diff -r 8939b8fd8603 -r 069d525f8f1d ProgTutorial/Package/Ind_Prelims.thy --- /dev/null Thu Jan 01 00:00:00 1970 +0000 +++ b/ProgTutorial/Package/Ind_Prelims.thy Thu Mar 19 13:28:16 2009 +0100 @@ -0,0 +1,352 @@ +theory Ind_Prelims +imports Main LaTeXsugar"../Base" Simple_Inductive_Package +begin + +section{* Preliminaries *} + +text {* + The user will just give a specification of an inductive predicate and + expects from the package to produce a convenient reasoning + infrastructure. This infrastructure needs to be derived from the definition + that correspond to the specified predicate. This will roughly mean that the + package has three main parts, namely: + + + \begin{itemize} + \item parsing the specification and typing the parsed input, + \item making the definitions and deriving the reasoning infrastructure, and + \item storing the results in the theory. + \end{itemize} + + Before we start with explaining all parts, let us first give three examples + showing how to define inductive predicates by hand and then also how to + prove by hand important properties about them. From these examples, we will + figure out a general method for defining inductive predicates. The aim in + this section is \emph{not} to write proofs that are as beautiful as + possible, but as close as possible to the ML-code we will develop in later + sections. + + + We first consider the transitive closure of a relation @{text R}. It is + an inductive predicate characterised by the two introduction rules: + + \begin{center}\small + @{prop[mode=Axiom] "trcl R x x"} \hspace{5mm} + @{prop[mode=Rule] "R x y \ trcl R y z \ trcl R x z"} + \end{center} + + In Isabelle, the user will state for @{term trcl\} the specification: +*} + +simple_inductive + trcl\ :: "('a \ 'a \ bool) \ 'a \ 'a \ bool" +where + base: "trcl\ R x x" +| step: "trcl\ R x y \ R y z \ trcl\ R x z" + +text {* + As said above the package has to make an appropriate definition and provide + lemmas to reason about the predicate @{term trcl\}. Since an inductively + defined predicate is the least predicate closed under a collection of + introduction rules, the predicate @{text "trcl R x y"} can be defined so + that it holds if and only if @{text "P x y"} holds for every predicate + @{text P} closed under the rules above. This gives rise to the definition +*} + +definition "trcl \ + \R x y. \P. (\x. P x x) + \ (\x y z. R x y \ P y z \ P x z) \ P x y" + +text {* + where we quantify over the predicate @{text P}. We have to use the + object implication @{text "\"} and object quantification @{text "\"} for + stating this definition (there is no other way for definitions in + HOL). However, the introduction rules and induction principles + should use the meta-connectives since they simplify the + reasoning for the user. + + With this definition, the proof of the induction principle for @{term trcl} + is almost immediate. It suffices to convert all the meta-level + connectives in the lemma to object-level connectives using the + proof method @{text atomize} (Line 4), expand the definition of @{term trcl} + (Line 5 and 6), eliminate the universal quantifier contained in it (Line~7), + and then solve the goal by assumption (Line 8). + +*} + +lemma %linenos trcl_induct: + assumes "trcl R x y" + shows "(\x. P x x) \ (\x y z. R x y \ P y z \ P x z) \ P x y" +apply(atomize (full)) +apply(cut_tac prems) +apply(unfold trcl_def) +apply(drule spec[where x=P]) +apply(assumption) +done + +text {* + The proofs for the introduction rules are slightly more complicated. + For the first one, we need to prove the following lemma: +*} + +lemma %linenos trcl_base: + shows "trcl R x x" +apply(unfold trcl_def) +apply(rule allI impI)+ +apply(drule spec) +apply(assumption) +done + +text {* + We again unfold first the definition and apply introduction rules + for @{text "\"} and @{text "\"} as often as possible (Lines 3 and 4). + We then end up in the goal