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morekeywords={abstract,case,catch,class,def,%+ −
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% beamer stuff + −
\renewcommand{\slidecaption}{AFL 03, King's College London, 10.~October 2012}+ −
\newcommand{\bl}[1]{\textcolor{blue}{#1}} + −
\newcommand{\dn}{\stackrel{\mbox{\scriptsize def}}{=}}% for definitions+ −
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\begin{document}+ −
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%+ −
\mode<presentation>{+ −
\begin{frame}<1>[t]+ −
\frametitle{%+ −
\begin{tabular}{@ {}c@ {}}+ −
\\[-3mm]+ −
\LARGE Automata and \\[-2mm] + −
\LARGE Formal Languages (3)\\[3mm] + −
\end{tabular}}+ −
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%\begin{center}+ −
%\includegraphics[scale=0.3]{pics/ante1.jpg}\hspace{5mm}+ −
%\includegraphics[scale=0.31]{pics/ante2.jpg}\\+ −
%\footnotesize\textcolor{gray}{Antikythera automaton, 100 BC (Archimedes?)}+ −
%\end{center}+ −
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\normalsize+ −
\begin{center}+ −
\begin{tabular}{ll}+ −
Email: & christian.urban at kcl.ac.uk\\+ −
Of$\!$fice: & S1.27 (1st floor Strand Building)\\+ −
Slides: & KEATS (also home work is there)\\+ −
& \alert{\bf (I have put a temporary link in there.)}\\+ −
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\end{center}+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}Last Week\end{tabular}}+ −
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Last week I showed you+ −
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\begin{itemize}+ −
\item one simple-minded regular expression matcher (which however does not work in all cases), and\bigskip+ −
\item one which works provably in all cases+ −
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\begin{center}+ −
\bl{matcher r s} \;\;if and only if \;\; \bl{s $\in$ $L$(r)}+ −
\end{center} + −
\end{itemize}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}The Derivative of a Rexp\end{tabular}}+ −
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\begin{center}+ −
\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {\hspace{-10mm}}l@ {}}+ −
\bl{der c ($\varnothing$)} & \bl{$\dn$} & \bl{$\varnothing$} & \\+ −
\bl{der c ($\epsilon$)} & \bl{$\dn$} & \bl{$\varnothing$} & \\+ −
\bl{der c (d)} & \bl{$\dn$} & \bl{if c $=$ d then $\epsilon$ else $\varnothing$} & \\+ −
\bl{der c (r$_1$ + r$_2$)} & \bl{$\dn$} & \bl{(der c r$_1$) + (der c r$_2$)} & \\+ −
\bl{der c (r$_1$ $\cdot$ r$_2$)} & \bl{$\dn$} & \bl{if nullable r$_1$}\\+ −
& & \bl{then ((der c r$_1$) $\cdot$ r$_2$) + (der c r$_2$)}\\ + −
& & \bl{else (der c r$_1$) $\cdot$ r$_2$}\\+ −
\bl{der c (r$^*$)} & \bl{$\dn$} & \bl{(der c r) $\cdot$ (r$^*$)}\\+ −
\end{tabular}+ −
\end{center}+ −
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``the regular expression after \bl{c} has been recognised'' + −
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\end{frame}}+ −
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\mode<presentation>{+ −
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For this we defined the set \bl{Der c A} as+ −
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\begin{center}+ −
\bl{Der c A $\dn$ $\{$ s $|$ c::s $\in$ A$\}$ } + −
\end{center}+ −
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which is called the semantic derivative of a set+ −
and proved + −
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\begin{center}+ −
\bl{$L$(der c r) $=$ Der c ($L$(r))}+ −
\end{center}+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}The Idea of the Algorithm\end{tabular}}+ −
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If we want to recognise the string \bl{abc} with regular expression \bl{r}+ −
then\medskip+ −
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\begin{enumerate}+ −
\item \bl{Der a ($L$(r))}\pause+ −
\item \bl{Der b (Der a ($L$(r)))}+ −
\item \bl{Der c (Der b (Der a ($L$(r))))}\pause+ −
\item finally we test whether the empty string is in set\pause\medskip+ −
\end{enumerate}+ −
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The matching algorithm works similarly, just over regular expression than sets.+ −
\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
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Input: string \bl{abc} and regular expression \bl{r} + −
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\begin{enumerate}+ −
\item \bl{der a r}+ −
\item \bl{der b (der a r)}+ −
\item \bl{der c (der b (der a r))}\pause+ −
\item finally check whether the latter regular expression can match the empty string+ −
\end{enumerate}+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
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We need to prove+ −
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\begin{center}+ −
\bl{$L$(der c r) $=$ Der c ($L$(r))}+ −
\end{center}+ −
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by induction on the regular expression.+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}Proofs about Rexp\end{tabular}}+ −
