Chengsong
parents: 557
diff changeset
  1624
we obtain a list
Chengsong
parents: 557
diff changeset
  1625
of the shape $\sum_{s' \in sSet} (r\backslash_r s') \cdot r^*$,
Chengsong
parents: 557
diff changeset
  1626
where $sSet = \starupdates \; s \; r \; [[c]]$.
Chengsong
parents: 557
diff changeset
  1627
\begin{lemma}\label{starHfauInduct}
Chengsong
parents: 557
diff changeset
  1628
	$\hflataux{(\rders{( (\rder{c}{r_0})\cdot(r_0^*))}{s})} = 
Chengsong
parents: 557
diff changeset
  1629
	\map \; (\lambda s_1. (r_0 \backslash_r s_1) \cdot (r_0^*)) \; 
Chengsong
parents: 557
diff changeset
  1630
	(\starupdates \; s \; r_0 \; [[c]])$
Chengsong
parents: 557
diff changeset
  1631
\end{lemma}
Chengsong
parents: 557
diff changeset
  1632
\begin{proof}
Chengsong
parents: 557
diff changeset
  1633
	By an induction on $s$, the inductive cases
Chengsong
parents: 557
diff changeset
  1634
	being $[]$ and $s@[c]$.
Chengsong
parents: 557
diff changeset
  1635
\end{proof}
Chengsong
parents: 557
diff changeset
  1636
\noindent
Chengsong
parents: 557
diff changeset
  1637
Here is a corollary that states the lemma in
Chengsong
parents: 557
diff changeset
  1638
a more intuitive way:
Chengsong
parents: 557
diff changeset
  1639
\begin{corollary}
Chengsong
parents: 557
diff changeset
  1640
	$\hflataux{r^* \backslash_r (c::xs)} = \map \; (\lambda s. (r \backslash_r s) \cdot
Chengsong
parents: 557
diff changeset
  1641
	(r^*))\; (\starupdates \; c\; r\; [[c]])$
Chengsong
parents: 557
diff changeset
  1642
\end{corollary}
Chengsong
parents: 557
diff changeset
  1643
\noindent
Chengsong
parents: 557
diff changeset
  1644
Note that this is also agnostic of the simplification
Chengsong
parents: 557
diff changeset
  1645
function we defined, and is therefore of more general interest.
Chengsong
parents: 557
diff changeset
  1646
Chengsong
parents: 557
diff changeset
  1647
Now adding the $\rsimp{}$ bit for closed forms,
Chengsong
parents: 557
diff changeset
  1648
we have
Chengsong
parents: 557
diff changeset
  1649
\begin{lemma}
Chengsong
parents: 557
diff changeset
  1650
	$a :: rs \grewrites \hflataux{a} @ rs$
Chengsong
parents: 557
diff changeset
  1651
\end{lemma}
Chengsong
parents: 557
diff changeset
  1652
\noindent
Chengsong
parents: 557
diff changeset
  1653
giving us
Chengsong
parents: 557
diff changeset
  1654
\begin{lemma}\label{cbsHfauRsimpeq1}
Chengsong
parents: 557
diff changeset
  1655
	$\rsimp{a+b} = \rsimp{(\sum \hflataux{a} @ \hflataux{b})}$.
Chengsong
parents: 557
diff changeset
  1656
\end{lemma}
Chengsong
parents: 557
diff changeset
  1657
\noindent
Chengsong
parents: 557
diff changeset
  1658
This yields
Chengsong
parents: 557
diff changeset
  1659
\begin{lemma}\label{hfauRsimpeq2}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1660
	$\rsimp{r} = \rsimp{(\sum \hflataux{r})}$
558
Chengsong
parents: 557
diff changeset
  1661
\end{lemma}
Chengsong
parents: 557
diff changeset
  1662
\noindent
Chengsong
parents: 557
diff changeset
  1663
Together with the rewriting relation
Chengsong
parents: 557
diff changeset
  1664
\begin{lemma}\label{starClosedForm6Hrewrites}
Chengsong
parents: 557
diff changeset
  1665
	$\map \; (\lambda s. (\rsimp{r \backslash_r s}) \cdot (r^*)) \; Ss
Chengsong
parents: 557
diff changeset
  1666
	\scfrewrites
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1667
	\map \; (\lambda s. (\rsimp{r \backslash_r s}) \cdot (r^*)) \; Ss$
558
Chengsong
parents: 557
diff changeset
  1668
\end{lemma}
Chengsong
parents: 557
diff changeset
  1669
\noindent
Chengsong
parents: 557
diff changeset
  1670
We obtain the closed form for star regular expression:
Chengsong
parents: 557
diff changeset
  1671
\begin{lemma}\label{starClosedForm}
Chengsong
parents: 557
diff changeset
  1672
	$\rderssimp{r^*}{c::s} = 
Chengsong
parents: 557
diff changeset
  1673
	\rsimp{
Chengsong
parents: 557
diff changeset
  1674
		(\sum (\map \; (\lambda s. (\rderssimp{r}{s})\cdot r^*) \; 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1675
		(\starupdates \; s\; r \; [[c]])
558
Chengsong
parents: 557
diff changeset
  1676
		)
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1677
		)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1678
	}
558
Chengsong
parents: 557
diff changeset
  1679
	$
Chengsong
parents: 557
diff changeset
  1680
\end{lemma}
Chengsong
parents: 557
diff changeset
  1681
\begin{proof}
Chengsong
parents: 557
diff changeset
  1682
	By an induction on $s$.
Chengsong
parents: 557
diff changeset
  1683
	The lemmas \ref{rsimpIdem}, \ref{starHfauInduct}, and \ref{hfauRsimpeq2}
Chengsong
parents: 557
diff changeset
  1684
	are used.	