state: +*} + +(*<*)lemma "trcl R x x" +apply (unfold trcl_def) +apply (rule allI impI)+(*>*) +txt {* @{subgoals [display]} *} +(*<*)oops(*>*) + +text {* + The two assumptions correspond to the introduction rules. Thus, all we have + to do is to eliminate the universal quantifier in front of the first + assumption (Line 5), and then solve the goal by assumption (Line 6). +*} + +text {* + Next we have to show that the second introduction rule also follows from the + definition. Since this rule has premises, the proof is a bit more + involved. After unfolding the definitions and applying the introduction + rules for @{text "\"} and @{text "\"} +*} + +lemma trcl_step: + shows "R x y \ trcl R y z \ trcl R x z" +apply (unfold trcl_def) +apply (rule allI impI)+ + +txt {* + we obtain the goal state + + @{subgoals [display]} + + To see better where we are, let us explicitly name the assumptions + by starting a subproof. +*} + +proof - + case (goal1 P) + have p1: "R x y" by fact + have p2: "\P. (\x. P x x) + \ (\x y z. R x y \ P y z \ P x z) \ P y z" by fact + have r1: "\x. P x x" by fact + have r2: "\x y z. R x y \ P y z \ P x z" by fact + show "P x z" + +txt {* + The assumptions @{text "p1"} and @{text "p2"} correspond to the premises of + the second introduction rule; the assumptions @{text "r1"} and @{text "r2"} + correspond to the introduction rules. We apply @{text "r2"} to the goal + @{term "P x z"}. In order for the assumption to be applicable as a rule, we + have to eliminate the universal quantifier and turn the object-level + implications into meta-level ones. This can be accomplished using the @{text + rule_format} attribute. So we continue the proof with: + +*} + + apply (rule r2[rule_format]) + +txt {* + This gives us two new subgoals + + @{subgoals [display]} + + which can be solved using assumptions @{text p1} and @{text p2}. The latter + involves a quantifier and implications that have to be eliminated before it + can be applied. To avoid potential problems with higher-order unification, + we explicitly instantiate the quantifier to @{text "P"} and also match + explicitly the implications with @{text "r1"} and @{text "r2"}. This gives + the proof: +*} + + apply(rule p1) + apply(rule p2[THEN spec[where x=P], THEN mp, THEN mp, OF r1, OF r2]) + done +qed + +text {* + Now we are done. It might be surprising that we are not using the automatic + tactics available in Isabelle for proving this lemmas. After all @{text + "blast"} would easily dispense of it. +*} + +lemma trcl_step_blast: + shows "R x y \ trcl R y z \ trcl R x z" +apply(unfold trcl_def) +apply(blast) +done + +text {* + Experience has shown that it is generally a bad idea to rely heavily on + @{text blast}, @{text auto} and the like in automated proofs. The reason is + that you do not have precise control over them (the user can, for example, + declare new intro- or simplification rules that can throw automatic tactics + off course) and also it is very hard to debug proofs involving automatic + tactics whenever something goes wrong. Therefore if possible, automatic + tactics should be avoided or sufficiently constrained. + + The method of defining inductive predicates by impredicative quantification + also generalises to mutually inductive predicates. The next example defines + the predicates @{text even} and @{text odd} characterised by the following + rules: + + \begin{center}\small + @{prop[mode=Axiom] "even (0::nat)"} \hspace{5mm} + @{prop[mode=Rule] "odd n \ even (Suc n)"} \hspace{5mm} + @{prop[mode=Rule] "even n \ odd (Suc n)"} + \end{center} + + The user will state for this inductive definition the specification: +*} + +simple_inductive + even and odd +where + even0: "even 0" +| evenS: "odd n \ even (Suc n)" +| oddS: "even n \ odd (Suc n)" + +text {* + Since the predicates @{term even} and @{term odd} are mutually inductive, each + corresponding definition must quantify over both