\documentclass[dvipsnames,14pt,t]{beamer}
\usepackage{beamerthemeplaincu}
\usepackage[absolute,overlay]{textpos}
\usepackage{ifthen}
\usepackage{tikz}
\usepackage{pgf}
\usepackage{calc}
\usepackage{ulem}
\usepackage{courier}
\usepackage{listings}
\renewcommand{\uline}[1]{#1}
\usetikzlibrary{arrows}
\usetikzlibrary{automata}
\usetikzlibrary{shapes}
\usetikzlibrary{shadows}
\usetikzlibrary{positioning}
\usetikzlibrary{calc}
\usepackage{graphicx}
\usepackage{pgfplots}
\usepackage{fontspec}
\usepackage{../langs}
\usepackage{../data}
% beamer stuff
\renewcommand{\slidecaption}{AFL 05, King's College London, 23.~October 2013}
\newcommand{\bl}[1]{\textcolor{blue}{#1}}
\newcommand{\dn}{\stackrel{\mbox{\scriptsize def}}{=}}% for definitions
\begin{document}
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\mode<presentation>{
\begin{frame}<1>[t]
\frametitle{%
\begin{tabular}{@ {}c@ {}}
\\[-3mm]
\LARGE Automata and \\[-2mm]
\LARGE Formal Languages (5)\\[3mm]
\end{tabular}}
\normalsize
\begin{center}
\begin{tabular}{ll}
Email: & christian.urban at kcl.ac.uk\\
Office: & S1.27 (1st floor Strand Building)\\
Slides: & KEATS (also home work is there)\\
\end{tabular}
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{DFA Minimisation}
\begin{enumerate}
\item Take all pairs \bl{$(q, p)$} with \bl{$q \not= p$}
\item Mark all pairs that accepting and non-accepting states
\item For all unmarked pairs \bl{$(q, p)$} and all characters \bl{$c$} tests wether
\begin{center}
\bl{$(\delta(q, c), \delta(p,c))$}
\end{center}
are marked. If yes, then also mark \bl{$(q, p)$}.
\item Repeat last step until no chance.
\item All unmarked pairs can be merged.
\end{enumerate}
\end{frame}}
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\mode<presentation>{
\begin{frame}<1-2>[c]
\begin{center}
\begin{tikzpicture}[>=stealth',very thick,auto,
every state/.style={minimum size=0pt,inner sep=2pt,draw=blue!50,very thick,fill=blue!20},]
\node[state,initial] (q_0) {$q_0$};
\node[state] (q_1) [right=of q_0] {$q_1$};
\node[state] (q_2) [below right=of q_0] {$q_2$};
\node[state] (q_3) [right=of q_2] {$q_3$};
\node[state, accepting] (q_4) [right=of q_1] {$q_4$};
\path[->] (q_0) edge node [above] {\alert{$a$}} (q_1);
\path[->] (q_1) edge node [above] {\alert{$a$}} (q_4);
\path[->] (q_4) edge [loop right] node {\alert{$a, b$}} ();
\path[->] (q_3) edge node [right] {\alert{$a$}} (q_4);
\path[->] (q_2) edge node [above] {\alert{$a$}} (q_3);
\path[->] (q_1) edge node [right] {\alert{$b$}} (q_2);
\path[->] (q_0) edge node [above] {\alert{$b$}} (q_2);
\path[->] (q_2) edge [loop left] node {\alert{$b$}} ();
\path[->] (q_3) edge [bend left=95, looseness=1.3] node [below] {\alert{$b$}} (q_0);
\end{tikzpicture}
\end{center}
\mbox{}\\[-20mm]\mbox{}
\begin{center}
\begin{tikzpicture}[scale=0.8,line width=0.8mm]
\draw (0,0) -- (4,0);
\draw (0,1) -- (4,1);
\draw (0,2) -- (3,2);
\draw (0,3) -- (2,3);
\draw (0,4) -- (1,4);
\draw (0,0) -- (0, 4);
\draw (1,0) -- (1, 4);
\draw (2,0) -- (2, 3);
\draw (3,0) -- (3, 2);
\draw (4,0) -- (4, 1);
\draw (0.5,-0.5) node {$q_0$};
\draw (1.5,-0.5) node {$q_1$};
\draw (2.5,-0.5) node {$q_2$};
\draw (3.5,-0.5) node {$q_3$};
\draw (-0.5, 3.5) node {$q_1$};
\draw (-0.5, 2.5) node {$q_2$};
\draw (-0.5, 1.5) node {$q_3$};
\draw (-0.5, 0.5) node {$q_4$};
\draw (0.5,0.5) node {\large$\star$};
