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\section*{Homework 2}
\HEADER
\begin{enumerate}
\item What is the difference between \emph{basic} regular expressions
and \emph{extended} regular expressions?
\solution{Basic regular expressions are $\ZERO$, $\ONE$, $c$, $r_1 + r_2$,
$r_1 \cdot r_2$, $r^*$. The extended ones are the bounded
repetitions, not, etc.}
\item What is the language recognised by the regular
expressions $(\ZERO^*)^*$.
\solution{$L(\ZERO^*{}^*) = \{[]\}$,
remember * always includes the empty string}
\item Review the first handout about sets of strings and read
the second handout. Assuming the alphabet is the set
$\{a, b\}$, decide which of the following equations are
true in general for arbitrary languages $A$, $B$ and
$C$:
\begin{eqnarray}
(A \cup B) @ C & =^? & A @ C \cup B @ C\nonumber\\
A^* \cup B^* & =^? & (A \cup B)^*\nonumber\\
A^* @ A^* & =^? & A^*\nonumber\\
(A \cap B)@ C & =^? & (A@C) \cap (B@C)\nonumber
\end{eqnarray}
\noindent In case an equation is true, give an
explanation; otherwise give a counter-example.
\solution{1 + 3 are equal; 2 + 4 are not. Interesting is 4 where
$A = \{[a]\}$, $B = \{[]\}$ and $C = \{[a], []\}$}
\item Given the regular expressions $r_1 = \ONE$ and $r_2 =
\ZERO$ and $r_3 = a$. How many strings can the regular
expressions $r_1^*$, $r_2^*$ and $r_3^*$ each match?
\solution{$r_1$ and $r_2$ can match the empty string only, $r_3$ can
match $[]$, $a$, $aa$, ....}
\item Give regular expressions for (a) decimal numbers and for
(b) binary numbers. Hint: Observe that the empty string
is not a number. Also observe that leading 0s are
normally not written---for example the JSON format for numbers
explicitly forbids this.
\solution{Just numbers without leading 0s: $0 + (1..9)\cdot(0..1)^*$;
can be extended to decimal; similar for binary numbers
}
\item Decide whether the following two regular expressions are
equivalent $(\ONE + a)^* \equiv^? a^*$ and $(a \cdot
b)^* \cdot a \equiv^? a \cdot (b \cdot a)^*$.
\solution{Both are equivalent, but why the second? Essentially you have to show that each string in one set is in the other. For 2 this means you can do an induction proof that $(ab)^na$ is the same string as $a(ba)^n$, where the former is in the first set and the latter in the second.}
\item Given the regular expression $r = (a \cdot b + b)^*$.
Compute what the derivative of $r$ is with respect to
$a$, $b$ and $c$. Is $r$ nullable?
\item Give an argument for why the following holds:
if $r$ is nullable then $r^{\{n\}} \equiv r^{\{..n\}}$.
\solution{This was from last week; I just explicitly added it here.}
\item Define what is meant by the derivative of a regular
expressions with respect to a character. (Hint: The
derivative is defined recursively.)
\solution{the recursive function for $der$}
\item Assume the set $Der$ is defined as
\begin{center}
$Der\,c\,A \dn \{ s \;|\; c\!::\!s \in A\}$
\end{center}
What is the relation between $Der$ and the notion of
derivative of regular expressions?
\solution{Main property is $L(der\,c\,r) = Der\,c\,(L(r))$.}
\item Give a regular expression over the alphabet $\{a,b\}$
recognising all strings that do not contain any
substring $bb$ and end in $a$.
\item Do $(a + b)^* \cdot b^+$ and $(a^* \cdot b^+) +
(b^*\cdot b^+)$ define the same language?
\solution{No, the first one can match for example abababababbbbb}
\item Define the function $zeroable$ by recursion over regular
expressions. This function should satisfy the property
\[
zeroable(r) \;\;\text{if and only if}\;\;L(r) = \{\}\qquad(*)
\]
The function $nullable$ for the not-regular expressions
can be defined by
\[
nullable(\sim r) \dn \neg(nullable(r))
\]
Unfortunately, a similar definition for $zeroable$ does
not satisfy the property in $(*)$:
\[
zeroable(\sim r) \dn \neg(zeroable(r))
\]
Find a counter example?
\item Give a regular expressions that can recognise all
strings from the language $\{a^n\;|\;\exists k.\; n = 3 k
+ 1 \}$.
\solution{$a(aaa)^*$}
\item Give a regular expression that can recognise an odd
number of $a$s or an even number of $b$s.
\item \POSTSCRIPT
\end{enumerate}
\end{document}
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