ChengsongTanPhdThesis/Chapters/Finite.tex
author Chengsong
Wed, 12 Oct 2022 14:01:33 +0100
changeset 613 b0f0d884a547
parent 611 bc1df466150a
child 614 d5e9bcb384ec
permissions -rwxr-xr-x
chap5
Ignore whitespace changes - Everywhere: Within whitespace: At end of lines:
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     1
% Chapter Template
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     2
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     3
\chapter{Finiteness Bound} % Main chapter title
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     4
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     5
\label{Finite} 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     6
%  In Chapter 4 \ref{Chapter4} we give the second guarantee
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     7
%of our bitcoded algorithm, that is a finite bound on the size of any 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     8
%regex's derivatives. 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
     9
613
Chengsong
parents: 611
diff changeset
    10
\begin{figure}
Chengsong
parents: 611
diff changeset
    11
\begin{center}
Chengsong
parents: 611
diff changeset
    12
	\begin{tabular}{ccc}
Chengsong
parents: 611
diff changeset
    13
		$\llbracket _{bs}\ONE \rrbracket$ & $\dn$ & $1$\\
Chengsong
parents: 611
diff changeset
    14
		$\llbracket \ZERO \rrbracket$ & $\dn$ & $1$ \\
Chengsong
parents: 611
diff changeset
    15
		$\llbracket _{bs} r_1 \cdot r_2 \rrbracket$ & $\dn$ & $\llbracket r_1 \rrbracket + \llbracket r_2 \rrbracket + 1$\\
Chengsong
parents: 611
diff changeset
    16
		$\llbracket _{bs}\mathbf{c} \rrbracket $ & $\dn$ & $1$\\
Chengsong
parents: 611
diff changeset
    17
		$\llbracket _{bs}\sum as \rrbracket $ & $\dn$ & $\map \; (\llbracket \_ \rrbracket)\; as   + 1$\\
Chengsong
parents: 611
diff changeset
    18
		$\llbracket _{bs} a^* \rrbracket $ & $\dn$ & $\llbracket a \rrbracket + 1$.
Chengsong
parents: 611
diff changeset
    19
	\end{tabular}
Chengsong
parents: 611
diff changeset
    20
\end{center}
Chengsong
parents: 611
diff changeset
    21
\caption{The size function of bitcoded regular expressions}\label{brexpSize}
Chengsong
parents: 611
diff changeset
    22
\end{figure}
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
    23
In this chapter we give a guarantee in terms of size: 
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    24
given an annotated regular expression $a$, for any string $s$
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    25
our algorithm $\blexersimp$'s internal annotated regular expression 
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    26
size  is finitely bounded
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    27
by a constant $N_a$ that only depends on $a$:
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
    28
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    29
	$\llbracket \bderssimp{a}{s} \rrbracket \leq N_a$
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
    30
\end{center}
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
    31
\noindent
577
f47fc4840579 thesis chap2
Chengsong
parents: 576
diff changeset
    32
where the size of an annotated regular expression is defined
613
Chengsong
parents: 611
diff changeset
    33
in terms of the number of nodes in its tree structure (see figure \ref{brexpSize}).
Chengsong
parents: 611
diff changeset
    34
We believe this size bound
Chengsong
parents: 611
diff changeset
    35
is important in the context of POSIX lexing, because 
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    36
\begin{itemize}
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    37
	\item
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    38
		It is a stepping stone towards an ``absence of catastrophic-backtracking''
613
Chengsong
parents: 611
diff changeset
    39
		guarantee. 
Chengsong
parents: 611
diff changeset
    40
		If the internal data structures used by our algorithm cannot grow very large,
Chengsong
parents: 611
diff changeset
    41
		then our algorithm (which traverses those structures) cannot be too slow.
Chengsong
parents: 611
diff changeset
    42
		The next step would be to refine the bound $N_a$ so that it
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    43
		is polynomial on $\llbracket a\rrbracket$.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    44
	\item
613
Chengsong
parents: 611
diff changeset
    45
		Having it formalised gives us a higher confidence that
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    46
		our simplification algorithm $\simp$ does not ``mis-behave''
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    47
		like $\simpsulz$ does.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    48
		The bound is universal, which is an advantage over work which 
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    49
		only gives empirical evidence on some test cases.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    50
\end{itemize}
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
    51
\section{Formalising About Size}
577
f47fc4840579 thesis chap2
Chengsong
parents: 576
diff changeset
    52
\noindent
613
Chengsong
parents: 611
diff changeset
    53
In our lexer ($\blexersimp$),
Chengsong
parents: 611
diff changeset
    54
we take an annotated regular expression as input,
Chengsong
parents: 611
diff changeset
    55
and repeately take derivative of and simplify it:
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    56
\begin{figure}[H]
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    57
	\begin{tikzpicture}[scale=2,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    58
		every node/.style={minimum size=11mm},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    59
		->,>=stealth',shorten >=1pt,auto,thick
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    60
		]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    61
		\node (r0) [rectangle, draw=black, thick, minimum size = 5mm, draw=blue] {$a$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    62
		\node (r1) [rectangle, draw=black, thick, right=of r0, minimum size = 7mm]{$a_1$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    63
		\draw[->,line width=0.2mm](r0)--(r1) node[above,midway] {$\backslash c_1$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    64
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    65
		\node (r1s) [rectangle, draw=blue, thick, right=of r1, minimum size=6mm]{$a_{1s}$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    66
		\draw[->, line width=0.2mm](r1)--(r1s) node[above, midway] {$\simp$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    67
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    68
		\node (r2) [rectangle, draw=black, thick,  right=of r1s, minimum size = 12mm]{$a_2$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    69
		\draw[->,line width=0.2mm](r1s)--(r2) node[above,midway] {$\backslash c_2$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    70
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    71
		\node (r2s) [rectangle, draw = blue, thick, right=of r2,minimum size=6mm]{$a_{2s}$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    72
		\draw[->,line width=0.2mm](r2)--(r2s) node[above,midway] {$\simp$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    73
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    74
		\node (rns) [rectangle, draw = blue, thick, right=of r2s,minimum size=6mm]{$a_{ns}$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    75
		\draw[->,line width=0.2mm, dashed](r2s)--(rns) node[above,midway] {$\backslash \ldots$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    76
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    77
		\node (v) [circle, thick, draw, right=of rns, minimum size=6mm, right=1.7cm]{$v$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    78
		\draw[->, line width=0.2mm](rns)--(v) node[above, midway] {\bmkeps} node [below, midway] {\decode};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    79
	\end{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    80
	\caption{Regular expression size change during our $\blexersimp$ algorithm}\label{simpShrinks}
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    81
\end{figure}
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
    82
\noindent
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    83
Each time
613
Chengsong
parents: 611
diff changeset
    84
a derivative is taken, the regular expression might grow.
Chengsong
parents: 611
diff changeset
    85
However, the simplification that is immediately afterwards will always shrink it so that 
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    86
it stays small.
577
f47fc4840579 thesis chap2
Chengsong
parents: 576
diff changeset
    87
This intuition is depicted by the relative size
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    88
change between the black and blue nodes:
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    89
After $\simp$ the node always shrinks.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    90
Our proof says that all the blue nodes
613
Chengsong
parents: 611
diff changeset
    91
stay below a size bound $N_a$ determined by the input $a$.
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
    92
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    93
\noindent
613
Chengsong
parents: 611
diff changeset
    94
Sulzmann and Lu's assumed a similar picture about their algorithm,
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    95
though in fact their algorithm's size might be better depicted by the following graph:
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
    96
\begin{figure}[H]
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    97
	\begin{tikzpicture}[scale=2,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    98
		every node/.style={minimum size=11mm},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
    99
		->,>=stealth',shorten >=1pt,auto,thick
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   100
		]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   101
		\node (r0) [rectangle, draw=black, thick, minimum size = 5mm, draw=blue] {$a$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   102
		\node (r1) [rectangle, draw=black, thick, right=of r0, minimum size = 7mm]{$a_1$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   103
		\draw[->,line width=0.2mm](r0)--(r1) node[above,midway] {$\backslash c_1$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   104
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   105
		\node (r1s) [rectangle, draw=blue, thick, right=of r1, minimum size=7mm]{$a_{1s}$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   106
		\draw[->, line width=0.2mm](r1)--(r1s) node[above, midway] {$\simp'$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   107
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   108
		\node (r2) [rectangle, draw=black, thick,  right=of r1s, minimum size = 17mm]{$a_2$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   109
		\draw[->,line width=0.2mm](r1s)--(r2) node[above,midway] {$\backslash c_2$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   110
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   111
		\node (r2s) [rectangle, draw = blue, thick, right=of r2,minimum size=14mm]{$a_{2s}$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   112
		\draw[->,line width=0.2mm](r2)--(r2s) node[above,midway] {$\simp'$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   113
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   114
		\node (r3) [rectangle, draw = black, thick, right= of r2s, minimum size = 22mm]{$a_3$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   115
		\draw[->,line width=0.2mm](r2s)--(r3) node[above,midway] {$\backslash c_3$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   116
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   117
		\node (rns) [right = of r3, draw=blue, minimum size = 20mm]{$a_{3s}$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   118
		\draw[->,line width=0.2mm] (r3)--(rns) node [above, midway] {$\simp'$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   119
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   120
		\node (rnn) [right = of rns, minimum size = 1mm]{};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   121
		\draw[->, dashed] (rns)--(rnn) node [above, midway] {$\ldots$};
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   122
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   123
	\end{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   124
	\caption{Regular expression size change during our $\blexersimp$ algorithm}\label{sulzShrinks}
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   125
\end{figure}
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   126
\noindent
613
Chengsong
parents: 611
diff changeset
   127
The picture means that on certain cases their lexer (where they use $\simpsulz$ 
Chengsong
parents: 611
diff changeset
   128
as the simplification function)
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   129
will have an indefinite size explosion, causing the running time 
613
Chengsong
parents: 611
diff changeset
   130
of each derivative step to grow continuously (for example 
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   131
in \ref{SulzmannLuLexerTime}).
613
Chengsong
parents: 611
diff changeset
   132
They tested out the run time of their
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   133
lexer on particular examples such as $(a+b+ab)^*$
613
Chengsong
parents: 611
diff changeset
   134
and claimed that their algorithm is linear w.r.t to the input.
Chengsong
parents: 611
diff changeset
   135
With our mecahnised proof, we avoid this type of unintentional
Chengsong
parents: 611
diff changeset
   136
generalisation.\\
Chengsong
parents: 611
diff changeset
   137
Chengsong
parents: 611
diff changeset
   138
Before delving in to the details of the formalisation,
Chengsong
parents: 611
diff changeset
   139
we are going to provide an overview of it.
Chengsong
parents: 611
diff changeset
   140
In the next subsection, we draw a picture of the bird's eye view
Chengsong
parents: 611
diff changeset
   141
of the proof.
Chengsong
parents: 611
diff changeset
   142
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   143
577
f47fc4840579 thesis chap2
Chengsong
parents: 576
diff changeset
   144
\subsection{Overview of the Proof}
613
Chengsong
parents: 611
diff changeset
   145
Here is a bird's eye view of the main components of the finiteness proof,
577
f47fc4840579 thesis chap2
Chengsong
parents: 576
diff changeset
   146
which involves three steps:
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   147
\begin{figure}[H]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   148
	\begin{tikzpicture}[scale=1,font=\bf,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   149
		node/.style={
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   150
			rectangle,rounded corners=3mm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   151
			ultra thick,draw=black!50,minimum height=18mm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   152
			minimum width=20mm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   153
		top color=white,bottom color=black!20}]
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   154
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   155
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   156
		\node (0) at (-5,0) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   157
			[node, text width=1.8cm, text centered] 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   158
			{$\llbracket \bderssimp{a}{s} \rrbracket$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   159
		\node (A) at (0,0) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   160
			[node,text width=1.6cm,  text centered] 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   161
			{$\llbracket \rderssimp{r}{s} \rrbracket_r$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   162
		\node (B) at (3,0) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   163
			[node,text width=3.0cm, anchor=west, minimum width = 40mm] 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   164
			{$\llbracket \textit{ClosedForm}(r, s)\rrbracket_r$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   165
		\node (C) at (9.5,0) [node, minimum width=10mm] {$N_r$};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   166
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   167
		\draw [->,line width=0.5mm] (0) -- 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   168
			node [above,pos=0.45] {=} (A) node [below, pos = 0.45] {$(r = a \downarrow_r)$} (A); 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   169
		\draw [->,line width=0.5mm] (A) -- 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   170
			node [above,pos=0.35] {$\quad =\ldots=$} (B); 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   171
		\draw [->,line width=0.5mm] (B) -- 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   172
			node [above,pos=0.35] {$\quad \leq \ldots \leq$} (C); 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   173
	\end{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   174
	%\caption{
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   175
\end{figure}
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   176
\noindent
577
f47fc4840579 thesis chap2
Chengsong
parents: 576
diff changeset
   177
We explain the steps one by one:
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   178
\begin{itemize}
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   179
	\item
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   180
		We first introduce the operations such as 
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   181
		derivatives, simplification, size calculation, etc.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   182
		associated with $\rrexp$s, which we have given
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   183
		a very brief introduction to in chapter \ref{Bitcoded2}.
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   184
		The operations on $\rrexp$s are identical to those on
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   185
		annotated regular expressions except that they are unaware
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   186
		of bitcodes. This means that all proofs about size of $\rrexp$s will apply to
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   187
		annotated regular expressions.
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   188
	\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   189
		We prove that $\rderssimp{r}{s} = \textit{ClosedForm}(r, s)$,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   190
		where $\textit{ClosedForm}(r, s)$ is entirely 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   191
		written in the derivatives of their children regular 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   192
		expressions.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   193
		We call the right-hand-side the \emph{Closed Form}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   194
		of the derivative $\rderssimp{r}{s}$.
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
   195
	\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   196
		We estimate $\llbracket \textit{ClosedForm}(r, s) \rrbracket_r$.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   197
		The key observation is that $\distinctBy$'s output is
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   198
		a list with a constant length bound.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   199
\end{itemize}
594
Chengsong
parents: 593
diff changeset
   200
We will expand on these steps in the next sections.\\
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   201
613
Chengsong
parents: 611
diff changeset
   202
\section{The $\textit{Rrexp}$ Datatype}
594
Chengsong
parents: 593
diff changeset
   203
The first step is to define 
Chengsong
parents: 593
diff changeset
   204
$\textit{rrexp}$s.
Chengsong
parents: 593
diff changeset
   205
They are without bitcodes,
Chengsong
parents: 593
diff changeset
   206
allowing a much simpler size bound proof.
Chengsong
parents: 593
diff changeset
   207
Of course, the bits which encode the lexing information 
Chengsong
parents: 593
diff changeset
   208
would grow linearly with respect 
Chengsong
parents: 593
diff changeset
   209
to the input, which should be taken into account when we wish to tackle the runtime comlexity.
Chengsong
parents: 593
diff changeset
   210
But for the sake of the structural size 
Chengsong
parents: 593
diff changeset
   211
we can safely ignore them.\\
Chengsong
parents: 593
diff changeset
   212
To recapitulate, the datatype 
Chengsong
parents: 593
diff changeset
   213
definition of the $\rrexp$, called
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   214
\emph{r-regular expressions},
594
Chengsong
parents: 593
diff changeset
   215
was initially defined in \ref{rrexpDef}.
Chengsong
parents: 593
diff changeset
   216
The reason for the prefix $r$ is
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   217
to make a distinction  
594
Chengsong
parents: 593
diff changeset
   218
with basic regular expressions.
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   219
\[			\rrexp ::=   \RZERO \mid  \RONE
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   220
	\mid  \RCHAR{c}  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   221
	\mid  \RSEQ{r_1}{r_2}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   222
	\mid  \RALTS{rs}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   223
	\mid \RSTAR{r}        
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   224
\]
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   225
The size of an r-regular expression is
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   226
written $\llbracket r\rrbracket_r$, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   227
whose definition mirrors that of an annotated regular expression. 
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   228
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   229
	\begin{tabular}{ccc}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   230
		$\llbracket _{bs}\ONE \rrbracket_r$ & $\dn$ & $1$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   231
		$\llbracket \ZERO \rrbracket_r$ & $\dn$ & $1$ \\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   232
		$\llbracket _{bs} r_1 \cdot r_2 \rrbracket_r$ & $\dn$ & $\llbracket r_1 \rrbracket_r + \llbracket r_2 \rrbracket_r + 1$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   233
		$\llbracket _{bs}\mathbf{c} \rrbracket_r $ & $\dn$ & $1$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   234
		$\llbracket _{bs}\sum as \rrbracket_r $ & $\dn$ & $\map \; (\llbracket \_ \rrbracket_r)\; as   + 1$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   235
		$\llbracket _{bs} a^* \rrbracket_r $ & $\dn$ & $\llbracket a \rrbracket_r + 1$.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   236
	\end{tabular}
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   237
\end{center}
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   238
\noindent
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   239
The $r$ in the subscript of $\llbracket \rrbracket_r$ is to 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   240
differentiate with the same operation for annotated regular expressions.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   241
Adding $r$ as subscript will be used in 
594
Chengsong
parents: 593
diff changeset
   242
other operations as well.\\
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   243
The transformation from an annotated regular expression
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   244
to an r-regular expression is straightforward.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   245
\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   246
	\begin{tabular}{lcl}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   247
		$\rerase{\ZERO}$ & $\dn$ & $\RZERO$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   248
		$\rerase{_{bs}\ONE}$ & $\dn$ & $\RONE$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   249
		$\rerase{_{bs}\mathbf{c}}$ & $\dn$ & $\RCHAR{c}$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   250
		$\rerase{_{bs}r_1\cdot r_2}$ & $\dn$ & $\RSEQ{\rerase{r_1}}{\rerase{r_2}}$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   251
		$\rerase{_{bs}\sum as}$ & $\dn$ & $\RALTS{\map \; \rerase{\_} \; as}$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   252
		$\rerase{_{bs} a ^*}$ & $\dn$ & $\rerase{a} ^*$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   253
	\end{tabular}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   254
\end{center}
594
Chengsong
parents: 593
diff changeset
   255
613
Chengsong
parents: 611
diff changeset
   256
\subsection{Why a New Datatype?}
594
Chengsong
parents: 593
diff changeset
   257
The reason we take all the trouble 
Chengsong
parents: 593
diff changeset
   258
defining a new datatype is that $\erase$ makes things harder.
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   259
We initially started by using 
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   260
plain regular expressions and tried to prove
594
Chengsong
parents: 593
diff changeset
   261
the lemma \ref{rsizeAsize},
Chengsong
parents: 593
diff changeset
   262
however the $\erase$ function unavoidbly messes with the structure of the 
Chengsong
parents: 593
diff changeset
   263
annotated regular expression.
Chengsong
parents: 593
diff changeset
   264
The $+$ constructor
Chengsong
parents: 593
diff changeset
   265
of basic regular expressions is binary whereas $\sum$ 
Chengsong
parents: 593
diff changeset
   266
takes a list, and one has to convert between them:
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   267
\begin{center}
594
Chengsong
parents: 593
diff changeset
   268
	\begin{tabular}{ccc}
Chengsong
parents: 593
diff changeset
   269
		$\erase \; _{bs}\sum [] $ & $\dn$ & $\ZERO$\\
Chengsong
parents: 593
diff changeset
   270
		$\erase \; _{bs}\sum [a]$ & $\dn$ & $a$\\
Chengsong
parents: 593
diff changeset
   271
		$\erase \; _{bs}\sum a :: as$ & $\dn$ & $a + (\erase \; _{[]} \sum as)\quad \text{if $as$ length over 1}$
Chengsong
parents: 593
diff changeset
   272
	\end{tabular}
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
   273
\end{center}
594
Chengsong
parents: 593
diff changeset
   274
\noindent
Chengsong
parents: 593
diff changeset
   275
An alternative regular expression with an empty argument list
Chengsong
parents: 593
diff changeset
   276
will be turned into a $\ZERO$.
Chengsong
parents: 593
diff changeset
   277
The singleton alternative $\sum [r]$ would have $r$ during the
Chengsong
parents: 593
diff changeset
   278
$\erase$ function.
Chengsong
parents: 593
diff changeset
   279
The  annotated regular expression $\sum[a, b, c]$ would turn into
Chengsong
parents: 593
diff changeset
   280
$(a+(b+c))$.
Chengsong
parents: 593
diff changeset
   281
All these operations change the size and structure of
Chengsong
parents: 593
diff changeset
   282
an annotated regular expressions, adding unnecessary 
Chengsong
parents: 593
diff changeset
   283
complexities to the size bound proof.\\
613
Chengsong
parents: 611
diff changeset
   284
For example, if we define the size of a basic plain regular expression 
594
Chengsong
parents: 593
diff changeset
   285
in the usual way,
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   286
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   287
	\begin{tabular}{ccc}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   288
		$\llbracket \ONE \rrbracket_p$ & $\dn$ & $1$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   289
		$\llbracket \ZERO \rrbracket_p$ & $\dn$ & $1$ \\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   290
		$\llbracket r_1 \cdot r_2 \rrbracket_p$ & $\dn$ & $\llbracket r_1 \rrbracket_p + \llbracket r_2 \rrbracket_p + 1$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   291
		$\llbracket \mathbf{c} \rrbracket_p $ & $\dn$ & $1$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   292
		$\llbracket r_1 \cdot r_2 \rrbracket_p $ & $\dn$ & $\llbracket r_1 \rrbracket_p \; + \llbracket r_2 \rrbracket_p + 1$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   293
		$\llbracket a^* \rrbracket_p $ & $\dn$ & $\llbracket a \rrbracket_p + 1$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   294
	\end{tabular}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   295
\end{center}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   296
\noindent
594
Chengsong
parents: 593
diff changeset
   297
Then the property
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   298
\begin{center}
613
Chengsong
parents: 611
diff changeset
   299
	$\llbracket a \rrbracket \stackrel{?}{=} \llbracket a_\downarrow \rrbracket_p$
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   300
\end{center}
594
Chengsong
parents: 593
diff changeset
   301
does not hold.
613
Chengsong
parents: 611
diff changeset
   302
With $\textit{rerase}$, however, 
Chengsong
parents: 611
diff changeset
   303
only the bitcodes are thrown away.
Chengsong
parents: 611
diff changeset
   304
Everything about the structure remains intact.
Chengsong
parents: 611
diff changeset
   305
Therefore it does not change the size
Chengsong
parents: 611
diff changeset
   306
of an annotated regular expression:
Chengsong
parents: 611
diff changeset
   307
\begin{lemma}\label{rsizeAsize}
Chengsong
parents: 611
diff changeset
   308
	$\rsize{\rerase a} = \asize a$
Chengsong
parents: 611
diff changeset
   309
\end{lemma}
Chengsong
parents: 611
diff changeset
   310
\begin{proof}
Chengsong
parents: 611
diff changeset
   311
	By routine structural induction on $a$.
Chengsong
parents: 611
diff changeset
   312
\end{proof}
Chengsong
parents: 611
diff changeset
   313
\noindent
594
Chengsong
parents: 593
diff changeset
   314
One might be able to prove an inequality such as
Chengsong
parents: 593
diff changeset
   315
$\llbracket a \rrbracket  \leq \llbracket  a_\downarrow \rrbracket_p $
Chengsong
parents: 593
diff changeset
   316
and then estimate $\llbracket  a_\downarrow \rrbracket_p$,
Chengsong
parents: 593
diff changeset
   317
but we found our approach more straightforward.\\
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   318
613
Chengsong
parents: 611
diff changeset
   319
\subsection{Functions for R-regular Expressions}
Chengsong
parents: 611
diff changeset
   320
We shall define the r-regular expression version
Chengsong
parents: 611
diff changeset
   321
of $\blexer$ and $\blexersimp$ related functions.
Chengsong
parents: 611
diff changeset
   322
We use $r$ as the prefix or subscript to differentiate
Chengsong
parents: 611
diff changeset
   323
with the bitcoded version.
Chengsong
parents: 611
diff changeset
   324
For example,$\backslash_r$, $\rdistincts$, and $\rsimp$
Chengsong
parents: 611
diff changeset
   325
as opposed to $\backslash$, $\distinctBy$, and $\bsimp$.
Chengsong
parents: 611
diff changeset
   326
As promised, they are much simpler than their bitcoded counterparts.
