coursework/cw01.tex
author Christian Urban <urbanc@in.tum.de>
Sun, 21 May 2017 00:43:02 +0100
changeset 492 39b7ff2cf1bc
parent 473 dc528091eb70
child 494 d0fc671bcbbf
permissions -rw-r--r--
updated

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\section*{Coursework 1 (Strand 1)}

This coursework is worth 4\% and is due on 25 October at
16:00. You are asked to implement a regular expression matcher
and submit a document containing the answers for the questions
below. You can do the implementation in any programming
language you like, but you need to submit the source code with
which you answered the questions, otherwise a mark of 0\% will
be awarded. You can submit your answers in a txt-file or pdf.
Code send as code.



\subsubsection*{Disclaimer}

It should be understood that the work you submit represents
your own effort. You have not copied from anyone else. An
exception is the Scala code I showed during the lectures or
uploaded to KEATS, which you can freely use.\bigskip


\subsection*{Task}

The task is to implement a regular expression matcher based on
derivatives of regular expressions. The implementation should
be able to deal with the usual (basic) regular expressions

\[
\ZERO,\; \ONE,\; c,\; r_1 + r_2,\; r_1 \cdot r_2,\; r^*
\]

\noindent
but also with the following extended regular expressions:

\begin{center}
\begin{tabular}{ll}
  $[c_1,c_2,\ldots,c_n]$ & a set of characters---for character ranges\\
  $r^+$ & one or more times $r$\\
  $r^?$ & optional $r$\\
  $r^{\{n\}}$ & exactly $n$-times\\
  $r^{\{..m\}}$ & zero or more times $r$ but no more than $m$-times\\
  $r^{\{n..\}}$ & at least $n$-times $r$\\
  $r^{\{n..m\}}$ & at least $n$-times $r$ but no more than $m$-times\\
  $\sim{}r$ & not-regular-expression of $r$\\
\end{tabular}
\end{center}

\noindent You can assume that $n$ and $m$ are greater or equal than
$0$. In the case of $r^{\{n,m\}}$ you can also assume $0 \le n \le m$.\bigskip

\noindent {\bf Important!} Your implementation should have explicit
cases for the basic regular expressions, but also explicit cases for
the extended regular expressions. That means do not treat the extended
regular expressions by just translating them into the basic ones. See
also Question 2, where you are asked to explicitly give the rules for
\textit{nullable} and \textit{der} for the extended regular
expressions.\newpage

\noindent
The meanings of the extended regular expressions are

\begin{center}
\begin{tabular}{r@{\hspace{2mm}}c@{\hspace{2mm}}l}
  $L([c_1,c_2,\ldots,c_n])$ & $\dn$ & $\{[c_1], [c_2], \ldots, [c_n]\}$\\ 
  $L(r^+)$                  & $\dn$ & $\bigcup_{1\le i}.\;L(r)^i$\\
  $L(r^?)$                  & $\dn$ & $L(r) \cup \{[]\}$\\
  $L(r^{\{n\}})$             & $\dn$ & $L(r)^n$\\
  $L(r^{\{..m\}})$           & $\dn$ & $\bigcup_{0\le i \le m}.\;L(r)^i$\\
  $L(r^{\{n..\}})$           & $\dn$ & $\bigcup_{n\le i}.\;L(r)^i$\\
  $L(r^{\{n..m\}})$          & $\dn$ & $\bigcup_{n\le i \le m}.\;L(r)^i$\\
  $L(\sim{}r)$              & $\dn$ & $\Sigma^* - L(r)$
\end{tabular}
\end{center}

\noindent whereby in the last clause the set $\Sigma^*$ stands
for the set of \emph{all} strings over the alphabet $\Sigma$
(in the implementation the alphabet can be just what is
represented by, say, the type \pcode{Char}). So $\sim{}r$
means in effect ``all the strings that $r$ cannot match''.\medskip 

\noindent
Be careful that your implementation of \textit{nullable} and
\textit{der} satisfies for every regular expression $r$ the following
two properties (see also Question 2):

\begin{itemize}
\item $\textit{nullable}(r)$ if and only if $[]\in L(r)$
\item $L(der\,c\,r) = Der\,c\,(L(r))$
\end{itemize}



\subsection*{Question 1}

What is your King's email address (you will need it in
Question 4)?

\subsection*{Question 2}

From the
lectures you have seen the definitions for the functions
\textit{nullable} and \textit{der} for the basic regular
expressions. Implement the rules for the extended regular
expressions:

\begin{center}
\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}
  $\textit{nullable}([c_1,c_2,\ldots,c_n])$  & $\dn$ & $?$\\
  $\textit{nullable}(r^+)$                   & $\dn$ & $?$\\
  $\textit{nullable}(r^?)$                   & $\dn$ & $?$\\
  $\textit{nullable}(r^{\{n\}})$              & $\dn$ & $?$\\
  $\textit{nullable}(r^{\{..m\}})$            & $\dn$ & $?$\\
  $\textit{nullable}(r^{\{n..\}})$            & $\dn$ & $?$\\
  $\textit{nullable}(r^{\{n..m\}})$           & $\dn$ & $?$\\
  $\textit{nullable}(\sim{}r)$              & $\dn$ & $?$
\end{tabular}
\end{center}

\begin{center}
\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}
  $der\, c\, ([c_1,c_2,\ldots,c_n])$  & $\dn$ & $?$\\
  $der\, c\, (r^+)$                   & $\dn$ & $?$\\
  $der\, c\, (r^?)$                   & $\dn$ & $?$\\
  $der\, c\, (r^{\{n\}})$              & $\dn$ & $?$\\
  $der\, c\, (r^{\{..m\}})$           & $\dn$ & $?$\\
  $der\, c\, (r^{\{n..\}})$           & $\dn$ & $?$\\
  $der\, c\, (r^{\{n..m\}})$           & $\dn$ & $?$\\
  $der\, c\, (\sim{}r)$               & $\dn$ & $?$\\
\end{tabular}
\end{center}

