updated
authorChristian Urban <urbanc@in.tum.de>
Mon, 19 Nov 2018 23:21:32 +0000
changeset 604 9e75249e96f2
parent 603 155430aea517
child 605 bf0f370d42ba
updated
handouts/ho08.pdf
handouts/ho08.tex
Binary file handouts/ho08.pdf has changed
--- a/handouts/ho08.tex	Mon Nov 19 22:44:56 2018 +0000
+++ b/handouts/ho08.tex	Mon Nov 19 23:21:32 2018 +0000
@@ -22,12 +22,12 @@
 
 The language we looked at in the previous lecture was rather
 primitive and the compiler rather crude---everything was
-essentially estimated into a big monolithic chunk of code
+essentially compiled into a big monolithic chunk of code
 inside the main function. In this handout we like to have a
 look at a slightly more comfortable language, which I call
 Fun-language, and a tiny-teeny bit more realistic compiler.
 The Fun-language is a functional programming language. A small
-collection of programs we want to be able to write and estimate
+collection of programs we want to be able to write and compile
 is as follows:
 
 \begin{lstlisting}[numbers=none]
@@ -49,7 +49,7 @@
 more comfortable. We will still focus on programs involving
 integers only, that means for example that every function is
 expected to return an integer. The point of the Fun language
-is to estimate each function to a separate method in JVM
+is to compile each function to a separate method in JVM
 bytecode (not just a big monolithic code chunk). The means we
 need to adapt to some of the conventions of the JVM about
 methods.
@@ -122,8 +122,8 @@
 
 Let us first look at some clauses for compiling expressions.
 The compilation of arithmetic and boolean expressions is just
-like for the While-language and do not need any modification.
-(recall that the \textit{estimate}-function for boolean
+like for the While-language and do not need any modification
+(recall that the \textit{compile}-function for boolean
 expression takes a third argument for the label where the
 control-flow should jump when the boolean expression is
 \emph{not} true---this is needed for compiling \pcode{if}s).
@@ -227,7 +227,7 @@
 the Halting problem, and thus undecidable in general. 
 Fortunately, we are only asked how much stack a \emph{single} 
 call of the function requires. This can be relatively easily
-estimated by recursively analysing which instructions we 
+compiled by recursively analysing which instructions we 
 generate and how much stack they might require.
  
 \begin{center}