Chengsong
parents: 611
diff changeset
   327
%The operations on r-regular expressions are 
Chengsong
parents: 611
diff changeset
   328
%almost identical to those of the annotated regular expressions,
Chengsong
parents: 611
diff changeset
   329
%except that no bitcodes are used. For example,
Chengsong
parents: 611
diff changeset
   330
The derivative operation becomes simpler:\\
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   331
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   332
	\begin{tabular}{@{}lcl@{}}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   333
		$(\ZERO)\,\backslash_r c$ & $\dn$ & $\ZERO$\\  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   334
		$(\ONE)\,\backslash_r c$ & $\dn$ &
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   335
		$\textit{if}\;c=d\; \;\textit{then}\;
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   336
		\ONE\;\textit{else}\;\ZERO$\\  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   337
		$(\sum \;\textit{rs})\,\backslash_r c$ & $\dn$ &
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   338
		$\sum\;(\textit{map} \; (\_\backslash_r c) \; rs )$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   339
		$(r_1\cdot r_2)\,\backslash_r c$ & $\dn$ &
594
Chengsong
parents: 593
diff changeset
   340
		$\textit{if}\;(\textit{rnullable}\,r_1)$\\
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   341
						 & &$\textit{then}\;\sum\,[(r_1\,\backslash_r c)\cdot\,r_2,$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   342
						 & &$\phantom{\textit{then},\;\sum\,}((r_2\,\backslash_r c))]$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   343
						 & &$\textit{else}\;\,(r_1\,\backslash_r c)\cdot r_2$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   344
		$(r^*)\,\backslash_r c$ & $\dn$ &
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   345
		$( r\,\backslash_r c)\cdot
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   346
		(_{[]}r^*))$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   347
	\end{tabular}    
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   348
\end{center}  
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   349
\noindent
594
Chengsong
parents: 593
diff changeset
   350
Similarly, $\distinctBy$ does not need 
Chengsong
parents: 593
diff changeset
   351
a function checking equivalence because
Chengsong
parents: 593
diff changeset
   352
there are no bit annotations causing superficial differences
Chengsong
parents: 593
diff changeset
   353
between syntactically equal terms.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   354
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   355
	\begin{tabular}{lcl}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   356
		$\rdistinct{[]}{rset} $ & $\dn$ & $[]$\\
594
Chengsong
parents: 593
diff changeset
   357
		$\rdistinct{r :: rs}{rset}$ & $\dn$ & 
Chengsong
parents: 593
diff changeset
   358
		$\textit{if}(r \in \textit{rset}) \; \textit{then} \; \rdistinct{rs}{rset}$\\
Chengsong
parents: 593
diff changeset
   359
					    &        & $\textit{else}\; \;
Chengsong
parents: 593
diff changeset
   360
					    r::\rdistinct{rs}{(rset \cup \{r\})}$
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   361
	\end{tabular}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   362
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   363
%TODO: definition of rsimp (maybe only the alternative clause)
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   364
\noindent
595
Chengsong
parents: 594
diff changeset
   365
We would like to make clear
Chengsong
parents: 594
diff changeset
   366
a difference between our $\rdistincts$ and
Chengsong
parents: 594
diff changeset
   367
the Isabelle $\textit {distinct}$ predicate.
Chengsong
parents: 594
diff changeset
   368
In Isabelle $\textit{distinct}$ is a function that returns a boolean
Chengsong
parents: 594
diff changeset
   369
rather than a list.
Chengsong
parents: 594
diff changeset
   370
It tests if all the elements of a list are unique.\\
Chengsong
parents: 594
diff changeset
   371
With $\textit{rdistinct}$,
Chengsong
parents: 594
diff changeset
   372
and the flatten function for $\rrexp$s:
Chengsong
parents: 594
diff changeset
   373
 \begin{center}
Chengsong
parents: 594
diff changeset
   374
  \begin{tabular}{@{}lcl@{}}
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   375
  $\textit{rflts} \; (\sum \textit{as}) :: \textit{as'}$ & $\dn$ & $as \; @ \; \textit{rflts} \; as' $ \\
595
Chengsong
parents: 594
diff changeset
   376
  $\textit{rflts} \; \ZERO :: as'$ & $\dn$ & $ \textit{rflts} \;  \textit{as'} $ \\
Chengsong
parents: 594
diff changeset
   377
    $\textit{rflts} \; a :: as'$ & $\dn$ & $a :: \textit{rflts} \; \textit{as'}$ \quad(otherwise) 
Chengsong
parents: 594
diff changeset
   378
\end{tabular}    
Chengsong
parents: 594
diff changeset
   379
\end{center}  
Chengsong
parents: 594
diff changeset
   380
\noindent
Chengsong
parents: 594
diff changeset
   381
one can chain together all the other modules
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   382
such as $\rsimpalts$:
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   383
\begin{center}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   384
  \begin{tabular}{@{}lcl@{}}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   385
	  $\rsimpalts \;\; nil$ & $\dn$ & $\RZERO$\\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   386
	  $\rsimpalts \;\; r::nil$ & $\dn$ & $r$\\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   387
	  $\rsimpalts \;\; rs$ & $\dn$ & $\sum rs$\\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   388
\end{tabular}    
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   389
\end{center}  
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   390
\noindent
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   391
and $\rsimpseq$:
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   392
\begin{center}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   393
  \begin{tabular}{@{}lcl@{}}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   394
	  $\rsimpseq \;\; \RZERO \; \_ $ &   $=$ &   $\RZERO$\\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   395
	  $\rsimpseq \;\; \_ \; \RZERO $ &   $=$ &   $\RZERO$\\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   396
	  $\rsimpseq \;\; \RONE \cdot r_2$ & $\dn$ & $r_2$\\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   397
	  $\rsimpseq \;\; r_1 r_2$ & $\dn$ & $r_1 \cdot r_2$\\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   398
\end{tabular}    
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   399
\end{center}  
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   400
and get $\textit{rsimp}$ and $\rderssimp{\_}{\_}$:
595
Chengsong
parents: 594
diff changeset
   401
\begin{center}
Chengsong
parents: 594
diff changeset
   402
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents: 594
diff changeset
   403
   
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   404
	  $\textit{rsimp} \; (r_1\cdot r_2)$ & $\dn$ & $ \textit{rsimp}_{SEQ} \; bs \;(\textit{rsimp} \; r_1) \; (\textit{rsimp}  \; r_2)  $ \\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   405
	  $\textit{rsimp} \; (_{bs}\sum \textit{rs})$ & $\dn$ & $\textit{rsimp}_{ALTS} \; \textit{bs} \; (\textit{rdistinct} \; ( \textit{rflts} ( \textit{map} \; rsimp \; rs)) \; \rerases \; \varnothing) $ \\
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   406
   $\textit{rsimp} \; r$ & $\dn$ & $\textit{r} \qquad \textit{otherwise}$   
595
Chengsong
parents: 594
diff changeset
   407
\end{tabular}    
Chengsong
parents: 594
diff changeset
   408
\end{center} 
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   409
\begin{center}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   410
	\begin{tabular}{@{}lcl@{}}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   411
		$r\backslash_{rsimp} \, c$ & $\dn$ & $\rsimp \; (r\backslash_r \, c)$
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   412
	\end{tabular}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   413
\end{center}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   414
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   415
\begin{center}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   416
	\begin{tabular}{@{}lcl@{}}
601
Chengsong
parents: 596
diff changeset
   417
$r \backslash_{rsimps} \; \; c\!::\!s $ & $\dn$ & $(r \backslash_{rsimp}\, c) \backslash_{rsimps}\, s$ \\
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   418
$r \backslash_{rsimps} [\,] $ & $\dn$ & $r$
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   419
	\end{tabular}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   420
\end{center}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   421
\noindent
601
Chengsong
parents: 596
diff changeset
   422
We do not define an r-regular expression version of $\blexersimp$,
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   423
as our proof does not involve its use 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   424
(and there is no bitcode to decode into a lexical value). 
613
Chengsong
parents: 611
diff changeset
   425
Now we are ready to introduce how r-regular expressions allow
Chengsong
parents: 611
diff changeset
   426
us to prove the size bound on bitcoded regular expressions.
Chengsong
parents: 611
diff changeset
   427
Chengsong
parents: 611
diff changeset
   428
\subsection{Using R-regular Expressions to Bound Bit-coded Regular Expressions}
Chengsong
parents: 611
diff changeset
   429
Everything about the size of annotated regular expressions after the application
Chengsong
parents: 611
diff changeset
   430
of function $\bsimp$ and $\backslash_{simps}$
Chengsong
parents: 611
diff changeset
   431
can be calculated via the size of r-regular expressions after the application
Chengsong
parents: 611
diff changeset
   432
of $\rsimp$ and $\backslash_{rsimps}$:
564
Chengsong
parents: 562
diff changeset
   433
\begin{lemma}\label{sizeRelations}
553
0f00d440f484 more changes
Chengsong
parents: 543
diff changeset
   434
	The following equalities hold:
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   435
	\begin{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   436
		\item
601
Chengsong
parents: 596
diff changeset
   437
			$\asize{\bsimps \; a} = \rsize{\rsimp{ \rerase{a}}}$
554
Chengsong
parents: 553
diff changeset
   438
		\item
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   439
			$\asize{\bderssimp{a}{s}} =  \rsize{\rderssimp{\rerase{a}}{s}}$
554
Chengsong
parents: 553
diff changeset
   440
	\end{itemize}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   441
\end{lemma}
601
Chengsong
parents: 596
diff changeset
   442
\begin{proof}
Chengsong
parents: 596
diff changeset
   443
	The first part is by induction on the inductive cases
Chengsong
parents: 596
diff changeset
   444
	of $\textit{bsimp}$.
Chengsong
parents: 596
diff changeset
   445
	The second part is by induction on the string $s$,
Chengsong
parents: 596
diff changeset
   446
	where the inductive step follows from part one.
Chengsong
parents: 596
diff changeset
   447
\end{proof}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   448
\noindent
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   449
With lemma \ref{sizeRelations},
601
Chengsong
parents: 596
diff changeset
   450
we will be able to focus on 
Chengsong
parents: 596
diff changeset
   451
estimating only
Chengsong
parents: 596
diff changeset
   452
$\rsize{\rderssimp{\rerase{a}}{s}}$
Chengsong
parents: 596
diff changeset
   453
in later parts because
Chengsong
parents: 596
diff changeset
   454
\begin{center}
Chengsong
parents: 596
diff changeset
   455
	$\rsize{\rderssimp{\rerase{a}}{s}} \leq N_r \quad$
Chengsong
parents: 596
diff changeset
   456
	implies
Chengsong
parents: 596
diff changeset
   457
	$\quad \llbracket a \backslash_{bsimps} s \rrbracket \leq N_r$.
Chengsong
parents: 596
diff changeset
   458
\end{center}
613
Chengsong
parents: 611
diff changeset
   459
From now on we 
601
Chengsong
parents: 596
diff changeset
   460
Unless stated otherwise in the rest of this 
Chengsong
parents: 596
diff changeset
   461
chapter all regular expressions without
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   462
bitcodes are seen as r-regular expressions ($\rrexp$s).
601
Chengsong
parents: 596
diff changeset
   463
For the binary alternative r-regular expression $\RALTS{[r_1, r_2]}$,
Chengsong
parents: 596
diff changeset
   464
we use the notation $r_1 + r_2$
Chengsong
parents: 596
diff changeset
   465
for brevity.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   466
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   467
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   468
%-----------------------------------
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   469
%	SUB SECTION ROADMAP RREXP BOUND
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   470
%-----------------------------------
553
0f00d440f484 more changes
Chengsong
parents: 543
diff changeset
   471
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   472
%\subsection{Roadmap to a Bound for $\textit{Rrexp}$}
553
0f00d440f484 more changes
Chengsong
parents: 543
diff changeset
   473
596
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   474
%The way we obtain the bound for $\rrexp$s is by two steps:
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   475
%\begin{itemize}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   476
%	\item
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   477
%		First, we rewrite $r\backslash s$ into something else that is easier
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   478
%		to bound. This step is especially important for the inductive case 
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   479
%		$r_1 \cdot r_2$ and $r^*$, where the derivative can grow and bloat in a wild way,
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   480
%		but after simplification they will always be equal or smaller to a form consisting of an alternative
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   481
%		list of regular expressions $f \; (g\; (\sum rs))$ with some functions applied to it, where each element will be distinct after the function application.
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   482
%	\item
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   483
%		Then, for such a sum  list of regular expressions $f\; (g\; (\sum rs))$, we can control its size
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   484
%		by estimation, since $\distinctBy$ and $\flts$ are well-behaved and working together would only 
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   485
%		reduce the size of a regular expression, not adding to it.
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   486
%\end{itemize}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   487
%
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   488
%\section{Step One: Closed Forms}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   489
%We transform the function application $\rderssimp{r}{s}$
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   490
%into an equivalent 
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   491
%form $f\; (g \; (\sum rs))$.
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   492
%The functions $f$ and $g$ can be anything from $\flts$, $\distinctBy$ and other helper functions from $\bsimp{\_}$.
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   493
%This way we get a different but equivalent way of expressing : $r\backslash s = f \; (g\; (\sum rs))$, we call the
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   494
%right hand side the "closed form" of $r\backslash s$.
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   495
%
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   496
%\begin{quote}\it
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   497
%	Claim: For regular expressions $r_1 \cdot r_2$, we claim that
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   498
%\end{quote}
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   499
%\noindent
b306628a0eab more chap 56
Chengsong
parents: 595
diff changeset
   500
%We explain in detail how we reached those claims.
601
Chengsong
parents: 596
diff changeset
   501
If we attempt to prove 
Chengsong
parents: 596
diff changeset
   502
\begin{center}
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   503
	$\forall r. \; \exists N_r.\;\; s.t. \llbracket r\backslash_{rsimps} s \rrbracket_r \leq N_r$
601
Chengsong
parents: 596
diff changeset
   504
\end{center}
Chengsong
parents: 596
diff changeset
   505
using a naive induction on the structure of $r$,
Chengsong
parents: 596
diff changeset
   506
then we are stuck at the inductive cases such as
Chengsong
parents: 596
diff changeset
   507
$r_1\cdot r_2$.
Chengsong
parents: 596
diff changeset
   508
The inductive hypotheses are:
Chengsong
parents: 596
diff changeset
   509
\begin{center}
Chengsong
parents: 596
diff changeset
   510
	1: $\text{for } r_1, \text{there exists } N_{r_1}.\;\; s.t. 
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   511
	\;\;\forall s.  \llbracket r_1 \backslash_{rsimps} s \rrbracket_r \leq N_{r_1}. $\\
601
Chengsong
parents: 596
diff changeset
   512
	2: $\text{for } r_2, \text{there exists } N_{r_2}.\;\; s.t. 
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   513
	\;\; \forall s. \llbracket r_2 \backslash_{rsimps} s \rrbracket_r \leq N_{r_2}. $
601
Chengsong
parents: 596
diff changeset
   514
\end{center}
Chengsong
parents: 596
diff changeset
   515
The inductive step to prove would be 
Chengsong
parents: 596
diff changeset
   516
\begin{center}
Chengsong
parents: 596
diff changeset
   517
	$\text{there exists } N_{r_1\cdot r_2}. \;\; s.t. \forall s. 
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   518
	\llbracket (r_1 \cdot r_2) \backslash_{rsimps} s \rrbracket_r \leq N_{r_1\cdot r_2}.$
601
Chengsong
parents: 596
diff changeset
   519
\end{center}
Chengsong
parents: 596
diff changeset
   520
The problem is that it is not clear what 
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   521
$(r_1\cdot r_2) \backslash_{rsimps} s$ looks like,
601
Chengsong
parents: 596
diff changeset
   522
and therefore $N_{r_1}$ and $N_{r_2}$ in the
Chengsong
parents: 596
diff changeset
   523
inductive hypotheses cannot be directly used.
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   524
We have already seen that $(r_1 \cdot r_2)\backslash s$ 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   525
and $(r^*)\backslash s$ can grow in a wild way.
613
Chengsong
parents: 611
diff changeset
   526
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   527
The point is that they will be equivalent to a list of
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   528
terms $\sum rs$, where each term in $rs$ will
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   529
be made of $r_1 \backslash s' $, $r_2\backslash s'$,
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   530
and $r \backslash s'$ with $s' \in \textit{SubString} \; s$.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   531
The list $\sum rs$ will then be de-duplicated by $\textit{rdistinct}$
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   532
in the simplification which saves $rs$ from growing indefinitely.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   533
613
Chengsong
parents: 611
diff changeset
   534
Based on this idea, we develop a proof in two steps.
Chengsong
parents: 611
diff changeset
   535
First, we show the equality (where
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   536
$f$ and $g$ are functions that do not increase the size of the input)
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   537
\begin{center}
613
Chengsong
parents: 611
diff changeset
   538
$r\backslash_{rsimps} s = f\; (\textit{rdistinct} \; (g\; \sum rs))$,
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   539
\end{center}
613
Chengsong
parents: 611
diff changeset
   540
where $r = r_1 \cdot r_2$ or $r = r_0^*$ and so on.
Chengsong
parents: 611
diff changeset
   541
For example, for $r_1 \cdot r_2$ we have the equality as
Chengsong
parents: 611
diff changeset
   542
	\begin{center}
Chengsong
parents: 611
diff changeset
   543
		$ \rderssimp{r_1 \cdot r_2}{s} = 
Chengsong
parents: 611
diff changeset
   544
		\rsimp{(\sum (r_1 \backslash s \cdot r_2 ) \; :: \;(\map \; \rderssimp{r2}{\_} \;(\vsuf{s}{r_1})))}$
Chengsong
parents: 611
diff changeset
   545
	\end{center}
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   546
We call the right-hand-side the 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   547
\emph{Closed Form} of $(r_1 \cdot r_2)\backslash_{rsimps} s$.
613
Chengsong
parents: 611
diff changeset
   548
Second, we will bound the closed form of r-regular expressions
Chengsong
parents: 611
diff changeset
   549
using some estimation techniques
Chengsong
parents: 611
diff changeset
   550
and then piece it together
Chengsong
parents: 611
diff changeset
   551
with lemma \ref{sizeRelations} to show the bitcoded regular expressions
Chengsong
parents: 611
diff changeset
   552
in our $\blexersimp$ are finitely bounded.
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   553
613
Chengsong
parents: 611
diff changeset
   554
We will flesh out the first step of the proof we 
Chengsong
parents: 611
diff changeset
   555
sketched just now in the next section.
Chengsong
parents: 611
diff changeset
   556
Chengsong
parents: 611
diff changeset
   557
\section{Closed Forms}
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   558
In this section we introduce in detail
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   559
how the closed forms are obtained for regular expressions'
613
Chengsong
parents: 611
diff changeset
   560
derivatives.
Chengsong
parents: 611
diff changeset
   561
We start by proving some basic identities
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   562
involving the simplification functions for r-regular expressions.
613
Chengsong
parents: 611
diff changeset
   563
After that we introduce the rewrite relations
Chengsong
parents: 611
diff changeset
   564
$\rightsquigarrow_h$, $\rightsquigarrow^*_{scf}$
Chengsong
parents: 611
diff changeset
   565
$\rightsquigarrow_f$ and $\rightsquigarrow_g$.
Chengsong
parents: 611
diff changeset
   566
These relations involves similar techniques in chapter \ref{Bitcoded2}.
Chengsong
parents: 611
diff changeset
   567
Finally, we use these identities to establish the
Chengsong
parents: 611
diff changeset
   568
closed forms of the alternative regular expression,
Chengsong
parents: 611
diff changeset
   569
the sequence regular expression, and the star regular expression.
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   570
%$r_1\cdot r_2$, $r^*$ and $\sum rs$.
601
Chengsong
parents: 596
diff changeset
   571
Chengsong
parents: 596
diff changeset
   572
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   573
613
Chengsong
parents: 611
diff changeset
   574
\subsection{Some Basic Identities}
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   575
613
Chengsong
parents: 611
diff changeset
   576
We now introduce lemmas 
611
Chengsong
parents: 610
diff changeset
   577
that are repeatedly used in later proofs.
Chengsong
parents: 610
diff changeset
   578
Note that for the $\textit{rdistinct}$ function there
Chengsong
parents: 610
diff changeset
   579
will be a lot of conversion from lists to sets.
613
Chengsong
parents: 611
diff changeset
   580
We use $set$ to refere to the 
611
Chengsong
parents: 610
diff changeset
   581
function that converts a list $rs$ to the set
Chengsong
parents: 610
diff changeset
   582
containing all the elements in $rs$.
Chengsong
parents: 610
diff changeset
   583
\subsubsection{$\textit{rdistinct}$'s Does the Job of De-duplication}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   584
The $\textit{rdistinct}$ function, as its name suggests, will
613
Chengsong
parents: 611
diff changeset
   585
de-duplicate an r-regular expression list.
Chengsong
parents: 611
diff changeset
   586
It will also remove any elements that 
Chengsong
parents: 611
diff changeset
   587
is already in the accumulator set.
555
Chengsong
parents: 554
diff changeset
   588
\begin{lemma}\label{rdistinctDoesTheJob}
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   589
	%The function $\textit{rdistinct}$ satisfies the following
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   590
	%properties:
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   591
	Assume we have the predicate $\textit{isDistinct}$\footnote{We omit its
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   592
	recursive definition here, its Isabelle counterpart would be $\textit{distinct}$.} 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   593
	readily defined
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   594
	for testing
613
Chengsong
parents: 611
diff changeset
   595
	whether a list's elements are unique. Then the following
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   596
	properties about $\textit{rdistinct}$ hold:
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   597
	\begin{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   598
		\item
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   599
			If $a \in acc$ then $a \notin (\rdistinct{rs}{acc})$.
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   600
		\item
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   601
			%If list $rs'$ is the result of $\rdistinct{rs}{acc}$,
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   602
			$\textit{isDistinct} \;\;\; (\rdistinct{rs}{acc})$.
555
Chengsong
parents: 554
diff changeset
   603
		\item
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   604
			$\textit{set} \; (\rdistinct{rs}{acc}) 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   605
			= (textit{set} \; rs) - acc$
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   606
	\end{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   607
\end{lemma}
555
Chengsong
parents: 554
diff changeset
   608
\noindent
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   609
\begin{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   610
	The first part is by an induction on $rs$.
555
Chengsong
parents: 554
diff changeset
   611
	The second and third part can be proven by using the 
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   612
	inductive cases of $\textit{rdistinct}$.
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   613
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   614
\end{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   615
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   616
\noindent
613
Chengsong
parents: 611
diff changeset
   617
%$\textit{rdistinct}$ will out all regular expression terms
Chengsong
parents: 611
diff changeset
   618
%that are in the accumulator, therefore 
Chengsong
parents: 611
diff changeset
   619
Concatenating a list $rs_a$ at the front of another
Chengsong
parents: 611
diff changeset
   620
list $rs$ whose elements are all from the accumulator, and then calling $\textit{rdistinct}$
Chengsong
parents: 611
diff changeset
   621
on the merged list, the output will be as if we had called $\textit{rdistinct}$
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   622
without the prepending of $rs$:
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   623
\begin{lemma}\label{rdistinctConcat}
554
Chengsong
parents: 553
diff changeset
   624
	The elements appearing in the accumulator will always be removed.
Chengsong
parents: 553
diff changeset
   625
	More precisely,
Chengsong
parents: 553
diff changeset
   626
	\begin{itemize}
Chengsong
parents: 553
diff changeset
   627
		\item
Chengsong
parents: 553
diff changeset
   628
			If $rs \subseteq rset$, then 
Chengsong
parents: 553
diff changeset
   629
			$\rdistinct{rs@rsa }{acc} = \rdistinct{rsa }{acc}$.
Chengsong
parents: 553
diff changeset
   630
		\item
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   631
			More generally, if $a \in rset$ and $\rdistinct{rs}{\{a\}} = []$,
554
Chengsong
parents: 553
diff changeset
   632
			then $\rdistinct{(rs @ rs')}{rset} = \rdistinct{rs'}{rset}$
Chengsong
parents: 553
diff changeset
   633
	\end{itemize}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   634
\end{lemma}
554
Chengsong
parents: 553
diff changeset
   635
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   636
\begin{proof}
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
   637
	By induction on $rs$ and using \ref{rdistinctDoesTheJob}.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   638
\end{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   639
\noindent
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   640
On the other hand, if an element $r$ does not appear in the input list waiting to be deduplicated,
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   641
then expanding the accumulator to include that element will not cause the output list to change:
611
Chengsong
parents: 610
diff changeset
   642
\begin{lemma}\label{rdistinctOnDistinct}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   643
	The accumulator can be augmented to include elements not appearing in the input list,
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   644
	and the output will not change.	
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   645
	\begin{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   646
		\item
611
Chengsong
parents: 610
diff changeset
   647
			If $r \notin rs$, then $\rdistinct{rs}{acc} = \rdistinct{rs}{(\{r\} \cup acc)}$.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   648
		\item
611
Chengsong
parents: 610
diff changeset
   649
			Particularly, if $\;\;\textit{isDistinct} \; rs$, then we have\\
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   650
			\[ \rdistinct{rs}{\varnothing} = rs \]
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   651
	\end{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   652
\end{lemma}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   653
\begin{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   654
	The first half is by induction on $rs$. The second half is a corollary of the first.
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   655
\end{proof}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   656
\noindent
611
Chengsong
parents: 610
diff changeset
   657
The function $\textit{rdistinct}$ removes duplicates from anywhere in a list.
Chengsong
parents: 610
diff changeset
   658
Despite being seemingly obvious, 
Chengsong
parents: 610
diff changeset
   659
the induction technique is not as straightforward.
