etnms/etnms.tex
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\documentclass[a4paper,UKenglish]{lipics}
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\usepackage{graphic}
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\usepackage{data}
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\usepackage{tikz-cd}
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%\usepackage{algorithm}
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\usepackage{amsmath}
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\usepackage[noend]{algpseudocode}
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\usepackage{enumitem}
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\usepackage{nccmath}
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\definecolor{darkblue}{rgb}{0,0,0.6}
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\hypersetup{colorlinks=true,allcolors=darkblue}
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\newcommand{\comment}[1]%
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{{\color{red}$\Rightarrow$}\marginpar{\raggedright\small{\bf\color{red}#1}}}
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% \documentclass{article}
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%\usepackage[utf8]{inputenc}
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%\usepackage[english]{babel}
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%\usepackage{listings}
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% \usepackage{amsthm}
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%\usepackage{hyperref}
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% \usepackage[margin=0.5in]{geometry}
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%\usepackage{pmboxdraw}
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\title{POSIX Regular Expression Matching and Lexing}
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\author{Chengsong Tan}
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\affil{King's College London\\
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London, UK\\
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\texttt{chengsong.tan@kcl.ac.uk}}
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\authorrunning{Chengsong Tan}
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\Copyright{Chengsong Tan}
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\newcommand{\dn}{\stackrel{\mbox{\scriptsize def}}{=}}%
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\newcommand{\ZERO}{\mbox{\bf 0}}
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\newcommand{\ONE}{\mbox{\bf 1}}
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\def\erase{\textit{erase}}
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\def\bders{\textit{bders}}
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\def\lexer{\mathit{lexer}}
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\def\blexer{\textit{blexer}}
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\def\fuse{\textit{fuse}}
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\def\flatten{\textit{flatten}}
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\def\map{\textit{map}}
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\def\blexers{\mathit{blexer\_simp}}
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\def\simp{\mathit{simp}}
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\def\mkeps{\mathit{mkeps}}
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\def\bmkeps{\textit{bmkeps}}
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\def\inj{\mathit{inj}}
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\def\Empty{\mathit{Empty}}
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\def\Left{\mathit{Left}}
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\def\Right{\mathit{Right}}
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\def\Stars{\mathit{Stars}}
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\def\Char{\mathit{Char}}
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\def\Seq{\mathit{Seq}}
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\def\Der{\mathit{Der}}
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\def\nullable{\mathit{nullable}}
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\def\Z{\mathit{Z}}
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\def\S{\mathit{S}}
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\def\flex{\textit{flex}}
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\def\rup{r^\uparrow}
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\def\retrieve{\textit{retrieve}}
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\def\AALTS{\textit{AALTS}}
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\def\AONE{\textit{AONE}}
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%\theoremstyle{theorem}
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%\newtheorem{theorem}{Theorem}
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%\theoremstyle{lemma}
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%\newtheorem{lemma}{Lemma}
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%\newcommand{\lemmaautorefname}{Lemma}
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%\theoremstyle{definition}
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%\newtheorem{definition}{Definition}
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\algnewcommand\algorithmicswitch{\textbf{switch}}
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\algnewcommand\algorithmiccase{\textbf{case}}
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\algnewcommand\algorithmicassert{\texttt{assert}}
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\algnewcommand\Assert[1]{\State \algorithmicassert(#1)}%
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% New "environments"
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\algdef{SE}[SWITCH]{Switch}{EndSwitch}[1]{\algorithmicswitch\ #1\ \algorithmicdo}{\algorithmicend\ \algorithmicswitch}%
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\algdef{SE}[CASE]{Case}{EndCase}[1]{\algorithmiccase\ #1}{\algorithmicend\ \algorithmiccase}%
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\algtext*{EndSwitch}%
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\algtext*{EndCase}%
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\begin{document}
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\maketitle
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\begin{abstract}
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  Brzozowski introduced in 1964 a beautifully simple algorithm for
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  regular expression matching based on the notion of derivatives of
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  regular expressions. In 2014, Sulzmann and Lu extended this
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  algorithm to not just give a YES/NO answer for whether or not a
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  regular expression matches a string, but in case it does also
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  answers with \emph{how} it matches the string.  This is important for
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  applications such as lexing (tokenising a string). The problem is to
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  make the algorithm by Sulzmann and Lu fast on all inputs without
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  breaking its correctness. Being fast depends on a complete set of 
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  simplification rules, some of which 
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  have been put forward by Sulzmann and Lu. We have extended their
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  rules in order to obtain a tight bound on the size of regular expressions.
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  We have tested these extended rules, but have not 
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  formally established their correctness. We have also not yet looked 
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  at extended regular expressions, such as bounded repetitions,
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  negation and back-references.
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\end{abstract}
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\section{Recapitulation of Concepts From the Last Report}
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\subsection{The Algorithm by Brzozowski based on Derivatives of Regular
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Expressions}
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Suppose (basic) regular expressions are given by the following grammar:
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\[			r ::=   \ZERO \mid  \ONE
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			 \mid  c  
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			 \mid  r_1 \cdot r_2
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			 \mid  r_1 + r_2   
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			 \mid r^*         
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\]
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\noindent
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The ingenious contribution by Brzozowski is the notion of
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\emph{derivatives} of regular expressions.  
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\begin{center}
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		\begin{tabular}{lcl}
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			$\nullable(\ZERO)$     & $\dn$ & $\mathit{false}$ \\  
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			$\nullable(\ONE)$      & $\dn$ & $\mathit{true}$ \\
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			$\nullable(c)$ 	       & $\dn$ & $\mathit{false}$ \\
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			$\nullable(r_1 + r_2)$ & $\dn$ & $\nullable(r_1) \vee \nullable(r_2)$ \\
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			$\nullable(r_1\cdot r_2)$  & $\dn$ & $\nullable(r_1) \wedge \nullable(r_2)$ \\
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			$\nullable(r^*)$       & $\dn$ & $\mathit{true}$ \\
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		\end{tabular}
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	\end{center}
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\begin{center}
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\begin{tabular}{lcl}
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		$\ZERO \backslash c$ & $\dn$ & $\ZERO$\\  
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		$\ONE \backslash c$  & $\dn$ & $\ZERO$\\
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		$d \backslash c$     & $\dn$ & 
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		$\mathit{if} \;c = d\;\mathit{then}\;\ONE\;\mathit{else}\;\ZERO$\\
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$(r_1 + r_2)\backslash c$     & $\dn$ & $r_1 \backslash c \,+\, r_2 \backslash c$\\
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$(r_1 \cdot r_2)\backslash c$ & $\dn$ & $\mathit{if} \, nullable(r_1)$\\
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	&   & $\mathit{then}\;(r_1\backslash c) \cdot r_2 \,+\, r_2\backslash c$\\
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	&   & $\mathit{else}\;(r_1\backslash c) \cdot r_2$\\
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	$(r^*)\backslash c$           & $\dn$ & $(r\backslash c) \cdot r^*$\\
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\end{tabular}
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\end{center}
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%Assuming the classic notion of a
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%\emph{language} of a regular expression, written $L(\_)$, t
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\noindent
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The main property of the derivative operation is that
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\begin{center}
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$c\!::\!s \in L(r)$ holds
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if and only if $s \in L(r\backslash c)$.
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\end{center}
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\noindent
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Now we can generalise the derivative operation to strings like this:
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\begin{center}
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\begin{tabular}{lcl}
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$r \backslash (c\!::\!s) $ & $\dn$ & $(r \backslash c) \backslash s$ \\
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$r \backslash [\,] $ & $\dn$ & $r$
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\end{tabular}
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\end{center}
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\noindent
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and then define as  regular-expression matching algorithm: 
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\[
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match\;s\;r \;\dn\; nullable(r\backslash s)
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\]
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\noindent
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This algorithm looks graphically as follows:
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\begin{equation}\label{graph:*}
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\begin{tikzcd}
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r_0 \arrow[r, "\backslash c_0"]  & r_1 \arrow[r, "\backslash c_1"] & r_2 \arrow[r, dashed]  & r_n  \arrow[r,"\textit{nullable}?"] & \;\textrm{YES}/\textrm{NO}
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\end{tikzcd}
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\end{equation}
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\noindent
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where we start with  a regular expression  $r_0$, build successive
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derivatives until we exhaust the string and then use \textit{nullable}
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to test whether the result can match the empty string. It can  be
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relatively  easily shown that this matcher is correct  (that is given
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an $s = c_0...c_{n-1}$ and an $r_0$, it generates YES if and only if $s \in L(r_0)$).
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\subsection{Values and the Algorithm by Sulzmann and Lu}
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One limitation of Brzozowski's algorithm is that it only produces a
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YES/NO answer for whether a string is being matched by a regular
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expression.  Sulzmann and Lu~\cite{Sulzmann2014} extended this algorithm
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to allow generation of an actual matching, called a \emph{value} or
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sometimes also \emph{lexical value}.  These values and regular
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expressions correspond to each other as illustrated in the following
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table:
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\begin{center}
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	\begin{tabular}{c@{\hspace{20mm}}c}
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		\begin{tabular}{@{}rrl@{}}
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			\multicolumn{3}{@{}l}{\textbf{Regular Expressions}}\medskip\\
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			$r$ & $::=$  & $\ZERO$\\
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			& $\mid$ & $\ONE$   \\
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			& $\mid$ & $c$          \\
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			& $\mid$ & $r_1 \cdot r_2$\\
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			& $\mid$ & $r_1 + r_2$   \\
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			\\
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			& $\mid$ & $r^*$         \\
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		\end{tabular}
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		&
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		\begin{tabular}{@{\hspace{0mm}}rrl@{}}
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			\multicolumn{3}{@{}l}{\textbf{Values}}\medskip\\
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			$v$ & $::=$  & \\
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			&        & $\Empty$   \\
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			& $\mid$ & $\Char(c)$          \\
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			& $\mid$ & $\Seq\,v_1\, v_2$\\
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			& $\mid$ & $\Left(v)$   \\
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			& $\mid$ & $\Right(v)$  \\
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			& $\mid$ & $\Stars\,[v_1,\ldots\,v_n]$ \\
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		\end{tabular}
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	\end{tabular}
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\end{center}
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\noindent
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The contribution of Sulzmann and Lu is an extension of Brzozowski's
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algorithm by a second phase (the first phase being building successive
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derivatives---see \eqref{graph:*}). In this second phase, a POSIX value 
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is generated in case the regular expression matches  the string. 
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Pictorially, the Sulzmann and Lu algorithm is as follows:
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\begin{ceqn}
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\begin{equation}\label{graph:2}
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\begin{tikzcd}
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r_0 \arrow[r, "\backslash c_0"]  \arrow[d] & r_1 \arrow[r, "\backslash c_1"] \arrow[d] & r_2 \arrow[r, dashed] \arrow[d] & r_n \arrow[d, "mkeps" description] \\
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v_0           & v_1 \arrow[l,"inj_{r_0} c_0"]                & v_2 \arrow[l, "inj_{r_1} c_1"]              & v_n \arrow[l, dashed]         
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\end{tikzcd}
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\end{equation}
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\end{ceqn}
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\noindent
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For convenience, we shall employ the following notations: the regular
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expression we start with is $r_0$, and the given string $s$ is composed
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of characters $c_0 c_1 \ldots c_{n-1}$. In  the first phase from the
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left to right, we build the derivatives $r_1$, $r_2$, \ldots  according
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to the characters $c_0$, $c_1$  until we exhaust the string and obtain
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the derivative $r_n$. We test whether this derivative is
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$\textit{nullable}$ or not. If not, we know the string does not match
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$r$ and no value needs to be generated. If yes, we start building the
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values incrementally by \emph{injecting} back the characters into the
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earlier values $v_n, \ldots, v_0$. This is the second phase of the
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algorithm from the right to left. For the first value $v_n$, we call the
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function $\textit{mkeps}$, which builds the lexical value
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for how the empty string has been matched by the (nullable) regular
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expression $r_n$. This function is defined as
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	\begin{center}
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		\begin{tabular}{lcl}
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			$\mkeps(\ONE)$ 		& $\dn$ & $\Empty$ \\
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			$\mkeps(r_{1}+r_{2})$	& $\dn$ 
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			& \textit{if} $\nullable(r_{1})$\\ 
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			& & \textit{then} $\Left(\mkeps(r_{1}))$\\ 
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			& & \textit{else} $\Right(\mkeps(r_{2}))$\\
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			$\mkeps(r_1\cdot r_2)$ 	& $\dn$ & $\Seq\,(\mkeps\,r_1)\,(\mkeps\,r_2)$\\
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			$mkeps(r^*)$	        & $\dn$ & $\Stars\,[]$
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		\end{tabular}
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	\end{center}
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\noindent 
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After the $\mkeps$-call, we inject back the characters one by one in order to build
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the lexical value $v_i$ for how the regex $r_i$ matches the string $s_i$
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($s_i = c_i \ldots c_{n-1}$ ) from the previous lexical value $v_{i+1}$.
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After injecting back $n$ characters, we get the lexical value for how $r_0$
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matches $s$. For this Sulzmann and Lu defined a function that reverses
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the ``chopping off'' of characters during the derivative phase. The
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corresponding function is called \emph{injection}, written
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$\textit{inj}$; it takes three arguments: the first one is a regular
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expression ${r_{i-1}}$, before the character is chopped off, the second
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is a character ${c_{i-1}}$, the character we want to inject and the
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third argument is the value ${v_i}$, into which one wants to inject the
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character (it corresponds to the regular expression after the character
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has been chopped off). The result of this function is a new value. The
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definition of $\textit{inj}$ is as follows: 
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\begin{center}
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\begin{tabular}{l@{\hspace{1mm}}c@{\hspace{1mm}}l}
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  $\textit{inj}\,(c)\,c\,Empty$            & $\dn$ & $Char\,c$\\
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  $\textit{inj}\,(r_1 + r_2)\,c\,\Left(v)$ & $\dn$ & $\Left(\textit{inj}\,r_1\,c\,v)$\\
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  $\textit{inj}\,(r_1 + r_2)\,c\,Right(v)$ & $\dn$ & $Right(\textit{inj}\,r_2\,c\,v)$\\
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  $\textit{inj}\,(r_1 \cdot r_2)\,c\,Seq(v_1,v_2)$ & $\dn$  & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\
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  $\textit{inj}\,(r_1 \cdot r_2)\,c\,\Left(Seq(v_1,v_2))$ & $\dn$  & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\
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  $\textit{inj}\,(r_1 \cdot r_2)\,c\,Right(v)$ & $\dn$  & $Seq(\textit{mkeps}(r_1),\textit{inj}\,r_2\,c\,v)$\\
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  $\textit{inj}\,(r^*)\,c\,Seq(v,Stars\,vs)$         & $\dn$  & $Stars((\textit{inj}\,r\,c\,v)\,::\,vs)$\\
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\end{tabular}
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\end{center}
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\noindent This definition is by recursion on the ``shape'' of regular
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expressions and values. 
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\subsection{Simplification of Regular Expressions}
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The main drawback of building successive derivatives according
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to Brzozowski's definition is that they can grow very quickly in size.
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This is mainly due to the fact that the derivative operation generates
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often ``useless'' $\ZERO$s and $\ONE$s in derivatives.  As a result, if
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implemented naively both algorithms by Brzozowski and by Sulzmann and Lu
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are excruciatingly slow. For example when starting with the regular
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expression $(a + aa)^*$ and building 12 successive derivatives
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w.r.t.~the character $a$, one obtains a derivative regular expression
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with more than 8000 nodes (when viewed as a tree). Operations like
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$\textit{der}$ and $\nullable$ need to traverse such trees and
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consequently the bigger the size of the derivative the slower the
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algorithm. 
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Fortunately, one can simplify regular expressions after each derivative
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step. Various simplifications of regular expressions are possible, such
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as the simplification of $\ZERO + r$, $r + \ZERO$, $\ONE\cdot r$, $r
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\cdot \ONE$, and $r + r$ to just $r$. These simplifications do not
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affect the answer for whether a regular expression matches a string or
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not, but fortunately also do not affect the POSIX strategy of how
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regular expressions match strings---although the latter is much harder
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to establish. Some initial results in this regard have been
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obtained in \cite{AusafDyckhoffUrban2016}. 
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If we want the size of derivatives in Sulzmann and Lu's algorithm to
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stay below this bound, we would need more aggressive simplifications.
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Essentially we need to delete useless $\ZERO$s and $\ONE$s, as well as
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deleting duplicates whenever possible. For example, the parentheses in
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$(a+b) \cdot c + bc$ can be opened up to get $a\cdot c +  b \cdot c + b
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\cdot c$, and then simplified to just $a \cdot c + b \cdot c$. Another
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example is simplifying $(a^*+a) + (a^*+ \ONE) + (a +\ONE)$ to just
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$a^*+a+\ONE$. Adding these more aggressive simplification rules helps us
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to achieve the same size bound as that of the partial derivatives. 
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In order to implement the idea of ``spilling out alternatives'' and to
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make them compatible with the $\text{inj}$-mechanism, we use
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\emph{bitcodes}. Bits and bitcodes (lists of bits) are just:
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\begin{center}
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		$b ::=   S \mid  Z \qquad
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bs ::= [] \mid b:bs    
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$
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\end{center}
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\noindent
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The $S$ and $Z$ are arbitrary names for the bits in order to avoid 
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confusion with the regular expressions $\ZERO$ and $\ONE$. Bitcodes (or
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bit-lists) can be used to encode values (or incomplete values) in a
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compact form. This can be straightforwardly seen in the following
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coding function from values to bitcodes: 
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\begin{center}
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\begin{tabular}{lcl}
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  $\textit{code}(\Empty)$ & $\dn$ & $[]$\\
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  $\textit{code}(\Char\,c)$ & $\dn$ & $[]$\\
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  $\textit{code}(\Left\,v)$ & $\dn$ & $\Z :: code(v)$\\
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  $\textit{code}(\Right\,v)$ & $\dn$ & $\S :: code(v)$\\
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  $\textit{code}(\Seq\,v_1\,v_2)$ & $\dn$ & $code(v_1) \,@\, code(v_2)$\\
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  $\textit{code}(\Stars\,[])$ & $\dn$ & $[\Z]$\\
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  $\textit{code}(\Stars\,(v\!::\!vs))$ & $\dn$ & $\S :: code(v) \;@\;
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                                                 code(\Stars\,vs)$
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\end{tabular}    
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\end{center} 
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\noindent
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Here $\textit{code}$ encodes a value into a bitcodes by converting
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$\Left$ into $\Z$, $\Right$ into $\S$, the start point of a non-empty
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star iteration into $\S$, and the border where a local star terminates
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into $\Z$. This coding is lossy, as it throws away the information about
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characters, and also does not encode the ``boundary'' between two
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sequence values. Moreover, with only the bitcode we cannot even tell
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whether the $\S$s and $\Z$s are for $\Left/\Right$ or $\Stars$. The
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reason for choosing this compact way of storing information is that the
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relatively small size of bits can be easily manipulated and ``moved
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around'' in a regular expression. In order to recover values, we will 
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need the corresponding regular expression as an extra information. This
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means the decoding function is defined as:
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%\begin{definition}[Bitdecoding of Values]\mbox{}
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\begin{center}
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\begin{tabular}{@{}l@{\hspace{1mm}}c@{\hspace{1mm}}l@{}}
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  $\textit{decode}'\,bs\,(\ONE)$ & $\dn$ & $(\Empty, bs)$\\
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  $\textit{decode}'\,bs\,(c)$ & $\dn$ & $(\Char\,c, bs)$\\
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  $\textit{decode}'\,(\Z\!::\!bs)\;(r_1 + r_2)$ & $\dn$ &
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     $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}\;
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       (\Left\,v, bs_1)$\\
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  $\textit{decode}'\,(\S\!::\!bs)\;(r_1 + r_2)$ & $\dn$ &
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     $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_2\;\textit{in}\;
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   396
       (\Right\,v, bs_1)$\\                           
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diff changeset
   397
  $\textit{decode}'\,bs\;(r_1\cdot r_2)$ & $\dn$ &
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parents: 106
diff changeset
   398
        $\textit{let}\,(v_1, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}$\\
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parents: 106
diff changeset
   399
  & &   $\textit{let}\,(v_2, bs_2) = \textit{decode}'\,bs_1\,r_2$\\
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parents: 106
diff changeset
   400
  & &   \hspace{35mm}$\textit{in}\;(\Seq\,v_1\,v_2, bs_2)$\\
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parents: 106
diff changeset
   401
  $\textit{decode}'\,(\Z\!::\!bs)\,(r^*)$ & $\dn$ & $(\Stars\,[], bs)$\\
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parents: 106
diff changeset
   402
  $\textit{decode}'\,(\S\!::\!bs)\,(r^*)$ & $\dn$ & 
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parents: 106
diff changeset
   403
         $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r\;\textit{in}$\\
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parents: 106
diff changeset
   404
  & &   $\textit{let}\,(\Stars\,vs, bs_2) = \textit{decode}'\,bs_1\,r^*$\\
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parents: 106
diff changeset
   405
  & &   \hspace{35mm}$\textit{in}\;(\Stars\,v\!::\!vs, bs_2)$\bigskip\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   406
  
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parents: 106
diff changeset
   407
  $\textit{decode}\,bs\,r$ & $\dn$ &
b1e365afa29c changes
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parents: 106
diff changeset
   408
     $\textit{let}\,(v, bs') = \textit{decode}'\,bs\,r\;\textit{in}$\\
b1e365afa29c changes
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parents: 106
diff changeset
   409
  & & $\textit{if}\;bs' = []\;\textit{then}\;\textit{Some}\,v\;
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parents: 106
diff changeset
   410
       \textit{else}\;\textit{None}$                       
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parents: 106
diff changeset
   411
\end{tabular}    
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parents: 106
diff changeset
   412
\end{center}    
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parents: 106
diff changeset
   413
%\end{definition}
b1e365afa29c changes
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parents: 106
diff changeset
   414
b1e365afa29c changes
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diff changeset
   415
Sulzmann and Lu's integrated the bitcodes into regular expressions to
b1e365afa29c changes
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parents: 106
diff changeset
   416
create annotated regular expressions \cite{Sulzmann2014}.
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parents: 106
diff changeset
   417
\emph{Annotated regular expressions} are defined by the following
b1e365afa29c changes
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diff changeset
   418
grammar:%\comment{ALTS should have  an $as$ in  the definitions, not  just $a_1$ and $a_2$}
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diff changeset
   419
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parents: 106
diff changeset
   420
\begin{center}
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parents: 106
diff changeset
   421
\begin{tabular}{lcl}
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diff changeset
   422
  $\textit{a}$ & $::=$  & $\textit{ZERO}$\\
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parents: 106
diff changeset
   423
                  & $\mid$ & $\textit{ONE}\;\;bs$\\
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parents: 106
diff changeset
   424
                  & $\mid$ & $\textit{CHAR}\;\;bs\,c$\\
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parents: 106
diff changeset
   425
                  & $\mid$ & $\textit{ALTS}\;\;bs\,as$\\
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parents: 106
diff changeset
   426
                  & $\mid$ & $\textit{SEQ}\;\;bs\,a_1\,a_2$\\
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parents: 106
diff changeset
   427
                  & $\mid$ & $\textit{STAR}\;\;bs\,a$
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diff changeset
   428
\end{tabular}    
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parents: 106
diff changeset
   429
\end{center}  
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diff changeset
   430
%(in \textit{ALTS})
b1e365afa29c changes
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diff changeset
   431
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parents: 106
diff changeset
   432
\noindent
b1e365afa29c changes
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diff changeset
   433
where $bs$ stands for bitcodes, $a$  for $\bold{a}$nnotated regular
b1e365afa29c changes
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parents: 106
diff changeset
   434
expressions and $as$ for a list of annotated regular expressions.
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parents: 106
diff changeset
   435
The alternative constructor($\textit{ALTS}$) has been generalized to 
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parents: 106
diff changeset
   436
accept a list of annotated regular expressions rather than just 2.
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diff changeset
   437
We will show that these bitcodes encode information about
b1e365afa29c changes
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parents: 106
diff changeset
   438
the (POSIX) value that should be generated by the Sulzmann and Lu
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parents: 106
diff changeset
   439
algorithm.
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parents: 106
diff changeset
   440
b1e365afa29c changes
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parents: 106
diff changeset
   441
b1e365afa29c changes
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parents: 106
diff changeset
   442
To do lexing using annotated regular expressions, we shall first
b1e365afa29c changes
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parents: 106
diff changeset
   443
transform the usual (un-annotated) regular expressions into annotated
b1e365afa29c changes
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parents: 106
diff changeset
   444
regular expressions. This operation is called \emph{internalisation} and
b1e365afa29c changes
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parents: 106
diff changeset
   445
defined as follows:
b1e365afa29c changes
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diff changeset
   446
b1e365afa29c changes
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parents: 106
diff changeset
   447
%\begin{definition}
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parents: 106
diff changeset
   448
\begin{center}
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parents: 106
diff changeset
   449
\begin{tabular}{lcl}
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parents: 106
diff changeset
   450
  $(\ZERO)^\uparrow$ & $\dn$ & $\textit{ZERO}$\\
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parents: 106
diff changeset
   451
  $(\ONE)^\uparrow$ & $\dn$ & $\textit{ONE}\,[]$\\
b1e365afa29c changes
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parents: 106
diff changeset
   452
  $(c)^\uparrow$ & $\dn$ & $\textit{CHAR}\,[]\,c$\\
b1e365afa29c changes
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parents: 106
diff changeset
   453
  $(r_1 + r_2)^\uparrow$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   454
  $\textit{ALTS}\;[]\,List((\textit{fuse}\,[\Z]\,r_1^\uparrow),\,
b1e365afa29c changes
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parents: 106
diff changeset
   455
  (\textit{fuse}\,[\S]\,r_2^\uparrow))$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   456
  $(r_1\cdot r_2)^\uparrow$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   457
         $\textit{SEQ}\;[]\,r_1^\uparrow\,r_2^\uparrow$\\
b1e365afa29c changes
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parents: 106
diff changeset
   458
  $(r^*)^\uparrow$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   459
         $\textit{STAR}\;[]\,r^\uparrow$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   460
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   461
\end{center}    
b1e365afa29c changes
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parents: 106
diff changeset
   462
%\end{definition}
b1e365afa29c changes
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parents: 106
diff changeset
   463
b1e365afa29c changes
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parents: 106
diff changeset
   464
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   465
We use up arrows here to indicate that the basic un-annotated regular
b1e365afa29c changes
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parents: 106
diff changeset
   466
expressions are ``lifted up'' into something slightly more complex. In the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   467
fourth clause, $\textit{fuse}$ is an auxiliary function that helps to
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   468
attach bits to the front of an annotated regular expression. Its
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   469
definition is as follows:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   470
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   471
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   472
\begin{tabular}{lcl}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   473
  $\textit{fuse}\;bs\,(\textit{ZERO})$ & $\dn$ & $\textit{ZERO}$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   474
  $\textit{fuse}\;bs\,(\textit{ONE}\,bs')$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   475
     $\textit{ONE}\,(bs\,@\,bs')$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   476
  $\textit{fuse}\;bs\,(\textit{CHAR}\,bs'\,c)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   477
     $\textit{CHAR}\,(bs\,@\,bs')\,c$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   478
  $\textit{fuse}\;bs\,(\textit{ALTS}\,bs'\,as)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   479
     $\textit{ALTS}\,(bs\,@\,bs')\,as$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   480
  $\textit{fuse}\;bs\,(\textit{SEQ}\,bs'\,a_1\,a_2)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   481
     $\textit{SEQ}\,(bs\,@\,bs')\,a_1\,a_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   482
  $\textit{fuse}\;bs\,(\textit{STAR}\,bs'\,a)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   483
     $\textit{STAR}\,(bs\,@\,bs')\,a$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   484
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   485
\end{center}  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   486
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   487
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   488
After internalising the regular expression, we perform successive
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   489
derivative operations on the annotated regular expressions. This
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   490
derivative operation is the same as what we had previously for the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   491
basic regular expressions, except that we beed to take care of
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   492
the bitcodes:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   493
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   494
 %\begin{definition}{bder}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   495
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   496
  \begin{tabular}{@{}lcl@{}}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   497
  $(\textit{ZERO})\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   498
  $(\textit{ONE}\;bs)\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   499
  $(\textit{CHAR}\;bs\,d)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   500
        $\textit{if}\;c=d\; \;\textit{then}\;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   501
         \textit{ONE}\;bs\;\textit{else}\;\textit{ZERO}$\\  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   502
  $(\textit{ALTS}\;bs\,as)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   503
  $\textit{ALTS}\;bs\,(as.map(\backslash c))$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   504
  $(\textit{SEQ}\;bs\,a_1\,a_2)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   505
     $\textit{if}\;\textit{bnullable}\,a_1$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   506
					       & &$\textit{then}\;\textit{ALTS}\,bs\,List((\textit{SEQ}\,[]\,(a_1\,\backslash c)\,a_2),$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   507
					       & &$\phantom{\textit{then}\;\textit{ALTS}\,bs\,}(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\,\backslash c)))$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   508
  & &$\textit{else}\;\textit{SEQ}\,bs\,(a_1\,\backslash c)\,a_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   509
  $(\textit{STAR}\,bs\,a)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   510
      $\textit{SEQ}\;bs\,(\textit{fuse}\, [\Z] (r\,\backslash c))\,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   511
       (\textit{STAR}\,[]\,r)$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   512
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   513
\end{center}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   514
%\end{definition}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   515
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   516
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   517
For instance, when we unfold $\textit{STAR} \; bs \; a$ into a sequence,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   518
we need to attach an additional bit $Z$ to the front of $r \backslash c$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   519
to indicate that there is one more star iteration. Also the $SEQ$ clause
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   520
is more subtle---when $a_1$ is $\textit{bnullable}$ (here
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   521
\textit{bnullable} is exactly the same as $\textit{nullable}$, except
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   522
that it is for annotated regular expressions, therefore we omit the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   523
definition). Assume that $bmkeps$ correctly extracts the bitcode for how
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   524
$a_1$ matches the string prior to character $c$ (more on this later),
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   525
then the right branch of $ALTS$, which is $fuse \; bmkeps \;  a_1 (a_2
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   526
\backslash c)$ will collapse the regular expression $a_1$(as it has
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   527
already been fully matched) and store the parsing information at the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   528
head of the regular expression $a_2 \backslash c$ by fusing to it. The
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   529
bitsequence $bs$, which was initially attached to the head of $SEQ$, has
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   530
now been elevated to the top-level of $ALTS$, as this information will be
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   531
needed whichever way the $SEQ$ is matched---no matter whether $c$ belongs
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   532
to $a_1$ or $ a_2$. After building these derivatives and maintaining all
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   533
the lexing information, we complete the lexing by collecting the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   534
bitcodes using a generalised version of the $\textit{mkeps}$ function
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   535
for annotated regular expressions, called $\textit{bmkeps}$:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   536
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   537
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   538
%\begin{definition}[\textit{bmkeps}]\mbox{}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   539
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   540
\begin{tabular}{lcl}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   541
  $\textit{bmkeps}\,(\textit{ONE}\;bs)$ & $\dn$ & $bs$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   542
  $\textit{bmkeps}\,(\textit{ALTS}\;bs\,a::as)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   543
     $\textit{if}\;\textit{bnullable}\,a$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   544
  & &$\textit{then}\;bs\,@\,\textit{bmkeps}\,a$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   545
  & &$\textit{else}\;bs\,@\,\textit{bmkeps}\,(\textit{ALTS}\;bs\,as)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   546
  $\textit{bmkeps}\,(\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   547
     $bs \,@\,\textit{bmkeps}\,a_1\,@\, \textit{bmkeps}\,a_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   548
  $\textit{bmkeps}\,(\textit{STAR}\;bs\,a)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   549
     $bs \,@\, [\S]$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   550
\end{tabular}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   551
\end{center}    
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   552
%\end{definition}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   553
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   554
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   555
This function completes the value information by travelling along the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   556
path of the regular expression that corresponds to a POSIX value and
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   557
collecting all the bitcodes, and using $S$ to indicate the end of star
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   558
iterations. If we take the bitcodes produced by $\textit{bmkeps}$ and
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   559
decode them, we get the value we expect. The corresponding lexing
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   560
algorithm looks as follows:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   561
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   562
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   563
\begin{tabular}{lcl}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   564
  $\textit{blexer}\;r\,s$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   565
      $\textit{let}\;a = (r^\uparrow)\backslash s\;\textit{in}$\\                
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   566
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   567
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   568
  & & $\;\;\textit{else}\;\textit{None}$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   569
\end{tabular}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   570
\end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   571
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   572
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   573
In this definition $\_\backslash s$ is the  generalisation  of the derivative
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   574
operation from characters to strings (just like the derivatives for un-annotated
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   575
regular expressions).
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   576
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   577
The main point of the bitcodes and annotated regular expressions is that
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   578
we can apply rather aggressive (in terms of size) simplification rules
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   579
in order to keep derivatives small. We have developed such
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   580
``aggressive'' simplification rules and generated test data that show
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   581
that the expected bound can be achieved. Obviously we could only
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   582
partially cover  the search space as there are infinitely many regular
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   583
expressions and strings. 
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   584
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   585
One modification we introduced is to allow a list of annotated regular
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   586
expressions in the \textit{ALTS} constructor. This allows us to not just
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   587
delete unnecessary $\ZERO$s and $\ONE$s from regular expressions, but
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   588
also unnecessary ``copies'' of regular expressions (very similar to
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   589
simplifying $r + r$ to just $r$, but in a more general setting). Another
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   590
modification is that we use simplification rules inspired by Antimirov's
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   591
work on partial derivatives. They maintain the idea that only the first
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   592
``copy'' of a regular expression in an alternative contributes to the
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   593
calculation of a POSIX value. All subsequent copies can be pruned away from
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   594
the regular expression. A recursive definition of our  simplification function 
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   595
that looks somewhat similar to our Scala code is given below:
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   596
%\comment{Use $\ZERO$, $\ONE$ and so on. 
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   597
%Is it $ALTS$ or $ALTS$?}\\
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   598
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   599
\begin{center}
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   600
  \begin{tabular}{@{}lcl@{}}
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diff changeset
   601
   
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  $\textit{simp} \; (\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ & $ (\textit{simp} \; a_1, \textit{simp}  \; a_2) \; \textit{match} $ \\
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   603
   &&$\quad\textit{case} \; (\ZERO, \_) \Rightarrow  \ZERO$ \\
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   604
   &&$\quad\textit{case} \; (\_, \ZERO) \Rightarrow  \ZERO$ \\
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   &&$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$ \\
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   &&$\quad\textit{case} \; (a_1', \ONE) \Rightarrow  \textit{fuse} \; bs \;  a_1'$ \\
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   &&$\quad\textit{case} \; (a_1', a_2') \Rightarrow  \textit{SEQ} \; bs \; a_1' \;  a_2'$ \\
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diff changeset
   608
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   609
  $\textit{simp} \; (\textit{ALTS}\;bs\,as)$ & $\dn$ & $\textit{distinct}( \textit{flatten} ( \textit{map simp as})) \; \textit{match} $ \\
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   610
  &&$\quad\textit{case} \; [] \Rightarrow  \ZERO$ \\
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   611
   &&$\quad\textit{case} \; a :: [] \Rightarrow  \textit{fuse bs a}$ \\
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   612
   &&$\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$\\ 
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diff changeset
   613
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   614
   $\textit{simp} \; a$ & $\dn$ & $\textit{a} \qquad \textit{otherwise}$   
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   615
\end{tabular}    
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   616
\end{center}    
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   617
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   618
\noindent
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   619
The simplification does a pattern matching on the regular expression.
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   620
When it detected that the regular expression is an alternative or
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   621
sequence, it will try to simplify its children regular expressions
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   622
recursively and then see if one of the children turn into $\ZERO$ or
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   623
$\ONE$, which might trigger further simplification at the current level.
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   624
The most involved part is the $\textit{ALTS}$ clause, where we use two
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   625
auxiliary functions $\textit{flatten}$ and $\textit{distinct}$ to open up nested
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   626
$\textit{ALTS}$ and reduce as many duplicates as possible. Function
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   627
$\textit{distinct}$  keeps the first occurring copy only and remove all later ones
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   628
when detected duplicates. Function $\textit{flatten}$ opens up nested \textit{ALTS}.
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   629
Its recursive definition is given below:
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   630
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   631
 \begin{center}
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   632
  \begin{tabular}{@{}lcl@{}}
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   633
  $\textit{flatten} \; (\textit{ALTS}\;bs\,as) :: as'$ & $\dn$ & $(\textit{map} \;
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   634
     (\textit{fuse}\;bs)\; \textit{as}) \; @ \; \textit{flatten} \; as' $ \\
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   635
  $\textit{flatten} \; \textit{ZERO} :: as'$ & $\dn$ & $ \textit{flatten} \;  as' $ \\
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   636
    $\textit{flatten} \; a :: as'$ & $\dn$ & $a :: \textit{flatten} \; as'$ \quad(otherwise) 
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   637
\end{tabular}    
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   638
\end{center}  
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diff changeset
   639
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   640
\noindent
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   641
Here $\textit{flatten}$ behaves like the traditional functional programming flatten
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   642
function, except that it also removes $\ZERO$s. Or in terms of regular expressions, it
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   643
removes parentheses, for example changing $a+(b+c)$ into $a+b+c$.
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   644
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   645
Suppose we apply simplification after each derivative step, and view
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   646
these two operations as an atomic one: $a \backslash_{simp}\,c \dn
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   647
\textit{simp}(a \backslash c)$. Then we can use the previous natural
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   648
extension from derivative w.r.t.~character to derivative
b1e365afa29c changes
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   649
w.r.t.~string:%\comment{simp in  the [] case?}
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   650
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   651
\begin{center}
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   652
\begin{tabular}{lcl}
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diff changeset
   653
$r \backslash_{simp} (c\!::\!s) $ & $\dn$ & $(r \backslash_{simp}\, c) \backslash_{simp}\, s$ \\
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   654
$r \backslash_{simp} [\,] $ & $\dn$ & $r$
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   655
\end{tabular}
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   656
\end{center}
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diff changeset
   657
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   658
\noindent
b1e365afa29c changes
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   659
we obtain an optimised version of the algorithm:
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   660
b1e365afa29c changes
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diff changeset
   661
 \begin{center}
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diff changeset
   662
\begin{tabular}{lcl}
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diff changeset
   663
  $\textit{blexer\_simp}\;r\,s$ & $\dn$ &
b1e365afa29c changes
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diff changeset
   664
      $\textit{let}\;a = (r^\uparrow)\backslash_{simp}\, s\;\textit{in}$\\                
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diff changeset
   665
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
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diff changeset
   666
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
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   667
  & & $\;\;\textit{else}\;\textit{None}$
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diff changeset
   668
\end{tabular}
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diff changeset
   669
\end{center}
b1e365afa29c changes
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diff changeset
   670
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   671
\noindent
b1e365afa29c changes
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diff changeset
   672
This algorithm keeps the regular expression size small, for example,
b1e365afa29c changes
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diff changeset
   673
with this simplification our previous $(a + aa)^*$ example's 8000 nodes
b1e365afa29c changes
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   674
will be reduced to just 6 and stays constant, no matter how long the
b1e365afa29c changes
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diff changeset
   675
input string is.
b1e365afa29c changes
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diff changeset
   676
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   677
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   678
94
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   679
\section{Introduction}
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parents:
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   680
106
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diff changeset
   681
While we believe derivatives of regular expressions, written
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parents: 105 104
diff changeset
   682
$r\backslash s$, are a beautiful concept (in terms of ease of
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   683
implementing them in functional programming languages and in terms of
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   684
reasoning about them formally), they have one major drawback: every
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parents: 105 104
diff changeset
   685
derivative step can make regular expressions grow drastically in
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   686
size. This in turn has negative effect on the runtime of the
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   687
corresponding lexing algorithms. Consider for example the regular
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   688
expression $(a+aa)^*$ and the short string $aaaaaaaaaaaa$. The
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   689
corresponding derivative contains already 8668 nodes where we assume
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   690
the derivative is given as a tree. The reason for the poor runtime of
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   691
the derivative-based lexing algorithms is that they need to traverse
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   692
such trees over and over again. The solution is to find a complete set
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   693
of simplification rules that keep the sizes of derivatives uniformly
105
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   694
small.
94
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diff changeset
   695
105
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diff changeset
   696
For reasons beyond this report, it turns out that a complete set of
317a7d54ebcc updated
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diff changeset
   697
simplification rules depends on values being encoded as
317a7d54ebcc updated
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parents: 103
diff changeset
   698
bitsequences.\footnote{Values are the results the lexing algorithms
317a7d54ebcc updated
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parents: 103
diff changeset
   699
  generate; they encode how a regular expression matched a string.} We
317a7d54ebcc updated
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diff changeset
   700
already know that the lexing algorithm using bitsequences but
317a7d54ebcc updated
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parents: 103
diff changeset
   701
\emph{without} simplification is correct, albeilt horribly
106
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parents: 105 104
diff changeset
   702
slow. Therefore in the past 6 months I was trying to prove that the
105
317a7d54ebcc updated
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diff changeset
   703
algorithm using bitsequences plus our simplification rules is
106
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parents: 105 104
diff changeset
   704
also correct. Formally this amounts to show that
100
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diff changeset
   705
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diff changeset
   706
\begin{equation}\label{mainthm}
397b31867ea6 copied christian changes
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diff changeset
   707
\blexers \; r \; s = \blexer \;r\;s
397b31867ea6 copied christian changes
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diff changeset
   708
\end{equation}
397b31867ea6 copied christian changes
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diff changeset
   709
94
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diff changeset
   710
\noindent
105
317a7d54ebcc updated
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diff changeset
   711
whereby $\blexers$ simplifies (makes derivatives smaller) in each
317a7d54ebcc updated
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diff changeset
   712
step, whereas with $\blexer$ the size can grow exponentially. This
106
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parents: 105 104
diff changeset
   713
would be an important milestone for my thesis, because we already
105
317a7d54ebcc updated
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diff changeset
   714
have a very good idea how to establish that our set our simplification
317a7d54ebcc updated
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diff changeset
   715
rules keeps the size of derivativs below a relatively tight bound.
100
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   716
106
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parents: 105 104
diff changeset
   717
In order to prove the main theorem in \eqref{mainthm}, we need to prove that the
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   718
two functions produce the same output. The definition of these two  functions 
100
397b31867ea6 copied christian changes
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   719
is shown below.
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   720
94
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diff changeset
   721
\begin{center}
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parents:
diff changeset
   722
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
   723
  $\textit{blexer}\;r\,s$ & $\dn$ &
Chengsong
parents:
diff changeset
   724
      $\textit{let}\;a = (r^\uparrow)\backslash s\;\textit{in}$\\                
Chengsong
parents:
diff changeset
   725
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
Chengsong
parents:
diff changeset
   726
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
Chengsong
parents:
diff changeset
   727
  & & $\;\;\textit{else}\;\textit{None}$
Chengsong
parents:
diff changeset
   728
\end{tabular}
Chengsong
parents:
diff changeset
   729
\end{center}
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parents:
diff changeset
   730
100
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diff changeset
   731
\begin{center}
94
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parents:
diff changeset
   732
\begin{tabular}{lcl}
100
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diff changeset
   733
  $\blexers \; r \, s$ &$\dn$ &
397b31867ea6 copied christian changes
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diff changeset
   734
    $\textit{let} \; a = (r^\uparrow)\backslash_{simp}\, s\; \textit{in}$\\
397b31867ea6 copied christian changes
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diff changeset
   735
  & & $\; \; \textit{if} \; \textit{bnullable}(a)$\\
397b31867ea6 copied christian changes
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diff changeset
   736
  & & $\; \; \textit{then} \; \textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
397b31867ea6 copied christian changes
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diff changeset
   737
  & & $\;\;   \textit{else}\;\textit{None}$
94
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diff changeset
   738
\end{tabular}
Chengsong
parents:
diff changeset
   739
\end{center}
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parents:
diff changeset
   740
\noindent
105
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diff changeset
   741
In these definitions $(r^\uparrow)$ is a kind of coding function that
317a7d54ebcc updated
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diff changeset
   742
is the same in each case, similarly the decode and the \textit{bmkeps}
106
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parents: 105 104
diff changeset
   743
are functions that are the same in each case. Our main
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   744
theorem~\eqref{mainthm} therefore boils down to proving the following
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   745
two propositions (depending on which branch the if-else clause
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   746
takes). They establish how the derivatives \emph{with} simplification
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parents: 105 104
diff changeset
   747
do not change the computed result:
94
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   748
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diff changeset
   749
\begin{itemize}
105
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diff changeset
   750
\item{(a)} If a string $s$ is in the language of $L(r)$, then \\
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   751
$\textit{bmkeps} (r^\uparrow)\backslash_{simp}\,s = \textit{bmkeps} (r^\uparrow)\backslash s$,\\
105
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   752
\item{(b)} If a string $s$ is in the language $L(r)$, then 
100
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   753
$\rup \backslash_{simp} \,s$ is not nullable.
94
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   754
\end{itemize}
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diff changeset
   755
94
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parents:
diff changeset
   756
\noindent
106
e0db3242d8b5 added my comments
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parents: 105 104
diff changeset
   757
We have already proved the second part  in Isabelle. This is actually
105
317a7d54ebcc updated
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parents: 103
diff changeset
   758
not too difficult because we can show that simplification does not
317a7d54ebcc updated
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parents: 103
diff changeset
   759
change the language of simplified regular expressions.
100
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parents: 95
diff changeset
   760
105
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parents: 103
diff changeset
   761
If we can prove the first part, that is the bitsequence algorithm with
317a7d54ebcc updated
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parents: 103
diff changeset
   762
simplification produces the same result as the one without
317a7d54ebcc updated
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parents: 103
diff changeset
   763
simplification, then we are done.  Unfortunately that part requires
317a7d54ebcc updated
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parents: 103
diff changeset
   764
more effort, because simplification does not only need to \emph{not}
317a7d54ebcc updated
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parents: 103
diff changeset
   765
change the language, but also not change the value (that is the
317a7d54ebcc updated
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parents: 103
diff changeset
   766
computed result).
100
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parents: 95
diff changeset
   767
105
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parents: 103
diff changeset
   768
%\bigskip\noindent\rule[1.5ex]{\linewidth}{5pt}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   769
%Do you want to keep this? You essentially want to say that the old
317a7d54ebcc updated
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parents: 103
diff changeset
   770
%method used retrieve, which unfortunately cannot be adopted to 
317a7d54ebcc updated
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parents: 103
diff changeset
   771
%the simplification rules. You could just say that and give an example.
317a7d54ebcc updated
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parents: 103
diff changeset
   772
%However you have to think about how you give the example....nobody knows
317a7d54ebcc updated
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parents: 103
diff changeset
   773
%about AZERO etc yet. Maybe it might be better to use normal regexes
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   774
%like $a + aa$, but annotate bitsequences as subscript like $_1(_0a + _1aa)$.
104
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parents: 103
diff changeset
   775
105
317a7d54ebcc updated
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parents: 103
diff changeset
   776
%\bigskip\noindent\rule[1.5ex]{\linewidth}{5pt}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   777
%REPLY:\\
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   778
%Yes, I am essentially saying that the old method
317a7d54ebcc updated
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parents: 103
diff changeset
   779
%cannot be adopted without adjustments.
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   780
%But this does not mean we should skip
317a7d54ebcc updated
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parents: 103
diff changeset
   781
%the proof of the bit-coded algorithm
317a7d54ebcc updated
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parents: 103
diff changeset
   782
%as it is still the main direction we are looking into
317a7d54ebcc updated
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parents: 103
diff changeset
   783
%to prove things. We are trying to modify
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   784
%the old proof to suit our needs, but not give 
317a7d54ebcc updated
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parents: 103
diff changeset
   785
%up it totally, that is why i believe the old 
317a7d54ebcc updated
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parents: 103
diff changeset
   786
%proof is fundamental in understanding
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   787
%what we are doing in the past 6 months.
317a7d54ebcc updated
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parents: 103
diff changeset
   788
%\bigskip\noindent\rule[1.5ex]{\linewidth}{5pt}
100
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   789
106
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parents: 105 104
diff changeset
   790
\subsubsection*{Existing Proof}
100
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parents: 95
diff changeset
   791
104
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diff changeset
   792
For this we have started with looking at the original proof that
105
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parents: 103
diff changeset
   793
established that the bitsequence algorrithm produces the same result
317a7d54ebcc updated
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parents: 103
diff changeset
   794
as the algorithm not using bitsequences. Formally this proof
317a7d54ebcc updated
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parents: 103
diff changeset
   795
established
100
397b31867ea6 copied christian changes
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parents: 95
diff changeset
   796
105
317a7d54ebcc updated
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parents: 103
diff changeset
   797
\begin{equation}\label{lexer}
317a7d54ebcc updated
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parents: 103
diff changeset
   798
\blexer \; (r^\uparrow)  s = \lexer \;r \;s
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   799
\end{equation}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   800
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   801
%\noindent
317a7d54ebcc updated
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parents: 103
diff changeset
   802
%might provide us insight into proving 
317a7d54ebcc updated
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parents: 103
diff changeset
   803
%\begin{center}
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   804
%$\blexer \; r^\uparrow \;s = \blexers \; r^\uparrow \;s$
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   805
%\end{center}
104
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parents: 103
diff changeset
   806
94
Chengsong
parents:
diff changeset
   807
\noindent
106
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Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   808
The proof uses two ``tricks''. One is that it uses a \flex-function
104
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diff changeset
   809
94
Chengsong
parents:
diff changeset
   810
\begin{center}
Chengsong
parents:
diff changeset
   811
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
   812
$\textit{flex} \;r\; f\; (c\!::\!s) $ & $\dn$ & $\textit{flex} \;  (r\backslash c) \;(\lambda v. f (inj \; r \; c \; v)) \;s$ \\
Chengsong
parents:
diff changeset
   813
$\textit{flex} \;r\; f\;  [\,] $ & $\dn$ & $f$
Chengsong
parents:
diff changeset
   814
\end{tabular}
Chengsong
parents:
diff changeset
   815
\end{center}
104
e7ba4da53930 merged christian changes
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parents: 103
diff changeset
   816
94
Chengsong
parents:
diff changeset
   817
\noindent
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   818
and then proves for the right-hand side in \eqref{lexer}
104
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parents: 103
diff changeset
   819
e7ba4da53930 merged christian changes
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parents: 103
diff changeset
   820
\begin{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   821
$\lexer \;r\; s = \flex \;\textit{id} \; r\;s \;(\mkeps \; (r\backslash s))$
104
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   822
\end{center}.
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   823
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   824
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   825
104
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Chengsong
parents: 103
diff changeset
   826
e7ba4da53930 merged christian changes
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parents: 103
diff changeset
   827
\noindent
e7ba4da53930 merged christian changes
Chengsong
parents: 103
diff changeset
   828
The $\flex$-function essentially does lexing by
105
317a7d54ebcc updated
Christian Urban <urbanc@in.tum.de>
parents: 103
diff changeset
   829
stacking up injection functions while doing derivatives.
317a7d54ebcc updated
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parents: 103
diff changeset
   830
94
Chengsong
parents:
diff changeset
   831
explicitly showing the order of characters being
Chengsong
parents:
diff changeset
   832
injected back in each step.
Chengsong
parents:
diff changeset
   833
With $\flex$ we can write $\lexer$ this way: 
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   834
94
Chengsong
parents:
diff changeset
   835
\begin{center}
Chengsong
parents:
diff changeset
   836
$\lexer \;r\; s = \flex \;id \; r\;s \;(\mkeps r\backslash s)$
Chengsong
parents:
diff changeset
   837
\end{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   838
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   839
%\noindent
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   840
%$\flex$ focuses on the injections instead of the derivatives ,
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   841
%compared to the original definition of $\lexer$, which puts equal
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   842
%amount of emphasis on injection and derivative with respect to each
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   843
%character:
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   844
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   845
%\begin{center}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   846
%\begin{tabular}{lcl}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   847
%$\textit{lexer} \; r\; (c\!::\!s) $ & $\dn$ & $\textit{case} \; \lexer \; (r\backslash c) \;s \; %\textit{of}$ \\
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   848
% & & $\textit{None} \; \Longrightarrow \; \textit{None}$\\
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   849
%  & & $\textbar \; v \; \Longrightarrow \; \inj \; r\;c\;v$\\
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   850
%$\textit{lexer} \; r\;  [\,] $ & $\dn$ & $\textit{if} \; \nullable (r) \; \textit{then} \; \mkeps% (r) \; \textit{else} \;None$
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   851
%\end{tabular}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   852
%\end{center}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   853
94
Chengsong
parents:
diff changeset
   854
\noindent
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   855
The crux in the existing proof is how $\flex$ relates to injection, namely
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   856
94
Chengsong
parents:
diff changeset
   857
\begin{center}
Chengsong
parents:
diff changeset
   858
$\flex \; r \; id \; (s@[c]) \; v = \flex \;  r \; id \; s \; (inj \; (r\backslash s) \; c\; v)$.