Chengsong
parents: 557
diff changeset
  1685
\end{proof}
Chengsong
parents: 557
diff changeset
  1686
\section{Estimating the Closed Forms' sizes}
Chengsong
parents: 557
diff changeset
  1687
We now summarize the closed forms below:
Chengsong
parents: 557
diff changeset
  1688
\begin{itemize}
Chengsong
parents: 557
diff changeset
  1689
	\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1690
		$\rderssimp{(\sum rs)}{s} \sequal
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1691
		\sum \; (\map \; (\rderssimp{\_}{s}) \; rs)$
558
Chengsong
parents: 557
diff changeset
  1692
	\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1693
		$\rderssimp{(r_1 \cdot r_2)}{s} \sequal \sum ((r_1 \backslash s) \cdot r_2 ) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1694
		:: (\map \; (r_2 \backslash \_) (\vsuf{s}{r_1}))$
558
Chengsong
parents: 557
diff changeset
  1695
	\item
Chengsong
parents: 557
diff changeset
  1696
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1697
		$\rderssimp{r^*}{c::s} = 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1698
		\rsimp{
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1699
			(\sum (\map \; (\lambda s. (\rderssimp{r}{s})\cdot r^*) \; 
558
Chengsong
parents: 557
diff changeset
  1700
			(\starupdates \; s\; r \; [[c]])
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1701
			)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1702
			)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1703
		}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1704
		$
558
Chengsong
parents: 557
diff changeset
  1705
\end{itemize}	
Chengsong
parents: 557
diff changeset
  1706
\noindent	
Chengsong
parents: 557
diff changeset
  1707
The closed forms on the left-hand-side
Chengsong
parents: 557
diff changeset
  1708
are all of the same shape: $\rsimp{ (\sum rs)} $.
Chengsong
parents: 557
diff changeset
  1709
Such regular expression will be bounded by the size of $\sum rs'$, 
Chengsong
parents: 557
diff changeset
  1710
where every element in $rs'$ is distinct, and each element 
Chengsong
parents: 557
diff changeset
  1711
can be described by some inductive sub-structures 
Chengsong
parents: 557
diff changeset
  1712
(for example when $r = r_1 \cdot r_2$ then $rs'$ 
Chengsong
parents: 557
diff changeset
  1713
will be solely comprised of $r_1 \backslash s'$ 
Chengsong
parents: 557
diff changeset
  1714
and $r_2 \backslash s''$, $s'$ and $s''$ being 
Chengsong
parents: 557
diff changeset
  1715
sub-strings of $s$).
Chengsong
parents: 557
diff changeset
  1716
which will each have a size uppder bound 
Chengsong
parents: 557
diff changeset
  1717
according to inductive hypothesis, which controls $r \backslash s$.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1718
558
Chengsong
parents: 557
diff changeset
  1719
We elaborate the above reasoning by a series of lemmas
Chengsong
parents: 557
diff changeset
  1720
below, where straightforward proofs are omitted.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1721
\begin{lemma}
558
Chengsong
parents: 557
diff changeset
  1722
	If $\forall r \in rs. \rsize{r} $ is less than or equal to $N$,
Chengsong
parents: 557
diff changeset
  1723
	and $\textit{length} \; rs$ is less than or equal to $l$,
Chengsong
parents: 557
diff changeset
  1724
	then $\rsize{\sum rs}$ is less than or equal to $l*N + 1$.
Chengsong
parents: 557
diff changeset
  1725
\end{lemma}
Chengsong
parents: 557
diff changeset
  1726
\noindent
Chengsong
parents: 557
diff changeset
  1727
If we define all regular expressions with size no
Chengsong
parents: 557
diff changeset
  1728
more than $N$ as $\sizeNregex \; N$:
Chengsong
parents: 557
diff changeset
  1729
\[
Chengsong
parents: 557
diff changeset
  1730
	\sizeNregex \; N \dn  \{r \mid \rsize{r} \leq N \}
Chengsong
parents: 557
diff changeset
  1731
\]
Chengsong
parents: 557
diff changeset
  1732
Then such set is finite:
Chengsong
parents: 557
diff changeset
  1733
\begin{lemma}\label{finiteSizeN}
Chengsong
parents: 557
diff changeset
  1734
	$\textit{isFinite}\; (\sizeNregex \; N)$
Chengsong
parents: 557
diff changeset
  1735
\end{lemma}
Chengsong
parents: 557
diff changeset
  1736
\begin{proof}
Chengsong
parents: 557
diff changeset
  1737
	By overestimating the set $\sizeNregex \; N + 1$
Chengsong
parents: 557
diff changeset
  1738
	using union of sets like
Chengsong
parents: 557
diff changeset
  1739
	$\{r_1 \cdot r_2 \mid r_1 \in A
Chengsong
parents: 557
diff changeset
  1740
		\text{and}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1741
	r_2 \in A\}
558
Chengsong
parents: 557
diff changeset
  1742
	$ where $A = \sizeNregex \; N$.
Chengsong
parents: 557
diff changeset
  1743
\end{proof}
Chengsong
parents: 557
diff changeset
  1744
\noindent
Chengsong
parents: 557
diff changeset
  1745
From this we get a corollary that
Chengsong
parents: 557
diff changeset
  1746
if forall $r \in rs$, $\rsize{r} \leq N$, then the output of 
Chengsong
parents: 557
diff changeset
  1747
$\rdistinct{rs}{\varnothing}$ is a list of regular
Chengsong
parents: 557
diff changeset
  1748
expressions of finite size depending on $N$ only. 
561
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  1749
\begin{corollary}\label{finiteSizeNCorollary}
558
Chengsong
parents: 557
diff changeset
  1750
	Assumes that for all $r \in rs. \rsize{r} \leq N$,
Chengsong
parents: 557
diff changeset
  1751
	and the cardinality of $\sizeNregex \; N$ is $c_N$
Chengsong
parents: 557
diff changeset
  1752
	then$\rsize{\rdistinct{rs}{\varnothing}} \leq c*N$.