554
Chengsong
parents: 553
diff changeset
   660
\begin{lemma}\label{distinctRemovesMiddle}
Chengsong
parents: 553
diff changeset
   661
	The two properties hold if $r \in rs$:
Chengsong
parents: 553
diff changeset
   662
	\begin{itemize}
Chengsong
parents: 553
diff changeset
   663
		\item
555
Chengsong
parents: 554
diff changeset
   664
			$\rdistinct{rs}{rset} = \rdistinct{(rs @ [r])}{rset}$\\
Chengsong
parents: 554
diff changeset
   665
			and\\
554
Chengsong
parents: 553
diff changeset
   666
			$\rdistinct{(ab :: rs @ [ab])}{rset'} = \rdistinct{(ab :: rs)}{rset'}$
Chengsong
parents: 553
diff changeset
   667
		\item
555
Chengsong
parents: 554
diff changeset
   668
			$\rdistinct{ (rs @ rs') }{rset} = \rdistinct{rs @ [r] @ rs'}{rset}$\\
Chengsong
parents: 554
diff changeset
   669
			and\\
554
Chengsong
parents: 553
diff changeset
   670
			$\rdistinct{(ab :: rs @ [ab] @ rs'')}{rset'} = 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   671
			\rdistinct{(ab :: rs @ rs'')}{rset'}$
554
Chengsong
parents: 553
diff changeset
   672
	\end{itemize}
Chengsong
parents: 553
diff changeset
   673
\end{lemma}
Chengsong
parents: 553
diff changeset
   674
\noindent
Chengsong
parents: 553
diff changeset
   675
\begin{proof}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   676
	By induction on $rs$. All other variables are allowed to be arbitrary.
611
Chengsong
parents: 610
diff changeset
   677
	The second part of the lemma requires the first.
Chengsong
parents: 610
diff changeset
   678
	Note that for each part, the two sub-propositions need to be proven concurrently,
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   679
	so that the induction goes through.
554
Chengsong
parents: 553
diff changeset
   680
\end{proof}
555
Chengsong
parents: 554
diff changeset
   681
\noindent
611
Chengsong
parents: 610
diff changeset
   682
This allows us to prove a few more equivalence relations involving 
Chengsong
parents: 610
diff changeset
   683
$\textit{rdistinct}$ (it will be useful later):
555
Chengsong
parents: 554
diff changeset
   684
\begin{lemma}\label{rdistinctConcatGeneral}
611
Chengsong
parents: 610
diff changeset
   685
	\mbox{}
555
Chengsong
parents: 554
diff changeset
   686
	\begin{itemize}
Chengsong
parents: 554
diff changeset
   687
		\item
Chengsong
parents: 554
diff changeset
   688
			$\rdistinct{(rs @ rs')}{\varnothing} = \rdistinct{((\rdistinct{rs}{\varnothing})@ rs')}{\varnothing}$
Chengsong
parents: 554
diff changeset
   689
		\item
Chengsong
parents: 554
diff changeset
   690
			$\rdistinct{(rs @ rs')}{\varnothing} = \rdistinct{(\rdistinct{rs}{\varnothing} @ rs')}{\varnothing}$
Chengsong
parents: 554
diff changeset
   691
		\item
Chengsong
parents: 554
diff changeset
   692
			If $rset' \subseteq rset$, then $\rdistinct{rs}{rset} = 
Chengsong
parents: 554
diff changeset
   693
			\rdistinct{(\rdistinct{rs}{rset'})}{rset}$. As a corollary
Chengsong
parents: 554
diff changeset
   694
			of this,
Chengsong
parents: 554
diff changeset
   695
		\item
Chengsong
parents: 554
diff changeset
   696
			$\rdistinct{(rs @ rs')}{rset} = \rdistinct{
Chengsong
parents: 554
diff changeset
   697
			(\rdistinct{rs}{\varnothing}) @ rs')}{rset}$. This
Chengsong
parents: 554
diff changeset
   698
			gives another corollary use later:
Chengsong
parents: 554
diff changeset
   699
		\item
Chengsong
parents: 554
diff changeset
   700
			If $a \in rset$, then $\rdistinct{(rs @ rs')}{rset} = \rdistinct{
Chengsong
parents: 554
diff changeset
   701
			(\rdistinct{(a :: rs)}{\varnothing} @ rs')}{rset} $,
Chengsong
parents: 554
diff changeset
   702
Chengsong
parents: 554
diff changeset
   703
	\end{itemize}
Chengsong
parents: 554
diff changeset
   704
\end{lemma}
Chengsong
parents: 554
diff changeset
   705
\begin{proof}
Chengsong
parents: 554
diff changeset
   706
	By \ref{rdistinctDoesTheJob} and \ref{distinctRemovesMiddle}.
Chengsong
parents: 554
diff changeset
   707
\end{proof}
611
Chengsong
parents: 610
diff changeset
   708
\noindent
613
Chengsong
parents: 611
diff changeset
   709
The next lemma is a more general form of \ref{rdistinctConcat},
Chengsong
parents: 611
diff changeset
   710
it says that
611
Chengsong
parents: 610
diff changeset
   711
$\textit{rdistinct}$ is composable w.r.t list concatenation:
Chengsong
parents: 610
diff changeset
   712
\begin{lemma}\label{distinctRdistinctAppend}
Chengsong
parents: 610
diff changeset
   713
			If $\;\; \textit{isDistinct} \; rs_1$, 
Chengsong
parents: 610
diff changeset
   714
			and $(set \; rs_1) \cap acc = \varnothing$,
Chengsong
parents: 610
diff changeset
   715
			then applying $\textit{rdistinct}$ on $rs_1 @ rs_a$ does not 
Chengsong
parents: 610
diff changeset
   716
			have an effect on $rs_1$:
Chengsong
parents: 610
diff changeset
   717
			\[\textit{rdistinct}\;  (rs_1 @ rsa)\;\, acc
Chengsong
parents: 610
diff changeset
   718
			= rs_1@(\textit{rdistinct} rsa \; (acc \cup rs_1))\]
Chengsong
parents: 610
diff changeset
   719
\end{lemma}
Chengsong
parents: 610
diff changeset
   720
\begin{proof}
Chengsong
parents: 610
diff changeset
   721
	By an induction on 
Chengsong
parents: 610
diff changeset
   722
	$rs_1$, where $rsa$ and $acc$ are allowed to be arbitrary.
Chengsong
parents: 610
diff changeset
   723
\end{proof}
Chengsong
parents: 610
diff changeset
   724
\noindent
Chengsong
parents: 610
diff changeset
   725
$\textit{rdistinct}$ needs to be applied only once, and 
Chengsong
parents: 610
diff changeset
   726
applying it multiple times does not cause any difference:
Chengsong
parents: 610
diff changeset
   727
\begin{corollary}\label{distinctOnceEnough}
Chengsong
parents: 610
diff changeset
   728
	$\textit{rdistinct} \; (rs @ rsa) {} = \textit{rdistinct} \; (rdistinct \; 
Chengsong
parents: 610
diff changeset
   729
	rs \{ \} @ (\textit{rdistinct} \; rs_a \; (set \; rs)))$
Chengsong
parents: 610
diff changeset
   730
\end{corollary}
Chengsong
parents: 610
diff changeset
   731
\begin{proof}
Chengsong
parents: 610
diff changeset
   732
	By lemma \ref{distinctRdistinctAppend}.
Chengsong
parents: 610
diff changeset
   733
\end{proof}
555
Chengsong
parents: 554
diff changeset
   734
611
Chengsong
parents: 610
diff changeset
   735
\subsubsection{The Properties of $\textit{Rflts}$} 
Chengsong
parents: 610
diff changeset
   736
We give in this subsection some properties
Chengsong
parents: 610
diff changeset
   737
involving $\backslash_r$, $\backslash_{rsimp}$, $\textit{rflts}$ and 
Chengsong
parents: 610
diff changeset
   738
$\textit{rsimp}_{ALTS} $, together with any non-trivial lemmas that lead to them.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   739
These will be helpful in later closed form proofs, when
611
Chengsong
parents: 610
diff changeset
   740
we want to transform derivative terms which have
Chengsong
parents: 610
diff changeset
   741
%the ways in which multiple functions involving
Chengsong
parents: 610
diff changeset
   742
%those are composed together
Chengsong
parents: 610
diff changeset
   743
interleaving derivatives and  simplifications applied to them.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   744
611
Chengsong
parents: 610
diff changeset
   745
\noindent
Chengsong
parents: 610
diff changeset
   746
%When the function $\textit{Rflts}$ 
Chengsong
parents: 610
diff changeset
   747
%is applied to the concatenation of two lists, the output can be calculated by first applying the
Chengsong
parents: 610
diff changeset
   748
%functions on two lists separately, and then concatenating them together.
Chengsong
parents: 610
diff changeset
   749
$\textit{Rflts}$ is composable in terms of concatenation:
554
Chengsong
parents: 553
diff changeset
   750
\begin{lemma}\label{rfltsProps}
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   751
	The function $\rflts$ has the below properties:\\
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   752
	\begin{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   753
		\item
554
Chengsong
parents: 553
diff changeset
   754
			$\rflts \; (rs_1 @ rs_2) = \rflts \; rs_1 @ \rflts \; rs_2$
Chengsong
parents: 553
diff changeset
   755
		\item
Chengsong
parents: 553
diff changeset
   756
			If $r \neq \RZERO$ and $\nexists rs_1. r = \RALTS{rs}_1$, then $\rflts \; (r::rs) = r :: \rflts \; rs$
Chengsong
parents: 553
diff changeset
   757
		\item
Chengsong
parents: 553
diff changeset
   758
			$\rflts \; (rs @ [\RZERO]) = \rflts \; rs$
Chengsong
parents: 553
diff changeset
   759
		\item
Chengsong
parents: 553
diff changeset
   760
			$\rflts \; (rs' @ [\RALTS{rs}]) = \rflts \; rs'@rs$
Chengsong
parents: 553
diff changeset
   761
		\item
Chengsong
parents: 553
diff changeset
   762
			$\rflts \; (rs @ [\RONE]) = \rflts \; rs @ [\RONE]$
Chengsong
parents: 553
diff changeset
   763
		\item
Chengsong
parents: 553
diff changeset
   764
			If $r \neq \RZERO$ and $\nexists rs'. r = \RALTS{rs'}$ then $\rflts \; (rs @ [r])
Chengsong
parents: 553
diff changeset
   765
			= (\rflts \; rs) @ [r]$
555
Chengsong
parents: 554
diff changeset
   766
		\item
Chengsong
parents: 554
diff changeset
   767
			If $r = \RALTS{rs}$ and $r \in rs'$ then for all $r_1 \in rs. 
Chengsong
parents: 554
diff changeset
   768
			r_1 \in \rflts \; rs'$.
Chengsong
parents: 554
diff changeset
   769
		\item
Chengsong
parents: 554
diff changeset
   770
			$\rflts \; (rs_a @ \RZERO :: rs_b) = \rflts \; (rs_a @ rs_b)$
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   771
	\end{itemize}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   772
\end{lemma}
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   773
\noindent
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   774
\begin{proof}
555
Chengsong
parents: 554
diff changeset
   775
	By induction on $rs_1$ in the first sub-lemma, and induction on $r$ in the second part,
Chengsong
parents: 554
diff changeset
   776
	and induction on $rs$, $rs'$, $rs$, $rs'$, $rs_a$ in the third, fourth, fifth, sixth and 
Chengsong
parents: 554
diff changeset
   777
	last sub-lemma.
543
b2bea5968b89 thesis_thys
Chengsong
parents: 532
diff changeset
   778
\end{proof}
611
Chengsong
parents: 610
diff changeset
   779
\noindent
Chengsong
parents: 610
diff changeset
   780
Now we introduce the property that the operations 
Chengsong
parents: 610
diff changeset
   781
derivative and $\rsimpalts$
Chengsong
parents: 610
diff changeset
   782
commute, this will be used later in deriving the closed form for
Chengsong
parents: 610
diff changeset
   783
the alternative regular expression:
Chengsong
parents: 610
diff changeset
   784
\begin{lemma}\label{rderRsimpAltsCommute}
Chengsong
parents: 610
diff changeset
   785
	$\rder{x}{(\rsimpalts \; rs)} = \rsimpalts \; (\map \; (\rder{x}{\_}) \; rs)$
Chengsong
parents: 610
diff changeset
   786
\end{lemma}
Chengsong
parents: 610
diff changeset
   787
\noindent
613
Chengsong
parents: 611
diff changeset
   788
We need more equalities like the above to enable a closed form,
Chengsong
parents: 611
diff changeset
   789
for which we need to introduce a few rewrite relations
Chengsong
parents: 611
diff changeset
   790
to help
Chengsong
parents: 611
diff changeset
   791
us obtain them.
554
Chengsong
parents: 553
diff changeset
   792
610
d028c662a3df data files
Chengsong
parents: 609
diff changeset
   793
\subsection{The rewrite relation $\hrewrite$ , $\scfrewrites$ , $\frewrite$ and $\grewrite$}
613
Chengsong
parents: 611
diff changeset
   794
Inspired by the success we had in the correctness proof 
Chengsong
parents: 611
diff changeset
   795
in \ref{Bitcoded2},
Chengsong
parents: 611
diff changeset
   796
we follow suit here, defining atomic simplification
Chengsong
parents: 611
diff changeset
   797
steps as ``small-step'' rewriting steps. This allows capturing 
555
Chengsong
parents: 554
diff changeset
   798
similarities between terms that would be otherwise
Chengsong
parents: 554
diff changeset
   799
hard to express.
Chengsong
parents: 554
diff changeset
   800
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   801
We use $\hrewrite$ for one-step atomic rewrite of 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   802
regular expression simplification, 
555
Chengsong
parents: 554
diff changeset
   803
$\frewrite$ for rewrite of list of regular expressions that 
Chengsong
parents: 554
diff changeset
   804
include all operations carried out in $\rflts$, and $\grewrite$ for
613
Chengsong
parents: 611
diff changeset
   805
rewriting a list of regular expressions possible in both $\rflts$ and $\textit{rdistinct}$.
555
Chengsong
parents: 554
diff changeset
   806
Their reflexive transitive closures are used to denote zero or many steps,
Chengsong
parents: 554
diff changeset
   807
as was the case in the previous chapter.
613
Chengsong
parents: 611
diff changeset
   808
As we have already
Chengsong
parents: 611
diff changeset
   809
done something similar, the presentation about
Chengsong
parents: 611
diff changeset
   810
these rewriting rules will be more concise than that in \ref{Bitcoded2}.
554
Chengsong
parents: 553
diff changeset
   811
To differentiate between the rewriting steps for annotated regular expressions
Chengsong
parents: 553
diff changeset
   812
and $\rrexp$s, we add characters $h$ and $g$ below the squig arrow symbol
Chengsong
parents: 553
diff changeset
   813
to mean atomic simplification transitions 
Chengsong
parents: 553
diff changeset
   814
of $\rrexp$s and $\rrexp$ lists, respectively.
Chengsong
parents: 553
diff changeset
   815
555
Chengsong
parents: 554
diff changeset
   816
Chengsong
parents: 554
diff changeset
   817
Chengsong
parents: 554
diff changeset
   818
613
Chengsong
parents: 611
diff changeset
   819
\begin{figure}[H]
554
Chengsong
parents: 553
diff changeset
   820
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   821
	\begin{mathpar}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   822
		\inferrule[RSEQ0L]{}{\RZERO \cdot r_2 \hrewrite \RZERO\\}
555
Chengsong
parents: 554
diff changeset
   823
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   824
		\inferrule[RSEQ0R]{}{r_1 \cdot \RZERO \hrewrite \RZERO\\}
555
Chengsong
parents: 554
diff changeset
   825
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   826
		\inferrule[RSEQ1]{}{(\RONE \cdot r) \hrewrite  r\\}\\	
555
Chengsong
parents: 554
diff changeset
   827
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   828
		\inferrule[RSEQL]{ r_1 \hrewrite r_2}{r_1 \cdot r_3 \hrewrite r_2 \cdot r_3\\}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   829
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   830
		\inferrule[RSEQR]{ r_3 \hrewrite r_4}{r_1 \cdot r_3 \hrewrite r_1 \cdot r_4\\}\\
555
Chengsong
parents: 554
diff changeset
   831
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   832
		\inferrule[RALTSChild]{r \hrewrite r'}{\sum (rs_1 @ [r] @ rs_2) \hrewrite \sum (rs_1 @ [r'] @ rs_2)\\}
555
Chengsong
parents: 554
diff changeset
   833
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   834
		\inferrule[RALTS0]{}{\sum (rs_a @ [\RZERO] @ rs_b) \hrewrite \sum (rs_a @ rs_b)}
555
Chengsong
parents: 554
diff changeset
   835
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   836
		\inferrule[RALTSNested]{}{\sum (rs_a @ [\sum rs_1] @ rs_b) \hrewrite \sum (rs_a @ rs_1 @ rs_b)}
555
Chengsong
parents: 554
diff changeset
   837
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   838
		\inferrule[RALTSNil]{}{ \sum [] \hrewrite \RZERO\\}
555
Chengsong
parents: 554
diff changeset
   839
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   840
		\inferrule[RALTSSingle]{}{ \sum [r] \hrewrite  r\\}	
555
Chengsong
parents: 554
diff changeset
   841
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   842
		\inferrule[RALTSDelete]{\\ r_1 = r_2}{\sum rs_a @ [r_1] @ rs_b @ [r_2] @ rsc \hrewrite \sum rs_a @ [r_1] @ rs_b @ rs_c}
555
Chengsong
parents: 554
diff changeset
   843
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   844
	\end{mathpar}
555
Chengsong
parents: 554
diff changeset
   845
\end{center}
613
Chengsong
parents: 611
diff changeset
   846
\caption{List of one-step rewrite rules for r-regular expressions ($\hrewrite$)}\label{hRewrite}
Chengsong
parents: 611
diff changeset
   847
\end{figure}
554
Chengsong
parents: 553
diff changeset
   848
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   849
613
Chengsong
parents: 611
diff changeset
   850
Like $\rightsquigarrow_s$, it is
Chengsong
parents: 611
diff changeset
   851
convenient to define rewrite rules for a list of regular expressions,
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   852
where each element can rewrite in many steps to the other (scf stands for
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   853
li\emph{s}t \emph{c}losed \emph{f}orm). This relation is similar to the 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   854
$\stackrel{s*}{\rightsquigarrow}$ for annotated regular expressions.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   855
613
Chengsong
parents: 611
diff changeset
   856
\begin{figure}[H]
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   857
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   858
	\begin{mathpar}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   859
		\inferrule{}{[] \scfrewrites [] }
613
Chengsong
parents: 611
diff changeset
   860
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   861
		\inferrule{r \hrewrites r' \\ rs \scfrewrites rs'}{r :: rs \scfrewrites r' :: rs'}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   862
	\end{mathpar}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   863
\end{center}
613
Chengsong
parents: 611
diff changeset
   864
\caption{List of one-step rewrite rules for a list of r-regular expressions}\label{scfRewrite}
Chengsong
parents: 611
diff changeset
   865
\end{figure}
555
Chengsong
parents: 554
diff changeset
   866
%frewrite
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   867
List of one-step rewrite rules for flattening 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   868
a list of  regular expressions($\frewrite$):
613
Chengsong
parents: 611
diff changeset
   869
\begin{figure}[H]
555
Chengsong
parents: 554
diff changeset
   870
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   871
	\begin{mathpar}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   872
		\inferrule{}{\RZERO :: rs \frewrite rs \\}
555
Chengsong
parents: 554
diff changeset
   873
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   874
		\inferrule{}{(\sum rs) :: rs_a \frewrite rs @ rs_a \\}
555
Chengsong
parents: 554
diff changeset
   875
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   876
		\inferrule{rs_1 \frewrite rs_2}{r :: rs_1 \frewrite r :: rs_2}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   877
	\end{mathpar}
555
Chengsong
parents: 554
diff changeset
   878
\end{center}
613
Chengsong
parents: 611
diff changeset
   879
\caption{List of one-step rewrite rules characterising the $\rflts$ operation on a list}\label{fRewrites}
Chengsong
parents: 611
diff changeset
   880
\end{figure}
555
Chengsong
parents: 554
diff changeset
   881
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   882
Lists of one-step rewrite rules for flattening and de-duplicating
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   883
a list of regular expressions ($\grewrite$):
613
Chengsong
parents: 611
diff changeset
   884
\begin{figure}[H]
555
Chengsong
parents: 554
diff changeset
   885
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   886
	\begin{mathpar}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   887
		\inferrule{}{\RZERO :: rs \grewrite rs \\}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
   888
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   889
		\inferrule{}{(\sum rs) :: rs_a \grewrite rs @ rs_a \\}
555
Chengsong
parents: 554
diff changeset
   890
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   891
		\inferrule{rs_1 \grewrite rs_2}{r :: rs_1 \grewrite r :: rs_2}
555
Chengsong
parents: 554
diff changeset
   892
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   893
		\inferrule[dB]{}{rs_a @ [a] @ rs_b @[a] @ rs_c \grewrite rs_a @ [a] @ rsb @ rsc}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   894
	\end{mathpar}
555
Chengsong
parents: 554
diff changeset
   895
\end{center}
613
Chengsong
parents: 611
diff changeset
   896
\caption{List of one-step rewrite rules characterising the $\rflts$ and $\textit{rdistinct}$
Chengsong
parents: 611
diff changeset
   897
operations}\label{gRewrite}
Chengsong
parents: 611
diff changeset
   898
\end{figure}
555
Chengsong
parents: 554
diff changeset
   899
\noindent
611
Chengsong
parents: 610
diff changeset
   900
We defined
613
Chengsong
parents: 611
diff changeset
   901
two separate list rewriting relations $\frewrite$ and $\grewrite$.
611
Chengsong
parents: 610
diff changeset
   902
The rewriting steps that take place during
Chengsong
parents: 610
diff changeset
   903
flattening is characterised by $\frewrite$.
Chengsong
parents: 610
diff changeset
   904
$\grewrite$ characterises both flattening and de-duplicating.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   905
Sometimes $\grewrites$ is slightly too powerful
613
Chengsong
parents: 611
diff changeset
   906
so we would rather use $\frewrites$ to prove
Chengsong
parents: 611
diff changeset
   907
%because we only
Chengsong
parents: 611
diff changeset
   908
equalities related to $\rflts$.
Chengsong
parents: 611
diff changeset
   909
%certain equivalence under the rewriting steps of $\frewrites$.
556
Chengsong
parents: 555
diff changeset
   910
For example, when proving the closed-form for the alternative regular expression,
613
Chengsong
parents: 611
diff changeset
   911
one of the equalities needed is:
Chengsong
parents: 611
diff changeset
   912
\begin{center}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   913
	$\sum (\rDistinct \;\; (\map \; (\_ \backslash x) \; (\rflts \; rs)) \;\; \varnothing) \sequal
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   914
	\sum (\rDistinct \;\;  (\rflts \; (\map \; (\_ \backslash x) \; rs)) \;\; \varnothing)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   915
	$
613
Chengsong
parents: 611
diff changeset
   916
\end{center}
556
Chengsong
parents: 555
diff changeset
   917
\noindent
Chengsong
parents: 555
diff changeset
   918
Proving this is by first showing 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   919
\begin{lemma}\label{earlyLaterDerFrewrites}
556
Chengsong
parents: 555
diff changeset
   920
	$\map \; (\_ \backslash x) \;  (\rflts \; rs) \frewrites
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   921
	\rflts \; (\map \; (\_ \backslash x) \; rs)$
556
Chengsong
parents: 555
diff changeset
   922
\end{lemma}
Chengsong
parents: 555
diff changeset
   923
\noindent
613
Chengsong
parents: 611
diff changeset
   924
and then the equivalence between two terms
Chengsong
parents: 611
diff changeset
   925
that can reduce in many steps to each other.
556
Chengsong
parents: 555
diff changeset
   926
\begin{lemma}\label{frewritesSimpeq}
Chengsong
parents: 555
diff changeset
   927
	If $rs_1 \frewrites rs_2 $, then $\sum (\rDistinct \; rs_1 \; \varnothing) \sequal 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   928
	\sum (\rDistinct \;  rs_2 \;  \varnothing)$.
