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basicstyle=\ttfamily,
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% beamer stuff
\renewcommand{\slidecaption}{AFL 02, King's College London, 3.~October 2012}
\newcommand{\bl}[1]{\textcolor{blue}{#1}}
\newcommand{\dn}{\stackrel{\mbox{\scriptsize def}}{=}}% for definitions
\begin{document}
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\mode<presentation>{
\begin{frame}<1>[t]
\frametitle{%
\begin{tabular}{@ {}c@ {}}
\\[-3mm]
\LARGE Automata and \\[-2mm]
\LARGE Formal Languages (2)\\[3mm]
\end{tabular}}
%\begin{center}
%\includegraphics[scale=0.3]{pics/ante1.jpg}\hspace{5mm}
%\includegraphics[scale=0.31]{pics/ante2.jpg}\\
%\footnotesize\textcolor{gray}{Antikythera automaton, 100 BC (Archimedes?)}
%\end{center}
\normalsize
\begin{center}
\begin{tabular}{ll}
Email: & christian.urban at kcl.ac.uk\\
Of$\!$fice: & S1.27 (1st floor Strand Building)\\
Slides: & KEATS
\end{tabular}
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Languages\end{tabular}}
A \alert{language} is a set of strings.\bigskip
A \alert{regular expression} specifies a set of strings or language.
\end{frame}}
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\mode<presentation>{
\begin{frame}[t]
\frametitle{\begin{tabular}{c}Regular Expressions\end{tabular}}
Their inductive definition:
\begin{textblock}{6}(2,5)
\begin{tabular}{@ {}rrl@ {\hspace{13mm}}l}
\bl{r} & \bl{$::=$} & \bl{$\varnothing$} & null\\
& \bl{$\mid$} & \bl{$\epsilon$} & empty string / "" / []\\
& \bl{$\mid$} & \bl{c} & character\\
& \bl{$\mid$} & \bl{r$_1$ $\cdot$ r$_2$} & sequence\\
& \bl{$\mid$} & \bl{r$_1$ + r$_2$} & alternative / choice\\
& \bl{$\mid$} & \bl{r$^*$} & star (zero or more)\\
\end{tabular}
\end{textblock}
\end{frame}}
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\mode<presentation>{
\begin{frame}[t]
\frametitle{\begin{tabular}{c}Regular Expressions\end{tabular}}
Their implementation in Scala:
{\lstset{language=Scala}\fontsize{8}{10}\selectfont
\texttt{\lstinputlisting{app51.scala}}}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}The Meaning of a\\[-2mm] Regular Expression\end{tabular}}
\begin{textblock}{15}(1,4)
\begin{tabular}{@ {}rcl}
\bl{$L$($\varnothing$)} & \bl{$\dn$} & \bl{$\varnothing$}\\
\bl{$L$($\epsilon$)} & \bl{$\dn$} & \bl{$\{$""$\}$}\\
\bl{$L$(c)} & \bl{$\dn$} & \bl{$\{$"c"$\}$}\\
\bl{$L$(r$_1$ + r$_2$)} & \bl{$\dn$} & \bl{$L$(r$_1$) $\cup$ $L$(r$_2$)}\\
\bl{$L$(r$_1$ $\cdot$ r$_2$)} & \bl{$\dn$} & \bl{$L$(r$_1$) @ $L$(r$_2$)}\\
\bl{$L$(r$^*$)} & \bl{$\dn$} & \bl{$\bigcup_{n \ge 0}$ $L$(r)$^n$}\\
\end{tabular}\bigskip
\hspace{5mm}\textcolor{gray}{$L$(r)$^0$ $\;\dn\;$ $\{$""$\}$}\\
\textcolor{gray}{$L$(r)$^{n+1}$ $\;\dn\;$ $L$(r) @ $L$(r)$^n$}
\end{textblock}
\only<2->{
\begin{textblock}{5}(11,5)
\textcolor{gray}{\small
A @ B\\
\ldots you take out every string from A and
concatenate it with every string in B
}
\end{textblock}}
\only<3->{
\begin{textblock}{6}(9,12)\small
\bl{$L$} is a function from regular expressions to sets of strings\\
\bl{$L$ : Rexp $\Rightarrow$ Set[String]}
\end{textblock}}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\large
\begin{center}
What is \bl{$L$(a$^*$)}?