Chengsong
parents:
diff changeset
   859
\end{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   860
94
Chengsong
parents:
diff changeset
   861
\noindent
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   862
This property allows one to rewrite an induction hypothesis like 
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   863
94
Chengsong
parents:
diff changeset
   864
\begin{center} 
Chengsong
parents:
diff changeset
   865
$ \flex \; r\; id\; (s@[c])\; v = \textit{decode} \;( \textit{retrieve}\; (\rup \backslash s) \; (\inj \; (r\backslash s) \;c\;v)\;) r$
Chengsong
parents:
diff changeset
   866
\end{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   867
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   868
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   869
\subsubsection{Retrieve Function}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   870
The crucial point is to find the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   871
$\textit{POSIX}$  information of a regular expression and how it is modified,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   872
augmented and propagated 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   873
during simplification in parallel with the regular expression that
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   874
has not been simplified in the subsequent derivative operations.  To aid this,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   875
we use the helper function retrieve described by Sulzmann and Lu:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   876
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   877
\begin{tabular}{@{}l@{\hspace{2mm}}c@{\hspace{2mm}}l@{}}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   878
  $\textit{retrieve}\,(\textit{ONE}\,bs)\,\Empty$ & $\dn$ & $bs$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   879
  $\textit{retrieve}\,(\textit{CHAR}\,bs\,c)\,(\Char\,d)$ & $\dn$ & $bs$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   880
  $\textit{retrieve}\,(\textit{ALTS}\,bs\,a::as)\,(\Left\,v)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   881
     $bs \,@\, \textit{retrieve}\,a\,v$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   882
  $\textit{retrieve}\,(\textit{ALTS}\,bs\,a::as)\,(\Right\,v)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   883
  $bs \,@\, \textit{retrieve}\,(\textit{ALTS}\,bs\,as)\,v$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   884
  $\textit{retrieve}\,(\textit{SEQ}\,bs\,a_1\,a_2)\,(\Seq\,v_1\,v_2)$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   885
     $bs \,@\,\textit{retrieve}\,a_1\,v_1\,@\, \textit{retrieve}\,a_2\,v_2$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   886
  $\textit{retrieve}\,(\textit{STAR}\,bs\,a)\,(\Stars\,[])$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   887
     $bs \,@\, [\S]$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   888
  $\textit{retrieve}\,(\textit{STAR}\,bs\,a)\,(\Stars\,(v\!::\!vs))$ & $\dn$ &\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   889
  \multicolumn{3}{l}{
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   890
     \hspace{3cm}$bs \,@\, [\Z] \,@\, \textit{retrieve}\,a\,v\,@\,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   891
                    \textit{retrieve}\,(\textit{STAR}\,[]\,a)\,(\Stars\,vs)$}\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   892
\end{tabular}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   893
\end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   894
%\comment{Did not read further}\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   895
This function assembles the bitcode 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   896
%that corresponds to a lexical value for how
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   897
%the current derivative matches the suffix of the string(the characters that
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   898
%have not yet appeared, but will appear as the successive derivatives go on.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   899
%How do we get this "future" information? By the value $v$, which is
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   900
%computed by a pass of the algorithm that uses
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   901
%$inj$ as described in the previous section).  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   902
using information from both the derivative regular expression and the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   903
value. Sulzmann and Lu poroposed this function, but did not prove
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   904
anything about it. Ausaf and Urban used it to connect the bitcoded
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   905
algorithm to the older algorithm by the following equation:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   906
 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   907
 \begin{center} $inj \;a\; c \; v = \textit{decode} \; (\textit{retrieve}\;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   908
	 (r^\uparrow)\backslash_{simp} \,c)\,v)$ 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   909
 \end{center} 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   910
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   911
\noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   912
whereby $r^\uparrow$ stands for the internalised version of $r$. Ausaf
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   913
and Urban also used this fact to prove  the correctness of bitcoded
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   914
algorithm without simplification.  Our purpose of using this, however,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   915
is to establish 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   916
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   917
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   918
$ \textit{retrieve} \;
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   919
a \; v \;=\; \textit{retrieve}  \; (\textit{simp}\,a) \; v'.$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   920
\end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   921
The idea is that using $v'$, a simplified version of $v$ that had gone
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   922
through the same simplification step as $\textit{simp}(a)$, we are able
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   923
to extract the bitcode that gives the same parsing information as the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   924
unsimplified one. However, we noticed that constructing such a  $v'$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   925
from $v$ is not so straightforward. The point of this is that  we might
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   926
be able to finally bridge the gap by proving
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   927
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   928
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   929
\noindent\rule[1.5ex]{\linewidth}{4pt}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   930
There is no mention of retrieve yet .... this is the second trick in the
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   931
existing proof. I am not sure whether you need to explain annotated regular
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   932
expressions much earlier - maybe before the ``existing proof'' section, or
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   933
evan earlier.
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   934
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   935
\noindent\rule[1.5ex]{\linewidth}{4pt}
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   936
94
Chengsong
parents:
diff changeset
   937
\noindent
Chengsong
parents:
diff changeset
   938
By using a property of retrieve we have the $\textit{RHS}$ of the above equality is
Chengsong
parents:
diff changeset
   939
$decode (retrieve (r^\uparrow \backslash(s @ [c])) v) r$, and this gives the 
Chengsong
parents:
diff changeset
   940
main lemma result:
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   941
94
Chengsong
parents:
diff changeset
   942
\begin{center}
Chengsong
parents:
diff changeset
   943
$ \flex \;r\;  id \; (s@[c]) \; v =\textit{decode}(\textit{retrieve} (\rup \backslash (s@[c])) \;v) r$
Chengsong
parents:
diff changeset
   944
\end{center}
106
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   945
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   946
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   947
e0db3242d8b5 added my comments
Christian Urban <urbanc@in.tum.de>
parents: 105 104
diff changeset
   948
94
Chengsong
parents:
diff changeset
   949
\noindent
Chengsong
parents:
diff changeset
   950
To use this lemma result for our 
Chengsong
parents:
diff changeset
   951
correctness proof, simply replace the $v$ in the
Chengsong
parents:
diff changeset
   952
$\textit{RHS}$ of the above equality with
Chengsong
parents:
diff changeset
   953
$\mkeps\;(r\backslash (s@[c]))$, and apply the lemma that
Chengsong
parents:
diff changeset
   954
 
Chengsong
parents:
diff changeset
   955
\begin{center}
Chengsong
parents:
diff changeset
   956
$\textit{decode} \; \bmkeps \; \rup \; r = \textit{decode} \; (\textit{retrieve} \; \rup \; \mkeps(r)) \;r$
Chengsong
parents:
diff changeset
   957
\end{center}
Chengsong
parents:
diff changeset
   958
\noindent
Chengsong
parents:
diff changeset
   959
We get the correctness of our bit-coded algorithm:
Chengsong
parents:
diff changeset
   960
\begin{center}
Chengsong
parents:
diff changeset
   961
$\flex \;r\;  id \; s \; (\mkeps \; r\backslash s) = \textit{decode} \; \bmkeps \; \rup\backslash s \; r$
Chengsong
parents:
diff changeset
   962
\end{center}
Chengsong
parents:
diff changeset
   963
\noindent
Chengsong
parents:
diff changeset
   964
The bridge between the above chain of equalities
Chengsong
parents:
diff changeset
   965
is the use of $\retrieve$,
Chengsong
parents:
diff changeset
   966
if we want to use a similar technique for the 
Chengsong
parents:
diff changeset
   967
simplified version of algorithm,
Chengsong
parents:
diff changeset
   968
we face the problem that in the above 
Chengsong
parents:
diff changeset
   969
equalities,
Chengsong
parents:
diff changeset
   970
$\retrieve \; a \; v$ is not always defined.
Chengsong
parents:
diff changeset
   971
for example,
100
397b31867ea6 copied christian changes
Chengsong
parents: 95
diff changeset
   972
$\retrieve \; _0(_1a+_0a) \; \Left(\Empty)$
101
Chengsong
parents: 100
diff changeset
   973
is defined, but not $\retrieve \; (_{01}a) \;\Left(\Empty)$,
94
Chengsong
parents:
diff changeset
   974
though we can extract the same POSIX
Chengsong
parents:
diff changeset
   975
bits from the two annotated regular expressions.
95
Chengsong
parents: 94
diff changeset
   976
The latter might occur when we try to retrieve from 
Chengsong
parents: 94
diff changeset
   977
a simplified regular expression using the same value
Chengsong
parents: 94
diff changeset
   978
as the unsimplified one.
Chengsong
parents: 94
diff changeset
   979
This is because $\Left(\Empty)$ corresponds to
101
Chengsong
parents: 100
diff changeset
   980
the regular expression structure $\ONE+r_2$ instead of
Chengsong
parents: 100
diff changeset
   981
$\ONE$.
94
Chengsong
parents:
diff changeset
   982
That means, if we 
Chengsong
parents:
diff changeset
   983
want to prove that 
Chengsong
parents:
diff changeset
   984
\begin{center}
Chengsong
parents:
diff changeset
   985
$\textit{decode} \; \bmkeps \; \rup\backslash s \; r = \textit{decode} \; \bmkeps \; \rup\backslash_{simp} s \; r$
Chengsong
parents:
diff changeset
   986
\end{center}
Chengsong
parents:
diff changeset
   987
\noindent
Chengsong
parents:
diff changeset
   988
holds by using $\retrieve$,
Chengsong
parents:
diff changeset
   989
we probably need to prove an equality like below:
Chengsong
parents:
diff changeset
   990
\begin{center}
Chengsong
parents:
diff changeset
   991
%$\retrieve \; \rup\backslash_{simp} s \; \mkeps(r\backslash_{simp} s)=\textit{retrieve} \; \rup\backslash s \; \mkeps(r\backslash s)$
101
Chengsong
parents: 100
diff changeset
   992
$\retrieve \; \rup\backslash_{simp} s \; \mkeps(f(r\backslash s))=\textit{retrieve} \; \rup\backslash s \; \mkeps(r\backslash s)$
94
Chengsong
parents:
diff changeset
   993
\end{center}
Chengsong
parents:
diff changeset
   994
\noindent
101
Chengsong
parents: 100
diff changeset
   995
$f$ rectifies $r\backslash s$ so the value $\mkeps(f(r\backslash s))$ becomes
Chengsong
parents: 100
diff changeset
   996
 something simpler
94
Chengsong
parents:
diff changeset
   997
to make the retrieve function defined.\\
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
   998
\subsubsection{Ways to Rectify Value}
95
Chengsong
parents: 94
diff changeset
   999
One way to do this is to prove the following:
Chengsong
parents: 94
diff changeset
  1000
\begin{center}
Chengsong
parents: 94
diff changeset
  1001
$\retrieve \; \rup\backslash_{simp} s \; \mkeps(\simp(r\backslash s))=\textit{retrieve} \; \rup\backslash s \; \mkeps(r\backslash s)$
Chengsong
parents: 94
diff changeset
  1002
\end{center}
Chengsong
parents: 94
diff changeset
  1003
\noindent
101
Chengsong
parents: 100
diff changeset
  1004
The reason why we choose $\simp$ as $f$ is because
Chengsong
parents: 100
diff changeset
  1005
$\rup\backslash_{simp} \, s$ and $\simp(\rup\backslash \, s)$
Chengsong
parents: 100
diff changeset
  1006
have the same shape:
Chengsong
parents: 100
diff changeset
  1007
\begin{center}
Chengsong
parents: 100
diff changeset
  1008
$\erase (\rup\backslash_{simp} \, s) = \erase(\simp(\rup\backslash s))$
Chengsong
parents: 100
diff changeset
  1009
\end{center}
Chengsong
parents: 100
diff changeset
  1010
Chengsong
parents: 100
diff changeset
  1011
\noindent
Chengsong
parents: 100
diff changeset
  1012
$\erase$ in the above equality means to remove the bit-codes
Chengsong
parents: 100
diff changeset
  1013
in an annotated regular expression and only keep the original
Chengsong
parents: 100
diff changeset
  1014
regular expression(just like "erasing" the bits). Its definition is omitted.
Chengsong
parents: 100
diff changeset
  1015
$\rup\backslash_{simp} \, s$ and $\simp(\rup\backslash s)$
Chengsong
parents: 100
diff changeset
  1016
are very closely related, but not identical.
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1017
\subsubsection{Example for $\rup\backslash_{simp} \, s \neq \simp(\rup\backslash s)$}
101
Chengsong
parents: 100
diff changeset
  1018
For example, let $r$ be the regular expression
Chengsong
parents: 100
diff changeset
  1019
$(a+b)(a+a*)$ and $s$  be the string $aa$, then
103
Chengsong
parents: 102
diff changeset
  1020
both $\erase (\rup\backslash_{simp} \, s)$ and $\erase (\simp (\rup\backslash s))$
Chengsong
parents: 102
diff changeset
  1021
are $\ONE + a^*$. However, without $\erase$ 
101
Chengsong
parents: 100
diff changeset
  1022
\begin{center}
Chengsong
parents: 100
diff changeset
  1023
$\rup\backslash_{simp} \, s$ is equal to $_0(_0\ONE +_{11}a^*)$
Chengsong
parents: 100
diff changeset
  1024
\end{center}
Chengsong
parents: 100
diff changeset
  1025
\noindent
Chengsong
parents: 100
diff changeset
  1026
whereas
Chengsong
parents: 100
diff changeset
  1027
\begin{center}
103
Chengsong
parents: 102
diff changeset
  1028
$\simp(\rup\backslash  s)$ is equal to $(_{00}\ONE +_{011}a^*)$
101
Chengsong
parents: 100
diff changeset
  1029
\end{center}
Chengsong
parents: 100
diff changeset
  1030
\noindent
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1031
(For the sake of visual simplicity, we use numbers to denote the bits
103
Chengsong
parents: 102
diff changeset
  1032
in bitcodes as we have previously defined for annotated 
Chengsong
parents: 102
diff changeset
  1033
regular expressions. $\S$ is replaced by 
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1034
subscript $_1$ and $\Z$ by $_0$.)
103
Chengsong
parents: 102
diff changeset
  1035
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1036
What makes the difference?
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1037
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1038
%Two "rules" might be inferred from the above example.
103
Chengsong
parents: 102
diff changeset
  1039
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1040
%First, after erasing the bits the two regular expressions
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1041
%are exactly the same: both become $1+a^*$. Here the 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1042
%function $\simp$ exhibits the "one in the end equals many times
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1043
%at the front"
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1044
%property: one simplification in the end causes the 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1045
%same regular expression structure as
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1046
%successive simplifications done alongside derivatives.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1047
%$\rup\backslash_{simp} \, s$ unfolds to 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1048
%$\simp((\simp(r\backslash a))\backslash a)$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1049
%and $\simp(\rup\backslash s)$ unfolds to 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1050
%$\simp((r\backslash a)\backslash a)$. The one simplification
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1051
%in the latter causes the resulting regular expression to 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1052
%become $1+a^*$, exactly the same as the former with
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1053
%two simplifications.
103
Chengsong
parents: 102
diff changeset
  1054
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1055
%Second, the bit-codes are different, but they are essentially
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1056
%the same: if we push the outmost bits ${\bf_0}(_0\ONE +_{11}a^*)$ of $\rup\backslash_{simp} \, s$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1057
%inside then we get $(_{00}\ONE +_{011}a^*)$, exactly the 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1058
%same as that of $\rup\backslash \, s$. And this difference 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1059
%does not matter when we try to apply $\bmkeps$ or $\retrieve$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1060
%to it. This seems a good news if we want to use $\retrieve$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1061
%to prove things.
103
Chengsong
parents: 102
diff changeset
  1062
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1063
%If we look into the difference above, we could see that the
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1064
%difference is not fundamental: the bits are just being moved
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1065
%around in a way that does not hurt the correctness.
103
Chengsong
parents: 102
diff changeset
  1066
During the first derivative operation, 
Chengsong
parents: 102
diff changeset
  1067
$\rup\backslash a=(_0\ONE  + \ZERO)(_0a  +  _1a^*)$  is
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1068
in the form of a sequence regular expression with
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1069
two components, the first
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1070
one $\ONE + \ZERO$ being nullable. 
103
Chengsong
parents: 102
diff changeset
  1071
Recall the simplification function definition:
Chengsong
parents: 102
diff changeset
  1072
\begin{center}
Chengsong
parents: 102
diff changeset
  1073
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents: 102
diff changeset
  1074
   
Chengsong
parents: 102
diff changeset
  1075
  $\textit{simp} \; (\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ & $ (\textit{simp} \; a_1, \textit{simp}  \; a_2) \; \textit{match} $ \\
Chengsong
parents: 102
diff changeset
  1076
   &&$\quad\textit{case} \; (\ZERO, \_) \Rightarrow  \ZERO$ \\
Chengsong
parents: 102
diff changeset
  1077
   &&$\quad\textit{case} \; (\_, \ZERO) \Rightarrow  \ZERO$ \\
Chengsong
parents: 102
diff changeset
  1078
   &&$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$ \\
Chengsong
parents: 102
diff changeset
  1079
   &&$\quad\textit{case} \; (a_1', \ONE) \Rightarrow  \textit{fuse} \; bs \;  a_1'$ \\
Chengsong
parents: 102
diff changeset
  1080
   &&$\quad\textit{case} \; (a_1', a_2') \Rightarrow  \textit{SEQ} \; bs \; a_1' \;  a_2'$ \\
Chengsong
parents: 102
diff changeset
  1081
Chengsong
parents: 102
diff changeset
  1082
  $\textit{simp} \; (\textit{ALTS}\;bs\,as)$ & $\dn$ & $\textit{distinct}( \textit{flatten} ( \textit{map simp as})) \; \textit{match} $ \\
Chengsong
parents: 102
diff changeset
  1083
  &&$\quad\textit{case} \; [] \Rightarrow  \ZERO$ \\
Chengsong
parents: 102
diff changeset
  1084
   &&$\quad\textit{case} \; a :: [] \Rightarrow  \textit{fuse bs a}$ \\
Chengsong
parents: 102
diff changeset
  1085
   &&$\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$\\ 
Chengsong
parents: 102
diff changeset
  1086
Chengsong
parents: 102
diff changeset
  1087
   $\textit{simp} \; a$ & $\dn$ & $\textit{a} \qquad \textit{otherwise}$   
Chengsong
parents: 102
diff changeset
  1088
\end{tabular}    
Chengsong
parents: 102
diff changeset
  1089
\end{center}    
Chengsong
parents: 102
diff changeset
  1090
Chengsong
parents: 102
diff changeset
  1091
\noindent
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1092
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1093
and the difinition of $\flatten$:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1094
 \begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1095
 \begin{tabular}{c c c}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1096
 $\flatten \; []$ & $\dn$ & $[]$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1097
 $\flatten \; \ZERO::rs$ & $\dn$ & $rs$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1098
 $\flatten \;(_{\textit{bs}_1}\oplus \textit{rs}_1 ::rs)$ & $\dn$ & $(\map \, (\fuse \, \textit{bs}_1) \,\textit{rs}_1) ::: \flatten(rs)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1099
 $\flatten \; r :: rs$ & $\dn$ & $r::\flatten(rs)$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1100
 \end{tabular}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1101
 \end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1102
 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1103
 \noindent
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1104
If we call $\simp$ on $\rup\backslash a$, just as $\backslash_{simp}$
103
Chengsong
parents: 102
diff changeset
  1105
requires, then we would go throught the third clause of 
Chengsong
parents: 102
diff changeset
  1106
the sequence case:$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$.
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1107
The $\ZERO$ of $(_0\ONE  + \ZERO)$ is thrown away 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1108
by $\flatten$ and 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1109
$_0\ONE$ merged into $(_0a  +  _1a^*)$ by simply
103
Chengsong
parents: 102
diff changeset
  1110
putting its bits($_0$) to the front of the second component:
Chengsong
parents: 102
diff changeset
  1111
 ${\bf_0}(_0a  +  _1a^*)$. 
Chengsong
parents: 102
diff changeset
  1112
 After a second derivative operation,
Chengsong
parents: 102
diff changeset
  1113
 namely, $(_0(_0a  +  _1a^*))\backslash a$, we get 
Chengsong
parents: 102
diff changeset
  1114
 $
Chengsong
parents: 102
diff changeset
  1115
 _0(_0 \ONE  +  _1(_1\ONE \cdot a^*))
Chengsong
parents: 102
diff changeset
  1116
 $, and this simplifies to $_0(_0 \ONE  +  _{11} a^*)$
Chengsong
parents: 102
diff changeset
  1117
 by the third clause of the alternative case:
Chengsong
parents: 102
diff changeset
  1118
 $\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$.
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1119
The outmost bit $_0$ stays with 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1120
the outmost regular expression, rather than being fused to
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1121
its child regular expressions, as what we will later see happens
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1122
to $\simp(\rup\backslash \, s)$.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1123
If we choose to not simplify in the midst of derivative operations,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1124
but only do it at the end after the string has been exhausted, 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1125
namely, $\simp(\rup\backslash \, s)=\simp((\rup\backslash a)\backslash a)$,
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1126
then at the {\bf second} derivative of 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1127
$(\rup\backslash a)\bf{\backslash a}$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1128
we will go throught the clause of $\backslash$:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1129
\begin{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1130
\begin{tabular}{lcl}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1131
$(\textit{SEQ}\;bs\,a_1\,a_2)\,\backslash c$ & $\dn$ &
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1132
     $(when \; \textit{bnullable}\,a_1)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1133
					       & &$\textit{ALTS}\,bs\,List(\;\;(\textit{SEQ}\,[]\,(a_1\,\backslash c)\,a_2),$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1134
					       & &$(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\,\backslash c))\;\;)$\\
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1135
\end{tabular}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1136
\end{center}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1137
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1138
because
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1139
$\rup\backslash a = (_0\ONE  + \ZERO)(_0a  +  _1a^*)$  
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1140
is a sequence
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1141
with the first component being nullable
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1142
(unsimplified, unlike the first round of running$\backslash_{simp}$).
103
Chengsong
parents: 102
diff changeset
  1143
Therefore $((_0\ONE  + \ZERO)(_0a  +  _1a^*))\backslash a$ splits into
Chengsong
parents: 102
diff changeset
  1144
$([(\ZERO + \ZERO)\cdot(_0a  +  _1a^*)] + _0( _0\ONE  + _1[_1\ONE \cdot a^*]))$.
Chengsong
parents: 102
diff changeset
  1145
After these two successive derivatives without simplification,
Chengsong
parents: 102
diff changeset
  1146
we apply $\simp$ to this regular expression, which goes through
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1147
the alternative clause, and each component of 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1148
$([(\ZERO + \ZERO)\cdot(_0a  +  _1a^*)] + _0( _0\ONE  + _1[_1\ONE \cdot a^*]))$ 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1149
will be simplified, giving us the list:$[\ZERO, _0(_0\ONE  + _{11}a^*)]$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1150
This list is then "flattened"--$\ZERO$ will be
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1151
thrown away by $\textit{flatten}$; $ _0(_0\ONE  + _{11}a^*)$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1152
is opened up to make the list consisting of two separate elements 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1153
$_{00}\ONE$ and $_{011}a^*$, note that $flatten$ 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1154
$\fuse$s the bit(s) $_0$ to the front of $_0\ONE $ and $_{11}a^*$.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1155
In a nutshell, the order of simplification causes
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1156
the bits to be moved differently.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1157
 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1158
 \subsubsection{A Failed Attempt To Remedy the Problem Above}
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1159
A simple class of regular expressions and strings 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1160
pairs can be deduced 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1161
from the above example which 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1162
trigger the difference between 
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1163
$\rup\backslash_{simp} \, s$
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1164
and  $\simp(\rup\backslash s)$:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1165
\[
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1166
D = (c_1c_2, \{r_1\cdot r_2 \mid \text{$ c_1\in L(r_1), r_1 \; not \; \nullable, c_2 \in L(r_2),
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1167
r_2 \backslash c_2$ is of shape alternative  and $c_1c_2 \notin L(r_1)$}\})
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1168
\]
102
Chengsong
parents: 101
diff changeset
  1169
and we can use this to construct a set of examples based 
103
Chengsong
parents: 102
diff changeset
  1170
on this type of behaviour of two operations:
Chengsong
parents: 102
diff changeset
  1171
$r_1$
101
Chengsong
parents: 100
diff changeset
  1172
that is to say, despite the bits are being moved around on the regular expression
Chengsong
parents: 100
diff changeset
  1173
(difference in bits), the structure of the (unannotated)regular expression
Chengsong
parents: 100
diff changeset
  1174
after one simplification is exactly the same after the 
Chengsong
parents: 100
diff changeset
  1175
same sequence of derivative operations 
Chengsong
parents: 100
diff changeset
  1176
regardless of whether we did simplification
Chengsong
parents: 100
diff changeset
  1177
along the way.
107
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1178
 One way would be to give a function that calls
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1179
 %CONSTRUCTION SITE
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1180
fuse is the culprit: it causes the order in which alternatives
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1181
are opened up to be remembered and finally the difference
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1182
appear in $\simp(\rup \backslash s)$ and $\rup \backslash{simp} \,s$.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1183
but we have to use them as they are essential in the simplification:
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1184
flatten needs them.
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1185
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1186
b1e365afa29c changes
Chengsong
parents: 106
diff changeset
  1187
101
Chengsong
parents: 100
diff changeset
  1188
However, without erase the above equality does not hold:
Chengsong
parents: 100
diff changeset
  1189
for the regular expression  
Chengsong
parents: 100
diff changeset
  1190
$(a+b)(a+a*)$,
Chengsong
parents: 100
diff changeset
  1191
if we do derivative with respect to string $aa$,
Chengsong
parents: 100
diff changeset
  1192
we get
103
Chengsong
parents: 102
diff changeset
  1193
101
Chengsong
parents: 100
diff changeset
  1194
sdddddr does not equal sdsdsdsr sometimes.\\
Chengsong
parents: 100
diff changeset
  1195
For example,
Chengsong
parents: 100
diff changeset
  1196
Chengsong
parents: 100
diff changeset
  1197
This equicalence class method might still have the potential of proving this,
Chengsong
parents: 100
diff changeset
  1198
but not yet
Chengsong
parents: 100
diff changeset
  1199
i parallelly tried another method of using retrieve\\
Chengsong
parents: 100
diff changeset
  1200
Chengsong
parents: 100
diff changeset
  1201
Chengsong
parents: 100
diff changeset
  1202
94
Chengsong
parents:
diff changeset
  1203
%HERE CONSTRUCTION SITE
Chengsong
parents:
diff changeset
  1204
The vsimp function, defined as follows
Chengsong
parents:
diff changeset
  1205
tries to simplify the value in lockstep with 
Chengsong
parents:
diff changeset
  1206
regular expression:\\
Chengsong
parents:
diff changeset
  1207
Chengsong
parents:
diff changeset
  1208
Chengsong
parents:
diff changeset
  1209
The problem here is that 
Chengsong
parents:
diff changeset
  1210
Chengsong
parents:
diff changeset
  1211
we used retrieve for the key induction:
Chengsong
parents:
diff changeset
  1212
$decode (retrieve (r\backslash (s @ [c])) v) r $
Chengsong
parents:
diff changeset
  1213
$decode (retrieve (r\backslash s) (inj (r\backslash s) c v)) r$
Chengsong
parents:
diff changeset
  1214
Here, decode recovers a value that corresponds to a match(possibly partial)
Chengsong
parents:
diff changeset
  1215
from bits, and the bits are extracted by retrieve,
Chengsong
parents:
diff changeset
  1216
and the key value $v$ that guides retrieve is
Chengsong
parents:
diff changeset
  1217
$mkeps r\backslash s$, $inj r c (mkeps r\backslash s)$, $inj (inj (v))$, ......