Chengsong
parents: 557
diff changeset
  1753
\end{corollary}
Chengsong
parents: 557
diff changeset
  1754
\noindent
Chengsong
parents: 557
diff changeset
  1755
We have proven that the output of $\rdistinct{rs'}{\varnothing}$
Chengsong
parents: 557
diff changeset
  1756
is bounded by a constant $c_N$ depending only on $N$,
Chengsong
parents: 557
diff changeset
  1757
provided that each of $rs'$'s element
Chengsong
parents: 557
diff changeset
  1758
is bounded by $N$.
Chengsong
parents: 557
diff changeset
  1759
We want to apply it to our setting $\rsize{\rsimp{\sum rs}}$.
Chengsong
parents: 557
diff changeset
  1760
Chengsong
parents: 557
diff changeset
  1761
We show how $\rdistinct$ and $\rflts$
Chengsong
parents: 557
diff changeset
  1762
in the simplification function together is at least as 
Chengsong
parents: 557
diff changeset
  1763
good as $\rdistinct{}{}$ alone.
Chengsong
parents: 557
diff changeset
  1764
\begin{lemma}\label{interactionFltsDB}
Chengsong
parents: 557
diff changeset
  1765
	$\llbracket \rdistinct{(\rflts \; \textit{rs})}{\varnothing} \rrbracket_r 
Chengsong
parents: 557
diff changeset
  1766
	\leq 
Chengsong
parents: 557
diff changeset
  1767
	\llbracket \rdistinct{rs}{\varnothing}  \rrbracket_r  $.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1768
\end{lemma}
558
Chengsong
parents: 557
diff changeset
  1769
\noindent
Chengsong
parents: 557
diff changeset
  1770
The intuition is that if we remove duplicates from the $\textit{LHS}$, at least the same amount of 
Chengsong
parents: 557
diff changeset
  1771
duplicates will be removed from the list $\textit{rs}$ in the $\textit{RHS}$. 
Chengsong
parents: 557
diff changeset
  1772
Chengsong
parents: 557
diff changeset
  1773
Now this $\rsimp{\sum rs}$ can be estimated using $\rdistinct{rs}{\varnothing}$:
Chengsong
parents: 557
diff changeset
  1774
\begin{lemma}\label{altsSimpControl}
Chengsong
parents: 557
diff changeset
  1775
	$\rsize{\rsimp{\sum rs}} \leq \rsize{\rdistinct{rs}{\varnothing}}+ 1$
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1776
\end{lemma}
558
Chengsong
parents: 557
diff changeset
  1777
\begin{proof}
Chengsong
parents: 557
diff changeset
  1778
	By using \ref{interactionFltsDB}.
Chengsong
parents: 557
diff changeset
  1779
\end{proof}
Chengsong
parents: 557
diff changeset
  1780
\noindent
Chengsong
parents: 557
diff changeset
  1781
which says that the size of regular expression
Chengsong
parents: 557
diff changeset
  1782
is always smaller if we apply the full simplification
Chengsong
parents: 557
diff changeset
  1783
rather than just one component ($\rdistinct{}{}$).
Chengsong
parents: 557
diff changeset
  1784
Chengsong
parents: 557
diff changeset
  1785
Chengsong
parents: 557
diff changeset
  1786
Now we are ready to control the sizes of
Chengsong
parents: 557
diff changeset
  1787
$r_1 \cdot r_2 \backslash s$, $r^* \backslash s$.
Chengsong
parents: 557
diff changeset
  1788
\begin{theorem}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1789
	For any regex $r$, $\exists N_r. \forall s. \; \rsize{\rderssimp{r}{s}} \leq N_r$
558
Chengsong
parents: 557
diff changeset
  1790
\end{theorem}
Chengsong
parents: 557
diff changeset
  1791
\noindent
Chengsong
parents: 557
diff changeset
  1792
\begin{proof}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1793
	We prove this by induction on $r$. The base cases for $\RZERO$,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1794
	$\RONE $ and $\RCHAR{c}$ are straightforward. 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1795
	In the sequence $r_1 \cdot r_2$ case,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1796
	the inductive hypotheses state 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1797
	$\exists N_1. \forall s. \; \llbracket \rderssimp{r}{s} \rrbracket \leq N_1$ and
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1798
	$\exists N_2. \forall s. \; \llbracket \rderssimp{r_2}{s} \rrbracket \leq N_2$. 
562
Chengsong
parents: 561
diff changeset
  1799
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1800
	When the string $s$ is not empty, we can reason as follows
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1801
	%
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1802
	\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1803
		\begin{tabular}{lcll}
558
Chengsong
parents: 557
diff changeset
  1804
& & $ \llbracket   \rderssimp{r_1\cdot r_2 }{s} \rrbracket_r $\\
561
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  1805
& $ = $ & $\llbracket \rsimp{(\sum(r_1 \backslash_{rsimp} s \cdot r_2 \; \;  :: \; \; 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1806
		\map \; (r_2\backslash_{rsimp} \_)\; (\vsuf{s}{r})))} \rrbracket_r $ & (1) \\			
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1807
										     & $\leq$ & $\llbracket \rdistinct{(r_1 \backslash_{rsimp} s \cdot r_2 \; \;  :: \; \; 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1808
	\map \; (r_2\backslash_{rsimp} \_)\; (\vsuf{s}{r}))}{\varnothing} \rrbracket_r  + 1$ & (2) \\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1809
											     & $\leq$ & $2 + N_1 + \rsize{r_2} + (N_2 * (card\;(\sizeNregex \; N_2)))$ & (3)\\
558
Chengsong
parents: 557
diff changeset
  1810
\end{tabular}
Chengsong
parents: 557
diff changeset
  1811
\end{center}
561
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  1812
\noindent
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  1813
(1) is by the corollary \ref{seqEstimate1}.