556
Chengsong
parents: 555
diff changeset
   929
\end{lemma}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   930
\noindent
613
Chengsong
parents: 611
diff changeset
   931
Chengsong
parents: 611
diff changeset
   932
\begin{corollary}
Chengsong
parents: 611
diff changeset
   933
	$\sum (\rDistinct \;\; (\map \; (\_ \backslash x) \; (\rflts \; rs)) \;\; \varnothing) \sequal
Chengsong
parents: 611
diff changeset
   934
	\sum (\rDistinct \;\;  (\rflts \; (\map \; (\_ \backslash x) \; rs)) \;\; \varnothing)
Chengsong
parents: 611
diff changeset
   935
	$
Chengsong
parents: 611
diff changeset
   936
\end{corollary}
Chengsong
parents: 611
diff changeset
   937
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   938
But this trick will not work for $\grewrites$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   939
For example, a rewriting step in proving
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   940
closed forms is:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   941
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   942
	$\rsimp{(\rsimpalts \; (\map \; (\_ \backslash x) \; (\rdistinct{(\rflts \; (\map \; (\rsimp{} \; \circ \; (\lambda r. \rderssimp{r}{xs}))))}{\varnothing})))}$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   943
	$=$ \\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   944
	$\rsimp{(\rsimpalts \; (\rdistinct{(\map \; (\_ \backslash x) \; (\rflts \; (\map \; (\rsimp{} \; \circ \; (\lambda r. \rderssimp{r}{xs})))) ) }{\varnothing}))} $
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   945
	\noindent
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   946
\end{center}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   947
For this one would hope to have a rewriting relation between the two lists involved,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   948
similar to \ref{earlyLaterDerFrewrites}. However, it turns out that 
556
Chengsong
parents: 555
diff changeset
   949
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   950
	$\map \; (\_ \backslash x) \; (\rDistinct \; rs \; rset) \grewrites \rDistinct \; (\map \;
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
   951
	(\_ \backslash x) \; rs) \; ( rset \backslash x)$
556
Chengsong
parents: 555
diff changeset
   952
\end{center}
Chengsong
parents: 555
diff changeset
   953
\noindent
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   954
does $\mathbf{not}$ hold in general.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   955
For this rewriting step we will introduce some slightly more cumbersome
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   956
proof technique in later sections.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   957
The point is that $\frewrite$
613
Chengsong
parents: 611
diff changeset
   958
allows us to prove equivalence in a straightforward way that is 
Chengsong
parents: 611
diff changeset
   959
not possible for $\grewrite$. 
555
Chengsong
parents: 554
diff changeset
   960
556
Chengsong
parents: 555
diff changeset
   961
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   962
\subsubsection{Terms That Can Be Rewritten Using $\hrewrites$, $\grewrites$, and $\frewrites$}
613
Chengsong
parents: 611
diff changeset
   963
In this part, we present lemmas stating
Chengsong
parents: 611
diff changeset
   964
pairs of r-regular expressions or r-regular expression lists
Chengsong
parents: 611
diff changeset
   965
where one could rewrite from one in many steps to the other.
Chengsong
parents: 611
diff changeset
   966
Most of the proofs to these lemmas are straightforward, using
Chengsong
parents: 611
diff changeset
   967
an induction on the inductive cases of the corresponding rewriting relations.
Chengsong
parents: 611
diff changeset
   968
These proofs will therefore be omitted when this is the case.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   969
We present in the below lemma a few pairs of terms that are rewritable via 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   970
$\grewrites$:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   971
\begin{lemma}\label{gstarRdistinctGeneral}
613
Chengsong
parents: 611
diff changeset
   972
	\mbox{}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   973
	\begin{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   974
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   975
			$rs_1 @ rs \grewrites rs_1 @ (\rDistinct \; rs \; rs_1)$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   976
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   977
			$rs \grewrites \rDistinct \; rs \; \varnothing$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   978
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   979
			$rs_a @ (\rDistinct \; rs \; rs_a) \grewrites rs_a @ (\rDistinct \; 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   980
			rs \; (\{\RZERO\} \cup rs_a))$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   981
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   982
			$rs \;\; @ \;\; \rDistinct \; rs_a \; rset \grewrites rs @  \rDistinct \; rs_a \;
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   983
			(rest \cup rs)$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   984
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   985
	\end{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   986
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   987
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   988
If a pair of terms $rs_1, rs_2$ are rewritable via $\grewrites$ to each other,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   989
then they are equivalent under $\rsimp{}$:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   990
\begin{lemma}\label{grewritesSimpalts}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   991
	If $rs_1 \grewrites rs_2$, then
613
Chengsong
parents: 611
diff changeset
   992
	we have the following equivalence:
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   993
	\begin{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   994
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   995
			$\sum rs_1 \sequal \sum rs_2$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   996
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   997
			$\rsimpalts \; rs_1 \sequal \rsimpalts \; rs_2$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   998
	\end{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
   999
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1000
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1001
Here are a few connecting lemmas showing that
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1002
if a list of regular expressions can be rewritten using $\grewrites$ or $\frewrites $ or
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1003
$\scfrewrites$,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1004
then an alternative constructor taking the list can also be rewritten using $\hrewrites$:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1005
\begin{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1006
	\begin{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1007
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1008
			If $rs \grewrites rs'$ then $\sum rs \hrewrites \sum rs'$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1009
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1010
			If $rs \grewrites rs'$ then $\sum rs \hrewrites \rsimpalts \; rs'$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1011
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1012
			If $rs_1 \scfrewrites rs_2$ then $\sum (rs @ rs_1) \hrewrites \sum (rs @ rs_2)$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1013
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1014
			If $rs_1 \scfrewrites rs_2$ then $\sum rs_1 \hrewrites \sum rs_2$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1015
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1016
	\end{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1017
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1018
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1019
Here comes the meat of the proof, 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1020
which says that once two lists are rewritable to each other,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1021
then they are equivalent under $\rsimp{}$:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1022
\begin{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1023
	If $r_1 \hrewrites r_2$ then $r_1 \sequal r_2$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1024
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1025
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1026
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1027
And similar to \ref{Bitcoded2} one can preserve rewritability after taking derivative
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1028
of two regular expressions on both sides:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1029
\begin{lemma}\label{interleave}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1030
	If $r \hrewrites r' $ then $\rder{c}{r} \hrewrites \rder{c}{r'}$
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1031
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1032
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1033
This allows proving more $\mathbf{rsimp}$-equivalent terms, involving $\backslash_r$ now.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1034
\begin{lemma}\label{insideSimpRemoval}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1035
	$\rsimp{\rder{c}{\rsimp{r}}} = \rsimp{\rder{c}{r}}  $
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1036
\end{lemma}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1037
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1038
\begin{proof}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1039
	By \ref{interleave} and \ref{rsimpIdem}.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1040
\end{proof}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1041
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1042
And this unlocks more equivalent terms:
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1043
\begin{lemma}\label{Simpders}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1044
	As corollaries of \ref{insideSimpRemoval}, we have
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1045
	\begin{itemize}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1046
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1047
			If $s \neq []$ then $\rderssimp{r}{s} = \rsimp{(\rders \; r \; s)}$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1048
		\item
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1049
			$\rsimpalts \; (\map \; (\_ \backslash_r x) \;
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1050
			(\rdistinct{rs}{\varnothing})) \sequal
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1051
			\rsimpalts \; (\rDistinct \; 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1052
			(\map \; (\_ \backslash_r x) rs) \;\varnothing  )$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1053
	\end{itemize}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1054
\end{lemma}
611
Chengsong
parents: 610
diff changeset
  1055
\begin{proof}
Chengsong
parents: 610
diff changeset
  1056
	Part 1 is by lemma \ref{insideSimpRemoval},
613
Chengsong
parents: 611
diff changeset
  1057
	part 2 is by lemma \ref{insideSimpRemoval} .%and \ref{distinctDer}.
611
Chengsong
parents: 610
diff changeset
  1058
\end{proof}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1059
\noindent
613
Chengsong
parents: 611
diff changeset
  1060
Chengsong
parents: 611
diff changeset
  1061
\subsection{Closed Forms for $\sum rs$, $r_1\cdot r_2$ and $r^*$}
Chengsong
parents: 611
diff changeset
  1062
\subsubsection{Closed Form for Alternative Regular Expression}
Chengsong
parents: 611
diff changeset
  1063
Lemma \ref{Simpders} leads to the first closed form--
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1064
\begin{lemma}\label{altsClosedForm}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1065
	\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1066
		$\rderssimp{(\sum rs)}{s} \sequal
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1067
		\sum \; (\map \; (\rderssimp{\_}{s}) \; rs)$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1068
	\end{center}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1069
\end{lemma}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1070
556
Chengsong
parents: 555
diff changeset
  1071
\noindent
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1072
\begin{proof}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1073
	By a reverse induction on the string $s$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1074
	One rewriting step, as we mentioned earlier,
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1075
	involves
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1076
	\begin{center}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1077
		$\rsimpalts \; (\map \; (\_ \backslash x) \; 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1078
		(\rdistinct{(\rflts \; (\map \; (\rsimp{} \; \circ \; 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1079
		(\lambda r. \rderssimp{r}{xs}))))}{\varnothing}))
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1080
		\sequal
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1081
		\rsimpalts \; (\rdistinct{(\map \; (\_ \backslash x) \; 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1082
			(\rflts \; (\map \; (\rsimp{} \; \circ \; 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1083
		(\lambda r. \rderssimp{r}{xs})))) ) }{\varnothing}) $.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1084
	\end{center}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1085
	This can be proven by a combination of 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1086
	\ref{grewritesSimpalts}, \ref{gstarRdistinctGeneral}, \ref{rderRsimpAltsCommute}, and
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1087
	\ref{insideSimpRemoval}.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1088
\end{proof}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1089
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1090
This closed form has a variant which can be more convenient in later proofs:
559
Chengsong
parents: 558
diff changeset
  1091
\begin{corollary}{altsClosedForm1}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1092
	If $s \neq []$ then 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1093
	$\rderssimp \; (\sum \; rs) \; s = 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1094
	\rsimp{(\sum \; (\map \; \rderssimp{\_}{s} \; rs))}$.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1095
\end{corollary}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1096
\noindent
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1097
The harder closed forms are the sequence and star ones.
613
Chengsong
parents: 611
diff changeset
  1098
Before we obtain them, some preliminary definitions
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1099
are needed to make proof statements concise.
556
Chengsong
parents: 555
diff changeset
  1100
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1101
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1102
\subsubsection{Closed Form for Sequence Regular Expressions}
558
Chengsong
parents: 557
diff changeset
  1103
First let's look at a series of derivatives steps on a sequence 
Chengsong
parents: 557
diff changeset
  1104
regular expression, assuming that each time the first
Chengsong
parents: 557
diff changeset
  1105
component of the sequence is always nullable):
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1106
\begin{center}
558
Chengsong
parents: 557
diff changeset
  1107
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1108
	$r_1 \cdot r_2 \quad \longrightarrow_{\backslash c}  \quad   r_1  \backslash c \cdot r_2 + r_2 \backslash c \quad \longrightarrow_{\backslash c'} \quad (r_1 \backslash cc' \cdot r_2 + r_2 \backslash c') + r_2 \backslash cc' \longrightarrow_{\backslash c''} \quad$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1109
	$((r_1 \backslash cc'c'' \cdot r_2 + r_2 \backslash c'') + r_2 \backslash c'c'') + r_2 \backslash cc'c''   \longrightarrow_{\backslash c''} \quad
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1110
	\ldots$
558
Chengsong
parents: 557
diff changeset
  1111
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1112
\end{center}
558
Chengsong
parents: 557
diff changeset
  1113
Roughly speaking $r_1 \cdot r_2 \backslash s$ can be expresssed as 
Chengsong
parents: 557
diff changeset
  1114
a giant alternative taking a list of terms 
Chengsong
parents: 557
diff changeset
  1115
$[r_1 \backslash_r s \cdot r_2, r_2 \backslash_r s'', r_2 \backslash_r s_1'', \ldots]$,
Chengsong
parents: 557
diff changeset
  1116
where the head of the list is always the term
Chengsong
parents: 557
diff changeset
  1117
representing a match involving only $r_1$, and the tail of the list consisting of
Chengsong
parents: 557
diff changeset
  1118
terms of the shape $r_2 \backslash_r s''$, $s''$ being a suffix of $s$.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1119
This intuition is also echoed by IndianPaper, where they gave
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1120
a pencil-and-paper derivation of $(r_1 \cdot r_2)\backslash s$:
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1121
\begin{center}
558
Chengsong
parents: 557
diff changeset
  1122
	\begin{tabular}{c}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1123
		$(r_1 \cdot r_2) \backslash_r (c_1 :: c_2 :: \ldots c_n) \myequiv$\\ 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1124
		\rule{0pt}{3ex} $((r_1 \backslash_r c_1) \cdot r_2 + (\delta\; (\rnullable \; r_1) \; r_2 \backslash_r c_1)) \backslash_r (c_2 :: \ldots c_n) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1125
		\myequiv$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1126
		\rule{0pt}{3ex} $((r_1 \backslash_r c_1c_2 \cdot r_2 + (\delta \; (\rnullable \; r_1) \; r_2 \backslash_r c_1c_2))
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1127
		+ (\delta \ (\rnullable \; r_1 \backslash_r c)\; r_2 \backslash_r c_2)) \backslash_r (c_3 \ldots c_n)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1128
		$
558
Chengsong
parents: 557
diff changeset
  1129
	\end{tabular}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1130
\end{center}
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1131
\noindent
558
Chengsong
parents: 557
diff changeset
  1132
The equality in above should be interpretated
Chengsong
parents: 557
diff changeset
  1133
as language equivalence. 
Chengsong
parents: 557
diff changeset
  1134
The $\delta$ function works similarly to that of
Chengsong
parents: 557
diff changeset
  1135
a Kronecker delta function:
Chengsong
parents: 557
diff changeset
  1136
\[ \delta \; b\; r\]
Chengsong
parents: 557
diff changeset
  1137
will produce $r$
Chengsong
parents: 557
diff changeset
  1138
if $b$ evaluates to true, 
Chengsong
parents: 557
diff changeset
  1139
and $\RZERO$ otherwise.
Chengsong
parents: 557
diff changeset
  1140
Note that their formulation  
Chengsong
parents: 557
diff changeset
  1141
\[
Chengsong
parents: 557
diff changeset
  1142
	((r_1 \backslash_r \, c_1c_2 \cdot r_2 + (\delta \; (\rnullable) \; r_1, r_2 \backslash_r c_1c_2)
Chengsong
parents: 557
diff changeset
  1143
	+ (\delta \; (\rnullable \; r_1 \backslash_r c)\; r_2 \backslash_r c_2)
Chengsong
parents: 557
diff changeset
  1144
\]
Chengsong
parents: 557
diff changeset
  1145
does not faithfully
Chengsong
parents: 557
diff changeset
  1146
represent what the intermediate derivatives would actually look like
Chengsong
parents: 557
diff changeset
  1147
when one or more intermediate results $r_1 \backslash s' \cdot r_2$ are not 
Chengsong
parents: 557
diff changeset
  1148
nullable in the head of the sequence.
Chengsong
parents: 557
diff changeset
  1149
For example, when $r_1$ and $r_1 \backslash_r c_1$ are not nullable,
Chengsong
parents: 557
diff changeset
  1150
the regular expression would not look like 
Chengsong
parents: 557
diff changeset
  1151
\[
Chengsong
parents: 557
diff changeset
  1152
	(r_1 \backslash_r c_1c_2 + \RZERO ) + \RZERO,
Chengsong
parents: 557
diff changeset
  1153
\]
Chengsong
parents: 557
diff changeset
  1154
but actually $r_1 \backslash_r c_1c_2$, the redundant $\RZERO$s will not be created in the
Chengsong
parents: 557
diff changeset
  1155
first place.
Chengsong
parents: 557
diff changeset
  1156
In a closed-form one would want to take into account this 
Chengsong
parents: 557
diff changeset
  1157
and generate the list of
Chengsong
parents: 557
diff changeset
  1158
regular expressions $r_2 \backslash_r s''$ with
Chengsong
parents: 557
diff changeset
  1159
string pairs $(s', s'')$ where $s'@s'' = s$ and
Chengsong
parents: 557
diff changeset
  1160
$r_1 \backslash s'$ nullable.
Chengsong
parents: 557
diff changeset
  1161
We denote the list consisting of such 
Chengsong
parents: 557
diff changeset
  1162
strings $s''$ as $\vsuf{s}{r_1}$.
Chengsong
parents: 557
diff changeset
  1163
Chengsong
parents: 557
diff changeset
  1164
The function $\vsuf{\_}{\_}$ is defined recursively on the structure of the string:
Chengsong
parents: 557
diff changeset
  1165
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1166
	\begin{tabular}{lcl}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1167
		$\vsuf{[]}{\_} $ & $=$ &  $[]$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1168
		$\vsuf{c::cs}{r_1}$ & $ =$ & $ \textit{if} (\rnullable{r_1}) \textit{then} \; (\vsuf{cs}{(\rder{c}{r_1})}) @ [c :: cs]$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1169
				    && $\textit{else} \; (\vsuf{cs}{(\rder{c}{r_1}) })  $
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1170
	\end{tabular}
558
Chengsong
parents: 557
diff changeset
  1171
\end{center}
Chengsong
parents: 557
diff changeset
  1172
\noindent
Chengsong
parents: 557
diff changeset
  1173
The list is sorted in the order $r_2\backslash s''$ 
Chengsong
parents: 557
diff changeset
  1174
appears in $(r_1\cdot r_2)\backslash s$.
Chengsong
parents: 557
diff changeset
  1175
In essence, $\vsuf{\_}{\_}$ is doing a 
Chengsong
parents: 557
diff changeset
  1176
"virtual derivative" of $r_1 \cdot r_2$, but instead of producing 
Chengsong
parents: 557
diff changeset
  1177
the entire result $(r_1 \cdot r_2) \backslash s$, 
Chengsong
parents: 557
diff changeset
  1178
it only stores all the strings $s''$ such that $r_2 \backslash s''$
Chengsong
parents: 557
diff changeset
  1179
are occurring terms in $(r_1\cdot r_2)\backslash s$.
Chengsong
parents: 557
diff changeset
  1180
Chengsong
parents: 557
diff changeset
  1181
To make the closed form representation 
Chengsong
parents: 557
diff changeset
  1182
more straightforward,
Chengsong
parents: 557
diff changeset
  1183
the flattetning function $\sflat{\_}$ is used to enable the transformation from 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1184
a left-associative nested sequence of alternatives into 
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1185
a flattened list:
558
Chengsong
parents: 557
diff changeset
  1186
\[
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1187
	\sum [r_1, r_2, r_3, \ldots] \stackrel{\sflat{\_}}{\rightarrow} 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1188
	(\ldots ((r_1 + r_2) + r_3) + \ldots)
558
Chengsong
parents: 557
diff changeset
  1189
\]
Chengsong
parents: 557
diff changeset
  1190
\noindent
Chengsong
parents: 557
diff changeset
  1191
The definitions $\sflat{\_}$, $\sflataux{\_}$ are given below.
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1192
\begin{center}  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1193
	\begin{tabular}{ccc}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1194
		$\sflataux{\AALTS{ }{r :: rs}}$ & $=$ & $\sflataux{r} @ rs$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1195
		$\sflataux{\AALTS{ }{[]}}$ & $ = $ & $ []$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1196
		$\sflataux r$ & $=$ & $ [r]$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1197
	\end{tabular}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1198
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1199
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1200
\begin{center} 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1201
	\begin{tabular}{ccc}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1202
		$\sflat{(\sum r :: rs)}$ & $=$ & $\sum (\sflataux{r} @ rs)$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1203
		$\sflat{\sum []}$ & $ = $ & $ \sum []$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1204
		$\sflat r$ & $=$ & $ r$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1205
	\end{tabular}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1206
\end{center}
558
Chengsong
parents: 557
diff changeset
  1207
\noindent
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  1208
$\sflataux{\_}$ breaks up nested alternative regular expressions 
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1209
of the $(\ldots((r_1 + r_2) + r_3) + \ldots )$(left-associated) shape
558
Chengsong
parents: 557
diff changeset
  1210
into a "balanced" list: $\AALTS{\_}{[r_1,\, r_2 ,\, r_3, \ldots]}$.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1211
It will return the singleton list $[r]$ otherwise.
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1212
$\sflat{\_}$ works the same  as $\sflataux{\_}$, except that it keeps
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1213
the output type a regular expression, not a list.
558
Chengsong
parents: 557
diff changeset
  1214
$\sflataux{\_}$  and $\sflat{\_}$ are only recursive on the  
Chengsong
parents: 557
diff changeset
  1215
first element of the list.
Chengsong
parents: 557
diff changeset
  1216
Chengsong
parents: 557
diff changeset
  1217
With $\sflataux{}$ a preliminary to the closed form can be stated,
Chengsong
parents: 557
diff changeset
  1218
where the derivative of $r_1 \cdot r_2 \backslash s$ can be
Chengsong
parents: 557
diff changeset
  1219
flattened into a list whose head and tail meet the description
Chengsong
parents: 557
diff changeset
  1220
we gave earlier.
Chengsong
parents: 557
diff changeset
  1221
\begin{lemma}\label{seqSfau0}
Chengsong
parents: 557
diff changeset
  1222
	$\sflataux{\rders{(r_1 \cdot r_2) \backslash s }} = (r_1 \backslash_r s) \cdot r_2 
Chengsong
parents: 557
diff changeset
  1223
	:: (\map \; (r_2 \backslash_r \_) \; (\textit{Suffix} \; s \; r1))$ 
Chengsong
parents: 557
diff changeset
  1224
\end{lemma}
Chengsong
parents: 557
diff changeset
  1225
\begin{proof}
Chengsong
parents: 557
diff changeset
  1226
	By an induction on the string $s$, where the inductive cases 
Chengsong
parents: 557
diff changeset
  1227
	are split as $[]$ and $xs @ [x]$.
Chengsong
parents: 557
diff changeset
  1228
	Note the key identify holds:
Chengsong
parents: 557
diff changeset
  1229
	\[
Chengsong
parents: 557
diff changeset
  1230
		\map \; (r_2 \backslash_r \_) \; (\vsuf{[x]}{(r_1 \backslash_r xs)}) \;\; @ \;\;
Chengsong
parents: 557
diff changeset
  1231
		\map \; (\_ \backslash_r x) \; (\map \; (r_2 \backslash \_) \; (\vsuf{xs}{r_1}))
Chengsong
parents: 557
diff changeset
  1232
	\]
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1233
	=
558
Chengsong
parents: 557
diff changeset
  1234
	\[
Chengsong
parents: 557
diff changeset
  1235
		\map \; (r_2 \backslash_r \_) \; (\vsuf{xs @ [x]}{r_1})
Chengsong
parents: 557
diff changeset
  1236
	\]
Chengsong
parents: 557
diff changeset
  1237
	This enables the inductive case to go through.
Chengsong
parents: 557
diff changeset
  1238
\end{proof}
Chengsong
parents: 557
diff changeset
  1239
\noindent 
Chengsong
parents: 557
diff changeset
  1240
Note that this lemma does $\mathbf{not}$ depend on any
Chengsong
parents: 557
diff changeset
  1241
specific definitions we used,
Chengsong
parents: 557
diff changeset
  1242
allowing people investigating derivatives to get an alternative
Chengsong
parents: 557
diff changeset
  1243
view of what $r_1 \cdot r_2$ is.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1244
558
Chengsong
parents: 557
diff changeset
  1245
Now we are able to use this for the intuition that 
Chengsong
parents: 557
diff changeset
  1246
the different ways in which regular expressions are 
Chengsong
parents: 557
diff changeset
  1247
nested do not matter under $\rsimp{}$:
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1248
\begin{center}
558
Chengsong
parents: 557
diff changeset
  1249
	$\rsimp{r} \stackrel{?}{\sequal} \rsimp{r'}$ if $r = \sum [r_1, r_2, r_3, \ldots]$ 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1250
	and $r' =(\ldots ((r_1 + r_2) + r_3) + \ldots)$
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1251
\end{center}
558
Chengsong
parents: 557
diff changeset
  1252
Simply wrap with $\sum$ constructor and add 
Chengsong
parents: 557
diff changeset
  1253
simplifications to both sides of \ref{seqSfau0}
Chengsong
parents: 557
diff changeset
  1254
and one gets
Chengsong
parents: 557
diff changeset
  1255
\begin{corollary}\label{seqClosedFormGeneral}
Chengsong
parents: 557
diff changeset
  1256
	$\rsimp{\sflat{(r_1 \cdot r_2) \backslash s} }
Chengsong
parents: 557
diff changeset
  1257
	=\rsimp{(\sum (  (r_1 \backslash s) \cdot r_2 :: 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1258
	\map\; (r_2 \backslash \_) \; (\vsuf{s}{r_1})))}$
558
Chengsong
parents: 557
diff changeset
  1259
\end{corollary}
Chengsong
parents: 557
diff changeset
  1260
Together with the idempotency property of $\rsimp{}$ (lemma \ref{rsimpIdem}),
Chengsong
parents: 557
diff changeset
  1261
it is possible to convert the above lemma to obtain a "closed form"
Chengsong
parents: 557
diff changeset
  1262
for  derivatives nested with simplification:
Chengsong
parents: 557
diff changeset
  1263
\begin{lemma}\label{seqClosedForm}
Chengsong
parents: 557
diff changeset
  1264
	$\rderssimp{(r_1 \cdot r_2)}{s} = \rsimp{(\sum ((r_1 \backslash s) \cdot r_2 ) 
Chengsong
parents: 557
diff changeset
  1265
	:: (\map \; (r_2 \backslash \_) (\vsuf{s}{r_1})))}$
Chengsong
parents: 557
diff changeset
  1266
\end{lemma}
Chengsong
parents: 557
diff changeset
  1267
\begin{proof}
Chengsong
parents: 557
diff changeset
  1268
	By a case analysis of string $s$.
