hws/hw09.tex
author Christian Urban <christian dot urban at kcl dot ac dot uk>
Sat, 17 Oct 2015 11:24:41 +0100
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\documentclass{article}
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\usepackage{../style}
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\usepackage{../graphics}
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\begin{document}
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Christian Urban <christian dot urban at kcl dot ac dot uk>
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\section*{Homework 9}
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\begin{enumerate}
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\item Describe what is meant by \emph{eliminating tail
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      recursion}, when such an optimization can be applied and
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      why it is a benefit?
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%  \item It is true (I confirmed it) that
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%  
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%  \begin{center} if $\varnothing$ does not occur in $r$
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%  \;\;then\;\;$L(r) \not= \{\}$ 
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%  \end{center}
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%  
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%  \noindent
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%  holds, or equivalently
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%  
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%  \begin{center}
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%  $L(r) = \{\}$ \;\;implies\;\; $\varnothing$ occurs in $r$.
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%  \end{center}
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%  
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%  \noindent
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%  You can prove either version by induction on $r$. The best way to
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%  make more formal what is meant by `$\varnothing$ occurs in $r$', you can define
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%  the following function:
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%  
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%  \begin{center}
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%  \begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}
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%  $occurs(\varnothing)$      & $\dn$ & $true$\\
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%  $occurs(\epsilon)$           & $\dn$ &  $f\!alse$\\
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%  $occurs (c)$                    & $\dn$ &  $f\!alse$\\
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%  $occurs (r_1 + r_2)$       & $\dn$ &  $occurs(r_1) \vee occurs(r_2)$\\ 
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%  $occurs (r_1 \cdot r_2)$ & $\dn$ &  $occurs(r_1) \vee occurs(r_2)$\\
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%  $occurs (r^*)$                & $\dn$ & $occurs(r)$ \\
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%  \end{tabular}
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%  \end{center}
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%  
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%  \noindent
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%  Now you can prove 
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%  
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%  \begin{center}
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%  $L(r) = \{\}$ \;\;implies\;\; $occurs(r)$.
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%  \end{center}
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%  
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%  \noindent
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%  The interesting cases are $r_1 + r_2$ and $r^*$.
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%  The other direction is not true, that is if $occurs(r)$ then $L(r) = \{\}$. A counter example
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%  is $\varnothing + a$: although $\varnothing$ occurs in this regular expression, the corresponding
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%  language is not empty. The obvious extension to include the not-regular expression, $\sim r$,
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%  also leads to an incorrect statement. Suppose we add the clause
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%    
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%  \begin{center}
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%  \begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}
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%  $occurs(\sim r)$      & $\dn$ & $occurs(r)$
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%  \end{tabular}
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%  \end{center}  
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%  
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%  \noindent
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%  to the definition above, then it will not be true that
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%  
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%  \begin{center}
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%  $L(r) = \{\}$ \;\;implies\;\; $occurs(r)$.
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%  \end{center}
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%  
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%  \noindent
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%  Assume the alphabet contains just $a$ and $b$, find a counter example to this
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%  property.
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\end{enumerate}
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\end{document}
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%%% Local Variables: 
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%%% mode: latex
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%%% TeX-master: t
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%%% End: