--- a/cws/cw01.tex Wed Sep 17 14:29:52 2025 +0100
+++ b/cws/cw01.tex Wed Sep 17 15:11:48 2025 +0100
@@ -81,13 +81,13 @@
\code{RANGE}, \code{PLUS}, \code{OPTIONAL}, \code{INTER}, \code{NTIMES},
\code{UPTO}, \code{FROM} and \code{BETWEEN}.}
That means do not treat the extended regular expressions
-by just translating them into the basic ones. See also Question 1,
+by just translating them into the basic ones. See also Task 1,
where you are asked to explicitly give the rules for \textit{nullable}
and \textit{der} for the extended regular expressions. Something like
\[der\,c\,(r^+) \dn der\,c\,(r\cdot r^*)\]
-\noindent is \emph{not} allowed as answer in Question 1 and \emph{not}
+\noindent is \emph{not} allowed as answer in Task 1 and \emph{not}
allowed in your code.\medskip
\noindent
@@ -116,7 +116,7 @@
\noindent
Be careful that your implementation of \textit{nullable} and
\textit{der} satisfies for every regular expression $r$ the following
-two properties (see also Question 1):
+two properties (see also Task 1):
\begin{itemize}
\item $\textit{nullable}(r)$ if and only if $[]\in L(r)$
@@ -139,7 +139,7 @@
%at least a good working day fiddling with a program)? This is just
%for my curiosity to estimate what your background is.
-\subsection*{Question 1}
+\subsection*{Task 1}
From the lectures you have seen the definitions for the functions
\textit{nullable} and \textit{der} for the basic regular
@@ -179,7 +179,7 @@
Does your matcher produce the expected results? Make sure you
also test corner-cases, like $a^{\{0\}}$!
-\subsection*{Question 2}
+\subsection*{Task 2}
As you can see, there are a number of explicit regular expressions
that deal with single or several characters, for example:
@@ -229,12 +229,12 @@
\noindent
You can either add the constructor $CFUN$ to your implementation in
-Question 3, or you can implement this questions first
-and then use $CFUN$ instead of \code{RANGE} and \code{CHAR} in Question 3.
+Task 3, or you can implement this questions first
+and then use $CFUN$ instead of \code{RANGE} and \code{CHAR} in Task 3.
In an ideal world one would do this task first, but this might confuse
you with what you need to do in the previous question.
-\subsection*{Question 3}
+\subsection*{Task 3}
Suppose $[a\mbox{-}z0\mbox{-}9\_\,.\mbox{-}]$ stands for the regular expression
@@ -270,7 +270,7 @@
instead of raw code.\bigskip
-\subsection*{Question 4}
+\subsection*{Task 4}
Implement the simplification rules in your regular expression matcher.
Consider the regular expression $/ \cdot * \cdot
@@ -285,7 +285,7 @@
\item \texttt{"/*test/*test*/"}
\end{enumerate}
-\subsection*{Question 5}
+\subsection*{Task 5}
Let $r_1$ be the regular expression $a\cdot a\cdot a$ and $r_2$ be
$(a^{\{19,19\}}) \cdot (a^?)$.\medskip
@@ -338,7 +338,7 @@
\uline{\hfill}\bigskip\bigskip
\noindent
-\textbf{Question 1:}
+\textbf{Task 1:}
\begin{center}
\def\arraystretch{1.6}
@@ -378,7 +378,7 @@
\noindent
-\textbf{Question 2:}
+\textbf{Task 2:}
\begin{center}
\def\arraystretch{1.6}
@@ -398,7 +398,7 @@
\newpage
\noindent
-\textbf{Question 3 (`mathematical' notation):}
+\textbf{Task 3 (`mathematical' notation):}
\noindent
\uline{\hfill}\medskip
@@ -416,7 +416,7 @@
\uline{\hfill}\bigskip\bigskip
\noindent
-\textbf{Question 4:}\medskip
+\textbf{Task 4:}\medskip
\noindent
\textbf{1)}\; Yes / No\qquad
@@ -426,7 +426,7 @@
\noindent
-\textbf{Question 5:}\medskip
+\textbf{Task 5:}\medskip
\def\arraystretch{1.5}
\begin{tabular}{l|c|c}