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\section*{Coursework 1 (Strand 1)}

This coursework is worth 5\% and is due on 20 October at

16:00. You are asked to implement a regular expression matcher

and submit a document containing the answers for the questions

below. You can do the implementation in any programming

language you like, but you need to submit the source code with

which you answered the questions, otherwise a mark of 0\% will

be awarded. However, the coursework will \emph{only} be judged

according to the answers. You can submit your answers in a

txt-file or pdf.

\subsubsection*{Disclaimer}

It should be understood that the work you submit represents your own

effort.  You have not copied from anyone else. An exception is the

Scala code I showed during the lectures, which you can use.\bigskip

\subsubsection*{Tasks}

The task is to implement a regular expression matcher based on

derivatives. The implementation should be able to deal with the usual

(basic) regular expressions

\[

\varnothing, \epsilon, c, r_1 + r_2, r_1 \cdot r_2, r^*

\]

\noindent

but also with the following extended regular expressions:

\begin{center}

\begin{tabular}{ll}

$[c_1 c_2 \ldots c_n]$ & a range of characters\\

$r^+$ & one or more times $r$\\

$r^?$ & optional $r$\\

$r^{\{n,m\}}$ & at least $n$-times $r$ but no more than $m$-times\\

$\sim{}r$ & not-regular expression of $r$\\

\end{tabular}

\end{center}

\noindent

In the case of $r^{\{n,m\}}$ we have the convention that $0 \le n \le m$.

The meaning of these regular expressions is

\begin{center}

\begin{tabular}{r@{\hspace{2mm}}c@{\hspace{2mm}}l}

$L([c_1 c_2 \ldots c_n])$ & $\dn$ & $\{[c_1], [c_2], \ldots, [c_n]\}$\\ 

$L(r^+)$                  & $\dn$ & $\bigcup_{1\le i}. L(r)^i$\\

$L(r^?)$                  & $\dn$ & $L(r) \cup \{[]\}$\\

$L(r^{\{n,m\}})$           & $\dn$ & $\bigcup_{n\le i \le m}. L(r)^i$\\

$L(\sim{}r)$              & $\dn$ & $\Sigma^* - L(r)$

\end{tabular}

\end{center}

\noindent

whereby in the last clause the set $\Sigma^*$ stands for the set of

\emph{all} strings over the alphabet $\Sigma$ (in the implementation the

alphabet can be just what is represented by, say, the type \pcode{char})).  

So $\sim{}r$ means `all the strings that $r$

cannot match'. 

Be careful that your implementation of $nullable$ and $der$ satisfies

for every $r$ the following two properties (see also Question 2):

\begin{itemize}

\item $nullable(r)$ if and only if $[]\in L(r)$

\item $L(der\,c\,r)) = Der\,c\,(L(r))$

\end{itemize}

\noindent

{\bf Important!} Your implementation should have explicit cases for

the basic regular expressions, but also explicit cases for the

extended regular expressions.  That means do not treat the extended

regular expressions by just translating them into the basic ones. See

also Question 2, where you are asked to explicitly give the rules for

\textit{nullable} and \textit{der} for the extended regular

expressions.

\subsection*{Question 1 (unmarked)}

What is your King's email address (you will need it in Question 3)?

\subsection*{Question 2 (marked with 2\%)}

This question does not require any implementation. From the lectures

you have seen the definitions for the functions \textit{nullable} and

\textit{der} for the basic regular expressions.  Give the rules for

the extended regular expressions:

\begin{center}

\begin{tabular}{@ {}l@ {\hspace{2mm}}c@ {\hspace{2mm}}l@ {}}

$nullable([c_1 c_2 \ldots c_n])$  & $\dn$ & $?$\\

$nullable(r^+)$                   & $\dn$ & $?$\\

$nullable(r^?)$                   & $\dn$ & $?$\\

$nullable(r^{\{n,m\}})$            & $\dn$ & $?$\\

$nullable(\sim{}r)$               & $\dn$ & $?$\medskip\\

$der\, c\, ([c_1 c_2 \ldots c_n])$  & $\dn$ & $?$\\

$der\, c\, (r^+)$                   & $\dn$ & $?$\\

$der\, c\, (r^?)$                   & $\dn$ & $?$\\

$der\, c\, (r^{\{n,m\}})$            & $\dn$ & $?$\\

$der\, c\, (\sim{}r)$               & $\dn$ & $?$\\

\end{tabular}

\end{center}

\noindent

Remember your definitions have to satisfy the two properties

\begin{itemize}

\item $nullable(r)$ if and only if $[]\in L(r)$

\item $L(der\,c\,r)) = Der\,c\,(L(r))$

\end{itemize}

\subsection*{Question 3 (marked with 1\%)}

Implement the following regular expression for email addresses

\[

([a\mbox{-}z0\mbox{-}9\_\!\_\,.-]^+)\cdot @\cdot ([a\mbox{-}z0\mbox{-}9\,.-]^+)\cdot .\cdot ([a\mbox{-}z\,.]^{\{2,6\}})

\]

\noindent

and calculate the derivative according to your email address. When

calculating the derivative, simplify all regular expressions as much

as possible, but at least apply the following six simplification

rules:

\begin{center}

\begin{tabular}{l@{\hspace{2mm}}c@{\hspace{2mm}}ll}

$r \cdot \varnothing$ & $\mapsto$ & $\varnothing$\\ 

$\varnothing \cdot r$ & $\mapsto$ & $\varnothing$\\ 

$r \cdot \epsilon$ & $\mapsto$ & $r$\\ 

$\epsilon \cdot r$ & $\mapsto$ & $r$\\ 

$r + \varnothing$ & $\mapsto$ & $r$\\ 

$\varnothing + r$ & $\mapsto$ & $r$\\ 

$r + r$ & $\mapsto$ & $r$\\ 

\end{tabular}

\end{center}

\noindent

Write down your simplified derivative in the ``mathematicical''

notation using parentheses where necessary.

\subsection*{Question 4 (marked with 1\%)}

Suppose \textit{[a-z]} stands for the range regular expression

$[a,b,c,\ldots,z]$.  Consider the regular expression $/ \cdot * \cdot

(\sim{}([a\mbox{-}z]^* \cdot * \cdot / \cdot [a\mbox{-}z]^*)) \cdot *

\cdot /$ and decide wether the following four strings are matched by

this regular expression. Answer yes or no.

\begin{enumerate}

\item \texttt{"/**/"}

\item \texttt{"/*foobar*/"}

\item \texttt{"/*test*/test*/"}

\item \texttt{"/*test/*test*/"}

\end{enumerate}

\subsection*{Question 5 (marked with 1\%)}

Let $r_1$ be the regular expression $a\cdot a\cdot a$ and $r_2$ be

$(a^{\{19,19\}}) \cdot (a^?)$.  Decide whether the following three

strings consisting of $a$s only can be matched by $(r_1^+)^+$.

Similarly test them with $(r_2^+)^+$. Again answer in all six cases

with yes or no. \medskip

\noindent

These are strings are meant to be entirely made up of $a$s. Be careful

when copy-and-pasting the strings so as to not forgetting any $a$ and

to not introducing any other character.

\begin{enumerate}

\item \texttt{"aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"}

\item \texttt{"aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\ 

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\ 

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"}

\item \texttt{"aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\ 

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa\\ 

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"}

\end{enumerate}

\end{document}

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