\draw (1.5,0.5) node {\large$\star$};
\draw (2.5,0.5) node {\large$\star$};
\draw (3.5,0.5) node {\large$\star$};
\end{tikzpicture}\\
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}<1-2>[c]
\begin{center}
\begin{tabular}{@{\hspace{-8mm}}cc@{}}
\begin{tikzpicture}[>=stealth',very thick,auto,
every state/.style={minimum size=0pt,inner sep=2pt,draw=blue!50,very thick,fill=blue!20},]
\node[state,initial] (q_0) {$q_0$};
\node[state] (q_1) [right=of q_0] {$q_1$};
\node[state] (q_2) [below right=of q_0] {$q_2$};
\node[state] (q_3) [right=of q_2] {$q_3$};
\node[state, accepting] (q_4) [right=of q_1] {$q_4$};
\path[->] (q_0) edge node [above] {\alert{$a$}} (q_1);
\path[->] (q_1) edge node [above] {\alert{$a$}} (q_4);
\path[->] (q_4) edge [loop right] node {\alert{$a, b$}} ();
\path[->] (q_3) edge node [right] {\alert{$a$}} (q_4);
\path[->] (q_2) edge node [above] {\alert{$a$}} (q_3);
\path[->] (q_1) edge node [right] {\alert{$b$}} (q_2);
\path[->] (q_0) edge node [above] {\alert{$b$}} (q_2);
\path[->] (q_2) edge [loop left] node {\alert{$b$}} ();
\path[->] (q_3) edge [bend left=95, looseness=1.3] node [below] {\alert{$b$}} (q_0);
\end{tikzpicture}
&
\raisebox{9mm}{\begin{tikzpicture}[scale=0.6,line width=0.8mm]
\draw (0,0) -- (4,0);
\draw (0,1) -- (4,1);
\draw (0,2) -- (3,2);
\draw (0,3) -- (2,3);
\draw (0,4) -- (1,4);
\draw (0,0) -- (0, 4);
\draw (1,0) -- (1, 4);
\draw (2,0) -- (2, 3);
\draw (3,0) -- (3, 2);
\draw (4,0) -- (4, 1);
\draw (0.5,-0.5) node {$q_0$};
\draw (1.5,-0.5) node {$q_1$};
\draw (2.5,-0.5) node {$q_2$};
\draw (3.5,-0.5) node {$q_3$};
\draw (-0.5, 3.5) node {$q_1$};
\draw (-0.5, 2.5) node {$q_2$};
\draw (-0.5, 1.5) node {$q_3$};
\draw (-0.5, 0.5) node {$q_4$};
\draw (0.5,0.5) node {\large$\star$};
\draw (1.5,0.5) node {\large$\star$};
\draw (2.5,0.5) node {\large$\star$};
\draw (3.5,0.5) node {\large$\star$};
\draw (0.5,1.5) node {\large$\star$};
\draw (2.5,1.5) node {\large$\star$};
\draw (0.5,3.5) node {\large$\star$};
\draw (1.5,2.5) node {\large$\star$};
\end{tikzpicture}}
\end{tabular}
\end{center}
\mbox{}\\[-20mm]\mbox{}
\begin{center}
\begin{tikzpicture}[>=stealth',very thick,auto,
every state/.style={minimum size=0pt,inner sep=2pt,draw=blue!50,very thick,fill=blue!20},]
\node[state,initial] (q_02) {$q_{0, 2}$};
\node[state] (q_13) [right=of q_02] {$q_{1, 3}$};
\node[state, accepting] (q_4) [right=of q_13] {$q_{4\phantom{,0}}$};
\path[->] (q_02) edge [bend left] node [above] {\alert{$a$}} (q_13);
\path[->] (q_13) edge [bend left] node [below] {\alert{$b$}} (q_02);
\path[->] (q_02) edge [loop below] node {\alert{$b$}} ();
\path[->] (q_13) edge node [above] {\alert{$a$}} (q_4);
\path[->] (q_4) edge [loop above] node {\alert{$a, b$}} ();
\end{tikzpicture}\\
minimal automaton
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\begin{center}
\begin{tikzpicture}[>=stealth',very thick,auto,
every state/.style={minimum size=0pt,inner sep=2pt,draw=blue!50,very thick,fill=blue!20},]
\only<1>{\node[state,initial] (q_0) {$q_0$};}
\only<2->{\node[state,accepting] (q_0) {$q_0$};}
\node[state] (q_1) [right=of q_0] {$q_1$};
\node[state] (q_2) [below right=of q_0] {$q_2$};
\node[state] (q_3) [right=of q_2] {$q_3$};
\only<1>{\node[state, accepting] (q_4) [right=of q_1] {$q_4$};}
\only<2->{\node[state, initial right] (q_4) [right=of q_1] {$q_4$};}
\only<1-2>{