Chengsong
parents:
diff changeset
  1218
if we can 
Chengsong
parents:
diff changeset
  1219
the problem is that 
Chengsong
parents:
diff changeset
  1220
need vsiimp to make a value that is suitable for decoding
Chengsong
parents:
diff changeset
  1221
$Some(flex rid(s@[c])v) = Some(flex rids(inj (r\backslash s)cv))$
Chengsong
parents:
diff changeset
  1222
another way that christian came up with that might circumvent the 
Chengsong
parents:
diff changeset
  1223
prblem of finding suitable value is by not stating the visimp
Chengsong
parents:
diff changeset
  1224
function but include all possible value in a set that a regex is able to produce,
Chengsong
parents:
diff changeset
  1225
and proving that both r and sr are able to produce the bits that correspond the POSIX value
Chengsong
parents:
diff changeset
  1226
Chengsong
parents:
diff changeset
  1227
produced by feeding the same initial regular expression $r$ and string $s$ to the
Chengsong
parents:
diff changeset
  1228
 two functions $ders$ and $ders\_simp$.
Chengsong
parents:
diff changeset
  1229
The reason why
Chengsong
parents:
diff changeset
  1230
Namely, if $bmkeps( r_1) = bmkeps(r_2)$, then we 
Chengsong
parents:
diff changeset
  1231
Chengsong
parents:
diff changeset
  1232
Chengsong
parents:
diff changeset
  1233
If we define the equivalence relation $\sim_{m\epsilon}$ between two regular expressions
Chengsong
parents:
diff changeset
  1234
$r_1$ and $r_2$as follows:
Chengsong
parents:
diff changeset
  1235
$r_1 \sim_{m\epsilon} r_2  \iff bmkeps(r_1)= bmkeps(r_2)$
Chengsong
parents:
diff changeset
  1236
(in other words, they $r1$ and $r2$ produce the same output under the function $bmkeps$.)
Chengsong
parents:
diff changeset
  1237
Then the first goal 
Chengsong
parents:
diff changeset
  1238
might be restated as 
Chengsong
parents:
diff changeset
  1239
$(r^\uparrow)\backslash_{simp}\, s  \sim_{m\epsilon} (r^\uparrow)\backslash s$.
Chengsong
parents:
diff changeset
  1240
I tried to establish an equivalence relation between the regular experssions 
Chengsong
parents:
diff changeset
  1241
like dddr dddsr,.....
Chengsong
parents:
diff changeset
  1242
but right now i am only able to establish dsr and dr, using structural induction on r.
Chengsong
parents:
diff changeset
  1243
Those involve multiple derivative operations are harder to prove.
Chengsong
parents:
diff changeset
  1244
Two attempts have been made:
Chengsong
parents:
diff changeset
  1245
(1)induction on the number of der operations(or in other words, the length of the string s),
Chengsong
parents:
diff changeset
  1246
the inductive hypothesis was initially specified as 
Chengsong
parents:
diff changeset
  1247
"For an arbitrary regular expression r, 
Chengsong
parents:
diff changeset
  1248
For all string s in the language of r whose length do not exceed 
Chengsong
parents:
diff changeset
  1249
the number n, ders s r me derssimp s r"
Chengsong
parents:
diff changeset
  1250
and the proof goal may be stated as
Chengsong
parents:
diff changeset
  1251
"For an arbitrary regular expression r, 
Chengsong
parents:
diff changeset
  1252
For all string s in the language of r whose length do not exceed 
Chengsong
parents:
diff changeset
  1253
the number n+1, ders s r me derssimp s r"
Chengsong
parents:
diff changeset
  1254
the problem here is that although we can easily break down
Chengsong
parents:
diff changeset
  1255
a string s of length n+1 into s1@list(c), it is not that easy
Chengsong
parents:
diff changeset
  1256
to use the i.h. as a stepping stone to prove anything because s1 may well be not
Chengsong
parents:
diff changeset
  1257
in the language L(r). This inhibits us from obtaining the fact that
Chengsong
parents:
diff changeset
  1258
ders s1 r me derssimps s1 r.
Chengsong
parents:
diff changeset
  1259
Further exploration is needed to amend this hypothesis so it includes the
Chengsong
parents:
diff changeset
  1260
situation when s1 is not nullable.
Chengsong
parents:
diff changeset
  1261
For example, what information(bits? 
Chengsong
parents:
diff changeset
  1262
values?) can be extracted
Chengsong
parents:
diff changeset
  1263
from the regular expression ders(s1,r) so that we can compute or predict the possible 
Chengsong
parents:
diff changeset
  1264
result of bmkeps after another derivative operation. What function f can used to 
Chengsong
parents:
diff changeset
  1265
carry out the task? The possible way of exploration can be 
Chengsong
parents:
diff changeset
  1266
more directly perceived throught the graph below:
Chengsong
parents:
diff changeset
  1267
find a function
Chengsong
parents:
diff changeset
  1268
f
Chengsong
parents:
diff changeset
  1269
such that
Chengsong
parents:
diff changeset
  1270
f(bders s1 r)
Chengsong
parents:
diff changeset
  1271
= re1
Chengsong
parents:
diff changeset
  1272
f(bderss s1 r)
Chengsong
parents:
diff changeset
  1273
= re2
Chengsong
parents:
diff changeset
  1274
bmkeps(bders s r) = g(re1,c)
Chengsong
parents:
diff changeset
  1275
bmkeps(bderssimp s r) = g(re2,c)
Chengsong
parents:
diff changeset
  1276
and g(re1,c) = g(re2,c)
Chengsong
parents:
diff changeset
  1277
The inductive hypothesis would be
Chengsong
parents:
diff changeset
  1278
"For all strings s1 of length <= n, 
Chengsong
parents:
diff changeset
  1279
f(bders s1 r)
Chengsong
parents:
diff changeset
  1280
= re1
Chengsong
parents:
diff changeset
  1281
f(bderss s1 r)
Chengsong
parents:
diff changeset
  1282
= re2"
Chengsong
parents:
diff changeset
  1283
proving this would be a lemma for the main proof:
Chengsong
parents:
diff changeset
  1284
the main proof would be 
Chengsong
parents:
diff changeset
  1285
"
Chengsong
parents:
diff changeset
  1286
bmkeps(bders s r) = g(re1,c)
Chengsong
parents:
diff changeset
  1287
bmkeps(bderssimp s r) = g(re2,c)
Chengsong
parents:
diff changeset
  1288
for s = s1@c
Chengsong
parents:
diff changeset
  1289
"
Chengsong
parents:
diff changeset
  1290
and f need to be a recursive property for the lemma to be proved:
Chengsong
parents:
diff changeset
  1291
it needs to store not only the "after one char nullable info",
Chengsong
parents:
diff changeset
  1292
but also the "after two char nullable info",
Chengsong
parents:
diff changeset
  1293
and so on so that it is able to  predict what f will compute after a derivative operation,
Chengsong
parents:
diff changeset
  1294
in other words, it needs to be "infinitely recursive"\\
Chengsong
parents:
diff changeset
  1295
To prove the lemma, in other words, to get
Chengsong
parents:
diff changeset
  1296
"For all strings s1 of length <= n+1, 
Chengsong
parents:
diff changeset
  1297
f(bders s1 r)
Chengsong
parents:
diff changeset
  1298
= re3
Chengsong
parents:
diff changeset
  1299
f(bderss s1 r)
Chengsong
parents:
diff changeset
  1300
= re4"\\
Chengsong
parents:
diff changeset
  1301
from\\
Chengsong
parents:
diff changeset
  1302
"For all strings s1 of length <= n, 
Chengsong
parents:
diff changeset
  1303
f(bders s1 r)
Chengsong
parents:
diff changeset
  1304
= re1
Chengsong
parents:
diff changeset
  1305
f(bderss s1 r)
Chengsong
parents:
diff changeset
  1306
= re2"\\
Chengsong
parents:
diff changeset
  1307
it might be best to construct an auxiliary function h such that\\
Chengsong
parents:
diff changeset
  1308
h(re1, c) = re3\\
Chengsong
parents:
diff changeset
  1309
h(re2, c) = re4\\
Chengsong
parents:
diff changeset
  1310
and re3 = f(bder c (bders s1 r))\\
Chengsong
parents:
diff changeset
  1311
re4 = f(simp(bder c (bderss s1 r)))
Chengsong
parents:
diff changeset
  1312
The key point here is that we are not satisfied with what bders s r will produce under
Chengsong
parents:
diff changeset
  1313
bmkeps, but also how it will perform after a derivative operation and then bmkeps, and two 
Chengsong
parents:
diff changeset
  1314
derivative operations and so on. In essence, we are preserving the regular expression 
Chengsong
parents:
diff changeset
  1315
itself under the function f, in a less compact way than the regluar expression: we are
Chengsong
parents:
diff changeset
  1316
not just recording but also interpreting what the regular expression matches.
Chengsong
parents:
diff changeset
  1317
In other words, we need to prove the properties of bderss s r beyond the bmkeps result,
Chengsong
parents:
diff changeset
  1318
i.e., not just the nullable ones, but also those containing remaining characters.\\
Chengsong
parents:
diff changeset
  1319
(2)we observed the fact that 
Chengsong
parents:
diff changeset
  1320
erase sdddddr= erase sdsdsdsr
Chengsong
parents:
diff changeset
  1321
that is to say, despite the bits are being moved around on the regular expression
Chengsong
parents:
diff changeset
  1322
(difference in bits), the structure of the (unannotated)regular expression
Chengsong
parents:
diff changeset
  1323
after one simplification is exactly the same after the 
Chengsong
parents:
diff changeset
  1324
same sequence of derivative operations 
Chengsong
parents:
diff changeset
  1325
regardless of whether we did simplification
Chengsong
parents:
diff changeset
  1326
along the way.
Chengsong
parents:
diff changeset
  1327
However, without erase the above equality does not hold:
Chengsong
parents:
diff changeset
  1328
for the regular expression  
Chengsong
parents:
diff changeset
  1329
$(a+b)(a+a*)$,
Chengsong
parents:
diff changeset
  1330
if we do derivative with respect to string $aa$,
Chengsong
parents:
diff changeset
  1331
we get
Chengsong
parents:
diff changeset
  1332
%TODO
Chengsong
parents:
diff changeset
  1333
sdddddr does not equal sdsdsdsr sometimes.\\
Chengsong
parents:
diff changeset
  1334
For example,
Chengsong
parents:
diff changeset
  1335
Chengsong
parents:
diff changeset
  1336
This equicalence class method might still have the potential of proving this,
Chengsong
parents:
diff changeset
  1337
but not yet
Chengsong
parents:
diff changeset
  1338
i parallelly tried another method of using retrieve\\
Chengsong
parents:
diff changeset
  1339
Chengsong
parents:
diff changeset
  1340
Chengsong
parents:
diff changeset
  1341
Chengsong
parents:
diff changeset
  1342
\noindent\rule[0.5ex]{\linewidth}{1pt}
Chengsong
parents:
diff changeset
  1343
Chengsong
parents:
diff changeset
  1344
This PhD-project is about regular expression matching and
Chengsong
parents:
diff changeset
  1345
lexing. Given the maturity of this topic, the reader might wonder:
Chengsong
parents:
diff changeset
  1346
Surely, regular expressions must have already been studied to death?
Chengsong
parents:
diff changeset
  1347
What could possibly be \emph{not} known in this area? And surely all
Chengsong
parents:
diff changeset
  1348
implemented algorithms for regular expression matching are blindingly
Chengsong
parents:
diff changeset
  1349
fast?
Chengsong
parents:
diff changeset
  1350
Chengsong
parents:
diff changeset
  1351
Unfortunately these preconceptions are not supported by evidence: Take
Chengsong
parents:
diff changeset
  1352
for example the regular expression $(a^*)^*\,b$ and ask whether
Chengsong
parents:
diff changeset
  1353
strings of the form $aa..a$ match this regular
Chengsong
parents:
diff changeset
  1354
expression. Obviously this is not the case---the expected $b$ in the last
Chengsong
parents:
diff changeset
  1355
position is missing. One would expect that modern regular expression
Chengsong
parents:
diff changeset
  1356
matching engines can find this out very quickly. Alas, if one tries
Chengsong
parents:
diff changeset
  1357
this example in JavaScript, Python or Java 8 with strings like 28
Chengsong
parents:
diff changeset
  1358
$a$'s, one discovers that this decision takes around 30 seconds and
Chengsong
parents:
diff changeset
  1359
takes considerably longer when adding a few more $a$'s, as the graphs
Chengsong
parents:
diff changeset
  1360
below show:
Chengsong
parents:
diff changeset
  1361
Chengsong
parents:
diff changeset
  1362
\begin{center}
Chengsong
parents:
diff changeset
  1363
\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}}
Chengsong
parents:
diff changeset
  1364
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  1365
\begin{axis}[
Chengsong
parents:
diff changeset
  1366
    xlabel={$n$},
Chengsong
parents:
diff changeset
  1367
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  1368
    ylabel={time in secs},
Chengsong
parents:
diff changeset
  1369
    enlargelimits=false,
Chengsong
parents:
diff changeset
  1370
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  1371
    xmax=33,
Chengsong
parents:
diff changeset
  1372
    ymax=35,
Chengsong
parents:
diff changeset
  1373
    ytick={0,5,...,30},
Chengsong
parents:
diff changeset
  1374
    scaled ticks=false,
Chengsong
parents:
diff changeset
  1375
    axis lines=left,
Chengsong
parents:
diff changeset
  1376
    width=5cm,
Chengsong
parents:
diff changeset
  1377
    height=4cm, 
Chengsong
parents:
diff changeset
  1378
    legend entries={JavaScript},  
Chengsong
parents:
diff changeset
  1379
    legend pos=north west,
Chengsong
parents:
diff changeset
  1380
    legend cell align=left]
Chengsong
parents:
diff changeset
  1381
\addplot[red,mark=*, mark options={fill=white}] table {re-js.data};
Chengsong
parents:
diff changeset
  1382
\end{axis}
Chengsong
parents:
diff changeset
  1383
\end{tikzpicture}
Chengsong
parents:
diff changeset
  1384
  &
Chengsong
parents:
diff changeset
  1385
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  1386
\begin{axis}[
Chengsong
parents:
diff changeset
  1387
    xlabel={$n$},
Chengsong
parents:
diff changeset
  1388
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  1389
    %ylabel={time in secs},
Chengsong
parents:
diff changeset
  1390
    enlargelimits=false,
Chengsong
parents:
diff changeset
  1391
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  1392
    xmax=33,
Chengsong
parents:
diff changeset
  1393
    ymax=35,
Chengsong
parents:
diff changeset
  1394
    ytick={0,5,...,30},
Chengsong
parents:
diff changeset
  1395
    scaled ticks=false,
Chengsong
parents:
diff changeset
  1396
    axis lines=left,
Chengsong
parents:
diff changeset
  1397
    width=5cm,
Chengsong
parents:
diff changeset
  1398
    height=4cm, 
Chengsong
parents:
diff changeset
  1399
    legend entries={Python},  
Chengsong
parents:
diff changeset
  1400
    legend pos=north west,
Chengsong
parents:
diff changeset
  1401
    legend cell align=left]
Chengsong
parents:
diff changeset
  1402
\addplot[blue,mark=*, mark options={fill=white}] table {re-python2.data};
Chengsong
parents:
diff changeset
  1403
\end{axis}
Chengsong
parents:
diff changeset
  1404
\end{tikzpicture}
Chengsong
parents:
diff changeset
  1405
  &
Chengsong
parents:
diff changeset
  1406
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  1407
\begin{axis}[
Chengsong
parents:
diff changeset
  1408
    xlabel={$n$},
Chengsong
parents:
diff changeset
  1409
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  1410
    %ylabel={time in secs},
Chengsong
parents:
diff changeset
  1411
    enlargelimits=false,
Chengsong
parents:
diff changeset
  1412
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  1413
    xmax=33,
Chengsong
parents:
diff changeset
  1414
    ymax=35,
Chengsong
parents:
diff changeset
  1415
    ytick={0,5,...,30},
Chengsong
parents:
diff changeset
  1416
    scaled ticks=false,
Chengsong
parents:
diff changeset
  1417
    axis lines=left,
Chengsong
parents:
diff changeset
  1418
    width=5cm,
Chengsong
parents:
diff changeset
  1419
    height=4cm, 
Chengsong
parents:
diff changeset
  1420
    legend entries={Java 8},  
Chengsong
parents:
diff changeset
  1421
    legend pos=north west,
Chengsong
parents:
diff changeset
  1422
    legend cell align=left]
Chengsong
parents:
diff changeset
  1423
\addplot[cyan,mark=*, mark options={fill=white}] table {re-java.data};
Chengsong
parents:
diff changeset
  1424
\end{axis}
Chengsong
parents:
diff changeset
  1425
\end{tikzpicture}\\
Chengsong
parents:
diff changeset
  1426
\multicolumn{3}{c}{Graphs: Runtime for matching $(a^*)^*\,b$ with strings 
Chengsong
parents:
diff changeset
  1427
           of the form $\underbrace{aa..a}_{n}$.}
Chengsong
parents:
diff changeset
  1428
\end{tabular}    
Chengsong
parents:
diff changeset
  1429
\end{center}  
Chengsong
parents:
diff changeset
  1430
Chengsong
parents:
diff changeset
  1431
\noindent These are clearly abysmal and possibly surprising results. One
Chengsong
parents:
diff changeset
  1432
would expect these systems to do  much better than that---after all,
Chengsong
parents:
diff changeset
  1433
given a DFA and a string, deciding whether a string is matched by this
Chengsong
parents:
diff changeset
  1434
DFA should be linear in terms of the size of the regular expression and
Chengsong
parents:
diff changeset
  1435
the string?
Chengsong
parents:
diff changeset
  1436
Chengsong
parents:
diff changeset
  1437
Admittedly, the regular expression $(a^*)^*\,b$ is carefully chosen to
Chengsong
parents:
diff changeset
  1438
exhibit this super-linear behaviour.  But unfortunately, such regular
Chengsong
parents:
diff changeset
  1439
expressions are not just a few outliers. They are actually 
Chengsong
parents:
diff changeset
  1440
frequent enough to have a separate name created for
Chengsong
parents:
diff changeset
  1441
them---\emph{evil regular expressions}. In empiric work, Davis et al
Chengsong
parents:
diff changeset
  1442
report that they have found thousands of such evil regular expressions
Chengsong
parents:
diff changeset
  1443
in the JavaScript and Python ecosystems \cite{Davis18}. Static analysis
Chengsong
parents:
diff changeset
  1444
approach that is both sound and complete exists\cite{17Bir}, but the running 
Chengsong
parents:
diff changeset
  1445
time on certain examples in the RegExLib and Snort regular expressions
Chengsong
parents:
diff changeset
  1446
libraries is unacceptable. Therefore the problem of efficiency still remains.
Chengsong
parents:
diff changeset
  1447
Chengsong
parents:
diff changeset
  1448
This superlinear blowup in matching algorithms sometimes causes
Chengsong
parents:
diff changeset
  1449
considerable grief in real life: for example on 20 July 2016 one evil
Chengsong
parents:
diff changeset
  1450
regular expression brought the webpage
Chengsong
parents:
diff changeset
  1451
\href{http://stackexchange.com}{Stack Exchange} to its
Chengsong
parents:
diff changeset
  1452
knees.\footnote{\url{https://stackstatus.net/post/147710624694/outage-postmortem-july-20-2016}}
Chengsong
parents:
diff changeset
  1453
In this instance, a regular expression intended to just trim white
Chengsong
parents:
diff changeset
  1454
spaces from the beginning and the end of a line actually consumed
Chengsong
parents:
diff changeset
  1455
massive amounts of CPU-resources---causing web servers to grind to a
Chengsong
parents:
diff changeset
  1456
halt. This happened when a post with 20,000 white spaces was submitted,
Chengsong
parents:
diff changeset
  1457
but importantly the white spaces were neither at the beginning nor at
Chengsong
parents:
diff changeset
  1458
the end. As a result, the regular expression matching engine needed to
Chengsong
parents:
diff changeset
  1459
backtrack over many choices. In this example, the time needed to process
Chengsong
parents:
diff changeset
  1460
the string was $O(n^2)$ with respect to the string length. This
Chengsong
parents:
diff changeset
  1461
quadratic overhead was enough for the homepage of Stack Exchange to
Chengsong
parents:
diff changeset
  1462
respond so slowly that the load balancer assumed there must be some
Chengsong
parents:
diff changeset
  1463
attack and therefore stopped the servers from responding to any
Chengsong
parents:
diff changeset
  1464
requests. This made the whole site become unavailable. Another very
Chengsong
parents:
diff changeset
  1465
recent example is a global outage of all Cloudflare servers on 2 July
Chengsong
parents:
diff changeset
  1466
2019. A poorly written regular expression exhibited exponential
Chengsong
parents:
diff changeset
  1467
behaviour and exhausted CPUs that serve HTTP traffic. Although the
Chengsong
parents:
diff changeset
  1468
outage had several causes, at the heart was a regular expression that
Chengsong
parents:
diff changeset
  1469
was used to monitor network
Chengsong
parents:
diff changeset
  1470
traffic.\footnote{\url{https://blog.cloudflare.com/details-of-the-cloudflare-outage-on-july-2-2019/}}
Chengsong
parents:
diff changeset
  1471
Chengsong
parents:
diff changeset
  1472
The underlying problem is that many ``real life'' regular expression
Chengsong
parents:
diff changeset
  1473
matching engines do not use DFAs for matching. This is because they
Chengsong
parents:
diff changeset
  1474
support regular expressions that are not covered by the classical
Chengsong
parents:
diff changeset
  1475
automata theory, and in this more general setting there are quite a few
Chengsong
parents:
diff changeset
  1476
research questions still unanswered and fast algorithms still need to be
Chengsong
parents:
diff changeset
  1477
developed (for example how to treat efficiently bounded repetitions, negation and
Chengsong
parents:
diff changeset
  1478
back-references).
Chengsong
parents:
diff changeset
  1479
%question: dfa can have exponential states. isn't this the actual reason why they do not use dfas?
Chengsong
parents:
diff changeset
  1480
%how do they avoid dfas exponential states if they use them for fast matching?
Chengsong
parents:
diff changeset
  1481
Chengsong
parents:
diff changeset
  1482
There is also another under-researched problem to do with regular
Chengsong
parents:
diff changeset
  1483
expressions and lexing, i.e.~the process of breaking up strings into
Chengsong
parents:
diff changeset
  1484
sequences of tokens according to some regular expressions. In this
Chengsong
parents:
diff changeset
  1485
setting one is not just interested in whether or not a regular
Chengsong
parents:
diff changeset
  1486
expression matches a string, but also in \emph{how}.  Consider for
Chengsong
parents:
diff changeset
  1487
example a regular expression $r_{key}$ for recognising keywords such as
Chengsong
parents:
diff changeset
  1488
\textit{if}, \textit{then} and so on; and a regular expression $r_{id}$
Chengsong
parents:
diff changeset
  1489
for recognising identifiers (say, a single character followed by
Chengsong
parents:
diff changeset
  1490
characters or numbers). One can then form the compound regular
Chengsong
parents:
diff changeset
  1491
expression $(r_{key} + r_{id})^*$ and use it to tokenise strings.  But
Chengsong
parents:
diff changeset
  1492
then how should the string \textit{iffoo} be tokenised?  It could be
Chengsong
parents:
diff changeset
  1493
tokenised as a keyword followed by an identifier, or the entire string
Chengsong
parents:
diff changeset
  1494
as a single identifier.  Similarly, how should the string \textit{if} be
Chengsong
parents:
diff changeset
  1495
tokenised? Both regular expressions, $r_{key}$ and $r_{id}$, would
Chengsong
parents:
diff changeset
  1496
``fire''---so is it an identifier or a keyword?  While in applications
Chengsong
parents:
diff changeset
  1497
there is a well-known strategy to decide these questions, called POSIX
Chengsong
parents:
diff changeset
  1498
matching, only relatively recently precise definitions of what POSIX
Chengsong
parents:
diff changeset
  1499
matching actually means have been formalised
Chengsong
parents:
diff changeset
  1500
\cite{AusafDyckhoffUrban2016,OkuiSuzuki2010,Vansummeren2006}. Such a
Chengsong
parents:
diff changeset
  1501
definition has also been given by Sulzmann and  Lu \cite{Sulzmann2014},
Chengsong
parents:
diff changeset
  1502
but the corresponding correctness proof turned out to be  faulty
Chengsong
parents:
diff changeset
  1503
\cite{AusafDyckhoffUrban2016}. Roughly, POSIX matching means matching
Chengsong
parents:
diff changeset
  1504
the longest initial substring. In the case of a tie, the initial
Chengsong
parents:
diff changeset
  1505
sub-match is chosen according to some priorities attached to the regular
Chengsong
parents:
diff changeset
  1506
expressions (e.g.~keywords have a higher priority than identifiers).
Chengsong
parents:
diff changeset
  1507
This sounds rather simple, but according to Grathwohl et al \cite[Page
Chengsong
parents:
diff changeset
  1508
36]{CrashCourse2014} this is not the case. They wrote:
Chengsong
parents:
diff changeset
  1509
Chengsong
parents:
diff changeset
  1510
\begin{quote}
Chengsong
parents:
diff changeset
  1511
\it{}``The POSIX strategy is more complicated than the greedy because of 
Chengsong
parents:
diff changeset
  1512
the dependence on information about the length of matched strings in the 
Chengsong
parents:
diff changeset
  1513
various subexpressions.''
Chengsong
parents:
diff changeset
  1514
\end{quote}
Chengsong
parents:
diff changeset
  1515
Chengsong
parents:
diff changeset
  1516
\noindent
Chengsong
parents:
diff changeset
  1517
This is also supported by evidence collected by Kuklewicz
Chengsong
parents:
diff changeset
  1518
\cite{Kuklewicz} who noticed that a number of POSIX regular expression
Chengsong
parents:
diff changeset
  1519
matchers calculate incorrect results.
Chengsong
parents:
diff changeset
  1520
Chengsong
parents:
diff changeset
  1521
Our focus in this project is on an algorithm introduced by Sulzmann and
Chengsong
parents:
diff changeset
  1522
Lu in 2014 for regular expression matching according to the POSIX
Chengsong
parents:
diff changeset
  1523
strategy \cite{Sulzmann2014}. Their algorithm is based on an older
Chengsong
parents:
diff changeset
  1524
algorithm by Brzozowski from 1964 where he introduced the notion of
Chengsong
parents:
diff changeset
  1525
derivatives of regular expressions~\cite{Brzozowski1964}. We shall
Chengsong
parents:
diff changeset
  1526
briefly explain this algorithm next.
Chengsong
parents:
diff changeset
  1527
Chengsong
parents:
diff changeset
  1528
\section{The Algorithm by Brzozowski based on Derivatives of Regular
Chengsong
parents:
diff changeset
  1529
Expressions}
Chengsong
parents:
diff changeset
  1530
Chengsong
parents:
diff changeset
  1531
Suppose (basic) regular expressions are given by the following grammar:
Chengsong
parents:
diff changeset
  1532
\[			r ::=   \ZERO \mid  \ONE
Chengsong
parents:
diff changeset
  1533
			 \mid  c  
Chengsong
parents:
diff changeset
  1534
			 \mid  r_1 \cdot r_2
Chengsong
parents:
diff changeset
  1535
			 \mid  r_1 + r_2   
Chengsong
parents:
diff changeset
  1536
			 \mid r^*         
Chengsong
parents:
diff changeset
  1537
\]
Chengsong
parents:
diff changeset
  1538
Chengsong
parents:
diff changeset
  1539
\noindent
Chengsong
parents:
diff changeset
  1540
The intended meaning of the constructors is as follows: $\ZERO$
Chengsong
parents:
diff changeset
  1541
cannot match any string, $\ONE$ can match the empty string, the
Chengsong
parents:
diff changeset
  1542
character regular expression $c$ can match the character $c$, and so
Chengsong
parents:
diff changeset
  1543
on.