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  1814
(2) is by \ref{altsSimpControl}.
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  1815
(3) is by \ref{finiteSizeNCorollary}.
562
Chengsong
parents: 561
diff changeset
  1816
Chengsong
parents: 561
diff changeset
  1817
Chengsong
parents: 561
diff changeset
  1818
Combining the cases when $s = []$ and $s \neq []$, we get (4):
Chengsong
parents: 561
diff changeset
  1819
\begin{center}
Chengsong
parents: 561
diff changeset
  1820
	\begin{tabular}{lcll}
Chengsong
parents: 561
diff changeset
  1821
		$\rsize{(r_1 \cdot r_2) \backslash_r s}$ & $\leq$ & 
Chengsong
parents: 561
diff changeset
  1822
		$max \; (2 + N_1 + 
Chengsong
parents: 561
diff changeset
  1823
		\llbracket r_2 \rrbracket_r + 
Chengsong
parents: 561
diff changeset
  1824
		N_2 * (card\; (\sizeNregex \; N_2))) \; \rsize{r_1\cdot r_2}$ & (4)
Chengsong
parents: 561
diff changeset
  1825
	\end{tabular}
Chengsong
parents: 561
diff changeset
  1826
\end{center}
558
Chengsong
parents: 557
diff changeset
  1827
562
Chengsong
parents: 561
diff changeset
  1828
We reason similarly for  $\STAR$.
Chengsong
parents: 561
diff changeset
  1829
The inductive hypothesis is
Chengsong
parents: 561
diff changeset
  1830
$\exists N. \forall s. \; \llbracket \rderssimp{r}{s} \rrbracket \leq N$.
564
Chengsong
parents: 562
diff changeset
  1831
Let $n_r = \llbracket r^* \rrbracket_r$.
562
Chengsong
parents: 561
diff changeset
  1832
When $s = c :: cs$ is not empty,
Chengsong
parents: 561
diff changeset
  1833
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1834
	\begin{tabular}{lcll}
562
Chengsong
parents: 561
diff changeset
  1835
& & $ \llbracket   \rderssimp{r^* }{c::cs} \rrbracket_r $\\
Chengsong
parents: 561
diff changeset
  1836
& $ = $ & $\llbracket \rsimp{(\sum (\map \; (\lambda s. (r \backslash_{rsimp} s) \cdot r^*) \; (\starupdates\; 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1837
	cs \; r \; [[c]] )) )} \rrbracket_r $ & (5) \\			
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1838
					      & $\leq$ & $\llbracket 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1839
					      \rdistinct{
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1840
						      (\map \; 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1841
						      (\lambda s. (r \backslash_{rsimp} s) \cdot r^*) \; 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1842
						      (\starupdates\; cs \; r \; [[c]] )
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1843
					      )}
562
Chengsong
parents: 561
diff changeset
  1844
	{\varnothing} \rrbracket_r  + 1$ & (6) \\
Chengsong
parents: 561
diff changeset
  1845
					 & $\leq$ & $1 + (\textit{card} (\sizeNregex \; (N + n_r)))
Chengsong
parents: 561
diff changeset
  1846
	* (1 + (N + n_r)) $ & (7)\\
Chengsong
parents: 561
diff changeset
  1847
\end{tabular}
Chengsong
parents: 561
diff changeset
  1848
\end{center}
Chengsong
parents: 561
diff changeset
  1849
\noindent
Chengsong
parents: 561
diff changeset
  1850
(5) is by the lemma  \ref{starClosedForm}.
Chengsong
parents: 561
diff changeset
  1851
(6) is by \ref{altsSimpControl}.
Chengsong
parents: 561
diff changeset
  1852
(7) is by \ref{finiteSizeNCorollary}.
Chengsong
parents: 561
diff changeset
  1853
Combining with the case when $s = []$, one gets
Chengsong
parents: 561
diff changeset
  1854
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1855
	\begin{tabular}{lcll}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1856
		$\rsize{r^* \backslash_r s}$ & $\leq$ & $max \; n_r \; 1 + (\textit{card} (\sizeNregex \; (N + n_r)))
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1857
		* (1 + (N + n_r)) $ & (8)\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1858
	\end{tabular}
562
Chengsong
parents: 561
diff changeset
  1859
\end{center}
Chengsong
parents: 561
diff changeset
  1860
\noindent
Chengsong
parents: 561
diff changeset
  1861
Chengsong
parents: 561
diff changeset
  1862
The alternative case is slightly less involved.
Chengsong
parents: 561
diff changeset
  1863
The inductive hypothesis 
Chengsong
parents: 561
diff changeset
  1864
is equivalent to $\exists N. \forall r \in (\map \; (\_ \backslash_r s) \; rs). \rsize{r} \leq N$.
Chengsong
parents: 561
diff changeset
  1865
In the case when $s = c::cs$, we have 
Chengsong
parents: 561
diff changeset
  1866
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1867
	\begin{tabular}{lcll}
562
Chengsong
parents: 561
diff changeset
  1868
& & $ \llbracket   \rderssimp{\sum rs }{c::cs} \rrbracket_r $\\
Chengsong
parents: 561
diff changeset
  1869
& $ = $ & $\llbracket \rsimp{(\sum (\map \; (\_ \backslash_{rsimp} s)  \; rs) )} \rrbracket_r $ & (9) \\			
Chengsong
parents: 561
diff changeset
  1870
& $\leq$ & $\llbracket (\sum (\map \; (\_ \backslash_{rsimp} s)  \; rs) ) \rrbracket_r $  & (10) \\
Chengsong
parents: 561
diff changeset
  1871
& $\leq$ & $1 + N * (length \; rs) $ & (11)\\
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1872
	\end{tabular}
562
Chengsong
parents: 561
diff changeset
  1873
\end{center}
Chengsong
parents: 561
diff changeset
  1874
\noindent
Chengsong
parents: 561
diff changeset
  1875
(9) is by \ref{altsClosedForm}, (10) by \ref{rsimpSize} and (11) by inductive hypothesis.