predicates (we name them + below @{text "P"} and @{text "Q"}). +*} + +definition "even\ \ + \n. \P Q. P 0 \ (\m. Q m \ P (Suc m)) + \ (\m. P m \ Q (Suc m)) \ P n" + +definition "odd\ \ + \n. \P Q. P 0 \ (\m. Q m \ P (Suc m)) + \ (\m. P m \ Q (Suc m)) \ Q n" + +text {* + For proving the induction principles, we use exactly the same technique + as in the transitive closure example, namely: +*} + +lemma even_induct: + assumes "even n" + shows "P 0 \ + (\m. Q m \ P (Suc m)) \ (\m. P m \ Q (Suc m)) \ P n" +apply(atomize (full)) +apply(cut_tac prems) +apply(unfold even_def) +apply(drule spec[where x=P]) +apply(drule spec[where x=Q]) +apply(assumption) +done + +text {* + The only difference with the proof @{text "trcl_induct"} is that we have to + instantiate here two universal quantifiers. We omit the other induction + principle that has @{term "Q n"} as conclusion. The proofs of the + introduction rules are also very similar to the ones in the @{text + "trcl"}-example. We only show the proof of the second introduction rule. + +*} + +lemma %linenos evenS: + shows "odd m \ even (Suc m)" +apply (unfold odd_def even_def) +apply (rule allI impI)+ +proof - + case (goal1 P Q) + have p1: "\P Q. P 0 \ (\m. Q m \ P (Suc m)) + \ (\m. P m \ Q (Suc m)) \ Q m" by fact + have r1: "P 0" by fact + have r2: "\m. Q m \ P (Suc m)" by fact + have r3: "\m. P m \ Q (Suc m)" by fact + show "P (Suc m)" + apply(rule r2[rule_format]) + apply(rule p1[THEN spec[where x=P], THEN spec[where x=Q], + THEN mp, THEN mp, THEN mp, OF r1, OF r2, OF r3]) + done +qed + +text {* + In Line 13, we apply the assumption @{text "r2"} (since we prove the second + introduction rule). In Lines 14 and 15 we apply assumption @{text "p1"} (if + the second introduction rule had more premises we have to do that for all + of them). In order for this assumption to be applicable, the quantifiers + need to be instantiated and then also the implications need to be resolved + with the other rules. + + + As a final example, we define the accessible part of a relation @{text R} characterised + by the introduction rule + + \begin{center}\small + \mbox{\inferrule{@{term "\y. R y x \ accpart R y"}}{@{term "accpart R x"}}} + \end{center} + + whose premise involves a universal quantifier and an implication. The + definition of @{text accpart} is: +*} + +definition "accpart \ \R x. \P. (\x. (\y. R y x \ P y) \ P x) \ P x" + +text {* + The proof of the induction principle is again straightforward. +*} + +lemma accpart_induct: + assumes "accpart R x" + shows "(\x. (\y. R y x \ P y) \ P x) \ P x" +apply(atomize (full)) +apply(cut_tac prems) +apply(unfold accpart_def) +apply(drule spec[where x=P]) +apply(assumption) +done + +text {* + Proving the introduction rule is a little more complicated, because the quantifier + and the implication in the premise. The proof is as follows. +*} + +lemma %linenos accpartI: + shows "(\y. R y x \ accpart R y) \ accpart R x" +apply (unfold accpart_def) +apply (rule allI impI)+ +proof - + case (goal1 P) + have p1: "\y. R y x \ + (\P. (\x. (\y. R y x \ P y) \ P x) \ P y)" by fact + have r1: "\x. (\y. R y x \ P y) \ P x" by fact + show "P x" + apply(rule r1[rule_format]) + proof - + case (goal1 y) + have r1_prem: "R y x" by fact + show "P y" + apply(rule p1[OF r1_prem, THEN spec[where x=P], THEN mp, OF r1]) + done + qed +qed + +text {* + In Line 11, applying the assumption @{text "r1"} generates a goal state with + the new local assumption @{term "R y x"}, named @{text "r1_prem"} in the + proof above (Line 14). This local assumption is used to solve + the goal @{term "P y"} with the help of assumption @{text "p1"}. + + The point of these examples is to get a feeling what the automatic proofs + should do in order to solve all inductive definitions we throw at them. + This is usually the first step in writing a package. We next explain + the parsing and typing part of the package. + +*} +(*<*)end(*>*)