Chengsong
parents: 557
diff changeset
  1269
	When $s$ is empty list, the rewrite is straightforward.
Chengsong
parents: 557
diff changeset
  1270
	When $s$ is a list, one could use the corollary \ref{seqSfau0},
Chengsong
parents: 557
diff changeset
  1271
	and lemma \ref{Simpders} to rewrite the left-hand-side.
Chengsong
parents: 557
diff changeset
  1272
\end{proof}
Chengsong
parents: 557
diff changeset
  1273
As a corollary for this closed form, one can estimate the size 
Chengsong
parents: 557
diff changeset
  1274
of the sequence derivative $r_1 \cdot r_2 \backslash_r s$ using 
Chengsong
parents: 557
diff changeset
  1275
an easier-to-handle expression:
Chengsong
parents: 557
diff changeset
  1276
\begin{corollary}\label{seqEstimate1}
Chengsong
parents: 557
diff changeset
  1277
	\begin{center}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1278
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1279
		$\llbracket \rderssimp{(r_1 \cdot r_2)}{s} \rrbracket_r = \llbracket \rsimp{(\sum ((r_1 \backslash s) \cdot r_2 ) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1280
		:: (\map \; (r_2 \backslash \_) (\vsuf{s}{r_1})))} \rrbracket_r$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1281
558
Chengsong
parents: 557
diff changeset
  1282
	\end{center}
Chengsong
parents: 557
diff changeset
  1283
\end{corollary}
Chengsong
parents: 557
diff changeset
  1284
\noindent
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1285
\subsubsection{Closed Forms for Star Regular Expressions}
564
Chengsong
parents: 562
diff changeset
  1286
We have shown how to control the size of the sequence regular expression $r_1\cdot r_2$ using
Chengsong
parents: 562
diff changeset
  1287
the "closed form" of $(r_1 \cdot r_2) \backslash s$ and then 
Chengsong
parents: 562
diff changeset
  1288
the property of the $\distinct$ function.
Chengsong
parents: 562
diff changeset
  1289
Now we try to get a bound on $r^* \backslash s$ as well.
Chengsong
parents: 562
diff changeset
  1290
Again, we first look at how a star's derivatives evolve, if they grow maximally: 
Chengsong
parents: 562
diff changeset
  1291
\begin{center}
Chengsong
parents: 562
diff changeset
  1292
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1293
	$r^* \quad \longrightarrow_{\backslash c}  \quad   (r\backslash c)  \cdot  r^* \quad \longrightarrow_{\backslash c'}  \quad
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1294
	r \backslash cc'  \cdot r^* + r \backslash c' \cdot r^*  \quad \longrightarrow_{\backslash c''} \quad 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1295
	(r_1 \backslash cc'c'' \cdot r^* + r \backslash c'') + (r \backslash c'c'' \cdot r^* + r \backslash c'' \cdot r^*)   \quad \longrightarrow_{\backslash c'''}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1296
	\quad \ldots$
564
Chengsong
parents: 562
diff changeset
  1297
Chengsong
parents: 562
diff changeset
  1298
\end{center}
Chengsong
parents: 562
diff changeset
  1299
When we have a string $s = c :: c' :: c'' \ldots$  such that $r \backslash c$, $r \backslash cc'$, $r \backslash c'$, 
Chengsong
parents: 562
diff changeset
  1300
$r \backslash cc'c''$, $r \backslash c'c''$, $r\backslash c''$ etc. are all nullable,
Chengsong
parents: 562
diff changeset
  1301
the number of terms in $r^* \backslash s$ will grow exponentially, causing the size
Chengsong
parents: 562
diff changeset
  1302
of the derivatives $r^* \backslash s$ to grow exponentially, even if we do not 
Chengsong
parents: 562
diff changeset
  1303
count the possible size explosions of $r \backslash c$ themselves.
Chengsong
parents: 562
diff changeset
  1304
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  1305
Thanks to $\rflts$ and $\rDistinct$, we are able to open up regular expressions like
564
Chengsong
parents: 562
diff changeset
  1306
$(r_1 \backslash cc'c'' \cdot r^* + r \backslash c'') + 
Chengsong
parents: 562
diff changeset
  1307
(r \backslash c'c'' \cdot r^* + r \backslash c'' \cdot r^*) $ 
Chengsong
parents: 562
diff changeset
  1308
into $\RALTS{[r_1 \backslash cc'c'' \cdot r^*, r \backslash c'', 
Chengsong
parents: 562
diff changeset
  1309
r \backslash c'c'' \cdot r^*, r \backslash c'' \cdot r^*]}$
Chengsong
parents: 562
diff changeset
  1310
and then de-duplicate terms of the form $r\backslash s' \cdot r^*$ ($s'$ being a substring of $s$).
Chengsong
parents: 562
diff changeset
  1311
This allows us to use a similar technique as $r_1 \cdot r_2$ case,
Chengsong
parents: 562
diff changeset
  1312
where the crux is to get an equivalent form of 
Chengsong
parents: 562
diff changeset
  1313
$\rderssimp{r^*}{s}$ with shape $\rsimp{\sum rs}$.
Chengsong
parents: 562
diff changeset
  1314
This requires generating 
558
Chengsong
parents: 557
diff changeset
  1315
all possible sub-strings $s'$ of $s$
Chengsong
parents: 557
diff changeset
  1316
such that $r\backslash s' \cdot r^*$ will appear 
Chengsong
parents: 557
diff changeset
  1317
as a term in $(r^*) \backslash s$.
Chengsong
parents: 557
diff changeset
  1318
The first function we define is a single-step
Chengsong
parents: 557
diff changeset
  1319
updating function $\starupdate$, which takes three arguments as input:
Chengsong
parents: 557
diff changeset
  1320
the new character $c$ to take derivative with, 
Chengsong
parents: 557
diff changeset
  1321
the regular expression
Chengsong
parents: 557
diff changeset
  1322
$r$ directly under the star $r^*$, and the
Chengsong
parents: 557
diff changeset
  1323
list of strings $sSet$ for the derivative $r^* \backslash s$ 
Chengsong
parents: 557
diff changeset
  1324
up til this point  
Chengsong
parents: 557
diff changeset
  1325
such that $(r^*) \backslash s = \sum_{s' \in sSet} (r\backslash s') \cdot r^*$ 
Chengsong
parents: 557
diff changeset
  1326
(the equality is not exact, more on this later).
Chengsong
parents: 557
diff changeset
  1327
\begin{center}
Chengsong
parents: 557
diff changeset
  1328
	\begin{tabular}{lcl}
Chengsong
parents: 557
diff changeset
  1329
		$\starupdate \; c \; r \; [] $ & $\dn$ & $[]$\\
Chengsong
parents: 557
diff changeset
  1330
		$\starupdate \; c \; r \; (s :: Ss)$ & $\dn$ & \\
Chengsong
parents: 557
diff changeset
  1331
						     & & $\textit{if} \; 
Chengsong
parents: 557
diff changeset
  1332
						     (\rnullable \; (\rders \; r \; s))$ \\
Chengsong
parents: 557
diff changeset
  1333
						     & & $\textit{then} \;\; (s @ [c]) :: [c] :: (
Chengsong
parents: 557
diff changeset
  1334
						     \starupdate \; c \; r \; Ss)$ \\
Chengsong
parents: 557
diff changeset
  1335
						     & & $\textit{else} \;\; (s @ [c]) :: (
Chengsong
parents: 557
diff changeset
  1336
						     \starupdate \; c \; r \; Ss)$
Chengsong
parents: 557
diff changeset
  1337
	\end{tabular}
Chengsong
parents: 557
diff changeset
  1338
\end{center}
Chengsong
parents: 557
diff changeset
  1339
\noindent
Chengsong
parents: 557
diff changeset
  1340
As a generalisation from characters to strings,
Chengsong
parents: 557
diff changeset
  1341
$\starupdates$ takes a string instead of a character
Chengsong
parents: 557
diff changeset
  1342
as the first input argument, and is otherwise the same
Chengsong
parents: 557
diff changeset
  1343
as $\starupdate$.
Chengsong
parents: 557
diff changeset
  1344
\begin{center}
Chengsong
parents: 557
diff changeset
  1345
	\begin{tabular}{lcl}
Chengsong
parents: 557
diff changeset
  1346
		$\starupdates \; [] \; r \; Ss$ & $=$ & $Ss$\\
Chengsong
parents: 557
diff changeset
  1347
		$\starupdates \; (c :: cs) \; r \; Ss$ &  $=$ &  $\starupdates \; cs \; r \; (
Chengsong
parents: 557
diff changeset
  1348
		\starupdate \; c \; r \; Ss)$
Chengsong
parents: 557
diff changeset
  1349
	\end{tabular}
Chengsong
parents: 557
diff changeset
  1350
\end{center}
Chengsong
parents: 557
diff changeset
  1351
\noindent
Chengsong
parents: 557
diff changeset
  1352
For the star regular expression,
Chengsong
parents: 557
diff changeset
  1353
its derivatives can be seen as  a nested gigantic
Chengsong
parents: 557
diff changeset
  1354
alternative similar to that of sequence regular expression's derivatives, 
Chengsong
parents: 557
diff changeset
  1355
and therefore need
Chengsong
parents: 557
diff changeset
  1356
to be ``straightened out" as well.
Chengsong
parents: 557
diff changeset
  1357
The function for this would be $\hflat{}$ and $\hflataux{}$.
Chengsong
parents: 557
diff changeset
  1358
\begin{center}
Chengsong
parents: 557
diff changeset
  1359
	\begin{tabular}{lcl}
Chengsong
parents: 557
diff changeset
  1360
		$\hflataux{r_1 + r_2}$ & $\dn$ & $\hflataux{r_1} @ \hflataux{r_2}$\\
Chengsong
parents: 557
diff changeset
  1361
		$\hflataux{r}$ & $\dn$ & $[r]$
Chengsong
parents: 557
diff changeset
  1362
	\end{tabular}
Chengsong
parents: 557
diff changeset
  1363
\end{center}
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1364
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1365
\begin{center}
558
Chengsong
parents: 557
diff changeset
  1366
	\begin{tabular}{lcl}
Chengsong
parents: 557
diff changeset
  1367
		$\hflat{r_1 + r_2}$ & $\dn$ & $\sum (\hflataux {r_1} @ \hflataux {r_2}) $\\
Chengsong
parents: 557
diff changeset
  1368
		$\hflat{r}$ & $\dn$ & $r$
Chengsong
parents: 557
diff changeset
  1369
	\end{tabular}
Chengsong
parents: 557
diff changeset
  1370
\end{center}
Chengsong
parents: 557
diff changeset
  1371
\noindent
Chengsong
parents: 557
diff changeset
  1372
%MAYBE TODO: introduce createdByStar
564
Chengsong
parents: 562
diff changeset
  1373
Again these definitions are tailor-made for dealing with alternatives that have
Chengsong
parents: 562
diff changeset
  1374
originated from a star's derivatives, so we do not attempt to open up all possible 
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  1375
regular expressions of the form $\RALTS{rs}$, where $\textit{rs}$ might not contain precisely 2
564
Chengsong
parents: 562
diff changeset
  1376
elements.
Chengsong
parents: 562
diff changeset
  1377
We give a predicate for such "star-created" regular expressions:
Chengsong
parents: 562
diff changeset
  1378
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1379
	\begin{tabular}{lcr}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1380
	 &    &       $\createdByStar{(\RSEQ{ra}{\RSTAR{rb}}) }$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1381
		$\createdByStar{r_1} \land \createdByStar{r_2} $ & $ \Longrightarrow$ & $\createdByStar{(r_1 + r_2)}$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1382
	\end{tabular}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1383
\end{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1384
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1385
These definitions allows us the flexibility to talk about 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1386
regular expressions in their most convenient format,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1387
for example, flattened out $\RALTS{[r_1, r_2, \ldots, r_n]} $
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1388
instead of binary-nested: $((r_1 + r_2) + (r_3 + r_4)) + \ldots$.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1389
These definitions help express that certain classes of syntatically 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1390
distinct regular expressions are actually the same under simplification.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1391
This is not entirely true for annotated regular expressions: 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1392
%TODO: bsimp bders \neq bderssimp
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1393
\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1394
	$(1+ (c\cdot \ASEQ{bs}{c^*}{c} ))$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1395
\end{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1396
For bit-codes, the order in which simplification is applied
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1397
might cause a difference in the location they are placed.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1398
If we want something like
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1399
\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1400
	$\bderssimp{r}{s} \myequiv \bsimp{\bders{r}{s}}$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1401
\end{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1402
Some "canonicalization" procedure is required,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1403
which either pushes all the common bitcodes to nodes
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1404
as senior as possible:
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1405
\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1406
	$_{bs}(_{bs_1 @ bs'}r_1 + _{bs_1 @ bs''}r_2) \rightarrow _{bs @ bs_1}(_{bs'}r_1 + _{bs''}r_2) $
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1407
\end{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1408
or does the reverse. However bitcodes are not of interest if we are talking about
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1409
the $\llbracket r \rrbracket$ size of a regex.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1410
Therefore for the ease and simplicity of producing a
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1411
proof for a size bound, we are happy to restrict ourselves to 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1412
unannotated regular expressions, and obtain such equalities as
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1413
\begin{lemma}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1414
	$\rsimp{r_1 + r_2} = \rsimp{\RALTS{\hflataux{r_1} @ \hflataux{r_2}}}$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1415
\end{lemma}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1416
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1417
\begin{proof}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1418
	By using the rewriting relation $\rightsquigarrow$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1419
\end{proof}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1420
%TODO: rsimp sflat
564
Chengsong
parents: 562
diff changeset
  1421
And from this we obtain a proof that a star's derivative will be the same
Chengsong
parents: 562
diff changeset
  1422
as if it had all its nested alternatives created during deriving being flattened out:
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1423
For example,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1424
\begin{lemma}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1425
	$\createdByStar{r} \implies \rsimp{r} = \rsimp{\RALTS{\hflataux{r}}}$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1426
\end{lemma}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1427
\begin{proof}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1428
	By structural induction on $r$, where the induction rules are these of $\createdByStar{_}$.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1429
\end{proof}
564
Chengsong
parents: 562
diff changeset
  1430
% The simplification of a flattened out regular expression, provided it comes
Chengsong
parents: 562
diff changeset
  1431
%from the derivative of a star, is the same as the one nested.
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1432
564
Chengsong
parents: 562
diff changeset
  1433
Chengsong
parents: 562
diff changeset
  1434
558
Chengsong
parents: 557
diff changeset
  1435
We first introduce an inductive property
Chengsong
parents: 557
diff changeset
  1436
for $\starupdate$ and $\hflataux{\_}$, 
Chengsong
parents: 557
diff changeset
  1437
it says if we do derivatives of $r^*$
Chengsong
parents: 557
diff changeset
  1438
with a string that starts with $c$,
Chengsong
parents: 557
diff changeset
  1439
then flatten it out,
Chengsong
parents: 557
diff changeset
  1440
we obtain a list
Chengsong
parents: 557
diff changeset
  1441
of the shape $\sum_{s' \in sSet} (r\backslash_r s') \cdot r^*$,
Chengsong
parents: 557
diff changeset
  1442
where $sSet = \starupdates \; s \; r \; [[c]]$.
Chengsong
parents: 557
diff changeset
  1443
\begin{lemma}\label{starHfauInduct}
Chengsong
parents: 557
diff changeset
  1444
	$\hflataux{(\rders{( (\rder{c}{r_0})\cdot(r_0^*))}{s})} = 
Chengsong
parents: 557
diff changeset
  1445
	\map \; (\lambda s_1. (r_0 \backslash_r s_1) \cdot (r_0^*)) \; 
Chengsong
parents: 557
diff changeset
  1446
	(\starupdates \; s \; r_0 \; [[c]])$
Chengsong
parents: 557
diff changeset
  1447
\end{lemma}
Chengsong
parents: 557
diff changeset
  1448
\begin{proof}
Chengsong
parents: 557
diff changeset
  1449
	By an induction on $s$, the inductive cases
Chengsong
parents: 557
diff changeset
  1450
	being $[]$ and $s@[c]$.
Chengsong
parents: 557
diff changeset
  1451
\end{proof}
Chengsong
parents: 557
diff changeset
  1452
\noindent
Chengsong
parents: 557
diff changeset
  1453
Here is a corollary that states the lemma in
Chengsong
parents: 557
diff changeset
  1454
a more intuitive way:
Chengsong
parents: 557
diff changeset
  1455
\begin{corollary}
Chengsong
parents: 557
diff changeset
  1456
	$\hflataux{r^* \backslash_r (c::xs)} = \map \; (\lambda s. (r \backslash_r s) \cdot
Chengsong
parents: 557
diff changeset
  1457
	(r^*))\; (\starupdates \; c\; r\; [[c]])$
Chengsong
parents: 557
diff changeset
  1458
\end{corollary}
Chengsong
parents: 557
diff changeset
  1459
\noindent
Chengsong
parents: 557
diff changeset
  1460
Note that this is also agnostic of the simplification
Chengsong
parents: 557
diff changeset
  1461
function we defined, and is therefore of more general interest.
Chengsong
parents: 557
diff changeset
  1462
Chengsong
parents: 557
diff changeset
  1463
Now adding the $\rsimp{}$ bit for closed forms,
Chengsong
parents: 557
diff changeset
  1464
we have
Chengsong
parents: 557
diff changeset
  1465
\begin{lemma}
Chengsong
parents: 557
diff changeset
  1466
	$a :: rs \grewrites \hflataux{a} @ rs$
Chengsong
parents: 557
diff changeset
  1467
\end{lemma}
Chengsong
parents: 557
diff changeset
  1468
\noindent
Chengsong
parents: 557
diff changeset
  1469
giving us
Chengsong
parents: 557
diff changeset
  1470
\begin{lemma}\label{cbsHfauRsimpeq1}
Chengsong
parents: 557
diff changeset
  1471
	$\rsimp{a+b} = \rsimp{(\sum \hflataux{a} @ \hflataux{b})}$.
Chengsong
parents: 557
diff changeset
  1472
\end{lemma}
Chengsong
parents: 557
diff changeset
  1473
\noindent
Chengsong
parents: 557
diff changeset
  1474
This yields
Chengsong
parents: 557
diff changeset
  1475
\begin{lemma}\label{hfauRsimpeq2}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1476
	$\rsimp{r} = \rsimp{(\sum \hflataux{r})}$
558
Chengsong
parents: 557
diff changeset
  1477
\end{lemma}
Chengsong
parents: 557
diff changeset
  1478
\noindent
Chengsong
parents: 557
diff changeset
  1479
Together with the rewriting relation
Chengsong
parents: 557
diff changeset
  1480
\begin{lemma}\label{starClosedForm6Hrewrites}
Chengsong
parents: 557
diff changeset
  1481
	$\map \; (\lambda s. (\rsimp{r \backslash_r s}) \cdot (r^*)) \; Ss
Chengsong
parents: 557
diff changeset
  1482
	\scfrewrites
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1483
	\map \; (\lambda s. (\rsimp{r \backslash_r s}) \cdot (r^*)) \; Ss$
558
Chengsong
parents: 557
diff changeset
  1484
\end{lemma}
Chengsong
parents: 557
diff changeset
  1485
\noindent
Chengsong
parents: 557
diff changeset
  1486
We obtain the closed form for star regular expression:
Chengsong
parents: 557
diff changeset
  1487
\begin{lemma}\label{starClosedForm}
Chengsong
parents: 557
diff changeset
  1488
	$\rderssimp{r^*}{c::s} = 
Chengsong
parents: 557
diff changeset
  1489
	\rsimp{
Chengsong
parents: 557
diff changeset
  1490
		(\sum (\map \; (\lambda s. (\rderssimp{r}{s})\cdot r^*) \; 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1491
		(\starupdates \; s\; r \; [[c]])
558
Chengsong
parents: 557
diff changeset
  1492
		)
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1493
		)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1494
	}
558
Chengsong
parents: 557
diff changeset
  1495
	$
Chengsong
parents: 557
diff changeset
  1496
\end{lemma}
Chengsong
parents: 557
diff changeset
  1497
\begin{proof}
Chengsong
parents: 557
diff changeset
  1498
	By an induction on $s$.
Chengsong
parents: 557
diff changeset
  1499
	The lemmas \ref{rsimpIdem}, \ref{starHfauInduct}, and \ref{hfauRsimpeq2}
Chengsong
parents: 557
diff changeset
  1500
	are used.	
Chengsong
parents: 557
diff changeset
  1501
\end{proof}
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1502
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1503
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1504
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1505
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1506
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1507
613
Chengsong
parents: 611
diff changeset
  1508
%----------------------------------------------------------------------------------------
Chengsong
parents: 611
diff changeset
  1509
%	SECTION ??
Chengsong
parents: 611
diff changeset
  1510
%----------------------------------------------------------------------------------------
Chengsong
parents: 611
diff changeset
  1511
Chengsong
parents: 611
diff changeset
  1512
%-----------------------------------
Chengsong
parents: 611
diff changeset
  1513
%	SECTION syntactic equivalence under simp
Chengsong
parents: 611
diff changeset
  1514
%-----------------------------------
Chengsong
parents: 611
diff changeset
  1515
Chengsong
parents: 611
diff changeset
  1516
Chengsong
parents: 611
diff changeset
  1517
%----------------------------------------------------------------------------------------
Chengsong
parents: 611
diff changeset
  1518
%	SECTION ALTS CLOSED FORM
Chengsong
parents: 611
diff changeset
  1519
%----------------------------------------------------------------------------------------
Chengsong
parents: 611
diff changeset
  1520
%\section{A Closed Form for \textit{ALTS}}
Chengsong
parents: 611
diff changeset
  1521
%Now we prove that  $rsimp (rders\_simp (RALTS rs) s) = rsimp (RALTS (map (\lambda r. rders\_simp r s) rs))$.
Chengsong
parents: 611
diff changeset
  1522
%
Chengsong
parents: 611
diff changeset
  1523
%
Chengsong
parents: 611
diff changeset
  1524
%There are a few key steps, one of these steps is
Chengsong
parents: 611
diff changeset
  1525
%
Chengsong
parents: 611
diff changeset
  1526
%
Chengsong
parents: 611
diff changeset
  1527
%
Chengsong
parents: 611
diff changeset
  1528
%One might want to prove this by something a simple statement like: 
Chengsong
parents: 611
diff changeset
  1529
%
Chengsong
parents: 611
diff changeset
  1530
%For this to hold we want the $\textit{distinct}$ function to pick up
Chengsong
parents: 611
diff changeset
  1531
%the elements before and after derivatives correctly:
Chengsong
parents: 611
diff changeset
  1532
%$r \in rset \equiv (rder x r) \in (rder x rset)$.
Chengsong
parents: 611
diff changeset
  1533
%which essentially requires that the function $\backslash$ is an injective mapping.
Chengsong
parents: 611
diff changeset
  1534
%
Chengsong
parents: 611
diff changeset
  1535
%Unfortunately the function $\backslash c$ is not an injective mapping.
Chengsong
parents: 611
diff changeset
  1536
%
Chengsong
parents: 611
diff changeset
  1537
%\subsection{function $\backslash c$ is not injective (1-to-1)}
Chengsong
parents: 611
diff changeset
  1538
%\begin{center}
Chengsong
parents: 611
diff changeset
  1539
%	The derivative $w.r.t$ character $c$ is not one-to-one.
Chengsong
parents: 611
diff changeset
  1540
%	Formally,
Chengsong
parents: 611
diff changeset
  1541
%	$\exists r_1 \;r_2. r_1 \neq r_2 \mathit{and} r_1 \backslash c = r_2 \backslash c$
Chengsong
parents: 611
diff changeset
  1542
%\end{center}
Chengsong
parents: 611
diff changeset
  1543
%This property is trivially true for the
Chengsong
parents: 611
diff changeset
  1544
%character regex example:
Chengsong
parents: 611
diff changeset
  1545
%\begin{center}
Chengsong
parents: 611
diff changeset
  1546
%	$r_1 = e; \; r_2 = d;\; r_1 \backslash c = \ZERO = r_2 \backslash c$
Chengsong
parents: 611
diff changeset
  1547
%\end{center}
Chengsong
parents: 611
diff changeset
  1548
%But apart from the cases where the derivative
Chengsong
parents: 611
diff changeset
  1549
%output is $\ZERO$, are there non-trivial results
Chengsong
parents: 611
diff changeset
  1550
%of derivatives which contain strings?
Chengsong
parents: 611
diff changeset
  1551
%The answer is yes.
Chengsong
parents: 611
diff changeset
  1552
%For example,
Chengsong
parents: 611
diff changeset
  1553
%\begin{center}
Chengsong
parents: 611
diff changeset
  1554
%	Let $r_1 = a^*b\;\quad r_2 = (a\cdot a^*)\cdot b + b$.\\
Chengsong
parents: 611
diff changeset
  1555
%	where $a$ is not nullable.\\
Chengsong
parents: 611
diff changeset
  1556
%	$r_1 \backslash c = ((a \backslash c)\cdot a^*)\cdot c + b \backslash c$\\
Chengsong
parents: 611
diff changeset
  1557
%	$r_2 \backslash c = ((a \backslash c)\cdot a^*)\cdot c + b \backslash c$
Chengsong
parents: 611
diff changeset
  1558
%\end{center}
Chengsong
parents: 611
diff changeset
  1559
%We start with two syntactically different regular expressions,
Chengsong
parents: 611
diff changeset
  1560
%and end up with the same derivative result.
Chengsong
parents: 611
diff changeset
  1561
%This is not surprising as we have such 
Chengsong
parents: 611
diff changeset
  1562
%equality as below in the style of Arden's lemma:\\
Chengsong
parents: 611
diff changeset
  1563
%\begin{center}
Chengsong
parents: 611
diff changeset
  1564
%	$L(A^*B) = L(A\cdot A^* \cdot B + B)$
Chengsong
parents: 611
diff changeset
  1565
%\end{center}
Chengsong
parents: 611
diff changeset
  1566
\section{Bounding Closed Forms}
Chengsong
parents: 611
diff changeset
  1567
Chengsong
parents: 611
diff changeset
  1568
In this section, we introduce how we formalised the bound
Chengsong
parents: 611
diff changeset
  1569
on closed forms.
Chengsong
parents: 611
diff changeset
  1570
We first prove that functions such as $\rflts$
Chengsong
parents: 611
diff changeset
  1571
will not cause the size of r-regular expressions to grow.
Chengsong
parents: 611
diff changeset
  1572
Putting this together with a general bound 
Chengsong
parents: 611
diff changeset
  1573
on the finiteness of distinct regular expressions
Chengsong
parents: 611
diff changeset
  1574
smaller than a certain size, we obtain a bound on 
Chengsong
parents: 611
diff changeset
  1575
the closed forms.
Chengsong
parents: 611
diff changeset
  1576
Chengsong
parents: 611
diff changeset
  1577
\subsection{$\textit{rsimp}$ Does Not Increment the Size}
Chengsong
parents: 611
diff changeset
  1578
Although it seems evident, we need a series
Chengsong
parents: 611
diff changeset
  1579
of non-trivial lemmas to establish that functions such as $\rflts$
Chengsong
parents: 611
diff changeset
  1580
do not cause the regular expressions to grow.
Chengsong
parents: 611
diff changeset
  1581
\begin{lemma}\label{rsimpMonoLemmas}
Chengsong
parents: 611
diff changeset
  1582
	\mbox{}
Chengsong
parents: 611
diff changeset
  1583
	\begin{itemize}
Chengsong
parents: 611
diff changeset
  1584
		\item
Chengsong
parents: 611
diff changeset
  1585
			\[
Chengsong
parents: 611
diff changeset
  1586
				\llbracket \rsimpalts \; rs \rrbracket_r \leq
Chengsong
parents: 611
diff changeset
  1587
				\llbracket \sum \; rs \rrbracket_r
Chengsong
parents: 611
diff changeset
  1588
			\]
Chengsong
parents: 611
diff changeset
  1589
		\item
Chengsong
parents: 611
diff changeset
  1590
			\[
Chengsong
parents: 611
diff changeset
  1591
				\llbracket \rsimpseq \; r_1 \;  r_2 \rrbracket_r \leq
Chengsong
parents: 611
diff changeset
  1592
				\llbracket r_1 \cdot r_2 \rrbracket_r
Chengsong
parents: 611
diff changeset
  1593
			\]
Chengsong
parents: 611
diff changeset
  1594
		\item
Chengsong
parents: 611
diff changeset
  1595
			\[
Chengsong
parents: 611
diff changeset
  1596
				\llbracket \rflts \; rs \rrbracket_r  \leq
Chengsong
parents: 611
diff changeset
  1597
				\llbracket rs \rrbracket_r 
Chengsong
parents: 611
diff changeset
  1598
			\]
Chengsong
parents: 611
diff changeset
  1599
		\item
Chengsong
parents: 611
diff changeset
  1600
			\[
Chengsong
parents: 611
diff changeset
  1601
				\llbracket \rDistinct \; rs \; ss \rrbracket_r  \leq
Chengsong
parents: 611
diff changeset
  1602
				\llbracket rs \rrbracket_r 
Chengsong
parents: 611
diff changeset
  1603
			\]
Chengsong
parents: 611
diff changeset
  1604
		\item
Chengsong
parents: 611
diff changeset
  1605
			If all elements $a$ in the set $as$ satisfy the property
Chengsong
parents: 611
diff changeset
  1606
			that $\llbracket \textit{rsimp} \; a \rrbracket_r \leq
Chengsong
parents: 611
diff changeset
  1607
			\llbracket a \rrbracket_r$, then we have 
Chengsong
parents: 611
diff changeset
  1608
			\[
Chengsong
parents: 611
diff changeset
  1609
				\llbracket \; \rsimpalts \; (\textit{rdistinct} \;
Chengsong
parents: 611
diff changeset
  1610
				(\textit{rflts} \; (\textit{map}\;\textit{rsimp} as)) \{\})
Chengsong
parents: 611
diff changeset
  1611
				\rrbracket \leq
Chengsong
parents: 611
diff changeset
  1612
				\llbracket \; \sum \; (\rDistinct \; (\rflts \;(\map \;
Chengsong
parents: 611
diff changeset
  1613
				\textit{rsimp} \; x))\; \{ \} ) \rrbracket_r 
Chengsong
parents: 611
diff changeset
  1614
			\]
Chengsong
parents: 611
diff changeset
  1615
	\end{itemize}
Chengsong
parents: 611
diff changeset
  1616
\end{lemma}
Chengsong
parents: 611
diff changeset
  1617
\begin{proof}
Chengsong
parents: 611
diff changeset
  1618
	Point 1, 3, 4 can be proven by an induction on $rs$.
Chengsong
parents: 611
diff changeset
  1619
	Point 2 is by case analysis on $r_1$ and $r_2$.
Chengsong
parents: 611
diff changeset
  1620
	The last part is a corollary of the previous ones.
Chengsong
parents: 611
diff changeset
  1621
\end{proof}
Chengsong
parents: 611
diff changeset
  1622
\noindent
Chengsong
parents: 611
diff changeset
  1623
With the lemmas for each inductive case in place, we are ready to get 
Chengsong
parents: 611
diff changeset
  1624
the non-increasing property as a corollary:
Chengsong
parents: 611
diff changeset
  1625
\begin{corollary}\label{rsimpMono}
Chengsong
parents: 611
diff changeset
  1626
	$\llbracket \textit{rsimp} \; r \rrbracket_r \leq \llbracket r \rrbracket_r$
Chengsong
parents: 611
diff changeset
  1627
\end{corollary}
Chengsong
parents: 611
diff changeset
  1628
\begin{proof}
Chengsong
parents: 611
diff changeset
  1629
	By \ref{rsimpMonoLemmas}.
Chengsong
parents: 611
diff changeset
  1630
\end{proof}
Chengsong
parents: 611
diff changeset
  1631
Chengsong
parents: 611
diff changeset
  1632
\subsubsection{The $RL$ Function: Language Interpretation of $\textit{Rrexp}$s}
Chengsong
parents: 611
diff changeset
  1633
Much like the definition of $L$ on plain regular expressions, one could also 
Chengsong
parents: 611
diff changeset
  1634
define the language interpretation of $\rrexp$s.
Chengsong
parents: 611
diff changeset
  1635
\begin{center}
Chengsong
parents: 611
diff changeset
  1636
	\begin{tabular}{lcl}
Chengsong
parents: 611
diff changeset
  1637
		$RL \; (\ZERO)$ & $\dn$ & $\phi$\\
Chengsong
parents: 611
diff changeset
  1638
		$RL \; (\ONE)$ & $\dn$ & $\{[]\}$\\
Chengsong
parents: 611
diff changeset
  1639
		$RL \; (c)$ & $\dn$ & $\{[c]\}$\\
Chengsong
parents: 611
diff changeset
  1640
		$RL \; \sum rs$ & $\dn$ & $ \bigcup_{r \in rs} (RL \; r)$\\
Chengsong
parents: 611
diff changeset
  1641
		$RL \; (r_1 \cdot r_2)$ & $\dn$ & $ RL \; (r_1) @ RL \; (r_2)$\\
Chengsong
parents: 611
diff changeset
  1642
		$RL \; (r^*)$ & $\dn$ & $ (RL(r))^*$
Chengsong
parents: 611
diff changeset
  1643
	\end{tabular}
Chengsong
parents: 611
diff changeset
  1644
\end{center}
Chengsong
parents: 611
diff changeset
  1645
\noindent
Chengsong
parents: 611
diff changeset
  1646
The main use of $RL$ is to establish some connections between $\rsimp{}$ 
Chengsong
parents: 611
diff changeset
  1647
and $\rnullable{}$:
Chengsong
parents: 611
diff changeset
  1648
\begin{lemma}
Chengsong
parents: 611
diff changeset
  1649
	The following properties hold:
Chengsong
parents: 611
diff changeset
  1650
	\begin{itemize}
Chengsong
parents: 611
diff changeset
  1651
		\item
Chengsong
parents: 611
diff changeset
  1652
			If $\rnullable{r}$, then $\rsimp{r} \neq \RZERO$.
Chengsong
parents: 611
diff changeset
  1653
		\item
Chengsong
parents: 611
diff changeset
  1654
			$\rnullable{r \backslash s} \quad $ if and only if $\quad \rnullable{\rderssimp{r}{s}}$.
Chengsong
parents: 611
diff changeset
  1655
	\end{itemize}
Chengsong
parents: 611
diff changeset
  1656
\end{lemma}
Chengsong
parents: 611
diff changeset
  1657
\begin{proof}
Chengsong
parents: 611
diff changeset
  1658
	The first part is by induction on $r$. 
Chengsong
parents: 611
diff changeset
  1659
	The second part is true because property 
Chengsong
parents: 611
diff changeset
  1660
	\[ RL \; r = RL \; (\rsimp{r})\] holds.
Chengsong
parents: 611
diff changeset
  1661
\end{proof}
Chengsong
parents: 611
diff changeset
  1662
Chengsong
parents: 611
diff changeset
  1663
\subsubsection{Simplified $\textit{Rrexp}$s are Good}
Chengsong
parents: 611
diff changeset
  1664
We formalise the notion of ``good" regular expressions,
Chengsong
parents: 611
diff changeset
  1665
which means regular expressions that
Chengsong
parents: 611
diff changeset
  1666
are not fully simplified. For alternative regular expressions that means they
Chengsong
parents: 611
diff changeset
  1667
do not contain any nested alternatives like 
Chengsong
parents: 611
diff changeset
  1668
\[ r_1 + (r_2 + r_3) \], un-removed $\RZERO$s like \[\RZERO + r\]
Chengsong
parents: 611
diff changeset
  1669
or duplicate elements in a children regular expression list like \[ \sum [r, r, \ldots]\]:
Chengsong
parents: 611
diff changeset
  1670
\begin{center}
Chengsong
parents: 611
diff changeset
  1671
	\begin{tabular}{@{}lcl@{}}
Chengsong
parents: 611
diff changeset
  1672
		$\good\; \RZERO$ & $\dn$ & $\textit{false}$\\
Chengsong
parents: 611
diff changeset
  1673
		$\good\; \RONE$ & $\dn$ & $\textit{true}$\\
Chengsong
parents: 611
diff changeset
  1674
		$\good\; \RCHAR{c}$ & $\dn$ & $\btrue$\\
Chengsong
parents: 611
diff changeset
  1675
		$\good\; \RALTS{[]}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 611
diff changeset
  1676
		$\good\; \RALTS{[r]}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 611
diff changeset
  1677
		$\good\; \RALTS{r_1 :: r_2 :: rs}$ & $\dn$ & 
Chengsong
parents: 611
diff changeset
  1678
		$\textit{isDistinct} \; (r_1 :: r_2 :: rs) \;$\\
Chengsong
parents: 611
diff changeset
  1679
						   & & $\textit{and}\; (\forall r' \in (r_1 :: r_2 :: rs).\; \good \; r'\; \,  \textit{and}\; \, \textit{nonAlt}\; r')$\\
Chengsong
parents: 611
diff changeset
  1680
		$\good \; \RSEQ{\RZERO}{r}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 611
diff changeset
  1681
		$\good \; \RSEQ{\RONE}{r}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 611
diff changeset
  1682
		$\good \; \RSEQ{r}{\RZERO}$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 611
diff changeset
  1683
		$\good \; \RSEQ{r_1}{r_2}$ & $\dn$ & $\good \; r_1 \;\, \textit{and} \;\, \good \; r_2$\\
Chengsong
parents: 611
diff changeset
  1684
		$\good \; \RSTAR{r}$ & $\dn$ & $\btrue$\\
Chengsong
parents: 611
diff changeset
  1685
	\end{tabular}
Chengsong
parents: 611
diff changeset
  1686
\end{center}
Chengsong
parents: 611
diff changeset
  1687
\noindent
Chengsong
parents: 611
diff changeset
  1688
The predicate $\textit{nonAlt}$ evaluates to true when the regular expression is not an
Chengsong
parents: 611
diff changeset
  1689
alternative, and false otherwise.
Chengsong
parents: 611
diff changeset
  1690
The $\good$ property is preserved under $\rsimp_{ALTS}$, provided that
Chengsong
parents: 611
diff changeset
  1691
its non-empty argument list of expressions are all good themsleves, and $\textit{nonAlt}$, 
Chengsong
parents: 611
diff changeset
  1692
and unique:
Chengsong
parents: 611
diff changeset
  1693
\begin{lemma}\label{rsimpaltsGood}
Chengsong
parents: 611
diff changeset
  1694
	If $rs \neq []$ and forall $r \in rs. \textit{nonAlt} \; r$ and $\textit{isDistinct} \; rs$,
Chengsong
parents: 611
diff changeset
  1695
	then $\good \; (\rsimpalts \; rs)$ if and only if forall $r \in rs. \; \good \; r$.
Chengsong
parents: 611
diff changeset
  1696
\end{lemma}
Chengsong
parents: 611
diff changeset
  1697
\noindent
Chengsong
parents: 611
diff changeset
  1698
We also note that
Chengsong
parents: 611
diff changeset
  1699
if a regular expression $r$ is good, then $\rflts$ on the singleton
Chengsong
parents: 611
diff changeset
  1700
list $[r]$ will not break goodness:
Chengsong
parents: 611
diff changeset
  1701
\begin{lemma}\label{flts2}
Chengsong
parents: 611
diff changeset
  1702
	If $\good \; r$, then forall $r' \in \rflts \; [r]. \; \good \; r'$ and $\textit{nonAlt} \; r'$.
Chengsong
parents: 611
diff changeset
  1703
\end{lemma}
Chengsong
parents: 611
diff changeset
  1704
\begin{proof}
Chengsong
parents: 611
diff changeset
  1705
	By an induction on $r$.
Chengsong
parents: 611
diff changeset
  1706
\end{proof}
Chengsong
parents: 611
diff changeset
  1707
\noindent
Chengsong
parents: 611
diff changeset
  1708
The other observation we make about $\rsimp{r}$ is that it never
Chengsong
parents: 611
diff changeset
  1709
comes with nested alternatives, which we describe as the $\nonnested$
Chengsong
parents: 611
diff changeset
  1710
property:
Chengsong
parents: 611
diff changeset
  1711
\begin{center}
Chengsong
parents: 611
diff changeset
  1712
	\begin{tabular}{lcl}
Chengsong
parents: 611
diff changeset
  1713
		$\nonnested \; \, \sum []$ & $\dn$ & $\btrue$\\
Chengsong
parents: 611
diff changeset
  1714
		$\nonnested \; \, \sum ((\sum rs_1) :: rs_2)$ & $\dn$ & $\bfalse$\\
Chengsong
parents: 611
diff changeset
  1715
		$\nonnested \; \, \sum (r :: rs)$ & $\dn$ & $\nonnested (\sum rs)$\\
Chengsong
parents: 611
diff changeset
  1716
		$\nonnested \; \, r $ & $\dn$ & $\btrue$
Chengsong
parents: 611
diff changeset
  1717
	\end{tabular}
Chengsong
parents: 611
diff changeset
  1718
\end{center}
Chengsong
parents: 611
diff changeset
  1719
\noindent
Chengsong
parents: 611
diff changeset
  1720
The $\rflts$ function
Chengsong
parents: 611
diff changeset
  1721
always opens up nested alternatives,
Chengsong
parents: 611
diff changeset
  1722
which enables $\rsimp$ to be non-nested:
Chengsong
parents: 611
diff changeset
  1723
Chengsong
parents: 611
diff changeset
  1724
\begin{lemma}\label{nonnestedRsimp}
Chengsong
parents: 611
diff changeset
  1725
	$\nonnested \; (\rsimp{r})$
Chengsong
parents: 611
diff changeset
  1726
\end{lemma}
Chengsong
parents: 611
diff changeset
  1727
\begin{proof}
Chengsong
parents: 611
diff changeset
  1728
	By an induction on $r$.
Chengsong
parents: 611
diff changeset
  1729
\end{proof}
Chengsong
parents: 611
diff changeset
  1730
\noindent
Chengsong
parents: 611
diff changeset
  1731
With this we could prove that a regular expressions
Chengsong
parents: 611
diff changeset
  1732
after simplification and flattening and de-duplication,
Chengsong
parents: 611
diff changeset
  1733
will not contain any alternative regular expression directly:
Chengsong
parents: 611
diff changeset
  1734
\begin{lemma}\label{nonaltFltsRd}
Chengsong
parents: 611
diff changeset
  1735
	If $x \in \rdistinct{\rflts\; (\map \; \rsimp{} \; rs)}{\varnothing}$ 
Chengsong
parents: 611
diff changeset
  1736
	then $\textit{nonAlt} \; x$.
Chengsong
parents: 611
diff changeset
  1737
\end{lemma}
Chengsong
parents: 611
diff changeset
  1738
\begin{proof}
Chengsong
parents: 611
diff changeset
  1739
	By \ref{nonnestedRsimp}.
Chengsong
parents: 611
diff changeset
  1740
\end{proof}
Chengsong
parents: 611
diff changeset
  1741
\noindent
Chengsong
parents: 611
diff changeset
  1742
The other thing we know is that once $\rsimp{}$ had finished
Chengsong
parents: 611
diff changeset
  1743
processing an alternative regular expression, it will not
Chengsong
parents: 611
diff changeset
  1744
contain any $\RZERO$s, this is because all the recursive 
Chengsong
parents: 611
diff changeset
  1745
calls to the simplification on the children regular expressions
Chengsong
parents: 611
diff changeset
  1746
make the children good, and $\rflts$ will not take out
Chengsong
parents: 611
diff changeset
  1747
any $\RZERO$s out of a good regular expression list,
Chengsong
parents: 611
diff changeset
  1748
and $\rdistinct{}$ will not mess with the result.
Chengsong
parents: 611
diff changeset
  1749
\begin{lemma}\label{flts3Obv}
Chengsong
parents: 611
diff changeset
  1750
	The following are true:
Chengsong
parents: 611
diff changeset
  1751
	\begin{itemize}
Chengsong
parents: 611
diff changeset
  1752
		\item
Chengsong
parents: 611
diff changeset
  1753
			If for all $r \in rs. \, \good \; r $ or $r = \RZERO$,
Chengsong
parents: 611
diff changeset
  1754
			then for all $r \in \rflts\; rs. \, \good \; r$.
Chengsong
parents: 611
diff changeset
  1755
		\item
Chengsong
parents: 611
diff changeset
  1756
			If $x \in \rdistinct{\rflts\; (\map \; rsimp{}\; rs)}{\varnothing}$
Chengsong
parents: 611
diff changeset
  1757
			and for all $y$ such that $\llbracket y \rrbracket_r$ less than
Chengsong
parents: 611
diff changeset
  1758
			$\llbracket rs \rrbracket_r + 1$, either
Chengsong
parents: 611
diff changeset
  1759
			$\good \; (\rsimp{y})$ or $\rsimp{y} = \RZERO$,
Chengsong
parents: 611
diff changeset
  1760
			then $\good \; x$.
Chengsong
parents: 611
diff changeset
  1761
	\end{itemize}
Chengsong
parents: 611
diff changeset
  1762
\end{lemma}
Chengsong
parents: 611
diff changeset
  1763
\begin{proof}
Chengsong
parents: 611
diff changeset
  1764
	The first part is by induction on $rs$, where the induction
Chengsong
parents: 611
diff changeset
  1765
	rule is the inductive cases for $\rflts$.
Chengsong
parents: 611
diff changeset
  1766
	The second part is a corollary from the first part.
Chengsong
parents: 611
diff changeset
  1767
\end{proof}
Chengsong
parents: 611
diff changeset
  1768
Chengsong
parents: 611
diff changeset
  1769
And this leads to good structural property of $\rsimp{}$,
Chengsong
parents: 611
diff changeset
  1770
that after simplification, a regular expression is
Chengsong
parents: 611
diff changeset
  1771
either good or $\RZERO$:
Chengsong
parents: 611
diff changeset
  1772
\begin{lemma}\label{good1}
Chengsong
parents: 611
diff changeset
  1773
	For any r-regular expression $r$, $\good \; \rsimp{r}$ or $\rsimp{r} = \RZERO$.
Chengsong
parents: 611
diff changeset
  1774
\end{lemma}
Chengsong
parents: 611
diff changeset
  1775
\begin{proof}
Chengsong
parents: 611
diff changeset
  1776
	By an induction on $r$. The inductive measure is the size $\llbracket \rrbracket_r$.
Chengsong
parents: 611
diff changeset
  1777
	Lemma \ref{rsimpSize} says that 
Chengsong
parents: 611
diff changeset
  1778
	$\llbracket \rsimp{r}\rrbracket_r$ is smaller than or equal to
Chengsong
parents: 611
diff changeset
  1779
	$\llbracket r \rrbracket_r$.
Chengsong
parents: 611
diff changeset
  1780
	Therefore, in the $r_1 \cdot r_2$ and $\sum rs$ case,
Chengsong
parents: 611
diff changeset
  1781
	Inductive hypothesis applies to the children regular expressions
Chengsong
parents: 611
diff changeset
  1782
	$r_1$, $r_2$, etc. The lemma \ref{flts3Obv}'s precondition is satisfied
Chengsong
parents: 611
diff changeset
  1783
	by that as well.
Chengsong
parents: 611
diff changeset
  1784
	The lemmas \ref{nonnestedRsimp} and  \ref{nonaltFltsRd} are used
Chengsong
parents: 611
diff changeset
  1785
	to ensure that goodness is preserved at the topmost level.
Chengsong
parents: 611
diff changeset
  1786
\end{proof}
Chengsong
parents: 611
diff changeset
  1787
We shall prove that any good regular expression is 
Chengsong
parents: 611
diff changeset
  1788
a fixed-point for $\rsimp{}$.
Chengsong
parents: 611
diff changeset
  1789
First we prove an auxiliary lemma:
Chengsong
parents: 611
diff changeset
  1790
\begin{lemma}\label{goodaltsNonalt}
Chengsong
parents: 611
diff changeset
  1791
	If $\good \; \sum rs$, then $\rflts\; rs = rs$.
Chengsong
parents: 611
diff changeset
  1792
\end{lemma}
Chengsong
parents: 611
diff changeset
  1793
\begin{proof}
Chengsong
parents: 611
diff changeset
  1794
	By an induction on $\sum rs$. The inductive rules are the cases
Chengsong
parents: 611
diff changeset
  1795
	for $\good$.
Chengsong
parents: 611
diff changeset
  1796
\end{proof}
Chengsong
parents: 611
diff changeset
  1797
\noindent
Chengsong
parents: 611
diff changeset
  1798
Now we are ready to prove that good regular expressions are invariant
Chengsong
parents: 611
diff changeset
  1799
of $\rsimp{}$ application:
Chengsong
parents: 611
diff changeset
  1800
\begin{lemma}\label{test}
Chengsong
parents: 611
diff changeset
  1801
	If $\good \;r$ then $\rsimp{r} = r$.
Chengsong
parents: 611
diff changeset
  1802
\end{lemma}
Chengsong
parents: 611
diff changeset
  1803
\begin{proof}
Chengsong
parents: 611
diff changeset
  1804
	By an induction on the inductive cases of $\good$, using lemmas
Chengsong
parents: 611
diff changeset
  1805
	\ref{goodaltsNonalt} and \ref{rdistinctOnDistinct}.
Chengsong
parents: 611
diff changeset
  1806
	The lemma \ref{goodaltsNonalt} is used in the alternative
Chengsong
parents: 611
diff changeset
  1807
	case where 2 or more elements are present in the list.