Chengsong
parents: 561
diff changeset
  1876
Chengsong
parents: 561
diff changeset
  1877
Combining with the case when $s = []$, one gets
Chengsong
parents: 561
diff changeset
  1878
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1879
	\begin{tabular}{lcll}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1880
		$\rsize{\sum rs \backslash_r s}$ & $\leq$ & $max \; \rsize{\sum rs} \; 1+N*(length \; rs)$ 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1881
						 & (12)\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1882
	\end{tabular}
562
Chengsong
parents: 561
diff changeset
  1883
\end{center}
Chengsong
parents: 561
diff changeset
  1884
(4), (8), and (12) are all the inductive cases proven.
558
Chengsong
parents: 557
diff changeset
  1885
\end{proof}
Chengsong
parents: 557
diff changeset
  1886
564
Chengsong
parents: 562
diff changeset
  1887
Chengsong
parents: 562
diff changeset
  1888
\begin{corollary}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1889
	For any regex $a$, $\exists N_r. \forall s. \; \rsize{\bderssimp{a}{s}} \leq N_r$
564
Chengsong
parents: 562
diff changeset
  1890
\end{corollary}
Chengsong
parents: 562
diff changeset
  1891
\begin{proof}
Chengsong
parents: 562
diff changeset
  1892
	By \ref{sizeRelations}.
Chengsong
parents: 562
diff changeset
  1893
\end{proof}
558
Chengsong
parents: 557
diff changeset
  1894
\noindent
Chengsong
parents: 557
diff changeset
  1895
Chengsong
parents: 557
diff changeset
  1896
%-----------------------------------
Chengsong
parents: 557
diff changeset
  1897
%	SECTION 2
Chengsong
parents: 557
diff changeset
  1898
%-----------------------------------
Chengsong
parents: 557
diff changeset
  1899
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1900
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1901
%----------------------------------------------------------------------------------------
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1902
%	SECTION 3
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1903
%----------------------------------------------------------------------------------------
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1904
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1905
554
Chengsong
parents: 553
diff changeset
  1906
\subsection{A Closed Form for the Sequence Regular Expression}
Chengsong
parents: 553
diff changeset
  1907
\noindent
Chengsong
parents: 553
diff changeset
  1908
Chengsong
parents: 553
diff changeset
  1909
Before we get to the proof that says the intermediate result of our lexer will
Chengsong
parents: 553
diff changeset
  1910
remain finitely bounded, which is an important efficiency/liveness guarantee,
Chengsong
parents: 553
diff changeset
  1911
we shall first develop a few preparatory properties and definitions to 
Chengsong
parents: 553
diff changeset
  1912
make the process of proving that a breeze.
Chengsong
parents: 553
diff changeset
  1913
Chengsong
parents: 553
diff changeset
  1914
We define rewriting relations for $\rrexp$s, which allows us to do the 
Chengsong
parents: 553
diff changeset
  1915
same trick as we did for the correctness proof,
Chengsong
parents: 553
diff changeset
  1916
but this time we will have stronger equalities established.
Chengsong
parents: 553
diff changeset
  1917
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1918
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1919
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1920
What guarantee does this bound give us?
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1921
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1922
Whatever the regex is, it will not grow indefinitely.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1923
Take our previous example $(a + aa)^*$ as an example:
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1924
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1925
	\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1926
		\begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1927
			\begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1928
				xlabel={number of $a$'s},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1929
				x label style={at={(1.05,-0.05)}},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1930
				ylabel={regex size},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1931
				enlargelimits=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1932
				xtick={0,5,...,30},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1933
				xmax=33,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1934
				ymax= 40,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1935
				ytick={0,10,...,40},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1936
				scaled ticks=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1937
				axis lines=left,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1938
				width=5cm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1939
				height=4cm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1940
				legend entries={$(a + aa)^*$},  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1941
				legend pos=north west,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1942
				legend cell align=left]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1943
				\addplot[red,mark=*, mark options={fill=white}] table {a_aa_star.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1944
			\end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1945
		\end{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1946
	\end{tabular}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1947
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1948
We are able to limit the size of the regex $(a + aa)^*$'s derivatives
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1949
with our simplification
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1950
rules very effectively.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1951
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1952
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1953
In our proof for the inductive case $r_1 \cdot r_2$, the dominant term in the bound
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1954
is $l_{N_2} * N_2$, where $N_2$ is the bound we have for $\llbracket \bderssimp{r_2}{s} \rrbracket$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1955
Given that $l_{N_2}$ is roughly the size $4^{N_2}$, the size bound $\llbracket \bderssimp{r_1 \cdot r_2}{s} \rrbracket$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1956
inflates the size bound of $\llbracket \bderssimp{r_2}{s} \rrbracket$ with the function
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1957
$f(x) = x * 2^x$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1958
This means the bound we have will surge up at least
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1959
tower-exponentially with a linear increase of the depth.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1960
For a regex of depth $n$, the bound
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1961
would be approximately $4^n$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1962
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1963
Test data in the graphs from randomly generated regular expressions
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1964
shows that the giant bounds are far from being hit.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1965
%a few sample regular experessions' derivatives
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1966
%size change
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  1967
%TODO: giving regex1_size_change.data showing a few regular expressions' size changes 
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1968
%w;r;t the input characters number, where the size is usually cubic in terms of original size
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1969
%a*, aa*, aaa*, .....