Chengsong
parents:
diff changeset
  1544
Chengsong
parents:
diff changeset
  1545
The ingenious contribution by Brzozowski is the notion of
Chengsong
parents:
diff changeset
  1546
\emph{derivatives} of regular expressions.  The idea behind this
Chengsong
parents:
diff changeset
  1547
notion is as follows: suppose a regular expression $r$ can match a
Chengsong
parents:
diff changeset
  1548
string of the form $c\!::\! s$ (that is a list of characters starting
Chengsong
parents:
diff changeset
  1549
with $c$), what does the regular expression look like that can match
Chengsong
parents:
diff changeset
  1550
just $s$? Brzozowski gave a neat answer to this question. He started
Chengsong
parents:
diff changeset
  1551
with the definition of $nullable$:
Chengsong
parents:
diff changeset
  1552
\begin{center}
Chengsong
parents:
diff changeset
  1553
		\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1554
			$\nullable(\ZERO)$     & $\dn$ & $\mathit{false}$ \\  
Chengsong
parents:
diff changeset
  1555
			$\nullable(\ONE)$      & $\dn$ & $\mathit{true}$ \\
Chengsong
parents:
diff changeset
  1556
			$\nullable(c)$ 	       & $\dn$ & $\mathit{false}$ \\
Chengsong
parents:
diff changeset
  1557
			$\nullable(r_1 + r_2)$ & $\dn$ & $\nullable(r_1) \vee \nullable(r_2)$ \\
Chengsong
parents:
diff changeset
  1558
			$\nullable(r_1\cdot r_2)$  & $\dn$ & $\nullable(r_1) \wedge \nullable(r_2)$ \\
Chengsong
parents:
diff changeset
  1559
			$\nullable(r^*)$       & $\dn$ & $\mathit{true}$ \\
Chengsong
parents:
diff changeset
  1560
		\end{tabular}
Chengsong
parents:
diff changeset
  1561
	\end{center}
Chengsong
parents:
diff changeset
  1562
This function simply tests whether the empty string is in $L(r)$.
Chengsong
parents:
diff changeset
  1563
He then defined
Chengsong
parents:
diff changeset
  1564
the following operation on regular expressions, written
Chengsong
parents:
diff changeset
  1565
$r\backslash c$ (the derivative of $r$ w.r.t.~the character $c$):
Chengsong
parents:
diff changeset
  1566
Chengsong
parents:
diff changeset
  1567
\begin{center}
Chengsong
parents:
diff changeset
  1568
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1569
		$\ZERO \backslash c$ & $\dn$ & $\ZERO$\\  
Chengsong
parents:
diff changeset
  1570
		$\ONE \backslash c$  & $\dn$ & $\ZERO$\\
Chengsong
parents:
diff changeset
  1571
		$d \backslash c$     & $\dn$ & 
Chengsong
parents:
diff changeset
  1572
		$\mathit{if} \;c = d\;\mathit{then}\;\ONE\;\mathit{else}\;\ZERO$\\
Chengsong
parents:
diff changeset
  1573
$(r_1 + r_2)\backslash c$     & $\dn$ & $r_1 \backslash c \,+\, r_2 \backslash c$\\
Chengsong
parents:
diff changeset
  1574
$(r_1 \cdot r_2)\backslash c$ & $\dn$ & $\mathit{if} \, nullable(r_1)$\\
Chengsong
parents:
diff changeset
  1575
	&   & $\mathit{then}\;(r_1\backslash c) \cdot r_2 \,+\, r_2\backslash c$\\
Chengsong
parents:
diff changeset
  1576
	&   & $\mathit{else}\;(r_1\backslash c) \cdot r_2$\\
Chengsong
parents:
diff changeset
  1577
	$(r^*)\backslash c$           & $\dn$ & $(r\backslash c) \cdot r^*$\\
Chengsong
parents:
diff changeset
  1578
\end{tabular}
Chengsong
parents:
diff changeset
  1579
\end{center}
Chengsong
parents:
diff changeset
  1580
Chengsong
parents:
diff changeset
  1581
%Assuming the classic notion of a
Chengsong
parents:
diff changeset
  1582
%\emph{language} of a regular expression, written $L(\_)$, t
Chengsong
parents:
diff changeset
  1583
Chengsong
parents:
diff changeset
  1584
\noindent
Chengsong
parents:
diff changeset
  1585
The main property of the derivative operation is that
Chengsong
parents:
diff changeset
  1586
Chengsong
parents:
diff changeset
  1587
\begin{center}
Chengsong
parents:
diff changeset
  1588
$c\!::\!s \in L(r)$ holds
Chengsong
parents:
diff changeset
  1589
if and only if $s \in L(r\backslash c)$.
Chengsong
parents:
diff changeset
  1590
\end{center}
Chengsong
parents:
diff changeset
  1591
Chengsong
parents:
diff changeset
  1592
\noindent
Chengsong
parents:
diff changeset
  1593
For us the main advantage is that derivatives can be
Chengsong
parents:
diff changeset
  1594
straightforwardly implemented in any functional programming language,
Chengsong
parents:
diff changeset
  1595
and are easily definable and reasoned about in theorem provers---the
Chengsong
parents:
diff changeset
  1596
definitions just consist of inductive datatypes and simple recursive
Chengsong
parents:
diff changeset
  1597
functions. Moreover, the notion of derivatives can be easily
Chengsong
parents:
diff changeset
  1598
generalised to cover extended regular expression constructors such as
Chengsong
parents:
diff changeset
  1599
the not-regular expression, written $\neg\,r$, or bounded repetitions
Chengsong
parents:
diff changeset
  1600
(for example $r^{\{n\}}$ and $r^{\{n..m\}}$), which cannot be so
Chengsong
parents:
diff changeset
  1601
straightforwardly realised within the classic automata approach.
Chengsong
parents:
diff changeset
  1602
For the moment however, we focus only on the usual basic regular expressions.
Chengsong
parents:
diff changeset
  1603
Chengsong
parents:
diff changeset
  1604
Chengsong
parents:
diff changeset
  1605
Now if we want to find out whether a string $s$ matches with a regular
Chengsong
parents:
diff changeset
  1606
expression $r$, we can build the derivatives of $r$ w.r.t.\ (in succession)
Chengsong
parents:
diff changeset
  1607
all the characters of the string $s$. Finally, test whether the
Chengsong
parents:
diff changeset
  1608
resulting regular expression can match the empty string.  If yes, then
Chengsong
parents:
diff changeset
  1609
$r$ matches $s$, and no in the negative case. To implement this idea
Chengsong
parents:
diff changeset
  1610
we can generalise the derivative operation to strings like this:
Chengsong
parents:
diff changeset
  1611
Chengsong
parents:
diff changeset
  1612
\begin{center}
Chengsong
parents:
diff changeset
  1613
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1614
$r \backslash (c\!::\!s) $ & $\dn$ & $(r \backslash c) \backslash s$ \\
Chengsong
parents:
diff changeset
  1615
$r \backslash [\,] $ & $\dn$ & $r$
Chengsong
parents:
diff changeset
  1616
\end{tabular}
Chengsong
parents:
diff changeset
  1617
\end{center}
Chengsong
parents:
diff changeset
  1618
Chengsong
parents:
diff changeset
  1619
\noindent
Chengsong
parents:
diff changeset
  1620
and then define as  regular-expression matching algorithm: 
Chengsong
parents:
diff changeset
  1621
\[
Chengsong
parents:
diff changeset
  1622
match\;s\;r \;\dn\; nullable(r\backslash s)
Chengsong
parents:
diff changeset
  1623
\]
Chengsong
parents:
diff changeset
  1624
Chengsong
parents:
diff changeset
  1625
\noindent
Chengsong
parents:
diff changeset
  1626
This algorithm looks graphically as follows:
Chengsong
parents:
diff changeset
  1627
\begin{equation}\label{graph:*}
Chengsong
parents:
diff changeset
  1628
\begin{tikzcd}
Chengsong
parents:
diff changeset
  1629
r_0 \arrow[r, "\backslash c_0"]  & r_1 \arrow[r, "\backslash c_1"] & r_2 \arrow[r, dashed]  & r_n  \arrow[r,"\textit{nullable}?"] & \;\textrm{YES}/\textrm{NO}
Chengsong
parents:
diff changeset
  1630
\end{tikzcd}
Chengsong
parents:
diff changeset
  1631
\end{equation}
Chengsong
parents:
diff changeset
  1632
Chengsong
parents:
diff changeset
  1633
\noindent
Chengsong
parents:
diff changeset
  1634
where we start with  a regular expression  $r_0$, build successive
Chengsong
parents:
diff changeset
  1635
derivatives until we exhaust the string and then use \textit{nullable}
Chengsong
parents:
diff changeset
  1636
to test whether the result can match the empty string. It can  be
Chengsong
parents:
diff changeset
  1637
relatively  easily shown that this matcher is correct  (that is given
Chengsong
parents:
diff changeset
  1638
an $s = c_0...c_{n-1}$ and an $r_0$, it generates YES if and only if $s \in L(r_0)$).
Chengsong
parents:
diff changeset
  1639
Chengsong
parents:
diff changeset
  1640
 
Chengsong
parents:
diff changeset
  1641
\section{Values and the Algorithm by Sulzmann and Lu}
Chengsong
parents:
diff changeset
  1642
Chengsong
parents:
diff changeset
  1643
One limitation of Brzozowski's algorithm is that it only produces a
Chengsong
parents:
diff changeset
  1644
YES/NO answer for whether a string is being matched by a regular
Chengsong
parents:
diff changeset
  1645
expression.  Sulzmann and Lu~\cite{Sulzmann2014} extended this algorithm
Chengsong
parents:
diff changeset
  1646
to allow generation of an actual matching, called a \emph{value} or
Chengsong
parents:
diff changeset
  1647
sometimes also \emph{lexical value}.  These values and regular
Chengsong
parents:
diff changeset
  1648
expressions correspond to each other as illustrated in the following
Chengsong
parents:
diff changeset
  1649
table:
Chengsong
parents:
diff changeset
  1650
Chengsong
parents:
diff changeset
  1651
Chengsong
parents:
diff changeset
  1652
\begin{center}
Chengsong
parents:
diff changeset
  1653
	\begin{tabular}{c@{\hspace{20mm}}c}
Chengsong
parents:
diff changeset
  1654
		\begin{tabular}{@{}rrl@{}}
Chengsong
parents:
diff changeset
  1655
			\multicolumn{3}{@{}l}{\textbf{Regular Expressions}}\medskip\\
Chengsong
parents:
diff changeset
  1656
			$r$ & $::=$  & $\ZERO$\\
Chengsong
parents:
diff changeset
  1657
			& $\mid$ & $\ONE$   \\
Chengsong
parents:
diff changeset
  1658
			& $\mid$ & $c$          \\
Chengsong
parents:
diff changeset
  1659
			& $\mid$ & $r_1 \cdot r_2$\\
Chengsong
parents:
diff changeset
  1660
			& $\mid$ & $r_1 + r_2$   \\
Chengsong
parents:
diff changeset
  1661
			\\
Chengsong
parents:
diff changeset
  1662
			& $\mid$ & $r^*$         \\
Chengsong
parents:
diff changeset
  1663
		\end{tabular}
Chengsong
parents:
diff changeset
  1664
		&
Chengsong
parents:
diff changeset
  1665
		\begin{tabular}{@{\hspace{0mm}}rrl@{}}
Chengsong
parents:
diff changeset
  1666
			\multicolumn{3}{@{}l}{\textbf{Values}}\medskip\\
Chengsong
parents:
diff changeset
  1667
			$v$ & $::=$  & \\
Chengsong
parents:
diff changeset
  1668
			&        & $\Empty$   \\
Chengsong
parents:
diff changeset
  1669
			& $\mid$ & $\Char(c)$          \\
Chengsong
parents:
diff changeset
  1670
			& $\mid$ & $\Seq\,v_1\, v_2$\\
Chengsong
parents:
diff changeset
  1671
			& $\mid$ & $\Left(v)$   \\
Chengsong
parents:
diff changeset
  1672
			& $\mid$ & $\Right(v)$  \\
Chengsong
parents:
diff changeset
  1673
			& $\mid$ & $\Stars\,[v_1,\ldots\,v_n]$ \\
Chengsong
parents:
diff changeset
  1674
		\end{tabular}
Chengsong
parents:
diff changeset
  1675
	\end{tabular}
Chengsong
parents:
diff changeset
  1676
\end{center}
Chengsong
parents:
diff changeset
  1677
Chengsong
parents:
diff changeset
  1678
\noindent
Chengsong
parents:
diff changeset
  1679
No value  corresponds to $\ZERO$; $\Empty$ corresponds to $\ONE$;
Chengsong
parents:
diff changeset
  1680
$\Char$ to the character regular expression; $\Seq$ to the sequence
Chengsong
parents:
diff changeset
  1681
regular expression and so on. The idea of values is to encode a kind of
Chengsong
parents:
diff changeset
  1682
lexical value for how the sub-parts of a regular expression match the
Chengsong
parents:
diff changeset
  1683
sub-parts of a string. To see this, suppose a \emph{flatten} operation,
Chengsong
parents:
diff changeset
  1684
written $|v|$ for values. We can use this function to extract the
Chengsong
parents:
diff changeset
  1685
underlying string of a value $v$. For example, $|\mathit{Seq} \,
Chengsong
parents:
diff changeset
  1686
(\textit{Char x}) \, (\textit{Char y})|$ is the string $xy$.  Using
Chengsong
parents:
diff changeset
  1687
flatten, we can describe how values encode lexical values: $\Seq\,v_1\,
Chengsong
parents:
diff changeset
  1688
v_2$ encodes a tree with two children nodes that tells how the string
Chengsong
parents:
diff changeset
  1689
$|v_1| @ |v_2|$ matches the regex $r_1 \cdot r_2$ whereby $r_1$ matches
Chengsong
parents:
diff changeset
  1690
the substring $|v_1|$ and, respectively, $r_2$ matches the substring
Chengsong
parents:
diff changeset
  1691
$|v_2|$. Exactly how these two are matched is contained in the children
Chengsong
parents:
diff changeset
  1692
nodes $v_1$ and $v_2$ of parent $\textit{Seq}$. 
Chengsong
parents:
diff changeset
  1693
Chengsong
parents:
diff changeset
  1694
To give a concrete example of how values work, consider the string $xy$
Chengsong
parents:
diff changeset
  1695
and the regular expression $(x + (y + xy))^*$. We can view this regular
Chengsong
parents:
diff changeset
  1696
expression as a tree and if the string $xy$ is matched by two Star
Chengsong
parents:
diff changeset
  1697
``iterations'', then the $x$ is matched by the left-most alternative in
Chengsong
parents:
diff changeset
  1698
this tree and the $y$ by the right-left alternative. This suggests to
Chengsong
parents:
diff changeset
  1699
record this matching as
Chengsong
parents:
diff changeset
  1700
Chengsong
parents:
diff changeset
  1701
\begin{center}
Chengsong
parents:
diff changeset
  1702
$\Stars\,[\Left\,(\Char\,x), \Right(\Left(\Char\,y))]$
Chengsong
parents:
diff changeset
  1703
\end{center}
Chengsong
parents:
diff changeset
  1704
Chengsong
parents:
diff changeset
  1705
\noindent
Chengsong
parents:
diff changeset
  1706
where $\Stars \; [\ldots]$ records all the
Chengsong
parents:
diff changeset
  1707
iterations; and $\Left$, respectively $\Right$, which
Chengsong
parents:
diff changeset
  1708
alternative is used. The value for
Chengsong
parents:
diff changeset
  1709
matching $xy$ in a single ``iteration'', i.e.~the POSIX value,
Chengsong
parents:
diff changeset
  1710
would look as follows
Chengsong
parents:
diff changeset
  1711
Chengsong
parents:
diff changeset
  1712
\begin{center}
Chengsong
parents:
diff changeset
  1713
$\Stars\,[\Seq\,(\Char\,x)\,(\Char\,y)]$
Chengsong
parents:
diff changeset
  1714
\end{center}
Chengsong
parents:
diff changeset
  1715
Chengsong
parents:
diff changeset
  1716
\noindent
Chengsong
parents:
diff changeset
  1717
where $\Stars$ has only a single-element list for the single iteration
Chengsong
parents:
diff changeset
  1718
and $\Seq$ indicates that $xy$ is matched by a sequence regular
Chengsong
parents:
diff changeset
  1719
expression.
Chengsong
parents:
diff changeset
  1720
Chengsong
parents:
diff changeset
  1721
The contribution of Sulzmann and Lu is an extension of Brzozowski's
Chengsong
parents:
diff changeset
  1722
algorithm by a second phase (the first phase being building successive
Chengsong
parents:
diff changeset
  1723
derivatives---see \eqref{graph:*}). In this second phase, a POSIX value 
Chengsong
parents:
diff changeset
  1724
is generated in case the regular expression matches  the string. 
Chengsong
parents:
diff changeset
  1725
Pictorially, the Sulzmann and Lu algorithm is as follows:
Chengsong
parents:
diff changeset
  1726
Chengsong
parents:
diff changeset
  1727
\begin{ceqn}
Chengsong
parents:
diff changeset
  1728
\begin{equation}\label{graph:2}
Chengsong
parents:
diff changeset
  1729
\begin{tikzcd}
Chengsong
parents:
diff changeset
  1730
r_0 \arrow[r, "\backslash c_0"]  \arrow[d] & r_1 \arrow[r, "\backslash c_1"] \arrow[d] & r_2 \arrow[r, dashed] \arrow[d] & r_n \arrow[d, "mkeps" description] \\
Chengsong
parents:
diff changeset
  1731
v_0           & v_1 \arrow[l,"inj_{r_0} c_0"]                & v_2 \arrow[l, "inj_{r_1} c_1"]              & v_n \arrow[l, dashed]         
Chengsong
parents:
diff changeset
  1732
\end{tikzcd}
Chengsong
parents:
diff changeset
  1733
\end{equation}
Chengsong
parents:
diff changeset
  1734
\end{ceqn}
Chengsong
parents:
diff changeset
  1735
Chengsong
parents:
diff changeset
  1736
\noindent
Chengsong
parents:
diff changeset
  1737
For convenience, we shall employ the following notations: the regular
Chengsong
parents:
diff changeset
  1738
expression we start with is $r_0$, and the given string $s$ is composed
Chengsong
parents:
diff changeset
  1739
of characters $c_0 c_1 \ldots c_{n-1}$. In  the first phase from the
Chengsong
parents:
diff changeset
  1740
left to right, we build the derivatives $r_1$, $r_2$, \ldots  according
Chengsong
parents:
diff changeset
  1741
to the characters $c_0$, $c_1$  until we exhaust the string and obtain
Chengsong
parents:
diff changeset
  1742
the derivative $r_n$. We test whether this derivative is
Chengsong
parents:
diff changeset
  1743
$\textit{nullable}$ or not. If not, we know the string does not match
Chengsong
parents:
diff changeset
  1744
$r$ and no value needs to be generated. If yes, we start building the
Chengsong
parents:
diff changeset
  1745
values incrementally by \emph{injecting} back the characters into the
Chengsong
parents:
diff changeset
  1746
earlier values $v_n, \ldots, v_0$. This is the second phase of the
Chengsong
parents:
diff changeset
  1747
algorithm from the right to left. For the first value $v_n$, we call the
Chengsong
parents:
diff changeset
  1748
function $\textit{mkeps}$, which builds the lexical value
Chengsong
parents:
diff changeset
  1749
for how the empty string has been matched by the (nullable) regular
Chengsong
parents:
diff changeset
  1750
expression $r_n$. This function is defined as
Chengsong
parents:
diff changeset
  1751
Chengsong
parents:
diff changeset
  1752
	\begin{center}
Chengsong
parents:
diff changeset
  1753
		\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1754
			$\mkeps(\ONE)$ 		& $\dn$ & $\Empty$ \\
Chengsong
parents:
diff changeset
  1755
			$\mkeps(r_{1}+r_{2})$	& $\dn$ 
Chengsong
parents:
diff changeset
  1756
			& \textit{if} $\nullable(r_{1})$\\ 
Chengsong
parents:
diff changeset
  1757
			& & \textit{then} $\Left(\mkeps(r_{1}))$\\ 
Chengsong
parents:
diff changeset
  1758
			& & \textit{else} $\Right(\mkeps(r_{2}))$\\
Chengsong
parents:
diff changeset
  1759
			$\mkeps(r_1\cdot r_2)$ 	& $\dn$ & $\Seq\,(\mkeps\,r_1)\,(\mkeps\,r_2)$\\
Chengsong
parents:
diff changeset
  1760
			$mkeps(r^*)$	        & $\dn$ & $\Stars\,[]$
Chengsong
parents:
diff changeset
  1761
		\end{tabular}
Chengsong
parents:
diff changeset
  1762
	\end{center}
Chengsong
parents:
diff changeset
  1763
Chengsong
parents:
diff changeset
  1764
Chengsong
parents:
diff changeset
  1765
\noindent There are no cases for $\ZERO$ and $c$, since
Chengsong
parents:
diff changeset
  1766
these regular expression cannot match the empty string. Note
Chengsong
parents:
diff changeset
  1767
also that in case of alternatives we give preference to the
Chengsong
parents:
diff changeset
  1768
regular expression on the left-hand side. This will become
Chengsong
parents:
diff changeset
  1769
important later on about what value is calculated.
Chengsong
parents:
diff changeset
  1770
Chengsong
parents:
diff changeset
  1771
After the $\mkeps$-call, we inject back the characters one by one in order to build
Chengsong
parents:
diff changeset
  1772
the lexical value $v_i$ for how the regex $r_i$ matches the string $s_i$
Chengsong
parents:
diff changeset
  1773
($s_i = c_i \ldots c_{n-1}$ ) from the previous lexical value $v_{i+1}$.
Chengsong
parents:
diff changeset
  1774
After injecting back $n$ characters, we get the lexical value for how $r_0$
Chengsong
parents:
diff changeset
  1775
matches $s$. For this Sulzmann and Lu defined a function that reverses
Chengsong
parents:
diff changeset
  1776
the ``chopping off'' of characters during the derivative phase. The
Chengsong
parents:
diff changeset
  1777
corresponding function is called \emph{injection}, written
Chengsong
parents:
diff changeset
  1778
$\textit{inj}$; it takes three arguments: the first one is a regular
Chengsong
parents:
diff changeset
  1779
expression ${r_{i-1}}$, before the character is chopped off, the second
Chengsong
parents:
diff changeset
  1780
is a character ${c_{i-1}}$, the character we want to inject and the
Chengsong
parents:
diff changeset
  1781
third argument is the value ${v_i}$, into which one wants to inject the
Chengsong
parents:
diff changeset
  1782
character (it corresponds to the regular expression after the character
Chengsong
parents:
diff changeset
  1783
has been chopped off). The result of this function is a new value. The
Chengsong
parents:
diff changeset
  1784
definition of $\textit{inj}$ is as follows: 
Chengsong
parents:
diff changeset
  1785
Chengsong
parents:
diff changeset
  1786
\begin{center}
Chengsong
parents:
diff changeset
  1787
\begin{tabular}{l@{\hspace{1mm}}c@{\hspace{1mm}}l}
Chengsong
parents:
diff changeset
  1788
  $\textit{inj}\,(c)\,c\,Empty$            & $\dn$ & $Char\,c$\\
Chengsong
parents:
diff changeset
  1789
  $\textit{inj}\,(r_1 + r_2)\,c\,\Left(v)$ & $\dn$ & $\Left(\textit{inj}\,r_1\,c\,v)$\\
Chengsong
parents:
diff changeset
  1790
  $\textit{inj}\,(r_1 + r_2)\,c\,Right(v)$ & $\dn$ & $Right(\textit{inj}\,r_2\,c\,v)$\\
Chengsong
parents:
diff changeset
  1791
  $\textit{inj}\,(r_1 \cdot r_2)\,c\,Seq(v_1,v_2)$ & $\dn$  & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\
Chengsong
parents:
diff changeset
  1792
  $\textit{inj}\,(r_1 \cdot r_2)\,c\,\Left(Seq(v_1,v_2))$ & $\dn$  & $Seq(\textit{inj}\,r_1\,c\,v_1,v_2)$\\
Chengsong
parents:
diff changeset
  1793
  $\textit{inj}\,(r_1 \cdot r_2)\,c\,Right(v)$ & $\dn$  & $Seq(\textit{mkeps}(r_1),\textit{inj}\,r_2\,c\,v)$\\
Chengsong
parents:
diff changeset
  1794
  $\textit{inj}\,(r^*)\,c\,Seq(v,Stars\,vs)$         & $\dn$  & $Stars((\textit{inj}\,r\,c\,v)\,::\,vs)$\\
Chengsong
parents:
diff changeset
  1795
\end{tabular}
Chengsong
parents:
diff changeset
  1796
\end{center}
Chengsong
parents:
diff changeset
  1797
Chengsong
parents:
diff changeset
  1798
\noindent This definition is by recursion on the ``shape'' of regular
Chengsong
parents:
diff changeset
  1799
expressions and values. To understands this definition better consider
Chengsong
parents:
diff changeset
  1800
the situation when we build the derivative on regular expression $r_{i-1}$.
Chengsong
parents:
diff changeset
  1801
For this we chop off a character from $r_{i-1}$ to form $r_i$. This leaves a
Chengsong
parents:
diff changeset
  1802
``hole'' in $r_i$ and its corresponding value $v_i$. 
Chengsong
parents:
diff changeset
  1803
To calculate $v_{i-1}$, we need to
Chengsong
parents:
diff changeset
  1804
locate where that hole is and fill it. 