Chengsong
parents: 611
diff changeset
  1808
\end{proof}
Chengsong
parents: 611
diff changeset
  1809
\noindent
Chengsong
parents: 611
diff changeset
  1810
Given below is a property involving $\rflts$, $\rdistinct{}{}$, $\rsimp{}$ and $\rsimp_{ALTS}$,
Chengsong
parents: 611
diff changeset
  1811
which requires $\ref{good1}$ to go through smoothly.
Chengsong
parents: 611
diff changeset
  1812
It says that an application of $\rsimp_{ALTS}$ can be "absorbed",
Chengsong
parents: 611
diff changeset
  1813
if it its output is concatenated with a list and then applied to $\rflts$.
Chengsong
parents: 611
diff changeset
  1814
\begin{lemma}\label{flattenRsimpalts}
Chengsong
parents: 611
diff changeset
  1815
	$\rflts \; ( (\rsimp_{ALTS} \; 
Chengsong
parents: 611
diff changeset
  1816
	(\rdistinct{(\rflts \; (\map \; \rsimp{}\; rs))}{\varnothing})) :: 
Chengsong
parents: 611
diff changeset
  1817
	\map \; \rsimp{} \; rs' ) = 
Chengsong
parents: 611
diff changeset
  1818
	\rflts \; ( (\rdistinct{(\rflts \; (\map \; \rsimp{}\; rs))}{\varnothing}) @ (
Chengsong
parents: 611
diff changeset
  1819
	\map \; \rsimp{rs'}))$
Chengsong
parents: 611
diff changeset
  1820
Chengsong
parents: 611
diff changeset
  1821
Chengsong
parents: 611
diff changeset
  1822
\end{lemma}
Chengsong
parents: 611
diff changeset
  1823
\begin{proof}
Chengsong
parents: 611
diff changeset
  1824
	By \ref{good1}.
Chengsong
parents: 611
diff changeset
  1825
\end{proof}
Chengsong
parents: 611
diff changeset
  1826
\noindent
Chengsong
parents: 611
diff changeset
  1827
Chengsong
parents: 611
diff changeset
  1828
Chengsong
parents: 611
diff changeset
  1829
Chengsong
parents: 611
diff changeset
  1830
Chengsong
parents: 611
diff changeset
  1831
Chengsong
parents: 611
diff changeset
  1832
We are also ready to prove that $\textit{rsimp}$ is idempotent.
Chengsong
parents: 611
diff changeset
  1833
\subsubsection{$\rsimp$ is Idempotent}
Chengsong
parents: 611
diff changeset
  1834
The idempotency of $\rsimp$ is very useful in 
Chengsong
parents: 611
diff changeset
  1835
manipulating regular expression terms into desired
Chengsong
parents: 611
diff changeset
  1836
forms so that key steps allowing further rewriting to closed forms
Chengsong
parents: 611
diff changeset
  1837
are possible.
Chengsong
parents: 611
diff changeset
  1838
\begin{lemma}\label{rsimpIdem}
Chengsong
parents: 611
diff changeset
  1839
	$\rsimp{r} = \rsimp{\rsimp{r}}$
Chengsong
parents: 611
diff changeset
  1840
\end{lemma}
Chengsong
parents: 611
diff changeset
  1841
Chengsong
parents: 611
diff changeset
  1842
\begin{proof}
Chengsong
parents: 611
diff changeset
  1843
	By \ref{test} and \ref{good1}.
Chengsong
parents: 611
diff changeset
  1844
\end{proof}
Chengsong
parents: 611
diff changeset
  1845
\noindent
Chengsong
parents: 611
diff changeset
  1846
This property means we do not have to repeatedly
Chengsong
parents: 611
diff changeset
  1847
apply simplification in each step, which justifies
Chengsong
parents: 611
diff changeset
  1848
our definition of $\blexersimp$.
Chengsong
parents: 611
diff changeset
  1849
Chengsong
parents: 611
diff changeset
  1850
Chengsong
parents: 611
diff changeset
  1851
On the other hand, we could repeat the same $\rsimp{}$ applications
Chengsong
parents: 611
diff changeset
  1852
on regular expressions as many times as we want, if we have at least
Chengsong
parents: 611
diff changeset
  1853
one simplification applied to it, and apply it wherever we would like to:
Chengsong
parents: 611
diff changeset
  1854
\begin{corollary}\label{headOneMoreSimp}
Chengsong
parents: 611
diff changeset
  1855
	The following properties hold, directly from \ref{rsimpIdem}:
Chengsong
parents: 611
diff changeset
  1856
Chengsong
parents: 611
diff changeset
  1857
	\begin{itemize}
Chengsong
parents: 611
diff changeset
  1858
		\item
Chengsong
parents: 611
diff changeset
  1859
			$\map \; \rsimp{(r :: rs)} = \map \; \rsimp{} \; (\rsimp{r} :: rs)$
Chengsong
parents: 611
diff changeset
  1860
		\item
Chengsong
parents: 611
diff changeset
  1861
			$\rsimp{(\RALTS{rs})} = \rsimp{(\RALTS{\map \; \rsimp{} \; rs})}$
Chengsong
parents: 611
diff changeset
  1862
	\end{itemize}
Chengsong
parents: 611
diff changeset
  1863
\end{corollary}
Chengsong
parents: 611
diff changeset
  1864
\noindent
Chengsong
parents: 611
diff changeset
  1865
This will be useful in later closed form proof's rewriting steps.
Chengsong
parents: 611
diff changeset
  1866
Similarly, we point out the following useful facts below:
Chengsong
parents: 611
diff changeset
  1867
\begin{lemma}
Chengsong
parents: 611
diff changeset
  1868
	The following equalities hold if $r = \rsimp{r'}$ for some $r'$:
Chengsong
parents: 611
diff changeset
  1869
	\begin{itemize}
Chengsong
parents: 611
diff changeset
  1870
		\item
Chengsong
parents: 611
diff changeset
  1871
			If $r  = \sum rs$ then $\rsimpalts \; rs = \sum rs$.
Chengsong
parents: 611
diff changeset
  1872
		\item
Chengsong
parents: 611
diff changeset
  1873
			If $r = \sum rs$ then $\rdistinct{rs}{\varnothing} = rs$.
Chengsong
parents: 611
diff changeset
  1874
		\item
Chengsong
parents: 611
diff changeset
  1875
			$\rsimpalts \; (\rdistinct{\rflts \; [r]}{\varnothing}) = r$.
Chengsong
parents: 611
diff changeset
  1876
	\end{itemize}
Chengsong
parents: 611
diff changeset
  1877
\end{lemma}
Chengsong
parents: 611
diff changeset
  1878
\begin{proof}
Chengsong
parents: 611
diff changeset
  1879
	By application of lemmas \ref{rsimpIdem} and \ref{good1}.
Chengsong
parents: 611
diff changeset
  1880
\end{proof}
Chengsong
parents: 611
diff changeset
  1881
Chengsong
parents: 611
diff changeset
  1882
\noindent
Chengsong
parents: 611
diff changeset
  1883
With the idempotency of $\rsimp{}$ and its corollaries, 
Chengsong
parents: 611
diff changeset
  1884
we can start proving some key equalities leading to the 
Chengsong
parents: 611
diff changeset
  1885
closed forms.
Chengsong
parents: 611
diff changeset
  1886
Now presented are a few equivalent terms under $\rsimp{}$.
Chengsong
parents: 611
diff changeset
  1887
We use $r_1 \sequal r_2 $ here to denote $\rsimp{r_1} = \rsimp{r_2}$.
Chengsong
parents: 611
diff changeset
  1888
\begin{lemma}
Chengsong
parents: 611
diff changeset
  1889
	\begin{itemize}
Chengsong
parents: 611
diff changeset
  1890
		The following equivalence hold:
Chengsong
parents: 611
diff changeset
  1891
	\item
Chengsong
parents: 611
diff changeset
  1892
		$\rsimpalts \; (\RZERO :: rs) \sequal \rsimpalts\; rs$
Chengsong
parents: 611
diff changeset
  1893
	\item
Chengsong
parents: 611
diff changeset
  1894
		$\rsimpalts \; rs \sequal \rsimpalts (\map \; \rsimp{} \; rs)$
Chengsong
parents: 611
diff changeset
  1895
	\item
Chengsong
parents: 611
diff changeset
  1896
		$\RALTS{\RALTS{rs}} \sequal \RALTS{rs}$
Chengsong
parents: 611
diff changeset
  1897
	\item
Chengsong
parents: 611
diff changeset
  1898
		$\sum ((\sum rs_a) :: rs_b) \sequal \sum rs_a @ rs_b$
Chengsong
parents: 611
diff changeset
  1899
	\item
Chengsong
parents: 611
diff changeset
  1900
		$\RALTS{rs} = \RALTS{\map \; \rsimp{} \; rs}$
Chengsong
parents: 611
diff changeset
  1901
\end{itemize}
Chengsong
parents: 611
diff changeset
  1902
\end{lemma}
Chengsong
parents: 611
diff changeset
  1903
\begin{proof}
Chengsong
parents: 611
diff changeset
  1904
	By induction on the lists involved.
Chengsong
parents: 611
diff changeset
  1905
\end{proof}
Chengsong
parents: 611
diff changeset
  1906
\noindent
Chengsong
parents: 611
diff changeset
  1907
The above allows us to prove
Chengsong
parents: 611
diff changeset
  1908
two similar equalities (which are a bit more involved).
Chengsong
parents: 611
diff changeset
  1909
It says that we could flatten out the elements
Chengsong
parents: 611
diff changeset
  1910
before simplification and still get the same result.
Chengsong
parents: 611
diff changeset
  1911
\begin{lemma}\label{simpFlatten3}
Chengsong
parents: 611
diff changeset
  1912
	One can flatten the inside $\sum$ of a $\sum$ if it is being 
Chengsong
parents: 611
diff changeset
  1913
	simplified. Concretely,
Chengsong
parents: 611
diff changeset
  1914
	\begin{itemize}
Chengsong
parents: 611
diff changeset
  1915
		\item
Chengsong
parents: 611
diff changeset
  1916
			If for all $r \in rs, rs', rs''$, we have $\good \; r $
Chengsong
parents: 611
diff changeset
  1917
			or $r = \RZERO$, then $\sum (rs' @ rs @ rs'') \sequal 
Chengsong
parents: 611
diff changeset
  1918
			\sum (rs' @ [\sum rs] @ rs'')$ holds. As a corollary,
Chengsong
parents: 611
diff changeset
  1919
		\item
Chengsong
parents: 611
diff changeset
  1920
			$\sum (rs' @ [\sum rs] @ rs'') \sequal \sum (rs' @ rs @ rs'')$
Chengsong
parents: 611
diff changeset
  1921
	\end{itemize}
Chengsong
parents: 611
diff changeset
  1922
\end{lemma}
Chengsong
parents: 611
diff changeset
  1923
\begin{proof}
Chengsong
parents: 611
diff changeset
  1924
	By rewriting steps involving the use of \ref{test} and \ref{rdistinctConcatGeneral}.
Chengsong
parents: 611
diff changeset
  1925
	The second sub-lemma is a corollary of the previous.
Chengsong
parents: 611
diff changeset
  1926
\end{proof}
Chengsong
parents: 611
diff changeset
  1927
%Rewriting steps not put in--too long and complicated-------------------------------
Chengsong
parents: 611
diff changeset
  1928
\begin{comment}
Chengsong
parents: 611
diff changeset
  1929
	\begin{center}
Chengsong
parents: 611
diff changeset
  1930
		$\rsimp{\sum (rs' @ rs @ rs'')}  \stackrel{def of bsimp}{=}$  \\
Chengsong
parents: 611
diff changeset
  1931
		$\rsimpalts \; (\rdistinct{\rflts \; ((\map \; \rsimp{}\; rs') @ (\map \; \rsimp{} \; rs ) @ (\map \; \rsimp{} \; rs''))}{\varnothing})$ \\
Chengsong
parents: 611
diff changeset
  1932
		$\stackrel{by \ref{test}}{=} 
Chengsong
parents: 611
diff changeset
  1933
		\rsimpalts \; (\rdistinct{(\rflts \; rs' @ \rflts \; rs @ \rflts \; rs'')}{
Chengsong
parents: 611
diff changeset
  1934
		\varnothing})$\\
Chengsong
parents: 611
diff changeset
  1935
		$\stackrel{by \ref{rdistinctConcatGeneral}}{=}
Chengsong
parents: 611
diff changeset
  1936
		\rsimpalts \; (\rdistinct{\rflts \; rs'}{\varnothing} @ \rdistinct{(
Chengsong
parents: 611
diff changeset
  1937
		\rflts\; rs @ \rflts \; rs'')}{\rflts \; rs'})$\\
Chengsong
parents: 611
diff changeset
  1938
Chengsong
parents: 611
diff changeset
  1939
	\end{center}
Chengsong
parents: 611
diff changeset
  1940
\end{comment}
Chengsong
parents: 611
diff changeset
  1941
%Rewriting steps not put in--too long and complicated-------------------------------
Chengsong
parents: 611
diff changeset
  1942
\noindent
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  1943
\subsection{Estimating the Closed Forms' sizes}
558
Chengsong
parents: 557
diff changeset
  1944
We now summarize the closed forms below:
Chengsong
parents: 557
diff changeset
  1945
\begin{itemize}
Chengsong
parents: 557
diff changeset
  1946
	\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1947
		$\rderssimp{(\sum rs)}{s} \sequal
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1948
		\sum \; (\map \; (\rderssimp{\_}{s}) \; rs)$
558
Chengsong
parents: 557
diff changeset
  1949
	\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1950
		$\rderssimp{(r_1 \cdot r_2)}{s} \sequal \sum ((r_1 \backslash s) \cdot r_2 ) 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1951
		:: (\map \; (r_2 \backslash \_) (\vsuf{s}{r_1}))$
558
Chengsong
parents: 557
diff changeset
  1952
	\item
Chengsong
parents: 557
diff changeset
  1953
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1954
		$\rderssimp{r^*}{c::s} = 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1955
		\rsimp{
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1956
			(\sum (\map \; (\lambda s. (\rderssimp{r}{s})\cdot r^*) \; 
558
Chengsong
parents: 557
diff changeset
  1957
			(\starupdates \; s\; r \; [[c]])
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1958
			)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1959
			)
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1960
		}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1961
		$
558
Chengsong
parents: 557
diff changeset
  1962
\end{itemize}	
Chengsong
parents: 557
diff changeset
  1963
\noindent	
Chengsong
parents: 557
diff changeset
  1964
The closed forms on the left-hand-side
Chengsong
parents: 557
diff changeset
  1965
are all of the same shape: $\rsimp{ (\sum rs)} $.
Chengsong
parents: 557
diff changeset
  1966
Such regular expression will be bounded by the size of $\sum rs'$, 
Chengsong
parents: 557
diff changeset
  1967
where every element in $rs'$ is distinct, and each element 
Chengsong
parents: 557
diff changeset
  1968
can be described by some inductive sub-structures 
Chengsong
parents: 557
diff changeset
  1969
(for example when $r = r_1 \cdot r_2$ then $rs'$ 
Chengsong
parents: 557
diff changeset
  1970
will be solely comprised of $r_1 \backslash s'$ 
Chengsong
parents: 557
diff changeset
  1971
and $r_2 \backslash s''$, $s'$ and $s''$ being 
Chengsong
parents: 557
diff changeset
  1972
sub-strings of $s$).
Chengsong
parents: 557
diff changeset
  1973
which will each have a size uppder bound 
Chengsong
parents: 557
diff changeset
  1974
according to inductive hypothesis, which controls $r \backslash s$.
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  1975
558
Chengsong
parents: 557
diff changeset
  1976
We elaborate the above reasoning by a series of lemmas
Chengsong
parents: 557
diff changeset
  1977
below, where straightforward proofs are omitted.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  1978
\begin{lemma}
558
Chengsong
parents: 557
diff changeset
  1979
	If $\forall r \in rs. \rsize{r} $ is less than or equal to $N$,
Chengsong
parents: 557
diff changeset
  1980
	and $\textit{length} \; rs$ is less than or equal to $l$,
Chengsong
parents: 557
diff changeset
  1981
	then $\rsize{\sum rs}$ is less than or equal to $l*N + 1$.
Chengsong
parents: 557
diff changeset
  1982
\end{lemma}
Chengsong
parents: 557
diff changeset
  1983
\noindent
Chengsong
parents: 557
diff changeset
  1984
If we define all regular expressions with size no
Chengsong
parents: 557
diff changeset
  1985
more than $N$ as $\sizeNregex \; N$:
Chengsong
parents: 557
diff changeset
  1986
\[
Chengsong
parents: 557
diff changeset
  1987
	\sizeNregex \; N \dn  \{r \mid \rsize{r} \leq N \}
Chengsong
parents: 557
diff changeset
  1988
\]
Chengsong
parents: 557
diff changeset
  1989
Then such set is finite:
Chengsong
parents: 557
diff changeset
  1990
\begin{lemma}\label{finiteSizeN}
Chengsong
parents: 557
diff changeset
  1991
	$\textit{isFinite}\; (\sizeNregex \; N)$
Chengsong
parents: 557
diff changeset
  1992
\end{lemma}
Chengsong
parents: 557
diff changeset
  1993
\begin{proof}
Chengsong
parents: 557
diff changeset
  1994
	By overestimating the set $\sizeNregex \; N + 1$
Chengsong
parents: 557
diff changeset
  1995
	using union of sets like
Chengsong
parents: 557
diff changeset
  1996
	$\{r_1 \cdot r_2 \mid r_1 \in A
Chengsong
parents: 557
diff changeset
  1997
		\text{and}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  1998
	r_2 \in A\}
558
Chengsong
parents: 557
diff changeset
  1999
	$ where $A = \sizeNregex \; N$.
Chengsong
parents: 557
diff changeset
  2000
\end{proof}
Chengsong
parents: 557
diff changeset
  2001
\noindent
Chengsong
parents: 557
diff changeset
  2002
From this we get a corollary that
Chengsong
parents: 557
diff changeset
  2003
if forall $r \in rs$, $\rsize{r} \leq N$, then the output of 
Chengsong
parents: 557
diff changeset
  2004
$\rdistinct{rs}{\varnothing}$ is a list of regular
Chengsong
parents: 557
diff changeset
  2005
expressions of finite size depending on $N$ only. 
561
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  2006
\begin{corollary}\label{finiteSizeNCorollary}
558
Chengsong
parents: 557
diff changeset
  2007
	Assumes that for all $r \in rs. \rsize{r} \leq N$,
Chengsong
parents: 557
diff changeset
  2008
	and the cardinality of $\sizeNregex \; N$ is $c_N$
Chengsong
parents: 557
diff changeset
  2009
	then$\rsize{\rdistinct{rs}{\varnothing}} \leq c*N$.
Chengsong
parents: 557
diff changeset
  2010
\end{corollary}
Chengsong
parents: 557
diff changeset
  2011
\noindent
Chengsong
parents: 557
diff changeset
  2012
We have proven that the output of $\rdistinct{rs'}{\varnothing}$
Chengsong
parents: 557
diff changeset
  2013
is bounded by a constant $c_N$ depending only on $N$,
Chengsong
parents: 557
diff changeset
  2014
provided that each of $rs'$'s element
Chengsong
parents: 557
diff changeset
  2015
is bounded by $N$.
Chengsong
parents: 557
diff changeset
  2016
We want to apply it to our setting $\rsize{\rsimp{\sum rs}}$.
Chengsong
parents: 557
diff changeset
  2017
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2018
We show that $\rdistinct$ and $\rflts$
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2019
working together is at least as 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2020
good as $\rdistinct{}{}$ alone, which can be written as
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2021
\begin{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2022
	$\llbracket \rdistinct{(\rflts \; \textit{rs})}{\varnothing} \rrbracket_r 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2023
	\leq 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2024
	\llbracket \rdistinct{rs}{\varnothing}  \rrbracket_r  $.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2025
\end{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2026
We need this so that we know the outcome of our real 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2027
simplification is better than or equal to a rough estimate,
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2028
and therefore can be bounded by that estimate.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2029
This is a bit harder to establish compared with proving
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2030
$\textit{flts}$ does not make a list larger (which can
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2031
be proven using routine induction):
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2032
\begin{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2033
	$\llbracket  \textit{rflts}\; rs \rrbracket_r \leq
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2034
	\llbracket  \textit{rs} \rrbracket_r$
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2035
\end{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2036
We cannot simply prove how each helper function
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2037
reduces the size and then put them together:
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2038
From
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2039
\begin{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2040
$\llbracket  \textit{rflts}\; rs \rrbracket_r \leq
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2041
	\llbracket \; \textit{rs} \rrbracket_r$
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2042
\end{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2043
and
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2044
\begin{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2045
     $\llbracket  \textit{rdistinct} \; rs \; \varnothing \leq
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2046
     \llbracket rs \rrbracket_r$
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2047
\end{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2048
one cannot imply
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2049
\begin{center}
558
Chengsong
parents: 557
diff changeset
  2050
	$\llbracket \rdistinct{(\rflts \; \textit{rs})}{\varnothing} \rrbracket_r 
Chengsong
parents: 557
diff changeset
  2051
	\leq 
Chengsong
parents: 557
diff changeset
  2052
	\llbracket \rdistinct{rs}{\varnothing}  \rrbracket_r  $.
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2053
\end{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2054
What we can imply is that 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2055
\begin{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2056
	$\llbracket \rdistinct{(\rflts \; \textit{rs})}{\varnothing} \rrbracket_r 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2057
	\leq
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2058
	\llbracket rs \rrbracket_r$
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2059
\end{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2060
but this estimate is too rough and $\llbracket rs \rrbracket_r$	is unbounded.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2061
The way we 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2062
get through this is by first proving a more general lemma 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2063
(so that the inductive case goes through):
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2064
\begin{lemma}\label{fltsSizeReductionAlts}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2065
	If we have three accumulator sets:
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2066
	$noalts\_set$, $alts\_set$ and $corr\_set$,
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2067
	satisfying:
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2068
	\begin{itemize}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2069
		\item
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2070
			$\forall r \in noalts\_set. \; \nexists xs.\; r = \sum  xs$
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2071
		\item
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2072
			$\forall r \in alts\_set. \; \exists xs. \; r = \sum xs
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2073
			\; \textit{and} \; set \; xs \subseteq corr\_set$
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2074
	\end{itemize}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2075
	then we have that
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2076
	\begin{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2077
	\begin{tabular}{lcl}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2078
	$\llbracket  (\textit{rdistinct} \; (\textit{rflts} \; as) \;
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2079
	(noalts\_set \cup corr\_set)) \rrbracket_r$ & $\leq$ &\\
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2080
						    $\llbracket  (\textit{rdistinct} \; as \; (noalts\_set \cup alts\_set \cup
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2081
	\{ \ZERO \} )) \rrbracket_r$ & & \\ 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2082
	\end{tabular}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2083
	\end{center}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2084
		holds.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2085
\end{lemma}
558
Chengsong
parents: 557
diff changeset
  2086
\noindent
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2087
We need to split the accumulator into two parts: the part
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2088
which contains alternative regular expressions ($alts\_set$), and 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2089
the part without any of them($noalts\_set$).
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2090
The set $corr\_set$ is the corresponding set
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2091
of $alts\_set$ with all elements under the $\sum$ constructor
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2092
spilled out.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2093
\begin{proof}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2094
	By induction on the list $as$. We make use of lemma \ref{rdistinctConcat}.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2095
\end{proof}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2096
By setting all three sets to the empty set, one gets the desired size estimate:
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2097
\begin{corollary}\label{interactionFltsDB}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2098
	$\llbracket \rdistinct{(\rflts \; \textit{rs})}{\varnothing} \rrbracket_r 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2099
	\leq 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2100
	\llbracket \rdistinct{rs}{\varnothing}  \rrbracket_r  $.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2101
\end{corollary}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2102
\begin{proof}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2103
	By using the lemma \ref{fltsSizeReductionAlts}.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2104
\end{proof}
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2105
\noindent
558
Chengsong
parents: 557
diff changeset
  2106
The intuition is that if we remove duplicates from the $\textit{LHS}$, at least the same amount of 
Chengsong
parents: 557
diff changeset
  2107
duplicates will be removed from the list $\textit{rs}$ in the $\textit{RHS}$. 
Chengsong
parents: 557
diff changeset
  2108
Chengsong
parents: 557
diff changeset
  2109
Now this $\rsimp{\sum rs}$ can be estimated using $\rdistinct{rs}{\varnothing}$:
Chengsong
parents: 557
diff changeset
  2110
\begin{lemma}\label{altsSimpControl}
Chengsong
parents: 557
diff changeset
  2111
	$\rsize{\rsimp{\sum rs}} \leq \rsize{\rdistinct{rs}{\varnothing}}+ 1$
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2112
\end{lemma}
558
Chengsong
parents: 557
diff changeset
  2113
\begin{proof}
Chengsong
parents: 557
diff changeset
  2114
	By using \ref{interactionFltsDB}.
Chengsong
parents: 557
diff changeset
  2115
\end{proof}
Chengsong
parents: 557
diff changeset
  2116
\noindent
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2117
This is a key lemma in establishing the bounds on all the 
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2118
closed forms.
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2119
With this we are now ready to control the sizes of
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2120
$(r_1 \cdot r_2 )\backslash s$, $r^* \backslash s$.
558
Chengsong
parents: 557
diff changeset
  2121
\begin{theorem}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2122
	For any regex $r$, $\exists N_r. \forall s. \; \rsize{\rderssimp{r}{s}} \leq N_r$
558
Chengsong
parents: 557
diff changeset
  2123
\end{theorem}
Chengsong
parents: 557
diff changeset
  2124
\noindent
Chengsong
parents: 557
diff changeset
  2125
\begin{proof}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2126
	We prove this by induction on $r$. The base cases for $\RZERO$,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2127
	$\RONE $ and $\RCHAR{c}$ are straightforward. 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2128
	In the sequence $r_1 \cdot r_2$ case,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2129
	the inductive hypotheses state 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2130
	$\exists N_1. \forall s. \; \llbracket \rderssimp{r}{s} \rrbracket \leq N_1$ and
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2131
	$\exists N_2. \forall s. \; \llbracket \rderssimp{r_2}{s} \rrbracket \leq N_2$. 
562
Chengsong
parents: 561
diff changeset
  2132
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2133
	When the string $s$ is not empty, we can reason as follows
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2134
	%
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2135
	\begin{center}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2136
		\begin{tabular}{lcll}
558
Chengsong
parents: 557
diff changeset
  2137
& & $ \llbracket   \rderssimp{r_1\cdot r_2 }{s} \rrbracket_r $\\
561
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  2138
& $ = $ & $\llbracket \rsimp{(\sum(r_1 \backslash_{rsimp} s \cdot r_2 \; \;  :: \; \; 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2139
		\map \; (r_2\backslash_{rsimp} \_)\; (\vsuf{s}{r})))} \rrbracket_r $ & (1) \\			
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2140
										     & $\leq$ & $\llbracket \rdistinct{(r_1 \backslash_{rsimp} s \cdot r_2 \; \;  :: \; \; 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2141
	\map \; (r_2\backslash_{rsimp} \_)\; (\vsuf{s}{r}))}{\varnothing} \rrbracket_r  + 1$ & (2) \\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2142
											     & $\leq$ & $2 + N_1 + \rsize{r_2} + (N_2 * (card\;(\sizeNregex \; N_2)))$ & (3)\\
558
Chengsong
parents: 557
diff changeset
  2143
\end{tabular}
Chengsong
parents: 557
diff changeset
  2144
\end{center}
561
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  2145
\noindent
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  2146
(1) is by the corollary \ref{seqEstimate1}.
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  2147
(2) is by \ref{altsSimpControl}.
486fb297ac7c more done
Chengsong
parents: 559
diff changeset
  2148
(3) is by \ref{finiteSizeNCorollary}.
562
Chengsong
parents: 561
diff changeset
  2149
Chengsong
parents: 561
diff changeset
  2150
Chengsong
parents: 561
diff changeset
  2151
Combining the cases when $s = []$ and $s \neq []$, we get (4):
Chengsong
parents: 561
diff changeset
  2152
\begin{center}
Chengsong
parents: 561
diff changeset
  2153
	\begin{tabular}{lcll}
Chengsong
parents: 561
diff changeset
  2154
		$\rsize{(r_1 \cdot r_2) \backslash_r s}$ & $\leq$ & 
Chengsong
parents: 561
diff changeset
  2155
		$max \; (2 + N_1 + 
Chengsong
parents: 561
diff changeset
  2156
		\llbracket r_2 \rrbracket_r + 
Chengsong
parents: 561
diff changeset
  2157
		N_2 * (card\; (\sizeNregex \; N_2))) \; \rsize{r_1\cdot r_2}$ & (4)
Chengsong
parents: 561
diff changeset
  2158
	\end{tabular}
Chengsong
parents: 561
diff changeset
  2159
\end{center}
558
Chengsong
parents: 557
diff changeset
  2160
562
Chengsong
parents: 561
diff changeset
  2161
We reason similarly for  $\STAR$.
Chengsong
parents: 561
diff changeset
  2162
The inductive hypothesis is
Chengsong
parents: 561
diff changeset
  2163
$\exists N. \forall s. \; \llbracket \rderssimp{r}{s} \rrbracket \leq N$.
564
Chengsong
parents: 562
diff changeset
  2164
Let $n_r = \llbracket r^* \rrbracket_r$.
562
Chengsong
parents: 561
diff changeset
  2165
When $s = c :: cs$ is not empty,
Chengsong
parents: 561
diff changeset
  2166
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2167
	\begin{tabular}{lcll}
562
Chengsong
parents: 561
diff changeset
  2168
& & $ \llbracket   \rderssimp{r^* }{c::cs} \rrbracket_r $\\
Chengsong
parents: 561
diff changeset
  2169
& $ = $ & $\llbracket \rsimp{(\sum (\map \; (\lambda s. (r \backslash_{rsimp} s) \cdot r^*) \; (\starupdates\; 
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2170
	cs \; r \; [[c]] )) )} \rrbracket_r $ & (5) \\			
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2171
					      & $\leq$ & $\llbracket 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2172
					      \rdistinct{
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2173
						      (\map \; 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2174
						      (\lambda s. (r \backslash_{rsimp} s) \cdot r^*) \; 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2175
						      (\starupdates\; cs \; r \; [[c]] )
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2176
					      )}
562
Chengsong
parents: 561
diff changeset
  2177
	{\varnothing} \rrbracket_r  + 1$ & (6) \\
Chengsong
parents: 561
diff changeset
  2178
					 & $\leq$ & $1 + (\textit{card} (\sizeNregex \; (N + n_r)))
Chengsong
parents: 561
diff changeset
  2179
	* (1 + (N + n_r)) $ & (7)\\
Chengsong
parents: 561
diff changeset
  2180
\end{tabular}
Chengsong
parents: 561
diff changeset
  2181
\end{center}
Chengsong
parents: 561
diff changeset
  2182
\noindent
Chengsong
parents: 561
diff changeset
  2183
(5) is by the lemma  \ref{starClosedForm}.
Chengsong
parents: 561
diff changeset
  2184
(6) is by \ref{altsSimpControl}.
Chengsong
parents: 561
diff changeset
  2185
(7) is by \ref{finiteSizeNCorollary}.
Chengsong
parents: 561
diff changeset
  2186
Combining with the case when $s = []$, one gets
Chengsong
parents: 561
diff changeset
  2187
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2188
	\begin{tabular}{lcll}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2189
		$\rsize{r^* \backslash_r s}$ & $\leq$ & $max \; n_r \; 1 + (\textit{card} (\sizeNregex \; (N + n_r)))
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2190
		* (1 + (N + n_r)) $ & (8)\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2191
	\end{tabular}
562
Chengsong
parents: 561
diff changeset
  2192
\end{center}
Chengsong
parents: 561
diff changeset
  2193
\noindent
Chengsong
parents: 561
diff changeset
  2194
Chengsong
parents: 561
diff changeset
  2195
The alternative case is slightly less involved.
Chengsong
parents: 561
diff changeset
  2196
The inductive hypothesis 
Chengsong
parents: 561
diff changeset
  2197
is equivalent to $\exists N. \forall r \in (\map \; (\_ \backslash_r s) \; rs). \rsize{r} \leq N$.
Chengsong
parents: 561
diff changeset
  2198
In the case when $s = c::cs$, we have 
Chengsong
parents: 561
diff changeset
  2199
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2200
	\begin{tabular}{lcll}
562
Chengsong
parents: 561
diff changeset
  2201
& & $ \llbracket   \rderssimp{\sum rs }{c::cs} \rrbracket_r $\\
Chengsong
parents: 561
diff changeset
  2202
& $ = $ & $\llbracket \rsimp{(\sum (\map \; (\_ \backslash_{rsimp} s)  \; rs) )} \rrbracket_r $ & (9) \\			
Chengsong
parents: 561
diff changeset
  2203
& $\leq$ & $\llbracket (\sum (\map \; (\_ \backslash_{rsimp} s)  \; rs) ) \rrbracket_r $  & (10) \\
Chengsong
parents: 561
diff changeset
  2204
& $\leq$ & $1 + N * (length \; rs) $ & (11)\\
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2205
	\end{tabular}
562
Chengsong
parents: 561
diff changeset
  2206
\end{center}
Chengsong
parents: 561
diff changeset
  2207
\noindent
Chengsong
parents: 561
diff changeset
  2208
(9) is by \ref{altsClosedForm}, (10) by \ref{rsimpSize} and (11) by inductive hypothesis.
Chengsong
parents: 561
diff changeset
  2209
Chengsong
parents: 561
diff changeset
  2210
Combining with the case when $s = []$, one gets
Chengsong
parents: 561
diff changeset
  2211
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2212
	\begin{tabular}{lcll}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2213
		$\rsize{\sum rs \backslash_r s}$ & $\leq$ & $max \; \rsize{\sum rs} \; 1+N*(length \; rs)$ 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2214
						 & (12)\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2215
	\end{tabular}
562
Chengsong
parents: 561
diff changeset
  2216
\end{center}
Chengsong
parents: 561
diff changeset
  2217
(4), (8), and (12) are all the inductive cases proven.
558
Chengsong
parents: 557
diff changeset
  2218
\end{proof}
Chengsong
parents: 557
diff changeset
  2219
564
Chengsong
parents: 562
diff changeset
  2220
Chengsong
parents: 562
diff changeset
  2221
\begin{corollary}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2222
	For any regex $a$, $\exists N_r. \forall s. \; \rsize{\bderssimp{a}{s}} \leq N_r$
564
Chengsong
parents: 562
diff changeset
  2223
\end{corollary}
Chengsong
parents: 562
diff changeset
  2224
\begin{proof}
Chengsong
parents: 562
diff changeset
  2225
	By \ref{sizeRelations}.
Chengsong
parents: 562
diff changeset
  2226
\end{proof}
558
Chengsong
parents: 557
diff changeset
  2227
\noindent
Chengsong
parents: 557
diff changeset
  2228
609
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2229
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2230
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2231
61139fdddae0 chap1 totally done
Chengsong
parents: 601
diff changeset
  2232
558
Chengsong
parents: 557
diff changeset
  2233
%-----------------------------------
Chengsong
parents: 557
diff changeset
  2234
%	SECTION 2
Chengsong
parents: 557
diff changeset
  2235
%-----------------------------------
Chengsong
parents: 557
diff changeset
  2236
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2237
557
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  2238
%----------------------------------------------------------------------------------------
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  2239
%	SECTION 3
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  2240
%----------------------------------------------------------------------------------------
812e5d112f49 more changes
Chengsong
parents: 556
diff changeset
  2241
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2242
554
Chengsong
parents: 553
diff changeset
  2243
\subsection{A Closed Form for the Sequence Regular Expression}
Chengsong
parents: 553
diff changeset
  2244
\noindent
Chengsong
parents: 553
diff changeset
  2245
Chengsong
parents: 553
diff changeset
  2246
Before we get to the proof that says the intermediate result of our lexer will
Chengsong
parents: 553
diff changeset
  2247
remain finitely bounded, which is an important efficiency/liveness guarantee,
Chengsong
parents: 553
diff changeset
  2248
we shall first develop a few preparatory properties and definitions to 
Chengsong
parents: 553
diff changeset
  2249
make the process of proving that a breeze.
Chengsong
parents: 553
diff changeset
  2250
Chengsong
parents: 553
diff changeset
  2251
We define rewriting relations for $\rrexp$s, which allows us to do the 
Chengsong
parents: 553
diff changeset
  2252
same trick as we did for the correctness proof,
Chengsong
parents: 553
diff changeset
  2253
but this time we will have stronger equalities established.
Chengsong
parents: 553
diff changeset
  2254
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2255
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2256
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2257
What guarantee does this bound give us?
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2258
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2259
Whatever the regex is, it will not grow indefinitely.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2260
Take our previous example $(a + aa)^*$ as an example:
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2261
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2262
	\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2263
		\begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2264
			\begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2265
				xlabel={number of $a$'s},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2266
				x label style={at={(1.05,-0.05)}},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2267
				ylabel={regex size},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2268
				enlargelimits=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2269
				xtick={0,5,...,30},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2270
				xmax=33,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2271
				ymax= 40,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2272
				ytick={0,10,...,40},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2273
				scaled ticks=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2274
				axis lines=left,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2275
				width=5cm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2276
				height=4cm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2277
				legend entries={$(a + aa)^*$},  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2278
				legend pos=north west,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2279
				legend cell align=left]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2280
				\addplot[red,mark=*, mark options={fill=white}] table {a_aa_star.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2281
			\end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2282
		\end{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2283
	\end{tabular}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2284
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2285
We are able to limit the size of the regex $(a + aa)^*$'s derivatives
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2286
with our simplification
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2287
rules very effectively.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2288
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2289
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2290
In our proof for the inductive case $r_1 \cdot r_2$, the dominant term in the bound
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2291
is $l_{N_2} * N_2$, where $N_2$ is the bound we have for $\llbracket \bderssimp{r_2}{s} \rrbracket$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2292
Given that $l_{N_2}$ is roughly the size $4^{N_2}$, the size bound $\llbracket \bderssimp{r_1 \cdot r_2}{s} \rrbracket$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2293
inflates the size bound of $\llbracket \bderssimp{r_2}{s} \rrbracket$ with the function
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2294
$f(x) = x * 2^x$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2295
This means the bound we have will surge up at least
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2296
tower-exponentially with a linear increase of the depth.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2297
For a regex of depth $n$, the bound
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2298
would be approximately $4^n$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2299
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2300
Test data in the graphs from randomly generated regular expressions
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2301
shows that the giant bounds are far from being hit.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2302
%a few sample regular experessions' derivatives
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2303
%size change
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  2304
%TODO: giving regex1_size_change.data showing a few regular expressions' size changes 
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2305
%w;r;t the input characters number, where the size is usually cubic in terms of original size
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2306
%a*, aa*, aaa*, .....
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  2307
%randomly generated regular expressions
611
Chengsong
parents: 610
diff changeset
  2308
\begin{figure}{H}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2309
	\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2310
		\begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2311
			\begin{axis}[
611
Chengsong
parents: 610
diff changeset
  2312
				xlabel={number of characters},
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2313
				x label style={at={(1.05,-0.05)}},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2314
				ylabel={regex size},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2315
				enlargelimits=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2316
				xtick={0,5,...,30},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2317
				xmax=33,
611
Chengsong
parents: 610
diff changeset
  2318
				%ymax=1000,
Chengsong
parents: 610
diff changeset
  2319
				%ytick={0,100,...,1000},
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2320
				scaled ticks=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2321
				axis lines=left,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2322
				width=5cm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2323
				height=4cm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2324
				legend entries={regex1},  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2325
				legend pos=north west,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2326
				legend cell align=left]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2327
				\addplot[red,mark=*, mark options={fill=white}] table {regex1_size_change.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2328
			\end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2329
		\end{tikzpicture}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2330
  &
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2331
  \begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2332
	  \begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2333
		  xlabel={$n$},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2334
		  x label style={at={(1.05,-0.05)}},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2335
		  %ylabel={time in secs},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2336
		  enlargelimits=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2337
		  xtick={0,5,...,30},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2338
		  xmax=33,
611
Chengsong
parents: 610
diff changeset
  2339
		  %ymax=1000,
Chengsong
parents: 610
diff changeset
  2340
		  %ytick={0,100,...,1000},
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2341
		  scaled ticks=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2342
		  axis lines=left,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2343
		  width=5cm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2344
		  height=4cm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2345
		  legend entries={regex2},  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2346
		  legend pos=north west,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2347
		  legend cell align=left]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2348
		  \addplot[blue,mark=*, mark options={fill=white}] table {regex2_size_change.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2349
	  \end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2350
  \end{tikzpicture}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2351
  &
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2352
  \begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2353
	  \begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2354
		  xlabel={$n$},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2355
		  x label style={at={(1.05,-0.05)}},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2356
		  %ylabel={time in secs},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2357
		  enlargelimits=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2358
		  xtick={0,5,...,30},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2359
		  xmax=33,
611
Chengsong
parents: 610
diff changeset
  2360
		  %ymax=1000,
Chengsong
parents: 610
diff changeset
  2361
		  %ytick={0,100,...,1000},
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2362
		  scaled ticks=false,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2363
		  axis lines=left,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2364
		  width=5cm,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2365
		  height=4cm, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2366
		  legend entries={regex3},  
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2367
		  legend pos=north west,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2368
		  legend cell align=left]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2369
		  \addplot[cyan,mark=*, mark options={fill=white}] table {regex3_size_change.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2370
	  \end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2371
  \end{tikzpicture}\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2372
  \multicolumn{3}{c}{Graphs: size change of 3 randomly generated regular expressions $w.r.t.$ input string length.}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2373
	\end{tabular}    
611
Chengsong
parents: 610
diff changeset
  2374
\end{figure}  
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2375
\noindent
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2376
Most of the regex's sizes seem to stay within a polynomial bound $w.r.t$ the 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2377
original size.
591
b2d0de6aee18 more polishing integrated comments chap2
Chengsong
parents: 590
diff changeset
  2378
We will discuss improvements to this bound in the next chapter.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2379
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2380
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2381
613
Chengsong
parents: 611
diff changeset
  2382
\section{Possible Further Improvements}
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2383
There are two problems with this finiteness result, though.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2384
\begin{itemize}
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2385
	\item
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2386
		First, It is not yet a direct formalisation of our lexer's complexity,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2387
		as a complexity proof would require looking into 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2388
		the time it takes to execute {\bf all} the operations
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2389
		involved in the lexer (simp, collect, decode), not just the derivative.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2390
	\item
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2391
		Second, the bound is not yet tight, and we seek to improve $N_a$ so that
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2392
		it is polynomial on $\llbracket a \rrbracket$.
590
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2393
\end{itemize}
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2394
Still, we believe this contribution is fruitful,
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2395
because
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2396
\begin{itemize}
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2397
	\item
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2398
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2399
		The size proof can serve as a cornerstone for a complexity
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2400
		formalisation.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2401
		Derivatives are the most important phases of our lexer algorithm.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2402
		Size properties about derivatives covers the majority of the algorithm
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2403
		and is therefore a good indication of complexity of the entire program.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2404
	\item
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2405
		The bound is already a strong indication that catastrophic
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2406
		backtracking is much less likely to occur in our $\blexersimp$
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2407
		algorithm.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2408
		We refine $\blexersimp$ with $\blexerStrong$ in the next chapter
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2409
		so that the bound becomes polynomial.
988e92a70704 more chap5 and chap6 bsimp_idem
Chengsong
parents: 577
diff changeset
  2410
\end{itemize}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2411
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2412
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2413
%	SECTION 4
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2414
%----------------------------------------------------------------------------------------
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2415
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2416
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2417
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2418
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2419
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2420
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2421
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2422
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2423
One might wonder the actual bound rather than the loose bound we gave
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2424
for the convenience of an easier proof.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2425
How much can the regex $r^* \backslash s$ grow? 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2426
As  earlier graphs have shown,
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2427
%TODO: reference that graph where size grows quickly
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2428
they can grow at a maximum speed
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2429
exponential $w.r.t$ the number of characters, 
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2430
but will eventually level off when the string $s$ is long enough.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2431
If they grow to a size exponential $w.r.t$ the original regex, our algorithm
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2432
would still be slow.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2433
And unfortunately, we have concrete examples
576
3e1b699696b6 thesis chap5
Chengsong
parents: 564
diff changeset
  2434
where such regular expressions grew exponentially large before levelling off:
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2435
$(a ^ * + (aa) ^ * + (aaa) ^ * + \ldots + 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2436
(\underbrace{a \ldots a}_{\text{n a's}})^*$ will already have a maximum
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2437
size that is  exponential on the number $n$ 
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2438
under our current simplification rules:
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2439
%TODO: graph of a regex whose size increases exponentially.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2440
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2441
	\begin{tikzpicture}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2442
		\begin{axis}[
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2443
			height=0.5\textwidth,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2444
			width=\textwidth,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2445
			xlabel=number of a's,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2446
			xtick={0,...,9},
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2447
			ylabel=maximum size,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2448
			ymode=log,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2449
			log basis y={2}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2450
			]
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2451
			\addplot[mark=*,blue] table {re-chengsong.data};
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2452
		\end{axis}
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2453
	\end{tikzpicture}
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2454
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2455
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2456
For convenience we use $(\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2457
to express $(a ^ * + (aa) ^ * + (aaa) ^ * + \ldots + 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2458
(\underbrace{a \ldots a}_{\text{n a's}})^*$ in the below discussion.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2459
The exponential size is triggered by that the regex
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2460
$\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2461
inside the $(\ldots) ^*$ having exponentially many
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2462
different derivatives, despite those difference being minor.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2463
$(\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*\backslash \underbrace{a \ldots a}_{\text{m a's}}$
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2464
will therefore contain the following terms (after flattening out all nested 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2465
alternatives):
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2466
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2467
	$(\oplus_{i = 1]{n}  (\underbrace{a \ldots a}_{\text{((i - (m' \% i))\%i) a's}})\cdot  (\underbrace{a \ldots a}_{\text{i a's}})^* })\cdot (\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)$\\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2468
	$(1 \leq m' \leq m )$
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2469
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2470
These terms are distinct for $m' \leq L.C.M.(1, \ldots, n)$ (will be explained in appendix).
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2471
With each new input character taking the derivative against the intermediate result, more and more such distinct
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2472
terms will accumulate, 
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2473
until the length reaches $L.C.M.(1, \ldots, n)$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2474
$\textit{distinctBy}$ will not be able to de-duplicate any two of these terms 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2475
$(\oplus_{i = 1}^{n}  (\underbrace{a \ldots a}_{\text{((i - (m' \% i))\%i) a's}})\cdot  (\underbrace{a \ldots a}_{\text{i a's}})^* )\cdot (\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*$\\
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2476
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2477
$(\oplus_{i = 1}^{n}  (\underbrace{a \ldots a}_{\text{((i - (m'' \% i))\%i) a's}})\cdot  (\underbrace{a \ldots a}_{\text{i a's}})^* )\cdot (\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*$\\
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2478
where $m' \neq m''$ \\
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2479
as they are slightly different.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2480
This means that with our current simplification methods,
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2481
we will not be able to control the derivative so that
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2482
$\llbracket \bderssimp{r}{s} \rrbracket$ stays polynomial %\leq O((\llbracket r\rrbacket)^c)$
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2483
as there are already exponentially many terms.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2484
These terms are similar in the sense that the head of those terms
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2485
are all consisted of sub-terms of the form: 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2486
$(\underbrace{a \ldots a}_{\text{j a's}})\cdot  (\underbrace{a \ldots a}_{\text{i a's}})^* $.
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2487
For  $\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*$, there will be at most
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2488
$n * (n + 1) / 2$ such terms. 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2489
For example, $(a^* + (aa)^* + (aaa)^*) ^*$'s derivatives
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2490
can be described by 6 terms:
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2491
$a^*$, $a\cdot (aa)^*$, $ (aa)^*$, 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2492
$aa \cdot (aaa)^*$, $a \cdot (aaa)^*$, and $(aaa)^*$.
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2493
The total number of different "head terms",  $n * (n + 1) / 2$,
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2494
is proportional to the number of characters in the regex 
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2495
$(\oplus_{i=1}^{n} (\underbrace{a \ldots a}_{\text{i a's}})^*)^*$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2496
This suggests a slightly different notion of size, which we call the 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2497
alphabetic width:
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2498
%TODO:
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2499
(TODO: Alphabetic width def.)
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2500
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2501
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2502
Antimirov\parencite{Antimirov95} has proven that 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2503
$\textit{PDER}_{UNIV}(r) \leq \textit{awidth}(r)$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2504
where $\textit{PDER}_{UNIV}(r)$ is a set of all possible subterms
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2505
created by doing derivatives of $r$ against all possible strings.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2506
If we can make sure that at any moment in our lexing algorithm our 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2507
intermediate result hold at most one copy of each of the 
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2508
subterms then we can get the same bound as Antimirov's.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2509
This leads to the algorithm in the next chapter.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2510
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2511
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2512
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2513
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2514
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2515
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2516
%	SECTION 1
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2517
%----------------------------------------------------------------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2518
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2519
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2520
%-----------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2521
%	SUBSECTION 1
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2522
%-----------------------------------
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2523
\subsection{Syntactic Equivalence Under $\simp$}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2524
We prove that minor differences can be annhilated
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2525
by $\simp$.
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2526
For example,
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2527
\begin{center}
593
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2528
	$\simp \;(\simpALTs\; (\map \;(\_\backslash \; x)\; (\distinct \; \mathit{rs}\; \phi))) = 
83fab852d72d more chap5
Chengsong
parents: 591
diff changeset
  2529
	\simp \;(\simpALTs \;(\distinct \;(\map \;(\_ \backslash\; x) \; \mathit{rs}) \; \phi))$
532
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2530
\end{center}
cc54ce075db5 restructured
Chengsong
parents:
diff changeset
  2531