Binary file handouts/ho08.pdf has changed

--- a/handouts/ho08.tex	Mon Nov 19 22:16:25 2018 +0000
+++ b/handouts/ho08.tex	Mon Nov 19 22:44:56 2018 +0000
@@ -1,3 +1,4 @@
+% !TEX program = xelatex
 \documentclass{article}
 \usepackage{../style}
 \usepackage{../langs}
@@ -20,11 +21,11 @@
 
 
 The language we looked at in the previous lecture was rather
-primitive and the estimater rather crude---everything was
+primitive and the compiler rather crude---everything was
 essentially estimated into a big monolithic chunk of code
 inside the main function. In this handout we like to have a
 look at a slightly more comfortable language, which I call
-Fun-language, and a tiny-teeny bit more realistic estimater.
+Fun-language, and a tiny-teeny bit more realistic compiler.
 The Fun-language is a functional programming language. A small
 collection of programs we want to be able to write and estimate
 is as follows:
@@ -124,7 +125,7 @@
 like for the While-language and do not need any modification.
 (recall that the \textit{estimate}-function for boolean
 expression takes a third argument for the label where the
-contro-flow should jump when the boolean expression is
+control-flow should jump when the boolean expression is
 \emph{not} true---this is needed for compiling \pcode{if}s).
 One additional feature in the Fun-language are sequences.
 Their purpose is to do one calculation after another. The
@@ -184,7 +185,7 @@
 argument-expression of write, which in the While-language was
 only allowed to be a single variable.
 
-Most of the new code in the estimater for the Fun-language
+Most of the new code in the compiler for the Fun-language
 comes from function definitions and function calls. For this
 have a look again at the helper function in
 Figure~\ref{write}. Assuming we have a function definition
@@ -268,7 +269,7 @@
                 else suc(add(x - 1, y));
 \end{lstlisting}
 
-\noindent The succesor function is a simple loading of the
+\noindent The successor function is a simple loading of the
 argument $x$ (index $0$) onto the stack, as well as the number
 $1$. Then we add both elements leaving the result of the 
 addition on top of the stack. This value will be returned by