\noindent
Remember your definitions have to satisfy the two properties

\begin{itemize}
\item $\textit{nullable}(r)$ if and only if $[]\in L(r)$
\item $L(der\,c\,r)) = Der\,c\,(L(r))$
\end{itemize}

\noindent
Given the definitions of \textit{nullable} and \textit{der}, it is
easy to implement a regular expression matcher.  Test your regular
expression matcher with (at least) the examples:


\begin{center}
\def\arraystretch{1.2}  
\begin{tabular}{r|m{12mm}|m{12mm}|m{12mm}|m{12mm}|m{12mm}|m{12mm}}
  string & $a^{\{3\}}$ & $(a^?)^{\{3\}}$ & $a^{\{..3\}}$ &
     $(a^?)^{\{..3\}}$ & $a^{\{3..5\}}$ & $(a^?)^{\{3..5\}}$\\\hline
  $[]$           &&&&&& \\\hline 
  \texttt{a}     &&&&&& \\\hline 
  \texttt{aa}    &&&&&& \\\hline 
  \texttt{aaa}   &&&&&& \\\hline 
  \texttt{aaaaa} &&&&&& \\\hline 
  \texttt{aaaaaa}&&&&&& \\
\end{tabular}
\end{center}

\noindent
Does your matcher produce the expected results?

\subsection*{Question 3}

There are a number of explicit regular expressions that deal with single or several
characters, for example:

\begin{center}
\begin{tabular}{ll}
  $c$ & match a single character\\  
  $[c_1,c_2,\ldots,c_n]$ & match a set of characters---for character ranges\\
  $\textit{ALL}$ & match any character
\end{tabular}
\end{center}

\noindent
the latter is useful for matching any string (for example
$\textit{ALL}^*$). In order to avoid having an explicit constructor
for each case, we can generalise all such cases and introduce a single
constructor $\textit{CFUN}(f)$ where $f$ is a function from characters
to a boolean. Implement

\begin{center}
\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}
  $\textit{nullable}(\textit{CFUN}(f))$  & $\dn$ & $?$\\
  $\textit{der}\,c\,(\textit{CFUN}(f))$  & $\dn$ & $?$
\end{tabular}
\end{center}

\noindent in your matcher and then give definitions for

\begin{center}
\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}
  $c$  & $\dn$ & $\textit{CFUN}(?)$\\
  $[c_1,c_2,\ldots,c_n]$  & $\dn$ & $\textit{CFUN}(?)$\\
  $\textit{ALL}$  & $\dn$ & $\textit{CFUN}(?)$
\end{tabular}
\end{center}


\subsection*{Question 4}

Suppose $[a\mbox{-}z0\mbox{-}9\_\,.\mbox{-}]$ stands for the regular expression

\[[a,b,c,\ldots,z,0,\dots,9,\_,.,\mbox{-}]\;.\]

\noindent
Define in your code the following regular expression for email addresses

\[
([a\mbox{-}z0\mbox{-}9\_\,.-]^+)\cdot @\cdot ([a\mbox{-}z0\mbox{-}9\,.-]^+)\cdot .\cdot ([a\mbox{-}z\,.]^{\{2,6\}})
\]

\noindent and calculate the derivative according to your email
address. When calculating the derivative, simplify all regular
expressions as much as possible by applying the
following 7 simplification rules:

\begin{center}
\begin{tabular}{l@{\hspace{2mm}}c@{\hspace{2mm}}ll}
$r \cdot \ZERO$ & $\mapsto$ & $\ZERO$\\ 
$\ZERO \cdot r$ & $\mapsto$ & $\ZERO$\\ 
$r \cdot \ONE$ & $\mapsto$ & $r$\\ 
$\ONE \cdot r$ & $\mapsto$ & $r$\\ 
$r + \ZERO$ & $\mapsto$ & $r$\\ 
$\ZERO + r$ & $\mapsto$ & $r$\\ 
$r + r$ & $\mapsto$ & $r$\\ 
\end{tabular}
\end{center}

\noindent Write down your simplified derivative in a readable
notation using parentheses where necessary. That means you
should use the infix notation $+$, $\cdot$, $^*$ and so on,
instead of code.\bigskip
 
\noindent
Implement the simplification rules in your regular expression matcher.
Consider the regular expression $/ \cdot * \cdot
(\sim{}(\textit{ALL}^* \cdot * \cdot / \cdot \textit{ALL}^*)) \cdot *
\cdot /$ and decide wether the following four strings are matched by
this regular expression. Answer yes or no.

\begin{enumerate}
\item \texttt{"/**/"}
\item \texttt{"/*foobar*/"}
\item \texttt{"/*test*/test*/"}
\item \texttt{"/*test/*test*/"}
\end{enumerate}

\noindent
Also let $r_1$ be the regular expression $a\cdot a\cdot a$ and $r_2$ be
$(a^{\{19,19\}}) \cdot (a^?)$.  Decide whether the following three
strings consisting of $a$s only can be matched by $(r_1^+)^+$.
Similarly test them with $(r_2^+)^+$. Again answer in all six cases
with yes or no. \medskip

\noindent
These are strings are meant to be entirely made up of $a$s. Be careful
when copy-and-pasting the strings so as to not forgetting any $a$ and
to not introducing any other character.

\begin{enumerate}
\setcounter{enumi}{4}
\item \texttt{"aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"}
\item \texttt{"aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\ 
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\ 
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"}
\item \texttt{"aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\ 
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\ 
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"}
\end{enumerate}



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