Chengsong
parents:
diff changeset
  1805
We can find this location by
Chengsong
parents:
diff changeset
  1806
comparing $r_{i-1}$ and $v_i$. For instance, if $r_{i-1}$ is of shape
Chengsong
parents:
diff changeset
  1807
$r_a \cdot r_b$, and $v_i$ is of shape $\Left(Seq(v_1,v_2))$, we know immediately that 
Chengsong
parents:
diff changeset
  1808
%
Chengsong
parents:
diff changeset
  1809
\[ (r_a \cdot r_b)\backslash c = (r_a\backslash c) \cdot r_b \,+\, r_b\backslash c,\]
Chengsong
parents:
diff changeset
  1810
Chengsong
parents:
diff changeset
  1811
\noindent
Chengsong
parents:
diff changeset
  1812
otherwise if $r_a$ is not nullable,
Chengsong
parents:
diff changeset
  1813
\[ (r_a \cdot r_b)\backslash c = (r_a\backslash c) \cdot r_b,\]
Chengsong
parents:
diff changeset
  1814
Chengsong
parents:
diff changeset
  1815
\noindent
Chengsong
parents:
diff changeset
  1816
the value $v_i$ should be  $\Seq(\ldots)$, contradicting the fact that
Chengsong
parents:
diff changeset
  1817
$v_i$ is actually of shape $\Left(\ldots)$. Furthermore, since $v_i$ is of shape
Chengsong
parents:
diff changeset
  1818
$\Left(\ldots)$ instead of $\Right(\ldots)$, we know that the left
Chengsong
parents:
diff changeset
  1819
branch of \[ (r_a \cdot r_b)\backslash c =
Chengsong
parents:
diff changeset
  1820
\bold{\underline{ (r_a\backslash c) \cdot r_b} }\,+\, r_b\backslash c,\](underlined)
Chengsong
parents:
diff changeset
  1821
 is taken instead of the right one. This means $c$ is chopped off 
Chengsong
parents:
diff changeset
  1822
from $r_a$ rather than $r_b$.
Chengsong
parents:
diff changeset
  1823
We have therefore found out 
Chengsong
parents:
diff changeset
  1824
that the hole will be on $r_a$. So we recursively call $\inj\, 
Chengsong
parents:
diff changeset
  1825
r_a\,c\,v_a$ to fill that hole in $v_a$. After injection, the value 
Chengsong
parents:
diff changeset
  1826
$v_i$ for $r_i = r_a \cdot r_b$ should be $\Seq\,(\inj\,r_a\,c\,v_a)\,v_b$.
Chengsong
parents:
diff changeset
  1827
Other clauses can be understood in a similar way.
Chengsong
parents:
diff changeset
  1828
Chengsong
parents:
diff changeset
  1829
%\comment{Other word: insight?}
Chengsong
parents:
diff changeset
  1830
The following example gives an insight of $\textit{inj}$'s effect and
Chengsong
parents:
diff changeset
  1831
how Sulzmann and Lu's algorithm works as a whole. Suppose we have a
Chengsong
parents:
diff changeset
  1832
regular expression $((((a+b)+ab)+c)+abc)^*$, and want to match it
Chengsong
parents:
diff changeset
  1833
against the string $abc$ (when $abc$ is written as a regular expression,
Chengsong
parents:
diff changeset
  1834
the standard way of expressing it is $a \cdot (b \cdot c)$. But we
Chengsong
parents:
diff changeset
  1835
usually omit the parentheses and dots here for better readability. This
Chengsong
parents:
diff changeset
  1836
algorithm returns a POSIX value, which means it will produce the longest
Chengsong
parents:
diff changeset
  1837
matching. Consequently, it matches the string $abc$ in one star
Chengsong
parents:
diff changeset
  1838
iteration, using the longest alternative $abc$ in the sub-expression (we shall use $r$ to denote this
Chengsong
parents:
diff changeset
  1839
sub-expression for conciseness):
Chengsong
parents:
diff changeset
  1840
Chengsong
parents:
diff changeset
  1841
\[((((a+b)+ab)+c)+\underbrace{abc}_r)\] 
Chengsong
parents:
diff changeset
  1842
Chengsong
parents:
diff changeset
  1843
\noindent
Chengsong
parents:
diff changeset
  1844
Before $\textit{inj}$ is called, our lexer first builds derivative using
Chengsong
parents:
diff changeset
  1845
string $abc$ (we simplified some regular expressions like $\ZERO \cdot
Chengsong
parents:
diff changeset
  1846
b$ to $\ZERO$ for conciseness; we also omit parentheses if they are
Chengsong
parents:
diff changeset
  1847
clear from the context):
Chengsong
parents:
diff changeset
  1848
Chengsong
parents:
diff changeset
  1849
%Similarly, we allow
Chengsong
parents:
diff changeset
  1850
%$\textit{ALT}$ to take a list of regular expressions as an argument
Chengsong
parents:
diff changeset
  1851
%instead of just 2 operands to reduce the nested depth of
Chengsong
parents:
diff changeset
  1852
%$\textit{ALT}$
Chengsong
parents:
diff changeset
  1853
Chengsong
parents:
diff changeset
  1854
\begin{center}
Chengsong
parents:
diff changeset
  1855
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  1856
$r^*$ & $\xrightarrow{\backslash a}$ & $r_1 = (\ONE+\ZERO+\ONE \cdot b + \ZERO + \ONE \cdot b \cdot c) \cdot r^*$\\
Chengsong
parents:
diff changeset
  1857
      & $\xrightarrow{\backslash b}$ & $r_2 = (\ZERO+\ZERO+\ONE \cdot \ONE + \ZERO + \ONE \cdot \ONE \cdot c) \cdot r^* +(\ZERO+\ONE+\ZERO  + \ZERO + \ZERO) \cdot r^*$\\
Chengsong
parents:
diff changeset
  1858
      & $\xrightarrow{\backslash c}$ & $r_3 = ((\ZERO+\ZERO+\ZERO + \ZERO + \ONE \cdot \ONE \cdot \ONE) \cdot r^* + (\ZERO+\ZERO+\ZERO  + \ONE + \ZERO) \cdot r^*) + $\\ 
Chengsong
parents:
diff changeset
  1859
      &                              & $\phantom{r_3 = (} ((\ZERO+\ONE+\ZERO  + \ZERO + \ZERO) \cdot r^* + (\ZERO+\ZERO+\ZERO  + \ONE + \ZERO) \cdot r^* )$
Chengsong
parents:
diff changeset
  1860
\end{tabular}
Chengsong
parents:
diff changeset
  1861
\end{center}
Chengsong
parents:
diff changeset
  1862
Chengsong
parents:
diff changeset
  1863
\noindent
Chengsong
parents:
diff changeset
  1864
In  case $r_3$ is nullable, we can call $\textit{mkeps}$ 
Chengsong
parents:
diff changeset
  1865
to construct a lexical value for how $r_3$ matched the string $abc$. 
Chengsong
parents:
diff changeset
  1866
This function gives the following value $v_3$: 
Chengsong
parents:
diff changeset
  1867
Chengsong
parents:
diff changeset
  1868
Chengsong
parents:
diff changeset
  1869
\begin{center}
Chengsong
parents:
diff changeset
  1870
$\Left(\Left(\Seq(\Right(\Seq(\Empty, \Seq(\Empty,\Empty))), \Stars [])))$
Chengsong
parents:
diff changeset
  1871
\end{center}
Chengsong
parents:
diff changeset
  1872
The outer $\Left(\Left(\ldots))$ tells us the leftmost nullable part of $r_3$(underlined):
Chengsong
parents:
diff changeset
  1873
Chengsong
parents:
diff changeset
  1874
\begin{center}
Chengsong
parents:
diff changeset
  1875
	\begin{tabular}{l@{\hspace{2mm}}l}
Chengsong
parents:
diff changeset
  1876
    & $\big(\underline{(\ZERO+\ZERO+\ZERO+ \ZERO+ \ONE \cdot \ONE \cdot \ONE) \cdot r^*} 
Chengsong
parents:
diff changeset
  1877
    \;+\; (\ZERO+\ZERO+\ZERO + \ONE + \ZERO) \cdot r^*\big)$ \smallskip\\
Chengsong
parents:
diff changeset
  1878
    $+$ & $\big((\ZERO+\ONE+\ZERO  + \ZERO + \ZERO) \cdot r^*
Chengsong
parents:
diff changeset
  1879
    \;+\; (\ZERO+\ZERO+\ZERO  + \ONE + \ZERO) \cdot r^* \big)$
Chengsong
parents:
diff changeset
  1880
  	\end{tabular}
Chengsong
parents:
diff changeset
  1881
 \end{center}
Chengsong
parents:
diff changeset
  1882
Chengsong
parents:
diff changeset
  1883
\noindent
Chengsong
parents:
diff changeset
  1884
 Note that the leftmost location of term $(\ZERO+\ZERO+\ZERO + \ZERO + \ONE \cdot \ONE \cdot
Chengsong
parents:
diff changeset
  1885
 \ONE) \cdot r^*$ (which corresponds to the initial sub-match $abc$) allows
Chengsong
parents:
diff changeset
  1886
 $\textit{mkeps}$ to pick it up because $\textit{mkeps}$ is defined to always choose the
Chengsong
parents:
diff changeset
  1887
 left one when it is nullable. In the case of this example, $abc$ is
Chengsong
parents:
diff changeset
  1888
 preferred over $a$ or $ab$. This $\Left(\Left(\ldots))$ location is
Chengsong
parents:
diff changeset
  1889
 generated by two applications of the splitting clause
Chengsong
parents:
diff changeset
  1890
Chengsong
parents:
diff changeset
  1891
\begin{center}
Chengsong
parents:
diff changeset
  1892
     $(r_1 \cdot r_2)\backslash c  \;\;(when \; r_1 \; nullable) \, = (r_1\backslash c) \cdot r_2 \,+\, r_2\backslash c.$
Chengsong
parents:
diff changeset
  1893
\end{center}
Chengsong
parents:
diff changeset
  1894
       
Chengsong
parents:
diff changeset
  1895
\noindent
Chengsong
parents:
diff changeset
  1896
By this clause, we put $r_1 \backslash c \cdot r_2 $ at the
Chengsong
parents:
diff changeset
  1897
$\textit{front}$ and $r_2 \backslash c$ at the $\textit{back}$. This
Chengsong
parents:
diff changeset
  1898
allows $\textit{mkeps}$ to always pick up among two matches the one with a longer
Chengsong
parents:
diff changeset
  1899
initial sub-match. Removing the outside $\Left(\Left(...))$, the inside
Chengsong
parents:
diff changeset
  1900
sub-value 
Chengsong
parents:
diff changeset
  1901
 
Chengsong
parents:
diff changeset
  1902
\begin{center}
Chengsong
parents:
diff changeset
  1903
 $\Seq(\Right(\Seq(\Empty, \Seq(\Empty, \Empty))), \Stars [])$
Chengsong
parents:
diff changeset
  1904
\end{center}
Chengsong
parents:
diff changeset
  1905
Chengsong
parents:
diff changeset
  1906
\noindent
Chengsong
parents:
diff changeset
  1907
tells us how the empty string $[]$ is matched with $(\ZERO+\ZERO+\ZERO + \ZERO + \ONE \cdot
Chengsong
parents:
diff changeset
  1908
\ONE \cdot \ONE) \cdot r^*$. We match $[]$ by a sequence of two nullable regular
Chengsong
parents:
diff changeset
  1909
expressions. The first one is an alternative, we take the rightmost
Chengsong
parents:
diff changeset
  1910
alternative---whose language contains the empty string. The second
Chengsong
parents:
diff changeset
  1911
nullable regular expression is a Kleene star. $\Stars$ tells us how it
Chengsong
parents:
diff changeset
  1912
generates the nullable regular expression: by 0 iterations to form
Chengsong
parents:
diff changeset
  1913
$\ONE$. Now $\textit{inj}$ injects characters back and incrementally
Chengsong
parents:
diff changeset
  1914
builds a lexical value based on $v_3$. Using the value $v_3$, the character
Chengsong
parents:
diff changeset
  1915
c, and the regular expression $r_2$, we can recover how $r_2$ matched
Chengsong
parents:
diff changeset
  1916
the string $[c]$ : $\textit{inj} \; r_2 \; c \; v_3$ gives us
Chengsong
parents:
diff changeset
  1917
 \begin{center}
Chengsong
parents:
diff changeset
  1918
 $v_2 = \Left(\Seq(\Right(\Seq(\Empty, \Seq(\Empty, c))), \Stars [])),$
Chengsong
parents:
diff changeset
  1919
 \end{center}
Chengsong
parents:
diff changeset
  1920
which tells us how $r_2$ matched $[c]$. After this we inject back the character $b$, and get
Chengsong
parents:
diff changeset
  1921
\begin{center}
Chengsong
parents:
diff changeset
  1922
$v_1 = \Seq(\Right(\Seq(\Empty, \Seq(b, c))), \Stars [])$
Chengsong
parents:
diff changeset
  1923
\end{center}
Chengsong
parents:
diff changeset
  1924
 for how 
Chengsong
parents:
diff changeset
  1925
 \begin{center}
Chengsong
parents:
diff changeset
  1926
 $r_1= (\ONE+\ZERO+\ONE \cdot b + \ZERO + \ONE \cdot b \cdot c) \cdot r*$
Chengsong
parents:
diff changeset
  1927
 \end{center}
Chengsong
parents:
diff changeset
  1928
  matched  the string $bc$ before it split into two substrings. 
Chengsong
parents:
diff changeset
  1929
  Finally, after injecting character $a$ back to $v_1$, 
Chengsong
parents:
diff changeset
  1930
  we get  the lexical value tree 
Chengsong
parents:
diff changeset
  1931
  \begin{center}
Chengsong
parents:
diff changeset
  1932
  $v_0= \Stars [\Right(\Seq(a, \Seq(b, c)))]$
Chengsong
parents:
diff changeset
  1933
  \end{center}
Chengsong
parents:
diff changeset
  1934
   for how $r$ matched $abc$. This completes the algorithm.
Chengsong
parents:
diff changeset
  1935
   
Chengsong
parents:
diff changeset
  1936
%We omit the details of injection function, which is provided by Sulzmann and Lu's paper \cite{Sulzmann2014}. 
Chengsong
parents:
diff changeset
  1937
Readers might have noticed that the lexical value information is actually
Chengsong
parents:
diff changeset
  1938
already available when doing derivatives. For example, immediately after
Chengsong
parents:
diff changeset
  1939
the operation $\backslash a$ we know that if we want to match a string
Chengsong
parents:
diff changeset
  1940
that starts with $a$, we can either take the initial match to be 
Chengsong
parents:
diff changeset
  1941
Chengsong
parents:
diff changeset
  1942
 \begin{center}
Chengsong
parents:
diff changeset
  1943
\begin{enumerate}
Chengsong
parents:
diff changeset
  1944
    \item[1)] just $a$ or
Chengsong
parents:
diff changeset
  1945
    \item[2)] string $ab$ or 
Chengsong
parents:
diff changeset
  1946
    \item[3)] string $abc$.
Chengsong
parents:
diff changeset
  1947
\end{enumerate}
Chengsong
parents:
diff changeset
  1948
\end{center}
Chengsong
parents:
diff changeset
  1949
Chengsong
parents:
diff changeset
  1950
\noindent
Chengsong
parents:
diff changeset
  1951
In order to differentiate between these choices, we just need to
Chengsong
parents:
diff changeset
  1952
remember their positions---$a$ is on the left, $ab$ is in the middle ,
Chengsong
parents:
diff changeset
  1953
and $abc$ is on the right. Which of these alternatives is chosen
Chengsong
parents:
diff changeset
  1954
later does not affect their relative position because the algorithm does
Chengsong
parents:
diff changeset
  1955
not change this order. If this parsing information can be determined and
Chengsong
parents:
diff changeset
  1956
does not change because of later derivatives, there is no point in
Chengsong
parents:
diff changeset
  1957
traversing this information twice. This leads to an optimisation---if we
Chengsong
parents:
diff changeset
  1958
store the information for lexical values inside the regular expression,
Chengsong
parents:
diff changeset
  1959
update it when we do derivative on them, and collect the information
Chengsong
parents:
diff changeset
  1960
when finished with derivatives and call $\textit{mkeps}$ for deciding which
Chengsong
parents:
diff changeset
  1961
branch is POSIX, we can generate the lexical value in one pass, instead of
Chengsong
parents:
diff changeset
  1962
doing the rest $n$ injections. This leads to Sulzmann and Lu's novel
Chengsong
parents:
diff changeset
  1963
idea of using bitcodes in derivatives.
Chengsong
parents:
diff changeset
  1964
Chengsong
parents:
diff changeset
  1965
In the next section, we shall focus on the bitcoded algorithm and the
Chengsong
parents:
diff changeset
  1966
process of simplification of regular expressions. This is needed in
Chengsong
parents:
diff changeset
  1967
order to obtain \emph{fast} versions of the Brzozowski's, and Sulzmann
Chengsong
parents:
diff changeset
  1968
and Lu's algorithms.  This is where the PhD-project aims to advance the
Chengsong
parents:
diff changeset
  1969
state-of-the-art.
Chengsong
parents:
diff changeset
  1970
Chengsong
parents:
diff changeset
  1971
Chengsong
parents:
diff changeset
  1972
\section{Simplification of Regular Expressions}
Chengsong
parents:
diff changeset
  1973
Chengsong
parents:
diff changeset
  1974
Using bitcodes to guide  parsing is not a novel idea. It was applied to
Chengsong
parents:
diff changeset
  1975
context free grammars and then adapted by Henglein and Nielson for
Chengsong
parents:
diff changeset
  1976
efficient regular expression  lexing using DFAs~\cite{nielson11bcre}.
Chengsong
parents:
diff changeset
  1977
Sulzmann and Lu took this idea of bitcodes a step further by integrating
Chengsong
parents:
diff changeset
  1978
bitcodes into derivatives. The reason why we want to use bitcodes in
Chengsong
parents:
diff changeset
  1979
this project is that we want to introduce more aggressive simplification
Chengsong
parents:
diff changeset
  1980
rules in order to keep the size of derivatives small throughout. This is
Chengsong
parents:
diff changeset
  1981
because the main drawback of building successive derivatives according
Chengsong
parents:
diff changeset
  1982
to Brzozowski's definition is that they can grow very quickly in size.
Chengsong
parents:
diff changeset
  1983
This is mainly due to the fact that the derivative operation generates
Chengsong
parents:
diff changeset
  1984
often ``useless'' $\ZERO$s and $\ONE$s in derivatives.  As a result, if
Chengsong
parents:
diff changeset
  1985
implemented naively both algorithms by Brzozowski and by Sulzmann and Lu
Chengsong
parents:
diff changeset
  1986
are excruciatingly slow. For example when starting with the regular
Chengsong
parents:
diff changeset
  1987
expression $(a + aa)^*$ and building 12 successive derivatives
Chengsong
parents:
diff changeset
  1988
w.r.t.~the character $a$, one obtains a derivative regular expression
Chengsong
parents:
diff changeset
  1989
with more than 8000 nodes (when viewed as a tree). Operations like
Chengsong
parents:
diff changeset
  1990
$\textit{der}$ and $\nullable$ need to traverse such trees and
Chengsong
parents:
diff changeset
  1991
consequently the bigger the size of the derivative the slower the
Chengsong
parents:
diff changeset
  1992
algorithm. 
Chengsong
parents:
diff changeset
  1993
Chengsong
parents:
diff changeset
  1994
Fortunately, one can simplify regular expressions after each derivative
Chengsong
parents:
diff changeset
  1995
step. Various simplifications of regular expressions are possible, such
Chengsong
parents:
diff changeset
  1996
as the simplification of $\ZERO + r$, $r + \ZERO$, $\ONE\cdot r$, $r
Chengsong
parents:
diff changeset
  1997
\cdot \ONE$, and $r + r$ to just $r$. These simplifications do not
Chengsong
parents:
diff changeset
  1998
affect the answer for whether a regular expression matches a string or
Chengsong
parents:
diff changeset
  1999
not, but fortunately also do not affect the POSIX strategy of how
Chengsong
parents:
diff changeset
  2000
regular expressions match strings---although the latter is much harder
Chengsong
parents:
diff changeset
  2001
to establish. Some initial results in this regard have been
Chengsong
parents:
diff changeset
  2002
obtained in \cite{AusafDyckhoffUrban2016}. 
Chengsong
parents:
diff changeset
  2003
Chengsong
parents:
diff changeset
  2004
Unfortunately, the simplification rules outlined above  are not
Chengsong
parents:
diff changeset
  2005
sufficient to prevent a size explosion in all cases. We
Chengsong
parents:
diff changeset
  2006
believe a tighter bound can be achieved that prevents an explosion in
Chengsong
parents:
diff changeset
  2007
\emph{all} cases. Such a tighter bound is suggested by work of Antimirov who
Chengsong
parents:
diff changeset
  2008
proved that (partial) derivatives can be bound by the number of
Chengsong
parents:
diff changeset
  2009
characters contained in the initial regular expression
Chengsong
parents:
diff changeset
  2010
\cite{Antimirov95}. He defined the \emph{partial derivatives} of regular
Chengsong
parents:
diff changeset
  2011
expressions as follows:
Chengsong
parents:
diff changeset
  2012
Chengsong
parents:
diff changeset
  2013
\begin{center}
Chengsong
parents:
diff changeset
  2014
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2015
 $\textit{pder} \; c \; \ZERO$ & $\dn$ & $\emptyset$\\
Chengsong
parents:
diff changeset
  2016
 $\textit{pder} \; c \; \ONE$ & $\dn$ & $\emptyset$ \\
Chengsong
parents:
diff changeset
  2017
 $\textit{pder} \; c \; d$ & $\dn$ & $\textit{if} \; c \,=\, d \; \{  \ONE   \}  \; \textit{else} \; \emptyset$ \\ 
Chengsong
parents:
diff changeset
  2018
  $\textit{pder} \; c \; r_1+r_2$ & $\dn$ & $pder \; c \; r_1 \cup pder \; c \;  r_2$ \\
Chengsong
parents:
diff changeset
  2019
   $\textit{pder} \; c \; r_1 \cdot r_2$ & $\dn$ & $\textit{if} \; nullable \; r_1 $\\
Chengsong
parents:
diff changeset
  2020
     & & $\textit{then} \; \{  r \cdot r_2 \mid r \in pder \; c \; r_1   \}  \cup pder \; c \; r_2 \;$\\
Chengsong
parents:
diff changeset
  2021
     & & $\textit{else} \; \{  r \cdot r_2 \mid r \in pder \; c \; r_1   \} $ \\ 
Chengsong
parents:
diff changeset
  2022
     $\textit{pder} \; c \; r^*$ & $\dn$ & $ \{  r' \cdot r^* \mid r' \in pder \; c \; r   \}  $ \\  
Chengsong
parents:
diff changeset
  2023
 \end{tabular}
Chengsong
parents:
diff changeset
  2024
 \end{center}
Chengsong
parents:
diff changeset
  2025
Chengsong
parents:
diff changeset
  2026
\noindent
Chengsong
parents:
diff changeset
  2027
A partial derivative of a regular expression $r$ is essentially a set of
Chengsong
parents:
diff changeset
  2028
regular expressions that are either $r$'s children expressions or a
Chengsong
parents:
diff changeset
  2029
concatenation of them. Antimirov has proved a tight bound of the sum of
Chengsong
parents:
diff changeset
  2030
the size of \emph{all} partial derivatives no matter what the string
Chengsong
parents:
diff changeset
  2031
looks like. Roughly speaking the size sum will be at most cubic in the
Chengsong
parents:
diff changeset
  2032
size of the regular expression.
Chengsong
parents:
diff changeset
  2033
Chengsong
parents:
diff changeset
  2034
If we want the size of derivatives in Sulzmann and Lu's algorithm to
Chengsong
parents:
diff changeset
  2035
stay below this bound, we would need more aggressive simplifications.
Chengsong
parents:
diff changeset
  2036
Essentially we need to delete useless $\ZERO$s and $\ONE$s, as well as
Chengsong
parents:
diff changeset
  2037
deleting duplicates whenever possible. For example, the parentheses in
Chengsong
parents:
diff changeset
  2038
$(a+b) \cdot c + bc$ can be opened up to get $a\cdot c +  b \cdot c + b
Chengsong
parents:
diff changeset
  2039
\cdot c$, and then simplified to just $a \cdot c + b \cdot c$. Another
Chengsong
parents:
diff changeset
  2040
example is simplifying $(a^*+a) + (a^*+ \ONE) + (a +\ONE)$ to just
Chengsong
parents:
diff changeset
  2041
$a^*+a+\ONE$. Adding these more aggressive simplification rules helps us
Chengsong
parents:
diff changeset
  2042
to achieve the same size bound as that of the partial derivatives. 
Chengsong
parents:
diff changeset
  2043
Chengsong
parents:
diff changeset
  2044
In order to implement the idea of ``spilling out alternatives'' and to
Chengsong
parents:
diff changeset
  2045
make them compatible with the $\text{inj}$-mechanism, we use
Chengsong
parents:
diff changeset
  2046
\emph{bitcodes}. Bits and bitcodes (lists of bits) are just:
Chengsong
parents:
diff changeset
  2047
Chengsong
parents:
diff changeset
  2048
%This allows us to prove a tight
Chengsong
parents:
diff changeset
  2049
%bound on the size of regular expression during the running time of the
Chengsong
parents:
diff changeset
  2050
%algorithm if we can establish the connection between our simplification
Chengsong
parents:
diff changeset
  2051
%rules and partial derivatives.
Chengsong
parents:
diff changeset
  2052
Chengsong
parents:
diff changeset
  2053
 %We believe, and have generated test
Chengsong
parents:
diff changeset
  2054
%data, that a similar bound can be obtained for the derivatives in
Chengsong
parents:
diff changeset
  2055
%Sulzmann and Lu's algorithm. Let us give some details about this next.