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  1970
%randomly generated regular expressions
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1971
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1972
	\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1973
		\begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1974
			\begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1975
				xlabel={number of $a$'s},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1976
				x label style={at={(1.05,-0.05)}},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1977
				ylabel={regex size},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1978
				enlargelimits=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1979
				xtick={0,5,...,30},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1980
				xmax=33,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1981
				ymax=1000,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1982
				ytick={0,100,...,1000},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1983
				scaled ticks=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1984
				axis lines=left,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1985
				width=5cm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1986
				height=4cm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1987
				legend entries={regex1},  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1988
				legend pos=north west,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1989
				legend cell align=left]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1990
				\addplot[red,mark=*, mark options={fill=white}] table {regex1_size_change.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1991
			\end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1992
		\end{tikzpicture}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1993
  &
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1994
  \begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1995
	  \begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1996
		  xlabel={$n$},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1997
		  x label style={at={(1.05,-0.05)}},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1998
		  %ylabel={time in secs},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1999
		  enlargelimits=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2000
		  xtick={0,5,...,30},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2001
		  xmax=33,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2002
		  ymax=1000,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2003
		  ytick={0,100,...,1000},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2004
		  scaled ticks=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2005
		  axis lines=left,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2006
		  width=5cm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2007
		  height=4cm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2008
		  legend entries={regex2},  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2009
		  legend pos=north west,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2010
		  legend cell align=left]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2011
		  \addplot[blue,mark=*, mark options={fill=white}] table {regex2_size_change.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2012
	  \end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2013
  \end{tikzpicture}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2014
  &
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2015
  \begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2016
	  \begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2017
		  xlabel={$n$},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2018
		  x label style={at={(1.05,-0.05)}},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2019
		  %ylabel={time in secs},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2020
		  enlargelimits=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2021
		  xtick={0,5,...,30},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2022
		  xmax=33,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2023
		  ymax=1000,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2024
		  ytick={0,100,...,1000},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2025
		  scaled ticks=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2026
		  axis lines=left,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2027
		  width=5cm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2028
		  height=4cm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2029
		  legend entries={regex3},  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2030
		  legend pos=north west,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2031
		  legend cell align=left]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2032
		  \addplot[cyan,mark=*, mark options={fill=white}] table {regex3_size_change.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2033
	  \end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2034
  \end{tikzpicture}\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2035
  \multicolumn{3}{c}{Graphs: size change of 3 randomly generated regular expressions $w.r.t.$ input string length.}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2036
	\end{tabular}    
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2037
\end{center}  
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2038
\noindent
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2039
Most of the regex's sizes seem to stay within a polynomial bound $w.r.t$ the 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2040
original size.
591
b2d0de6aee18 more polishing integrated comments chap2
Chengsong
parents: 590
diff changeset
  2041
We will discuss improvements to this bound in the next chapter.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2042
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2043
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2044
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2045
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2046
%	SECTION ??
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2047
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2048
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2049
%-----------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2050
%	SECTION syntactic equivalence under simp
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2051
%-----------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2052
\section{Syntactic Equivalence Under $\simp$}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2053
We prove that minor differences can be annhilated
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2054
by $\simp$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2055
For example,
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2056
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2057
	$\simp \;(\simpALTs\; (\map \;(\_\backslash \; x)\; (\distinct \; \mathit{rs}\; \phi))) = 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2058
	\simp \;(\simpALTs \;(\distinct \;(\map \;(\_ \backslash\; x) \; \mathit{rs}) \; \phi))$
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2059
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2060
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2061
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2062
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2063
%	SECTION ALTS CLOSED FORM
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2064
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2065
\section{A Closed Form for \textit{ALTS}}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2066
Now we prove that  $rsimp (rders\_simp (RALTS rs) s) = rsimp (RALTS (map (\lambda r. rders\_simp r s) rs))$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2067
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2068
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2069
There are a few key steps, one of these steps is
556
Chengsong
parents: 555
diff changeset
  2070
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2071
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2072
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2073
One might want to prove this by something a simple statement like: 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2074
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2075
For this to hold we want the $\textit{distinct}$ function to pick up
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2076
the elements before and after derivatives correctly:
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2077
$r \in rset \equiv (rder x r) \in (rder x rset)$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2078
which essentially requires that the function $\backslash$ is an injective mapping.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2079
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2080
Unfortunately the function $\backslash c$ is not an injective mapping.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2081
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2082
\subsection{function $\backslash c$ is not injective (1-to-1)}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2083
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2084
	The derivative $w.r.t$ character $c$ is not one-to-one.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2085
	Formally,
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2086
	$\exists r_1 \;r_2. r_1 \neq r_2 \mathit{and} r_1 \backslash c = r_2 \backslash c$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2087
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2088
This property is trivially true for the
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2089
character regex example:
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2090
\begin{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2091
	$r_1 = e; \; r_2 = d;\; r_1 \backslash c = \ZERO = r_2 \backslash c$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2092
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2093
But apart from the cases where the derivative
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2094
output is $\ZERO$, are there non-trivial results
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2095
of derivatives which contain strings?