\end{center}
\end{frame}}
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\newcommand{\YES}{\textcolor{gray}{yes}}
\newcommand{\NO}{\textcolor{gray}{no}}
\newcommand{\FORALLR}{\textcolor{gray}{$\forall$ r.}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Reg Exp Equivalences\end{tabular}}
\begin{center}
\begin{tabular}{l@ {\hspace{7mm}}rcl@ {\hspace{7mm}}l}
&\bl{(a + b) + c} & \bl{$\equiv^?$} & \bl{a + (b + c)} & \onslide<2->{\YES}\\
&\bl{a + a} & \bl{$\equiv^?$} & \bl{a} & \onslide<3->{\YES}\\
&\bl{(a $\cdot$ b) $\cdot$ c} & \bl{$\equiv^?$} & \bl{a $\cdot$ (b $\cdot$ c)} & \onslide<4->{\YES}\\
&\bl{a $\cdot$ a} & \bl{$\equiv^?$} & \bl{a} & \onslide<5->{\NO}\\
&\bl{$\epsilon^*$} & \bl{$\equiv^?$} & \bl{$\epsilon$} & \onslide<6->{\YES}\\
&\bl{$\varnothing^*$} & \bl{$\equiv^?$} & \bl{$\varnothing$} & \onslide<7->{\NO}\\
\FORALLR &\bl{r $\cdot$ $\epsilon$} & \bl{$\equiv^?$} & \bl{r} & \onslide<8->{\YES}\\
\FORALLR &\bl{r + $\epsilon$} & \bl{$\equiv^?$} & \bl{r} & \onslide<9->{\NO}\\
\FORALLR &\bl{r + $\varnothing$} & \bl{$\equiv^?$} & \bl{r} & \onslide<10->{\YES}\\
\FORALLR &\bl{r $\cdot$ $\varnothing$} & \bl{$\equiv^?$} & \bl{r} & \onslide<11->{\NO}\\
&\bl{c $\cdot$ (a + b)} & \bl{$\equiv^?$} & \bl{(c $\cdot$ a) + (c $\cdot$ b)} & \onslide<12->{\YES}\\
&\bl{a$^*$} & \bl{$\equiv^?$} & \bl{$\epsilon$ + (a $\cdot$ a$^*$)} & \onslide<13->{\YES}
\end{tabular}
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}The Meaning of Matching\end{tabular}}
\large
a regular expression \bl{r} matches a string \bl{s} is defined as
\begin{center}
\bl{s $\in$ $L$(r)}\\
\end{center}\bigskip\bigskip\pause
\small
if \bl{r$_1$ $\equiv$ r$_2$}, then \bl{$s$ $\in$ $L$(r$_1$)} iff \bl{$s$ $\in$ $L$(r$_2$)}
\end{frame}}
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\mode<presentation>{
\begin{frame}[t]
\frametitle{\begin{tabular}{c}A Matching Algorithm\end{tabular}}
\begin{itemize}
\item given a regular expression \bl{r} and a string \bl{s}, say yes or no for whether
\begin{center}
\bl{s $\in$ $L$(r)}
\end{center}
or not.\bigskip\bigskip\pause
\end{itemize}\pause
\small
\begin{itemize}
\item Identifiers (strings of letters or digits, starting with a letter)
\item Integers (a non-empty sequence of digits)
\item Keywords (else, if, while, \ldots)
\item White space (a non-empty sequence of blanks, newlines and tabs)
\end{itemize}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}A Matching Algorithm\end{tabular}}
\small
whether a regular expression matches the empty string:\medskip
{\lstset{language=Scala}\fontsize{8}{10}\selectfont
\texttt{\lstinputlisting{app5.scala}}}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}The Derivative of a Rexp\end{tabular}}
\large
If \bl{r} matches the string \bl{c::s}, what is a regular expression that matches \bl{s}?\bigskip\bigskip\bigskip\bigskip
\small
\bl{der c r} gives the answer
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}The Derivative\end{tabular}}
\begin{center}
\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {\hspace{-10mm}}l@ {}}
\bl{der c ($\varnothing$)} & \bl{$\dn$} & \bl{$\varnothing$} & \\
\bl{der c ($\epsilon$)} & \bl{$\dn$} & \bl{$\varnothing$} & \\
\bl{der c (d)} & \bl{$\dn$} & \bl{if c $=$ d then [] else $\varnothing$} & \\
\bl{der c (r$_1$ + r$_2$)} & \bl{$\dn$} & \bl{(der c r$_1$) + (der c r$_2$)} & \\