\path[->] (q_0) edge node [above] {\alert{$a$}} (q_1);
\path[->] (q_1) edge node [above] {\alert{$a$}} (q_4);
\path[->] (q_4) edge [loop above] node {\alert{$a, b$}} ();
\path[->] (q_3) edge node [right] {\alert{$a$}} (q_4);
\path[->] (q_2) edge node [above] {\alert{$a$}} (q_3);
\path[->] (q_1) edge node [right] {\alert{$b$}} (q_2);
\path[->] (q_0) edge node [above] {\alert{$b$}} (q_2);
\path[->] (q_2) edge [loop left] node {\alert{$b$}} ();
\path[->] (q_3) edge [bend left=95, looseness=1.3] node [below] {\alert{$b$}} (q_0);}
\only<3->{
\path[<-] (q_0) edge node [above] {\alert{$a$}} (q_1);
\path[<-] (q_1) edge node [above] {\alert{$a$}} (q_4);
\path[<-] (q_4) edge [loop above] node {\alert{$a, b$}} ();
\path[<-] (q_3) edge node [right] {\alert{$a$}} (q_4);
\path[<-] (q_2) edge node [above] {\alert{$a$}} (q_3);
\path[<-] (q_1) edge node [right] {\alert{$b$}} (q_2);
\path[<-] (q_0) edge node [above] {\alert{$b$}} (q_2);
\path[<-] (q_2) edge [loop left] node {\alert{$b$}} ();
\path[<-] (q_3) edge [bend left=95, looseness=1.3] node [below] {\alert{$b$}} (q_0);}
\end{tikzpicture}
\end{center}
\begin{itemize}
\item<2-> exchange initial / accepting states
\item<3-> reverse all edges
\item<4-> subset construction $\Rightarrow$ DFA
\item<5-> repeat once more \onslide<6->{$\Rightarrow$ minimal DFA}
\end{itemize}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\mbox{\lstinputlisting[language=while]{../progs/fib.while}}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\mbox{\lstinputlisting[language=while]{../progs/collatz.while}}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\mbox{\lstinputlisting[language=while]{../progs/collatz.while}}
\begin{textblock}{6}(10,2)
\begin{tikzpicture}[scale=0.46]
\begin{axis}[axis x line=bottom, axis y line=left, ylabel=secs,
xlabel=n,
enlargelimits=0.05,
ybar interval=0.7, legend style=small]
\addplot file {interpreted2.data};
\addplot file {compiled2.data};
%\legend{interpreted, compiled}
\end{axis}
\end{tikzpicture}
\end{textblock}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\begin{tikzpicture}[scale=1]
\draw[line width=1mm] (-.3, 0) rectangle (1.5,2);
\draw (4.2,1) node {Code Gen};
\draw (0.6,1.7) node {\footnotesize Parser};
\draw (-2.7,1.7) node {\footnotesize Lexer};
\draw[line width=1mm] (-1.8, 0) rectangle (-3.6,2);
\draw[white] (1.7,1) node (X) {};
\draw[white] (3.2,1) node (Y) {};
\draw[red, ->, line width = 2mm] (X) -- (Y);
\draw[red, <-, line width = 2mm] (-0.6,1) -- (-1.6,1);
\draw[red, <-, line width = 2mm] (-3.8,1) -- (-4.8,1);
\end{tikzpicture}
\end{frame}}
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\mode<presentation>{
\begin{frame}[t]
\consolas
\begin{center}
"if true then then 42 else +"
\end{center}
\begin{tabular}{@{}l}
KEYWORD: \\
\hspace{5mm}{if}, {then}, {else},\\
WHITESPACE:\\
\hspace{5mm}{" "}, {$\backslash$n},\\
IDENT:\\
\hspace{5mm}LETTER $\cdot$ (LETTER + DIGIT + {\_})$^*$\\
NUM:\\
\hspace{5mm}(NONZERODIGIT $\cdot$ DIGIT$^*$) + {0}\\
OP:\\
\hspace{5mm}{+}\\
COMMENT:\\
\hspace{5mm}{$\slash$*} $\cdot$ (ALL$^*$ $\cdot$ {*$\slash$} $\cdot$ ALL$^*$) $\cdot$ {*$\slash$}
\end{tabular}
\end{frame}}
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\mode<presentation>{
\begin{frame}[t]
\consolas
\begin{center}
"if true then then 42 else +"
\end{center}
\only<1>{
\small\begin{tabular}{l}
KEYWORD(if),\\
WHITESPACE,\\