Chengsong
parents:
diff changeset
  2056
Chengsong
parents:
diff changeset
  2057
Chengsong
parents:
diff changeset
  2058
\begin{center}
Chengsong
parents:
diff changeset
  2059
		$b ::=   S \mid  Z \qquad
Chengsong
parents:
diff changeset
  2060
bs ::= [] \mid b:bs    
Chengsong
parents:
diff changeset
  2061
$
Chengsong
parents:
diff changeset
  2062
\end{center}
Chengsong
parents:
diff changeset
  2063
Chengsong
parents:
diff changeset
  2064
\noindent
Chengsong
parents:
diff changeset
  2065
The $S$ and $Z$ are arbitrary names for the bits in order to avoid 
Chengsong
parents:
diff changeset
  2066
confusion with the regular expressions $\ZERO$ and $\ONE$. Bitcodes (or
Chengsong
parents:
diff changeset
  2067
bit-lists) can be used to encode values (or incomplete values) in a
Chengsong
parents:
diff changeset
  2068
compact form. This can be straightforwardly seen in the following
Chengsong
parents:
diff changeset
  2069
coding function from values to bitcodes: 
Chengsong
parents:
diff changeset
  2070
Chengsong
parents:
diff changeset
  2071
\begin{center}
Chengsong
parents:
diff changeset
  2072
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2073
  $\textit{code}(\Empty)$ & $\dn$ & $[]$\\
Chengsong
parents:
diff changeset
  2074
  $\textit{code}(\Char\,c)$ & $\dn$ & $[]$\\
Chengsong
parents:
diff changeset
  2075
  $\textit{code}(\Left\,v)$ & $\dn$ & $\Z :: code(v)$\\
Chengsong
parents:
diff changeset
  2076
  $\textit{code}(\Right\,v)$ & $\dn$ & $\S :: code(v)$\\
Chengsong
parents:
diff changeset
  2077
  $\textit{code}(\Seq\,v_1\,v_2)$ & $\dn$ & $code(v_1) \,@\, code(v_2)$\\
Chengsong
parents:
diff changeset
  2078
  $\textit{code}(\Stars\,[])$ & $\dn$ & $[\Z]$\\
Chengsong
parents:
diff changeset
  2079
  $\textit{code}(\Stars\,(v\!::\!vs))$ & $\dn$ & $\S :: code(v) \;@\;
Chengsong
parents:
diff changeset
  2080
                                                 code(\Stars\,vs)$
Chengsong
parents:
diff changeset
  2081
\end{tabular}    
Chengsong
parents:
diff changeset
  2082
\end{center} 
Chengsong
parents:
diff changeset
  2083
Chengsong
parents:
diff changeset
  2084
\noindent
Chengsong
parents:
diff changeset
  2085
Here $\textit{code}$ encodes a value into a bitcodes by converting
Chengsong
parents:
diff changeset
  2086
$\Left$ into $\Z$, $\Right$ into $\S$, the start point of a non-empty
Chengsong
parents:
diff changeset
  2087
star iteration into $\S$, and the border where a local star terminates
Chengsong
parents:
diff changeset
  2088
into $\Z$. This coding is lossy, as it throws away the information about
Chengsong
parents:
diff changeset
  2089
characters, and also does not encode the ``boundary'' between two
Chengsong
parents:
diff changeset
  2090
sequence values. Moreover, with only the bitcode we cannot even tell
Chengsong
parents:
diff changeset
  2091
whether the $\S$s and $\Z$s are for $\Left/\Right$ or $\Stars$. The
Chengsong
parents:
diff changeset
  2092
reason for choosing this compact way of storing information is that the
Chengsong
parents:
diff changeset
  2093
relatively small size of bits can be easily manipulated and ``moved
Chengsong
parents:
diff changeset
  2094
around'' in a regular expression. In order to recover values, we will 
Chengsong
parents:
diff changeset
  2095
need the corresponding regular expression as an extra information. This
Chengsong
parents:
diff changeset
  2096
means the decoding function is defined as:
Chengsong
parents:
diff changeset
  2097
Chengsong
parents:
diff changeset
  2098
Chengsong
parents:
diff changeset
  2099
%\begin{definition}[Bitdecoding of Values]\mbox{}
Chengsong
parents:
diff changeset
  2100
\begin{center}
Chengsong
parents:
diff changeset
  2101
\begin{tabular}{@{}l@{\hspace{1mm}}c@{\hspace{1mm}}l@{}}
Chengsong
parents:
diff changeset
  2102
  $\textit{decode}'\,bs\,(\ONE)$ & $\dn$ & $(\Empty, bs)$\\
Chengsong
parents:
diff changeset
  2103
  $\textit{decode}'\,bs\,(c)$ & $\dn$ & $(\Char\,c, bs)$\\
Chengsong
parents:
diff changeset
  2104
  $\textit{decode}'\,(\Z\!::\!bs)\;(r_1 + r_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2105
     $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}\;
Chengsong
parents:
diff changeset
  2106
       (\Left\,v, bs_1)$\\
Chengsong
parents:
diff changeset
  2107
  $\textit{decode}'\,(\S\!::\!bs)\;(r_1 + r_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2108
     $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r_2\;\textit{in}\;
Chengsong
parents:
diff changeset
  2109
       (\Right\,v, bs_1)$\\                           
Chengsong
parents:
diff changeset
  2110
  $\textit{decode}'\,bs\;(r_1\cdot r_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2111
        $\textit{let}\,(v_1, bs_1) = \textit{decode}'\,bs\,r_1\;\textit{in}$\\
Chengsong
parents:
diff changeset
  2112
  & &   $\textit{let}\,(v_2, bs_2) = \textit{decode}'\,bs_1\,r_2$\\
Chengsong
parents:
diff changeset
  2113
  & &   \hspace{35mm}$\textit{in}\;(\Seq\,v_1\,v_2, bs_2)$\\
Chengsong
parents:
diff changeset
  2114
  $\textit{decode}'\,(\Z\!::\!bs)\,(r^*)$ & $\dn$ & $(\Stars\,[], bs)$\\
Chengsong
parents:
diff changeset
  2115
  $\textit{decode}'\,(\S\!::\!bs)\,(r^*)$ & $\dn$ & 
Chengsong
parents:
diff changeset
  2116
         $\textit{let}\,(v, bs_1) = \textit{decode}'\,bs\,r\;\textit{in}$\\
Chengsong
parents:
diff changeset
  2117
  & &   $\textit{let}\,(\Stars\,vs, bs_2) = \textit{decode}'\,bs_1\,r^*$\\
Chengsong
parents:
diff changeset
  2118
  & &   \hspace{35mm}$\textit{in}\;(\Stars\,v\!::\!vs, bs_2)$\bigskip\\
Chengsong
parents:
diff changeset
  2119
  
Chengsong
parents:
diff changeset
  2120
  $\textit{decode}\,bs\,r$ & $\dn$ &
Chengsong
parents:
diff changeset
  2121
     $\textit{let}\,(v, bs') = \textit{decode}'\,bs\,r\;\textit{in}$\\
Chengsong
parents:
diff changeset
  2122
  & & $\textit{if}\;bs' = []\;\textit{then}\;\textit{Some}\,v\;
Chengsong
parents:
diff changeset
  2123
       \textit{else}\;\textit{None}$                       
Chengsong
parents:
diff changeset
  2124
\end{tabular}    
Chengsong
parents:
diff changeset
  2125
\end{center}    
Chengsong
parents:
diff changeset
  2126
%\end{definition}
Chengsong
parents:
diff changeset
  2127
Chengsong
parents:
diff changeset
  2128
Sulzmann and Lu's integrated the bitcodes into regular expressions to
Chengsong
parents:
diff changeset
  2129
create annotated regular expressions \cite{Sulzmann2014}.
Chengsong
parents:
diff changeset
  2130
\emph{Annotated regular expressions} are defined by the following
Chengsong
parents:
diff changeset
  2131
grammar:%\comment{ALTS should have  an $as$ in  the definitions, not  just $a_1$ and $a_2$}
Chengsong
parents:
diff changeset
  2132
Chengsong
parents:
diff changeset
  2133
\begin{center}
Chengsong
parents:
diff changeset
  2134
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2135
  $\textit{a}$ & $::=$  & $\textit{ZERO}$\\
Chengsong
parents:
diff changeset
  2136
                  & $\mid$ & $\textit{ONE}\;\;bs$\\
Chengsong
parents:
diff changeset
  2137
                  & $\mid$ & $\textit{CHAR}\;\;bs\,c$\\
Chengsong
parents:
diff changeset
  2138
                  & $\mid$ & $\textit{ALTS}\;\;bs\,as$\\
Chengsong
parents:
diff changeset
  2139
                  & $\mid$ & $\textit{SEQ}\;\;bs\,a_1\,a_2$\\
Chengsong
parents:
diff changeset
  2140
                  & $\mid$ & $\textit{STAR}\;\;bs\,a$
Chengsong
parents:
diff changeset
  2141
\end{tabular}    
Chengsong
parents:
diff changeset
  2142
\end{center}  
Chengsong
parents:
diff changeset
  2143
%(in \textit{ALTS})
Chengsong
parents:
diff changeset
  2144
Chengsong
parents:
diff changeset
  2145
\noindent
Chengsong
parents:
diff changeset
  2146
where $bs$ stands for bitcodes, $a$  for $\bold{a}$nnotated regular
Chengsong
parents:
diff changeset
  2147
expressions and $as$ for a list of annotated regular expressions.
Chengsong
parents:
diff changeset
  2148
The alternative constructor($\textit{ALTS}$) has been generalized to 
Chengsong
parents:
diff changeset
  2149
accept a list of annotated regular expressions rather than just 2.
Chengsong
parents:
diff changeset
  2150
We will show that these bitcodes encode information about
Chengsong
parents:
diff changeset
  2151
the (POSIX) value that should be generated by the Sulzmann and Lu
Chengsong
parents:
diff changeset
  2152
algorithm.
Chengsong
parents:
diff changeset
  2153
Chengsong
parents:
diff changeset
  2154
Chengsong
parents:
diff changeset
  2155
To do lexing using annotated regular expressions, we shall first
Chengsong
parents:
diff changeset
  2156
transform the usual (un-annotated) regular expressions into annotated
Chengsong
parents:
diff changeset
  2157
regular expressions. This operation is called \emph{internalisation} and
Chengsong
parents:
diff changeset
  2158
defined as follows:
Chengsong
parents:
diff changeset
  2159
Chengsong
parents:
diff changeset
  2160
%\begin{definition}
Chengsong
parents:
diff changeset
  2161
\begin{center}
Chengsong
parents:
diff changeset
  2162
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2163
  $(\ZERO)^\uparrow$ & $\dn$ & $\textit{ZERO}$\\
Chengsong
parents:
diff changeset
  2164
  $(\ONE)^\uparrow$ & $\dn$ & $\textit{ONE}\,[]$\\
Chengsong
parents:
diff changeset
  2165
  $(c)^\uparrow$ & $\dn$ & $\textit{CHAR}\,[]\,c$\\
Chengsong
parents:
diff changeset
  2166
  $(r_1 + r_2)^\uparrow$ & $\dn$ &
Chengsong
parents:
diff changeset
  2167
  $\textit{ALTS}\;[]\,List((\textit{fuse}\,[\Z]\,r_1^\uparrow),\,
Chengsong
parents:
diff changeset
  2168
  (\textit{fuse}\,[\S]\,r_2^\uparrow))$\\
Chengsong
parents:
diff changeset
  2169
  $(r_1\cdot r_2)^\uparrow$ & $\dn$ &
Chengsong
parents:
diff changeset
  2170
         $\textit{SEQ}\;[]\,r_1^\uparrow\,r_2^\uparrow$\\
Chengsong
parents:
diff changeset
  2171
  $(r^*)^\uparrow$ & $\dn$ &
Chengsong
parents:
diff changeset
  2172
         $\textit{STAR}\;[]\,r^\uparrow$\\
Chengsong
parents:
diff changeset
  2173
\end{tabular}    
Chengsong
parents:
diff changeset
  2174
\end{center}    
Chengsong
parents:
diff changeset
  2175
%\end{definition}
Chengsong
parents:
diff changeset
  2176
Chengsong
parents:
diff changeset
  2177
\noindent
Chengsong
parents:
diff changeset
  2178
We use up arrows here to indicate that the basic un-annotated regular
Chengsong
parents:
diff changeset
  2179
expressions are ``lifted up'' into something slightly more complex. In the
Chengsong
parents:
diff changeset
  2180
fourth clause, $\textit{fuse}$ is an auxiliary function that helps to
Chengsong
parents:
diff changeset
  2181
attach bits to the front of an annotated regular expression. Its
Chengsong
parents:
diff changeset
  2182
definition is as follows:
Chengsong
parents:
diff changeset
  2183
Chengsong
parents:
diff changeset
  2184
\begin{center}
Chengsong
parents:
diff changeset
  2185
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2186
  $\textit{fuse}\;bs\,(\textit{ZERO})$ & $\dn$ & $\textit{ZERO}$\\
Chengsong
parents:
diff changeset
  2187
  $\textit{fuse}\;bs\,(\textit{ONE}\,bs')$ & $\dn$ &
Chengsong
parents:
diff changeset
  2188
     $\textit{ONE}\,(bs\,@\,bs')$\\
Chengsong
parents:
diff changeset
  2189
  $\textit{fuse}\;bs\,(\textit{CHAR}\,bs'\,c)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2190
     $\textit{CHAR}\,(bs\,@\,bs')\,c$\\
Chengsong
parents:
diff changeset
  2191
  $\textit{fuse}\;bs\,(\textit{ALTS}\,bs'\,as)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2192
     $\textit{ALTS}\,(bs\,@\,bs')\,as$\\
Chengsong
parents:
diff changeset
  2193
  $\textit{fuse}\;bs\,(\textit{SEQ}\,bs'\,a_1\,a_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2194
     $\textit{SEQ}\,(bs\,@\,bs')\,a_1\,a_2$\\
Chengsong
parents:
diff changeset
  2195
  $\textit{fuse}\;bs\,(\textit{STAR}\,bs'\,a)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2196
     $\textit{STAR}\,(bs\,@\,bs')\,a$
Chengsong
parents:
diff changeset
  2197
\end{tabular}    
Chengsong
parents:
diff changeset
  2198
\end{center}  
Chengsong
parents:
diff changeset
  2199
Chengsong
parents:
diff changeset
  2200
\noindent
Chengsong
parents:
diff changeset
  2201
After internalising the regular expression, we perform successive
Chengsong
parents:
diff changeset
  2202
derivative operations on the annotated regular expressions. This
Chengsong
parents:
diff changeset
  2203
derivative operation is the same as what we had previously for the
Chengsong
parents:
diff changeset
  2204
basic regular expressions, except that we beed to take care of
Chengsong
parents:
diff changeset
  2205
the bitcodes:
Chengsong
parents:
diff changeset
  2206
Chengsong
parents:
diff changeset
  2207
 %\begin{definition}{bder}
Chengsong
parents:
diff changeset
  2208
\begin{center}
Chengsong
parents:
diff changeset
  2209
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents:
diff changeset
  2210
  $(\textit{ZERO})\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
Chengsong
parents:
diff changeset
  2211
  $(\textit{ONE}\;bs)\,\backslash c$ & $\dn$ & $\textit{ZERO}$\\  
Chengsong
parents:
diff changeset
  2212
  $(\textit{CHAR}\;bs\,d)\,\backslash c$ & $\dn$ &
Chengsong
parents:
diff changeset
  2213
        $\textit{if}\;c=d\; \;\textit{then}\;
Chengsong
parents:
diff changeset
  2214
         \textit{ONE}\;bs\;\textit{else}\;\textit{ZERO}$\\  
Chengsong
parents:
diff changeset
  2215
  $(\textit{ALTS}\;bs\,as)\,\backslash c$ & $\dn$ &
Chengsong
parents:
diff changeset
  2216
  $\textit{ALTS}\;bs\,(as.map(\backslash c))$\\
Chengsong
parents:
diff changeset
  2217
  $(\textit{SEQ}\;bs\,a_1\,a_2)\,\backslash c$ & $\dn$ &
Chengsong
parents:
diff changeset
  2218
     $\textit{if}\;\textit{bnullable}\,a_1$\\
Chengsong
parents:
diff changeset
  2219
					       & &$\textit{then}\;\textit{ALTS}\,bs\,List((\textit{SEQ}\,[]\,(a_1\,\backslash c)\,a_2),$\\
Chengsong
parents:
diff changeset
  2220
					       & &$\phantom{\textit{then}\;\textit{ALTS}\,bs\,}(\textit{fuse}\,(\textit{bmkeps}\,a_1)\,(a_2\,\backslash c)))$\\
Chengsong
parents:
diff changeset
  2221
  & &$\textit{else}\;\textit{SEQ}\,bs\,(a_1\,\backslash c)\,a_2$\\
Chengsong
parents:
diff changeset
  2222
  $(\textit{STAR}\,bs\,a)\,\backslash c$ & $\dn$ &
Chengsong
parents:
diff changeset
  2223
      $\textit{SEQ}\;bs\,(\textit{fuse}\, [\Z] (r\,\backslash c))\,
Chengsong
parents:
diff changeset
  2224
       (\textit{STAR}\,[]\,r)$
Chengsong
parents:
diff changeset
  2225
\end{tabular}    
Chengsong
parents:
diff changeset
  2226
\end{center}    
Chengsong
parents:
diff changeset
  2227
%\end{definition}
Chengsong
parents:
diff changeset
  2228
Chengsong
parents:
diff changeset
  2229
\noindent
Chengsong
parents:
diff changeset
  2230
For instance, when we unfold $\textit{STAR} \; bs \; a$ into a sequence,
Chengsong
parents:
diff changeset
  2231
we need to attach an additional bit $Z$ to the front of $r \backslash c$
Chengsong
parents:
diff changeset
  2232
to indicate that there is one more star iteration. Also the $SEQ$ clause
Chengsong
parents:
diff changeset
  2233
is more subtle---when $a_1$ is $\textit{bnullable}$ (here
Chengsong
parents:
diff changeset
  2234
\textit{bnullable} is exactly the same as $\textit{nullable}$, except
Chengsong
parents:
diff changeset
  2235
that it is for annotated regular expressions, therefore we omit the
Chengsong
parents:
diff changeset
  2236
definition). Assume that $bmkeps$ correctly extracts the bitcode for how
Chengsong
parents:
diff changeset
  2237
$a_1$ matches the string prior to character $c$ (more on this later),
Chengsong
parents:
diff changeset
  2238
then the right branch of $ALTS$, which is $fuse \; bmkeps \;  a_1 (a_2
Chengsong
parents:
diff changeset
  2239
\backslash c)$ will collapse the regular expression $a_1$(as it has
Chengsong
parents:
diff changeset
  2240
already been fully matched) and store the parsing information at the
Chengsong
parents:
diff changeset
  2241
head of the regular expression $a_2 \backslash c$ by fusing to it. The
Chengsong
parents:
diff changeset
  2242
bitsequence $bs$, which was initially attached to the head of $SEQ$, has
Chengsong
parents:
diff changeset
  2243
now been elevated to the top-level of $ALTS$, as this information will be
Chengsong
parents:
diff changeset
  2244
needed whichever way the $SEQ$ is matched---no matter whether $c$ belongs
Chengsong
parents:
diff changeset
  2245
to $a_1$ or $ a_2$. After building these derivatives and maintaining all
Chengsong
parents:
diff changeset
  2246
the lexing information, we complete the lexing by collecting the
Chengsong
parents:
diff changeset
  2247
bitcodes using a generalised version of the $\textit{mkeps}$ function
Chengsong
parents:
diff changeset
  2248
for annotated regular expressions, called $\textit{bmkeps}$:
Chengsong
parents:
diff changeset
  2249
Chengsong
parents:
diff changeset
  2250
Chengsong
parents:
diff changeset
  2251
%\begin{definition}[\textit{bmkeps}]\mbox{}
Chengsong
parents:
diff changeset
  2252
\begin{center}
Chengsong
parents:
diff changeset
  2253
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2254
  $\textit{bmkeps}\,(\textit{ONE}\;bs)$ & $\dn$ & $bs$\\
Chengsong
parents:
diff changeset
  2255
  $\textit{bmkeps}\,(\textit{ALTS}\;bs\,a::as)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2256
     $\textit{if}\;\textit{bnullable}\,a$\\
Chengsong
parents:
diff changeset
  2257
  & &$\textit{then}\;bs\,@\,\textit{bmkeps}\,a$\\
Chengsong
parents:
diff changeset
  2258
  & &$\textit{else}\;bs\,@\,\textit{bmkeps}\,(\textit{ALTS}\;bs\,as)$\\
Chengsong
parents:
diff changeset
  2259
  $\textit{bmkeps}\,(\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2260
     $bs \,@\,\textit{bmkeps}\,a_1\,@\, \textit{bmkeps}\,a_2$\\
Chengsong
parents:
diff changeset
  2261
  $\textit{bmkeps}\,(\textit{STAR}\;bs\,a)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2262
     $bs \,@\, [\S]$
Chengsong
parents:
diff changeset
  2263
\end{tabular}    
Chengsong
parents:
diff changeset
  2264
\end{center}    
Chengsong
parents:
diff changeset
  2265
%\end{definition}
Chengsong
parents:
diff changeset
  2266
Chengsong
parents:
diff changeset
  2267
\noindent
Chengsong
parents:
diff changeset
  2268
This function completes the value information by travelling along the
Chengsong
parents:
diff changeset
  2269
path of the regular expression that corresponds to a POSIX value and
Chengsong
parents:
diff changeset
  2270
collecting all the bitcodes, and using $S$ to indicate the end of star
Chengsong
parents:
diff changeset
  2271
iterations. If we take the bitcodes produced by $\textit{bmkeps}$ and
Chengsong
parents:
diff changeset
  2272
decode them, we get the value we expect. The corresponding lexing
Chengsong
parents:
diff changeset
  2273
algorithm looks as follows:
Chengsong
parents:
diff changeset
  2274
Chengsong
parents:
diff changeset
  2275
\begin{center}
Chengsong
parents:
diff changeset
  2276
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2277
  $\textit{blexer}\;r\,s$ & $\dn$ &
Chengsong
parents:
diff changeset
  2278
      $\textit{let}\;a = (r^\uparrow)\backslash s\;\textit{in}$\\                
Chengsong
parents:
diff changeset
  2279
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
Chengsong
parents:
diff changeset
  2280
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
Chengsong
parents:
diff changeset
  2281
  & & $\;\;\textit{else}\;\textit{None}$
Chengsong
parents:
diff changeset
  2282
\end{tabular}
Chengsong
parents:
diff changeset
  2283
\end{center}
Chengsong
parents:
diff changeset
  2284
Chengsong
parents:
diff changeset
  2285
\noindent
Chengsong
parents:
diff changeset
  2286
In this definition $\_\backslash s$ is the  generalisation  of the derivative
Chengsong
parents:
diff changeset
  2287
operation from characters to strings (just like the derivatives for un-annotated
Chengsong
parents:
diff changeset
  2288
regular expressions).
Chengsong
parents:
diff changeset
  2289
Chengsong
parents:
diff changeset
  2290
The main point of the bitcodes and annotated regular expressions is that
Chengsong
parents:
diff changeset
  2291
we can apply rather aggressive (in terms of size) simplification rules
Chengsong
parents:
diff changeset
  2292
in order to keep derivatives small. We have developed such
Chengsong
parents:
diff changeset
  2293
``aggressive'' simplification rules and generated test data that show
Chengsong
parents:
diff changeset
  2294
that the expected bound can be achieved. Obviously we could only
Chengsong
parents:
diff changeset
  2295
partially cover  the search space as there are infinitely many regular
Chengsong
parents:
diff changeset
  2296
expressions and strings. 
Chengsong
parents:
diff changeset
  2297
Chengsong
parents:
diff changeset
  2298
One modification we introduced is to allow a list of annotated regular
Chengsong
parents:
diff changeset
  2299
expressions in the \textit{ALTS} constructor. This allows us to not just
Chengsong
parents:
diff changeset
  2300
delete unnecessary $\ZERO$s and $\ONE$s from regular expressions, but
Chengsong
parents:
diff changeset
  2301
also unnecessary ``copies'' of regular expressions (very similar to
Chengsong
parents:
diff changeset
  2302
simplifying $r + r$ to just $r$, but in a more general setting). Another
Chengsong
parents:
diff changeset
  2303
modification is that we use simplification rules inspired by Antimirov's
Chengsong
parents:
diff changeset
  2304
work on partial derivatives. They maintain the idea that only the first
Chengsong
parents:
diff changeset
  2305
``copy'' of a regular expression in an alternative contributes to the
Chengsong
parents:
diff changeset
  2306
calculation of a POSIX value. All subsequent copies can be pruned away from
Chengsong
parents:
diff changeset
  2307
the regular expression. A recursive definition of our  simplification function 
Chengsong
parents:
diff changeset
  2308
that looks somewhat similar to our Scala code is given below:
Chengsong
parents:
diff changeset
  2309
%\comment{Use $\ZERO$, $\ONE$ and so on. 
Chengsong
parents:
diff changeset
  2310
%Is it $ALTS$ or $ALTS$?}\\
Chengsong
parents:
diff changeset
  2311
Chengsong
parents:
diff changeset
  2312
\begin{center}
Chengsong
parents:
diff changeset
  2313
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents:
diff changeset
  2314
   
Chengsong
parents:
diff changeset
  2315
  $\textit{simp} \; (\textit{SEQ}\;bs\,a_1\,a_2)$ & $\dn$ & $ (\textit{simp} \; a_1, \textit{simp}  \; a_2) \; \textit{match} $ \\
Chengsong
parents:
diff changeset
  2316
   &&$\quad\textit{case} \; (\ZERO, \_) \Rightarrow  \ZERO$ \\
Chengsong
parents:
diff changeset
  2317
   &&$\quad\textit{case} \; (\_, \ZERO) \Rightarrow  \ZERO$ \\
Chengsong
parents:
diff changeset
  2318
   &&$\quad\textit{case} \;  (\ONE, a_2') \Rightarrow  \textit{fuse} \; bs \;  a_2'$ \\
Chengsong
parents:
diff changeset
  2319
   &&$\quad\textit{case} \; (a_1', \ONE) \Rightarrow  \textit{fuse} \; bs \;  a_1'$ \\
Chengsong
parents:
diff changeset
  2320
   &&$\quad\textit{case} \; (a_1', a_2') \Rightarrow  \textit{SEQ} \; bs \; a_1' \;  a_2'$ \\
Chengsong
parents:
diff changeset
  2321
Chengsong
parents:
diff changeset
  2322
  $\textit{simp} \; (\textit{ALTS}\;bs\,as)$ & $\dn$ & $\textit{distinct}( \textit{flatten} ( \textit{map simp as})) \; \textit{match} $ \\
Chengsong
parents:
diff changeset
  2323
  &&$\quad\textit{case} \; [] \Rightarrow  \ZERO$ \\
Chengsong
parents:
diff changeset
  2324
   &&$\quad\textit{case} \; a :: [] \Rightarrow  \textit{fuse bs a}$ \\
Chengsong
parents:
diff changeset
  2325
   &&$\quad\textit{case} \;  as' \Rightarrow  \textit{ALTS}\;bs\;as'$\\ 
Chengsong
parents:
diff changeset
  2326
Chengsong
parents:
diff changeset
  2327
   $\textit{simp} \; a$ & $\dn$ & $\textit{a} \qquad \textit{otherwise}$   
Chengsong
parents:
diff changeset
  2328
\end{tabular}    
Chengsong
parents:
diff changeset
  2329
\end{center}    
Chengsong
parents:
diff changeset
  2330
Chengsong
parents:
diff changeset
  2331
\noindent
Chengsong
parents:
diff changeset
  2332
The simplification does a pattern matching on the regular expression.
Chengsong
parents:
diff changeset
  2333
When it detected that the regular expression is an alternative or
Chengsong
parents:
diff changeset
  2334
sequence, it will try to simplify its children regular expressions
Chengsong
parents:
diff changeset
  2335
recursively and then see if one of the children turn into $\ZERO$ or
Chengsong
parents:
diff changeset
  2336
$\ONE$, which might trigger further simplification at the current level.
Chengsong
parents:
diff changeset
  2337
The most involved part is the $\textit{ALTS}$ clause, where we use two
Chengsong
parents:
diff changeset
  2338
auxiliary functions $\textit{flatten}$ and $\textit{distinct}$ to open up nested
Chengsong
parents:
diff changeset
  2339
$\textit{ALTS}$ and reduce as many duplicates as possible. Function
Chengsong
parents:
diff changeset
  2340
$\textit{distinct}$  keeps the first occurring copy only and remove all later ones
Chengsong
parents:
diff changeset
  2341
when detected duplicates. Function $\textit{flatten}$ opens up nested \textit{ALTS}.