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2096
The answer is yes.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2097
For example,
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2098
\begin{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2099
	Let $r_1 = a^*b\;\quad r_2 = (a\cdot a^*)\cdot b + b$.\\
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2100
	where $a$ is not nullable.\\
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2101
	$r_1 \backslash c = ((a \backslash c)\cdot a^*)\cdot c + b \backslash c$\\
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2102
	$r_2 \backslash c = ((a \backslash c)\cdot a^*)\cdot c + b \backslash c$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2103
\end{center}
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  2104
We start with two syntactically different regular expressions,
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2105
and end up with the same derivative result.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2106
This is not surprising as we have such 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2107
equality as below in the style of Arden's lemma:\\
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2108
\begin{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2109
	$L(A^*B) = L(A\cdot A^* \cdot B + B)$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2110
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2111
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2112
There are two problems with this finiteness result, though.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2113
\begin{itemize}
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2114
	\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2115
		First, It is not yet a direct formalisation of our lexer's complexity,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2116
		as a complexity proof would require looking into 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2117
		the time it takes to execute {\bf all} the operations
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2118
		involved in the lexer (simp, collect, decode), not just the derivative.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2119
	\item
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2120
		Second, the bound is not yet tight, and we seek to improve $N_a$ so that
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2121
		it is polynomial on $\llbracket a \rrbracket$.
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2122
\end{itemize}
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2123
Still, we believe this contribution is fruitful,
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2124
because
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2125
\begin{itemize}
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2126
	\item
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2127
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2128
		The size proof can serve as a cornerstone for a complexity
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2129
		formalisation.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2130
		Derivatives are the most important phases of our lexer algorithm.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2131
		Size properties about derivatives covers the majority of the algorithm
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2132
		and is therefore a good indication of complexity of the entire program.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2133
	\item
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2134
		The bound is already a strong indication that catastrophic
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2135
		backtracking is much less likely to occur in our $\blexersimp$
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2136
		algorithm.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2137
		We refine $\blexersimp$ with $\blexerStrong$ in the next chapter
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2138
		so that the bound becomes polynomial.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2139
\end{itemize}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2140
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2141
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2142
%	SECTION 4
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2143
%----------------------------------------------------------------------------------------
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2144
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2145
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2146
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2147
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2148
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2149
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2150
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2151
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2152
One might wonder the actual bound rather than the loose bound we gave
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2153
for the convenience of an easier proof.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2154
How much can the regex $r^* \backslash s$ grow? 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2155
As  earlier graphs have shown,
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2156
%TODO: reference that graph where size grows quickly
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2157
they can grow at a maximum speed
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2158
exponential $w.r.t$ the number of characters, 
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2159
but will eventually level off when the string $s$ is long enough.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2160
If they grow to a size exponential $w.r.t$ the original regex, our algorithm
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2161
would still be slow.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2162
And unfortunately, we have concrete examples
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  2163
where such regular expressions grew exponentially large before levelling off:
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2164
$(a ^ * + (aa) ^ * + (aaa) ^ * + \ldots + 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2165
(\underbrace{a \ldots a}_{\text{n a's}})^*$ will already have a maximum
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2166
size that is  exponential on the number $n$ 
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2167
under our current simplification rules:
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2168
%TODO: graph of a regex whose size increases exponentially.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2169
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2170
	\begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2171
		\begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2172
			height=0.5\textwidth,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2173
			width=\textwidth,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2174
			xlabel=number of a's,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2175
			xtick={0,...,9},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2176
			ylabel=maximum size,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2177
			ymode=log,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2178
			log basis y={2}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2179
			]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2180
			\addplot[mark=*,blue] table {re-chengsong.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2181
		\end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2182
	\end{tikzpicture}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2183
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2184
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2185
For convenience we use $(\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2186
to express $(a ^ * + (aa) ^ * + (aaa) ^ * + \ldots + 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2187
(\underbrace{a \ldots a}_{\text{n a's}})^*$ in the below discussion.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2188
The exponential size is triggered by that the regex
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2189
$\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2190
inside the $(\ldots) ^*$ having exponentially many
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2191
different derivatives, despite those difference being minor.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2192
$(\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*\backslash \underbrace{a \ldots a}_{\text{m a's}}$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2193
will therefore contain the following terms (after flattening out all nested 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2194
alternatives):
cc54ce075db5 restructured
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parents:
diff changeset
  2195
\begin{center}
593
83fab852d72d more chap5
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parents: 591
diff changeset
  2196
	$(\oplus_{i = 1]{n}  (\underbrace{a \ldots a}_{\text{((i - (m' \% i))\%i) a's}})\cdot  (\underbrace{a \ldots a}_{\text{i a's}})^* })\cdot (\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)$\\
83fab852d72d more chap5
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parents: 591
diff changeset
  2197
	$(1 \leq m' \leq m )$
532
cc54ce075db5 restructured
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parents:
diff changeset
  2198
\end{center}
cc54ce075db5 restructured
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parents:
diff changeset
  2199
These terms are distinct for $m' \leq L.C.M.(1, \ldots, n)$ (will be explained in appendix).
593
83fab852d72d more chap5
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parents: 591
diff changeset
  2200
With each new input character taking the derivative against the intermediate result, more and more such distinct
83fab852d72d more chap5
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parents: 591
diff changeset
  2201
terms will accumulate, 
532
cc54ce075db5 restructured
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parents:
diff changeset
  2202
until the length reaches $L.C.M.(1, \ldots, n)$.
cc54ce075db5 restructured
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parents:
diff changeset
  2203
$\textit{distinctBy}$ will not be able to de-duplicate any two of these terms 
cc54ce075db5 restructured
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parents:
diff changeset
  2204
$(\oplus_{i = 1}^{n}  (\underbrace{a \ldots a}_{\text{((i - (m' \% i))\%i) a's}})\cdot  (\underbrace{a \ldots a}_{\text{i a's}})^* )\cdot (\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*$\\
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2205
cc54ce075db5 restructured
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parents:
diff changeset
  2206
$(\oplus_{i = 1}^{n}  (\underbrace{a \ldots a}_{\text{((i - (m'' \% i))\%i) a's}})\cdot  (\underbrace{a \ldots a}_{\text{i a's}})^* )\cdot (\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*$\\
593
83fab852d72d more chap5
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parents: 591
diff changeset
  2207
where $m' \neq m''$ \\
83fab852d72d more chap5
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parents: 591
diff changeset
  2208
as they are slightly different.