\bl{der c (r$_1$ $\cdot$ r$_2$)} & \bl{$\dn$} & \bl{((der c r$_1$) $\cdot$ r$_2$) + } & \\
& & \bl{\hspace{3mm}(if nullable r$_1$ then der c r$_2$ else $\varnothing$)}\\
\bl{der c (r$^*$)} & \bl{$\dn$} & \bl{(der c r) $\cdot$ (r$^*$)} &\smallskip\\\pause
\bl{ders [] r} & \bl{$\dn$} & \bl{r} & \\
\bl{ders (c::s) r} & \bl{$\dn$} & \bl{ders s (der c r)} & \\
\end{tabular}
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}The Derivative\end{tabular}}
{\lstset{language=Scala}\fontsize{8}{10}\selectfont
\texttt{\lstinputlisting{app6.scala}}}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}The Rexp Matcher\end{tabular}}
{\lstset{language=Scala}\fontsize{8}{10}\selectfont
\texttt{\lstinputlisting{app7.scala}}}
\end{frame}}
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\mode<presentation>{
\begin{frame}[t]
\frametitle{\begin{tabular}{c}Proofs about Rexp\end{tabular}}
Remember their inductive definition:\\[5cm]
\begin{textblock}{6}(5,5)
\begin{tabular}{@ {}rrl}
\bl{r} & \bl{$::=$} & \bl{$\varnothing$}\\
& \bl{$\mid$} & \bl{$\epsilon$} \\
& \bl{$\mid$} & \bl{c} \\
& \bl{$\mid$} & \bl{r$_1$ $\cdot$ r$_2$}\\
& \bl{$\mid$} & \bl{r$_1$ + r$_2$} \\
& \bl{$\mid$} & \bl{r$^*$} \\
\end{tabular}
\end{textblock}
If we want to prove something, say a property \bl{$P$(r)}, for all regular expressions \bl{r} then \ldots
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Proofs about Rexp (2)\end{tabular}}
\begin{itemize}
\item \bl{$P$} holds for \bl{$\varnothing$}, \bl{$\epsilon$} and \bl{c}\bigskip
\item \bl{$P$} holds for \bl{r$_1$ + r$_2$} under the assumption that \bl{$P$} already
holds for \bl{r$_1$} and \bl{r$_2$}.\bigskip
\item \bl{$P$} holds for \bl{r$_1$ $\cdot$ r$_2$} under the assumption that \bl{$P$} already
holds for \bl{r$_1$} and \bl{r$_2$}.
\item \bl{$P$} holds for \bl{r$^*$} under the assumption that \bl{$P$} already
holds for \bl{r}.
\end{itemize}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Proofs about Rexp (3)\end{tabular}}
Assume \bl{$P(r)$} is the property:
\begin{center}
\bl{nullable(r)} if and only if \bl{"" $\in$ $L$(r)}
\end{center}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Proofs about Strings\end{tabular}}
If we want to prove something, say a property \bl{$P$(s)}, for all strings \bl{s} then \ldots\bigskip
\begin{itemize}
\item \bl{$P$} holds for the empty string, and\medskip
\item \bl{$P$} holds for the string \bl{c::s} under the assumption that \bl{$P$}
already holds for \bl{s}
\end{itemize}
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Regular Languages\end{tabular}}
A language (set of strings) is \alert{regular} iff there exists
a regular expression that recognises all its strings.
\end{frame}}
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\mode<presentation>{
\begin{frame}[c]
\frametitle{\begin{tabular}{c}Automata\end{tabular}}
A deterministic finite automaton consists of:
\begin{itemize}
\item a set of states
\item one of these states is the start state
\item some states are accepting states, and
\item there is transition function\medskip
\small
which takes a state as argument and a character and produces a new state\smallskip\\
this function might not always be defined
\end{itemize}
\end{frame}}
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\end{document}
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