Chengsong
parents:
diff changeset
  2342
Its recursive definition is given below:
Chengsong
parents:
diff changeset
  2343
Chengsong
parents:
diff changeset
  2344
 \begin{center}
Chengsong
parents:
diff changeset
  2345
  \begin{tabular}{@{}lcl@{}}
Chengsong
parents:
diff changeset
  2346
  $\textit{flatten} \; (\textit{ALTS}\;bs\,as) :: as'$ & $\dn$ & $(\textit{map} \;
Chengsong
parents:
diff changeset
  2347
     (\textit{fuse}\;bs)\; \textit{as}) \; @ \; \textit{flatten} \; as' $ \\
Chengsong
parents:
diff changeset
  2348
  $\textit{flatten} \; \textit{ZERO} :: as'$ & $\dn$ & $ \textit{flatten} \;  as' $ \\
Chengsong
parents:
diff changeset
  2349
    $\textit{flatten} \; a :: as'$ & $\dn$ & $a :: \textit{flatten} \; as'$ \quad(otherwise) 
Chengsong
parents:
diff changeset
  2350
\end{tabular}    
Chengsong
parents:
diff changeset
  2351
\end{center}  
Chengsong
parents:
diff changeset
  2352
Chengsong
parents:
diff changeset
  2353
\noindent
Chengsong
parents:
diff changeset
  2354
Here $\textit{flatten}$ behaves like the traditional functional programming flatten
Chengsong
parents:
diff changeset
  2355
function, except that it also removes $\ZERO$s. Or in terms of regular expressions, it
Chengsong
parents:
diff changeset
  2356
removes parentheses, for example changing $a+(b+c)$ into $a+b+c$.
Chengsong
parents:
diff changeset
  2357
Chengsong
parents:
diff changeset
  2358
Suppose we apply simplification after each derivative step, and view
Chengsong
parents:
diff changeset
  2359
these two operations as an atomic one: $a \backslash_{simp}\,c \dn
Chengsong
parents:
diff changeset
  2360
\textit{simp}(a \backslash c)$. Then we can use the previous natural
Chengsong
parents:
diff changeset
  2361
extension from derivative w.r.t.~character to derivative
Chengsong
parents:
diff changeset
  2362
w.r.t.~string:%\comment{simp in  the [] case?}
Chengsong
parents:
diff changeset
  2363
Chengsong
parents:
diff changeset
  2364
\begin{center}
Chengsong
parents:
diff changeset
  2365
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2366
$r \backslash_{simp} (c\!::\!s) $ & $\dn$ & $(r \backslash_{simp}\, c) \backslash_{simp}\, s$ \\
Chengsong
parents:
diff changeset
  2367
$r \backslash_{simp} [\,] $ & $\dn$ & $r$
Chengsong
parents:
diff changeset
  2368
\end{tabular}
Chengsong
parents:
diff changeset
  2369
\end{center}
Chengsong
parents:
diff changeset
  2370
Chengsong
parents:
diff changeset
  2371
\noindent
Chengsong
parents:
diff changeset
  2372
we obtain an optimised version of the algorithm:
Chengsong
parents:
diff changeset
  2373
Chengsong
parents:
diff changeset
  2374
 \begin{center}
Chengsong
parents:
diff changeset
  2375
\begin{tabular}{lcl}
Chengsong
parents:
diff changeset
  2376
  $\textit{blexer\_simp}\;r\,s$ & $\dn$ &
Chengsong
parents:
diff changeset
  2377
      $\textit{let}\;a = (r^\uparrow)\backslash_{simp}\, s\;\textit{in}$\\                
Chengsong
parents:
diff changeset
  2378
  & & $\;\;\textit{if}\; \textit{bnullable}(a)$\\
Chengsong
parents:
diff changeset
  2379
  & & $\;\;\textit{then}\;\textit{decode}\,(\textit{bmkeps}\,a)\,r$\\
Chengsong
parents:
diff changeset
  2380
  & & $\;\;\textit{else}\;\textit{None}$
Chengsong
parents:
diff changeset
  2381
\end{tabular}
Chengsong
parents:
diff changeset
  2382
\end{center}
Chengsong
parents:
diff changeset
  2383
Chengsong
parents:
diff changeset
  2384
\noindent
Chengsong
parents:
diff changeset
  2385
This algorithm keeps the regular expression size small, for example,
Chengsong
parents:
diff changeset
  2386
with this simplification our previous $(a + aa)^*$ example's 8000 nodes
Chengsong
parents:
diff changeset
  2387
will be reduced to just 6 and stays constant, no matter how long the
Chengsong
parents:
diff changeset
  2388
input string is.
Chengsong
parents:
diff changeset
  2389
Chengsong
parents:
diff changeset
  2390
Chengsong
parents:
diff changeset
  2391
Chengsong
parents:
diff changeset
  2392
\section{Current Work}
Chengsong
parents:
diff changeset
  2393
Chengsong
parents:
diff changeset
  2394
We are currently engaged in two tasks related to this algorithm. The
Chengsong
parents:
diff changeset
  2395
first task is proving that our simplification rules actually do not
Chengsong
parents:
diff changeset
  2396
affect the POSIX value that should be generated by the algorithm
Chengsong
parents:
diff changeset
  2397
according to the specification of a POSIX value and furthermore obtain a
Chengsong
parents:
diff changeset
  2398
much tighter bound on the sizes of derivatives. The result is that our
Chengsong
parents:
diff changeset
  2399
algorithm should be correct and faster on all inputs.  The original
Chengsong
parents:
diff changeset
  2400
blow-up, as observed in JavaScript, Python and Java, would be excluded
Chengsong
parents:
diff changeset
  2401
from happening in our algorithm. For this proof we use the theorem prover
Chengsong
parents:
diff changeset
  2402
Isabelle. Once completed, this result will advance the state-of-the-art:
Chengsong
parents:
diff changeset
  2403
Sulzmann and Lu wrote in their paper~\cite{Sulzmann2014} about the
Chengsong
parents:
diff changeset
  2404
bitcoded ``incremental parsing method'' (that is the lexing algorithm
Chengsong
parents:
diff changeset
  2405
outlined in this section):
Chengsong
parents:
diff changeset
  2406
Chengsong
parents:
diff changeset
  2407
\begin{quote}\it
Chengsong
parents:
diff changeset
  2408
  ``Correctness Claim: We further claim that the incremental parsing
Chengsong
parents:
diff changeset
  2409
  method in Figure~5 in combination with the simplification steps in
Chengsong
parents:
diff changeset
  2410
  Figure 6 yields POSIX parse tree [our lexical values]. We have tested this claim
Chengsong
parents:
diff changeset
  2411
  extensively by using the method in Figure~3 as a reference but yet
Chengsong
parents:
diff changeset
  2412
  have to work out all proof details.''
Chengsong
parents:
diff changeset
  2413
\end{quote}  
Chengsong
parents:
diff changeset
  2414
Chengsong
parents:
diff changeset
  2415
\noindent 
Chengsong
parents:
diff changeset
  2416
We like to settle this correctness claim. It is relatively
Chengsong
parents:
diff changeset
  2417
straightforward to establish that after one simplification step, the part of a
Chengsong
parents:
diff changeset
  2418
nullable derivative that corresponds to a POSIX value remains intact and can
Chengsong
parents:
diff changeset
  2419
still be collected, in other words, we can show that
Chengsong
parents:
diff changeset
  2420
%\comment{Double-check....I
Chengsong
parents:
diff changeset
  2421
%think this  is not the case}
Chengsong
parents:
diff changeset
  2422
%\comment{If i remember correctly, you have proved this lemma.
Chengsong
parents:
diff changeset
  2423
%I feel this is indeed not true because you might place arbitrary 
Chengsong
parents:
diff changeset
  2424
%bits on the regex r, however if this is the case, did i remember wrongly that
Chengsong
parents:
diff changeset
  2425
%you proved something like simplification does not affect $\textit{bmkeps}$ results?
Chengsong
parents:
diff changeset
  2426
%Anyway, i have amended this a little bit so it does not allow arbitrary bits attached
Chengsong
parents:
diff changeset
  2427
%to a regex. Maybe it works now.}
Chengsong
parents:
diff changeset
  2428
Chengsong
parents:
diff changeset
  2429
\begin{center}
Chengsong
parents:
diff changeset
  2430
	$\textit{bmkeps} \; a = \textit{bmkeps} \; \textit{bsimp} \; a\;($\textit{provided}$ \; a\; is \; \textit{bnullable} )$
Chengsong
parents:
diff changeset
  2431
\end{center} 
Chengsong
parents:
diff changeset
  2432
Chengsong
parents:
diff changeset
  2433
\noindent
Chengsong
parents:
diff changeset
  2434
as this basically comes down to proving actions like removing the
Chengsong
parents:
diff changeset
  2435
additional $r$ in $r+r$  does not delete important POSIX information in
Chengsong
parents:
diff changeset
  2436
a regular expression. The hard part of this proof is to establish that
Chengsong
parents:
diff changeset
  2437
Chengsong
parents:
diff changeset
  2438
\begin{center}
Chengsong
parents:
diff changeset
  2439
	$ \textit{blexer}\_{simp}(r, \; s) =  \textit{blexer}(r, \; s)$
Chengsong
parents:
diff changeset
  2440
\end{center}
Chengsong
parents:
diff changeset
  2441
%comment{This is not true either...look at the definion blexer/blexer-simp}
Chengsong
parents:
diff changeset
  2442
Chengsong
parents:
diff changeset
  2443
\noindent That is, if we do derivative on regular expression $r$ and then
Chengsong
parents:
diff changeset
  2444
simplify it, and repeat this process until we exhaust the string, we get a
Chengsong
parents:
diff changeset
  2445
regular expression $r''$($\textit{LHS}$)  that provides the POSIX matching
Chengsong
parents:
diff changeset
  2446
information, which is exactly the same as the result $r'$($\textit{RHS}$ of the
Chengsong
parents:
diff changeset
  2447
normal derivative algorithm that only does derivative repeatedly and has no
Chengsong
parents:
diff changeset
  2448
simplification at all.  This might seem at first glance very unintuitive, as
Chengsong
parents:
diff changeset
  2449
the $r'$ could be exponentially larger than $r''$, but can be explained in the
Chengsong
parents:
diff changeset
  2450
following way: we are pruning away the possible matches that are not POSIX.
Chengsong
parents:
diff changeset
  2451
Since there could be exponentially many 
Chengsong
parents:
diff changeset
  2452
non-POSIX matchings and only 1 POSIX matching, it
Chengsong
parents:
diff changeset
  2453
is understandable that our $r''$ can be a lot smaller.  we can still provide
Chengsong
parents:
diff changeset
  2454
the same POSIX value if there is one.  This is not as straightforward as the
Chengsong
parents:
diff changeset
  2455
previous proposition, as the two regular expressions $r'$ and $r''$ might have
Chengsong
parents:
diff changeset
  2456
become very different.  The crucial point is to find the
Chengsong
parents:
diff changeset
  2457
$\textit{POSIX}$  information of a regular expression and how it is modified,
Chengsong
parents:
diff changeset
  2458
augmented and propagated 
Chengsong
parents:
diff changeset
  2459
during simplification in parallel with the regular expression that
Chengsong
parents:
diff changeset
  2460
has not been simplified in the subsequent derivative operations.  To aid this,
Chengsong
parents:
diff changeset
  2461
we use the helper function retrieve described by Sulzmann and Lu:
Chengsong
parents:
diff changeset
  2462
\begin{center}
Chengsong
parents:
diff changeset
  2463
\begin{tabular}{@{}l@{\hspace{2mm}}c@{\hspace{2mm}}l@{}}
Chengsong
parents:
diff changeset
  2464
  $\textit{retrieve}\,(\textit{ONE}\,bs)\,\Empty$ & $\dn$ & $bs$\\
Chengsong
parents:
diff changeset
  2465
  $\textit{retrieve}\,(\textit{CHAR}\,bs\,c)\,(\Char\,d)$ & $\dn$ & $bs$\\
Chengsong
parents:
diff changeset
  2466
  $\textit{retrieve}\,(\textit{ALTS}\,bs\,a::as)\,(\Left\,v)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2467
     $bs \,@\, \textit{retrieve}\,a\,v$\\
Chengsong
parents:
diff changeset
  2468
  $\textit{retrieve}\,(\textit{ALTS}\,bs\,a::as)\,(\Right\,v)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2469
  $bs \,@\, \textit{retrieve}\,(\textit{ALTS}\,bs\,as)\,v$\\
Chengsong
parents:
diff changeset
  2470
  $\textit{retrieve}\,(\textit{SEQ}\,bs\,a_1\,a_2)\,(\Seq\,v_1\,v_2)$ & $\dn$ &
Chengsong
parents:
diff changeset
  2471
     $bs \,@\,\textit{retrieve}\,a_1\,v_1\,@\, \textit{retrieve}\,a_2\,v_2$\\
Chengsong
parents:
diff changeset
  2472
  $\textit{retrieve}\,(\textit{STAR}\,bs\,a)\,(\Stars\,[])$ & $\dn$ &
Chengsong
parents:
diff changeset
  2473
     $bs \,@\, [\S]$\\
Chengsong
parents:
diff changeset
  2474
  $\textit{retrieve}\,(\textit{STAR}\,bs\,a)\,(\Stars\,(v\!::\!vs))$ & $\dn$ &\\
Chengsong
parents:
diff changeset
  2475
  \multicolumn{3}{l}{
Chengsong
parents:
diff changeset
  2476
     \hspace{3cm}$bs \,@\, [\Z] \,@\, \textit{retrieve}\,a\,v\,@\,
Chengsong
parents:
diff changeset
  2477
                    \textit{retrieve}\,(\textit{STAR}\,[]\,a)\,(\Stars\,vs)$}\\
Chengsong
parents:
diff changeset
  2478
\end{tabular}
Chengsong
parents:
diff changeset
  2479
\end{center}
Chengsong
parents:
diff changeset
  2480
%\comment{Did not read further}\\
Chengsong
parents:
diff changeset
  2481
This function assembles the bitcode 
Chengsong
parents:
diff changeset
  2482
%that corresponds to a lexical value for how
Chengsong
parents:
diff changeset
  2483
%the current derivative matches the suffix of the string(the characters that
Chengsong
parents:
diff changeset
  2484
%have not yet appeared, but will appear as the successive derivatives go on.
Chengsong
parents:
diff changeset
  2485
%How do we get this "future" information? By the value $v$, which is
Chengsong
parents:
diff changeset
  2486
%computed by a pass of the algorithm that uses
Chengsong
parents:
diff changeset
  2487
%$inj$ as described in the previous section).  
Chengsong
parents:
diff changeset
  2488
using information from both the derivative regular expression and the
Chengsong
parents:
diff changeset
  2489
value. Sulzmann and Lu poroposed this function, but did not prove
Chengsong
parents:
diff changeset
  2490
anything about it. Ausaf and Urban used it to connect the bitcoded
Chengsong
parents:
diff changeset
  2491
algorithm to the older algorithm by the following equation:
Chengsong
parents:
diff changeset
  2492
 
Chengsong
parents:
diff changeset
  2493
 \begin{center} $inj \;a\; c \; v = \textit{decode} \; (\textit{retrieve}\;
Chengsong
parents:
diff changeset
  2494
	 (r^\uparrow)\backslash_{simp} \,c)\,v)$ 
Chengsong
parents:
diff changeset
  2495
 \end{center} 
Chengsong
parents:
diff changeset
  2496
Chengsong
parents:
diff changeset
  2497
\noindent
Chengsong
parents:
diff changeset
  2498
whereby $r^\uparrow$ stands for the internalised version of $r$. Ausaf
Chengsong
parents:
diff changeset
  2499
and Urban also used this fact to prove  the correctness of bitcoded
Chengsong
parents:
diff changeset
  2500
algorithm without simplification.  Our purpose of using this, however,
Chengsong
parents:
diff changeset
  2501
is to establish 
Chengsong
parents:
diff changeset
  2502
Chengsong
parents:
diff changeset
  2503
\begin{center}
Chengsong
parents:
diff changeset
  2504
$ \textit{retrieve} \;
Chengsong
parents:
diff changeset
  2505
a \; v \;=\; \textit{retrieve}  \; (\textit{simp}\,a) \; v'.$
Chengsong
parents:
diff changeset
  2506
\end{center}
Chengsong
parents:
diff changeset
  2507
The idea is that using $v'$, a simplified version of $v$ that had gone
Chengsong
parents:
diff changeset
  2508
through the same simplification step as $\textit{simp}(a)$, we are able
Chengsong
parents:
diff changeset
  2509
to extract the bitcode that gives the same parsing information as the
Chengsong
parents:
diff changeset
  2510
unsimplified one. However, we noticed that constructing such a  $v'$
Chengsong
parents:
diff changeset
  2511
from $v$ is not so straightforward. The point of this is that  we might
Chengsong
parents:
diff changeset
  2512
be able to finally bridge the gap by proving
Chengsong
parents:
diff changeset
  2513
Chengsong
parents:
diff changeset
  2514
\begin{center}
Chengsong
parents:
diff changeset
  2515
$\textit{retrieve} \; (r^\uparrow   \backslash  s) \; v = \;\textit{retrieve} \;
Chengsong
parents:
diff changeset
  2516
(\textit{simp}(r^\uparrow)  \backslash  s) \; v'$
Chengsong
parents:
diff changeset
  2517
\end{center}
Chengsong
parents:
diff changeset
  2518
Chengsong
parents:
diff changeset
  2519
\noindent
Chengsong
parents:
diff changeset
  2520
and subsequently
Chengsong
parents:
diff changeset
  2521
Chengsong
parents:
diff changeset
  2522
\begin{center}
Chengsong
parents:
diff changeset
  2523
$\textit{retrieve} \; (r^\uparrow \backslash  s) \; v\; = \; \textit{retrieve} \;
Chengsong
parents:
diff changeset
  2524
(r^\uparrow  \backslash_{simp}  \, s) \; v'$.
Chengsong
parents:
diff changeset
  2525
\end{center}
Chengsong
parents:
diff changeset
  2526
Chengsong
parents:
diff changeset
  2527
\noindent
Chengsong
parents:
diff changeset
  2528
The $\textit{LHS}$ of the above equation is the bitcode we want. This
Chengsong
parents:
diff changeset
  2529
would prove that our simplified version of regular expression still
Chengsong
parents:
diff changeset
  2530
contains all the bitcodes needed. The task here is to find a way to
Chengsong
parents:
diff changeset
  2531
compute the correct $v'$.
Chengsong
parents:
diff changeset
  2532
Chengsong
parents:
diff changeset
  2533
The second task is to speed up the more aggressive simplification.  Currently
Chengsong
parents:
diff changeset
  2534
it is slower than the original naive simplification by Ausaf and Urban (the
Chengsong
parents:
diff changeset
  2535
naive version as implemented by Ausaf   and Urban of course can ``explode'' in
Chengsong
parents:
diff changeset
  2536
some cases).  It is therefore not surprising that the speed is also much slower
Chengsong
parents:
diff changeset
  2537
than regular expression engines in popular programming languages such as Java
Chengsong
parents:
diff changeset
  2538
and Python on most inputs that are linear. For example, just by rewriting the
Chengsong
parents:
diff changeset
  2539
example regular expression in the beginning of this report  $(a^*)^*\,b$ into
Chengsong
parents:
diff changeset
  2540
$a^*\,b$ would eliminate the ambiguity in the matching and make the time
Chengsong
parents:
diff changeset
  2541
for matching linear with respect to the input string size. This allows the 
Chengsong
parents:
diff changeset
  2542
DFA approach to become blindingly fast, and dwarf the speed of our current
Chengsong
parents:
diff changeset
  2543
implementation. For example, here is a comparison of Java regex engine 
Chengsong
parents:
diff changeset
  2544
and our implementation on this example.
Chengsong
parents:
diff changeset
  2545
Chengsong
parents:
diff changeset
  2546
\begin{center}
Chengsong
parents:
diff changeset
  2547
\begin{tabular}{@{}c@{\hspace{0mm}}c@{\hspace{0mm}}c@{}}
Chengsong
parents:
diff changeset
  2548
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  2549
\begin{axis}[
Chengsong
parents:
diff changeset
  2550
    xlabel={$n*1000$},
Chengsong
parents:
diff changeset
  2551
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  2552
    ylabel={time in secs},
Chengsong
parents:
diff changeset
  2553
    enlargelimits=false,
Chengsong
parents:
diff changeset
  2554
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  2555
    xmax=33,
Chengsong
parents:
diff changeset
  2556
    ymax=9,
Chengsong
parents:
diff changeset
  2557
    scaled ticks=true,
Chengsong
parents:
diff changeset
  2558
    axis lines=left,
Chengsong
parents:
diff changeset
  2559
    width=5cm,
Chengsong
parents:
diff changeset
  2560
    height=4cm, 
Chengsong
parents:
diff changeset
  2561
    legend entries={Bitcoded Algorithm},  
Chengsong
parents:
diff changeset
  2562
    legend pos=north west,
Chengsong
parents:
diff changeset
  2563
    legend cell align=left]
Chengsong
parents:
diff changeset
  2564
\addplot[red,mark=*, mark options={fill=white}] table {bad-scala.data};
Chengsong
parents:
diff changeset
  2565
\end{axis}
Chengsong
parents:
diff changeset
  2566
\end{tikzpicture}
Chengsong
parents:
diff changeset
  2567
  &
Chengsong
parents:
diff changeset
  2568
\begin{tikzpicture}
Chengsong
parents:
diff changeset
  2569
\begin{axis}[
Chengsong
parents:
diff changeset
  2570
    xlabel={$n*1000$},
Chengsong
parents:
diff changeset
  2571
    x label style={at={(1.05,-0.05)}},
Chengsong
parents:
diff changeset
  2572
    %ylabel={time in secs},
Chengsong
parents:
diff changeset
  2573
    enlargelimits=false,
Chengsong
parents:
diff changeset
  2574
    xtick={0,5,...,30},
Chengsong
parents:
diff changeset
  2575
    xmax=33,
Chengsong
parents:
diff changeset
  2576
    ymax=9,
Chengsong
parents:
diff changeset
  2577
    scaled ticks=false,
Chengsong
parents:
diff changeset
  2578
    axis lines=left,
Chengsong
parents:
diff changeset
  2579
    width=5cm,
Chengsong
parents:
diff changeset
  2580
    height=4cm, 
Chengsong
parents:
diff changeset
  2581
    legend entries={Java},  
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parents:
diff changeset
  2582
    legend pos=north west,
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parents:
diff changeset
  2583
    legend cell align=left]
Chengsong
parents:
diff changeset
  2584
\addplot[cyan,mark=*, mark options={fill=white}] table {good-java.data};
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parents:
diff changeset
  2585
\end{axis}
Chengsong
parents:
diff changeset
  2586
\end{tikzpicture}\\
Chengsong
parents:
diff changeset
  2587
\multicolumn{3}{c}{Graphs: Runtime for matching $a^*\,b$ with strings 
Chengsong
parents:
diff changeset
  2588
           of the form $\underbrace{aa..a}_{n}$.}
Chengsong
parents:
diff changeset
  2589
\end{tabular}    
Chengsong
parents:
diff changeset
  2590
\end{center}  
Chengsong
parents:
diff changeset
  2591
Chengsong
parents:
diff changeset
  2592
Chengsong
parents:
diff changeset
  2593
Java regex engine can match string of thousands of characters in a few milliseconds,
Chengsong
parents:
diff changeset
  2594
whereas our current algorithm gets excruciatingly slow on input of this size.
Chengsong
parents:
diff changeset
  2595
The running time in theory is linear, however it does not appear to be the 
Chengsong
parents:
diff changeset
  2596
case in an actual implementation. So it needs to be explored how to
Chengsong
parents:
diff changeset
  2597
make our algorithm faster on all inputs.  It could be the recursive calls that are
Chengsong
parents:
diff changeset
  2598
needed to manipulate bits that are causing the slow down. A possible solution
Chengsong
parents:
diff changeset
  2599
is to write recursive functions into tail-recusive form.
Chengsong
parents:
diff changeset
  2600
Another possibility would be to explore
Chengsong
parents:
diff changeset
  2601
again the connection to DFAs to speed up the algorithm on 
Chengsong
parents:
diff changeset
  2602
subcalls that are small enough. This is very much work in progress.
Chengsong
parents:
diff changeset
  2603
Chengsong
parents:
diff changeset
  2604
\section{Conclusion}
Chengsong
parents:
diff changeset
  2605
Chengsong
parents:
diff changeset
  2606
In this PhD-project we are interested in fast algorithms for regular
Chengsong
parents:
diff changeset
  2607
expression matching. While this seems to be a ``settled'' area, in
Chengsong
parents:
diff changeset
  2608
fact interesting research questions are popping up as soon as one steps
Chengsong
parents:
diff changeset
  2609
outside the classic automata theory (for example in terms of what kind
Chengsong
parents:
diff changeset
  2610
of regular expressions are supported). The reason why it is
Chengsong
parents:
diff changeset
  2611
interesting for us to look at the derivative approach introduced by
Chengsong
parents:
diff changeset
  2612
Brzozowski for regular expression matching, and then much further
Chengsong
parents:
diff changeset
  2613
developed by Sulzmann and Lu, is that derivatives can elegantly deal
Chengsong
parents:
diff changeset
  2614
with some of the regular expressions that are of interest in ``real
Chengsong
parents:
diff changeset
  2615
life''. This includes the not-regular expression, written $\neg\,r$
Chengsong
parents:
diff changeset
  2616
(that is all strings that are not recognised by $r$), but also bounded
Chengsong
parents:
diff changeset
  2617
regular expressions such as $r^{\{n\}}$ and $r^{\{n..m\}}$). There is
Chengsong
parents:
diff changeset
  2618
also hope that the derivatives can provide another angle for how to
Chengsong
parents:
diff changeset
  2619
deal more efficiently with back-references, which are one of the
Chengsong
parents:
diff changeset
  2620
reasons why regular expression engines in JavaScript, Python and Java
Chengsong
parents:
diff changeset
  2621
choose to not implement the classic automata approach of transforming
Chengsong
parents:
diff changeset
  2622
regular expressions into NFAs and then DFAs---because we simply do not
Chengsong
parents:
diff changeset
  2623
know how such back-references can be represented by DFAs.
Chengsong
parents:
diff changeset
  2624
We also plan to implement the bitcoded algorithm
Chengsong
parents:
diff changeset
  2625
in some imperative language like C to see if the inefficiency of the 
Chengsong
parents:
diff changeset
  2626
Scala implementation
Chengsong
parents:
diff changeset
  2627
is language specific. To make this research more comprehensive we also plan
Chengsong
parents:
diff changeset
  2628
to contrast our (faster) version of bitcoded algorithm with the
Chengsong
parents:
diff changeset
  2629
Symbolic Regex Matcher, the RE2, the Rust Regex Engine, and the static
Chengsong
parents:
diff changeset
  2630
analysis approach by implementing them in the same language and then compare
Chengsong
parents:
diff changeset
  2631
their performance.
Chengsong
parents:
diff changeset
  2632
Chengsong
parents:
diff changeset
  2633
\bibliographystyle{plain}
Chengsong
parents:
diff changeset
  2634
\bibliography{root}
Chengsong
parents:
diff changeset
  2635
Chengsong
parents:
diff changeset
  2636
Chengsong
parents:
diff changeset
  2637
\end{document}