83fab852d72d more chap5
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parents: 591
diff changeset
  2209
This means that with our current simplification methods,
83fab852d72d more chap5
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parents: 591
diff changeset
  2210
we will not be able to control the derivative so that
83fab852d72d more chap5
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parents: 591
diff changeset
  2211
$\llbracket \bderssimp{r}{s} \rrbracket$ stays polynomial %\leq O((\llbracket r\rrbacket)^c)$
83fab852d72d more chap5
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parents: 591
diff changeset
  2212
as there are already exponentially many terms.
83fab852d72d more chap5
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parents: 591
diff changeset
  2213
These terms are similar in the sense that the head of those terms
83fab852d72d more chap5
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parents: 591
diff changeset
  2214
are all consisted of sub-terms of the form: 
83fab852d72d more chap5
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parents: 591
diff changeset
  2215
$(\underbrace{a \ldots a}_{\text{j a's}})\cdot  (\underbrace{a \ldots a}_{\text{i a's}})^* $.
83fab852d72d more chap5
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parents: 591
diff changeset
  2216
For  $\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*$, there will be at most
83fab852d72d more chap5
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parents: 591
diff changeset
  2217
$n * (n + 1) / 2$ such terms. 
83fab852d72d more chap5
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parents: 591
diff changeset
  2218
For example, $(a^* + (aa)^* + (aaa)^*) ^*$'s derivatives
83fab852d72d more chap5
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parents: 591
diff changeset
  2219
can be described by 6 terms:
83fab852d72d more chap5
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parents: 591
diff changeset
  2220
$a^*$, $a\cdot (aa)^*$, $ (aa)^*$, 
83fab852d72d more chap5
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parents: 591
diff changeset
  2221
$aa \cdot (aaa)^*$, $a \cdot (aaa)^*$, and $(aaa)^*$.
532
cc54ce075db5 restructured
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parents:
diff changeset
  2222
The total number of different "head terms",  $n * (n + 1) / 2$,
593
83fab852d72d more chap5
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parents: 591
diff changeset
  2223
is proportional to the number of characters in the regex 
532
cc54ce075db5 restructured
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parents:
diff changeset
  2224
$(\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*$.
cc54ce075db5 restructured
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parents:
diff changeset
  2225
This suggests a slightly different notion of size, which we call the 
cc54ce075db5 restructured
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parents:
diff changeset
  2226
alphabetic width:
cc54ce075db5 restructured
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parents:
diff changeset
  2227
%TODO:
cc54ce075db5 restructured
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parents:
diff changeset
  2228
(TODO: Alphabetic width def.)
cc54ce075db5 restructured
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parents:
diff changeset
  2229
593
83fab852d72d more chap5
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parents: 591
diff changeset
  2230
532
cc54ce075db5 restructured
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parents:
diff changeset
  2231
Antimirov\parencite{Antimirov95} has proven that 
cc54ce075db5 restructured
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parents:
diff changeset
  2232
$\textit{PDER}_{UNIV}(r) \leq \textit{awidth}(r)$.
cc54ce075db5 restructured
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parents:
diff changeset
  2233
where $\textit{PDER}_{UNIV}(r)$ is a set of all possible subterms
cc54ce075db5 restructured
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parents:
diff changeset
  2234
created by doing derivatives of $r$ against all possible strings.
cc54ce075db5 restructured
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parents:
diff changeset
  2235
If we can make sure that at any moment in our lexing algorithm our 
cc54ce075db5 restructured
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parents:
diff changeset
  2236
intermediate result hold at most one copy of each of the 
cc54ce075db5 restructured
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parents:
diff changeset
  2237
subterms then we can get the same bound as Antimirov's.
cc54ce075db5 restructured
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parents:
diff changeset
  2238
This leads to the algorithm in the next chapter.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2239
cc54ce075db5 restructured
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parents:
diff changeset
  2240
cc54ce075db5 restructured
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parents:
diff changeset
  2241
cc54ce075db5 restructured
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parents:
diff changeset
  2242
cc54ce075db5 restructured
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parents:
diff changeset
  2243
cc54ce075db5 restructured
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parents:
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  2244
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
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parents:
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  2245
%	SECTION 1
cc54ce075db5 restructured
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parents:
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  2246
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
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parents:
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  2247
cc54ce075db5 restructured
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parents:
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  2248
cc54ce075db5 restructured
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parents:
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  2249
%-----------------------------------
cc54ce075db5 restructured
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parents:
diff changeset
  2250
%	SUBSECTION 1
cc54ce075db5 restructured
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parents:
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  2251
%-----------------------------------
cc54ce075db5 restructured
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parents:
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  2252
\subsection{Syntactic Equivalence Under $\simp$}
cc54ce075db5 restructured
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parents:
diff changeset
  2253
We prove that minor differences can be annhilated
cc54ce075db5 restructured
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parents:
diff changeset
  2254
by $\simp$.
cc54ce075db5 restructured
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parents:
diff changeset
  2255
For example,
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2256
\begin{center}
593
83fab852d72d more chap5
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parents: 591
diff changeset
  2257
	$\simp \;(\simpALTs\; (\map \;(\_\backslash \; x)\; (\distinct \; \mathit{rs}\; \phi))) = 
83fab852d72d more chap5
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parents: 591
diff changeset
  2258
	\simp \;(\simpALTs \;(\distinct \;(\map \;(\_ \backslash\; x) \; \mathit{rs}) \; \phi))$
532
cc54ce075db5 restructured
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parents:
diff changeset
  2259
\end{center}
cc54ce075db5 restructured
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parents:
diff changeset
  2260