IDENT(true),\\
WHITESPACE,\\
KEYWORD(then),\\
WHITESPACE,\\
KEYWORD(then),\\
WHITESPACE,\\
NUM(42),\\
WHITESPACE,\\
KEYWORD(else),\\
WHITESPACE,\\
OP(+)
\end{tabular}}
\only<2>{
\small\begin{tabular}{l}
KEYWORD(if),\\
IDENT(true),\\
KEYWORD(then),\\
KEYWORD(then),\\
NUM(42),\\
KEYWORD(else),\\
OP(+)
\end{tabular}}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
There is one small problem with the tokenizer. How should we
tokenize:
\begin{center}
{\consolas "x - 3"}
\end{center}
\consolas
\begin{tabular}{@{}l}
OP:\\
\hspace{5mm}\texttt{"+"}, \texttt{"-"}\\
NUM:\\
\hspace{5mm}(NONZERODIGIT $\cdot$ DIGIT$^*$) + {''0''}\\
NUMBER:\\
\hspace{5mm}NUM + (\texttt{"-"} $\cdot$ NUM)\\
\end{tabular}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Two Rules\end{tabular}}
\begin{itemize}
\item Longest match rule (``maximal munch rule''): The
longest initial substring matched by any regular expression is taken
as next token.\bigskip
\item Rule priority:
For a particular longest initial substring, the first regular
expression that can match determines the token.
\end{itemize}
%\url{http://www.technologyreview.com/tr10/?year=2011}
%finite deterministic automata/ nondeterministic automaton
%\item problem with infix operations, for example i-12
\end{frame}}
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\mode<presentation>{
\begin{frame}[t]
\frametitle{\begin{tabular}{c}Nullable\end{tabular}}
\small
\ldots{}whether a regular expression can match the empty string:
\begin{center}
\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}
\bl{$nullable(\varnothing)$} & \bl{$\dn$} & \bl{$f\!\/alse$}\\
\bl{$nullable(\epsilon)$} & \bl{$\dn$} & \bl{$true$}\\
\bl{$nullable (c)$} & \bl{$\dn$} & \bl{$f\!alse$}\\
\bl{$nullable (r_1 + r_2)$} & \bl{$\dn$} & \bl{$nullable(r_1) \vee nullable(r_2)$} \\
\bl{$nullable (r_1 \cdot r_2)$} & \bl{$\dn$} & \bl{$nullable(r_1) \wedge nullable(r_2)$} \\
\bl{$nullable (r^*)$} & \bl{$\dn$} & \bl{$true$} \\
\end{tabular}
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Zeroable\end{tabular}}
\small
\ldots{}whether a regular expression can match nothing:
\begin{center}
\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}
\bl{$zeroable(\varnothing)$} & \bl{$\dn$} & \bl{$true$}\\
\bl{$zeroable(\epsilon)$} & \bl{$\dn$} & \bl{$f\!alse$}\\
\bl{$zeroable (c)$} & \bl{$\dn$} & \bl{$f\!alse$}\\
\bl{$zeroable (r_1 + r_2)$} & \bl{$\dn$} & \bl{$zeroable(r_1) \wedge zeroable(r_2)$} \\
\bl{$zeroable (r_1 \cdot r_2)$} & \bl{$\dn$} & \bl{$zeroable(r_1) \vee zeroable(r_2)$} \\
\bl{$zeroable (r^*)$} & \bl{$\dn$} & \bl{$f\!alse$} \\
\end{tabular}
\end{center}\bigskip\pause
\begin{center}
\bl{$zeroable(r) \Leftrightarrow L(r) = \varnothing$}
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\begin{itemize}
\item The star-case in our proof about the matcher needs the following lemma
\begin{center}
\bl{$Der\,c\,A^* = (Der\,c\,A)\,@\, A^*$}
\end{center}
\end{itemize}\bigskip\bigskip
\begin{itemize}
\item \bl{$A^* = \{""\} \cup A\,@\,A^*$}
\item If \bl{\texttt{""} $\in A$}, then\\ \bl{$Der\,c\,(A @ B) = (Der\,c\,A) @ B \cup (Der\,c\,B)$}\medskip
\item If \bl{\texttt{""} $\not\in A$}, then\\ \bl{$Der\,c\,(A @ B) = (Der\,c\,A) @ B$}
\end{itemize}
\end{frame}}
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\end{document}
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