
diff -r 46eee459a999 -r 66adcae6c762 handouts/ho05.tex
--- a/handouts/ho05.tex	Thu Oct 05 14:36:54 2023 +0100
+++ b/handouts/ho05.tex	Fri Oct 13 15:07:37 2023 +0100
@@ -82,7 +82,7 @@
 \end{center}  
 
 \noindent
-from natural languages were the meaning of \emph{flies} depends on the
+from natural languages where the meaning of \emph{flies} depends on the
 surrounding \emph{context} are avoided as much as possible. Here is
 an interesting video about C++ not being a context-free language
 
@@ -368,7 +368,7 @@
 
 \noindent
 The point is that we can in principle transform every left-recursive
-grammar into one that is non-left-recursive one. This explains why often
+grammar into one that is non-left-recursive. This explains why often
 the following grammar is used for arithmetic expressions:
 
 \begin{plstx}[margin=1cm]
@@ -380,7 +380,7 @@
 \noindent
 In this grammar all $\meta{E}$xpressions, $\meta{T}$erms and
 $\meta{F}$actors are in some way protected from being
-left-recusive. For example if you start $\meta{E}$ you can derive
+left-recursive. For example if you start $\meta{E}$ you can derive
 another one by going through $\meta{T}$, then $\meta{F}$, but then
 $\meta{E}$ is protected by the open-parenthesis in the last rule.
 
@@ -408,7 +408,7 @@
 $\epsilon$-rules from grammars. Consider again the grammar above for
 binary numbers where have a rule $\meta{B'} ::= \epsilon$. In this case
 we look for rules of the (generic) form \mbox{$\meta{A} :=
-\alpha\cdot\meta{B'}\cdot\beta$}. That is there are rules that use
+\alpha\cdot\meta{B'}\cdot\beta$}. That is, there are rules that use
 $\meta{B'}$ and something ($\alpha$) is in front of $\meta{B'}$ and
 something follows ($\beta$). Such rules need to be replaced by
 additional rules of the form \mbox{$\meta{A} := \alpha\cdot\beta$}.
@@ -419,7 +419,7 @@
   : \meta{B} ::= 0 \cdot \meta{B'} | 1 \cdot \meta{B'}\\
 \end{plstx} 
 
-\noindent To follow the general scheme of the transfromation,
+\noindent To follow the general scheme of the transformation,
 the $\alpha$ is either is either $0$ or $1$, and the $\beta$ happens
 to be empty. So we need to generate new rules for the form 
 \mbox{$\meta{A} := \alpha\cdot\beta$}, which in our particular 