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\begin{itemize}+ −
\item \bl{$P$} holds for \bl{$\varnothing$}, \bl{$\epsilon$} and \bl{c}\bigskip+ −
\item \bl{$P$} holds for \bl{r$_1$ + r$_2$} under the assumption that \bl{$P$} already+ −
holds for \bl{r$_1$} and \bl{r$_2$}.\bigskip+ −
\item \bl{$P$} holds for \bl{r$_1$ $\cdot$ r$_2$} under the assumption that \bl{$P$} already+ −
holds for \bl{r$_1$} and \bl{r$_2$}.+ −
\item \bl{$P$} holds for \bl{r$^*$} under the assumption that \bl{$P$} already+ −
holds for \bl{r}.+ −
\end{itemize}+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}Proofs about Natural Numbers\\ and Strings\end{tabular}}+ −
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\begin{itemize}+ −
\item \bl{$P$} holds for \bl{$0$} and+ −
\item \bl{$P$} holds for \bl{$n + 1$} under the assumption that \bl{$P$} already+ −
holds for \bl{$n$}+ −
\end{itemize}\bigskip+ −
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\begin{itemize}+ −
\item \bl{$P$} holds for \bl{\texttt{""}} and+ −
\item \bl{$P$} holds for \bl{$c\!::\!s$} under the assumption that \bl{$P$} already+ −
holds for \bl{$s$}+ −
\end{itemize}+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[t]+ −
\frametitle{\begin{tabular}{c}Regular Expressions\end{tabular}}+ −
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\begin{center}+ −
\begin{tabular}{@ {}rrl@ {\hspace{13mm}}l}+ −
\bl{r} & \bl{$::=$} & \bl{$\varnothing$} & null\\+ −
& \bl{$\mid$} & \bl{$\epsilon$} & empty string / "" / []\\+ −
& \bl{$\mid$} & \bl{c} & character\\+ −
& \bl{$\mid$} & \bl{r$_1$ $\cdot$ r$_2$} & sequence\\+ −
& \bl{$\mid$} & \bl{r$_1$ + r$_2$} & alternative / choice\\+ −
& \bl{$\mid$} & \bl{r$^*$} & star (zero or more)\\+ −
\end{tabular}\bigskip\pause+ −
\end{center}+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}Languages\end{tabular}}+ −
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A \alert{language} is a set of strings.\bigskip+ −
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A \alert{regular expression} specifies a set of strings or language.\bigskip+ −
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A language is \alert{regular} iff there exists+ −
a regular expression that recognises all its strings.\bigskip\bigskip\pause+ −
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\textcolor{gray}{not all languages are regular, e.g.~\bl{a$^n$b$^n$}.}+ −
\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[t]+ −
\frametitle{\begin{tabular}{c}Regular Expressions\end{tabular}}+ −
+ −
\begin{center}+ −
\begin{tabular}{@ {}rrl@ {\hspace{13mm}}l}+ −
\bl{r} & \bl{$::=$} & \bl{$\varnothing$} & null\\+ −
& \bl{$\mid$} & \bl{$\epsilon$} & empty string / "" / []\\+ −
& \bl{$\mid$} & \bl{c} & character\\+ −
& \bl{$\mid$} & \bl{r$_1$ $\cdot$ r$_2$} & sequence\\+ −
& \bl{$\mid$} & \bl{r$_1$ + r$_2$} & alternative / choice\\+ −
& \bl{$\mid$} & \bl{r$^*$} & star (zero or more)\\+ −
\end{tabular}\bigskip+ −
\end{center}+ −
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How about ranges \bl{[a-z]}, \bl{r$^\text{+}$} and \bl{!r}?+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}Negation of Regular Expr's\end{tabular}}+ −
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\begin{itemize}+ −
\item \bl{!r} \hspace{6mm} (everything that \bl{r} cannot recognise)\medskip+ −
\item \bl{$L$(!r) $\dn$ UNIV - $L$(r)}\medskip+ −
\item \bl{nullable (!r) $\dn$ not (nullable(r))}\medskip+ −
\item \bl{der\,c\,(!r) $\dn$ !(der\,c\,r)}+ −
\end{itemize}+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}Regular Exp's for Lexing\end{tabular}}+ −
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Lexing separates strings into ``words'' / components.+ −
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\begin{itemize}+ −
\item Identifiers (non-empty strings of letters or digits, starting with a letter)+ −
\item Numbers (non-empty sequences of digits omitting leading zeros)+ −
\item Keywords (else, if, while, \ldots)+ −
\item White space (a non-empty sequence of blanks, newlines and tabs)+ −
\item Comments+ −
\end{itemize}+ −
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\end{frame}}+ −
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\mode<presentation>{+ −
\begin{frame}[c]+ −
\frametitle{\begin{tabular}{c}Automata\end{tabular}}+ −
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A deterministic finite automaton consists of:+ −
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\begin{itemize}+ −
\item a set of states+ −
\item one of these states is the start state+ −
\item some states are accepting states, and+ −
\item there is transition function\medskip + −
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\small+ −
which takes a state as argument and a character and produces a new state\smallskip\\+ −
this function might not always be defined+ −
\end{itemize}+ −
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\end{frame}}+ −
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\end{document}+ −
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